A group of 6 friends rent a cabin on a campsite. It costs $62.88 to rent the cabin. if they divide the cost evenly between them, how much does each friend need to pay?

Answer:

C. Both statements are true

The rate of growth will she need to achieve her goal is 2.8%

The formula for finding the compound amount is expressed as:

[tex]A =P(1+\frac{r}{n} )^{nt}[/tex]

P is the amount invested = $25000

t is the time in years = 25 years

A is the amount = $125000

r is the rate in %

Substitute the given parameters into the formula to have:

[tex]125000 =25000(1+r )^{25}\\5 =(1+r)^{25}\\log5=25log(1+r)\\log(1+r)=\frac{log5}{25} \\log(1+r)=0.02796\\1+r = e^{0.02795}\\1+r=1.0283\\r = 1.0283 -1\\r = 0.0283\\[/tex]

Hence the rate of growth will she need to achieve her goal is 2.8%

Learn more about compound amount here: https://brainly.com/question/18442810

Answer:

Step-by-step explanation:

(f/g)(-4) = (-4² - 13) / (4 - (-4)) = 3/8

Answer:

Your equation option is possibly in here somewhere.

Step-by-step explanation:

A = C - 2

B = A + 6  → A = B - 6

C - 2 = A = B - 6 → B = C + 4

44 = C + B + A

44 = C + (C + 4) + (C - 2)

44 = 3C + 2

42 = 3C

C = 7

Answer:

Ok, so I think it's x= 2.5 and y= 306.1 plz forgive me if I'm wrong.

Answer:

[tex]L=\frac{1}{2}P-W[/tex]

Step-by-step explanation:

Let's solve for L.

[tex]P=2L+2W[/tex]

Step 1: Flip the equation.

[tex]2L+2W=P[/tex]

Step 2: Add [tex]-2W[/tex] to both sides.

[tex]2L+2W+-2W=P+-2W[/tex]

[tex]2L=P-2W[/tex]

Step 3: Divide both sides by [tex]2[/tex].

[tex]\frac{2L}{2}=\frac{P-2W}{2}[/tex]

[tex]L=\frac{1}{2}P-W[/tex]

Answer:

[tex]L=\frac{1}{2}P-W[/tex]

Answer:

23

Step-by-step explanation:

the median is the "Middle" number of the set.21 and 25 are the middle numbers of the set. so now find the middle of 21 and 25.

21 22 23 24 25

23 is the median of the data set

Answer:

expression.

2(4x+3y)

2(4(4)+3(7))

2(16+21)

2( 37)

74

Answer:

C. y=3x-4

Step-by-step explanation:

I just know trust me

[tex]\\ \sf\longmapsto {\displaystyle{\lim_{x\to 1}}}\dfrac{x^2-1}{x-1}[/tex]

[tex]\\ \sf\longmapsto {\displaystyle{\lim_{x\to 1}}}\dfrac{x^2-1^2}{x-1}[/tex]

[tex]\\ \sf\longmapsto 2(1)^(2-1)[/tex]

[tex]\\ \sf\longmapsto 2(1)[/tex]

[tex]\\ \sf\longmapsto 1[/tex]

Step-by-step explanation:

[tex] \tt \lim \limits_{x \to1} \frac{ {x}^{2} - 1 }{x - 1} = ...[/tex]

[tex] = \tt \lim \limits_{x \to1} \frac{(x + 1) \cancel{(x - 1)}}{ \cancel{(x - 1)}} [/tex]

[tex] = \tt \lim \limits_{x \to1}(x + 1)[/tex]

[tex] = \tt1 + 1[/tex]

[tex] = \boxed{ \bold{ \blue{ \underline2}}}[/tex]

Answer:

Step-by-step explanation:

[tex]d(t)=(t^2+3)e^\frac{-1}{2} \\d'(t)=2t e^{-\frac{1}{2} }\\it~ is~ increasing ~if~d'(t)>0\\e^{-\frac{1}{2} } =\frac{1}{e^\frac{1}{2} } >0\\so~t>0\\and~decreasing~if~t<0\\[/tex]

so it is concave upward at t=0

Answer:

Step-by-step explanation:

opposite corners first, then adjacent corners, and so on

Answer:

8

Step-by-step explanation:

Add 5 and 3

-Lexi

Answer: No solution

The two lines don’t meet at any point(s). So, there are no solutions.

:)

Hello there!

We are given two points.

We use the following formula:

[tex]\frac{y2-y1}{x2-x1}[/tex]

[tex]\frac{4-7}{0-(-1)}[/tex]

[tex]\frac{4-7}{0+1} \\\frac{-3}{1} \\-3[/tex]

So the slope is -3. Hope it helps!

~Just a cheerful teen

#CarryOnLearning

[tex]SilentNature[/tex]

Answer:

[tex]\boxed{\boxed{\sf Slope: -3}}[/tex]

Step-by-step explanation:

To find the slope of a line given the coordinates of two points on the line, use the slope formula.

[tex]\boxed{\sf {Slope}=\cfrac{y_2-y_1}{x_2-x_1}}[/tex]

x1 and y1 are the coordinates of the first point. The second point's coordinates are x2, y2.

