A gun of mass 1.3 kg fires a bullet of mass .007 kg and recoils with a speed of .75 m/s. How fast did the bullet leave the gun?

The torque exerted on the wheel is 25 N·m.

The torque exerted on the wheel can be calculated using the formula:

Torque = force x radius

Given that the force applied to the cord is 50 N, and the radius of the wheel is 0.5 meters. Using the formula for torque, we can calculate that the torque exerted on the wheel is equal to the force applied multiplied by the radius of the wheel. We can plug these values into the formula to get:

Torque = 50 N x 0.5 m

Torque = 25 N·m

Therefore, the torque exerted on the wheel is 25 N·m.

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--The complete Question is, If a cord is wrapped around the rim of a solid uniform wheel with a radius of 0.5 meters, and a force of 50 N is applied to the cord, what is the torque exerted on the wheel? Assume no friction or slipping between the cord and the wheel. --

Before the use of radar, people relied on visual cues such as cloud formations, debris, and the sound of the tornado to know if one had formed.

Prior to the invention and widespread use of radar technology, people had to rely on their senses and observations to determine if a tornado had formed. They would look for signs such as a rotating cloud or a funnel-shaped cloud descending from the sky. Additionally, they would listen for the sound of the tornado, which has been described as a roar or a freight train.

Debris being thrown around in a circular motion is another visual clue that a tornado has formed. While these methods were not as accurate as modern radar technology, they did allow people to identify and take precautions against tornadoes to some degree.

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The normative statement in this list is b.

The normative statement in this list is b. "You should wear a helmet when cycling." This is because it is expressing a value judgment and prescribing a course of action, rather than simply stating a fact like the other options. The other statements are all descriptive and objective, stating things that are generally true or observable, such as the number of wheels on a bicycle or the color of the sky. The statement about electricity is a scientific principle, but it is still not normative in nature.

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We do not have the value of yo, the initial vertical position of the squirrel (height of the tree limb), so we cannot calculate the exact height of the squirrel above the ground without that information.

What is Velocity?

Velocity is a vector quantity that describes the rate of change of an object's position with respect to time. It specifies both the speed and direction of an object's motion. Velocity is defined as the displacement of an object per unit of time, and it is typically denoted by the symbol "v"

We need to convert the horizontal distance from centimeters to meters and use consistent units in our calculations. Plugging in the given values:

x = 0.186 m

xo = 0 m

vox = 0.1 m/s

Using the horizontal motion equation, we can calculate the time of flight (t) of the nut:

0.186 = 0 + 0.1*t

t = 1.86 seconds

Now, we can use the vertical motion equation to calculate the height (y) of the squirrel:

y = yo + voyt - 0.5g*[tex]t^{2}[/tex]

Since the squirrel loses its grip and has no initial vertical velocity (voy = 0), we have:

y = yo - 0.5g[tex]t^{2}[/tex]

Plugging in the known values:

g = 9.8 m/[tex]s^{2}[/tex]

t = 1.86 s

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To find the average power delivered to the train during its acceleration, we need to use the formula:
Power = Work / Time

First, we need to find the work done on the train during its acceleration. We can use the formula:
Work = Force x distance

The force on the train is equal to its mass times its acceleration:
Force = Mass x Acceleration

Using the given values, we get:
Force = 0.875 kg x (0.720 m/s^2) = 0.63 N

The distance the train travels during its acceleration can be found using the formula:
Distance = (1/2) x Acceleration x Time^2

Plugging in the given values, we get:
Distance = (1/2) x 0.720 m/s^2 x (22.0 x 10^-3 s)^2 = 0.17 m

So the work done on the train during its acceleration is:
Work = 0.63 N x 0.17 m = 0.1071 J

Now we can plug this value into the formula for power:
Power = Work / Time

The time given is 22.0 milliseconds, which is 0.0220 seconds:
Power = 0.1071 J / 0.0220 s = 4.87 W

Therefore, the average power delivered to the train during its acceleration is 4.87 watts.

