A is located at (-4,-2), B is located at (4, 4), C is located at (5,0) and D is located at 1-3,2). Classify ABCD andgive the justification for your classification.

Answers

Answer 1

The coordinates are to be placed in quadrants.

Since A is negative x ( -4 ) and negative y ( -2 ), then A is in the third quadrant because in the third quadrant ( -x, -y ) is the coordinate.

Since B is positive x ( 4 ) and positive y ( 4 ), then B is in the first quadrant because the first quadrant is (x, y ) coordinate.

C is therefore in the first quadrant since both of its values are positive.

D is in the 2nd quadrant since it has a negative x and positive y.

A Is Located At (-4,-2), B Is Located At (4, 4), C Is Located At (5,0) And D Is Located At 1-3,2). Classify
A Is Located At (-4,-2), B Is Located At (4, 4), C Is Located At (5,0) And D Is Located At 1-3,2). Classify

Related Questions

Select the interval (6,100) as an inequality and using set notation.

Answers

We are given the following interval:

(6,100].

This means that we want values greater than 6(since the interval is open at 6 it is not part of the interval) and lesser than or equal to 100(since the interval is closed at 100 it is part of the interval).

Inequality:

Greater than 6 and lesser than or equal to 100 is represented by the following inequality:

[tex]6Set notation:

Similar to the inequality, just with a prior notation.

[tex]\left\lbrace x\right|6

Write an equation that represents each side of the figure.please help as soon as possible.

Answers

EXPLANATION:

The correct equation is the one formulated below since we can see that two of its sides have the same measure, therefore, looking at the coordinates well, we have the following formula.

EQUATION:

[tex]\begin{gathered} 5x^2-1y^2^{} \\ \end{gathered}[/tex]

Do not round any intermediate computation, and round your final answer to the nearest cent.

Answers

SOLUTION:

Case: Simple interest

Method:

P= $5100

R= 6.5% or 0.065 annual rate

T= 365 days.

1. The formula for simple Interest is:

[tex]I=PRT[/tex]

Therefore:

[tex]\begin{gathered} I=5100\times0.065\times\frac{365}{365} \\ I=331.50 \end{gathered}[/tex]

The Interest, I= $331.50

2. The Amount, A

[tex]\begin{gathered} A=P+I \\ A=5100+331.50 \\ A=5431.50 \end{gathered}[/tex]

The Amount A= $5431.50

Find one positive AND one negative angle that are co-terminal with the given angle.π/3Be sure to label and leave your answers in radians (not degrees).

Answers

One positive angle:

[tex]\frac{\pi}{3}+2\pi=\frac{7\pi}{3}[/tex]

One negative angle:

[tex]\frac{\pi}{3}-2\pi=-\frac{5\pi}{3}[/tex]

6. Which point is the midpoint of AE?1BСE8 7 6 5 4 3 2 1 01234S678A. CB. BC. not B, C, or DD. D

Answers

we have that

the x-coordinate of A is -6

the x-coordinate of E is 6

so

the midpoint of AE is

(-6+6)/2=0

therefore

the midpoint is point C

answer is option A

CalculatorIn the coordinate plane, what is the length of the line segment that connects points at (4, -1) and (9, 7)?Enter your answer in the box. Round to the nearest hundredth.units1 2 3 45 6 7 8

Answers

The formula to calculate the distance between two points is given by

[tex]d=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}[/tex]

In this problem, we have the coordinates

(4, -1) and (9, 7)

substitute in the formula

[tex]\begin{gathered} d=\sqrt{(7+1)^2+(9-4)^2} \\ d=\sqrt{8^2+5^2} \\ d=\sqrt{89} \\ d=9.43 \end{gathered}[/tex]The answer is 9.43 units

My phone went dead I am plugged back in now I need to know how to fix this problem out

Answers

We have that

[tex]8\times10^8=800000000[/tex]

So the answer is the first one.

