Answer:
The wavelength of the waves on the string is found using v = λf:
λ = v/f = 315/370 = 0.85135m
The first harmonic (fundamental) standing wave formed on the string has nodes only at the ends (see diagram in link) so:
String length = λ/2 = 0.85135/2 = 0.426m (to 3 sig. figs.)
unit 3 test waves sps4 physics need all answers
Answer:
What is the question on the testtt
2. What is the total effect of sound produced in an enclosed space called?
Acoustics
Overtones
sound quality
Color
Answer:
Acoustics
Explanation:
You have been called as an expert witness for a trial in which a driver has been charged with speeding but is claiming innocence. He claims to have slammed on his brakes to avoid rear-ending another car, but tapped the back of the other car just as he came to rest. You have been hired by the prosecution to prove that the driver was indeed speeding. You have received data as follows from the police: skid marks left by the driver are 60.0 m long and the roadway is level. Tires matching those on the car of the driver have been dragged over the same roadway to determine that the coefficient of kinetic friction between the tires and the roadway is 0.620 at all points along the skid mark. The speed limit on the road is 35 mi/h. Construct an argument to be used in court to show that the driver was indeed speeding. (Enter the speed of the driver, in mi/h, just before braking.)
Answer:
v₀ = 60.38 mi / h
Explanation:
For this exercise let's start by using Newton's second law
Y axis
N-W = 0
N = W
X axis
fr = m a
the expression for the friction force is
fr = μ N
we substitute
μ mg = m a
μ g = a
calculate us
a = 0.620 9.8
a = 6.076 m / s²
now we can use the kinematics relations
v² = v₀² - 2 a x
suppose v = 0
v₀ = [tex]\sqrt{2ax}[/tex]
let's calculate
v₀ = [tex]\sqrt{2 \ 6.075 \ 60.0}[/tex]
v₀ = 27.00 m / s
let's slow down to the english system
v₀ = 27.0 m / s (3.28 ft / 1m) (1 mile / 5280 ft) (3600s / 1h)
v₀ = 60.38 mi / h
With this stopping distance, the starting speed should have been 60.38, which is much higher than the maximum speed allowed.
If 0.5 A is flowing through a household light
bulb and the bulb is plugged into a 120 V
outlet, what is the bulb’s power output?
Answer:
60W
Explanation:
P=IV=0.5x120
P =60W
Which conversion can take place in a transformer
A. An electric current into a magnetic field
B. Electric energy into mechanical energy
C. Mechanical energy into electric energy
D. A lower voltage into a higher voltage
Answer:
D. A lower Voltage into a higher
Which performers can benefit from a protein-rich diet?
A. Tennis players, golfers
B. Swimmers, footballers
C. 3000m runner, long-distance runner
D. Weight lifters, Sprinters
Answer:
in my opinion its A
Explanation:
A 14.6 g mass is attached to a horizontal spring with a spring constant of 15.7 N/m and released from rest with an amplitude of 29.8 cm. What is the speed of the mass when it is halfway to the equilibrium position if the surface is frictionless
Answer:
v = 8.46 m/s
Explanation:
Given that,
Mass of the object, m = 14.6 g
Spring constant of the spring, k = 15.7 N/m
It is released from rest with an amplitude of 29.8 cm.
We need to find the speed of the mass when it is halfway to the equilibrium position if the surface is frictionless.
We can use the conservation of energy in this case. Let v be the speed of the mass. So,
[tex]EPE_i=\dfrac{1}{2}mv^2+EPE_f\\\\\dfrac{1}{2}kx_i^2=\dfrac{1}{2}mv^2+\dfrac{1}{2}kx_f^2[/tex]
Substitue all the values in the above expression.
[tex]\dfrac{1}{2}\times 15.7\times (0.298)^2=\dfrac{1}{2}\times 0.0146\times v^2+\dfrac{1}{2}\times 15.7\times (\dfrac{0.298}{2})^2\\\\v=8.46\ m/s[/tex]
So, the speed of the mass is equal to 8.46 m/s.
