A dragster race car can accelerate from rest to incredible speeds. In one case a dragster is able to finish the 305 m run in 3.64 s. What was the average acceleration during this run?

Answer:acbd

Explanation:

Answer:

Explanation:

Given data

mass m= 1200kg

radius r=92m

coefficient of friction μ=0.65

We know that

F=mv2/r

F=μmg  

mv2/r = μsmg  

v^2/r = μsg  

vmax = √(rμg)

Substituting our data we have

vmax=√(92*0.65*9.81)

vmax=√586.638

vmax=24.22m/s

Answer:

Both cars convert more kinetic energy to thermal energy.

Explanation:

Given that,

Two cars come to a stop from the same initial speed, one braking gently and the other braking hard.

We know that,

The conservation of energy :  

The energy of the system is always constant.

The energy can be change one form to another form.

So, we can say that when both cars come to a stop from the same speed, one braking softly and the other braking strongly then both cars convert more kinetic energy to thermal energy.

Hence, Both cars convert more kinetic energy to thermal energy.

Based on the law of consevation of energy, the car that brakes hard will convert more kinetic energy to thermal energy.

According to the law of conservation of energy, the total energy is conserved in any closed system.

Since the cars have the same mass and had the same initial speed, their kinetic energies are the same.

However, the car braking hard comes to rest in a shorter time and in a shorter distance.

Using the formula for calculating power:

The car that braked hard will have greater power due to shorter time of action.

This power is seen as greater thermal energy, whereas some of the energy of the other car will still be used in travelling some distance before stopping.

Therefore, the car that brakes hard will convert more kinetic energy to thermal energy.

Learn more about kinetic energy and thermal energy at: https://brainly.com/question/3064483

Answer:They have made community members shareholders so they get a share of the profits, which they use for schools and healthcare clinics

Explanation: Edmentum

Answer:

shareholders of the community get profits and that is used for schools and healthcare clinics. cs. 

Explanation:

Answer:

Biology

Physics

Chemistry

Explanation:

Biology (life like cells, human reproduction, etc.)

Physics (Studies forces, like gravity.)

Chemistry (studies the atoms, the elements, etc.)

Answer:

significant

Explanation:

The digits in a measurement that are considered significant are all of those digits that represent marked calibrations on the measuring device plus one additional digit to represent the estimated digit (tenths of the smallest calibration).

Answer:

noun. a person who is connected with another or others by blood or marriage. something having, or standing in, some relation or connection to something else. something dependent upon external conditions for its specific nature, size, etc. (opposed to absolute).

1) describe the life cycle of a star before it collapses into a black hole.

1) describe the life cycle of a star before it collapses into a black hole.ans: A star's life cycle is determined by its mass. The larger its mass, the shorter its life cycle. A star's mass is determined by the amount of matter that is available in its nebula, the giant cloud of gas and dust from which it was born. Over time, the hydrogen gas in the nebula is pulled together by gravity and it begins to spin. As the gas spins faster, it heats up and becomes as a protostar. Eventually the temperature reaches 15,000,000 degrees and nuclear fusion occurs in the cloud's core. The cloud begins to glow brightly, contracts a little, and becomes stable. It is now a main sequence star and will remain in this stage, shining for millions to billions of years to come. This is the stage our Sun is at right now.

2) describe the life cycle of a star before it becomes a dwarf.

ans: The life cycle of a low mass star (left oval) and a high mass star (right oval). ... As the core collapses, the outer layers of the star are expelled. A planetary nebula is formed by the outer layers. The core remains as a white dwarf and eventually cools to become a black dwarf.

3) what is the likely outcome of our sun?

ans: All stars die, and eventually — in about 5 billion years — our sun will, too. Once its supply of hydrogen is exhausted, the final, dramatic stages of its life will unfold, as our host star expands to become a red giant and then tears its body to pieces to condense into a white dwarf.

I think it is D. Force

Answer:

Explanation:

Do you mean tire tracks?

If you do then the tracks show that there must have been a lot of heat involved. When the tires skid, the friction produced must be awfully hot to stop and 800 kg vehical (which is pretty small). The tire tracks that you see are bits of melted rubber taken from the tire.

