It's internal energy decreases of 18000J.
ΔQ = ΔU + ΔW
-12000J = ΔU + 6000
ΔU = - 18000J
Internal energy is the energy attributed to the disorderly, haphazard motion of molecules. It refers to the intangible microscopic energy on the atomic and molecular levels, which is distinct in scale from the macroscopic organised energy connected to moving objects. A glass of water that is at normal temperature and is resting on a table, for instance, has no discernible potential or kinetic energy. Although it is a seething mass of molecules moving at hundreds of metres per second at the microscopic level. When we superimpose an ordered big scale motion on the water as a whole, this tiny energy would not necessarily alter if the water were thrown across the room.
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fixing the brakes on your bicycle, you have the bicycle turned upside down. to test the brakes, you spin the wheel to a high speed in a counter-clockwise direction from your perspective. what is the direction of the angular displacement of the wheel?
The direction of the angular displacement of the wheel is -Toward you.
What does angular displacement refer to?The definition of angular displacement is "the angle, expressed in radians (degrees, revolutions), through which a point or line has been rotated in a particular sense about a certain axis." It is the angle at which a body travels around in a circle.
A vector quantity, angular velocity has both a magnitude and a direction. The direction matches the direction of the angular displacement, which is where we derived the angular velocity.
The rate at which angular velocity changes over time is referred to as angular acceleration. Typically, it is stated in radians per second per second. As a result, d = d t. The term "rotational acceleration" also applies to the angular acceleration.
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Stan argues that momentum cannot be conserved when a collision is not a head-on collision. Rachel insists it is conserved because each body receives an impulse of equal magnitude. Rachel is correct because.
Rachel is correct because she said that is body receive equal magnitude of impulse which completely satisfy the law of conservation of linear momentum.
According to law Conservation of Linear Momentum, if there is no external force working on the system, then the linear momentum remains conserved before and after the collision.
We know that,
Momentum is nothing but the product of force and the time taken for the contact period of the colliding bodies.
We assume that during the head on collision of the body, the body is remain in contact for such a short period of time that there is no external force all the impulse created due to the external force is neglected.
So, because the impulse imparted on both the bodies are equal to each other.
We know that impulse is nothing but the change in momentum.
So, from here we conclude that bodies received equal magnitude of impulse.
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what did the herschels find when they counted stars in 683 regions around the milky way? about the same number of stars in each direction. many more stars are in the direction of the constellation sagittarius than in any other direction in the milky way. the doppler shifts in stellar spectra are about half redshifted and half blueshifted. the mass-luminosity relationship for main sequence stars. that the sun is moving toward the constellation cygnus.
The sun is moving toward the constellation Cygnus, as discovered by Herschel when they counted stars in 683 regions around the Milky Way.
One of the significant discoveries made by Galileo in his Sidereus Nuncius in 1610 was that, when viewed through a telescope, some of the Milky Way resolved into a cluster of numerous stars.
The Sun is the darker star towards the image's center. Herschel has indicated its location in the image above. Herschel's research leads to the conclusion that the Sun is situated at or close to the Milky Way's center.
The Milky Way galaxy is the home of the Sun. About 100,000,000,000 stars are thought to be present in the Milky Way alone, according to astronomers.
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what is the linear separation d at the retina? the minimum diameter of the pupil is about 2 mm, the eye is most sensitive to wavelengths of about 500 nm (air), the index of refraction of the aqueous humor is n
the linear separation d at the retina is 5.73micrometers
diameter=2mm
lambda=500nm
nair=1.33
d=2.5cm
alpha=1.22lambda/nd
=1.22(500x10^9)/(1.33)(2x10^-3)
=2.3x10^-4 rad
D=(2.3x10^-4)(.025)=5.73micrometers
The area of the eye that transforms light into neural signals is called the retina (Latin: rete, "net"). Most vertebrates and some molluscs have this innermost, light-sensitive layer of tissue in their eyes. A two-dimensional representation of the visual world is created on the retina by the optics of the eye (cornea and lens); some of the image is in focus and some of the image is out of focus. Visual perception is produced by the retina's processing of the image and the optic nerve's transmission of nerve impulses to the visual cortex. Similar to a camera's image sensor, the retina fulfills a purpose.
