A facilities manager at a university reads in a research report that the mean amount of time spent in the shower by an adult is 5 minutes. He decides to collect data to see if the mean amount of time that college students spend in the shower is significantly different from 5 minutes. In a sample of 11 students, he found the average time was 4.52 minutes and the standard deviation was 0.75 minutes. Using this sample information, conduct the appropriate hypothesis test at the 0.1 level of significance. Assume normality. (can you please show how to do this without a calculator or excel i just dont want answer but want to know how to do it).
a) What are the appropriate null and alternative hypotheses?
A) H0: μ = 5 versus Ha: μ < 5
B) H0: μ = 5 versus Ha: μ ≠ 5
C) H0: x = 5 versus Ha: x ≠ 5
D) H0: μ = 5 versus Ha: μ > 5
b) What is the test statistic? Give your answer to four decimal places.
c) What is the P-value for the test? Give your answer to four decimal places.
d) What is the appropriate conclusion?
A) Fail to reject the claim that the mean time is 5 minutes because the P-value is larger than 0.01.
B) Reject the claim that the mean time is 5 minutes because the P-value is larger than 0.01.
C) Reject the claim that the mean time is 5 minutes because the P-value is smaller than 0.01.
D) Fail to reject the claim that the mean time is 5 minutes because the P-value is smaller than 0.01.

Answer:

The painting is [tex]t = 10911.1 \ years \ old[/tex]

Step-by-step explanation:

From the question we are told that

    The amount of carbon present after t year is

           [tex]y(t) = y_o * e ^{-0.00012t}[/tex]    {Note ; This is the function }

Here  [tex]y(t)[/tex] is the amount of carbon-14 after time t

        [tex]y_o[/tex] the original amount of carbon-14

Now given that the paint as at now contain 27% of the original carbon-14

  Then it mean that

            [tex]y(t) = 0.27 y_o[/tex]

So the equation is represented as

       [tex]0.27 y_o = y_o * e ^{-0.00012t}[/tex]

=>    [tex]0.27 = * e ^{-0.00012t}[/tex]

=>    [tex]ln(0.27) = -0.00012t[/tex]

=>  [tex]- 1.30933 = -0.00012t[/tex]

=>  [tex]t = \frac{-1.30933}{-0.00012}[/tex]

=>   [tex]t = 10911.1 \ years[/tex]

Answer:

hope this is right y=74

Step-by-step explanation:

have not done this since two years ago so...

but anyway 148-180 = 32

32 is that angle

if this were a right triangle my answer would be different but 148/2 still completes this triangle and somewhat makes sense.

The correct answer is 90.

Answer:

z = 70°

y = 103°

Step-by-step explanation:

From the picture attached,

110° + z° = 180° [Supplementary angles]

z = 180 - 110

z = 70°

Since sum of interior angles of a polygon = (n - 2)×180°

where n = number of sides of the polygon

For a quadrilateral (n = 4),

Sum of interior angles = (4 - 2) × 180°

                                     = 360°

z° + y° + 100° + 87° = 360°

70° + y° + 187° = 360°

y = 103°

Therefore, measure of the angles x = 70° and y = 103°.

Answer:

[tex] \sqrt{392 {x}^{7} } [/tex]

Simplify

that's

[tex] \sqrt{392} \times \sqrt{ {x}^{7} } \\ \\ = \sqrt{196 \times 2} \: \times \sqrt{ {x}^{7} } \\ \\ = 14 \sqrt{2} \times \sqrt{ {x}^{7} } \\ \\ = 14 \sqrt{2x ^{7} } [/tex]

Hope this helps you

Answer:

The volume of sphere is 267.95 units³.

Step-by-step explanation:

Given that the formula of volume of sphere is V = 4/3×π×r³ where r represents radius. Then, you have to substitute the values into the formula :

[tex]v = \frac{4}{3} \times \pi \times {r}^{3} [/tex]

[tex]let \: r = 4[/tex]

[tex]v = \frac{4}{3} \times \pi \times {4}^{3} [/tex]

[tex]v = \frac{4}{3} \times \pi \times 64[/tex]

[tex]v = \frac{256}{3} \times 3.14[/tex]

[tex]v = 267.95 \: {units}^{ 3} [/tex]

Answer:

120

Step-by-step explanation:

Answer: 120

Hope that helped!(:

Answer:

[tex]\boxed{\mathrm{view \: explanation}}[/tex]

Step-by-step explanation:

A) 3x²c² + 5xc² - 2c²

Factor c² from all terms in the expression.

c²(3x² + 5x - 2)

Factor 3x² + 5x - 2

c²(3x-1)(x+2)

B) x² + 6x + 9

x² + 3x + 3x + 9

Factor common terms.

x(x+3)+3(x+3)

Take x+3 common.