HELP ASAP PLEASE Comparing the types and amounts of EM radiation in an object could help scientists determine an object's what? structure age chemical composition all of the above are correct
Answer: Its all of the above
Explanation:
I had the same question and got it correct
A 50 kg crateis being pushed on a horizontal floor at constant velocity. Given that the coefficient of kenitic friction between crate and floor is hk= 0.1, what is push force f ( friction)?
Mike is deciding which route to take to the beach. If he takes the highway, he can travel at an average velocity of 100 km/hr for 17 km. If he takes surface streets, he can travel at an average velocity of 70 km/hr for 10 km. Which is the faster route for Make to take?
Answer: Highway
Explanation:
The sum of the initial and final velocity is divided by 2 to find the average. The average velocity calculator uses the formula that shows the average velocity (v) equals the sum of the final velocity (v) and the initial velocity (u), divided by 2.
Question number 11 how did we found the answer ?
Answer:
Option A. 57.14 Ω
Explanation:
From the question given above, the following data were obtained:
Resistor 1 (R₁) = 100 Ω
Resistor 2 (R₂) = 400 Ω
Resistor 3 (R₃) = 200 Ω
Equivalent Resistor (Rₚ) =?
The equivalent resistor in the above circuit can be obtained as follow:
1/Rₚ = 1/R₁ + 1/R₂ + 1/R₃
1/Rₚ = 1/100 + 1/400 + 1/200
Find the least common multiple (lcm) of 100, 400 and 200. The result is 400. Divide 400 by 100, 200 and 400 respectively and multiply the result with the numerator as shown
1/Rₚ = (4 + 1 + 2)/400
1/Rₚ = 7/400
Invert
Rₚ = 400/7
Rₚ = 57.14 Ω
Which graph shows acceleration? A graph of position (meters) versus time (seconds) has a straight line running from 0 seconds 0 meters upward. A graph of position (meters) versus time (seconds) has a concave line running from 0 seconds 0 meters upward. A graph of position (meters) versus time (seconds) has a straight line running from 0 seconds positive number of meters downward to some later time 0 meters.
It's the one that has a concave line running upward.
Answer:
its the middle one
Explanation:
i did it on edge 2021
suppose you and your two lab partners each read the volume of a sample of ñiquid in a graduate cylinder the three measurements you come up with are 211 mL,212mL and 212ML. the teacher tells you that the actual volume of the sample is 211 mL which of the following best describes your results?
A.neither accurate nor precise
B. Precise but not accurate
C.accurate but not precise
D.both accurate and precise
I need help please
calculate the tension in a horizontal string that whirls a 2kg toy in a circle of radius 2.5 meters when it moves 3m/s on icy surface
Answer:
The tension in the horizontal string is 7.2 N
Explanation:
With the assumption that the ice surface has no friction, the tension in the horizontal string is equal to the centripetal force, 'F', acting on the string to keep it in circular motion
[tex]The \ centripetal \ force, \ F = m \times \dfrac{v^2}{r}[/tex]
Where;
m = The mass of the object in the circular
v = The tangential velocity of the object
r= The radius of the circle through whose path the object is moved
The given parameters are;
The mass of the toy that is whirled in a circle by the string, m = 2 kg
The radius of the circle the toy's path turns, r = 2.5 meters
The velocity of the toy at the instant the tension is sought, v = 3 m/s
Therefore, we get;
[tex]The \ centripetal \ force, \ F = 2 \, kg \times \dfrac{(3 \, m/s)^2}{2.5 \, m} = 7.2 \, N[/tex]
The centripetal force, F = 7.2 N = The tension in the horizontal string
∴ The tension in the horizontal string = 7.2 N.
The heat of fusion of copper is 205000 J/kg. What is the mass of a copper rod that takes 4950000000 J of energy to melt the rod. Be sure to put the correct unit at the end of your answer and also for your final answer, place your final numbers two places after the decimal and round.
