A forest ranger spots a fire from the top of a lookout tower. the tower is 160 meters tall and the angle of depression to the fire is 12 degrees. how far is the fire from the base of the tower? round to the nearest meter.

Hey there!

You haven't provided any answer options but here's how you would solve a problem like this.

To find the number in between two numbers, you add it up and divide it by two!

So, what's between 1 and 3? Well you do 1+3 is 4 then divide by 2 you get 2!

100 and 580? You add them to get 680 then divide by two you get 340!

In between 0.57 and 0.69? Adding gives you 1.26 and then divide by two and we have 0.63!

And with percents, let's do 45% and 67%. You add you get 112% and then divide by two you have 56%!

So, with your answer options just add them up and divide by two and see which one gives you 76%!

I hope that this helps!

Answer:

h = - [tex]\frac{3}{2}[/tex]

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Given

y = 2x² + 6x + 11 ( factor out 2 from the first 2 terms )

   = 2(x² + 3x) + 11

Using the method of completing the square

add/subtract ( half the coefficient of the x- term )² to x² + 3x

y = 2(x² + 2([tex]\frac{3}{2}[/tex] )x + [tex]\frac{9}{4}[/tex] - [tex]\frac{9}{4}[/tex] ) + 11

  = 2(x + [tex]\frac{3}{2}[/tex] )² - [tex]\frac{9}{2}[/tex] + 11

  = 2(x + [tex]\frac{3}{2}[/tex] )² + [tex]\frac{13}{2}[/tex] ← in vertex form

with h = - [tex]\frac{3}{2}[/tex]

Hey there!

To solve this, we need to plug each of our answer options into the inequality and see if it is true. Which ever one doesn't make the inequality true when plugged in is the answer.

OPTION A

(x,y)=(-3,0)

We plug our values into the inequality.

0≥ I-3I+3

You may have noticed the bars surrounding the negative three.. If you didn't know, this is called absolute value. Absolute value is how far the number is from 0 on the number line. -7 is 7 away from 0 on a number line, so the absolute value of -7 is 7. The absolute value of 7 is 7. The absolute value of 0 is 0. Absolute value is signified by these bars. Le'ts finish evaluating.

0≥6

As you can see, zero is not greater than or equal to six. So, option A is false.

Since A is not a solution, we already know that that is the answer, so we don't even need to check B and C. But, we can still evaluate them if you want.

OPTION B

6≥I-3I+3

6≥6

This is true.

OPTION C

4≥I0I+3

4≥3

This is also true.

Therefore, the answer is A. (-3,0)

Have a wonderful day!

Answer:

We accept H₀

Step-by-step explanation:

Population mean  μ₀ = 47500

Population standard deviation unknown

Sample size    n = 86   degree of freedom  df = 86 - 1  df = 85

Sample mean    μ = 48061

Sample standard deviation 2,351

The claim implies a two tail test with t-studend distributon

Null  Hypothesis                 H₀               μ  =  μ₀

Alternative Hypothesis      Hₐ               μ  ≠  μ₀      

Confidence Interval  mean α = 0,02     and   α/2  =  0,01

With α/2 and df = 85, from t-table we find  t(c)  critical value

t(c) = 2,3710

We compute t(s) as

t(s)  =  ( μ - μ₀ ) / s /√n

t(s)  = ( 48061 - 47500 )/ 2351/√86

t(s)  = 561 * 9,273 / 2351

t(s) = 2,212

Now we compare t(s) and t(c)

t(s) < t(c)       2,212  < 2,371

Then we are in the acceptance region. We accept H₀

Answer:

180-130 = 50 degrees because its same side angle

m<2 = 50

Step-by-step explanation:

the second one m<1 is 105 for the same reason

Answer:

The answer is b=0 or b=9.085603

The equation is solved and the perfect squares are removed from the square root and A = b²√( 30b )

What is an Equation?

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the equation be represented as A

Now , the value of A is

Substituting the values in the equation , we get

A = √( 30b⁵ )

On simplifying the equation , we get

We can simplify the given expression by breaking down the number inside the square root into its prime factors:

30b⁵ = 2 x 3 x 5 x b⁵

Since we are looking to remove all perfect squares, we can remove the factors of 2 and 3, which are the only perfect squares present in the prime factorization of 30. This leaves us with:

30b⁵ = 2 x 3 x 5 x b⁵

= 2 x 3 x 5 x b⁴ x b

= 30b⁴ x b

Therefore, we can simplify the original expression as:

√(30b⁵) = √(30b⁴ x b) = √(30b⁴) x √b

A = b²√30 x √b

Hence , the expression √(30b⁵) simplifies to A = b²√30 x √b

To learn more about equations click :

https://brainly.com/question/19297665

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Answer:

