A metal has a work function of 3.68 eV. then the maximum kinetic energy of the ejected electrons is 3.57 × 10⁻¹⁹ J, when electromagnetic waves with a wavelength of 209 nm.
Maximum kinetic energy of the ejected electrons is given by,
Kinetic energy (K.E.) = Energy of incident photons - Work function
Given,
Workfuction = 6.68 eV
wavelength = 209 nm = 209 × 10⁻⁹ m
energy of the incident photons is given by
Energy = Planck's constant × (speed of light / wavelength)
E = (6.626 × 10^-34 J·s) × (3 × 10^8 m/s) / (2.09 × 10^-7 m)
E ≈ 9.46 × 10⁻¹⁹ J
the maximum kinetic energy of the ejected electrons is
K.E. = 9.46 × 10^-19 J - 3.68 eV
So, the work function is 3.68 eV × (1.602 × 10^-19 J/eV) ≈ 5.89 × 10^-19 J.
Substituting this value into the equation:
K.E. = 9.46 × 10^-19 J - 5.89 × 10^-19 J ≈ 3.57 × 10^-19 J
Therefore, the maximum kinetic energy of the ejected electrons
3.57 × 10⁻¹⁹ J.
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A ceiling fan has four blades. Each has a mass of 0.35 kg and a length of 600 mm. This assembly can be modelled as four rods connected at their ends to the fan’s axle. When the fan is switched on, it takes 4.35 seconds for the fan to reach an angular speed of 108 revolutions per minute.
The angular speed of the fan is 11.31 radians per second, and the net torque on the fan is 0.0655 Nm.
Rotational motion refers to the movement of an object around an axis or a fixed point, where the object rotates or spins about the axis or point. This motion can be described in terms of angular displacement, velocity, acceleration, and momentum.
To solve this problem, we can use the principles of rotational motion and apply them to the fan blades.
First, let's convert the given angular speed of the fan from revolutions per minute (RPM) to radians per second:
108 RPM = 108/60 = 1.8 revolutions per second
1 revolution = 2π radians, so 1.8 revolutions = 1.8 x 2π radians = 11.31 radians
Therefore, the angular speed of the fan is 11.31 radians per second.
Next, we can use the formula for the rotational kinetic energy of a rigid body:
K = (1/2) I ω^2
where K is the rotational kinetic energy, I is the moment of inertia, and ω is the angular speed.
For a system of four rods connected at their ends, the moment of inertia can be calculated as:
I = (1/3) m L^2
where m is the mass of each blade, L is the length of each blade, and we assume that the blades are thin rods rotating about their centers.
Substituting the given values, we get:
I = (1/3) (0.35 kg) (0.6 m)^2 = 0.0252 kg m^2
Now we can use the given time of 4.35 seconds to find the angular acceleration of the fan:
α = ω/t = 11.31 radians/4.35 seconds = 2.6 radians/second^2
Finally, we can use the formula for torque and the moment of inertia to find the net torque on the fan:
τ = I α
τ = (0.0252 kg m^2) (2.6 radians/second^2) = 0.0655 Nm
Therefore, the net torque on the fan is 0.0655 Nm.
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Normal forces are applied uniformly over the surface of a spherical volume of water whose radius is 20.0 cm. If the pressure on the surface is increased by 200 MPa, by how much does the radius of the sphere decrease?
The radius of the sphere decreases by 11 mm when the pressure on its surface is increased by 200 MPa.
To determine the decrease in radius of the spherical volume of water when the pressure on its surface is increased, we can use the equation relating pressure to the radius of a sphere:
ΔP = K/R
Where ΔP is the change in pressure, K is a constant, and R is the radius of the sphere.
In this case, we're given that ΔP (change in pressure) is 200 MPa and the initial radius R is 20.0 cm. We need to find the change in radius ΔR.
We can rearrange the equation to solve for ΔR:
ΔR = K/ΔP
Now, we need to determine the value of the constant K. The constant K depends on the bulk modulus of the material, which is a measure of its resistance to compression. For water, the bulk modulus is approximately 2.2 GPa (gigapascals).
Substituting the values into the equation, we have:
ΔR = (2.2 GPa) / (200 MPa)
To simplify the calculation, we need to convert the units so that they are consistent. Let's convert GPa to MPa:
ΔR = (2.2 GPa * 1000 MPa/GPa) / (200 MPa)
ΔR = 11 mm
Therefore, the radius of the sphere decreases by 11 mm when the pressure on its surface is increased by 200 MPa.