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The value of B depends on the distance z from the center of the ring, and it will increase as z gets closer to the ring.

The magnetic field on the axis of a circular loop carrying a current I can be calculated using the Biot-Savart law, which states that the magnetic field at a point is directly proportional to the current flowing through the loop and inversely proportional to the distance between the point and the loop.

For a circular loop of radius r, the magnetic field on its axis at a distance z from the center can be calculated as:

[tex]$B = \frac{\mu_0 I}{2}\frac{r^2 + z^2}{\sqrt{r^2 + z^2}^3}$[/tex]

where μ₀ is the permeability of free space.

In this case, the current I = 94.0 A and the diameter of the ring is 2.40 mm, which means the radius r of the ring is 1.20 mm = 0.00120 m.

The magnetic field on the axis of the ring at a distance z can be calculated as:

[tex]$B = \frac{\mu_0 I}{2}\frac{r^2 + z^2}{\sqrt{r^2 + z^2}^3}$[/tex]

[tex]$B = \left(4\pi \times 10^{-7} \frac{T \cdot m}{A}\right) \frac{94.0,A}{2}\left(\frac{0.00120,m}{2}^2 + z^2\right)^{-3/2}$[/tex]

[tex]$B = (2\pi \times 10^{-6},\mathrm{T})(0.0003606 + z^2)^{-3/2}$[/tex]

Therefore, the magnetic field on the axis of the ring is given by

[tex]$B = (2\pi \times 10^{-6},\mathrm{T})(0.0003606 + z^2)^{-3/2}$[/tex]

The value of B depends on the distance z from the center of the ring, and it will increase as z gets closer to the ring.

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The work done by the field along the parabolic path given by y = x as x goes from -1 to 1 is 19/3 Joules.

We can parametrize the parabolic path as follows:

x(t) = t, where t goes from -1 to 1

y(t) = t

Substituting these into the expression for the field F, we get:

F = [tex](3t^2 + 2t)i + (4t + 2t)j[/tex]

F = [tex](3t^2 + 6t)i + (6t)j[/tex]

To find the work done by the field along this path, we need to integrate the dot product of F and the path differential vector dr, evaluated along the path:

W = ∫ F · dr

dr = dx i + dy j

dr = dt i + dt j

dr = (i + j) dt

Substituting F and dr, we get:

W = ∫ F · dr

W = [tex]∫[(3t^2 + 6t)i + (6t)j] · (i + j) dt[/tex]

W = [tex]∫(3t^2 + 9t) dt[/tex]

Evaluating the integral from t = -1 to t = 1, we get:

W = [tex][t^3/3 + 9t^2/2] from -1 to 1[/tex]

W =[tex][(1/3 + 9/2) - (-1/3 + 9/2)][/tex]

W = [tex][19/3] Joules[/tex]

Therefore, the work done by the field along the parabolic path given by y = x as x goes from -1 to 1 is 19/3 Joules.

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Full Question: How much work is done by the field F = (3x2 + 2y)i + (4y + 2x)ị along the parabolic path given by y = x? as x goes from –1 to +1? (Remember: how you parametrize the path is up to you and will not change your answer...)

The correct answer is option D) When the fox eats an animal that eats plants, it receives energy indirectly from the sun.

Energy in a food chain flows from the sun, to the producers (plants), to the primary consumers (herbivores), to the secondary consumers (carnivores), and so on. Omnivores, such as foxes, consume both plants and animals, but they typically obtain more of their energy from consuming other animals.

When a fox eats an animal that eats plants, it is receiving energy indirectly from the sun. The plants that the prey animal consumed converted the energy from the sun into organic molecules through the process of photosynthesis. The prey animal then consumed those plants and converted the organic molecules into its own tissues. When the fox eats the prey animal, it is obtaining the energy stored in the prey's tissues.