1. 77520

2. [tex]P_1[/tex] = 0.0017

3. [tex]P_2[/tex] = 0.0019

4. [tex]P_3[/tex] = 0.9981

5. [tex]P_4[/tex] = 0.2036

Step-by-step explanation:

The number of ways or combinations in which we can select x elements from a group of n can be calculated as:

[tex]nCx = \frac{n!}{x!(n-x)!}[/tex]

So, there are 77520 selections that result in all 7 workers coming from the day shift. It is calculated as:

[tex]20C7 = \frac{20!}{7!(20-7)!}=77520[/tex]

At the same way, the total number of selections of 7 workers from the 45 is 45C7, so the probability that all 7 selected workers will be from the day shift is:

[tex]P_1=\frac{20C7}{45C7} =0.0017[/tex]

The probability that all 7 selected workers will be from the same shift is calculated as:

[tex]P_2=\frac{20C7+15C7+10C7}{45C7} =0.0019[/tex]

Because the consultant can select all workers from the day shift (20C7) or can select all workers from the swing shift (15C7) or can select all workers from the graveyard shift (10C7).

On the other hand, the probability that at least two different shifts will be represented among the selected workers is the complement of the probability that all 7 selected workers will be from the same shift. So it is calculated as:

[tex]P_3 = 1- P_2=1 - 0.0019 = 0.9981[/tex]

Finally, the probability that at least one of the shifts will be un-represented in that sample of workers is:

[tex]P_4=\frac{25C7+30C7+35C7}{45C7} =0.2036[/tex]

Where 25C7 is the number of ways to select all 7 workers from swing or graveyard shift, 30C7 is the number of ways to select all 7 workers from day or graveyard shift and 35C7 is the number of ways to selects all 7 workers from day shift and swing shift.

Answer:

18.2 :)

Have a great day!!!

Answer:

Solution,

____________________________

Men ------------------------------ Days

_____________________________

In case of indirect proportion,

4/6= 6/X

or, 6*X= 6*4 ( cross multiplication)

or, 6x= 24

or, 6x/6= 24/6 ( dividing both sides by 6)

Hope this helps...

Good luck on your assignment..

Answer:

[tex]\boxed{4 days}[/tex]

Step-by-step explanation:

M1 = 4

D1 = 6

M2 = 6

D2 = x (we've to find this)

Since,  it is an inverse proportion (more man takes less days for the work to complete and vice versa), so we'll write it in the form of

M1 : M2 = D2 : D1

4 : 6 = x : 6

Product of Means = Product of Extremes

=> 6x = 4*6

=> 6x = 24

Dividing both sides by 6

=> x = 4 days

Answer:

[tex]y(x)=\frac{9}{e^{1} } e^{-x} =3.310914971e^{-x}[/tex]

Step-by-step explanation:

This problem is very simple, since they give the solution for the differential equation from the start. So basically, you need to evaluate the initial conditions into the solution, and the derivative of the solution in order to find the value of the constants [tex]c_1[/tex] and [tex]c_2[/tex].

So, first of all, let's find the derivative of [tex]y(x)[/tex]:

[tex]y'(x)=c_1 e^{x} -c_2e^{-x}[/tex]

Now, let's evaluate the first initial condition:

[tex]y(-1)=c_1e^{-1} +c_2e^{-(-1)} =9\\\\c_1e^{-1} +c_2e^{1}=9\hspace{10}(1)[/tex]

Now, the second initial condition:

[tex]y'(-1)=c_1 e^{-1} -c_2e^{-(-1)}=-9\\\\c_1 e^{-1} -c_2e^{1}=-9\hspace{10}(2)[/tex]

Combining (1) and (2) we have a 2x2 System of Equations. Let's use elimination method in order to solve it:

[tex](1)+(2):\\\\c_1e^{-1} +c_2e^{1} +c_1e^{-1} -c_2e^{1}=9-9\\\\2c_1e^{-1} =0\\\\Hence\\\\c_1=0[/tex]

Replacing [tex]c_1[/tex] into (1)

[tex](0)e^{-1} +c_2e^{1}=9\\\\c_2e^{1}=9\\\\Hence\\\\c_2=\frac{9}{e^{1} } =3.310914971[/tex]

Therefore the solution of the second-order IVP is:

[tex]y(x)=\frac{9}{e^{1} } e^{-x} =3.310914971e^{-x}[/tex]

Answer:

50.6 m²

Step-by-step explanation:

The area of a rectangle is length × breadth.

9.96 × 5.08

= 50.5968

Rounding.