(4x2 – 2x + 1) – (5x2 – 7x - 5 )

Answers

,We have the next expression

[tex](4x^2-2x+1)-(5x^2-7x-5)[/tex]

First we will multiplicate the sign minus with the trinomial (5x^2 – 7x - 5 )

[tex]4x^2-2x+1-5x^2+7x+5[/tex]

then we can sum like terms and we obtain the solution

[tex]-x^2+5x+6[/tex]

i need help who know how to do this ?

Answers

The total amount needed for the equipment is $350.

The number of students on the team is x students.

To find the amount required per student, consider that each student will pay equally. Therefore, the amount can be gotten by division.

Hence, the amount per student can be gotten as:

[tex]\Rightarrow\frac{\text{Amount}}{\text{Number of Students}}[/tex]

This then becomes, by substitution:

[tex]=\frac{350}{x}[/tex]

The correct answer is OPTION C.

Sarah started a stamp collection with 12 stamps. She will buy 75 stamps each monthfor a certain number of months to add to her collection. After how many months willSarah have at least 200 stamps?

Answers

initial stamps = 12

Stamps bought per month = 75

number of moths = x

So the expression for the total number of stamps(y)

y =12+75x

To have 200 stamps replace y by 200 and solve for x (months)

200 = 12+75x

200-12 = 75x

188 =75x

188/75 =x

2.5 = months

2.5 months (2 and a half)

I need help with a question

Answers

k is the midpoint of JL

KL= 7n+ 10

JL= 76

Since k is the midpoint, then;

JK = KL = 7n + 10

Also

JL = JK + kL

76 = (7n + 10) + (7n+10)

76 = 7n + 10 + 7n + 10

76 = 14n + 20

subtract 20 from both-side of the equation

76 - 20 = 14n

56 = 14n

divide both-side of the equation by 14

56/14 = n

4 = n

n = 4

JK= 7n + 10 = 7(4) + 10 = 28 + 10 = 38

KL=JK=38

KL=38

The country of Whoville has export sales of $9 billion, government purchases of $1,022 billion, business investment is $42 billion, imports are $28 billion, and consumption spending is $1,945 billion. What is the value of GDP in billions of dollars?

Answers

Answer

The GDP of Whoville is $2990 billion

Step-by-step explanation:

The formula for calculating GDP is given as

GDP = C + G + I + NX

Where, C = all private consumption

G = All government spending

I = Investment by businesses

NX = The country's net export

The net export = total export - total import

Total export = $9 billion

Total import = $28 billion

The net export = ($9 - $28) billion

The net export = - $19 billion

GDP = [($1945 + $1022 + $42 + (- $19)] billion

GDP = ($1945 + $1022 + $42 - $19)

GDP = $2990 billion

Hence, the GDP of Whoville is $2990 billion

A gas tank of a car has a volume of 72.4 dm3. Find how many kiloliters of gas it would take to completely fill the gas tank.

Answers

Given:

Volume = 72.4 dm³

Hence:

[tex]72.4\text{ }dm^3\times\frac{1kL}{1000\text{ }dm^3}[/tex]

ANSWER

0.0724 kL, would completely fill the gas tank.

Identify the constant difference for a hyperbole with foci (-3, 0) and (3, 0) and a point on the hyperbola (7, 0)A. 14B. 6C. 10D. 2

Answers

Answer:

Explanations:

Let the coordinates of the focus(-3, 0) be:

x₁ = -3, y₁ = 0

Let the coordinates of the focus(3, 0) be:

x₂ = 3, y ₂ = 0

Let the coordinates of point(7, 0) be:

x₃ = 7, y₃ = 0

Let the distance between the Focus(-3, 0) and (7, 0) be d₁

[tex]\begin{gathered} d_1=\text{ }\sqrt[]{(x_3-x_1)^2+(y_3-y_1)^2} \\ d_1=\text{ }\sqrt[]{(7-(-3))^2+(0-0)^2} \\ d_1=\text{ }\sqrt[]{10^2} \\ d_1=\text{ 10} \end{gathered}[/tex]