Answer:
m = 24146.34 kg
Explanation:
The heat of fusion is defined as the amount of heat required to melt a unit mass of a substance completely. Hence, it can be calculated by the following formula:
[tex]H = \frac{Q}{m}\\\\m = \frac{Q}{H}[/tex]
where,
m = mass of copper = ?
Q = Heat absorbed by rod = 4950000000 J
H = Heat of fusion of copper = 205000 J/kg
Therefore,
[tex]m = \frac{4950000000\ J}{205000\ J/kg}[/tex]
m = 24146.34 kg
two resistors, 5.0 ohm's each can be combined to give an equivalent resistance of
Answer:
2 possible answers:
1# 2.5 Ω (when the resistors are in parallel)
2# 10 Ω (when the resistors are in series)
Explanation:
there are two possible answers for this:
1# if the resistors are in parallel in the circuit
then:
1/R-equivalent=1/5+1/5
1/R-equivalent=2/5
R-equivalent=5/2=2.5 Ω
2# if the resistors are in series in the circuit
then:
R-equivalent=5+5
R-equivalent=10 Ω
Two resistors, 5.0 ohm's each can be combined to give an equivalent resistance of
If connected in series :
R = R1 + R2
R = 5 + 5
R = 10 ohms
If connected in parallel :
R = 1/R1 + 1/R2
R = 1/ 5 + 1/5
= 2 / 5
= 2.5 ohms
What is equivalent resistance ?
"The equivalent resistance is where the aggregate resistance connected either in parallel or series is calculated." Essentially, the circuit is designed either in Series or Parallel. Electrical resistance shows how much energy one needs when you move the charges/current through your devices.
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pedro uses a bar magnet to pick up a nail. He then
touches the tip of the nail to some staples.
Why do some of the staples stick to the nail?
The nail and the bar magnet are now both permanent
magnets.
The nail has become a temporary magnet, while the
bar magnet remains a permanent magnet.
O The nail has become a permanent magnet, while the
bar magnet has become a temporary magnet.
The nail and the bar magnet are now both temporary
magnets.
Answer:
B
Explanation:
bababooey
B) The nail has become a temporary magnet, while the bar magnet remains a permanent magnet.
What is single touch method of making a magnet?Single touch method is one of various ways of making a magnetic material like soft iron into a magnet.
In this method one end of the magnet (say north pole) is placed at one end of the iron piece and then rubbed over the bar from end to other, then lifted and brought back to first end.
According to the question,
The nail will stick to the bar magnet because it will become magnetized. The presence of the nearby north pole rearranges the magnetic domains inside the steel so that their south poles all point toward the north pole of the permanent magnet.
As a result, the other end of the nail becomes a north pole.
If you bring a bar magnet close to the first iron nail, you can lift the the first iron nail with the magnet and also it will attract and lift the second iron nail.
To attract or even lift the third magnet will depend on the distance.
Hence , the nail has become a temporary magnet, while the bar magnet remains a permanent magnet.
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Suppose you design an apparatus in which a uniformly charged disk of radius R is to produce an electric field. The field magnitude is most important along the central perpendicular axis of the disk, at a point P at distance 2.00R from the disk. Cost analysis suggests that you switch to a ring of the same outer radius R but with inner radius R/2.00 . Assume that the ring will have the same surface charge density as the original disk. If you switch to the ring, by what percentage will you decrease the electric field magnitude at P?