The neural retina is supported by an outer layer and is made up of numerous layers of neurons coupled by synapses.
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what is re, the reynolds number re, for water flows at 10 m/s speed through a typical household water pipe of 30 mm diameter? viscosity of water is 8.90 x 10-4 pa.s.
To learn the viscosity and speed and resistance to calculate the diameter.
What is viscosity?
Viscosity is a fluid's (liquid or gas) resistance to a change in shape or motion of adjacent parts concerning one another. Viscosity indicates resistance to flow.
What constitutes speed?
The speed of a change in an object's position in any direction Speed is defined as the ratio of distance to the amount of time it takes to cover that distance. Since speed has only a direction and no magnitude, it is a scalar quantity.
Resistance AC circuit
in resistance AC circuit the voltage and current are related as,
Emf; E= EoSinωt
where, I_O=E_O/R
In purely resistive circuit, there is no phase change occurs. the phase angle between voltage and current is zero.
the maximum value of current is I_0 =v_0\R
if tha maximum volatge v_0 is increase with decrease of resistance R then current in the circuit will maximum and denoted asI_0
capacitive AC circuit
In capacitive AC circuit the voltage and current are related as,
Emf: E=E_Osinωt
and current I =I_Osinωt
⇒ I =I _0sin(ωt+π/2)
where,I_0 =E_0/X_C
in purely capacitive circuit, current leads the end by phase of π/2. the phase angle between volatge and current is π\2
The maximum value of current is,I_0 =E_0\X_C
if the maximum voltage E_0 is increases with decreases of capacitive X_c then current in the circuit will maxmium and denoted as I_0
when the emf is zero then current is maximum magnitude.so the current is maxmium before it leads or lag in the circuit.
inductive AC circuit:
Inductive AC circuit the voltage and current are related as
Emf: E= E_0sinωt
And current : I= (-)I_0cosωt
⇒ I= I_0sin(ωt -π/2)
where, Iπ_0 =E_0/X_L and x=∈L
In purely inductive circuit, the current lags behind the voltage (emf) by phase of π/2. The phase angle between volatge and current is π/2
The maximum value of current is, I_0 = E_0/X_L
if the maximum voltage E_0 is increase with decrease of inductive resistance X_L then current in the circuit will maximum and denoted is I_0.
Therefore, the emf is zero then current is maximum magnitude. so the current is maximum before it leads or lag in the circuit.
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suppose that a microscope has an objective whose focal length is 1.00 mm and an eyepiece whose focal length is 25.0 mm. what is the magnifying power (m)) of the microscope? group of answer choices 25x 0.04x we need more information to calculate mp. 625x 160x
The ratio of the image's distance from the lens to the object's distance determines a lens's magnifying capability. Thus, the microscope's magnification factor m=m1m2.
Explain about magnifying power?Magnifying power is a lens's capacity to enlarge an image by how much. The least distance of distinct vision, or LDDV, and the focal length of the lens are directly correlated. Your eyes can easily focus on an object up to their LDDV.
By dividing the focal length of the scanning object (lens) by the focal length of the eyepiece, the magnifying power is computed. A 1x magnification power results in a 100% increase in the size of the thing being enlarged. A 1-inch object, for instance, would appear to be 2 inches at 1x.
The ratio of the angle the image at the eye occupies to the angle the object occupies is known as the magnifying power of the microscope.
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in a simple electric circuit, ohm's law states that , where v is the voltage in volts, i is the current in amperes, and r is the resistance in ohms. assume that, as the battery wears out, the voltage decreases at 0.01 volts per second and, as the resistor heats up, the resistance is increasing at 0.04 ohms per second. when the resistance is 400 ohms and the current is 0.04 amperes, at what rate is the current changing?
The rate is the current changing is = - 1.3 x 10⁻⁴ A/s
Solution:
We take the derivative of Ohm's law with respect to time
V = IR
Using the product rule:
dV/dt = I(dR/dt) + R(dI/dt)
We are given that voltage is decreasing at 0.01 V/s
resistance is increasing at 0.04 ohm/s
resistance itself is 400 ohms,
and current is 0.04 A
Substituting:
-0.01 V/s = (0.04 A)(0.04 ohm/s) + (400 ohms)(dI/dt)
dI/dt = -1.3 x 10⁻⁴ A/s.
