A mass attached to a spring is displaced from its equilibrium position by 5cm and released. The system then oscillates in simple harmonic motion with a period of 1s. If that same mass–spring system is displaced from equilibrium by 10cm instead, what will its period be in this case?.

The location of the car after 11 seconds will be 445.05 m.

Mass of the car = 1550 kg

The momentum of the car = 46000

Distance of the car = 275 m

The velocity of the car is,

Momentum = Mass × Velocity

M = m × v

[tex]v = \frac{M }{m}[/tex]

[tex] = \frac{46000}{1550} [/tex]

= 29.67 m/s

The velocity of the car is 29.67 m/s.

The location of the car after 11 seconds will be,

[tex]Velocity = \frac{ Distance}{ Time}[/tex]

[tex]v = \frac{d}{t} [/tex]

d = v × t

= 29.67 × 15

= 445.05 m

Therefore, the location of the car after 11 seconds will be 445.05 m.

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By ideal gas approximation, the final volume is 6.84 liters.

We need to know about the ideal gas theory to solve this problem. The ideal gas is assumed that there is no interaction between particles in a gas. It can be determined by the equation

P . V = n . R . T

where P is pressure, V is volume, n is the number of moles gas, R is the ideal gas constant (8.31 J/mol.K) and T is temperature.

From the question above, we know that

V1 = 5 L

P1 = 1040 torr = 1040 / 760 atm

P2 = 1 atm

When the initial and final temperature is the same, we can use the ratio of pressure and volume as

P1 . V1 = P2 . V2

(1040 / 760) . 5 = 1 . V2

V2 = 6.84 liters

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A 30 hp 460v 3-section motor requires 35 amps at complete load. The strength thing is 0.86 which determines the motor performance of 93.32.

Given records:

Output electricity of motor = 30 hp

We recognize that 1 hp = 746 w

∴ Output = 30 × 746 = 22380 w

→ complete load cutting-edge

= 35 amp

→ Line voltage

= 460 v

→ power issue = 0.76

→ enter to the motor =?

⇒ [tex]P_{in} \sqrt{3}V_{L} I_{FL} cos[/tex]∅

⇒ [tex]p_{in} =\sqrt{3}[/tex] × 460 × 35 × 0.36

⇒ [tex]p_{in} = 23981.97 w[/tex]

We know that efficiency [tex]n=[/tex] output/input

⇒ [tex]n = \frac{22380}{23981.97}[/tex]

⇒ [tex]n = 0.9332[/tex]

[tex]% n = 93.32%[/tex]Efficiency % = 93.32%

So the efficiency in the question given above is 93.32%.

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You will have to wait for 5.92 seconds at the finish line for your friend to finish the dash.

The total distance of the dash is d = 200 meters.

Friends run with an average speed of v₁ = 2.5 m/s.

Your average speed is v₂ = 2.7 m/s.

Now, the speed of an object or particle is defined as the speed of the object per unit time.

Therefore,

Speed = distance / time

Now, friend's times will be:

v₁ = d / t₁

t₁ = d / v₁

t₁ = ( 200 m) / (2.5 m/s)

t₁ = 80 seconds

Your time to finish the dash is:

v₂ = d / t₂

t₂ = d / v₂

t₂ = ( 200 m) / ( 2.7 m/s)

t₂ = 74.07 seconds

The time you have to wait for your friend at the finish line will be:

t = t₁ - t₂

t = 80 - 74.07

t = 5.92 seconds.

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Answer: A.) Change in Velocity over Time

Explanation:

The definition of acceleration is Δv/t, or the change in velocity over time. Acceleration, like velocity, will therefore have a magnitude, as well as a direction.

The sum arithmetic sequence is 18,335 of a partial sum of an arithmetic sequence is given 5 9 13 . . . 381

Calculation

d = 9-5 = 4

a = 5

[tex]a_n[/tex] = 5 + 4(n -1) = 381

    = 5 + 4n -4 = 381

    = 4n +1 = 381

    = 4n = 380

    = n = 380/4

          = 95

Now,

     [tex]S_{95}[/tex] = [tex]95(\frac{5 + 381}{2} )[/tex]

           = 95 × 193

           =  18,335

The series where the common difference between any two next words stays constant is known as an arithmetic sequence. Let's review what a sequence is. A collection of numbers that follow a pattern is called a sequence. As an illustration, the numbers 1, 6, 11, 16,... are an arithmetic sequence because they follow a pattern in which the preceding term is multiplied by 5 to produce each subsequent number. There are two formulas for arithmetic sequences.