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The warning that objects seen in the mirror are closer than they appear is due to the fact that convex mirrors produce reduced, virtual images of objects. The image in a convex mirror appears to be closer than it actually is, as light rays are refracted back toward the optical axis and scattered. Also, because the image is smaller than the actual object, it appears to be further away than it actually is. Therefore, it is important to take into account this distortion in the perception of distance when using convex mirrors in vehicles and other devices

Tangential acceleration of the rim of the wheel = Change in speed / time = (10 m/s - 0 m/s)/(60 m/ 0.30 m) = 333.33 m/s²

Acceleration is the rate of change of velocity over time. It is a vector quantity, which means it has both magnitude and direction. Acceleration can be caused by a variety of factors, including an external force, a change in mass, or a change in velocity. Acceleration is typically measured in meters per second squared (m/s²). When an object is accelerating, its velocity changes over time.

Rotational acceleration of the wheel = Tangential acceleration / Radius of the wheel = 333.33 m/s² / 0.30 m = 1111.11 rad/s²
Rotational speed of the wheel just after traveling 60 m
= Initial rotational speed + Acceleration x Time
= 0 + 1111.11 rad/s² x (60 m / 0.30 m)
= 37,037.04 rad/s

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The downward force of the atmosphere on the book is equal to the pressure of the atmosphere multiplied by the surface area of the book's cover and it is calculated to be 5 N.

Atmospheric pressure is the pressure exerted by the weight of the Earth's atmosphere on objects on or near the surface of the Earth. It is caused by the gravitational attraction of the Earth on the gases in the atmosphere. The atmospheric pressure varies with altitude, temperature, and weather conditions, and is typically measured in units of pressure such as pascals (Pa) or kilopascals (kPa).

Force = Pressure x Area

Where:

Pressure = 100 kPa (given)

Area = 0.05 m² (given)

Substituting the given values, we get:

Force = 100 kPa x 0.05 m²

Force = 5 N

Therefore, the downward force of the atmosphere on the book is 5 N.

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A tidal wave is a type of wave known as a "tidal bore," also called a "seiche."

Tidal bores occur when the rising tide creates a wall of water that moves up a river or narrow bay against the direction of the river or bay's flow.

This occurs due to the gravitational forces of the Moon and Sun, which cause the ocean's water level to rise and fall in a regular cycle of tides.

As the high tide crests at the mouth of the river or bay, a surge of water propagates upstream and collides with the lower water level.

The interaction between the two bodies of water generates a large, powerful wave that moves upstream.

The height and speed of the tidal bore depend on the shape and depth of the river or bay, as well as the astronomical tide cycle.

Tidal waves can be dangerous, as they can cause damage to boats, structures, and ecosystems along the river or bay.

Some tidal bores can reach heights of up to several meters and travel at speeds of up to 30 km/h (18.6 mph), creating dangerous conditions for those caught in their path.

Despite their destructive potential, tidal bores can also be an attraction for surfers and thrill-seekers who ride the waves on specialized boards or boats.

Tidal bore surfing has become a popular sport in some parts of the world, such as the Qiantang River in China and the Amazon River in Brazil.

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The diameter is approximately 1.08 meters when a basketball player pushes down with a force of 50 n

To solve this problem, we can use the formula for the contact area between two objects under a given force:

A = F / P

where A is the contact area, F is the force applied, and P is the pressure between the two objects.

In this case, the basketball player pushes down on the basketball with a force of 50 N, and the basketball has a gauge pressure of 8 psi, which is equivalent to 55.16 kPa.

To find the contact area between the basketball and the floor, we need to convert the pressure from psi to kPa:

P = 8 psi * 6.89476 kPa/psi = 55.16 kPa

Next, we can plug in the values into the formula to get the contact area:

A = 50 N / 55.16 kPa = 0.91 square meters

However, this gives us the total contact area of the basketball, which is not the same as the diameter of contact between the ball and the floor. To find the diameter, we need to assume a shape for the contact area.