(x+3)(x+3)

C) x² - 9

x² -3²

Apply formula : a² - b² = (a+b)(a-b)

(x+3)(x-3)

Answer:

A) [tex]c^2(3x-1)(x+2)[/tex]

B) [tex](x+3)(x+3)[/tex]

C) [tex](x+3)(x-3)[/tex]

Step-by-step explanation:

Part A:

[tex]3x^2c^2+5xc^2-2c^2[/tex]

Taking [tex]c^2[/tex] common

[tex]c^2(3x^2+5x-2)[/tex]

Using mid term break formula

[tex]c^2 (3x^2+6x-x-2)[/tex]

[tex]c^2[3x(x+2)-1(x+2)][/tex]

[tex]c^2(3x-1)(x+2)[/tex]

Part B:

[tex]x^2 + 6x + 9.[/tex]

[tex](x)^2+2(x)(3)+(3)^2[/tex]

[tex](x+3)^2[/tex]

[tex](x+3)(x+3)[/tex]

Part C:

[tex]x^2-9[/tex]

[tex](x)^2-(3)^2[/tex]

[tex](x+3)(x-3)[/tex]

Answer:

5 ≥ c

Step-by-step explanation:

-15≤-3c

Divide each side by -3, remembering to flip the inequality

-15/-3 ≤ -3c/-3

5 ≥ c

Answer:

c ≤ 5

Step-by-step explanation:

Since you have to divide both sides of the equation by a negative number, you have to flip the equality sign.

-15 ≤ -3c

(-15)/(-3) ≤ (-3c)/-3

5 ≥ c

c ≤ 5

Answer:

answer there

Step-by-step explanation:

hope it. was. helpful

​Answer:

14.29cm

Step-by-step explanation:

Height of the building=10cm

Angle of depression=60°

We are therefore asked to find the distance from the stone to the

the foot of the building;Therefore we use Tan ratio which is opp/adj;

Let the distance from the stone to the foot of the building be x;

10/x=Tan60°

10/x=1.7/1

We then cross multiply to get 1.7x=10

x=10/1.7

=10*10/1.7*10

=100/17

=14.29cm.

Answer:

The last set.

Step-by-step explanation:

The first 3 sets  contain  'one-to-many' relations , for example (1, 3) and (1, 5) in set 1 and (0, 0) and (0, 2) in set  3 , so they are not functions.

The last set does not have any of these and is a function.

Answer:

y=(x/6)

Step-by-step explanation

divide every input by 6 to get the output

Answer:

second option

Step-by-step explanation:

x / x - 1 + 3x / x + 2

= x(x + 2) / (x - 1)(x + 2) + 3x(x - 1) / (x - 1)(x + 2)

= (x² + 2x) / (x² + x - 2) + (3x² - 3x) / (x² + x - 2)

= (4x² - x) / (x² + x - 2)

Answer:

For 3^-6 = 1/3^6 = 726 and for 3^-4 = 1/3^4 = 81

Step-by-step explanation:

ARE THE NUMBERS SEPARATED OR THEY ARE TO BE JOIN TOGETHER,IF THERE ARE SEPARATED THE SOLUTION IS GOING TO BE...

3^-6

using law of indices x^-a = 1/x^a

So 3^-6 = 1/3^6

Now find the power of 3^6

which is the same as 3×3×3×3×3×3 = 729

therefore 1/3^6 = 729

For 3^-4

using the above method

3^-4 is same as 1/3^4

which is equal to

finding the nominator

3×3×3×3 = 81

so the answer is 81

Answer:

69 meters

Step-by-step explanation:

Answer:

Please privately chat to us why you chose to cheat during online class, otherwise we will contact your parents and kick you out of our program for the reason stated.

Step-by-step explanation:

Please contact your Quantitive Reasoning teacher at her email, as stated in Google Classroom.

Answer:

18

Step-by-step explanation:

Two years ago, Lisa was 34 - 2 = 32 years old. If she was twice as old as her brother, he was 32 / 2 = 16 years old at that time. His age now will be 16 + 2 = 18.