Answer:
The electric field will be decreased by 29%
Explanation:
The distance between point P from the distance z = 2.0 R
Inner radius = R/2
Outer raidus = R
Thus;
The electrical field due to disk is:
[tex]\hat {K_a} = \dfrac{\sigma}{2 \varepsilon _o} \Big( 1 - \dfrac{z}{\sqrt{z^2+R_i^2}} \Big)[/tex])
[tex]\implies \dfrac{\sigma}{2 \vaepsilon _o} \Big ( 1 - \dfrac{2.0 \ R}{\sqrt{ (2.0\ R)^2+(R)^2}} \Big)[/tex]
Similarly;
[tex]\hat {K_b} = \hat {k_a} - \dfrac{\sigma}{2 \varepsilon_o} \Big( 1 - \dfrac{2.0 \ R}{\sqrt{(2.0 \ r)^2 + (\dfrac{R}{2}^2)}}\Big)[/tex]
However; the relative difference is: [tex]\dfrac{\hat {k_a} - \hat {k_b}}{\hat {k_a} }= \dfrac{E_a -E_a + \dfrac{\sigma}{2 \varepsilon_o \Big[1 - \dfrac{2.0 \ R}{\sqrt{(2.0 \ R)^2 + (\dfrac{R}{2})^2}} \Big] } } { \dfrac{\sigma}{2 \varepsilon_o \Big [ 1 - \dfrac{2.0 \ R}{\sqrt{ (2.0 \ R)^2 + (R)^2}} \Big] }}[/tex]
[tex]\dfrac{\hat {k_a} - \hat {k_b}}{\hat {k_a} }= \dfrac{1 - \dfrac{2.0}{\sqrt{(2.0)^2 + \dfrac{1}{4}}} }{1 - \dfrac{2.0 }{\sqrt{(2.0)^2 + 1}}}[/tex]
[tex]= 0.2828 \\ \\ \mathbf{\simeq 29\%}[/tex]
A car goes down a straight, horizontal road at 24.0 m/s. How many minutes will the car take to travel 18.0 km? (a) 10.0 min I (b) 7.20 min (C) 22.2 min (d) 12.5 min
Answer:
D. 12.5 min
Explanation:
Speed = distance ÷ time.
time = distance ÷ speed.
18km × 1000m = 18000m (as speed is in m/s).
time = 18000m ÷ 24.0m/s
t = 750s.
750s ÷ 60
= 12.5mins is your answer.
hope this helps. :)
What is the wavelength associated with an electron with a velocity of 4.8X10s m/s? (Mass of the electron is 9.1X10-31kg)?
Answer:
1.52 nm
Explanation:
Using the De Broglie wavelength equation,
λ = h/p where λ = wavelength associated with electron, h = Planck's constant = 6.63 × 10⁻³⁴ Js and p = momentum of electron = mv where m = mass of electron = 9.1 × 10⁻³¹ kg and v = velocity of electron = 4.8 × 10⁵ m/s
So, λ = h/p
λ = h/mv
substituting the values of the variables into the equation, we have
λ = h/mv
λ = 6.63 × 10⁻³⁴ Js/(9.1 × 10⁻³¹ kg × 4.8 × 10⁵ m/s)
λ = 6.63 × 10⁻³⁴ Js/(43.68 × 10⁻²⁶ kgm/s)
λ = 0.1518 × 10⁻⁸ m
λ = 1.518 × 10⁻⁹ m
λ = 1.518 nm
λ ≅ 1.52 nm
if up is up and down is down isn't downside up , upside down
Answer:
No they arent because they are opposite to each other.
What do all clouds contain the some amount of
Answer:
A cloud is made up of liquid water droplets. A cloud forms when air is heated by the sun. As it rises, it slowly cools it reaches the saturation point and water condenses, forming a cloud.
Explanation:
For a satellite to orbit Earth at a constant distance, its centrifugal acceleration
must be equal and opposite Earth's gravitational acceleration. If a satellite is
to orbit at a constant distance from Earth at a circular radius of 8,300,000 m,
what is the required velocity of the satellite? (Assume the acceleration due to
Earth's gravity is 5.6 m/s2 at this altitude.)
A. 7043 m/s
B. 8239 m/s
C. 7576 m/s
D. 6818 m/s
If a satellite is to orbit at a constant distance from Earth at a circular radius of 8,300,000, the required velocity of the satellite is 8239m/s.