Force is involved, but heat is the better answer.

gravity is necessary for friction to take place. If you were out in space, you could not get enough friction to leave tire tracks. (Force is awfully small).

Lubrication is there to give you a 4th choice. The exact opposite is what takes place. Lubrication reduces friction.

Answer:

b

Explanation:

Answer:

10.53m/s²

Explanation:

Centripetal acceleration is the acceleration of an object about a circle. The formula for calculating centripetal acceleration is expressed by:

[tex]a = \frac{v^2}{r}[/tex]

v is the velocity of the car = 24.5m/s

r is the radius of the track = 57.0m

Substitute the given values into the formula:

[tex]a = \frac{24.5^2}{57} \\\\a = \frac{600.25}{57}\\ \\a = 10.53m/s^{2}[/tex]

Hence the centripetal acceleration of the race car is 10.53m/s²

Answer:False

Explanation:

Answer:

False

Explanation:

Answer:

25.  Approximately 8.1 meters

26. North 1.31 km, and East 2.81 km

Explanation:

25.

Notice that the displacements: 6 meters east and 5.4 south create the legs of a right angle triangle. The hypotenuse of that triangle will be the distance (d) needed to cover in order to get the ball in the hole in one putt. That is:

[tex]d=\sqrt{6^2+5.4^2} =\sqrt{65.16} \approx 8.072\,\,\,m[/tex]

which can be rounded to 8.1 m.

26.

Notice that the 3.1 km at an angle of 25 degrees north of east, is the hypotenuse of a right angle triangle that has for legs the east and north components of that distance.

We can find the leg corresponding to the east displacement using the cosine function (that relates adjacent side with hypotenuse):

[tex]east\,\, comp=3.1 * cos(25^o)\approx 2.809\,\,km[/tex]

and we can calculate the north component using the sine function that relates the opposite side to the angle with the hypotenuse.

[tex]north\,\,component = 3.1 * sin(25^o) \approx 1.31 \,\,km[/tex]

Answer:

The rate the wheel will process about the vertical is 2.86 RPM

Explanation:

Given;

radius of the bicycle wheel, R = 0.36 m

mass of the wheel, m = 3.2 kg

angular velocity, ω = 4 rev/s

The rate at which the wheel will process about the vertical is given by;

Ф = τ/L

Where;

τ is the torque

L is the angular momentum

τ = Fr

τ = mgr = 3.2 x 9.8 x 0.1 = 3.126 N.m

L = Iω =  MR²ω

L = 3.2 x (0.36)² x (4 x 2π)

L = 10.4244 kg.m²/s

Ф = τ/L

Ф = (3.126) / (10.4244)

Ф = 0.29987 rad/s

Ф = 0.29987 rad/s  x (60 / 2π)

Ф = 2.86 RPM

Therefore, the rate the wheel will process about the vertical is 2.86 RPM

Answer:

The correct answer is A. A government that wants to increase its GDP would most likely increase the money supply to make it easier to borrow money.

Explanation:

If the government wanted to increase its GDP, the most appropriate way to do so would be to increase the money supply both through issuance and through a reduction in bank reserve requirements, thereby increasing the circulating money in the hands of society.

This, in turn, would make citizens reinvest that money, increasing economic production and, therefore, the national GDP.

Answer: A. Increase the money supply to make it easier to borrow money

Explanation: I just took the test on Ap ex

ans: 4m/s²

and 2m/s²

step:

f=m.a

in first condition

f=12N , M=3kg

so,

12=3.a

a=12/3

a=4m/s².

similarly

in second condition

f=12N ,M=6Kg

so,

12=a.6

a=12/6

a=2m/s²

Answer:

t = 5.77 s

Explanation:

This exercise will use Newton's second law for rotational motion

            τ = I α

             α = τ / I

             α = 66/175

             α = 0.3771   rad/s²

now we can use the rotational kinematics relations, remember that all angles must be in radians

            θ = 1 rev = 2π radians

            θ = w₀ t + ½ α t²

as the wheel starts from rest w₀ = 0

             t = √ (2θ/α)

let's calculate

             t = √ (2 2π / 0.3771)

             t = 5.77 s

Answer:

La aceleración necesaria para detener el avión es - 10.42 m/s².

