Answer:
The final volume when pressure is changed is 126.1mL
Explanation:
Based on Boyle's law, in a gas the volume is inversely proportional to its pressure when temperature remains constant. The equation is:
P₁V₁ = P₂V₂
Where P is pressure and V volume of 1, intial state and 2, final state.
Computing the values of the problem:
350mmHg*200mL = 555mmHgV₂
126.1mmHg = V₂
The final volume when pressure is changed is 126.1mLHow many hydrogen atoms in the
molecule (NH4)2C8H402?
Answer:
12 hydrogen atoms
Explanation:
Let's consider the chemical formula of the compound (NH₄)₂C₈H₄O₂.
We can see the ammonium ion, NH₄⁺, which contains 4 hydrogen atoms. However, this ion is enclosed in parenthesis with a subindex 2. That means that we have to multiply the whole ion by 2, therefore resulting in 8 atoms of hydrogen. Then, in C₈H₄O₂, we can see another 4 hydrogen atoms. The total number of hydrogen atoms in 1 molecule of (NH₄)₂C₈H₄O₂ is 8 + 4 = 12 hydrogen atoms.
Type the correct answer in the box. Spell all words correctly.
What forms the backbone of a DNA strand?
A DNA molecule is made up of building blocks known as nucleotides. Each nucleotide consists of deoxyribose, a phosphate group, and one of the chemical bases. The nucleotides join together to form a _______
, which form the backbone of a DNA strand.
if you are provided with 34.5 g iron (iii) chloride and 25.3 g sodium carbonate what is the limiting ractant
Answer:
Sodium carbonate, Na₂CO₃ is the limiting
Explanation:
We'll begin by writing the balanced equation for the reaction between iron (iii) chloride, FeCl₃ and sodium carbonate, Na₂CO₃.
This is illustrated below:
2FeCl₃ + 3Na₂CO₃ → Fe₂(CO₃)₃ + 6NaCl
Next, we shall determine the masses of FeCl₃ and Na₂CO₃ that reacted from the balanced equation. This can be obtained as follow:
Molar mass of FeCl₃ = 56 + (3×35.5)
= 56 + 106.5
= 162.5 g/mol
Mass of FeCl₃ from the balanced equation = 2 × 162.5 = 325 g
Molar mass of Na₂CO₃ = (2×23) + 12 + (3×16)
= 46 + 12 + 48
= 106 g/mol
Mass of Na₂CO₃ from the balanced equation = 3 × 106 = 318 g
SUMMARY:
From the balanced equation above,
325 g of FeCl₃ reacted with 318 g of Na₂CO₃.
Finally, we shall determine the limiting reactant. This can be obtained as follow:
From the balanced equation above,
325 g of FeCl₃ reacted with 318 g of Na₂CO₃.
Therefore, 34.5 g of FeCl₃ will react with = (34.5 × 318)/325 = 33.76 g of Na₂CO₃.
From the calculations made above, we can see clearly that it will take a higher amount (i.e 33.76 g) of Na₂CO₃ than what was given (i.e 25.3 g) to react completely with 34.5 g of FeCl₃. Therefore, Na₂CO₃ is the limiting reactant and FeCl₃ is the excess reactant.
If an object is accelerating at a rate of 25 m/s2, how long (in seconds) will it take to reach a speed of 550 m/s? (Assume an initial velocity of zero.)
Answer:
22s
Explanation:
Given parameters:
Acceleration = 25m/s²
Final velocity = 550m/s
Initial velocity = 0m/s
Unknown:
Time taken = ?
Solution:
To solve this problem, we are going to use one of the motion equations:
v = u + at
v is the final velocity
u is the initial velocity
a is the acceleration
t is the time taken
550 = 0 + 25 x t
550 = 25t
t = 22s
Arsenic(III) sulfide sublimes readily, even below its melting point of 320 °C. The molecules of the vapor phase are found to effuse through a tiny hole at 0.28 times the rate of effusion of Ar atoms under the same conditions of temperature and pressure. What is the molecular formula of arsenic(III) sulfide in the gas phase?
