H.w. balance the following equations:
a) Iron + chlorine → Iron (iii) chloride
b) Nitrogen + hydrogen → Ammonia
c) Phosphoric acid + sodium carbonate → sodium phosphate + water + carbon dioxide
d) Nitrogen dioxide + water + oxygen → Nitric acid
Answer:
3iron + chlorine=iron3 chloride
nitrogen +3hydrogen
Answer:
a) Iron + chlorine → Iron (iii) chloride
3fe+cl__fe3cl
b) Nitrogen + hydrogen → Ammonia
2N+3h2------2NH3
c) Phosphoric acid + sodium carbonate → sodium phosphate + water + carbon dioxide
2H3PO3+3Na2CO3-----2Na3PO4+3H2O+3CO2
d) Nitrogen dioxide + water + oxygen → Nitric acid
NO2+H2O+O2--NOH
sorry if mistake
Describe how naturally
acidic rainwater can affect a
mountain of limestone.
Answer:
The naturally acidic rain will gradually wear the mountain of limestone away.
Hope it helps!
On the basis of the information above, a buffer with a pH = 9 can best be made by using
A pure NaH2PO4
B H3PO4 + H2PO4–
C H2PO4– + PO42–
D H2PO4– + HPO42–
E HPO42– + PO43
Answer:
D H2PO4– + HPO42–
Explanation:
The acid dissociation constant for [tex]\mathbf{H_3PO_4 , H_2PO^{-}_4 , HPO_4^{2-}}[/tex] are [tex]\mathbf{7\times 10^{-3}, \ \ 8\times 10^{-8} ,\ \ 5\times 10^{-13}}[/tex] respectively.
[tex]\mathbf{pka (H_3PO_4) = -log (7\times 10^{-3} )=2.2}[/tex]
[tex]\mathbf{pka (H_2PO_4^-) = -log (8\times 10^{-8} )=7.1}[/tex]
[tex]\mathbf{pka (HPO_4^{2-}) = -log (5\times 10^{-13} )=12.3}[/tex]
The reason while option D is the best answer is that, the value of pKa for both
[tex]\mathbf{H_2PO^{-}_4 ,\ \& \ HPO_4^{2-}}[/tex] lies on either side of the desired pH of the buffer. This implies that one is slightly over and the other is slightly under.
Using Henderson-Hasselbach equation:
[tex]\mathbf{pH = pKa + log \Big( \dfrac{HPO_4^{2-}}{H_2PO_4^-} \Big)}[/tex]
The compounds that are used for the formulation of the pH 9 buffer are [tex]\rm H_2PO_4^-\;and\;HPO_4^+[/tex]. Thus, option D is correct.
The buffers are the solutions of acids and base of appropriate pH, that are able to limit the change in pH in the reaction mixture.
Which compound is used for pH 9 buffer?The buffer pH is adjusted with the compounds that has been able to add base or acid to the solution.
For the formulation of buffer of specific pH, the acid and base solutions are required.
The compounds that are used for the formulation of the pH 9 buffer are [tex]\rm H_2PO_4^-\;and\;HPO_4^+[/tex], as they are able to provide acid and base to the solution.
Thus, option D is correct.
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What is the source of most of the salt in the oceans?
human activities adds salt into the ocean
O rivers and streams carry sediment containing salt to the ocean
O marine fish produce salt adding it into the ocean
wind blows the salt into the ocean
Which of the following statements about steroid hormones is true?
A. They bind with receptor proteins in the plasma membrane.
B. They bind to carrier proteins in order to be transported in the blood to
their target cells.
C. They are synthesized from epinephrine in the adrenal gland.
D. They are mostly derivatives of the amino acid tyrosine.
Answer:
B. They bind to carrier proteins in order to be transported in the blood to
their target cells.
Explanation:
Steroid hormones are belongs to the class of chemical compound called steroid. Steroid hormones are majorly secreted by three glands - ovaries, testes and adrenal cortex.
Steroid hormones are released in the blood and are allowed to bind to the specific carrier proteins such as corticosteroid-binding globulin and albumin which helps them to carry to the target cells for the functioning.
The steroid hormone binds to receptor proteins in the target cell and not in the plasma membrane
Hence, the correct answer is "B. They bind to carrier proteins in order to be transported in the blood to their target cells."