The relationship between current, voltage, and resistance. The amount of continuous current flowing through many materials is directly proportional to the potential difference or voltage between them.
Law of Electricity The strength of a direct current is directly proportional to the potential difference and inversely proportional to the resistance of the circuit. Ohm's Law is a formula for calculating the relationship between voltage, current, and resistance in a circuit. Ohm's law describes the relationship between current, voltage, and resistance. This shows that at a constant temperature, the current through the circuit is directly proportional to the applied voltage and inversely proportional to the resistance of the circuit.
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the force needed to keep a car from skidding on a curve varies inversely as the radius of the curve and jointly as the weight of the car and the square of the car's speed. suppose that 640 pounds of force keeps a 2600-pound car from skidding on a curve of radius 650 at . what force would keep the same car from skidding on a curve of radius at ?
The force needed to keep a 2600-pound car from skidding on a curve of radius 650 at is 640 pounds.
The force needed to keep a car from skidding on a curve varies inversely as the radius of the curve and jointly as the weight of the car and the square of the car's speed.
The same force would keep the same car from skidding on a curve of radius at , because:
1) The force is inversely proportional to radius. If one goes up, the other goes down.
2) The force is jointly proportional to weight and square speed. If one goes up, so does another; if one goes down, so does another.
3) 1600 pounds will keep a 2600-pound car from skidding on both curves--the force does not depend on which curve you're talking about!
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for a slinky, the unstretched length is much shorter than the stretched length. suppose that the fundamental standing wave is oscillating on a slinky. how does the period of the standing wave change as the length of the slinky is altered?
Using the concepts of simple harmonic progression, we got that period of the standing wave changes directly proportional as the length of the slinky is altered.
We know very well that a standing wave traverse alternatively from crest to trough.
Crest is defined as that point when amplitude is maximum in positive y-direction and trough is defined as that point when amplitude is maximum in negative y-direction.
To traverse from crest to trough, a standing wave requires some time.
When the length of standing wave changes the time required by the standing wave also changes.
It means if we increase the length of slinky then the time required by the standing wave also increases and if we decrease the length of slinky then the time required by the standing wave also decreases.
Hence, when the fundamental standing wave is oscillating on a slinky, the period of the standing wave change directly proportional as the length of the slinky is altered.
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Thousands of small rocky objects are located in the solar system between mars and jupiter. These objects are.
Thousands of small rocky objects known as asteroids can be found in the solar system between Mars and Jupiter.
What exactly is a solar system?The Solar System is composed of the Sun and the objects that orbit it. It was created by the gravitational collapse of a massive interstellar molecular cloud 4.6 billion years ago. The Sun contains the vast majority of the system's mass, with Jupiter holding the majority of the remaining mass.
Asteroids are rocky bodies that orbit the Sun. Although asteroids orbit the Sun in the same way that planets do, they are much smaller. In our solar system, there are numerous asteroids. The majority of them are found in the main asteroid belt, which lies between the orbits of Mars and Jupiter.
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suppose the ring rotates once every 5.50 s . if a rider's mass is 51.0 kg , with how much force does the ring push on her at the top of the ride?
The force does the ring push on her at the top of the ride is 489.37N.
What does the word "force" mean?When an object with mass is pushed or pulled, it changes its velocity, according to the definition of force.
Given,
Ring rotates (T) = 5.50 s
Mass m= 51.0 kg
The velocity will now be determined as,
V = 2πr/T
V = 2π8/5.50
V = 50.54/5.50
V = 50.54/5.50
V = 9.134m/s.
