The graph should look like decreasing speed into zero into a permanent negative acceleration brought on by gravity.
What is negative acceleration ?
When an item experiences negative acceleration, its velocity changes in a negative direction, which can suggest that it is moving either slower or faster. In physics, a change in an object's velocity is referred to as "acceleration." Since this change in velocity is a vector quantity, it denotes both magnitude and direction. Positive velocity is likewise a vector, and experiencing negative acceleration means that something is slowing down. In contrast, an item moving at a negative velocity and acceleration is actually going faster.
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Question:
A fox locates its prey, usually a mouse, under the snow by slight sounds the rodents make. The fox then leaps straight into the air and burrows its nose into the snow to catch its next meal. What should the graph look like?
Compare your power output both climbing and running up the stair way to a 60- wattslight bulb?
Running up the flight of stairs produces more horsepower than strolling up them does. because running causes you to go through energy more quickly.
Work (in joules) equals your weight (in newtons) times the staircase's height (in meters.) The power you now possess is equal to the sum of the labor you completed and the time it took, or: Work (in joules) divided by time equals power (in watts) (in seconds.) The college alumnus questionnaire's physical activity index (PAI) is calculated on the basis of the assumption that every 20 steps is equivalent to 8 kcal of energy expenditure. This amount equates to a 0.40 kcal energy cost. You put in the same amount of effort as your potential energy changes.
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a person in good physical condition can put out 103 w of useful power for several hours at a stretch, perhaps by pedaling a mechanism that drives an electric generator. neglecting any problems of generator efficiency and practical considerations such as resting time: how many people would it take to run a 3.20–kw electric clothes dryer? (you do not need to enter any units.)
It will take exactly 32 persons to run a 3.20 KW electric clothes dryer
We have a person in good physical condition and can put out 103 W of useful power for several hours at a stretch.
We have to determine how many people would it take to run a 3.20 KW electric clothes dryer.
What is Power ?The rate of doing work is called Power. Mathematically -
P = [tex]$\frac{dW}{dt}[/tex]
According to the question -
A single person can generate 103 W of power.
Power needed by electric clothes dryer - 3.20 KW = 3.20 x 1000 =
3220 W
Therefore, the number of individuals required will be -
n = [tex]$\frac{3220}{103}[/tex] = 31.26 = 32 Persons
Hence, it will take exactly 32 persons to run a 3.20 KW electric clothes dryer.
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which low-energy state of condensed matter is characterized by structural rigidity and resistance to changes of shape or volume? gas
The low-energy state of condensed matter is characterized by structural rigidity and resistance to changes of shape or volume is solid.
Solids are made from the least energetic debris, which vibrate desk bound. As a end result, a solid acquires properties like a awesome form and quantity.
A substance's frozen kingdom of rely is what's called a solid. It is not important for a substance to freeze at a low temperature. as an instance, the tap at your chemistry lab station and the faucets in your property are each product of frozen chrome steel, as are your desk, pencils, pens, cell telephones, and computers. something is solid is frozen.
The molecules of count are more stiff and move less when it's miles in its stable state.
moreover, they are greater immune to shape changes. imagine ice, that's water in its strong kingdom. Ice is a ways extra strong in its structure than liquid water, making it greater hard to shape-alternate.
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four identical metallic spheres with charges of +5.0 µc, +4.2 µc, −3.8 µc, and −2.8 µc are placed on a piece of paper. the paper is lifted on all corners so that the spheres come into contact with each other simultaneously. the paper is then flattened so that the metallic spheres become separated. (a) what is the resulting charge on each sphere? 0.65 correct: your answer is correct. µc (b) how many excess or absent electrons (depending on the sign of your answer to part (a)) correspond to the resulting charge on each sphere? -4.0625e13 incorrect: your answer is incorrect. what is the charge of an electron/proton? electrons are ---select---
Four identical metallic spheres with charges of +8.6 UC, +5.0 PC, -4.2 pc, and -5.6 UC are placed on a piece of paper. The paper is lifted on all corners so that the spheres come into contact with each other simultaneously.