If we assume that the contact area is circular, we can use the formula for the area of a circle to find the diameter:

A = πr^2

where A is the contact area, and r is the radius of the circular contact area.

Rearranging this formula, we get:

r = sqrt(A/π) = sqrt(0.91/π) = 0.54 meters

Finally, we can compute the diameter by multiplying the radius by 2:

d = 2r = 2 * 0.54 meters = 1.08 meters

Therefore, the diameter of contact between the basketball and the floor is approximately 1.08 meters.

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To determine the electric field outside a charged sphere, we can use Gauss's Law, which states that the flux of the electric field through a closed surface is proportional to the charge enclosed by the surface.

If the charge is distributed uniformly throughout the spherical volume of radius R, then the charge enclosed by a Gaussian surface outside the sphere is simply the total charge of the sphere.

The electric field outside the sphere is radial, and by symmetry, it must have the same magnitude at any point on a sphere with radius r greater than R.

Therefore, we can choose a spherical Gaussian surface with radius r > R and calculate the flux of the electric field through that surface.

By Gauss's Law, the flux is proportional to the charge enclosed, which is the total charge Q of the sphere.

The electric field magnitude E is related to the flux Φ and the surface area A of the Gaussian surface by:

Φ = E * A

where Φ = Q / ε_0 is the total electric flux through the surface, and ε_0 is the electric constant.

Since the Gaussian surface is a sphere, its surface area is 4πr^2. Therefore, we have:

E * 4πr^2 = Q / ε_0

Solving for E, we get:

E = Q / (4πε_0r^2)

This expression tells us that the electric field outside the sphere decreases with the square of the distance from the center of the sphere.

At large distances (compared to the radius of the sphere), the electric field can be approximated as that of a point charge, with the same total charge as the sphere, located at the center of the sphere.

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True. The breaking force refers to the maximum amount of force that a material can withstand before it fractures or breaks.

The highest amount of stress or force that a material can sustain before it fractures or breaks is referred to as the breaking force, also known as the ultimate tensile strength. This is a crucial characteristic of materials that are frequently used to assess their durability and mechanical strength.

The composition, structure, temperature, and loading conditions of the material, among other things, can all have an impact on the breaking force. Higher breaking forces are often regarded as more robust materials, which makes them suited for applications requiring great strength and durability.

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The harmonic wave is n = (2m - 1), the frequency is 7582 Hz, the wavelength is 4.5 and the wave speed is 336.6 m/s.

In a closed pipe, the wave can only have odd-numbered harmonics, because the closed end of the pipe is a node of the wave. The harmonic number can be determined using the equation:

n = (2m - 1)

where n is the harmonic number and m is an integer.

The wavelength of the wave is given as λ = 0.2 m. The fundamental wavelength is given by the equation:

λ1 = 2L

where L is the length of the pipe. Substituting the value of L, we get:

λ1 = 2(0.45 m) = 0.9 m

The fundamental frequency is given by the equation:

f1 = v / λ1

where v is the speed of the wave. Rearranging the equation, we get:

v = f1 * λ1

The wave speed can also be determined using the equation:

v = f * λ

where f is the frequency of the wave and λ is its wavelength.

Equating the two expressions for v, we get:

f1 * λ1 = f * λ

Solving for the fundamental frequency, we obtain:

f1 = (λ1 / λ) * f = (0.9 m / 0.2 m) * 1683 Hz ≈ 7582 Hz

Therefore, the fundamental frequency of the wave is approximately 7582 Hz.

The harmonic number is given by the equation:

n = (2m - 1)

where m is an integer. To determine the harmonic number, we can rearrange the equation to get:

m = (n + 1) / 2

Substituting the value of λ and λ1, we can solve for n:

λ = λ1 / n

n = λ1 / λ = 0.9 m / 0.2 m = 4.5

Since n must be an integer, the nearest odd integer to 4.5 is 5.

Therefore, the wave is the fifth harmonic.