Explanation:

Un movimiento uniformemente acelerado (M.U.A) es aquél cuya aceleración es constante y la velocidad de un objeto cambia a medida que el movimiento evoluciona.

Siendo la aceleración "a" el cambio de velocidad al tiempo transcurrido en un punto A a B, la velocidad inicial la velocidad que tiene un cuerpo al iniciar su movimiento en un período de tiempo y la velocidad final la velocidad que tiene un cuerpo al finalizar su movimiento en un período de tiempo, entonces en  M.U.A se cumple:

Vf² - Vo² = 2*a*d

donde:

En este  caso:

Reemplazando:

(0 m/s)² - (50 m/s)² = 2*a*120 m

Resolviendo:

[tex]a=\frac{(0 m/s)^{2} -(50 m/s)^{2} }{2*120 m}[/tex]

a= - 10.42 m/s²

La aceleración necesaria para detener el avión es - 10.42 m/s².

Answer:

34k+B plus 9 :)

Explanation:

The answer is A I Hope this answer helps you (i got the question right)

Answer:

A. As speed increases, kinetic energy increases exponentially.

Explanation:

The amount of kinetic energy an object has depends on the speed. Kinetic energy is also known as "motion energy." This being said, if speed is increasing, decreasing, or staying constant, the kinetic energy of the object will too.

Answer:

y(i) = h

v(y.i) = 0

Explanation:

See attachment for elaboration

Answer:

40

Explanation:

Answer:

[tex]200.38^0[/tex]

Explanation:

Given the forces:

F1 = 8.92 i + 17.37 j

F2 = 8.31 i - 10.97 j

If a third vector is added to them such that they add up to to the null vector as F1 + F2 + F3 = 0

then to get F3:

F3 = -F2-F1

F3 = -(8.31 i - 10.97 j)-(8.92 i + 17.37 j )

F3 = -8.31 i + 10.97 j-8.92 i - 17.37 j

F3 = -8.31i-8.92i+10.97j-17.37j

F3 = -17.23i-6.4j

from the vector:

x = -17.23 and y = -6.4

angle of the third vector with respect to the +x-axis is expressed as:

[tex]\theta = tan^{-1}\frac{y}{x}\\ \theta = tan^{-1}\frac{-6.4}{-17.23}\\\theta = tan^{-1}0.3715\\\theta = 20.38^0[/tex]

Hence the angle the vector makes with the x axis will be [tex]\theta = 180+20.38 = 200.38^0[/tex]

Answer:

The force is [tex]F_b =  216 \  N [/tex]

Explanation:

From the question we are told that

   The  mass of the bungee jumper is  m  = 80 kg

    The spring constant is  [tex]k = 20 \ N/ m[/tex]

    The extension of the rubber bungee cords is  x = 50 m

Generally the weight of the jumper is

      [tex]W =  m *  g[/tex]

=>   [tex]W =  80 *  9.8 [/tex]

=>   tex]W =  784  \  N  [/tex]

Generally  the returning force of the rubber bungee cords is mathematically represented as

      [tex]F  =  k  *  x[/tex]

=>     [tex]F  =  20   * 50 [/tex]

=>     [tex]F  =  1000 \  N [/tex]

The force to be applied by the bear is

    [tex]F_b =  F -  W[/tex]

=>    [tex]F_b =  100 -  784[/tex]

=>  [tex]F_b =  216 \  N [/tex]

Answer:

3.2

Explanation:

I hope that this helps! Have a good day!!

Answer:

What do you mean ma´am/sir?

Explanation:

Answer:

m₁ = 70 lb

Explanation:

Here we will use the law of conservation of momentum:

m₁u₁ + m₂u₂ + m₃u₃ = m₁v₁ + m₂v₂ + m₃v₃

where,

m₁ = mass of first suitcase = ?