What are metallic spheres?It was a cause single to help charged programmer Gary McKinnon, yet it turned into the springboard for additional cooperation one year after the fact, after Circle principal man Dr. Alex Paterson, became involved. Metallic Circles is the outcome, a 49-minute odyssey that is purposefully separated into just two tracks. This is just valid for a metallic circle. A metallic circle has the property that there can be no static electric field inside it. Consequently, by Gauss' regulation there can be no charge inside it by the same token. The metal liner is utilized as a hindrance against pervasion. Instances of such COPV circles are clear in the accompanying picture where their surfaces are quite stringy by all accounts. Space circle tracked down in Spain.
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Recoil is noticeable if we throw a heavy ball while standing on roller skates. If instead we go through the motions of throwing the ball but hold onto it, our net recoil will be?.
Answer:
zero
Explanation:
determine the magnitude e(r) by applying gauss's law. express e(r) in terms of some or all of the variables/constants q , r , and ϵ0
The correct answer is E(r) = q/(4πr2ε_0)
The charge has now been extended along the z axis, so think about that scenario. Typically, this is referred to as a line charge. A line charge density is typically measured by the lambda variable, which has units of coulombs per metre (in the SI system).
The field lines must lie in planes that are perpendicular to the wire because symmetry requires that the electric field point radially outward from the wire at each point. It is recommended to utilise a cylindrical Gaussian surface with the line charge as its axis for calculating the size of the radial electric field E(r) produced by a line charge with charge density λ. The cylindrical surface's length L ought to cancel out in the expression for E. (r). The equation for E using this situation and Gauss's law (r).
E(r) = q/(4πr2ε_0)
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An atom has an electron in a state with = 5 and = -4. how many distinct values of the orbital quantum number would be compatible with this?
As you recognize , each electron features a unique set of quantum numbers that describes its exact location in an atom.
Specification :In your case, you're given two qunatum numbers, n, the principal quantum number, and ml , the *magnetic quantum number, and are sked to work out how many electrons can share these two quantum numbers in an atom.
The principal quantum number describes the energy state , or energy shell, on which the electron resides. Now, notice that the values the magnetic quantum number can take depend upon the value of l, the momentum quantum number.
Elaborating :For an electron that has n = 5, 4 are often l = {0 ; 1 ; 2; 3 ;4}
As you'll see, the magnetic quantum number can take values from − l all the high to l. If ml = 1, it follows that l could very easily be l = { 1 ;2 ;3; 4}
Finally, the spin quantum number, ms, which describes the electron's spin, can only take one among two values ms = {−1/2 ; + 1/2}
This means that you will have n = 5 ; l = 1 ; ml = 1 :ms = ± 1/2 n= 5 ; l = 2 ;ml=1 :ms= ± 1/2n = 5; l = 3 ;ml=1 :ms = ±1/2 n =5; l= 4 ;ml =1:ms=±1/2
Simply put, two electrons of opposite spins can share one orbital (given by ml=1) per sub shell (given by l).
Therefore, total of 9 electrons which will share those two quantum numbers.
What are the 4 quantum numbers?
In atoms, there are a complete of four quantum numbers: the principal quantum number (n), the orbital momentum quantum number (l), the magnetic quantum number (ml), and therefore the electron spin quantum number .
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A catapult can project a projectile at a speed as high as 37.0 m/s. If air resistance can be ignored, how high (in m) would a projectile launched at this speed rise if projected straight up?
The height of the projectile is 69.7 meters when air resistance can be ignored.
The initial speed (u) of the projectile is = 37 m/s
The final speed (v) is 0 because, at a high point, the projectiles come at the rest condition.
The acceleration is negative when the project is thrown in an upward direction. Therefore, the acceleration is, a = -g
Or, a = -9.81 m/s²
Now, by using the kinematics equation, we can find the height of the projectile.
v² = u² + 2gh
(0 m/s)² = (37 m/s)² + 2(-9.81 m/s²)h
2(9.81 m/s²)h = (37 m/s)²
Or, h = (37 m/s)²/ 2(9.81 m/s²)
Or, h = 69.7 m
Therefore, the height of the projectile is 69.7 meters.
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The planets never travel in a straight line as they orbit the sun. according to newton's second law of motion, this must mean that _________.
The planets never travel in a straight line as they orbit the sun. according to newton's second law of motion, this must mean that the force is acting on the planets.