Finally, we can determine the wave speed using the equation:

v = f * λ = (1683 Hz) * (0.2 m) = 336.6 m/s

Therefore, the wave speed is approximately 336.6 m/s.

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Answer:

acceleration = 2m/s^2

distance= 100 meters

Explanation:

acceleration = (final velocity - initial velocity) / time

acceleration = (20 m/s - 0 m/s) / 10 s

-----------------------------------------------------------------------------------

distance = (initial velocity * time) + (0.5 * acceleration * time^2)

since the car starts from rest, the initial velocity is 0.

distance = 0.5 * 2 m/s^2 * (10 s)^2

If the trench is dug too deep or if there are low spots in the trench, compacted backfill should be used as fill under the pipe. This helps to provide support and prevent the pipe from settling or becoming damaged over time.

The backfill material should be free from rocks, debris, and other sharp objects that could puncture the pipe, and it should be compacted in layers to ensure a stable foundation.

Additionally, it is important to make sure that the backfill material is properly graded to prevent water from pooling around the pipe and causing erosion or other issues.

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In the visible-light view of M82, the source of the white and blue light that dominates the image is mainly due to the presence of young, massive stars. These stars emit high amounts of energy, which results in a strong blue and white glow.

The white and blue light in the visible-light view of M82 is primarily coming from young, hot, massive stars that are forming in the galaxy's intense starburst regions. These stars emit large amounts of ultraviolet radiation, which ionizes the surrounding gas and causes it to glow brightly in visible light. Additionally, some of the blue light may be due to scattered starlight off of dust particles in the galaxy's disk.
The blue light comes from the hot, young stars, while the white light is a combination of light emitted by various types of stars within the galaxy. The high star formation rate in M82 contributes to the abundance of these bright stars and the overall appearance of the galaxy.

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To accurately measure the distance between Earth and a star using parallax measurements, the two observations should be made  C. six months apart.

This effect occurs due to Earth's orbit around the Sun. To maximize the accuracy of parallax measurements, astronomers observe the star from two positions in Earth's orbit that are as far apart as possible, which corresponds to a baseline of twice Earth's orbital radius. This maximum separation occurs when observations are made six months apart because Earth would have moved to the opposite side of its orbit around the Sun, creating the longest possible baseline for the measurements.

Observing the star with a shorter time interval (e.g., instantaneously, a day, or even a year) would result in a smaller baseline and less accurate distance measurement due to a smaller parallax angle. Therefore, taking measurements six months apart allows astronomers to obtain the most precise parallax measurement and consequently, the most accurate distance to the star. Therefore the correct option is C

The Question was Incomplete, Find the full content below :

If the distance between the Earth and a star is measured using parallax measurements, how far apart in time should the two measurements be made to make the parallax measurement as accurate as possible?

A. Instantaneously

B. A day

C. Six months

D. A year

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The angle between the plumb line on the train and the plumb line on the ground is approximately 0.02 degrees. The plumb line on the train is deflected towards the east, in the direction of the train's motion.

We need to calculate the angle between the plumb line on the train and the plumb line on the ground.

By using the tangent function

tanθ = (v² ÷ gR)

where,

θ = angle between the plumb line on the train and the plumb line on the ground

v = 150 m/s is velocity of the train

g = 9.81 m/s² is acceleration due to gravity

R = 6,371,000 m isradius of the earth

Plugging in the values, we get:

tanθ = (150₂ ÷ (9.81 × 6,371,000))

tanθ = 0.000346

Taking the inverse tangent of both sides, we get:

θ = tan⁻¹(0.000346)

θ = 0.0199 degrees

θ ≈ 0.02 degrees deflected towards the east, in the direction of the train

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Answer:

Correct Answer: Option B

Explanation:

Explanation

P1/T1 = P2/T2

80/(273+47) = P1/(273+27) = 75Nm-2

Answer: 75.0 Nm^-2

Explanation:

P1/T1 = P2/T2 80/(273+47) = P1/(273+27) = 75Nm-2

To determine the time a star with a right ascension of 6hr will transit, we can follow these steps:

1. Identify the right ascension of the star currently transiting (8hr) and the time of transit (5am).
2. Determine the difference in right ascension between the two stars (8hr - 6hr = 2hr).
3. Convert the difference in right ascension to a time difference (2hr x 4 minutes/degree x 15 degrees/hour = 120 minutes).
4. Calculate the transit time of the star with a right ascension of 6hr by subtracting the time difference from the given transit time (5am - 120 minutes = 3am).