By bringing the forces into balance,
N = mv²/R - mg
N = m (v²/R - g)
N = 51(9.134²/8 - 9.8)
N = 51(83.42/8 -9.8)
N = 489.37N
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a long solenoid that has 950 turns uniformly distributed over a length of 0.390 m produces a magnetic field of magnitude 1.00 10-4 t at its center. what current is required in the windings for that to occur? ma
current is required in the windings for that to occur is 32.67mA
N=950
L=0.390m
B=1.0×10⁻⁴
B=μ₀ni
n=N/L(number of turns per unit length)
i=current
μ₀=permeability of free space =4π×10⁻⁷mkgs⁻²A⁻²or4π×10⁻⁷Tesla-m/A
i=B/μ₀n
i=1.0×10⁻⁴×0.390/4π×10⁻⁷×950
i=32.67mA
Electric current is a flow of charged particles—such as electrons or ions—that moves through a conductor for electricity or into void space. It is measured by the net rate of electric charge passing through a surface or into a control volume. Moving particles, or charge carriers, can be any number of distinct kinds of particles depending on the conductor. The charge carriers in electrical circuits are frequently electrons moving down a wire. In semiconductors, they could be electrons or holes. Ions are the charge carriers in an electrolyte, and plasma, an ionized gas, is composed of both electrons and ions.
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Ryan scores during his Waterpolo match by throwing the water polo ball hard. If the water polo bairs mass is 0.45 kg, the ball’s weight is ___N
The ball accelerates at a rate of 5.0 m/a^2 after Ryan throws it The net force on the ball is ___N.
The friction between the ball and the air is 2.65 N. To throw the ball at 5.0 m/a^2. Ryan has to apply a force of ___N
Ball’s weight is 4.4129925 N , net force on the ball is 2.25 N , Ryan has to apply a force of 4.9 N.
What is force ?
Whenever there is an interaction between two objects, there is a force acting on each object. When the interaction stops, the two objects no longer receive forces. Forces arise only through interactions , describes the technique of rocks converting their bodily houses with out converting their simple composition.
What is acceleration ?
Acceleration is a vector quantity defined as the rate at which an object's velocity changes. An object accelerates when its velocity changes.
What is friction ?
Friction is the resistance to movement of 1 item transferring relative to another. According to the International Journal of Parallel, Emergent and Distributed Systems(opens in new tab), it isn't always handled as a essential force, like gravity or electromagnetism. Instead, scientists accept as true with it's miles the end result of the electromagnetic appeal among charged debris in touching surfaces.
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astronauts connect a line between their 3200-kg spaceship and a 7700-kg asteroid. using the ship's engine, they pull on the asteroid with 620 n of force. if the asteroid and the ship are initially 450 meters apart, how long does it take for the ship and asteroid to meet?
As the spaceship pull the asteroid with 620 N of force, they will meet after 105.4 seconds.
The gravitational force between the ship and the asteroid is very small compared to the force caused by pulling the asteroid. Hence, we can assume that the only force applied on the asteroid is the pulling force.
Using the Newton 2nd Law of motion:
F = m . a
Where
F = pulling force = 620 N
m = mass of the asteroid = 7700 kg
a = acceleration
Hence,
a = F/ m = 620 / 7700 = 0.081 m/s²
Using the equation of motion:
s = 1/2 . a t²
Where:
s = distance = 450 meters
t = time
Hence,
450 = 1/2 . (0.081) t²
t² = 11,111.11
t = 105.4 seconds
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if at a particular instant and at a certain point in space the electric field is in the x-direction and has a magnitude of 5.00 v/m , what is the magnitude of the magnetic field of the wave at this same point in space and instant in time? express your answer in teslas.
The magnitude of the magnetic field of the wave at this same point in space and instant in time is 1.67 × 10 ⁻⁸ T
The direction of the electric field is pointing in the positive x direction and the direction of propagation of the wave is in the positive z direction. Therefore, the direction of the magnetic field is in the positive y direction. Because in an electromagnetic wave, the direction of the electric field, the direction of wave propagation, and the magnetic field all lie perpendicular to each other.
According with the right-hand rule, the thumb points within the route of the current, the hands factor inside the course of the magnetic subject, and the resulting pressure at the charge points outwards from the palm. The pressure on a negatively charged particle is inside the opposite path.
Calculation:-
B₀ = E₀/c
= 5 / 3 × 10⁸
The magnitude of the magnetic field is equal to = 1.67 × 10 ⁻⁸ T
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consider a 20 kg sphere with a 10 cm radius. what weight would a scale read if the sphere was totally submerged in water?
