A garden hose attached with a nozzle is used to fill a 20-gallon bucket. The inner diameter of the hose is 1 inch and it reduces to 0.5 inch at the nozzle exit. If the average velocity in the hose is 8ft/s, determine
a) the volume and mass flow rates of water through the hose.
b) how long it will take to fill the bucket with water.
c) the average velocity of water at the nozzle exit.

Answers

Answer 1

Answer:

a). [tex]$0.0436 \ ft^3/s$[/tex] , [tex]$2.72 \ lb \ m/s$[/tex]

b). [tex]$61.32 \ s$[/tex]

c). 32. ft/s

Explanation:

a). The volume flow rate of the water is given by :

[tex]$\dot V = uA$[/tex]

   [tex]$=u \pi \left( \frac{d}{2}\right)^2$[/tex]

   [tex]$=\frac{u \pi d^2}{4}$[/tex]

   [tex]$=\frac{8\ ft/s \ \pi \left(\frac{1}{12}\right)^2}{4}$[/tex]

    [tex]$= 0.0436 \ ft^3/s$[/tex]

The mass flow rate of the water is given by :

[tex]$\dot m = \rho \dot V$[/tex]

    [tex]$= 62.4 \times 0.0436$[/tex]

    [tex]$=2.72 \ lb \ m/s$[/tex]

b). The time taken to fill the container is

     [tex]$\Delta t = \frac{V}{\dot V}$[/tex]

          [tex]$=\frac{20 \ gal}{0.0436 \ ft^3/s}\left( \frac{1 \ ft^3}{7.4804 \ gal}\right)$[/tex]

          [tex]$=61.32 \ s$[/tex]

c). The average velocity at the nozzle is :

[tex]$u=\frac{\dot V}{A}$[/tex]

  [tex]$=\frac{\dot V}{\frac{\pi d^2}{4}}$[/tex]

  [tex]$=\frac{0.0436}{\frac{\pi \left(\frac{0.5}{12}\right)^2}{4}}$[/tex]

  = 32. ft/s


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Answer:

fart

Explanation:

A landowner and a contractor entered into a written contract under which the contractor agreed to build a building and pave an adjacent sidewalk for the landowner for $200,000. Later, while construction was proceeding, the landowner and the contractor entered into an oral modification under which the contractor was not obligated to pave the sidewalk but still would be entitled to $200,000 upon completion of the building. The contractor completed the building. The landowner, after discussions with his landscaper, demanded that the contractor pave the adjacent sidewalk. The contractor refused.

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difference between theory and practice?​

Answers

Answer:

There is a huge difference between theory vs. practice. Theory assumes an outcome, while practice allows you to test the theory and see if it is accurate.

Theory and Practice Explained

Practice is the observation of disparate concepts (or a phenomenon) that needs explanation. A theory is a proposed explanation of the relationship between two or more concepts, or an explanation for how/why a phenomenon occurs.

(a) Calculate the heat flux through a sheet of steel that is 10 mm thick when the temperatures oneither side of the sheet are held constant at 300oC and 100oC, respectively.(b) Determine the heat loss per hour if the cross-sectional area of the sheet is 0.25 m2.(c) What will be the heat loss per hour if a sheet of soda-lime glass is used instead

Answers

Answer:

do the wam wam

Explanation:

The heat flux is =1038kW/m² , the heat lost per hour is =259.5 kW, the heat lost per hour using a sheet of soda- lime glass.

Calculation of heat flux

The thickness of steel( t) = 10mm = 10× 10^-³m

The temperature difference on both sides = 300-100

∆T = 200°C

But the formula for heat flux = q = k∆T/t

Where K = thermal conductivity for steel = 51.9W/mK.

Substitute the variables into the formula for heat flux;

q = 51.9 × 200/10 × 10-³

q = 10380 × 10³/10

q = 10380000/10

q = 1038000 W/m² = 1038kW/m²

To calculate the heat lost per hour if the cross sectional area is = 0.25 m2 use the formula q × A

= 1038kW/m² × 0.25 m2

= 259.5 kW.

Learn more about heat flux here:

https://brainly.com/question/15217121

Solved this question??????????????????

Answers

I do not know!!!!!!!!

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