Let the distance between the Focus (3, 0) and (7, 0) be d₂

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how many solutions does y=2x^2-3x+5

Answers

When we have a polynomial, the amount of solutions for a polynomial is given by its degree, and the degree of the polynomial is given by the biggest exponent in the polynomial. Our polynomial is

[tex]y=2x^2-3x+5[/tex]

The biggest exponent is 2, therefore this is a 2nd degree polynomial. This means this polynomial has 2 solutions.

I am really struggling and if anyone can help with these problems it would mean the world I need to get them done and I need to be eligible for sports please and thank you a lot solve question number 1

Answers

Explanation

The area and circumference of a circle can be seen below.

[tex]\begin{gathered} \text{Area}=\pi r^2 \\ \text{Circumference}=2\pi r \end{gathered}[/tex]

From the image, the diameter of the circle is given as;

[tex]d=16.6m[/tex]

Recall;

[tex]\text{radius(r)}=\frac{\text{diameter}}{2}=\frac{16.6}{2}=8.3m[/tex]

Hence;

[tex]\begin{gathered} \text{Area}=\pi\times8.3^2=216.4m \\ \text{Circumference = 2}\times\pi\times8.3=52.2m \end{gathered}[/tex]

Answer:

[tex]\begin{gathered} A=216.4m \\ C=52.2m \end{gathered}[/tex]

Solve 19x-9 ≥ - 1 + 6x

Answers

In order to solve this inequality, let's put all terms with x on the same side of the inequality, add the like terms and divide both sides by the coefficient of x.

So we have:

[tex]\begin{gathered} 19x-9\ge-1+6x \\ 19x-6x\ge-1+9 \\ 13x\ge8 \\ x\ge\frac{8}{13} \end{gathered}[/tex]

Therefore the solution is x >= 8/13

What does b equal to in this equation 88 = x(0) + b?

Answers

[tex]\begin{gathered} 88=x(0)+b \\ b=88 \end{gathered}[/tex]

answer: b= 88

A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll, n=1086 and x=571 who said "yes." Use a 99% confidence level. A) Construct the confidence interval._ < p <_ (round to three decimal places.)

Answers

The given information is:

n=1086

x=571

Confidence level 99%

First, we need to find the sample proportion. It is given by the formula:

[tex]\hat{p}=\frac{x}{n}[/tex]

By replacing the known values, we obtain:

[tex]\hat{p}=\frac{571}{1086}=0.526[/tex]

Now, the confidence interval is given by:

[tex]\begin{gathered} \hat{p}-E

Where z* is the z-value for the confidence level. As the C.L=99%, then z is:

[tex]\begin{gathered} z^*_{\frac{\alpha}{2}}\rightarrow\frac{\alpha}{2}=0.99+\frac{1-0.99}{2}=0.99+\frac{0.01}{2}=0.995 \\ \\ And\text{ z for 0.995 is} \\ z^*=2.576 \end{gathered}[/tex]

Now, replace this value into the formula and solve:

[tex]\begin{gathered} E=2.576\sqrt{\frac{0.526(1-0.526)}{1086}} \\ \\ E=2.576\sqrt{\frac{0.249}{1086}} \\ \\ E=2.576\sqrt{0.0002} \\ \\ E=2.576*0.015 \\ \\ E=0.039 \end{gathered}[/tex]

The confidence interval is then:

[tex]\begin{gathered} 0.526-0.039

The answer is above.