The weight the scale would read if the sphere of mass 20 kg with a 10 cm radius was totally submerged in water is 155.1 N
Fg = m g
Fb = ρ V g
Fg = Force of gravity
Fb = Buoyant force
m = Mass
g = Acceleration due to gravity
ρ = Density of medium
V = Volume of object
m = 20 kg
g = 9.8 m / s²
ρ = 1000 kg / m³
r = 10 cm = 0.1 m
Fg = 20 * 9.81
Fg = 196.2 N
Fb = ρ ( 4 / 3 π r³ ) g
Fb = 1000 * 4 / 3 * 3.14 * 0.1³ * 9.8
Fb = 41.1 N
N = Fg - Fb
N = Scale reading
N = 196.2 - 41.1
N = 155.1 N
Therefore, the scale reading if the sphere was totally submerged in water is 155.1 N
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A water trough is 10 m long and a cross-section has the shape of an isosceles trapezoid that is 30 cm wide at the bottom, 80 cm wide at the top, and has height 50 cm. if the trough is being filled with water at the rate of 0.2 m3/min, how fast is the water level rising when the water is 30 cm deep?
Answer:
Approximately [tex]0.033\; {\rm m\cdot min^{-1}}[/tex] (meters per minute.)
Explanation:
Let [tex]A[/tex] and [tex]B[/tex] denote the bottom and top width of the trough, respectively. It is given that [tex]A = 30\; {\rm cm} = 0.30\; {\rm m}[/tex] and [tex]B = 80\; {\rm cm} = 0.80\; {\rm m}[/tex]. Let [tex]H[/tex] denote the height of this trough; [tex]H = 50\; {\rm cm} = 0.50\; {\rm m}[/tex].
Let [tex]h[/tex] denote the current depth of the water in this trough.
Let [tex]b[/tex] denote the current width of the surface of the water. As water fills the trough, this width increases from [tex]A = 0.30\; {\rm m}[/tex] (width of bottom of trough) to [tex]B = 0.80\; {\rm m}[/tex] (width of top of trough.)
The relationship between [tex]b[/tex] and [tex]h[/tex] is linear:
[tex]\displaystyle b = \frac{h}{H}\, (B - A) + A[/tex].
Cross-section area of water in this trough:
[tex]\begin{aligned}(\text{area}) &= \frac{1}{2}\, (A + b) \, h \\ &= \frac{1}{2}\, \left(A + \frac{h}{H}\, (B - A) + A\right)\, h \\ &= A\, h + \frac{1}{2\, H} (B - A)\, h^{2}\end{aligned}[/tex].
Let [tex]L[/tex] denote the length of this trough; [tex]L = 10\; {\rm m}[/tex].
Let [tex]v[/tex] denote the volume of water in this trough:
[tex]\begin{aligned}v &= (\text{area})\, L \\ &= \frac{1}{2}\, (A + b) \, h\, L \\ &= \frac{1}{2}\, \left(A + \frac{h}{H}\, (B - A) + A\right)\, h\, L \\ &= A\, L\, h + \frac{L}{2\, H} (B - A)\, h^{2}\end{aligned}[/tex].
Differentiate both sides implicitly with respect to [tex]v[/tex]:
[tex]\displaystyle \frac{d}{dv}[v] = \frac{d}{dv}\left[A\, L\, h + \frac{L}{2\, H}\, (B - A)\, h^{2}\right][/tex].
[tex]\displaystyle \frac{d}{dv}[v] = \frac{d}{dv}[A\, L\, h] + \frac{d}{dv}\left[\frac{L}{2\, H}\, (B - A)\, h^{2}\right][/tex].
[tex]\displaystyle 1 = A\, L\, \frac{dh}{dv} + \frac{L}{2\, H}\, (B - A)\, 2\, h\, \frac{dh}{dv}[/tex].
(Note that [tex]A[/tex], [tex]B[/tex], [tex]L[/tex], and [tex]H[/tex] are constants.)
Rearrange this equation to obtain:
[tex]\displaystyle 1 = A\, L\, \frac{dh}{dv} + \frac{L}{H}\, (B - A)\, h\, \frac{dh}{dv}[/tex].