⇒ 50.60

⇒ 50.6

Answer:    20,736

Step-by-step explanation:

Math and History and Chemistry and Biology and Subjects

  3!     x        4!        x          3!          x        1!          x        4!       = 20,736

Answer: $12088.55

Step-by-step explanation:

A = p(1+r/n)^nt

A = 8000(1+0.07/2)^2*6

A = 12088.54926

Explanation:

The notation [tex]T_{-3,5}(x,y)[/tex]  or means to move any point (x,y) along the vector <-3,5>. Put another way, it says to shift (x,y) three units to the left and five units up. The x portion deals with left or right shifting, the y portion deals with up or down shifting. Since the x portion is negative, we go in the negative direction on the x axis. Y being positive means we move up rather than down.

This all means we end up with the translation rule [tex](x,y) \to (x-3,y+5)[/tex]

Replace x with 2 and solve:

2^2 + 4(2) = 4 + 8 = 12

Replace x with 3 and solve:

3^2 + 4(3) = 9 + 12 = 21

The difference between the two answers is : 21 -12 = 9

The difference between the two inputs is 3-2 = 1

The rate of change is the change in the answers I’ve the change in the inputs:

Rate of change = 9/1 = 9

Answer:

d. The length of a movie

Step-by-step explanation:

A discrete random variable is a variable which only takes on integer values.

A discrete distribution is used to describe the probability of the occurrence of each value of a discrete random variable.

From the given options, the length of a movie is not a discrete variable as it can have decimal values.

It therefore cannot have a Discrete probability distribution.

The correct option is D.

Answer:

B. Tanisha sold the CDs for $2 each.

Step-by-step explanation:

Answer:

1st one =  d y^27

2nd one = b 2x^9

Step-by-step explanation:

1st one: since the power is being raised to the power of 3 you multiply the numbers

2nd one: the powers aren't being raised so you add the powers together.

12x^13y^10/6X^4y^10

then dividing for exponents is subtracting them so

2x^9 since y gets canceled out

Answer:

Six

Step-by-step explanation:

The answer could be shown in multiple forms, but if I'm correct, the answer to this problem would be six.

Answer:

c = 730cm

Step-by-step explanation:

The first thing we would do is to draw the diagram using th given information.

Find attached the diagram.

a = 714 cm

the measure of angle A = 78°

To determine c, we would apply sine rule. This is because we know the opposite and we are to determine the hypotenuse

sin78 = opposite/hypotenuse

sin 78 = 714/c

c = 714/sin 78 = 714/0.9781

c= 729.99

c≅ 730 cm ( nearest cm)

Answer:

a) P(X∩Y) = 0.2

b) [tex]P_1[/tex] = 0.16

c) P = 0.47

Step-by-step explanation:

Let's call X the event that the motorist must stop at the first signal and Y the event that the motorist must stop at the second signal.

So, P(X) = 0.36, P(Y) = 0.51 and P(X∪Y) = 0.67

Then, the probability P(X∩Y) that the motorist must stop at both signal can be calculated as:

P(X∩Y) = P(X) + P(Y) - P(X∪Y)

P(X∩Y) = 0.36 + 0.51 - 0.67

P(X∩Y) = 0.2

On the other hand, the probability [tex]P_1[/tex] that he must stop at the first signal but not at the second one can be calculated as:

[tex]P_1[/tex] = P(X) - P(X∩Y)

[tex]P_1[/tex] = 0.36 - 0.2 = 0.16

At the same way, the probability [tex]P_2[/tex] that he must stop at the second signal but not at the first one can be calculated as:

[tex]P_2[/tex] = P(Y) - P(X∩Y)

[tex]P_2[/tex] = 0.51 - 0.2 = 0.31

So, the probability that he must stop at exactly one signal is:

[tex]P = P_1+P_2\\P=0.16+0.31\\P=0.47[/tex]

Answer:

[tex]\boxed{\sf \ \ \ \text{one possibility is } f(x)=3x \ and \ g(x)=x+2 \ \ \ }[/tex]

Step-by-step explanation:

hello

h(x)=f(g(x))=3(x+2)

if we have f(x)=3x and g(x)=x+2 then

f(g(x))=f(x+2)=3(x+2)

hope this helps

Answer:

d. (0.737, 0.823)

The 90% confidence interval is = (0.737, 0.823)

Step-by-step explanation:

Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.