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what subatomic particle is the smallest quarks
Given the two vectors A =i+ j and B = j + k, find the following.
(a) A + B and |A + B|
(b) 3A - 2B
(c) A • B
(d) AxB and |AxB|
a) The value of the vector A + B is i + 2j + k and |A + B| is √6 units.
Given:
A = i + j
B = j + k
A + B = i + j + j + k
= i + 2j + k
|A + B| is the magnitude of the vectors A and B
|A + B| = √(1² + 2² + 1²)
= √(1 + 4 +1)
= √6
b) The vector 3A - 2B has the value of 3i + j -2k
Given:
A = i + j
3A = 3i + 3j
B = j + k
2B = 2j + 2k
3A - 2B = 3i + 3j - 2j - 2k
= 3i + j -2k
c) The scalar product of the vector that is A • B is equal to 3 units
The scalar product is calculated as follows:
A • B = i + j • j + k
= 1 + 1 * 1 + 1
= 1 + 1 + 1
= 3 units
d) The vector product or A x B is i - j + k and the magnitude of the same is √3 units.
i j k
A 1 1 0
B 0 1 1
The vector product is calculated as follows:
A x B = (1 * 1 - 1 * 0) i + (0 * 0 - 1 * 0) j + (1 * 1 - 0 * 1) k
= (1 - 0) i + (0 - 1) j + (1 - 0) k
= i - j + k
| A x B | = √(1² + (-1)² + 1²
= √1 + 1 + 1
= √3 units
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calculate the weight of 100kg object onthe surface of planet with mass and diametre of 4.8×10^24 k and 12000km respectively
The weight of the 100 kg object on the surface of the planet is approximately 8.9 × 10¹² Newtons.
To calculate the weight of a 100 kg object on the surface of a planet, we need to use the formula for gravitational force:
F = (G * M * m) / r²
Where:
F is the gravitational force (weight)
G is the gravitational constant (approximately 6.67430 × 10⁻¹¹ N m²/kg²)
M is the mass of the planet (4.8 × 10²⁴ kg)
m is the mass of the object (100 kg)
r is the radius of the planet (diameter / 2)
Given that the diameter of the planet is 12,000 km, we can find the radius by dividing it by 2:
r = 12,000 km / 2 = 6,000 km = 6,000,000 m
Now, we can substitute the values into the formula:
F = (6.67430 × 10⁻¹¹ N m²/kg² * 4.8 × 10²⁴ kg * 100 kg) / (6,000,000 m)²
Simplifying the expression:
F = (6.67430 × 10⁻¹¹ N m²/kg² * 4.8 × 10²⁶ kg) / 36,000,000,000 m²
F ≈ 8.9 × 10¹² N
Therefore, the weight of the 100 kg object on the surface of the planet is approximately 8.9 × 10¹² Newtons.
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Which of the following is not a characteristic of electrical potential energy? a. It is a form of mechanical energy. b. It results from a single charge. c. It results from the interaction between charges. d. It is associated with a charge in an electric field. Please select the best answer from the choices provided A B C D
it is a form of mechanical energy, this is not a characteristic of electrical potential energy. Hence option A is correct.
Electrical potential energy is the energy that is held in a system of charges as a result of their arrangements or positions. It is connected to a charge in an electric field and results from the interaction of charges.
The relative locations of the charges and how they interact with the electric field determine the potential energy. Electrical potential energy is not regarded as a type of mechanical energy, though. The energy connected to the motion or location of an object is referred to as mechanical energy.
Both kinetic energy (energy of motion) and potential energy (energy resulting from position or configuration) are included in it; however, electrical potential energy belongs to the potential energy category rather than the mechanical energy category.
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2.3. An oil of specific gravity 0.8 is contained in a tube to a depth of 80cm. Determine the gauge pressure at this depth in kPa.
The gauge pressure at a depth of 80 cm in oil with specific gravity 0.8 is 6.2784 kPa.
The gauge pressure at a depth in a fluid can be found using the formula, P = ρgh, where gauge pressure is P, density of the fluid is ρ, acceleration due to gravity is g, and depth of the fluid is h. The specific gravity is given to be 0.8 hence, the density of oil is = 0.8 x 1000 kg/m³ = 800 kg/m³. The depth of the oil is given as 80 cm, which is equivalent to 0.8 m. The acceleration due to gravity is approximately 9.81 m/s².