The molecular formula : As₄S₆
Further explanationGiven
Rate of effusion of arsenic(III) sulfide = 0.28 times the rate of effusion of Ar atoms
Required
The molecular formula
Solution
Graham's law: the rate of effusion of a gas is inversely proportional to the square root of its molar masses or
the effusion rates of two gases = the square root of the inverse of their molar masses:
[tex]\rm \dfrac{r_1}{r_2}=\sqrt{\dfrac{M_2}{M_1} }[/tex]
or
[tex]\rm M_1\times r_1^2=M_2\times r_2^2[/tex]
Input the value :
1 = Arsenic(III) sulfide
2 = Ar
MM Ar = 40 g/mol
0.28 = √(40/M₁)
M₁=40 : 0.28²
M₁=510 g/mol
The empirical formula of arsenic(III) sulfide = As₂S₃
(Empirical formula)n = molecular formula
( As₂S₃)n = 510 g/mol
(246.02 g/mol)n = 510 g/mol
n = 2
So the molecular formula : As₄S₆
Briefly explain how will you describe which object is moving fast and which one is moving slow?
A 2.912 g sample of a compounds containing only C, H, and O was completely oxidized in a reaction that yielded 3.123 g of water and 7.691 g of carbon dioxide. Determine the empirical formula and molecular formula of the compound if it has a molar mass of 100.1 g/mol.
Answer:
Explanation:
18 gram of water contains 2 g of hydrogen
3.123 gram of water will contain 2 x 3.123 / 18 = .347 g of hydrogen .
44 gram of carbon dioxide contains 12 g of carbon
7.691 gram of carbon dioxide will contain 12 x 7.691 / 44 = 2.1 g of carbon .
So the sample will contain 2.912 - ( .347 + 2.1 ) g of oxygen .
= .465 g of oxygen .
moles of Carbon = 2.1 / 12 = .175
moles of hydrogen = .347 / 1 = .347
moles of oxygen = .465 / 16 = .029
Ratio of moles of carbon , oxygen and hydrogen ( C,O,H )
= 0.175 : 0.029 : 0.347
= .175/ .029 : 1 : .347 / .029
= 6 : 1 : 12
So empirical formula = C₆H₁₂O
Let the molecular formula be [tex](C_6H_{12}O)_n[/tex]
molecular weight = n ( 6 x 12 + 12x 1 + 16)
= 100 n
Given 100 n = 100.1
n = 1
Molecular formula = C₆H₁₂O.
which formula represents a molecule solid
Dry ice are the molecule which represent molecular solid. Hence option c is correct.
What are molecule?Molecules are defined as the lowest identifiable unit into which a pure material can be divided while maintaining its chemical makeup and attributes is made up of two or more atoms. When two or more atoms come together and form bonds with one another, a molecule is created. Each atom shares an electron when a bond is formed between them. A molecule is created as a result of a covalent bond.
Molecular solid are defined as composed of atoms or molecules joined by hydrogen bonds, London dispersion forces, and dipole-dipole forces. Solids made of molecules and held together by van der Waals forces are referred to as molecular solids. Examples include carbon dioxide, hydrogen, etc. Crystalline solids include ZnS. The ionic solid MgO is. Diamond is organized in a network.
Thus, dry ice are the molecule which represent molecular solid. Hence option c is correct.
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Your question is incomplete, but probably your complete question was
Which of the following is an example of molecular solid?
a. Zinc sulphide
b. Magnesium oxide
c. Dry ice
d. Diamond
How many oxygen molecules are produced when 3.2×1022 molecules of water decompose?
__H2O à __H2 + __O2
Answer: 1.6x10^22
Explanation: H2O —> H2 + 1/2O2 so half the number of water molecules
What is the Scientific notation for 0.10050
Answer:
1.005 x [tex]10^{1}[/tex]
Explanation:
Sulfur dioxide and oxygen react to form sulfur trioxide during one of the key steps in sulfuric acid synthesis. An industrial chemist studying this reaction fills a 200. mL flask with 3.9 atm of sulfur dioxide gas and 3.2 atm of oxygen gas, and when the mixture has come to equilibrium measures the partial pressure of sulfur trioxide gas to be 1.6 atm. Calculate the pressure equilibrium constant for the reaction of sulfur dioxide and oxygen at the final temperature of the mixture. Round your answer to 2 significant digits.
