A lamp is 15% efficient. How much electrical energy must be supplied to the lamp each second if it produces 30 J of light energy per second? *WILL MARK BRAINLIEST*

Answer:

Almost winter so fall

Explanation:

Hope this helps! Please let me know if you want me to elaborate more or think my answer is incorrect. Brainliest would be MUCH appreciated. Have a wonderful day!

Answer:

Beaker

Graduated Cylinders

Volumetric flask

Test tube

Funnel

Answer:

Power, technique, and timing

Explanation:

I just did the quiz and it was correct!! Hope this helps!

For two horses pull horizontally on ropes attached to a stump, the magnitude of F and its direction is mathematically given as

F=1711 N

dF= 135 degrees

Generally, the equation for the components of F1   is mathematically given as

For The x axis

1210 - F2x = 0

F2x = 1210

For the y axis

F2y = R

F2y = 1210

In conclusion

F = sqrt(2)*1210

F=1711 N

Fopt the direction of F2

dF= 90 + 45

dF= 135 degrees

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Answer:

100 kg

Explanation:

Net force = 350 - 50 = 300 N

F= ma

300 N  = m * 3 m/s^2

100 kg = mass

Required Answer:

Given:

(A)

As we know that,

↠ Current = 75/120

↠ Current = 0.625 A

(B)

Here,

↠ Resistance = 120/0.625

↠ Resistance = 192 Ω

(C)

Here,

↠ Energy = 75 × 1

↠ Energy = 75 J

Answer:

Explanation:

Assuming there is no friction or other force involved, recall that energy is conserved in a system as long as no external force acts on the system.

Using the data from point C, we can find out that the total energy of the system is 156 because  [tex]E = K+Pe[/tex].

Since at point A the object doesn't move, it has Kinetic energy of 0, because [tex]K=\frac{1}{2} mv^2[/tex], therefore [tex]0=\frac{1}{2} m0^2[/tex]. However at point A it has maximum Potential energy, because [tex]Pe=mgh[/tex].

At point B, we can find the Kinetic energy by using [tex]E = K+Pe[/tex]. Substitute values:

[tex]156=104+K\\52=K[/tex]

At point D, the object has maximum kinetic energy and no potential energy, therefore it's the opposite of point A.

Answer:

1) asking a question about something you observe, 2) doing background research to learn what is already known about the topic, 3) constructing a hypothesis, 4) experimenting to test the hypothesis

Answer:

1) make an observation that describes a problem - see something you can fix or improve and try to describe the problem like which type of vegetables does rabbit like

2) create a hypothesis - What do you think will happen - If the rabbit eat the lettuce than .........

3) test the hypothesis - Do your experiment with the variables and follow the procedures

4) draw conclusions and refine the hypothesis - see if your hypothesis was correct - In conclusion my hypothesis was not correct because.......

Answer:

First the charge is given 7.50×10^-6

Explanation:

so that we have

[tex]90 [/tex]

then the direction is one is left and other one is right so thats my hint

Hi there!

[tex]\Phi _B = \int B \cdot dA[/tex]

φ = Magnetic Flux (Wb or Tm²)
B = Magnetic field strength (T)
A = Area (m²)

This equation includes a dot product, so this can be rewritten as:

[tex]\Phi _B = B A cos\theta[/tex]

In this instance, the field is parallel to the area, so cos(0) = 1.

Calculate the magnetic flux by plugging in the given values.

[tex]\Phi _B = BA = 0.114 * 0.065 = \boxed{0.00741 Wb}[/tex]

Answer:

real kinetic theory means that kinetic energy

average velocity= tot displacement/total time

avg v = 20/(20+60+5+10+5)=20/100=0.2 m/s

Answer:

The answer is in the picture above.

The magnitude of emf induced in the single coil of wire rotated in the uniform magnetic field is 0.171 V.

The emf induced in the loop is determined by applying Faraday's law of electromagnetic induction.

emf = N(dФ/dt)

where;

Ф = BA

where;

emf = NBA/t

A = πr²

A = π x (0.13)²

A = 0.053 m²

emf = NBA/t

emf = (1 x 3.746 x 0.053)/(1.16)

emf = 0.171 V

Thus, the magnitude of emf induced in the single coil of wire is 0.171 V.