Substituting these values into the formula for gauge pressure, we get,
P = ρgh = (800 kg/m³) x (9.81 m/s²) x (0.8 m) = 6278.4 N/m²
To express the pressure in kPa, we divide by 1000,
P = 6278.4 N/m² ÷ 1000 = 6.2784 kPa
Therefore, the gauge pressure at a depth of 80 cm in the oil with specific gravity 0.8 is 6.2784 kPa.
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Particles q₁, 92, and q3 are in a straight line.
Particles q₁ = -5.00 10-6 C,q2 = +2.50 10-6 C, and
93 -2.50 10-6 C. Particles q₁ and q2 are separated
by 0.500 m. Particles q2 and q3 are separated by
0.250 m. What is the net force on q2?
=
Remember: Negative forces (-F) will point Left
Positive forces (+F) will point Right
-5.00-10-6 C
●
91
0.500 m
+2.50-10-6 C
+92
-2.50-10-6 C
93
0.250 m
Enter
If vector A represents displacement from point O(x1, y1,z1) and P(x2, Yz, Z2) ؟
The magnitude of the displacement of the vector A is determined as 6.2 units.
What is the magnitude of displacement of the vector?The magnitude of the displacement of the vector is calculated as follows;
| A | = √[ (x₂ - x₁ )² + (y₂ - y₁ )² + (z₂ - z₁ )²]
where;
| A | is the magnitude of vector Ax₂ and x₁ are the final and initial position on x - coordinate respectively.y₂ and y₁ are the final and initial position on y - coordinate respectively.z₂ and z₁ are the final and initial position on z- coordinate respectively.The magnitude of vector A is calculated as;
| A | = √[ (2 - 0 )² + (3 - 0 )² + (5 - 0 )²]
| A | = √ (4 + 9 + 25)
| A | = √ ( 38)
| A | = 6.2 units
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The complete question is below;
If vector A represents displacement from point O(x1, y1,z1) and P(x2, Yz, Z2). find the magnitude of the displacement of vector A.
Suppose an amateur astronomer discovers an asteroid that is moving at a speed of about 8 km/sec. She estimates that it must be about 13.5 AU from the Sun. Based on the chart above, does the pattern of planetary speeds and distance support, or fail to support, her estimated distance and why?
The pattern of planetary speeds and distance does not support the amateur astronomer's estimated distance of the asteroid being 13.5 AU from the Sun.
According to Kepler's laws of planetary motion, the speed of a planet or asteroid in its orbit is inversely proportional to its distance from the Sun. This means that as the distance from the Sun increases, the speed of the object should decrease.
Looking at the known planets in our solar system, we observe that the outer planets, such as Neptune and Uranus, have slower speeds compared to the inner planets, such as Mercury and Venus. This is consistent with the inverse relationship between speed and distance. However, the estimated speed of the discovered asteroid, 8 km/sec, is relatively high.
Given that the asteroid is moving at such a high speed, it suggests that its distance from the Sun should be closer, rather than at 13.5 AU. At that distance, the asteroid would be expected to have a slower speed.
Therefore, based on the established pattern of planetary speeds and distance, the estimated distance of 13.5 AU for the asteroid does not align with the expected speed. It is more likely that the asteroid is closer to the Sun than the estimated distance, possibly within the inner regions of the solar system. Further observations and calculations would be necessary to accurately determine its true distance from the Sun.
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Select the correct answer. What type of electric current does a power plant generate for use in your home? A. direct B. alternating C. repeating D. straight
Answer:
Alternating current
Explanation:
We know that electric current is defined as the electric charge divided by time.
There are two types of current i.e. direct current (D.C) and alternating current (A.C)
Direct current: The flow of electric charge in one direction is called as direct current. It was produced firstly by Alessandro Volta in 1800. One of the examples of direct current is the battery.
Alternating current: The flow of electric charges that reverses the direction periodically is known as alternating current.
a concave mirror has a focal length of 12cm the object is [laced at 24cm. What type, orientation,location and magnification does the image have?