Answer:
0.20
Explanation:
Step 1: Write the balanced equation
2 SO₂(g) + O₂(g) ⇄ 2 SO₃(g)
Step 2: Make an ICE chart
2 SO₂(g) + O₂(g) ⇄ 2 SO₃(g)
I 3.9 3.2 0
C -2x -x +2x
E 3.9-2x 3.2-x 2x
Step 3: Find the value of x
The partial pressure at equilbrium of SO₃ is 1.6 atm. Then,
2x = 1.6 atm
x = 0.80 atm
Step 4: Calculate the partial pressures at equilibrium
pSO₂ = 3.9-2(0.80) = 2.3 atm
pO₂ = 3.2-0.80 = 2.4 atm
pSO₃ = 1.6 atm
Step 5: Calculate the pressure equilibrium constant
Kp = pSO₃² / pSO₂² × pO₂
Kp = 1.6² / 2.3² × 2.4
Kp = 0.20
Question:
A coefficient is a number listed before a compound or atom, telling how many of the compounds are needed so that the Law of Conservation of Mass is obeyed. Given the information provided, how many iron atoms are there?
4 Fe2S3
Answers:
A.) 4
B.) 12
C.) 8
D.) 2
Answer: I think it’s 4
Explanation:
What is the volume of 67.1g of ethyl alcohol, which has a density of 0.79 g/mL?
Answer:
[tex]84.94\ \text{mL}[/tex]
Explanation:
[tex]m[/tex] = Mass of ethyl alcohol = [tex]67.1\ \text{g}[/tex]
[tex]\rho[/tex] = Density of ethyl alcohol = [tex]0.79\ \text{g/mL}[/tex]
[tex]V[/tex] = Volume of ethyl alcohol
Density is given by
[tex]\rho=\dfrac{m}{V}\\\Rightarrow V=\dfrac{m}{\rho}\\\Rightarrow V=\dfrac{67.1}{0.79}\\\Rightarrow V=84.94\ \text{mL}[/tex]
The volume of ethyl alcohol is [tex]84.94\ \text{mL}[/tex].
Consider the generic Lewis dot symbol for an element. An atom X with three valence electrons. Which element could this symbol represent?
The image having the complete question is attached to this answer.
Answer:
Ga
Explanation:
In order to answer this question well, we must have a good enough knowledge of the periodic table.
We know that the elements in group 3A or group 13 of the periodic table have three valence electrons in their outermost shell.
We just have to look out among the options to notice if there is any member of group 3A or 13.
Gallium is a member of this group. Hence the answer above.
Which change happens during evaporation?
A. A gas turns into a liquid.
B. A liquid turns into a gas.
C. A solid turns into a liquid.
D. A liquid turns into a solid.
Answer:
B.) A Liquid turns into Gas.
Identify each described physical separation technique.
A. A solid mixture is heated. One component transitions directly between solid and gas.
B. A liquid is carefully poured out, leaving the solid behind in the container.
C. A solvent is added to dissolve only one mixture component and then the liquids are separated.
D. A solid is caught on paper or a membrane while the liquid passes through.
Answer:
A. A solid mixture is heated. One component transitions directly between solid and gas ---> Sublimation
B. A liquid is carefully poured out, leaving the solid behind in the container ----> Decantation
C. A solvent is added to dissolve only one mixture component and then the liquids are separated ----> solvent extraction
D. A solid is caught on paper or a membrane while the liquid passes through ---> Filtration using filter paper
Explanation:
A. Sublimation is a process of separating solids which sublimes (solids turning directly to gases) from a a mixture of other solids which do not sublime. When the mixture is heated, the solids which sublime are separated and those which do not are left behind. examples of solids which sublime are naphthalene, Iodine crystals, etc.
B. Decantation is the process of carefully pouring out a liquid from a mixture of it with a solid, leaving the solid behind. Example, a mixture of sand and water where water can be easily decanted, leaving the sand behind.