What newton's second law of motion?Newton's subsequent regulation is a quantitative depiction of the progressions that a power can create on the movement of a body. It expresses that the time pace of progress of the energy of a body is equivalent in both extent and heading to the power forced on it. The force of a body is equivalent to the result of its mass and its speed. Force, similar to speed, is a vector amount, having both greatness and bearing. A power applied to a body can change the size of the energy or its heading or both. Newton's subsequent regulation is one of the main in all of material science. For a body whose mass m is consistent, it tends to be written in the structure F = mama, where F (force) and a (speed increase) are both vector amounts. On the off chance that a body has a net power following up on it, it is advanced quickly as per the condition. On the other hand, on the off chance that a body isn't sped up, there is no net power following up on it.
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A+tennis+ball+bounces+on+the+floor+three+times.+if+each+time+it+loses+22%+of+its+energy+due+to+heating,+how+high+does+it+rise+after+the+third+bounce,+provided+we+released+it+3.1+m+from+the+floor?
If a tennis ball bounces on the floor three times. if each time it loses 22% of its energy due to heating, the height it will rise after the third bounce, provided we released it 3.1 m from the floor is 1.4725 m.
What is energy loss due to heating?
The deliberate or accidental transfer of heat from one material to another is known as heat loss. Radiation, convection, and conduction can all contribute to this. When a component comes in direct touch with another component, whether it is insulated or not, conduction frequently happens. When a pipe, electric heater, or other component has an air barrier surrounding it, convection occurs. When there is no touch and heat is transmitted as waves, radiation results.
given,
Height = 3.1 m
Energy loss = 22%
Let, the total energy be equal to 1 unit
Balance of energy after first collision = 0.78 x 1 unit
= 0.78 unit
Balance after second collision = 0.78 ^2 unit
= 0.6084 unit
Balance after third collision = 0.78 ^3 unit
= 0.475 unit
Height achieved by the third collision will be equal to energy remained
H be the height achieved after 3 collision
0.475 ( m g h) = m g H
H = 0.475 x h
H = 0.475 x 3.1 m
H = 1.4725 m
Therefore,
It will rise up to 1.4725 m after the third bounce.
Complete Question
A tennis ball bounces on the floor three times. if each time it loses 22% of its energy due to heating, how high does it rise after the third bounce, provided we released it 3.1 m from the floor?
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in order that the connections inside an outlet box remain accessible, the nec requires that a surface extension from an outlet box cover be made using .
In order that the connections inside an outlet box remain accessible, the NEC requires that a surface extension from an outlet box cover be made using a flexible conduit only.
In the "surface extension" concept, the damper border dimensions are simply increased in relation to the air gap height. The extension coefficient is constant for continuum flow, but the rarefied gas causes the extension to vary on Kn. The elongation increases as Kn rises.
When a box's lid is constructed so that it is unlikely to come off or be removed if its locking mechanism becomes loose, one can create a surface extension from it. The wiring technique must be built for a length that is permitted and allows access to the inside of the box by removing the cover, and it must be set up such that any grounding continuous is independent of the connection between the box and cove.
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Complete Question:
The NEC requires that a box or conduit body be installed at each conductor splice connection point. In order that the connections inside an outlet box remain accessible, the NEC requires that a surface extension from an outlet box cover be made using ____.
four point charges, each of magnitude 9.66 µc, are placed at the corners of a square 87.1 cm on a side. if three of the charges are positive and one is negative, find the magnitude of the force experienced by the negative charge. the value of coulomb’s constant is 8.98755 × 109 n · m2 /c 2 .
The magnitude of the force experienced by the negative charge is 0.198N.
The Coulombs law is an expression that states that magnitude of the force between two charges q and Q separated by a distance r is given by
F=k|Q|q|r2
where k is Coulomb constant.
Answer and Explanation:
Let us visualize corners of the square as four points on the xy-axis. The four points would be origin (0,0), then (78.9 cm, 0), then (0, 78.9 cm) and (78.9 cm, 78.9 cm). These points are corners of the square described in the question. Let negative charge be at origin. Let charge 1 be located at (78.9 cm, 0), that is, its located along x-axis, a distance 78.9 cm away from the negative charge. The force due to this charge 1 acts in positive x-direction as the two charges attract. Let charge 2 be at point (0, 78.9 cm) and the force due to this charge acts in the positive y-direction. Charge 2 is also 78.9 cm away from negative charge. Let charge 3 be located at point (78.9 cm, 78.9 cm). Force due to this charge has the x and y-components. The angle this force makes with positive x-axis is 45 degrees since this is a square. The distance between charge 3 and negative charge is
√(78.9cm)2+(78.9 cm)2 =111.5814501cm.