(G.11b, 1 point) Two chords intersect with the measures shown in the drawing. What is the value of x? 5 6.5 8 O A. 2.2 O B. 6.2 0 C. 8.0 OD. 13.5

Answers

The value of x is 6.2

Here, we want to find the value of x

To do this, we use the theorem of intersecting chords

By this theorem, the products of the two sides of two chords which intersects are the same

Mathematically, we have this as follows;

[tex]\begin{gathered} 5\text{ }\times\text{ 8 = 6.5 }\times\text{ x} \\ \\ 40\text{ = 6.5x} \\ \\ x\text{ = }\frac{40}{6.5} \\ \\ x\text{ = 6.15 which is approx. 6.2} \end{gathered}[/tex]

Write the equation in slope-intercept form and then graph the equation that passes through (-4, -1) and is parallel to to y = −1/2x + 1

Answers

The general slope-intercept form of a linear equation is:

[tex]y=mx+b[/tex]

----------------------------------------

You have a linear equation parallel to:

[tex]y=-\frac{1}{2}x+1[/tex]

That means that both equations have the same slope

m= - 1/2

If the equation passes through (-4 , -1) we can use that point to find the value of the b in the slope-intercept form:

(-4 , -1) x= - 4 y= - 1

[tex]-1=-\frac{1}{2}(-4)+b[/tex]

We clear the b:

[tex]-1=\frac{4}{2}+b[/tex][tex]-1=2+b[/tex]

Then you know the values of

m=-1/2

b=-3

The equation in slope-intercept form is:

[tex]y=-\frac{1}{2}x-3[/tex]

To graph a linear equation you need two point, as you have (-4, -1) and the point of the y-intercept that is (0,b) = (0,-3)

You put in the plane the two points:

And you draw a line that link the two points to get the final graph:

solve the proportion below for X. Do not round your answer

Answers

Step 1:

Let us write out the proportion question,

[tex]\frac{5}{x}=\frac{10}{3}[/tex]

Step 2:

Cross multiply,

[tex]\begin{gathered} 5\times3=10\times x \\ 15=10x \end{gathered}[/tex]

Step 3:

Divide both sides by 10

[tex]\begin{gathered} \frac{15}{10}=\frac{10x}{10} \\ 1.5=x \\ \text{Hence,} \\ x=1.5 \end{gathered}[/tex]

Hence, x= 1.5.

are each of those congruent and if so what is there postulate

Answers

ANSWERS

a. Yes, congruent. By SSS postulate

b. Yes, congruent. By AAA postulate

c. Yes, conguent. By SAS postulate

EXPLANATION

a. Sides MQ and MN are congruent as shown in the diagram. So are sides PN and PQ. Side PM is shared by both triangles so it must be congruent to both.

b. It is shown in the diagram which angles are congruent:

c. Angles DEC and AEB are vertical angles and they are therefore congruent. The two sides that form those angles are shown congruent in the diagram, so we have a side, the next angle and the next side: SAS postulate.

Jack is making a scale drawing of his house. He has decided to use a scale of 1 in.: 100 m. If a part of his house is 20 m long, what will be the length of this part on his scale drawing?

Answers

we can use cross-multiplication

[tex]\begin{gathered} 1\longrightarrow100 \\ x\longrightarrow20 \end{gathered}[/tex]

where x is the measure we need

[tex]\begin{gathered} x=\frac{20\times1}{100} \\ x=0.2 \end{gathered}[/tex]

so, the measure is 0.2 in

PLEASE HELPWrite a word problem for 7×9

Answers

There are 7 cans of food. Each can contains 9 grams of food.

How much is the total food (in grams)

how would I solve this problem with synthetic division and graph it without a calculator?

Answers

[tex]\begin{gathered} x^4-11x^2-18x-8\text{ has factor of (x+2) and (x+1) with multiplicity 2. This means that} \\ \text{the polynomial could be divided by} \\ (x+2)(x+1)^2=(x+2)(x^2+2x+1) \\ (x+2)(x+1)^2=x^3+2x^2+x+2x^2+4x+2 \\ (x+2)(x+1)^2=x^3+4x^2+5x+2 \end{gathered}[/tex][tex]\begin{gathered} from\text{ the synthetic division, we obtain that} \\ x^4-11x^2-18x-8=(x+2)(x+1)^2(x-4) \end{gathered}[/tex][tex]do\text{ you have questions?}[/tex]

A community center is holding a raffle. The table below shows the number of tickets purchased and total price paid for three different people. Who paid the highest price per ticket?