[tex]\displaystyle 1 = \left(A\, L + \frac{L}{H}\, (B - A)\, h \right)\, \frac{dh}{dv}[/tex].
[tex]\displaystyle \frac{dh}{dv} = \frac{1}{\displaystyle A\, L + \frac{L}{H}\, (B - A)\, h}[/tex].
Let [tex]t[/tex] denote time. It is given that the trough is being filled at a rate of [tex]0.2\; {\rm m^{3}\cdot min^{-1}}[/tex]. In other words:
[tex]\displaystyle \frac{dv}{dt} = 0.2\; {\rm m^{3}\cdot min^{-1}}[/tex].
Apply the chain rule to find the rate at which [tex]h[/tex] is changing with respect to time [tex]t[/tex]:
[tex]\begin{aligned} \frac{dh}{dt} &= \frac{dh}{dv}\cdot \frac{dv}{dt} \\ &= \frac{1}{\displaystyle A\, L + \frac{L}{H}\, (B - A)\, h}\cdot \frac{dv}{dt} \end{aligned}[/tex].
Substitute in [tex]A = 0.30\; {\rm m}[/tex], [tex]L = 10\; {\rm m}[/tex], [tex]H = 0.50\; {\rm m}[/tex], [tex]B = 0.80\; {\rm m}[/tex], [tex]h = 0.30\; {\rm m}[/tex] (converted from [tex]30\; {\rm cm}[/tex]), and that the rate of change in [tex]v[/tex] is [tex]0.2\; {\rm m^{3}\cdot min^{-1}}[/tex]:
[tex]\begin{aligned} \frac{dh}{dt} &= \frac{dh}{dv}\cdot \frac{dv}{dt} \\ &= \frac{1}{\displaystyle A\, L + \frac{L}{H}\, (B - A)\, h}\cdot \frac{dv}{dt} \\ &= \frac{0.2\; {\rm m^{3}\cdot min^{-1}}}{\displaystyle 0.30\; {\rm m} \times 10\; {\rm m} + \frac{10\; {\rm m}}{0.60\; {\rm m}}\, (0.80\; {\rm m} - 0.30\; {\rm m}) \, 0.30\; {\rm m}} \\ &=0.033\; {\rm m\cdot min^{-1}} \end{aligned}[/tex].
In other words, the depth of the water in this trough increases at a rate of approximately [tex]0.033\; {\rm m \cdot min^{-1}}[/tex] (meters per minute.)
a uniform meter stick is suspended from the ceiling by a string attached to the 60. cm mark. a 0.050 kg mass placed at 90. cm mark causes the meter stick to balance in the horizontal position. find the mass of the meter stick.
The mass of the meter stick is 0.15 kg.
The parameter
Meter Stick length = 100 cmA string attached to the 60 cmMass = m = 0.05 kgA mass placed at 90 cmAcceleration due to gravity = 10 m/s²Calculate the weight of the mass.
w = mg
w = [tex]0.05 \times 10[/tex]
w = 0,5 N
Look at the picture. The weight of the stick is in the middle of its length at 50 cm. The meter stick is balanced in the horizontal position. At point A
Distance between mass and string = 90-60 = 30 cmDistance between weight of the stick and string = 60-50 = 10 cmΣ τ = 0
(ws × 10) - (w × 30) = 0
ws × 10 = w × 30
ws × 10 = 0.5 × 30
ws × 10 = 15
[tex]w_s = \frac{15}{10}[/tex]
ws = 1.5 N
ms × 10 = 1.5
[tex]m_s = \frac{1.5}{10}[/tex]
ms = 0.15 kg
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An object i aid to be poitively charged if it number of electron i greater than the number of proton
An object I aid to be positively charged if it has a number of electrons i greater than the number of protons. TRUE
If an object has extra protons than electrons, then the internet fee on the item is fantastic. If there are extra electrons than protons, then the net charge at the item is bad. If there are equal numbers of protons and electrons, then the object is electrically impartial.
An electrical price is created while electrons are transferred to or removed from an object. because electrons have a bad charge, while they are added to an item, it turns negatively charged. when electrons are removed from an object, it will become undoubtedly charged.