m₂ = mass of second suitcase = 30 lb

m₃ = mass of baggage carrier = 50 lb

u₁ = initial speed of first suitcase = 7.2 ft/s

u₂ = initial speed of second suitcase = 7.2 ft/s

u₃ = initial speed of baggage carrier = 0 ft/s

v₁ = Final speed of first suitcase = 4.8 ft/s

v₂ = Final speed of second suitcase = 4.8 ft/s

v₃ = Final speed of baggage carrier = 4.8 ft/s

because after collision all three will have same speed

Therefore,

(m₁)(7.2 ft/s) + (30 lb)(7.2 ft/s) + (50 lb)(0 ft/s) = (m₁)(4.8 ft/s) + (30 lb)(4.8 ft/s) + (50 lb)(4.8 ft/s)

(m₁)(7.2 ft/s) + (216 lb ft/s) + (0 lb ft/s) = (m₁)(4.8 ft/s) + (144 lb ft/s) + (240 lb ft/s)

(m₁)(7.2 ft/s) - (m₁)(4.8 ft/s) = 168 lb ft/s

m₁ = (168 lb ft/s)/(2.4 ft/s)

m₁ = 70 lb

Answer:

10) The distance between the archer and the tree is 50.074 meters.

11) The speed of the banana when it hits the water is approximately 13.554 meters per second.

Explanation:

10) The arrow experiments a parabolic motion, which is the combination of horizontal motion at constant velocity and vertical uniform accelerated motion. In this case we need to find the horizontal distance between the archer and the tree, calculated by the following kinematic equation:

[tex]x = x_{o} +v_{o}\cdot t \cdot \cos \theta[/tex] (Eq. 1)

Where:

[tex]x_{o}[/tex] - Initial position of the arrow, measured in meters.

[tex]x[/tex] - Final position of the arrow, measured in meters.

[tex]v_{o}[/tex] - Initial speed of the arrow, measured in meters per second.

[tex]t[/tex] - Time, measured in seconds.

[tex]\theta[/tex] - Launch angle, measured in sexagesimal degrees.

If we know that [tex]x_{o} = 0\,m[/tex], [tex]v_{o} = 65\,\frac{m}{s}[/tex], [tex]t = 0.85\,s[/tex] and [tex]\theta = 25^{\circ}[/tex], the horizontal distance between the archer and the tree is:

[tex]x = 0\,m + \left(65\,\frac{m}{s}\right)\cdot (0.85\,s)\cdot \cos 25^{\circ}[/tex]

[tex]x = 50.074\,m[/tex]

The distance between the archer and the tree is 50.074 meters.

11) The final speed of the banana ([tex]v[/tex]), measured in meters per second, just before hitting the water is determined by the Pythagorean Theorem:

[tex]v = \sqrt{v_{x}^{2}+v_{y}^{2}}[/tex] (Eq. 2)

Where:

[tex]v_{x}[/tex] - Horizontal speed of the banana, measured in meters per second.

[tex]v_{y}[/tex] - Vertical speed of the banana, measured in meters per second.

Each component of the speed are obtained by using these kinematic equations:

[tex]v_{x} = v_{o}\cdot \cos \theta[/tex] (Eq. 3)

[tex]v_{y} = v_{o}\cdot \sin \theta +g\cdot t[/tex] (Eq. 4)

Where [tex]g[/tex] is the gravitational acceleration, measured in meters per square second.

If we know that [tex]v_{o} = 7.6\,\frac{m}{s}[/tex], [tex]\theta = -40^{\circ}[/tex], [tex]g = -9.807\,\frac{m}{s^{2}}[/tex] and [tex]t = 0.75\,s[/tex], the components of final speed are, respectively:

[tex]v_{x} = \left(7.6\,\frac{m}{s} \right)\cdot \cos (-40^{\circ})[/tex]

[tex]v_{x} = 5.822\,\frac{m}{s}[/tex]

[tex]v_{y} = \left(7.6\,\frac{m}{s}\right)\cdot \sin (-40^{\circ})+\left(-9.807\,\frac{m}{s^{2}} \right) \cdot (0.75\,s)[/tex]

[tex]v_{y} = -12.240\,\frac{m}{s}[/tex]

And the speed of the banana right before hitting the water is:

[tex]v = \sqrt{\left(5.822\,\frac{m}{s} \right)^{2}+\left(-12.240\,\frac{m}{s} \right)^{2}}[/tex]

[tex]v \approx 13.554\,\frac{m}{s}[/tex]

The speed of the banana when it hits the water is approximately 13.554 meters per second.