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It has been demonstrated that modified sports, in which the equipment and rules are altered to improve skill performance, foster skill learning and may even boost participation.

The sport is replicated in a modified game, although some of the regulations are altered. Limited touches or time with the ball, a smaller field or court, different-sized balls or goals, or the obligation to defend repeatedly are some examples of modified rules. Like any other sport you may have played, such as basketball or football, modified sports feature regulations that have been modified to take into account the talents and abilities of older or less mobile participants. Depending on the skills of the participants who want to participate, modified sports can be altered.

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The agreement must be aimed at preventing or reducing ozone depletion internationally to save the ozone layer from more damage.

The agreement must be aimed at preventing or reducing ozone depletion internationally because ozone depletion is the most dangerous cause of human activities such as chlorofluorocarbon gas. Ozone is the protective layer that can filter incoming solar radiation from harmful ultraviolet radiation. The Montreal Protocol is a global agreement to protect the ozone layer of the earth by preventing the use of chemicals that deplete it.

So we can conclude that the agreement must be aimed at preventing or reducing ozone depletion internationally to save the ozone layer from more damage.

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Chlorine is likely to form an ionic bond with potassium.

A chemical bond is a strong bond that can be formed between atoms, ions, or molecules to generate chemical compounds. The bond may be created by the sharing of electrons in covalent bonds or by the electrostatic attraction of two oppositely charged ions, as in ionic bonds.

The main interaction in ionic compounds is ionic bonding, a type of chemical bonding that involves the electrostatic attraction between two atoms or ions with dramatically differing electronegativities.

When a metal and a non-metal react, an ionic bond is created.

To establish an ionic bond, the metal loses electrons (donates them), whereas non-metals receive electrons (accept them).

Chlorine (Cl) is a non-metal, whereas potassium is a metal. As they interact to create an ionic bond, potassium donates one electron while chlorine accepts one.

The correct option is (A).

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To travel directly southward relative to the ground, the bird should head

to an angle direction of approximately South 23.58° East.

The velocity of the bird can be directed such that the resultant velocity of

the bird and the wind will be in the southward direction.

component of the velocity is;

The magnitude of the velocity of the bird = 100 km/h

The direction of the bird = North-South direction

The magnitude of the velocity of the wind = 40 km/h

The direction of the wind = East-west direction

The component vector of the two velocities are;

Velocity of bird, v = -100·j

The velocity of wind, v = 40·i

The direction of the velocity of the bird will be southward if it has a

component of velocity to accommodate the velocity of the wind.

Let θ represent the angle of the direction of the bird relative to the

negative x-axis, we have;

-100 × cos(θ) = -40·i

θ ≈ 66.42° in the third quadrat, given that both the y, and x, values are

negative.

In the South-West direction, the angle is, therefore; 90 - 66.42 ≈ 23.58°

Therefore, the bird should fly in the direction south 23.58° east to fly

directly southward relative to the ground.

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By using vector

a. the distance traveled is 12 kilometres

b. the resultant displacement is (7 i + 5 j) kilometres

We need to know about vectors to solve this problem. Vector has magnitude and also direction. Displacement is included in vector. It can be written as

s = sx i + sy j + sz k

where s is displacement, sx is displacement on x-axis, sy is displacement on y-axis and sz us displacement on z-axis.

From the question above, we know that

east = positive x

south = negative y

west = negative x

north = positive y

s1 = 7 j

s2 = 5 j

The distance traveled is

s = s1 + s2

s = 7 + 5

s = 12 kilometres

The resultant displacement is

s = s1 + s2

s = 7 i + 5 j

s = (7 i + 5 j) kilometres

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Since it takes exactly 2 minutes and 52 seconds to travel that distance ,your average speed is 29.07 m/s

Average speed is the total distance travelled/time taken for the distance.