C. In the process of solvent extraction, a mixture of solids which are soluble in different solvent, one of the components is dissolved in a solvent in which it is soluble while the others are not. The solution is then filtered out and the solid is then separated from the solvent by evaporation.
D. In filtration using a filter paper, the solid-liquid mixture is passed through a filter paper which has pores the size through which liquids can pass through but the solid can not. therefore, the solid remains behind on the paper while the liquid passes through.
A is sublimation, B is decantation, C is solvent extraction, and D is filtration.
Separation of mixturesChemical mixtures are separated in different ways.
A mixture in which one of the components can sublime may be separated using sublimation. The sublime-able component transition from solid straight into gas.A mixture of a liquid plus solid can be decanted if the solid is allowed to settle below the liquid. The liquid can then be decanted off.Solvent extraction has to do with the recovery of a component of a liquid mixture. A solvent is poured into the mixture and the component to be recovered dissolves in the solvent. The liquid is then separated.Filtration is used to separate a mixture consisting of soluble and insoluble components. The insoluble component can be filtered off using a filter paper of suitable pore size.More on separation of mixtures can be found here: https://brainly.com/question/863988
How would you make 5mls of a solution that is 2.0% lactose and 0.1M SPG buffer from separate stock solutions that are 6% lactose and 1M SPG in concentration
Answer:
Check the explanation section.
Explanation:
The following steps should be followed orderly.
STEP ONE:
Use the dilution equation in the calculation of the volume for the stock solution. That is, C1 × V1 = C2 × V2.
Where C1 and C2 are the concentration of the stock solution and the diluted solution.
STEP TWO:
Put 6% of lactose and make sure to dilute it in order to make 2.0% lactose
and put it in Beaker A. Also, make sure to dilute the 1M to 0.1M SPG buffer in Beaker B.
STEP TWO:
Now, from beaker A containing 2% lactose, measure and remove 5.0 mL from it. Also, measure and remove 5.0 mL from beaker B containing 0.1M SPG.
So, in STEP TWO above we won't know how much water we need to use for dilution, thus, there is the need to make use of STEP ONE.
Therefore, from STEP ONE ABOVE, we have the dilution equation given as;
C1 × V1 = C2 × V2.
Hence, 6 × V1 = 2 × 5. Therefore, the volume needed from the stock solution, V1 = (2 × 5)/ 6 = 1.6 mL.
STEP THREE:
Now measure out 1.6 mL from the stock solution, that is 6% lactose and add it to 5mL of the diluted solution of 2% in beaker A into another container, say beaker C and add H2O to form SOLUTION X.
STEP FOUR:
Using the dilution equation again, Determine the the volume that is needed from 1M SPG.
C1 × V1 = C2 × V2.
V1 = ( 0.1 × 5)/ 1 = 0.5mL.
STEP FIVE:
measure 0.5mL out from the 1M SPG and 5 mL out of 0.1M SPG buffer and add water to it to form SOLUTION Y.
STEP SIX:
Now, mix solution X and solution Y together and take the required 5ml
How many grams are in 4.63 x 1024
molecules of CCl4?
Answer:
[tex]m=1,182.8g[/tex]
Explanation:
Hello!
In this case, since the relationship between molecules and mass is first analyzed via the Avogadro's number to compute the moles in the given molecules:
[tex]mol=4.63x10^{24}molec*\frac{1mol}{6.022x10^{23}molec}=7.69mol[/tex]
We now use the molar mass of carbon tetrachloride (153.81 g/mol) to obtain the required grams:
[tex]m=7.69mol*\frac{153.81g}{1mol} \\\\m=1,182.8g[/tex]
Best regards!
Sometimes atoms form molecules by sharing two pairs of valence electrons. When this occurs, the atoms are said to be joined by...
Answer:
A double covalent bond
Explanation:
A double covalent bond is a situation where we have two pairs of electrons shared together between the atoms instead of just one pair. Oxygen gas is an example of a simple molecule that contains double bonds.
In other words, it is a type of chemical bond that has 2 electron pairs shared between two atoms.
7.