What is a satellite?
Most spacecraft, with the exception of passive satellites, contain a means of generating electricity for the technology they carry, such as solar panels or radioisotope thermoelectric generators (RTGs). The majority of satellites also feature transponders, which are a type of ground station communication system. The most common satellites, small CubeSats, use a standardised bus to reduce costs and labour. Satellites of a similar type can cooperate with one another to form constellations.To know more about satellite, click the link given below:
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A 1.8-kg object is attached to a spring and placed on frictionless, horizontal surface. A force of 40 N stretches a spring 20 cm from its equilibrium position (the origin of the x axis). The object is now released from rest from this stretched position, and it subsequently undergoes simple harmonic oscillations. a) Find the force constant of the spring. b) Find the total energy of the oscillating system. c) Where will the object be from the equilibrium position when its velocity is -2.0 m/s (negative 2 m/s)
Answer:
a) k = 200 N/m
b) E = 4 J
c) Δx = 6.3 cm
Explanation:
a)
In order to find force constant of the spring, k, we can use the the Hooke's Law, which reads as follows:[tex]F = - k * \Delta x (1)[/tex]
where F = 40 N and Δx =- 0.2 m (since the force opposes to the displacement from the equilibrium position, we say that it's a restoring force).Solving for k:[tex]k =- \frac{F}{\Delta x} =-\frac{40 N}{-0.2m} = 200 N/m (2)[/tex]
b)
Assuming no friction present, total mechanical energy mus keep constant.When the spring is stretched, all the energy is elastic potential, and can be expressed as follows:[tex]U = \frac{1}{2}* k* (\Delta x)^{2} (3)[/tex]
Replacing k and Δx by their values, we get:[tex]U = \frac{1}{2}* k* (\Delta x)^{2} = \frac{1}{2}* 200 N/m* (0.2m)^{2} = 4 J (4)[/tex]
c)
When the object is oscillating, at any time, its energy will be part elastic potential, and part kinetic energy.We know that due to the conservation of energy, this sum will be equal to the total energy that we found in b).So, we can write the following expression:[tex]\frac{1}{2}* k* \Delta x_{1} ^{2} + \frac{1}{2} * m* v^{2} = \frac{1}{2}*k*\Delta x^{2} (5)[/tex]
Replacing the right side of (5) with (4), k, m, and v by the givens, and simplifying, we can solve for Δx₁, as follows:[tex]\frac{1}{2}* 200N/m* \Delta x_{1} ^{2} + \frac{1}{2} * 1.8kg* (-2.0m/s)^{2} = 4J (6)[/tex]
⇒ [tex]\frac{1}{2}* 200N/m* \Delta x_{1} ^{2} = 4J - 3.6 J = 0.4 J (7)[/tex]
⇒ [tex]\Delta x_{1} = \sqrt{\frac{0.8J}{200N/m} } = 6.3 cm (8)[/tex]
n moles of CO2 gas (T1, V1) obey a van der Waals equation of state are contained in an insulated piston-cylinder arrangement. A reversible expansion of the gas is carried out until the volume become 2V1.
[CV.m = 28.80 J mol−1K−1, a = 3.610 atm. dm6. mol−2, b = 4.29 x 10−2 dm3. mol−1]
(a) Find the final temperature of gas as a function of n, . , T1, V1 and the van
der Waals parameter a and b.
(b) If two moles of CO2 gas involved and T1 = 350K, V1 = 40L, compute final
temperature of the gas.
(c) Find work done and internal energy of the gas.
Answer:
one or two three or four
Explanation:
animals of CO2 gas find the final temperature of gas
The final temperature of the 2 moles of gas has been 0.0014 K.
The gas has been assumed to be the ideal gas. The moles of the has been n. According to the ideal gas equation:
(a) PV= nRT.
