A linear function contains the following points. What are the slope and yintercept of this function? O A. O B. O C. O D. 25 The slope is 4. The yintercept is (5, O). The slope is —4. The yintercept is (O, 5). 1 The slope is Tthe yintercept is (O, 5). 1 The slope is . The yintercept is (O, 5).

A Linear Function Contains The Following Points. What Are The Slope And Yintercept Of This Function?

Answers

Answer 1

Answer:

D

Step-by-step explanation:

points (-4,4) and (0,5)

slope: (y2-y1)/(x2-x1)

(5-4)/(0+4) = 1/4

y intercept given: (0,5)


Related Questions

How many different ways can you write a ratio?

Answers

Answer:

3 different ways

Step-by-step explanation:

Answer:

3 different ways

Step-by-step explanation:

hope this helps

example of the diffrent way to write a ratio :

5 to 10

5 : 10

[tex]\frac{5}{10}[/tex]

The rectangle shown

Answers

The answer is C- 20

a^2 + b^2=c^2


Pls help really fast I don't know this!!!!!

Answers

I think it's (3,4) but I am not confident so please be understanding

Answer:

(3, 1 )

Step-by-step explanation:

The centre of the circle is at the midpoint of the diameter.

Given endpoint (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is

( [tex]\frac{x_{1}+x_{2} }{2}[/tex] , [tex]\frac{y_{1}+y_{2} }{2}[/tex] )

Here (x₁, y₁ ) = (9, 7) and (x₂, y₂ ) = (- 3, - 5 ) , then

midpoint = ( [tex]\frac{9-3}{2}[/tex], [tex]\frac{7-5}{2}[/tex] ) = ( [tex]\frac{6}{2}[/tex], [tex]\frac{2}{2}[/tex] ) = (3, 1 )

Thus centre of circle = (3, 1 )

The terminal side of Ø is in quadrant II and sin ø = 5/13 What is cos ø?

A. 5/12
B. -12/13
C. -5/12
D. 12/13

Answers

Step-by-step explanation:

In Quadrant II, cosine is negative.

We know that sin²x + cos²x = 1, so:

cosx = sqrt[1 - sin²x]

= sqrt[1 - (5/13)²]

= sqrt(144/169)

= -12/13 (since cosx is negative here)

The answer is -12/13. (B)

Option B is correct.

Quadrants and the "cast" Rule:In the first quadrant, the values for sin, cos, and tan are positive.In the second quadrant, the values for sin are positive only.In the third quadrant, the values for tan are positive only.In the fourth quadrant, the values for cos are positive only.

According to the given question

We have,  sin ∅ = 5/13

From the trigonometric identities we know that

[tex]sin^{2}[/tex]∅ + [tex]cos^{2}[/tex]∅ =1

substitute the value of sin∅ in the above identity

[tex](\frac{5}{13} )^{2} + cos^{2}[/tex]∅  =1

⇒ [tex]\frac{25}{69} +cos^{2}[/tex]∅  =1

⇒ [tex]cos^{2}[/tex]∅ = 1 - [tex]\frac{25}{169}[/tex]

⇒ [tex]cos^{2}[/tex]∅ = [tex]\frac{169-25}{69} =\frac{144}{169}[/tex]

⇒[tex]cos[/tex]∅ = [tex]\sqrt{\frac{144}{169} }[/tex]

⇒cos∅ = ±[tex]\frac{12}{13}[/tex]

Since, ∅ is in quadrant II, then cos<0

⇒ cos∅ = -[tex]\frac{12}{13}[/tex]

Hence, option B is correct.

Learn more about quadrant and cast rule here:

https://brainly.com/question/11099638

#SPJ2

Given g(x)=2x+3, solve for x when g(x)=3

Answers

Answer:

-3/2

Step-by-step explanation:

15. Write the first four terms of the sequence:
a. f(n) = −2[tex]n^{2}[/tex] + 4
b. f (1) = 7, f(n)= −4 ∙ f(n-1) − 1 + 15

Answers

Answer:

16 17

Step-by-step explanation:

write and equation of the line below ​

Answers

Answer:

y = 1/4x + 0 or just y = 1/4x

Step-by-step explanation:

First I need the slope so I look at the dots and see how much boxes it goes up and then to the side. So it’s up 2 to the side 8. The slope would be 2/8 but you can simply it by 2 and you get 1/4. And the y intercept is given its zero.

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