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(a) The torque acting on the disk is 66 Nm.

(b) The moment of inertia of the disk is 0.05 kgm².

(c) The angular acceleration is produced by the torque is 1,320 rad/s².

(d) The final angular velocity of the disk is  3,960 rad/s.

(e) The angle of rotation of the disk is 5,940 rad.

The torque acting on the disk is calculated as follows;

τ = Fr

τ = 300 x 0.22

τ = 66 Nm

The moment of inertia of a solid disk is calculated as follows;

I = ¹/₂MR²

I = ¹/₂ x 2 x (0.22)²

I = 0.05 kgm²

The angular acceleration of the disk is calculated as follows;

τ = Iα

[tex]\alpha = \frac{\tau }{I} \\\\\alpha = \frac{66}{0.05} \\\\\alpha = 1,320 \ rad/s^2[/tex]

ωf = ωi + αt

ωf = 0 + (1320 x 3)

ωf = 3,960 rad/s

ωf² = ωi²+ 2αθ

(3,960)² = 0 + 2(1320)θ

θ = (3,960²) / (2 x 1320)

θ = 5,940 rad

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If electromagnetic radiation acted like particles in the double-slit experiment, we would observe one bright band would appear in the center of the screen.

In a double-slit experiment, single particles, such as photons, pass one at a time through a screen containing two slits.

The photons behave like wave and the constructive interfernce of the waves of these photons will generate a high amplitude wave seen as a bright band in the center of the screen.

Thus, if electromagnetic radiation acted like particles in the double-slit experiment, we would observe one bright band would appear in the center of the screen.

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Answer:

1.55 x 10⁷ m²

Explanation:

Unit conversion

Solving

Answer:

Explanation:

The velocity of sound from the plucked string in the tennis racquet is:

[tex]v=\sqrt{\frac{FL}{m}}=\sqrt{\frac{274(0.74)}{28}}\approx 2.69 ms^{-1}[/tex]

Then the frequency will be:

[tex]f=\frac{v}{2L}=\frac{2.69}{2(0.74)}\approx 1.81 Hz[/tex]

Box A has 2x the mass of Box B so Box A has more inertia as compared to Box B.

More the mass of an object, there is more inertia of the body. Thus, if mass of two bodies is same their inertia will also be same. Hence, inertia of A and B will be same as mass of both A and B are same.

So we can conclude that Box A has 2x the mass of Box B so Box A has more inertia as compared to Box B.

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[tex] \huge \mathbb \red{HEY \: THERE ♡}[/tex]

[tex] \huge \mathbb\pink{HOPE \: IT \: HELPS}[/tex]

(1) The time taken for the drag racer to accelerate is 4.89 s

(2) The speed of the contestant (a) in feet per second is 30.89 ft/s (b) in miles per hr is 21.12 miles per hr.

(1) To calculate the time required to accelerate 18 ft/sec² from rest to a velocity of 60 mph, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

(2) To calculate the speed of the contestant, we use the formula below

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

(a) In feet = (9.43/0.3048) = 30.94 ft/s

(b)  in miles per hr = (9.43×2.24) = 21.12 miles per hr

Hence, (1) The time taken for the drag racer to accelerate is 4.89 s (2) The speed of the contestant (a) in feet per second is 30.89 ft/s (b) in miles per hr is 21.12 miles per hr.

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Answer:

The π is from the initial formula of period T=2π/omega

Answer:

Current(I)= charge(q)/time

I=15/22

I=0.680.68A

Explanation:

Current is flow of charge per unit time. Always make sure the time is in seconds. istthe

The linear mass density of the rope in the given motion of the wave is 0.15 kg/m.

The linear mass density of the rope in the given motion of the wave is determined by dividing the mass of the rope with the length of the entire rope.

The linear mass density of the rope is calculated as follows;

μ = m/L

μ = 0.6 kg / 4 m

μ = 0.15 kg/m

Thus, the linear mass density of the rope in the given motion of the wave is 0.15 kg/m.