Now we can calculate force on the negative charge due to each individual positive charge. Force due to the charge 1 is [tex]F_{1} =k|+q||-q| r^{2}(8.98755*109N.m^{2}/C^{2})*(2.68*106)*(2.68*106)^{2}(0.789m)^{2} =0.1036947816N[/tex]
in positive x-direction. Force due to the charge 2 has same magnitude as force due to charge 1, but acts in the positive y-direction.
F2 =0.1036947816N
The force due to the charge 3 is
[tex]F_{3}=k|+q||-q| r^{2} =(8.98755*109N.m^{2}/C^{2})*2.68*10^{-6} )^{2}(1.115814501m)^{2}= 0.05184739076N[/tex]
The x and y-components of force due to charge 3 are
F3,x=F3cos45=(0.05184739076√22)N=0.03666164159N
in positive x-direction, and
F3,y=F3sin45=(0.05184739076√22)N=0.03666164159N
in positive y-direction.
Therefore, x-component of the resultant force experienced by the negative charge is
Fx=F1+F3,x=0.1036947816N+0.03666164159N=0.1403564232N
and y-component is
Fy=F2+F3,y=0.1036947816N+0.03666164159N=0.1403564232N
Therefore, magnitude of the force experienced by the negative charge is
[tex]F= \sqrt{Fx_{2}+F_{2y} }= \sqrt{(0.1403564232N)^{2}+(0.140356432N)^{2} } =0.198493973N[/tex] =0.198N
correct to the three significant figures.
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hoover dam is about 180 m180 m high, measured from its low‑water surface to the crest of the dam, and about 380 m380 m long. assume that the dam is filled to 85�% of its full height. estimate the total hydrostatic force ????f on the hoover dam.
The total hydrostatic force on the hoovar dam = f=41.56 GN
Dam filled upto height =83% of 180 m =83/100 *180 =149.4 m
Hydrostatic power p= xpg
force acting on dam f= pressure *area =∫p da
=∫₀¹⁴⁹°⁴(xpg) (380dx)
=380pg∫₀¹⁴⁹°⁴xdx
=380*1000*9.8[x²/2]₀¹⁴⁹°⁴
f=380*9.8*1000/2[(149.4)²-0²]
f=4.156*10¹⁰ N
f=41.56 GN
The net hydrostatic pressure (hp) is the hydrostatic pressure in the __________ minus hydrostatic pressure in the __The net hydrostatic pressure (hp) is the hydrostatic pressure in the capillary minus hydrostatic pressure in the interstitial fluid.
Hydrostatic strain is a power produced by the tension of liquid on the slim walls either by the blood plasma or interstitial liquid.The net hydrostatic pressure is the equilibrium of the four Starling powers and decides the net progression of liquid across the slim layer.The net hydrostatic pressure got from the amount of the four powers depicted above decides the liquid stream into or out of the narrow.Development from the circulatory system into the interstitium is inclined toward by blood hydrostatic strain and interstitial liquid oncotic pressure.On the other hand, blood oncotic pressure and interstitial liquid hydrostatic strain tend to promote development from the interstitial into the circulatory system.To know more about hydrostatic , visit :
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A system gains 747 kj of heat, resulting in a change in internal energy of the system equal to 176 kj. how much work is done? = kj
A system gains 747 kJ of heat, resulting in a change in internal energy of the system equal to 176 kJ, here -571 kJ of work has been done.
ExplanationUsing the First law of thermodynamics
ΔU = q + w
Here Change in internal energy ΔU = 176 kJ
And Heat gained by the system (q) = 747 kJ
With Work done being w
So, apply the formula in the given information we get
176 kJ = 747 + w
w = 176 - 747 kJ
= -571 kJ
Here, the negative symbol denotes that the work has been done.
What is thermodynamics?The study of how heat and other types of energy interact is the subject of the physics field known as thermodynamics. The effects of thermal energy on matter are specifically discussed, as well as how thermal energy is changed into and out of other types of energy.
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the focal length of a thin lens is 40 mm and its aperture diameter is 10 mm. what is the f-number of this lens?
The f-number is 4
We need to know about f-number to solve this problem. The f-number of an optical system such as a camera lens is the ratio of the system's focal length to the diameter of the entrance pupil . It can be written as
N = f / D
where N is f-number, f is focal length and D is aperture diameter
From the question above, we know that
f = 40 mm
D = 10 mm
By substituting the question above, we know that
N = f / D
N = 40 / 10
N = 4
Hence, the f-number is 4
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Which two activities are normally controlled by the northbridge part of the chipset?