A positively charged object has misplaced electrons. A definitely charged object has won protons. A negatively charged item has lost protons. If the variety of electrons is greater than the range of protons, the particle is a negative ion, also referred to as an anion.
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Disclaimer:- your question is incomplete, please see below for the complete question.
An object I aid to be positively charged if it has a number of electrons i greater than the number of a proton. TRUE/FALSE
9. Determine the total capacitance between points A and B. D н А- В с E с C C с с с c
Answer:
Determine the total capacitance between points A and B in the figure below. C =104F C = 5uF C=20uF MAE ce Select the best answer: 2.84uF 2.80uF O 2.90pF 2.86F
Explanation:
hoped it help cutie if u need more help js ask meh
what is the compressive stress exerted on the soles of your feet by your body weight? assume that each foot has a contact area of 200 cm2, the stress spreads out evenly over that area and that your mass is 72 kg.
The stress that spreads over the soles of the feet by the body is 18000 N/m².
The compressive stress exerted on a body is given by the force applied to the body divided by the area,
So, we can write,
Stress = force/area
In this case, the force will be equal to the weight of the body.
F = Mg
M is the mass of the person,
g is the acceleration due to gravity.
F = 72×10
F = 720N
The area of the soles is given to be 200 cm²
Converting into meter square,
Area = 0.02 m²
As there are two soles,
Area = 0.04
Putting values to find stress,
Stress = 720/0.04
Stress = 18000N/m²
So, the stress on the soles is 18000 N/m².
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Please someone help!! I don’t know how to figure this out!
Answer:
relax
Explanation:
your answer is right there in front of you force = weight
area of feet = area
while your pressure = force per unit area i.e
force/area = 600/0.03
= 2 × 10⁵
The graph shows the displacement of a mouse
What is the farthest position the mouse reaches inside the tunnel?
7 meters into the tunnel
4 meters into the tunnel
3 meters into the tunnel
It cannot be determined from the information given
The farthest position the mouse reaches inside the tunnel is 4 meters into the tunnel.
From the graph,
The positions reached after,
5 s = 4 m
10 s = 2 m
20 s = 2 m
35 s = 3 m
40 s = 0 m
So the farthest position here is 4 m into the tunnel.
The rate of change of positions is displacement. So displacement will be change in initial and final positions divided by change in time.
s = Δx / Δt
Therefore, the farthest position the mouse reaches inside the tunnel is 4 meters into the tunnel.
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two parallel metal plates are 5 cm apart and have equal surface charge densities of 9 nc/m2 of opposite signs on their inner surfaces. what is the electric field between the plates?
1.01 x 10³ C/m² is the electric field present between the two metal plates.
The electric field is defined as the region around a charged particle or charged body in which if another charge is placed experiences an electrostatic force.
The electric field inside two equal and opposite charged plates is given by
E = σ / ε ------ equation 1
here σ is the surface charge density = 9 x 10⁻⁹ C/m²
ε = Dielectric permittivity = 8.85 x 10⁻¹² C²/Nm²
Putting the values in equation 1
E = 9 x 10⁻⁹ / 8.85 x 10⁻¹²
=> 1.01 x 10³ N/C
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What is the potential difference measured if the following voltmeter (refer to picture) is used and connected to the circuit via the 3V terminal?
Since the meter's 3V terminals are connected to the circuit, we have to read the "zero-to-3" scale on the meter to get our measurement. That's the scale under the marks.
On that scale, the needle points to 1.4 DC Volts. That's the potential difference between the two points the meter probes are touching.
at a location in europe, it is necessary to supply 1000 kw of 60-hz power. the only power sources available operate at 50 hz. it is decided to generate the power by means of a motor- generator set consisting of a synchronous motor driving a synchronous generator. how many poles should each of the two machines have in order to convert a 50-hz power to 60 hz?
