A group of 59 randomly selected students have a mean score of 29.5 with a standard deviation of 5.2 on a placement test. What is the​ 90% confidence interval for the mean​ score, ​, of all students taking the​ test?

Answers

Answer 1

Answer:

29.5+/-1.11

= ( 28.39, 30.61)

Therefore, the 90% confidence interval (a,b) =( 28.39, 30.61)

Step-by-step explanation:

Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.

The confidence interval of a statistical data can be written as.

x+/-zr/√n

Given that;

Mean x = 29.5

Standard deviation r = 5.2

Number of samples n = 59

Confidence interval = 90%

z-value (at 90% confidence) = 1.645

Substituting the values we have;

29.5+/-1.645(5.2/√59)

29.5+/-1.645(0.676982337100)

29.5+/-1.113635944529

29.5+/-1.11

= ( 28.39, 30.61)

Therefore, the 90% confidence interval (a,b) =( 28.39, 30.61)


Related Questions

Can someone help pls !

Answers

Answer:

(B). [tex]A_{y}[/tex] = [tex]\left[\begin{array}{cc}12&7\\17&-51\end{array}\right][/tex]

Step-by-step explanation:

12x - 13y = 7

17x - 22y = - 51

A = [tex]\left[\begin{array}{cc}12&-13\\17&-22\end{array}\right][/tex]

[tex]A_{x}[/tex] = [tex]\left[\begin{array}{cc}7&-13\\-51&-22\end{array}\right][/tex]

[tex]A_{y}[/tex] = [tex]\left[\begin{array}{cc}12&7\\17&-51\end{array}\right][/tex]

A manufacturer of handcrafted wine racks has determined that the cost to produce x units per month is given by C=0.3X^2+8,000. How fast is the cost per month changing when production is changing at the rate of 14 units per month and the production level is 70 UNITS?


Costs are ___ at the rate of $___ per month at this production level.

Answers

Answer:

Costs are changing at the rate of $588 per month at this production level.

Step-by-step explanation:

From the question, we have:

C = 0.3X^2 + 8,000 ........................ (1)

Differentiating equation (1) with respect to time, t, we have:

dC/dt = (0.3 * 2) X (dX/dt)....................... (2)

Where;

X = 70

dX/dt = 14

Substituting this into equation (2), we have:

dC/dt = (0.3 * 2) * 70 * 14

dC/dt = 588

This implies that costs are changing at the rate of $588 per month at this production level.

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