The yield for a particular well is 280 gallons per minute (gpm). Of the drawdown for this well is 23 feet, what is the specific yield in gpm/ft?
Answer:
[tex]Y=12.2 \frac{gpm}{ft}[/tex]
Explanation:
Hello!
In this case, since we can find that the well produces 280 gpm, and the given drawdown is 23 ft, we need to divide 280 by 23 to obtain the yield in gmp/ft as shown below:
[tex]Y=\frac{280gpm}{23ft} \\\\Y=12.2 \frac{gpm}{ft}[/tex]
Best regards!
what information is shown in the infographics?
Answer:
An infographic is a collection of imagery, charts, and minimal text that gives an easy-to-understand overview of a topic. As in the example below, infographics use striking, engaging visuals to communicate information quickly and clearly. Infographics are a valuable tool for visual communication.
1. How many molecules are in 4.5 moles?
Answer:
depends on what molecule you are looking for
Explanation:
In one mole of stuff (atoms, molecules, eggses), there are NA individual items of that stuff. So, there are 4.5 × NA BCl3 molecules; i.e. 4.5 × 6.022×1023 ≅ 27×1023 individual molecules of BCl3
Mass number 107 and 61 neutrons
Which of the following things would be the MOST irresistible for a dog?
A
a veterinarian
B
a fire hydrant
C broccoli vomit surprise
Answer:
B.a fire hydrant
hope it helps!
Answer:
a veterinarian
Explanation:
i think
The hybridisation of the central atom in ICL-2
a) sp.
b) sp2
c) sp3d d)sp3
Explanation:
For ICl²-, the central iodine atom is bonded to the 2 chlorine atoms and has 3 lone electron pairs.
Altogether it has 5 electron domains, which means it is sp3d hybridized. (C)
What is the half life of the graphed material?
Answer:
3 hours
Explanation:
To know the the correct answer to the question given above, it is important we know the definition of half-life.
The half-life of a substance is simply defined as the time taken for half the substance to decay.
Considering the diagram given above, the initial mass of the substance is 100 g.
Half of the initial mass = 100 / 2 = 50 g
Now, we shall determine the time from the graph taken to get to 50 g.
Considering the diagram given above, the time taken to get to 50 g is 3 hours.
Therefore, the half-life of the material is 3 hours.
5. Write the two resonance hybrids for the carbocation that would be formed by protonation at C-1 of 2-methyl-1,3-pentadiene. Without doing a calculation, would you expect C-2 or C-4 (the two end carbons of the allylic cation) to have the most positive charge on it
Answer:
Follows are the solution to this question:
Explanation:
Please find the complete solution in the attached file.
The temperature of an oxyacetylene torch flame can reach as high as 3137 °C. What is this temperature in Fahrenheit and Kelvin? Please show work.
Answer:
A)3410K
B)5678.6 °F
Explanation:
✓ To convert Celcius to Kelvin expression below can be used
K= °C + 273
We were given T=3137 °C
= 3137 + 273= 3410K
✓To convert Celcius to Fahrenheit, expression below can be used
°F =(°C × 9/5) + 32
We were given T=3137 °C
°F= (3137 × 9/5) + 32
= 5646.6+32
=5678.6 °F
Select the option that best represents recycling food waste
O turning food scraps into biogas
O donating unused food to food pantries
O incinerating leftover food
O feeding scraps to livestock
Answer:
feeding leftover or scraps to livestock
Explanation:
Because feeding leftover healthy food instead of leaving livestock to eat garbage is good for health of the animals and they give good quality of milk, eggs, meat, etc in return
10 points Part F
Identify at least two limitations of the simulation. How do these limitations influence the
simulation's ability to model the synthesis of ammonia?
Answer and Explanation:
When using simulations, it is important that the researcher knows some limitations. This is because the simulations do not behave exactly like what they represent, in addition to not presenting very important details for analysis and without approximations of what really happens with what they are representing. When modeling the synthesis of Ammonia, for example, these limitations can cause inaccuracies that will compromise the entire analysis.
When using simulations, it is important that the researcher knows some limitations. This is because the simulations do not behave exactly like what they represent, in addition to not presenting very important details for analysis and without approximations of what really happens with what they are representing. When modeling the synthesis of Ammonia, for example, these limitations can cause inaccuracies that will compromise the entire analysis.