The number of poles that the two machines should have in order to convert a 50-hz power to 60-hz is a 10 pole synchronous motor must be coupled to a 12-pole synchronous generator.
n = 120 f / P
n = Speed of synchronous machine
f = Frequency
P = Number of poles
For motor,
f = 50 Hz
n = 120 * 50 / Pm
For generator,
f = 60 Hz
n = 120 * 60 / Pg
To accomplish the frequency conversion, the speed of the motor and generator must be equal. So,
120 * 50 / Pm = 120 * 60 / Pg
Pg / Pm = 6 / 5
Pg / Pm = 12 / 10
Therefore, to accomplish the frequency conversion, a 10 pole synchronous motor must be coupled to a 12 pole synchronous generator.
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compared to the flow of water in streams, most ground water moves relatively slowly. group of answer choices true false
Most ground water will move rather slowly when compared to how fast water moves in streams.
The statement is true
Why does water movement matter?Water quantity both affect flow. It is significant because it affects the habitats of living things in the stream as well as the water quality. Small streams are less able to dilute and degrade contaminants than large, fast running rivers, which can receive pollution releases with little impact.
How do we define flow?To "flow" is to move in a stream, just like water. As air circulates, the word "flow" also signifies to move. Flow is a noun that refers to motion that resembles a stream. The noun and verb 'flow' can be used in a variety of various contexts. Something flows when it moves like a stream of water.
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a light bulb consumes energy at a rate of . how long in will it take for the light bulb to consume in energy?
It will take the lightbulb 2875 seconds to use 2.3×10⁵J of energy.
Why does power matter?Power is the amount of work completed in a given amount of time, or time spent working. The joules per second (J/s)-based SI unit of power is the Watt (W).
Given,
Power (P) = 80 J/s
Energy (E) = 2.3×10⁵ J
Time (t) = ?
The pace at which energy is utilized is a straightforward definition of power. Power can be mathematically stated as:
Energy x time equals power
P = E/t
We can calculate the time it takes for the bulb to use 2.3 105 J using the formula above. This is attainable as follows:
Power (P) = 80 J/s
Energy (E) = 2.3×10⁵ J
Time (t) = ?
Power = Energy / time
P = E/t
80 = 2.3×10⁵ /t
80 × t = 2.3×10⁵
Divide both side by 80
t = 2.3×10⁵ / 80
t = 2875 s
As a result, it will take the lightbulb 2875 seconds to use 2.3×10⁵J of energy.
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Complete question is "A light bulb consumes energy at a rate of 80joules per second . How long in seconds will it take for the light bulb to consume 2.3×10⁵in energy?".
an atwood's machine (see the figure below) consists of two masses: one of mass 4.93 kg and the other of mass 11.9 kg. when released from rest, what is the acceleration of the system? (enter the magnitude in m/s2.)
Using the concepts of atwood machine, we got 4.05m[tex]s^{-2}[/tex]. is the acceleration of system when released from rest.
We know very well that in atwood`s two bodies having different mass are hanged around the pulley.
The accceleration of the atwood is given by :
a=((m2-m1)/(m2+m1))×g, where m2 is the mass of heavier body,m1 is the mass of lighter body and g is the acceleration due to gravity.
So, according to question m2=11.9,m1=4.93 and g=9.8
So, on putting the value in above formula, we got
a=[(11.9-4.93)/(11.9+4.93)]×9.8
=>a=[(6.97)/(16.83)]×9.8
=>a=4.05m[tex]s^{-2}[/tex].
Hence, an atwood machine in which two masses: one of mass 4.93 kg and the other of mass 11.9 kg. when released from rest, the acceleration of the system is 4.05m[tex]s^{-2}[/tex].
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two resistors are connected in series across a constant voltage source without internal resistance. another resistor is added in series to the other two resistors. what happens to the power supplied by the source?
Adding a third resistor in series with two resistors connected across a constant voltage source without internal resistance will cause the power supplied by the source to decrease.
The reason is that adding the extra resistor will increase the total resistance and decrease the current through all three resistors. The new total resistance is: Rtot = R1 + R2 + R3
And as we see from Ohm's Law, V/I = R, so we can also express this as: V2/I2 + V1/I1 + V3/I3 = V4/I4.
From here, we can see that when we add a third resistor in series with two others, we have more voltage across each individual part of our circuit, but less current flowing through each part of it. That means our total power supplied by the source decreases because there is less current flowing through all three resistors combined.
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