For the reversible expansion of 1 mole of gas:
P = [tex]\rm \dfrac{RT}{V - b}\;\times\;\dfrac{a}{V^2}[/tex]
For n moles of gas, the reversible expansion will be:
P = [tex]\rm \dfrac{nRT}{V - b}\;\times\;\dfrac{a}{V^2}[/tex]
The final temperature of the reversible expansion has been:
[tex]\rm T_f\;=\;T_i\;+\;\dfrac{an^2\;[\frac{1}{Vf\;-\;\frac{1}{Vi} } ]}{Cv}[/tex]
(B) The ideal gas equation can be given as:
[tex]\rm \dfrac{P1V1}{nT1}\;=\; \dfrac{P2V2}{nT2}[/tex]
Substituting the values:
[tex]\rm \dfrac{40}{2\;\times\;350}\;=\;\dfrac{80}{2\;\times\;T2}[/tex]
T2 = 0.0014 K.
The final temperature of the 2 moles of gas has been 0.0014 K.
(c) The work done can be given by:
W = nRT In[tex]\rm \dfrac{V2}{V1}[/tex]
The internal energy of the system has been given by:
[tex]\Delta[/tex]U = [tex]\rm C_v[/tex][[tex]\rm T_f\;-\;T_i[/tex]] - a[tex]\rm n^2[/tex] [tex]\rm [\dfrac{1}{Vf}\;-\;\dfrac{1}{Vi} ][/tex]
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Write any two differences between echo and reverberation.
Why the speed of sound in hot air is more than that in the cold air
Answer:
1) Because of the size and time the sound wave moves, an echo is typically transparent and easy to discern. Since reverberations typically don't have enough distance or time to fly, they will pile up on top of each other, making it impossible to understand.
People will detect an echo if the distance between the source of the sound and the reflected body is greater than 50 feet. When a sound wave is bounced off a nearby surface, it may create a reverberation.
2) The speed of sound in hot air is more than that in cold air because air molecules are traveling faster in hot air.
Explanation:
How do these terms relate to what is being attempted when making a nuclear
bomb (quick, explosive effect) as opposed to a nuclear power plant (controlled
steady production of energy)?.
Answer:
More than four-fifths of the single points of light we observe in the night sky are actually two or more stars orbiting together. The most common of the multiple star systems are binary stars, systems of only two stars together.o
A train is travelong at 22 m/s when the condutor gets a radio call about a car stalled on the tracks. He hits the emergancy brake and the train comes to a halt in 135 sevonds several meters before the car. What was the train's accleration during the emergency?
Answer:
final velocity = 0
because the train stoped
so,
acceleration = (v - u) ÷ tacceleration = (0 - 22) ÷ 135acceleration = -22 ÷ 135acceleration = -0.162 m/s²what are the materials that you have illustrated?
Answer:
An illustration is a decoration, interpretation or visual explanation of a text, concept ... such as posters, flyers, magazines, books, teaching materials, animations, video games and films.
Explanation:
Someone please help me
What effect would lowering the temperature have on this reaction?
3H2 + N2 + 2NH3 + energy
A. H2 and N2 would react to produce more NH3.
B. The reaction would proceed more slowly in both directions.
C. Decreasing the temperature would not have an effect on this
reaction.
D. NH3 would react to produce more H2 and N2.
On lowering the temperature of the given reaction, H₂ gas and N₂ gas would react to produce more NH₃. Therefore, option (A) is correct.
What is the effect of temperature on equilibrium?When the chemical reaction is exothermic then increasing the temperature will cause the backward reaction to occur, decreasing the amounts of the products while increasing the amounts of reactants. Lowering the temperature will produce more reactants and cause the reaction to occur in the forward direction.
The formation of the ammonia is an exothermic reaction that can be represented as:
N₂ (g) + 3 H₂ (g) ⇄ 2NH₃ (g)
If the temperature will be decreased, the chemical reaction will proceed forward to produce more heat. The effect of temperature on equilibrium will change the value of the equilibrium constant of the chemical reaction. The production of more ammonia on lowering the temperature.
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