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Answer:

3 pi R / s     or   9.42 R/s    or  540 degrees/sec

Explanation:

Ball covers 2 pi radians each rotation

2 pi * 3 R / 2  s =   3 pi R / s

the angular speed of the ball is 3 pi R / s     or   9.42 R/s    or  540 degrees/sec

Angular speed can be defined as the measures of speed of how fast the central angle of a rotating body changes with respect to time

Angular speed mainly implies how quickly the rotation of an object occur means it is described as the change in the angle of the object per unit of time.

To calculate the speed of a rotational motion the angular speed value need to be known, hence  The angular speeds formula is used to calculate the distance traveled by an object in terms of rotation and revolutions per unit of time.

The unit of angular speed of an object is radian per second and Both angular speed, angular velocity are determined by using the same formula, angular velocity is  vector quantity which describes both magnitude and direction.

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Hi there!

We can begin by using Coulomb's Law:

[tex]E = \frac{kq}{r^2}[/tex]

k = Coulomb's Constant (8.99 × 10⁹ Nm²/C²)

E = Electric field strength (N/C)
r = distance from point (m)

q = charge (C)

Since this is a continuous charge, we must use calculus.

We can express this as the following:
[tex]q = \lambda L[/tex]

λ = Linear charge density (C/m)

L = Length of rod (m)

Now, since this is an arc, L = s (arc length). Additionally, we must find the differential elements of each:
[tex]dq = \lambda ds\\\\dq = \lambda rd\theta[/tex]

Our new equation is:
[tex]dE = \frac{kdq}{r^2}\\\\dE = \frac{k\lambda rd\theta}{r^2}[/tex]

However, we will only take the cosine component of the electric field since the vertical components will cancel out. (Electric fields are a vector). Therefore:
[tex]dE = \frac{k\lambda rd\theta}{r^2}cos\theta\\\\dE = \frac{k\lambda}{r}cos\theta d\theta[/tex]

Integrate. For a semicircle, the bounds will be from -π/2 to π/2.

[tex]E = \frac{k\lambda}{r}\int\limits^{\frac{\pi}{2}}_{-\frac{\pi}{2}}} {cos\theta} \, d\theta\\\\E = \frac{k\lambda}{r}sin\theta\left \|{\frac{\pi}{2}} \atop {-\frac{\pi}{2}}} \right. \\\\E = \frac{k\lambda}{r}(1 - (-1)) = \frac{2k\lambda}{r}[/tex]

We need to solve for λ, which is Q/ L:
[tex]\lambda = \frac{3.10 \times 10^{-9} C}{\pi (0.05)} = 1.9735 \times 10^{-8} \frac{C}{m}[/tex]

Now, plug and solve for the electric field strength:
[tex]E = \frac{2(8.99\times 10^9)(1.9735\times 10^{-8})}{0.05} = \boxed{7096.783 \frac{N}{C}}[/tex]

**A diagram was not provided, but if the hemisphere's focus was to the right, the electric field would be to the right, and etcetera.

A karate expert breaks a stack of bricks with his bare hand. If the force applied is 520 newtons and the impact time is [tex] \sf{5.0 \times 10^{-4}} [/tex] seconds, what is the value of impulse ?

So, the value of impulse is (A). 0.26 newton seconds.

Hi ! Here, I will help you about the impulse. Impulse is described as a quantity which expresses the integral of the amount force respect to time. The amount of impulse will be proportional to the amount of force or time (the greater  value of the force or the value of time, the value of impuls is greater too). The relationship between impulse, force, and time is expressed in this equation :

[tex] \boxed{sf{\bold{I = F \times \Delta t}}} [/tex]

With the following condition:

What was asked :

Step by step :

[tex] \sf{I = F \times \Delta t} [/tex]

[tex] \sf{I = 520 \times (5.0 \times 10^{-4}} [/tex]

[tex] \sf{I = 2,600 \times 10^{-4}} [/tex]

[tex] \sf{I = 2.60 \times 10^3 \times 10^{-4}} [/tex]

[tex] \sf{I = 2.60 \times 10^{3 + (-4)}} [/tex]

[tex] \sf{I = 2.60 \times 10^{-1} = \boxed{0.26 \: N.s}} [/tex]

So, the value of impulse is (A). 0.26 newton seconds

Answer:

out of the screen

Explanation:

because charge +Q is already moving upward