A mustang, has an average velocity of 33 m/s while covering a course that is 21 miles long. (1 mile = 1609 m). How long did it take the driver to complete the course?
Answer:
t = 1023.9 seconds
Explanation:
Given that,
The average velocity of a Mustang, v = 33m/s
Distance, d = 21 miles = 33789 m
Let the driver takes t seconds. So,
Speed = distance/time
[tex]t=\dfrac{d}{v}\\\\t=\dfrac{33789}{33}\\\\t=1023.9\ s[/tex]
So, it will take 1023.9 seconds to complete the course.
5. Impulse is...
a. A change in the time it takes an object to come to rest
b. A change in an object's velocity
C. A change in an object's mass
d. A change in an object's momentum
Answer:
The answer should be C
Explanation:
Wavelength and frequency have an inverse relationship. Which of these other examples also shows an inverse relationship?
A. Distance covered on a hike versus the number of steps taken
B. Grade on an assessment versus the amount of time spent studying
C. Time it takes to get somewhere versus driving speed
D. None of these shown an inverse relationship
I threw a plastic ball in the pool for my dog to fetch. The mass of the ball was 125g. What must the volume be to have a density of 0.500g/mL
Answer:
250 mL
Explanation:
Density equation:
[tex]Density = \frac{mass}{volume}[/tex]
Variables:
D = density
m = mass
V = volume
Solve:
M = 125 g
D = 0.500 g/mL
V = ?
[tex]0.500 g/mL = \frac{125 g}{V}[/tex]
V = 250 mL
a person walks 750m due north then 250 m due east of the entire walk takes 12 min find the person average velocity
Answer:
v = 1.098 m/s
Explanation:
Given that,
A person walks 750m due north then 250 m due east of the entire walk takes 12 min.
We need to find the average velocity of the person.
Displacement,
[tex]d=\sqrt{750^2+250^2} \\\\d=790.56\ m[/tex]
Average velocity = displacement/time
[tex]v=\dfrac{790.56\ m}{12\times 60\ s}\\\\v=1.098\ m/s[/tex]
So, the average velocity of the person is 1.098 m/s.
What is a wavelength of induced radiation quantum if 2-nd order diffraction maximum change on distancе 3.5 сm from сentral and distance between screen to diffraction lattice 0.5 m? Lattice period 0.01 mm.
Answer:
λ = 3,5 10⁻⁷ m
Explanation:
El fenómeno de difracción es descrito por la expresión
a sin θ = m λ
usemos trigonometría para encontrar el sino
tan θ = y/L
tan θ = sin θ /cos θ
los experiemtos de difraccion ocurran para langulos pequeños
tan θ = sin θ
sin θ =y/L
substituimos
a y/L = m λ
λ = a y /m L
calculemos
λ = 0,01 10-3 0,035 / 2 0,5
λ = 3,5 10⁻⁷ m
an object with a mass of 3.2 kg has a force of 7.3 newtons applied to it. what is the resulting acceleration of the object?
Answer:
2.28m/s^2
Explanation:
F=ma
a=F/m
a=7.3/3.2
a=2.28m/s^2
Which statement best explains why sensors (or senses) are necessary to produce a change in behavior?
A.
Organisms cannot sense stimuli without a central nervous system.
B.
Stimuli must be sensed in order to produce a response.
C.
Stimuli must be responded to in order to be sensed.
D.
Organisms cannot respond to stimuli without a central nervous system.
Answer:
It is (B) Stimuli must be sensed in order to produce a response.
Explanation:
Name five atoms of good and bad conductors
Answer:
Good Atoms Of Conductors: Copper , Silver, Gold , Aluminum, and Steel
Good Atoms Of Bad Conductors: Glass , Wood , Cork , Cotton Wool, and Air
I hope this helps you :)
32. Which statement best describes the difference between strong nuclear forces and weak nuclear forces? (2 points)
• Weak nuclear forces are involved when certain types of atoms break down. Strong nuclear forces are
responsible for holding atoms' nucleus together.
• Weak nuclear forces hold bonds between atoms together. Strong nuclear forces hold together the nucleus of an atom.
• Strong nuclear bonds prevent atoms from falling apart. Weak nuclear bonds prevent compounds from falling apart.
• Strong nuclear forces are involved in breaking electrons from their shells. Weak nuclear forces hold protons in the nucleus. in
Answer:
The strong force. ... Specific kinds of bosons are responsible for the weak force, ... In the weak force, the bosons are charged particles called W and Z bosons.