How many grams are contained in 3.9 x 1023 sulfur atoms?
atoms → moles
grams
I
Answer: 20.775 g S
Explanation: 3.9x10^23 atoms = 0.648 mol
Atomic mass S = 32.08
S in grams = 20.775
Draw a Lewis structure for H3O+ . Include all hydrogen atoms and show all unshared electrons and the formal charges, if any. Assume that bonding follows the octet rule.
Answer:
In this Lewis equation it can be seen how oxygen and hydrogen have a dative union, that is, there is a proton that is temporarily "borrowed"
Explanation:
This molecule is the same as water but with one more hydrogen, that is why the general charge of the molecule is positive
If I use warm water on my plants then they will grow faster as hot water increases metabolism this is an example of
Answer:
The options are
A. a hypothesis
B. a theory
C. a research question
D. a scientific explanation
The answer is A. a hypothesis
Explanation:
A hypothesis is referred to as a brief explanation on the occurrence of an event.
In the example above using of warm water on plants was inferred to make it grow faster as hot water increases the metabolism.
Which body system or systems are affected by asthma?
Answer:
The lungs
Explanation:
Asthma is a disease that affects the airways of your lungs. With asthma, your airways' lining tends to always be in a hypersensitive state characterized by redness and swelling. Causing the airways to swell and, in severe cases, close completely off.
hope this helps, this should also probably be in biology:)
How can you make an item that is made of magnetic material become a permanent magnet instead of a temporary magnet? *.
Answer:
You can heat it and then let it cool it in a very strong magnetic field.
It can be heated and then allowed to cool in a very powerful magnetic field. To make an item that is made of magnetic material become a permanent magnet instead of a temporary magnet.
What is magnetic field ?The magnetic influence on moving electric charges, electric currents, and magnetic materials is described by a magnetic field, which is a vector field. A force perpendicular to the charge's own velocity and the magnetic field acts on it when the charge is travelling through a magnetic field.
Heating a ferromagnetic material to a crucially high temperature is the primary method for producing permanent magnets. Although the temperature varies depending on the type of metal, it has the effect of aligning and "fixing" the magnet's domains in place over time.
Electric charges in motion are what generate magnetism. The smallest building blocks of matter are called atoms. Each atom contains electrons, which are tiny particles with electric charges.
Thus, It can be heated and then allowed to cool in a very powerful magnetic field.
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Find the atomic mass unit of Silicon-28, Silicon-29, Silicon-30 with masses of 27.977, 28.976, 29.974, respectively.
Answer:
28.085
Explanation:
The formular to obtain average atomic mass unit from isotopes is given as;
sum of (Percentage abundance * Atomic mass) of all isotopes = Average atomic mass unit
Silicon 28 = 92.23%
Silicon 29 = 4.67%
Silicon 30 = 3.1%
(92.23 / 100 * 27.977) + (4.67 / 100 * 28.976) + (3.1 / 100 * 29.974) = Average atomic mass
Average atomic mass = 25.803 + 1.353 + 0.929 = 28.085
Which number should go in the blank?
- H₂ + O2 -> 2H₂O
O
2
3
1
Smallest particle of a substance that can retain its properties & is
composed of one or more atoms *
O A. Atom
O B. Molecules
O C. Matter
O D. Everything
Answer:
Molecules
Explanation:
What is the density of lead (in g/cm^3 3 ) if a rectangular bar measuring 0.500 cm in height, 1.55 cm in width, and 25.00 cm in length has a mass of 220.9 g? Report the answer with the units of g/cm^3 3 and the proper number of significant figures. Numbers in bold count towards significant figures. Type your answer here with correct significant figures and units:
Answer:
Density = 11.4 g/cm³
Explanation:
Given data:
Density of lead = ?
Height of lead bar = 0.500 cm
Width of lead bar = 1.55 cm
Length of lead bar = 25.00 cm
Mass of lead bar = 220.9 g
Solution:
Density = mass/ volume
Volume of bar = length × width × height
Volume of bar = 25.00 cm × 1.55 cm × 0.500 cm
Volume of bar = 19.4 cm³
Density of bar:
Density = 220.9 g/ 19.4 cm³
Density = 11.4 g/cm³
In 42 hrs, 4.32 g of argon-35 decay to leave only 0.54 g. What is the half-life of argon-
35?
o 21 hrs
O 7 hrs
O 84 hrs
14 hrs
Answer:
14 hrs.