Given that Freeways in Australia have a maximum speed of 100kph (27.78m/s) and an average speed camera measured the time over the course of 5km and found that it took me exactly 2 minutes and 52 seconds to travel that distance,

Since the average speed = total distance/total time, substituting the values of the variables into the equationm we have

average speed = total distance/total time

average speed = 5000 m/172 s

= 29.07 m/s

So, your average speed is 29.07 m/s

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The deceleration of a snowboarder going up is 1.8 m / s²

We know that,

F = m * a

[tex]f_{k}[/tex] = μ[tex]_{k}[/tex] * [tex]F_{N}[/tex]

F = Force

m = Mass

a = Acceleration

[tex]f_{k}[/tex] = Kinetic frictional force

μ[tex]_{k}[/tex] = Co-efficient of kinetic friction

[tex]F_{N}[/tex] = Normal force

θ = 5°

μ[tex]_{k}[/tex] = 0.1

Since the snowboarder is going up the hill at an angle of 5°, the weight of the snowboarder does not align with the traditional y-axis direction. So resolving the weight into horizontal and vertical components.

sin 5° = - [tex]W_{x}[/tex] / W

[tex]W_{x}[/tex] = - W sin 5°

cos 5° = - [tex]W_{y}[/tex] / W

[tex]W_{y}[/tex] = - W cos 5°

[tex]f_{k}[/tex] = 0.1 ( [tex]W_{y}[/tex] )

[tex]f_{k}[/tex] = - 0.1 ( W cos 5° )

Σ [tex]F_{x}[/tex] = m [tex]a_{x}[/tex]

[tex]W_{x}[/tex] + [tex]f_{k}[/tex] = m [tex]a_{x}[/tex]

- W sin 5° - 0.1 ( W cos 5° ) = m [tex]a_{x}[/tex]

- W ( sin 5° + 0.1 cos 5° ) = m [tex]a_{x}[/tex]

- m g ( sin 5° + 0.1 cos 5° ) = m [tex]a_{x}[/tex]

- 9.8 ( sin 5° + 0.1 cos 5° ) = [tex]a_{x}[/tex]

[tex]a_{x}[/tex] = - 1.8 m / s²

Deceleration is the negative acceleration. When an object slows down it has deceleration. Kinetic friction is the frictional force created due to an object's motion.

Therefore, the deceleration of a snowboarder going up is 1.8 m / s²

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Answer: philosophers

Explanation:

If the current is 6A and the voltage is 420 V, the resistance is 70ohms.

Resistance is the opposition offered by an electrical conductor to the flow of a current through itself, resulting in a conversion of electrical energy into heat and radiation.

The resistance of a current can be calculated using the following formula;

V = IR

Where;

According to this question, a current of 6 A and the voltage of 420V is given. The resistance is as follows:

420 = 6 × R

R = 420/6

R = 70 ohms

Therefore, If the current is 6A and the voltage is 420 V, the resistance is 70ohms.

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The affirmation redox reactions involve the loss of an electron by an electron donor, and a gain of an electron by an electron acceptor is true.

Redox reactions are chemical reactions in which there is an exchange of electrons between atoms or molecules, some of which will lose electrons that will be transferred to other molecules or atoms. Then the reagent that is going to give up the electrons is going to go through an oxidation process and the one that is going to receive them is going to go through a reduction process.

Therefore, we can confirm that the affirmation redox reactions involve the loss of an electron by an electron donor, and a gain of an electron by an electron acceptor is true.

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Height above the top of Tom's window the ball was dropped= 1.31m

Given that,

The height of window (s) = 1.50m

Time(t) = 0.240s

We have to find the height, and for this, we have to find the velocity using the equation of motion:

s = ut  + 1/2 g[tex]t^{2}[/tex]

By putting the value of h and t in the  equation

1.50 = u × 0.240 + 1/2 × 9.8 × [tex]0.240^{2}[/tex]

1.50 = u × 0.240 + 0.28224

u = (1.50 - 0.28224) / 0.240

u= 1.21776 / 0.240

u=  5.074

Now we have to calculate height by using the formula

[tex]v^{2}[/tex] = [tex]u^{2}[/tex] + 2gh

By putting the value of u and v we get

[tex]5.074^{2}[/tex] = 0 + 2 × 9.8 × h

h = [tex](5.074)^{2}[/tex]/ 2 × 9.8

h = 1.31 m

Therefore the height is 1.31 m above the window.

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The complete question is:

A ball is dropped from an upper floor, some unknown distance above Tom's apartment. As he looks out of his window, which is 1..50 m tall, Tom observes that it takes the ball 0.240 s to traverse the length of the window. Determine how high ℎ above the top of Tom's window the ball was dropped. Ignore the effects of air resistance.

There is a positive acceleration where −x direction decreasing in speed.

The term acceleration refers to the change of velocity with time of the body. Now we know that both velocity and acceleration  are both vector quantities. We have to put the direction into consideration when looking at the acceleration of a body.