Answers

The person that paid the highest price per ticket is A.

How to calculate the price?

From the information, the following can be deduced:

Person A price per ticket

= Total price / Number of ticket

= 191 / 3

= $63.7 per ticket

Person B price per ticket

= Total price / Number of ticket

= 309/5

= $61.8 per ticket

Person C price per ticket

= Total price / Number of ticket

= 435/8

= $54.4 per ticket

In this case, A paid the highest price based on the calculation above.

Learn more about price on:

brainly.com/question/1153322

#SPJ1

Answer: A

Step-by-step explanation:

Khan

systems of equations homework (b) graph these equations to solve the system

Answers

Answer

a) Option A

y = 2x + 10

Option B

y = 3x

b) Option A is represented with the red line and Option B is represented by the blue line.

Total Cost is presented on the y-axis and the Number of rides is presented on the x-axis.

The graph is presented below.

From this graph, we can see that the two lines cross at (10, 30)

So, the two options will have the same rides and the same total cost when

x = 10 rides

y = 30 dollars

Explanation

There are two options to consider,

Let the amount to be paid be y

Let the number of rides be x

Option A

Each ride costs $2

x rides will cost 2x dollars

Activation fee = 10 dollars

Total cost = y

y = 2x + 10

Option B

Each ride costs $3

x rides will cost 3x dollars

Activation fee = 0

Total cost = y

y = 3x

So, we end up with a system of equation for when the number of rides and the total cost for both options become the same

y = 2x + 10

y = 3x

b) We are asked to solve this system of equations by graphing.

To do this, we will first plot the two lines for each equation, then the solution will be where the two lines cross each other.

We will use intercepts to plot the first line

y = 2x + 10

when x = 0,

y = 2x + 10

y = 2(0) + 10

y = 0 + 10

y = 10

First point on this line is (0, 10)

when y = 0

y = 2x + 10

0 = 2x + 10

-2x = 10

Divide both sides by -2

(-2x/2) = (10/-2)

x = -5

Second point on the line is (-5, 0)

For the second option

y = 3x

when x = 0

y = 3x

y = 3(0)

y = 0

First point on this line is (0, 0)

when x = 1

y = 3x

y = 3(1) = 3

Second point on the line is (1, 3)

We will now plot each of the lines by connecting each of the two points obtained for each line.

Hope this Helps!!!

Can someone please help? I’m unsure how to go about this.

Answers

Okay, here we have this:

Considering the provided information, we are going to calculate the requested interval, so we obtain the following:

Then we will assume that the unknown number is x:

-26<2x-2<30

-26+2<2x<30+2

-24<2x<32

-24/2-12(-12, 16)

Finally we obtain that the interval solution is (-12, 16).

Find all solutions to the equation 4ln(5x)+5=2. Show your work.

Answers

Given the equation:

[tex]4\ln \mleft(5x\mright)+5=2[/tex]

We will find the value of (x) as follows:

a) subtract 5 from both sides

[tex]\begin{gathered} 4\ln \mleft(5x\mright)+5-5=2-5 \\ 4\ln \mleft(5x\mright)=-3 \end{gathered}[/tex]

b) Divide both sides by 4

[tex]\ln (5x)=-\frac{3}{4}[/tex]

c) Taking the exponential of both sides to remove ln

[tex]5x=e^{-\frac{3}{4}}[/tex]

Finally, divide both sides by 5

[tex]x=\frac{1}{5}e^{-\frac{3}{4}}\approx0.09447[/tex]

So, the answer will be x = 0.09447

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