Explanation:
From the question given above, the following data were obtained:
Time (t) = 42 hrs
Original amount (N₀) = 4.32 g
Amount remaining (N) = 0.54 g
Half-life (t½) =…?
Next, we shall determine number of half-lives required for 4.32 g of the isotope to decay to 0.54 g. This can be obtained as follow:
Original amount (N₀) = 4.32 g
Amount remaining (N) = 0.54 g
Number of half-lives (n) =?
N = 1/2ⁿ × N₀
0.54 = 1/2ⁿ × 4.32
Cross multiply
0.54 × 2ⁿ = 4.32
Divide both side by 0.54
2ⁿ = 4.32 / 0.54
2ⁿ = 8
Express 8 in index form with 2 as the base
2ⁿ = 2³
n = 3
Thus, it took 3 half lives for 4.32 g of the isotope to decay to 0.54 g.
Finally, we shall determine the half-life of the isotope. This can be obtained as follow:
Time (t) = 42 h
Number of half-lives (n) = 3
Half-life (t½) =
n × t½ = t
3 × t½ = 42
Divide both side by 3
t½ = 42 / 3
t½ = 14 hrs
Thus, the half-life of the isotope is 14 hrs
4.00 g of a certain Compound X, known to be made of carbon, hydrogen and perhaps oxygen, and to have a molecular molar mass of 152. gimol, is burned completely in excess oxygen, and the mass of the products carefully measured:
product mass
carbon dioxide 5.79 g
water 2.84 g
Use this information to find the molecular formula of X.
Answer:
C₄H₁₀O₄
Explanation:
From the question given above, the following data were obtained:
Mass of compound = 4 g
Molar mass of compound = 152 g/mol
Mass of CO₂ = 5.79 g
Mass of H₂O = 2.84 g
Molecular formula of compound X =?
Next, we shall determine the mass of Carbon, Hydrogen and Oxygen in the compound. This can be obtained as follow:
For Carbon (C):
Mass of CO₂ = 5.79 g
Molar mass of CO₂ = 12 + (2×16) = 44 g/mol
Mass of C = 12/44 × 5.79
Mass of C = 1.58 g
For Hydrogen (H):
Mass of H₂O = 2.84 g
Molar mass of H₂O = (2×1) + 16 = 18 g/mol
Mass of H = 2/18 × 2.84
Mass of H = 0.32 g
For Oxygen (O):
Mass of C = 1.58 g
Mass of H = 0.32 g
Mass of compound = 4 g
Mass of O =?
Mass of O = (Mass of compound) – (Mass of C + Mass of H)
Mass of O = 4 – (1.58 + 0.32)
Mass of O = 4 – 1.9
Mass of O = 2.1 g
Next, we shall determine the empirical for compound X. This can be obtained as follow:
C = 1.58 g
H = 0.32 g
O = 2.1 g
Divide by their molar mass
C = 1.58 / 12 = 0.13
H = 0.32 / 1 = 0.32
O = 2.1 / 16 = 0.13
Divide by the smallest
C = 0.13 / 0.13 = 1
H = 0.32 / 0.13 = 2.46
O = 0.131 / 0.13 = 1
Multiply by 2 to express in whole number
C = 1 × 2 = 2
H = 2.46 × 2 = 5
O = 1 × 2 = 2
Thus, the empirical formula for the compound is C₂H₅O₂
Finally, we shall determine the molecular formula for the compound. This can be obtained as follow:
Molar mass of compound = 152 g/mol
Empirical formula => C₂H₅O₂
Molecular formula =?
Molecular formula => [C₂H₅O₂]ₙ
[C₂H₅O₂]ₙ = 152
[(2×12) + (5×1) + (2×16)]n = 152
[24 + 5 + 32]n = 152
61n = 152
Divide both side by 61
n = 152 / 61
n = 2
Molecular formula => [C₂H₅O₂]₂
Molecular formula => C₄H₁₀O₄