MnO4 - is a stronger oxidizing agent than ReO4 - . Both ions have charge-transfer (LMCT) bands; however, the charge-transfer band for ReO4 - is in the ultraviolet, whereas the corresponding band for MnO4 - is responsible for its intensely purple color. Are the relative positions of the charge-transfer absorptions consistent with the oxidizing abilities of these ions? Explain
Answer:
[tex]$MnO^-_4$[/tex] is a strong oxidizing agent.
Explanation:
The 5d orbitals of Re are higher in energy than 3 d orbitals of Mn. So an LMCT ligand to metal charge transfer excitation requires more energy of [tex]$ReO^-_4$[/tex].
Also, since the molecular orbitals are derived primarily from 3d orbitals of [tex]$MnO^-_4$[/tex] are lower in energy than the corresponding MO's of [tex]$ReO^-_4$[/tex], [tex]$MnO^-_4$[/tex] is better able to accept the electrons.
So it is a better oxidizing agent.
The ligand to metal charge transfer band in ReO4- occurs in the near UV region hence ReO4 - appears colorless.
The electron configuration of Re is Xe 4f14 5d5 6s2 and the electron configuration of Mn is [Ar] 3d5 4s2. We can see that Mn^7+ and Re^7+ have empty d orbitals.
The color of MnO4 - must result from ligand to metal charge transfer hence the purple color of MnO4 -. In the case of ReO4 -, the ligand to metal charge transfer occurs at a much higher energy owing to the fact that 5d orbitals are involved. This transition occurs in the near UV region hence ReO4 - appears colorless. The ligand to metal charge transfer in MnO4- involves lower energy 3d orbitals hence it occurs in the visible region of the spectrum.
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Complete the following reaction: Li + S -->
Answer:
Li2S
Explanation:
Hope this helps.
Answer:
can u do an real answer pls so i can help u thanks
For the following reaction, 33.7 grams of bromine are allowed to react with 13.0 grams of chlorine gas.
bromine (g) + chlorine (g)>bromine monochloride (g)
What is the maximum amount of bromine monochloride that can be formed? __________grams
What is the FORMULA for the limiting reagent?
What amount of the excess reagent remains after the reaction is complete? __________grams
Explanation:
The reaction is given as;
Br2(g) + Cl2(g) ----> 2BrCl(g)
From the equation;
1 mol of Br2 reacts with 1 mol of Cl2
Converting the masses given to moles, using the formular;
Number of moles = Mass / Molar mass
Br2;
Number of moles = 33.7 g / 159.808 g/mol = 0.21088 mol
Cl2;
Number of moles = 13.0 g / 70.906 g/mol = 0.18334 mol
From the values;
0.18334 mol of Cl2 would react with 0.18334 mol of Br2 with an excess of 0.02754 mol of Br2
What is the maximum amount of bromine monochloride that can be formed? __________grams
1 mol of Cl2 produces 2 mol of Bromine Monochloride
0.18334 mol of Cl2 would produce x
Solving for x;
x = 0.18334 * 2 = 0.36668 mol
Converting to mass;
Mass = Number of moles * Molar mass = 0.36668 mol * 115.357 g/mol
Mass = 42.299 g
What is the FORMULA for the limiting reagent?
The limiting reagent is Cl2 as it determines the amount of product formed. The moment the reaction uses up Cl2, the reaction stops.
What amount of the excess reagent remains after the reaction is complete? __________grams
The excess reagent is Br2
The number of moles left is;
0.02754 mol of Br2
Converting to mass;
Mass = Number of moles * Molar mass = 0.02754 mol * 159.808 g/mol
Mass = 4.401 g
What is the functional groups of CH3CH2CH(OH)CH2C(CH3)2Br?
Answer:
What is the functional groups of CH3CH2CH(OH)CH2C(CH3)2Br?
Please help me I need this really quick
Answer:
The answer is (a)
.
.
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What is the voltage in a circuit is the current is 3 amps and the resistance is 3 ohms
Answer:
9
Explanation:
V=I*R
3*3
Thats the answer
A gas has a pressure of 0.0370 atm at 50.0°C. What is the pressure at 0.00°C?