So, a star with a right ascension of 6hr will transit at 3am.

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The argument that best supports the student's claim is: "If the distance between two objects increases, the gravitational force between the objects will decrease." This statement aligns with the principles of gravitational force as defined by Isaac Newton's Law of Universal Gravitation.

According to this law, the gravitational force between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers. In simpler terms, as the distance between two objects increases, the gravitational force between them decreases, and vice versa.

The other statements provided do not accurately represent the relationship between distance and gravitational force. For example, saying that the gravitational force will not change or will disappear as the distance changes contradicts the Law of Universal Gravitation. Similarly, claiming that the gravitational force will increase as the distance between objects increases is also incorrect based on the principles of this law.

In conclusion, the argument stating that an increase in distance between two objects leads to a decrease in the gravitational force between them best supports the student's claim, as it accurately reflects the principles established in the Law of Universal Gravitation.

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The investigator must increase the current by a factor of 5 to keep the magnetic field strength constant when the distance is increased from 1.0 cm to 5.0 cm.

When a current flows through a wire, it produces a magnetic field around it. The strength of this field depends on the current and the distance from the wire. According to the inverse-square law, the magnetic field strength decreases as the distance from the wire increases.

For a long, straight wire carrying a current I, the magnetic field strength at a distance r from it can be calculated as follows:

B = μ0 I ÷ (2πr)

where μ0 is the permeability of free space, which is a constant.

If the magnetic field strength is to remain constant when the distance is increased from 1.0 cm to 5.0 cm, then we can set the two expressions for B equal to each other:

μ0 I ÷ (2πr₁) = μ0 (xI) ÷ (2πr₂)

where x is the factor by which the current must be increased.

Simplifying this expression, we get:

x = r₂ ÷ r₁ = 5.0 cm ÷ 1.0 cm = 5

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Answer:  the tub makes approximately 1939.25 revolutions in the first 8.4 seconds before slowing down to rest in the next 10.7 seconds.

Explanation:

the final angular velocity of the tub is:

ω = 32.6 x 8.4 = 274.44 rad/s

During the 8.4 seconds, the tub undergoes angular displacement given by:

θ = (1/2) x α x t^2

where θ is the angular displacement.

thus the angular displacement of the tub is:

θ = (1/2) x 32.6 x (8.4)^2 = 12185.44 rad

The tub makes one full revolution when it completes an angular displacement of 2π radians

N = θ / 2π = 12185.44 / (2 x π) = 1939.25 revolutions (approx)?

is it correct?

In a single-slit diffraction pattern, the width will double if the distance from the slit to the screen is doubled.

The width of the central bright fringe in a single-slit diffraction pattern is given by the formula:

[tex]w = (λL) / d[/tex]

where w is the width of the central bright fringe, [tex]λ[/tex] is the wavelength of light used, L is the distance from the slit to the screen, and d is the width of the slit.

If we double the distance from the slit to the screen (i.e., double L), the width of the central bright fringe will be halved:

[tex]w' = (λ(2L)) / d = 2[(λL) / d] = 2w[/tex]

where w' is the new width of the central bright fringe.

Therefore, the width of the central bright fringe will be twice its original size if the distance from the slit to the screen is doubled.

So, the answer is: "The width of the central bright fringe will be twice its original size."

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Answer:

Conductor.

Explanation:

Resistors conduct electricity, but put up oppisition to the current flow.