Explanation:
hope it helps please mark me as a brainliest please
Answer:
Strong nuclear forces are involved in breaking electrons from their shells. Weak nuclear forces hold protons in the nucleus. in
Explanation:
sana maka help if Mali sowwy.
which toy car had the greatest applied force?
Answer:
d
Explanation:
Help me with this thanks!
Answer:
a. slope = 1
b. 70
c. y = 1.058x - 3.29 (it says under the graph)
d. about -3.29 or -3.3
hope this helps:)
Which of the following is an electric potential?
A. 2.5C
B. 2.5 J
C. 2.5 N
D. 2.5 V
Answer:
D. 2.5 V
Explanation:
Electric potential of a point in space is a scalar magnitude that allows a measurement of the electric field at that point to be obtained through the electrostatic potential energy that a electric charge would acquire if it is placed at that point.
Hope this helps a lot!!
Which of the following DOES NOT affect the electric force?
Answer:did you get an answer ?
Explanation:
Drake lifted a couch a height of 0.2 meters in 1.3 seconds. He did 300 j of work. how much power did drake use?
Answer:
c is correct
Explanation:
I hope this helps.
When Drake lifted a couch to a height of 0.2 meters in 1.3 seconds. He did 300 j of work then the power used by Drake is
What is work done?The total amount of energy transferred when a force is applied to move an object through some distance
The work done is the multiplication of applied force with displacement.
Work Done = Force * Displacement
As given in the problem Drake lifted a couch at a height of 0.2 meters in 1.3 seconds. He did 300 j of work.
Work done by the drake = 300 J
Time taken by the drake to do the work = 1.3 seconds
By substituting the values of the work and time in the formula of power
Power = work done / time
= 300/1.3
= 230.77 Watt
Thus, the power used by Drake is 230.77 Watt
Learn more about work done here
brainly.com/question/13662169
#SPJ5
PLEASE HELP ME WITH THIS ONE QUESTION
How many joules are needed to vaporize 125 g of liquid water at 100°C? The latent heat of vaporization is 2258 J/g.
Answer:
282,250 joules
Explanation:
Given that :
Mass of liquid water = 125 gram.
Latent heat of vaporization, L = 2258 J/g
Recall :
Q = mL
Where, Q = quantity of heat required in Joules
Mass) m
L = latent heat of vaporization
Q = mL
Q = 125 g * 2258j/g
Q = 282,250 joules
A rocket is launched vertically and returns its launch point in 7 seconds.
a. What us it’s launch velocity?
b. How high did it go?
C. What is its velocity right before it hits ground?
Answer:
A. 35 m/s
B. 61.25 m
C. 35 m/s
Explanation:
From the question given above, the following data were obtained:
Time of flight (T) = 7 s
Next, we shall determine the time taken to reach the maximum height. This can be obtained as follow:
Time of flight (T) = 7 s
Time (t) take to reach maximum height =?
T = 2t
7 = 2t
Divide both side by 2
t = 7/2
t = 3.5 s
A. Determination of the Lauch velocity.
Time (t) to reach maximum height = 3.5 s
Final velocity (v) = 0 (at maximum height)
Acceleration due to gravity (g) = 10 m/s²
Initial velocity (u) =?
v = u – gt (since the rocket is going against gravity)
0 = u – (10 × 3.5)
0 = u – 35
Collect like terms
0 + 35 = u
u = 35 m/s
Thus, the Lauch velocity is 35 m/s
B. Determination of maximum height reached by the rocket.
Final velocity (v) = 0 (at maximum height)
Acceleration due to gravity (g) = 10 m/s²
Initial velocity (u) = 35 m/s
Maximum height (h) =?
v² = u² – 2gh (since the rocket is going against gravity)
0² = 35² – (2 × 10 × h)
0 = 1225 – 20h
Rearrange
20h = 1225
Divide both side by 20
h = 1225 / 20
h = 61.25 m
Thus, the maximum height reached by the rocket is 61.25 m
C. Determination of the velocity before hitting ground.
Initial velocity (u) = 0 m/s
Acceleration due to gravity (g) = 10 m/s²
Time (t) to reach the ground from the maximum height = 3.5 s
Final velocity (v) =?
v = u + gt (since the rocket is moving towards gravity)
v = 0 + (3.5 × 10)
v = 0 + 35
v = 35 m/s
Thus, the velocity of the rocket before hitting ground is 35 m/s
Compare an earthquake with a Richter scale magnitude of 5.5 to one with a magnitude of 7.5.