RAM, video card, are the two activities normally controlled by the northbridge part of the chipset.
The Northbridge chipset generally controls access to the RAM, video card, and the speeds at which the CPU can communicate with them. Northbridge is an Intel chipset that communicates with the computer processor and controls interaction with memory, the Peripheral Component Interconnect (PCI) bus, Level 2 cache, and all Accelerated Graphics Port (AGP) activities.
There are two activities that are normally controlled by the Northbridge part of the chipset. These include having access to the RAM and video card. To understand the Northbridge, you must understand part of it is used to be the memory controller chip used to retrieve memory from RAM for the LPU.
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we investigated a jet landing on an aircraft carrier. in a later maneuver, the jet comes in for a landing on solid ground with a speed of 87 m/s, and its acceleration can have a maximum magnitude of 8.55 m/s2 as it comes to rest. (a) from the instant the jet touches the runway, what is the minimum time interval needed before it can come to rest? (b) can this jet land on a small tropical island airport where the runway is 0.800 km long? (c) explain your answer.
For a successful landing the aircraft will need:
(a) A time from the instant the jet touches the runway of: 10.1754 s(b) A distance of: 0.44263 km(c) Due to the jet need just 0.44263 km of distance to landing it can land on a small tropical island airport where the runway is 0.800 km longThe formula for uniformly varied rectilinear motion (UVRM) and procedure we will use to solve this exercise is:
vf = vi + (a * t)x = (vf²-vi²)/ (2a)Where:
x = distancevf = final velocityvi = initial velocitya = accelerationInformation about the problem:
vf= 0 m/svi = 87 m/sa = -8.55 m/s²t =?x= ?Applying the final velocity formula, and clearing the time we get:
vf = vi + (a * t)
t = (vf – vi) /a
t = (0 m/s – 87 m/s) /-8.55 m/s²
t = -87 m/s/ -8.55 m/s²
t = 10.1754 s
Applying the distance formula, we get:
x = (vf²-vi²)/ (2a)
x = [(0 m/s)²- (87 m/s)²]/ (2 * -8.55 m/s²)
x = (0 m²/s²- 7569 m²/s²)/ -17.1 m/s²
x = -7569 m²/s²/ -17.1 m/s²
x = 442.63 m
By converting the distance units form (m) to (km) we have
x = 442.63 m * 1 km/1000 m
x = 0.44263 km
What is acceleration?
It is a physical quantity that indicates the variation of velocity as a function of time, it is expressed in units of distance per time squared e.g.: m/sec2 ; km/h2
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At a distance of 10 km from a point source (isotropic) radio transmitter, the amplitude of the e-field is 0.20 volts/meter. what is the total power emitted by the radio transmitter?
The total power emitted by the radio transmitter is 6.67×[tex]10^{4}[/tex]W .
What is a transmitter?The given parameters;
amplitude of the electric field, E = 0.2 V/m
distance of the transmitter, = 10 km = 10,000 m
The intensity of the radio wave from the transmitter is calculated as follows
[tex]I=E^{2}[/tex]/μc
I = [tex]5.305[/tex]×[tex]10^{-5}[/tex] [tex]W/m^{2}[/tex]
The total power emitted by the radio transmitter is calculated as follows;
I= P/A
P= IA
P = 6.67×[tex]10^{4}[/tex]W.
A radio transmitter, often known as a transmitter, is an electronic device used in electronics and telecommunications that uses an antenna to emit radio waves. A radio frequency alternating current is produced by the transmitter and applied to the antenna. The antenna emits radio waves after being stimulated by this alternating current.
All radio-communicating electronic devices, including radio and television broadcasting stations, cell phones, walkie-talkies, wireless computer networks, Bluetooth-enabled gadgets, garage door openers, two-way radios in aircraft, ships, and spacecraft, radar systems, and navigational beacons, require transmitters as essential component parts.
A transmitter could be a standalone electronic device or an electrical circuit housed inside another electronic gadget.
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You run around neyland stadium. when you are halfway around the stadium, which value cannot be 0?
a) instantaneous speed
b) average speed
c) instantaneous acceleration
d) average acceleration
When you are halfway around the stadium, average speed value cannot be 0.