[tex]\sf Points: \left(-1,\:7\right)\: and\: \left(0,\:4\right)[/tex]

[tex]\boxed{\sf \left(x_1,\:y_1\right):\left(-1,\:7\right)}[/tex]

[tex]\boxed{\sf \:\left(x_2,\:y_2\right):\left(0,\:4\right)}[/tex]

[tex]\longmapsto\sf slope\:(m)=\cfrac{4-7}{0-\left(-1\right)}[/tex]

[tex]\longmapsto\sf slope\:(m)=-3[/tex]

_________________________________

Using the binomial distribution, it is found that:

a) There is a 0.0501 = 5.01% probability that you need to contact four people.

b) You expect to contact 1.82 students until you find one who lives within five miles of you.

c) The standard deviation is of 1.22 students.

d) 0.3369 = 33.69% probability that 3 of them live within five miles of you.

e) It is expected that 2.75 students live within five miles of you.

For each student, there are only two possible outcomes. Either they live within 5 miles of you, or they do not. The probability of a student living within 5 miles of you is independent of any other student, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

The parameters are:

In this problem:

Item a:

This probability is P(X = 0) when n = 3(none of the first three) multiplied by 0.55(the fourth does live within five miles), hence:

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 0) = C_{3,0}.(0.55)^{0}.(0.45)^{3} = 0.091125[/tex]

[tex]p = 0.091125(0.55) = 0.0501[/tex]

0.0501 = 5.01% probability that you need to contact four people.

Item b:

The expected number of trials in the binomial distribution until q successes is given by:

[tex]E = \frac{q}{p}[/tex]

In this problem, [tex]p = 0.55[/tex], and 1 trial, thus [tex]q = 1[/tex], hence:

[tex]E = \frac{1}{0.55} = 1.82[/tex]

You expect to contact 1.82 students until you find one who lives within five miles of you.

Item c:

The standard deviation of the number of trials until q successes are found is given by:

[tex]S = \frac{\sqrt{q(1 - p)}}{p}[/tex]

Hence:

[tex]S = \frac{\sqrt{0.45}}{0.55} = 1.22[/tex]

The standard deviation is of 1.22 students.

Item d:

This probability is P(X = 3) when n = 5, hence:

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 3) = C_{5,3}.(0.55)^{3}.(0.45)^{2} = 0.3369[/tex]

0.3369 = 33.69% probability that 3 of them live within five miles of you.

Item e:

The expected value of the binomial distribution is:

[tex]E(X) = np[/tex]

Hence:

[tex]E(X) = 5(0.55) = 2,75[/tex]

It is expected that 2.75 students live within five miles of you.

A similar problem is given at https://brainly.com/question/25343741

Answer:

C. X=4

Step-by-step explanation:

Answer:

Step-by-step explanation:

Today only, a sofa is being sold at a 32% discount. The sale price is $289.

What was the price yesterday?

289 is 68%                          (100% - 32% = 68%)

289 : 68 * 100 =

425

--------------------------

check

425 - 32% = 289

the answer is good

Answer:

[tex]\sf k + 6 > -37[/tex]

[tex]\sf k+6-6>-37-6[/tex]

[tex]\boxed{\sf k>-43}[/tex]

Answer:

Subtract 6 from both sides:

K +6 - 6 > - 37 - 6

Simplify the arithmetic:

k > - 37 - 6

Simplify the arithmetic

k > - 43

Answer:

its the last one i think

Step-by-step explanation:

.

Answer:

$1343

Step-by-step explanation:

The equation would be

x= 1580 (1-0.15)

x represents how much he actually pays.

1-0.15=0.85.

1580×0.85=1343

9514 1404 393

Answer:

Step-by-step explanation:

In this context, "per" and "for" mean "divided by."

Answer:

Step-by-step explanation:

9514 1404 393

Answer:

  (b)  9

Step-by-step explanation:

Maybe you want to simplify ...

  [tex]\sqrt{81}=\sqrt{9^2} =\boxed{9}[/tex]

[tex]\\ \sf\longmapsto tan28=\dfrac{BC}{AC}[/tex]

[tex]\\ \sf\longmapsto 0.5317=\dfrac{BC}{29.3}[/tex]

[tex]\\ \sf\longmapsto BC=29.3(0.5317)[/tex]

[tex]\\ \sf\longmapsto BC=15.5mi[/tex]

Now

[tex]\\ \sf\longmapsto AB^2=29.3^2+15.5^2[/tex]

[tex]\\ \sf\longmapsto AB^2=848.49+240.25[/tex]

[tex]\\ \sf\longmapsto AB^2=1088.74[/tex]

[tex]\\ \sf\longmapsto AB=32.9mi[/tex]

1. -40 - 180 = -220

2. -40 - 175 = -135

3. -40 - 185 = -225

4. 2:15 = -40

2:18 = 185

distance b/w them is = -40 - 185 = - 225

hope this answer helps you dear! btw I'm not sure but hope so this helps...!!

I agree with the first person that answered.

Answer:

161oz = 10.0625 (then you round)

Step-by-step explanation:

Therefore the percentage increase is 72