____________________________________________________________________
A. 2 times stronger
B. 1000 times stronger
C. 100 times stronger
D. 20 times stronger
Answer:
100 stronger
Explanation:
pick the correct answer
The answer is A. Photosynthesis is caused when plants trap light energy in their leaves and use that energy to change water and carbon dioxide into glucose. Hope this helps :)
A deer is running at 7.29 m/s. He hears a wolf and accelerates at 3.22 m/s/s. 2.8
seconds after hearing the wolf, how far has he travelled?
Answer:
V=16.306m/s
Explanation:
Use V=vi+at
So V= 7.29m/s+(3.22)(2.8s)= 16.306m/s
An object has a mass 4kg kept at a height 6m what is its gravitational energy?
Answer:
-24 from the solution I got using this formula pe=mgh and pe=0 then make g as a subject of the formula
If a roller coaster cart, with a mass of 100 kg, traveled this coaster, how much kinetic energy would it have at point 'E'?
Answer:
Explanation:
Assuming no friction between the roller coaster car and the hill, and neglecting air resistance, the kinetic energy the roller coaster car would have at the bottom of the hill would be equal to its gravitational potential energy at the top of the hill, by conservation of energy.
.What is the work done in a 20-Newton object that is being moved in a 4-meter distance? show
calculation *
Answer:
Explanation:
Harrison pursued the British forces and defeated them at the Battle of the Thames in October. This victory put an end to the British threat to the Northwest—and also claimed the life of Tecumseh, who died in the battle fighting for the British.
A diver leaves the end of a 5.00 m high diving board and reaches a maximum height of 5.50 m before she strikes the water below. The landing point is 3.25 m beyond the end of the diving board in the horizontal direction. You may approximate the diver as a point particle. Hint: Carefully consider your placement of the origin before starting your calculations.
Determine:_____.
(a) After the diver leaves the diving board, how long does it take for her to strike the water?
(b) The initial velocity of the projectile 7. (hint: a vector has both direction and magnitude).
(c) The final velocity with which the diver enters the water ö, (hint: a vector has both direction and magnitude).
Answer:
a) 1.38 s
b) v₀ = 3.92 m/s θ₀ = 53.1º
c) vf = 10.7 m/s θf = -77.2º
Explanation:
a)
Once the diver leaves the board, she has an initial velocity vector, that we can split in two directions perpendicular each other, the vertical direction (coincident with the y-axis, positive upward) and the horizontal direction (coincident with the x-axis, positive away from the diving board).These velocities, are independent each other, due to they are perpendicular.In the horizontal direction, since no acceleration takes place, she keeps the horizontal component v₀ₓ, constant.In the vertical direction, she is always accelerated downward by gravity, which constant value is g = 9.8m/s2.With this all information, we can find the total time since she left the diving board till she strikes the water below, taking advantage of the fact that she reached to a maximum height of 5.5 m,i.e. , 0.5m above the diving board. When at this point, the vertical component of the velocity is zero, so we can write the following kinematic equation:[tex]v_{fy} ^{2} - v_{oy} ^{2} = 2* g* \Delta y (1)[/tex]
Solving for v₀y in (1):[tex]v_{oy} = \sqrt{2*g*\Delta_{ymax} } = \sqrt{2*9.8m/s2*0.5m} = 3.13 m/s (2)[/tex]
When she is at the highest point, her final vertical speed is zero, so we can find the time when she reached to this point, applying the definition of acceleration, as follows:[tex]v_{fyhmax} = v_{oy} - g*t_{hmax} = 0 (3)[/tex]
Solving for t in (3), we get:[tex]t_{hmax} =- \frac{v_{oy}}{g} =\frac{3.13m/s}{9.8m/s2} = 0.32 s (4)[/tex]