To obtain the type, orientation, location and magnification of the image, we shall first obtain the location (i.e distance) of the image from the mirror. Details below:
The location i.e distance of the image can be obtained as follow:
Focal length (f) = 12 cmObject distance (u) = 24 cmImage distance (v) =?1/f = 1/v + 1/u
Rearrange
1/v = 1/f - 1/u
v = (f × u) / (u - f)
v = (12 × 24) / (24 - 12)
v = 288 / 12
v = 24 cm
Thus, the the location of the image is 24 cm
Since the location of the image is positive (i.e 24 cm). Thus,
The type of image is realThe orientation of the image is invertedNow, we shall obtain the magnification of the image. Details below:
Object distance (u) = 24 cmImage distance (v) = 24 cmMagnification (m) = ?Magnification = image distance (v) / object distance (u)
Magnification = 24 / 24
Magnification = 1
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two forces f1=(8i+3j)N and f2=(4i+6j) are acting on 5kg object then what is the magnitude and the direction of the resultant force
what is its acceleration of x and y component
what is the magnitude of acceleration of the object
Two forces f1=(8i+3j)N and f2=(4i+6j) are acting on 5kg object then the magnitude of the resultant force is 15 N and the direction of the resultant force is approximately 36.87 degrees from the positive x-axis.
The acceleration of the object in the x-component ([tex]a_x[/tex]) is 2.4 [tex]m/s^{2}[/tex], and the acceleration in the y-component ([tex]a_y[/tex]) is 1.8 [tex]m/s^{2}[/tex].
The magnitude of the acceleration of the object is 3 [tex]m/s^{2}[/tex].
To find the magnitude and direction of the resultant force, we need to add the two given forces together.
Given:
f1 = (8i + 3j) N
f2 = (4i + 6j) N
To find the resultant force ([tex]F_res[/tex]), we simply add the corresponding components:
[tex]F_res[/tex] = f1 + f2
= (8i + 3j) + (4i + 6j)
= (8 + 4)i + (3 + 6)j
= 12i + 9j
The magnitude of the resultant force ([tex]|F_res|[/tex]) can be found using the Pythagorean theorem:
[tex]|F_res|[/tex]= [tex]\sqrt{(12^2) + (9^2)}[/tex]
= [tex]\sqrt{144 + 81}[/tex]
= [tex]\sqrt{225}[/tex]
= 15 N
So, the magnitude of the resultant force is 15 N.
To find the direction of the resultant force, we can use trigonometry. The direction can be represented by the angle θ between the positive x-axis and the resultant force vector. We can calculate θ using the inverse tangent function:
θ = arctan(9/12)
= arctan(3/4)
≈ 36.87 degrees
Therefore, the direction of the resultant force is approximately 36.87 degrees from the positive x-axis.
Now let's calculate the acceleration of the object in the x and y components. We know that force (F) is related to acceleration (a) through Newton's second law:
F = ma
For the x-component:
[tex]F_x[/tex]= 12 N
m = 5 kg
Using [tex]F_x[/tex]= [tex]ma_x[/tex], we can solve for [tex]a_x[/tex]:
12 N = 5 kg * [tex]a_x[/tex]
[tex]a_x[/tex]= 12 N / 5 kg
[tex]a_x[/tex] = 2.4 [tex]m/s^{2}[/tex]
For the y-component:
[tex]F_y[/tex] = 9 N
m = 5 kg
Using [tex]F_y[/tex] = [tex]ma_y[/tex], we can solve for [tex]a_y[/tex]:
9 N = 5 kg * [tex]a_y[/tex]
[tex]a_y[/tex] = 9 N / 5 kg
[tex]a_y[/tex]= 1.8 [tex]m/s^{2}[/tex]
So, the acceleration of the object in the x-component ([tex]a_x[/tex]) is 2.4 [tex]m/s^{2}[/tex], and the acceleration in the y-component ([tex]a_y[/tex]) is 1.8 [tex]m/s^{2}[/tex].
To find the magnitude of the acceleration (|a|), we can use the Pythagorean theorem:
|a| = [tex]\sqrt{(a_x^2) + (a_y^2)}[/tex]
= [tex]\sqrt{(2.4^2) + (1.8^2}[/tex]
= [tex]\sqrt{5.76 + 3.24}[/tex]
= [tex]\sqrt{9}[/tex]
= 3 [tex]m/s^{2}[/tex]
Therefore, the magnitude of the acceleration of the object is 3 [tex]m/s^{2}[/tex]
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certain force is expressible as F= 10i+bj. What is the value of b if the magnitude the force is 26N?
The value of force b if the magnitude the force is 26N is determined as 24 N.
What is the value of force b?