Answer:

x = 43

Step-by-step explanation:

125^(3x+7)=25^(5x−11)

Rewriting the bases as powers of 5

125 = 5^3  and 25 = 5^2

5^3 ^ (3x+7) = 5^2^(5x-11)

We know a^b^c = a^ (b*c)

5^(3 * (3x+7)) = 5^(2*(5x-11))

Distribute

5^(9x+21) = 5^(10x-22)

The bases are the same so the exponents are the same

9x+21 = 10x-22

Subtract 9x from each side

9x+21 -9x = 10x-9x-22

21 = x-22

Add 22 to each side

21+22 = x-22+22

43 = x

Answer:

[tex] P(X<6.4)= \frac{6.4*0.2}{2}= 0.64[/tex]

[tex] P(X>4.8) =1-P(X<4.8)= 1- \frac{4.8*0.15}{2}= 1-0.36= 0.64[/tex]

Step-by-step explanation:

Part a

We want to find:

[tex] P(X<6.4)[/tex]

And we just need to find the area below the curve until x=6.4, since we have a triangle we can do this:

[tex] P(X<6.4)= \frac{6.4*0.2}{2}= 0.64[/tex]

Part b

For this case we want to find this probability:

[tex] P(X>4.8)[/tex]

And we can use the complement rule and we got:

[tex] P(X>4.8) =1-P(X<4.8)= 1- \frac{4.8*0.15}{2}= 1-0.36= 0.64[/tex]

Answer:

A

Step-by-step explanation:

Answer: 23, 25, 27

Step-by-step explanation:

Let the 3 consecutive odd numbers be x, x+2 and x+4.

So

2x+(x+2)+3(x+4)=152

2x + x + 2 + 3x + 12 = 152

6x+14=152

6x = 152 - 14

x=138/6

x=23

So, the numbers are 23, 25 and 27.

Answer:

when we add all the angles.

=58+94+15=167

so it's a 180..

180_167

=13

round to nearest tenth.

=10..

Answer:

The answer is B.

Step-by-step explanation:

You have to substitute x = 2, into the equation of y :

[tex]y = 6 {x}^{3} - 5 {x}^{2} + 4x - 3[/tex]

[tex]let \: x = 2[/tex]

[tex]y = 6 {( 2)}^{3} - 5 {(2)}^{2} + 4(2) - 3[/tex]

[tex]y = 48 - 20 + 8 - 3[/tex]

[tex]y = 33[/tex]

Answer:

the answer is c

Step-by-step explanation:

because if the surgery has a 92% success rate and the splints have a 72% success rate then surgery would be recommended because it has a higher success rate

for labor. Joni paid $85 less per hour for labor. explanation:

The correct comparison of the cost of labor between Shannon and Joni is that Shannon paid $7 more per hour for labor.

It refers to the total amount of the expenditure done on a product in manufacturing or procuring.

It refers to the expenditure done on procuring labor for the work.

In our situation Shannon paid total $339.50 in which the cost of the parts is $112 and 3.5 hours of labor. So,

labor cost Shannon Paid=339.50-112

=$227.50

labor cost per hour=227.50/3.5

=$6.5 per hour

Joni paid total $455 in which the cost of spare parts is $310 and rest is labor

labor cost paid by Joni=455-310

=$145

labor cost per hour=145/2.5

=$58 per hour

So by doing comparing we found that Shannon had paid $6 per hour extra for labor.

Learn more about cost at https://brainly.com/question/1153322

#SPJ2

Answer:

Cricket only= 30

Volleyball only = 15

Hockey only = 25

Explanation:

Number of students that play cricket= n(C)

Number of students that play hockey= n(H)

Number of students that play volleyball = n(V)

From the question, we have that;

n(C) = 50, n(H) = 50, n(V) = 40

Number of students that play cricket and hockey= n(C∩H)

Number of students that play hockey and volleyball= n(H∩V)

Number of students that play cricket and volleyball = n(C∩V)

Number of students that play all three games= n(C∩H∩V)

From the question; we have,

n(C∩H) = 15

n(H∩V) = 20

n(C∩V) = 15

n(C∩H∩V) = 10

Therefore, number of students that play at least one game

n(CᴜHᴜV) = n(C) + n(H) + n(V) – n(C∩H) – n(H∩V) – n(C∩V) + n(C∩H∩V)

= 50 + 50 + 40 – 15 – 20 – 15 + 10

Thus, total number of students n(U)= 100.

Note;n(U)= the universal set

Let a = number of people who played cricket and volleyball only.

