A graph titled Position versus time for with horizontal axis time (seconds) and vertical axis position (meters). A straight blue line runs with an upward slope from 0 seconds 3 meters to 4 seconds 15 meters.
The starting position of this object is
[___] m.

The object is traveling at a velocity of
[___] m/s.

Answers

Answer 1

Answer:

The starting position of this object is

3m.

The object is traveling at a velocity of

3m/s.

Answer 2

Answer:

it never moved (c or 3)

Explanation:

np


Related Questions

Dominic has a brain injury. Why is this MOST likely to be a serious injury?

Answers

If Dominic has a brain injury, then he must have sustained a serious injury.

Functions of the brain

The brain coordinates all the activities in the body such as speech, locomotion, coordination and intelligence. This makes the brain the master point of control in the body.

Brain injury

Whenever there is an injury to the brain, various parts of the body could be affected. Functions such as speech, locomotion and general coordination may become largely impaired.

Therefore, if Dominic has a brain injury, then he must have sustained a serious injury.

Learn more about the brain: https://brainly.com/question/5361122

the amplitude of an oscillator decreases to 36.8% of its initial value in 10.0 s. what is the value of the time constant

Answers

Answer:

τ = 5 s

Explanation:

When a vibrating body is damped. Its amplitude starts to decrease. This decrement is exponential. And it is given as follows:

[tex]X = X_{0}e^{-\frac{t}{2\tau}[/tex]

where,

τ = Time Constant = ?

X = Instantaneous value of amplitude

X₀ = Initial Value of amplitude

t = time interval = 10 s

The ratio of decrement is given as:

[tex]\frac{X}{X_0} = 36.8\% = 0.368[/tex]

therefore, using these values, we get:

[tex]\frac{X}{X_{0}} = 0.368 = e^{\frac{10\ s}{2\tau}}[/tex]

Taking natural log (ln) on both sides, we get:

[tex]ln(0.368) = \frac{10\ s}{2\tau}\\\\\tau = \frac{10\ s}{2ln(0.368)}[/tex]

τ = 5 s

The value of the time constant for the decrease in the amplitude of this oscillator is 5.

Given the following data:

Decrease in amplitude = 36.8% = 0.368Time = 10.0 seconds.

To determine the value of the time constant:

Mathematically, the amplitude for damped harmonic motion is given by the formula:

[tex]X = X_o e^\frac{t}{2 \tau}[/tex]

Where:

t is the time.[tex]\tau[/tex] is the time constant.X is the instantaneous value of amplitude.[tex]X_o[/tex] is the initial value of amplitude.

Rearranging the formula, we have:

[tex]\frac{X}{X_o} = e^{-\frac{t}{2 \tau}}[/tex]

Substituting the given parameters into the formula, we have;

[tex]0.368 = e^\frac{-10}{2 \tau}\\\\ln(0.368) = \frac{-10}{2 \tau}\\\\-0.9997 = \frac{-10}{2 \tau}\\\\2 \tau \times -0.9997 = 10\\\\-1.9994\tau=-10\\\\\tau =\frac{-10}{-1.9994} \\\\\tau = 5.0[/tex]

Time constant = 5

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An object in static equilibrium has a coefficient of static friction as 0.110. If the normal force acting on the object is 95.0 newtons, what is the mass of the object? A. 9.70 kilograms B. 10.5 kilograms C. 85.3 kilograms D. 95.0 kilograms E. 1.00 × 102 kilograms

Answers

Answer:

9.70 kilograms

Explanation:

I got a 100% on my test

The mass of the object is 9.7 kg. Option (A) is correct.

What is normal force?

Every day, we experience the normal force. For instance, when a book is placed on a table, the usual response force prevents the book from falling through the table, even though gravity is pulling the book downward. That implies that there is a force acting to push it upward. The word "normal force" refers to the force. Normal in this context refers to being perpendicular to the ground.

Given parameters:

the normal force acting on the object is: N =  95.0 newtons.

coefficient of static friction: μ = 0.110.

We have to find mass of the object: m = ?

We know that:

Normal force = weight of the object

⇒ N = mg

⇒ m = N/g = 95.0/9.8 kg = 9.7 kg

Hence, the mass of the object be 9.7 kg.

Learn more about normal force here:

https://brainly.com/question/13340671

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. A ventilation fan has blades 0.25 m long rotating at 20 rpm (revolutions per minute). What is the centripetal acceleration of a point on the outer tip of a blade

Answers

Answer:

The centripetal acceleration of a point on the outer tip of a blade is 1.097 m/s²

Explanation:

Given;

length of the fan blade, r = 0.25 m

angular speed = 20 rpm

The angular speed in rad/s is given as;

[tex]\omega = \frac{20 \ rev}{ \ \ \min} \ \times \ \frac{2\pi}{1 \ rev} \ \times \ \frac{1 \ \min}{60s} = 2.095 \ rad/s \\\\[/tex]

The centripetal acceleration of a point on the outer tip of a blade is given as;

[tex]\alpha_c = \frac{v^2}{r} = \omega ^2r[/tex]

[tex]\alpha _c = (2.095)^2(0.25)\\\\\alpha _c =1.097 \ m/s^2[/tex]

Therefore, the centripetal acceleration of a point on the outer tip of a blade is 1.097 m/s²

Answer:

The centripetal acceleration = [tex]1.1m/s^2[/tex]

Explanation:

Given

[tex]rpm = 20[/tex]

therefore,

[tex]20rpm = \frac{20*2\pi}{60}\\\\=2.1 rad/s = w[/tex]

From,

[tex]V = rw\\\\V = 0.25 * 2.1\\\\V = 0.525m/s[/tex]

Centripetal acceleration,

[tex]a_c = \frac{V^2}{r}\\\\a_c = \frac{0.525^2}{0.25}\\\\a_c = 1.1m/s^2[/tex]

For more information centripetal acceleration, visit

https://brainly.com/subject/physics

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