The case in which the car has a positive acceleration is the option where a car has a negative velocity and a positive acceleration is −x direction decreasing in speed.

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Missing parts;

In which of the following cases does a car have a negative velocity and a positive acceleration? A car that is traveling in the Check all that apply. Check all that apply.

a.+x direction decreasing in speed.

b.+x direction increasing in speed.

c.−x direction decreasing in speed.

d.−x direction increasing in speed.

e.−x direction at a constant 20 m/s.

Astronomer who introduced the most widely accepted hypothesis regarding the origin of the solar system was Immanuel Kant in 1755.

The Solar System is gravitationally bound system of the Sun and objects that orbit it. It formed 4.6 billion years ago from gravitational collapse of a giant interstellar molecular cloud. The vast majority (99.86%) of system's mass is in the Sun, with most of the remaining mass contained in the planet Jupiter. Four inner system planets—Mercury, Venus, Earth and Mars—are terrestrial planets, being composed primarily of rock and metal. Four giant planets of the outer system are substantially larger and more massive than the terrestrials.

The two largest, Jupiter and Saturn, are gas giants, being composed mainly of hydrogen and helium; next two, Uranus and Neptune, are ice giants, being composed mostly of volatile substances with the relatively high melting points compared with hydrogen and helium, such as water, ammonia, and methane. All eight planets have nearly circular orbits that lie near the plane of the Earth's orbit, called the ecliptic.

There are an unknown number of smaller dwarf planets and the innumerable small Solar System bodies orbiting the Sun. Six of the major planets, six largest possible dwarf planets, and many of the smaller bodies are orbited by natural satellites, commonly called "moons" after Earth's Moon.

Two natural satellites, Jupiter's moon Ganymede and Saturn's moon Titan, are larger but not more massive than Mercury, smallest terrestrial planet, and Jupiter's moon Callisto is nearly as large. Each of the giant planets and some smaller bodies are encircled by the planetary rings of ice, dust and moonlets. The asteroid belt, which lies between orbits of Mars and Jupiter, contains objects composed of rock, metal and ice. Beyond Neptune's orbit lie Kuiper belt and scattered disc, which are populations of objects composed mostly of ice and rock.

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The instrument, other than a thermometer, that works using the principle of thermal expansion is thermostat.

Thermostat is made up of two metals with differing expansion coefficients, Inver and Brass.

We employ it in an electrical device, it is straight at room temperature, if there is a short-circuit or any other issue and the circuit temperature suddenly rises, the thermostat's temperature will rise as well.

Thermal expansion, which typically excludes phase transitions, is the tendency of matter to change its area, volume, shape and density in response to a change in temperature. The material's coefficient of linear thermal expansion typically fluctuates with temperature and is calculated as the relative expansion divided by the change in temperature.

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Answer

1/2 m v^2 = m g H        by conservation of energy for an object fired straight up or

H = v^2 / (2 * g)

For an object traveling at 45 deg then

Vy = V sin 45 = 2^1/2 / 2 * V

So now

H = 1/2 * v^2 / (2 * g) = v^2 / (4 * g)

and the projectile will travel H / 2 instead of H

The correct answer 322mm/s^2.

The growing x-axis, symbolised by i shows the direction of the velocity. Since integration and differentiation can be used to solve problems of this nature, it is recommended for students to study and comprehend their fundamental processes.

v=300mm/s

a_t=dv/dt=0

y=20(10^3)/x ____(1)

For x=200

dy/dx|x=200 = - 20(10^3)/(200)^2

dy/dx|x=200=-0.5

Now differentiating equation (1) with respect to x again

d^2y/dx^2|(x=200)=40(10^3)/(200)^3

d^2y/dx^2|(x=200)=5(10^-3)

Write the expression of ρ.

ρ=(1+(dy/dx)^2)^3/2/|d^2y/dx^2|

substitute the values,

ρ=(1+(0.5)^2)^3/2/5(10^-3)

ρ=279.5mm

Write the expression of the radial acceleration.

a_n=v^2/ρ

a_n=(300mm/s)^/279.5mm

a_n=322mm/s^2

Understand that the tangential acceleration is zero. Thus, write the expression of the net acceleration.

a=√a_t^2+a_n^2

a=√((0mmm/s^2)^2+(322mm/s^2)^2

a=322mm/s^2

Understand that the given information,

dy/dx=-0.5

tanθ=-0.5

θ=26.6(anticlockwise)

Draw the calculated vector on the curve.