Average speed = Total distance travelled / Time taken.
Since you ran halfway across the stadium, a certain amount of distance has been covered. The only way the average speed can be zero is if you remained stationary over a given interval of time.
In a distance-time graph, at the halfway point in the stadium, slope is equal to zero. So, Instantaneous speed is zero. In a Velocity-time graph, at the halfway point in the stadium, slope is equal to zero. So, Instantaneous acceleration is zero. In a Velocity ( w.r.t. time )-time graph, at the halfway point in the stadium, slope is equal to zero. So, Average acceleration is zero.
Therefore, when you are halfway around the stadium, average speed value cannot be 0.
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(i) when vs 10 v with the switch on, what is the total charge q transported through rl in 2.5 seconds? (ii) when vs 15 v with the switch on, what is the energy w required to transport 0.5 (c) of charge through rl?
(i) when vs 10 v with the switch on, what is the total charge q transported through rl in 2.5 seconds?
(ii) when vs 15 v with the switch on, what is the energy w required to transport 0.5
The is 7.5 Joule.
The unit of energy in line with the metric device of devices (SI) is said to be the joule (J).
similarly, power is expressed non a extensive style of other SI-incompatible units. energy, ergs, kilowatt-hours, kilocalories, and British Thermal gadgets are some of these gadgets.
(i) v_s = 10 v when switch ON
q_0=0 [when switch off]
q=q_0+∫0-t i(t)dt
q=∫0-t=2.5sec i(t)dt
q= ∫0-t=sec 1mAdt
q=1×10^-3[t]0 - 2.5 sec
q=1×10^-3[2.5]
q=2.5×10^-3
q=2.5mC
(ii)
i=15/10=1.5mA
w=vit
q=0.5 column
q=q_0-0+∫0-t i(t)dt
q=∫ 0-t 1.5mAdt
q= 1.5×10^-3t
0.5= 1.5×10^-3t
t=0.5/ 1.5×10^-3t=(0.5/1.5)×10^3t
t=0.3333×10^3=333.3 second
w=vit
=15×1.5×10^3×0.3333×10^3
w=15×1.5×0.3333
w=7.49925
w=7.5 Joule
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Determine the average speed in m/s of a hockey puck that takes 15 seconds to move 90.0 meters.
Explanation:
average speed= total distance/total time
=90÷15
=6
-50 1/2 + 12.3
What's answer
Answer:
-12.7
Explanation:
Answer: -38.2
Explanation: -50 1/2 + 10 = -40 1/2 + 2 = 38 1/2 + 0.3 = 38.2
The resolution of radio telescopes suffers greatly from the large wavelengths of the light they are observing. What can be done to a radio telescope to improve its angular resolution?.
make its dish bigger to improve its angular resolution
Because the wavelengths of radio waves are so larger than the wavelengths of visible light, radio telescopes must be much larger than optical telescopes. The wavelengths of radio waves range from 3 km to 1 cm, while the wavelengths of visible light range from 4 x 10-7 m (ultraviolet) to 7 x 10-7 m. (red). The degree of detail that can be observed in an area of the sky is measured in terms of angular resolution. More detail can be seen at a given wavelength with a larger telescope. The wavelength of the light or radio waves being observed by the telescope (λ) and the telescope's diameter (D) can be used to compute the angular resolution (θ) of the telescope.
θ = 2.5 × 105 × λ/D
θ = 1.22 × λ/D
The ability of any image-forming tool, such as a optical or radio telescope, a microscope, a camera, or an eye, to differentiate minute features of an object is known as angular resolution, and as such, it is a key factor in determining picture resolution. It is utilized in the application of acoustics to sound waves, antenna theory to radio waves, and optics to light waves.
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During a __________ year period starting at about 4.5 billion years ago, bits and pieces of metal-rich particles, rocks, and ices accumulated to form the earth.
During a 30-10 million year period starting at about 4.5 billion years ago, bits and pieces of metal-rich particles, rocks, and ices accumulated to form the earth.
What is the Earth?This is referred to as a type of planet which is habitable for different types of life forms. It is also the third planet from the sun and a majority of it contains water such as oceans etc.
Earth was formed billions of years ago through the bits and pieces of metal-rich particles, rocks, and ices which was in a 30-10 million year period which therefore makes it the correct choice.