Since at this point, the vertical speed is zero, we can apply the equation for the displacement (vertical in this case) for a total displacement of 5.5 m (taking as the origin the point just below the end of the diving board, on the surface of the water), with initial speed equal to zero, as follows:[tex]\Delta y = \frac{1}{2}* g * t^{2} = 5.5 m (5)[/tex]
Solving for t (which we will call t₂) in (5), we get:[tex]t_{2} = \sqrt{\frac{2*\Delta y}{g}} = \sqrt{\frac{2*5.5m}{9.8m/s2} } = 1.06 s (6)[/tex]
The total time will be just the sum of (4) (since leaving the diving board till reaching the maximum height) and (6) (from there until she strikes the water), as follows:Δt = thmax + t₂ = 0.32 s + 1.06 s = 1.38 s (7)b)
In order to know the value of v₀, we need first to get the values of vox and voy.We know that the horizontal speed remains constant, so, if we know the total time traveled (same as in a)) and the horizontal distance (given), we can find v₀ₓ applying the definition of average velocity, as follows:[tex]v_{ox} =\frac{\Delta x}{\Delta t} =\frac{3.25m}{1.38s} = 2.36 m/s (8)[/tex]
We know the value of v₀y from (2):[tex]v_{oy} = 3.13 m/s (9)[/tex]
Applying the Pythagorean theorem, we can get the magnitude of v₀ as follows:[tex]v_{o} = \sqrt{v_{ox}^{2} + v_{oy}^{2}} = \sqrt{(2.36m/s)^{2} + (3.13m/s)^{2}} = 3.92m/s (10)[/tex]
We can find the angle that it makes with the horizontal, applying the definition of tangent of an angle, as follows:[tex]tg_{(\theta o)} = \frac{v_{oy}}{v_{ox} } = \frac{3.13}{2.36} = 1.33 (11)[/tex]
⇒ θ₀ = tg⁻¹ (1.33) = 53.1º
c)
In order to find the vertical component of the final velocity, we can use the following kinematic equation, for the total vertical displacement of 5.5 m since it started to fall after reaching to the maximum speed:[tex]v_{fy} ^{2} - v_{oy} ^{2} = 2* g* \Delta y (12)[/tex]
When it started to fall, in the vertical direction, the diver was at rest, so in (12) we have v₀y = 0.Solving for vfy in (12) we get:[tex]v_{fy} = \sqrt{2*g*\Delta_{y} } = \sqrt{2*9.8m/s2*5.5m} = -10.4 m/s (13)[/tex]
We already know that the horizontal component is the same as the initial v₀ₓ, so we can find the magnitude of the final velocity applying the Pythagorean Theorem as follows:[tex]v_{f} = \sqrt{v_{fx}^{2} + v_{fy}^{2}} = \sqrt{(2.36m/s)^{2} + (-10.4m/s)^{2}} = 10.7 m/s (14)[/tex]
Finally, as we did in (11) to find the angle that it makes with the horizontal, we can find θf as follows:[tex]tg_{(\theta f)} = \frac{v_{fy}}{v_{fx} } = \frac{-10.4}{2.36} = -4.41 (15)[/tex]
⇒ θf = tg⁻¹ (-4.41) = -77.2º
What are the similarities between day and night sky
Explanation:
Daytime is when you can see the sun from where you are, and its light and heat can reach you. Nighttime is when the sun is on the other side of the Earth from you, and its light and heat don't get to you. ...
Answer:
Day and night is the two main parts of a day. Day is very bright with the presence of the sun while night is dark with the absence of the sun. Everything seems familiar during daytime, while same things look unfamiliar at night.
The speed of light in air is 3.00 x 10^8 m/s. If a light wave has a wavelength of 5.80 x 10^-7m, what is its frequency?
Answer:
5.17 x 10^14 1/s
Explanation:
Equation:
c = λ f
c = speed of light
λ = wavelength
f = frequency
Solve:
3.00 x 10^8 m/s = (5.80 x 10^-7m) * f
f = (3.00 x 10^8 m/s) / (5.80 x 10^-7m)
f = 5.17 x 10^14 1/s
Describe the pattern you see in the chart PLEASE HURRY IS URGENT
Answer:
0-0
Explanation:
Forgive me..... I'm getting points 0-0
If a car travels 400m
in 25s
Calculate the
average Speed
Marcy pulls a backpack on wheels down the 100 m hall. The 60N force is applied at an angle of 30° above the horizontal. How much work done on the weights? show full working out
Work= Fcos∆×S
W=60N×cos 30⁰×100
W=60×0.866×100=5196.1J
A mysterious electric appliance has a current of 0.37 amperes running through it when connected to a 240 volt electrical outlet. The appliance will develop a power of A)649 watts B) 89 watts C)240 watts D)120 watts
Answer:
88.8 rounds to 89 so ur anwsers b
Explanation:
rounding and 240*.37=88.8