Let b = number of people who played cricket and hockey only.

Let c = number of people who played hockey and volleyball only.

Let d = number of people who played all three games.

This implies that,

d = n (CnHnV) = 10

n(CnV) = a + d = 15

n(CnH) = b + d = 15

n(HnV) = c + d = 20

Hence,

a = 15 – 10 = 5

b = 15 – 10 = 5

c = 20 – 10 = 10

Therefore;

For number of students that play cricket only;

n(C) – [a + b + d] = 50 – (5 + 5 + 10) = 30

For number of students that play hockey only

n(H) – [b + c + d] = 50 – ( 5 + 10 + 10) = 25

For number of students that play volleyball only

n(V) – [a + c + d] = 40 – (10 + 5 + 10) = 15

Answer:

Cricket only= 30

Volleyball only = 15

Hockey only = 25

Explanation of the answer:

Number of students that play cricket= n(C)

Number of students that play hockey= n(H)

Number of students that play volleyball = n(V)

From the question, we have that;

n(C) = 50, n(H) = 50, n(V) = 40

Number of students that play cricket and hockey= n(C∩H)

Number of students that play hockey and volleyball= n(H∩V)

Number of students that play cricket and volleyball = n(C∩V)

Number of students that play all three games= n(C∩H∩V)

From the question; we have,

n(C∩H) = 15

n(H∩V) = 20

n(C∩V) = 15

n(C∩H∩V) = 10

Therefore, number of students that play at least one game

n(CᴜHᴜV) = n(C) + n(H) + n(V) – n(C∩H) – n(H∩V) – n(C∩V) + n(C∩H∩V)

= 50 + 50 + 40 – 15 – 20 – 15 + 10

Thus, total number of students n(U)= 100.

Note;n(U)= the universal set

Let a = number of people who played cricket and volleyball only.

Let b = number of people who played cricket and hockey only.

Let c = number of people who played hockey and volleyball only.

Let d = number of people who played all three games.

This implies that,

d = n (CnHnV) = 10

n(CnV) = a + d = 15

n(CnH) = b + d = 15

n(HnV) = c + d = 20

Hence,

a = 15 – 10 = 5

b = 15 – 10 = 5

c = 20 – 10 = 10

Therefore;

For number of students that play cricket only;

n(C) – [a + b + d] = 50 – (5 + 5 + 10) = 30

For number of students that play hockey only

n(H) – [b + c + d] = 50 – ( 5 + 10 + 10) = 25

For number of students that play volleyball only

n(V) – [a + c + d] = 40 – (10 + 5 + 10) = 15

▬▬▬▬▬▬▬▬▬▬▬▬

Answer:

[tex]\huge\boxed{(6;\ -31)}[/tex]

Step-by-step explanation:

Let: [tex]f(x)=ax^2+bx+c[/tex].

The coordinates of the vertex:

[tex](h;\ k)\to h=\dfrac{-b}{2a};\ k=f(h)=\dfrac{-(b^2-4ac)}{4a}[/tex]

We have

[tex]f(x)=x^2-12x+5\to a=1;\ b=-12;\ c=5[/tex]

Substitute:

[tex]h=\dfrac{-(-12)}{2(1)}=\dfrac{12}{2}=6\\\\k=f(6)=6^2-12(6)+5=36-72+5=-31[/tex]

The vertex form of an equation of a quadratic function:

[tex]f(x)=a(x-h)^2+k[/tex]

We have:

[tex]f(x)=x^2-12x+5\to a=1[/tex]

Complete to the square [tex](a\pm b)^2=a^2\pm2ab+b^2[/tex]

[tex]x^2-12x+5=x^2-\underbrace{2(x)(6)}_{12x}+5=\underbrace{x^2-2(x)(6)+6^2}_{a^2-2ab+b^2}-6^2+5\\\\=\underbrace{(x-6)^2}_{(a-b)^2}-36+5=(x-6)^2-31\\\\h=6;\ k=-31\to(6;\ -31)[/tex]

Answer:

The probability that only one candidate is hired is 0.10.

Step-by-step explanation:

The probability of event E occurring is the ration of the favorable number of outcomes to the total number of outcomes.

[tex]P(E)=\frac{n(E)}{N}[/tex]

It is provided that N = 10  candidates are presented in a random order.

Compute the probability that only one candidate is hired as follows:

[tex]P(\text{Only 1 Hire})=\frac{1}{10}=0.10[/tex]

Thus, the probability that only one candidate is hired is 0.10.