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A mass attached to a spring is displaced from its equilibrium position by 5cm and released. The system then oscillates in simple harmonic motion with a period of 1s. If that same mass–spring system is displaced from equilibrium by 10cm instead, what will its period be in this case?.
The period of the pendulum is √2 seconds.
We need to know about pendulum experiments to solve this problem. The pendulum is a simple experiment to calculate gravitational acceleration. The gravitational acceleration can be calculated by
g = 4π² . L / T²
where g is gravitational acceleration, L is the length of the string and T is the period.
From the question above, we know that:
T1 = 1 s
L1 = 5 cm
L2 = 10 cm
By using proportionality, the squared period is proportional to the length. Hence,
T² ~ L
Using the ratio, we can write
T1² / T2² = L1 / L2
1² / T2² = 5 / 10
1 / T2² = 1 / 2
T2² = 2
T2 = √2 second
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a boy is to catch a ball which drops vertically from the top of a 14.9-m tower. find the average velocity at which the boy, initially 6.62 m from the base of the tower,
The velocity of the boy in order to catch the ball is 3.8 m/s.
Time of motion of the ballThe time taken for the for the ball to fall from the given tower is calculated as follows;
t = √(2h/g)
where;
h is the height of fall of the ballg is acceleration due to gravityt = √(2 x 14.9 / 9.8)
t = 1.74 seconds
Velocity of the boyThe velocity of the boy in order to catch the ball is calculated as follows;
x = Vxt
Vx = x/t
Vx = 6.62 m / 1.74 s
Vx = 3.8 m/s
Thus, the velocity of the boy in order to catch the ball is 3.8 m/s.
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If the density of water a given temperature and pressure is 1000 kg/m^3, what is the specific volume of the water?
The specific volume of the water with a density of 1000 kg/m^3 is: 0.001 m^3/kg
The specific volume formula and the procedure we will use is:
v = 1/ρ
Where:
v= specific volumeρ= densityInformation about the problem:
ρ= 1000 kg/m^3v= ?Applying the specific volume formula we get:
v = 1/ρ
v = 1/1000 kg/m^3
v = 0.001 m^3/kg
What is density?It is a physical quantity that expresses the ratio of the body mass to the volume it occupies.
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rolls of foil are 304 mm wide and 0.020 mm thick. (the density of foil is 2.7 g/cm3 .) what maximum length of foil can be made from 1.09 kg of foil?
The maximum length of foil will be 6639.8635 cm or 66.3986 m
To find the maximum length of the foil, the given datas are:
Width of roll of foil = 304 mm
Height or thickness = 0.020 mm
Density of foil = 2.7 g/cm³
Mass of foil = 1.09 Kg
What is Density?Density is the substance's mass per unit volume. It can be also described by measuring how the particles in the substances tightly packed together.
d = m/ v
v = length (l) × width (w) × height (h)
First of we will convert the Kg into gram and mm into cm.
For 1 Kg = 1000 g
1.09 × 1000 = 1090 g
For 1 cm = 10 mm
304 / 10 = 30.4 cm
0.020 / 10 = 0.0020 cm
Now we will put the values in formula:
d = m/ l× h× w
l = m / d × h× w
l = 1090 g / 2.7 g/cm³× 30.4 cm × 0.0020 cm
l = 1090 g/ 0.16416 g/cm
l = 6639.8635 cm or 66.3986 m
The maximum length of foil will be 6639.8635 cm or 66.3986 m
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A pumpkin is dropped from a 35 m building. What is its initial velocity (vi )?
Answer:
0 m/s
Explanation:
It is correct answer.
shot from a cannon in 1998, david "cannonball" smith set the distance record for being shot from a cannon (56.64 m). during a launch in the cannon’s barrel, his speed increased from zero to 80 km/h in 0.40 s. while he was being stopped by the catching net, his speed decreased from 80 km/h to zero with an average acceleration of 180 m/s2m/s2. what can you determine about smith’s flight using this information?
The final velocity of the cannon camera is 22m/s
We are informed in this query that David will launch from a journey at his final speed. Consequently, it is 80 kilometers per hour. Therefore, we must convert. Listen at a 2 m/s rate. In order to convert our number of 80 into units, we must multiply it by the number of meters in a club. As a result, his final velocity equals 22.2.
a= v/ t = 56m/sec square dec acceleration = 80km/h converting into final velocity m /s sec its 22.2m/s
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