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According to the current, the charge is 72,000 coulombs.

We need to know about current to solve this problem. Current can be defined as the flowrate of charge through the medium. It can be determined as

I = Q / t

where I is current, Q is charge and t is time.

From the question above, we know that

I = 10 A

h = 2 hours = 2 x 3600 second = 7200 second

By substituting the given parameters, we can calculate the charge

I = Q / t

10 = Q / 7200

Q = 72,000 coulombs

Hence, the charge is 72,000 coulombs.

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The take my largest plastic shopping bag square between the light source and the wall

Rays of light can travel through the cardboard when I hold my largest cardboard square between the light source and the wall, but because the cardboard is not very thick, the light can still pass through and create a shadow.

Do cardboard sheets block light?

Based on the precise materials and light sources that were employed, the results of the cardboard experiment frequently differ.

Keep in mind that it is generally expected that reflective materials, such aluminium foil and mirrors, would reflect the specified or given light.

Since the cardboard is not very thick, light rays do penetrate when I hold my largest cardboard square between the light source and the wall. As a result, the cardboard tends to cast a shadow when held in this position.

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No, the words can be interpreted in one way only:

* If the word is consisting of only a's, it can be factored in one way as groups of (aa).

* If there is a single b (or the first b), then

if there is an even number of a's (including 0) before the b, this b is denoted as the start of (baa) and the a's before it is factored in one way as groups of (aa).

if there is an odd number of a's before the b, this b is a part of (aba) and the a's before it is factored in one way as groups of (aa).

* If there is a second b, then if the first b was denoted as a part of (baa), then if there is an even calculated numbers of a's between the b's, then

the second b is part of (baa), and the a's in between are factored in just one way as groups of (aa).

if there is an odd number present that is a's between the b's, then

this second b is denoted as a part of aba, and the a's in between are factored to be in one way as groups of (aa).

if the first b was part of (aba), then

if there is taken to be an even number of a's between the b's, then

the second b is part of (aba), and the a's in between are factored in one way as groups of (aa).

if there is an odd number of a's between the b's, then

the second b is a part of (baa), and then the a's in between are factored in a one way denoted as groups of (aa).

The same argument can be used for words containing more than 2 b's.

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Answer:

bro just copy and paste the questions for us

Explanation:

Research is defined as "creative and methodical activity done  to enhance  the body of knowledge."  It entails the target gathering, organizing, and analysis of knowledge in order to improve comprehension of a subject or issue.  a search effort could build on prior contributions to the field. Research may duplicate portions of earlier projects or the project as an entire to verify the accuracy of instruments, processes, or experiments. 

Documentation, discovery, interpretation,  and therefore the research and development (R&D) of methods and systems for the advancement of human knowledge are the main goals of basic research (as opposed to applied research). Research methodologies are supported by epistemologies, which differ greatly within and between the humanities and sciences.

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The volume of soybean oil displaced by the boat to float is 0.00011 liters or 1.1 x 10^-4 liters.

An object floating in a liquid follows Archimedes’ Principle.

According to the Archimedes Principle, the amount of fluid displaced by the body is equal to its weight.

So, the buoyant force applied by the liquid should be equal to the weight of the bowl.

Hence

Weight of bowl = Buoyant Force of Soybean Oil

Mg = V(ρ)(g)

Here V = volume of soybean oil

ρ = density of soybean oil

1.05 = V x 917 x 9.8

The volume(V) comes out to be 0.00011 liters.

Thus, the volume of soybean oil displaced by the bowl to float is 0.00011 liters or 1.1 x 10^-4 liters.

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Answer:

electromagnetic radiation

Explanation:

The block of wood is 65.84g so, the volume of the wood is 97.83 cm3.

Given:

Weighs =65.84 g

Density= 0.673 g/cm3

=65.84/0.673

=97.83 cm3

The amount of space or volume that a three-dimensional object occupies. Volumes are measured in cubic units. an evaluation of how loud or powerful a sound is.

It is more common to think of a container's volume as its capacity rather than as the quantity of room it occupies. In other words, a container's volume is determined by how much liquid or gas it can hold.

To measure volume, first standardized containers are employed, and subsequently naturally occurring containers with a similar shape. A number of simple three-dimensional shapes can have their volume easily calculated using arithmetic methods.

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