The confidence interval of a statistical data can be written as.

p+/-z√(p(1-p)/n)

Given that;

Proportion p = 195/250 = 0.78

Number of samples n = 250

Confidence interval = 90%

z value(at 90% confidence) = 1.645

Substituting the values we have;

0.78 +/- 1.645√(0.78(1-0.78)/250)

0.78 +/- 1.645√(0.0006864)

0.78 +/- 1.645(0.026199236630)

0.78 +/- 0.043097744256

0.78 +/- 0.043

(0.737, 0.823)

The 90% confidence interval is = (0.737, 0.823)

━━━━━━━☆☆━━━━━━━

▹ Answer

Answer = b. 13/5

▹ Step-by-Step Explanation

|4 - 5| ÷ 9 × 3³ - 2/5

|-1| ÷ 9 × 3³ - 2/5

1 ÷ 9 × 3³ - 2/5

1/9 × 3³ - 2/5

1/3² × 3³ - 2/5

3 - 2/5

Answer = 13/5

Hope this helps!

- CloutAnswers ❁

Brainliest is greatly appreciated!

━━━━━━━☆☆━━━━━━━

Answer:

[tex] \boxed{\sf b. \ \frac{13}{5}} [/tex]

Step-by-step explanation:

[tex] \sf Simplify \: the \: following: \\ \sf \implies \frac{ |4 - 5| }{9} \times {3}^{3} - \frac{2}{5} \\ \\ \sf 4 - 5 = - 1 : \\ \sf \implies \frac{ | - 1| }{9} \times {3}^{3} - \frac{2}{5} \\ \\ \sf Since \: - 1 \: is \: a \: negative \: constant, \: |-1| = 1: \\ \sf \implies \frac{1}{9} \times {3}^{3} - \frac{2}{5} \\ \\ \sf {3}^{3} = 3 \times {3}^{2} : \\ \sf \implies \frac{ \boxed{ \sf 3 \times {3}^{2}} }{9} - \frac{2}{5} \\ \\ \sf {3}^{2} = 9 : \\ \sf \implies \frac{3 \times 9}{9} - \frac{2}{5} \\ \\ \sf \frac{9}{9} = 1 : \\ \sf \implies 3 - \frac{2}{5} [/tex]

[tex] \sf Put \: 3 - \frac{2}{5} \: over \: the \: common \: denominator \: 5 : \\ \sf \implies 3 \times \frac{5}{5} - \frac{2}{5} \\ \\ \sf \implies \frac{3 \times 5}{5} - \frac{2}{5} \\ \\ \sf 3 \times 5 = 15 : \\ \sf \implies \frac{ \boxed{ \sf 15}}{5} - \frac{2}{5} \\ \\ \sf \implies \frac{15 - 2}{5} \\ \\ \sf 15 - 2 = 13 : \\ \sf \implies \frac{13}{5} [/tex]

Answer:

[tex] Conf= 0.80[/tex]

With the confidence level we can find the significance level:

[tex]\alpha =1-0.8=0.2[/tex]

And the value for [tex]\alpha/2=0.1[/tex]. Then we can use the normal standard distribution and we can find a quantile who accumulates 0.1 of the area on each tail and we got:

[tex] z_{\alpha/2}= \pm 1.28[/tex]

Step-by-step explanation:

For this problem we have the confidence level given

[tex] Conf= 0.80[/tex]

With the confidence level we can find the significance level:

[tex]\alpha =1-0.8=0.2[/tex]

And the value for [tex]\alpha/2=0.1[/tex]. Then we can use the normal standard distribution and we can find a quantile who accumulates 0.1 of the area on each tail and we got:

[tex] z_{\alpha/2}= \pm 1.28[/tex]

Answer:

Equilateral

Acute

Step-by-step explanation:

The sides are all equal as indicated by the lines on each side - Equilateral

The angles are all equal by the angle marks  180/3 = 60 which is less than 90 degrees.  This makes the angles acute

Answer:

14%

Step-by-step explanation:

On edge 2020

Answer:

  (x, z) = (7, 69)

Step-by-step explanation:

Easy first: 69° and z° are vertical angles, so congruent:

  z = 69

__

The angle marked with an expression in x is supplementary to either of the other two:

  (6x +69)° +69° = 180°

  6x = 42 . . . . . . . . . . . . divide by °, subtract 138

  x = 7 . . . . . . . . . . . . . . divide by 6

Answer:

A

Step-by-step explanation:

Answer:

"But even this is admitting more than is true, for I answer roundly, that America would have flourished as much, and probably much more, had no European power had any thing to do with her."

Step-by-step explanation:

Checked 2021

Answer: 42

Step-by-step explanation:

Simply substitute 7 for x.

56 - 2(7)

56 - 14

42

Hope it helps <3

Answer:

f(7)=42

Step-by-step explanation:

f(x)=56-2x

Here put x=7

f(7)=56-2(7)

f(7)=56-14

f(7)=43

I hope this will help you :)