How can we solve food insecurity while reducing food waste?
o inventory food supplies to avoid overbuying
O donate unused food to food banks
O purchase only as much food as you need
O don't throw scraps in the landfill
Answer:
donate unused food to food banks
Explanation:
Becuse food banks processes food to make very fine particles which is mixed with soil and can be given to the plants
Based on the vibrational difference you observed, state a hypothesis to explain why diatomic molecules in the air, such as oxygen and nitrogen, are not greenhouse gases while those with 3 or more atoms, such as methane, are?
Answer:
See explanation
Explanation:
The ability of a gas to function as a green house gas depends on its ability to absorb infra red rays. In turn, the absorption of infrared red rays depends on whether or not the molecule is IR active.
The triatomic molecules such as methane and water are IR active. Only IR active molecules can lead to green house effect.
Note that for a molecular vibrational mode to be IR active, the dipole moment of the molecule is changed as the vibration occurs .
How many grams are in 0.500 liters of SBr6?
Please show work if possible or say how to do it
Answer:
250 grams = 0.25 liter
Explanation:
Determine the entropy change for the combustion of gaseous propane, C3H8, under standard state conditions to give gaseous carbon dioxide and water.
Answer:
ΔS°reaction = 100.9 J K⁻¹ (mol C₃H₈)⁻¹
Explanation:
The equation for the reaction is given as;
C₃H₈(g) + 5O₂(g) → 4H₂O(g) + 3CO₂(g)
In order to determine the entropy change, we have to use the entropy valuues for the species in the reaction. This is given as;
S°[C₃H₈(g)] = 269.9 J K⁻¹ mol⁻¹
S°[O₂(g)] = 205.1 J K⁻¹ mol⁻¹
S°[H₂O(g)] = 188.8 J K⁻¹ mol⁻¹
S°[CO₂(g)] = 213.7 J K⁻¹ mol⁻¹
The unit of entropy is J K⁻¹ mol⁻¹
Entropy change for the reaction is given as;
ΔS°reaction = ΔS°product - ΔS°reactant
ΔS°reaction = [(4 * 188.8) + (3 * 213.7)] - [269.9 + (5 * 205.1)]
ΔS°reaction = 100.9 J K⁻¹ (mol C₃H₈)⁻¹
The entropy change for the combustion of gaseous propane, under standard state conditions 100.9 J K⁻¹.
The equation for the combustion of gaseous propane is given as follows:-
C₃H₈(g) + 5O₂(g) → 4H₂O(g) + 3CO₂(g)
In order to determine the entropy change, we have to use the entropy values for the species in the reaction. This is as follows:-
S°[C₃H₈(g)] = 269.9 J K⁻¹ mol⁻¹
S°[O₂(g)] = 205.1 J K⁻¹ mol⁻¹
S°[H₂O(g)] = 188.8 J K⁻¹ mol⁻¹
S°[CO₂(g)] = 213.7 J K⁻¹ mol⁻¹
The unit of entropy is J K⁻¹ mol⁻¹
Entropy change for the reaction is given as;
ΔS°reaction =nproduct ΔS°product - nreactantΔS°reactant
ΔS°reaction = [(4mol * 188.8 J K⁻¹ mol⁻¹) + (3 mol * 213.7 J K⁻¹ mol⁻¹)] - [(1 mol*269.9J K⁻¹ mol⁻¹ )+ (5 mol* 205.1 J K⁻¹ mol⁻¹)]
ΔS°reaction = 100.9 J K⁻¹
So, the entropy change for the combustion of gaseous propane is 100.9 J K⁻¹ .
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According to the graph, what is the instantaneous speed of the object at 5 seconds? *
Captionless Image
4 m/s
7 m/s
0.25 m/s
3 m/s
Answer:4m/s
Explanation:The reason why that the answer is because I am Smart.
When the number of molecules, atoms, or ions of a particular type (here we consider H ions) is in the hundreds of millions, we can confidently speak of concentrations and analyze an average behavior.
a. True
b. False
Answer:
True.
Explanation:
When the number of molecules, atoms or ions of any element is in the hundreds of millions, we can safely speak of concentrations and analyze a standard behavior, and can even specify the different dilutions used, if there are dilutions. This allows analyzes to be clearly understood by any individual. However, it is not possible to do this if the number of molecules, atoms and ions is very small.
I need help explaining what are the differences between Solids, Liquids, and Gases.
Explanation: solids are frozen like if you freeze tea it becomes a solid , liquids is like tea and gases is like when you boil water and it becomes a gas