The value of force is calculated by applying the formula for determining the magnitude of a force as shown below;
The magnitude of a force is calculated as;
F = √ x² + y²
where;
x is the component of the forcey is the y component of the forceF is the magnitude of the forceThe given magnitude of the force = 26 N
The x component of the force = 10
The y component of the force = b
26 = √ ( 10² + b² )
26² = 10² + b²
676 = 100 + b²
b² = 676 - 100
b² = 576
b = √ 576
b = 24 N
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Sunlight is incident on a diffraction grating that has 3,300 lines/cm. The second-order spectrum over the visible range (400-700 nm) is to be limited to 2.15 cm along a screen that is a distance L from the grating. What is the required value of L?
The required length of L which is the distance from the grating to screen is: 8.696 cm
What is the length of the diffraction Grating?The event of deviating the wave from the original path of propagating due to obstruction of any obstacle. Diffraction happens near the slit, edges, or corners of the object. Interference differs from the diffraction in such a way that in interference, only some waves are considered.
We are given that:
Grating: n = 3300 lines/cm
The shortest wavelength is: λs = 400 nm
The longest wavelength is: λl = 700nm
The distance limited is: y = 2.15 cm
The expression for separation of slit is given for the second order as,
d sin θ = mλ
Here,
d is spacing,
m is the order.
Calculate the value of spacing.
d = 1/n
d = 1/3300
d = 0.0003030 cm
d = 3030.30 nm
Substituting the value in the above expression for shorter wavelength,
3030.30 sinθ = 2 * 400
sinθ_s = 800/3030.30
sinθ_s = 0.264
θ_s = 15.31°
Substituting the value in the above expression for longer wavelength,
3030.30 sinθ = 2 * 700
sinθ_l = 1400/3030.30
sinθ_l = 0.462
θ_l = 27.52°
Now, for expression for the distance from the grating to screen is calculated as:
L = y/(tan θ_l - tan θ_s)
L = 2.15/(tan 27.52° - tan 15.31)
L = 8.696 cm
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a beam of monochromatic light travels through flint glass, crown glass, lucite, and water. the speed of light beam is slowest in
Answer:
The answer is flint glass.
What blues elements can you hear in ( Bessie Smith, St Louis Blues ) ??
"Bessie Smith, St. Louis Blues" is a classic example of the Blues genre. Here are some Blues elements you can hear in the song:
12-bar blues chord progression: The song follows a standard 12-bar blues chord progression, which is a common feature of Blues music.
Call and response: The lyrics and melody are structured in a call-and-response format between the lead vocalist and the band, which is another common element of Blues music.
Soulful vocal delivery: Bessie Smith's powerful, emotional vocal delivery is characteristic of the Blues genre. She uses a lot of vibrato, melisma, and other vocal techniques to convey the feeling of the song.
Blues scale: The melody and solos in the song are based on the Blues scale, which consists of the root, flat third, fourth, flat fifth, fifth, and flat seventh notes of the major scale.
Use of blue notes: The use of blue notes, which are microtonal notes that fall in between the pitches of the standard major scale, is another hallmark of the Blues genre.
Name: Mallachi
Period:
Weather V. Climate, Circa Aug. 2020
Weather and climate may seem to be the same entity but there are crucial
differences between the two that one must understand in order to understand
the effects that events have on either the weather or the climate. The weather
is what we can see when we look out the window. It might be a sunny day with
children playing soccer games outside or a rainy day when all you can see is a
sea of umbrellas. We might use the weather to predict whether or not we will
have a white Christmas. The climate, on the other hand, is measured over
periods of at least 30 years, while sometimes spanning centuries. Let's say we
are looking at an artic environment and this particular environment has had a
warmer winter, much warmer than the average for this artic region, and is
caused by melting ice caps. Would this change be classified as a change in
weather or climate? When might the classification change?
CLAIM
A total of how many pairs of electrons are being shared between the atoms in the bond diagram H-H?
here are a total of two electrons being shared between the atoms in the H-H bond diagram.
In the bond diagram H-H, the symbol "H" represents a hydrogen atom. Hydrogen is an element that exists as diatomic molecules, meaning it naturally forms pairs of atoms. In the case of H-H, two hydrogen atoms are bonded together.
Each hydrogen atom contributes one electron to the shared pair in the bond. Therefore, in the H-H bond diagram, there is a single pair of electrons being shared between the two hydrogen atoms.
Since each pair of electrons consists of two electrons, we can say that there are a total of two electrons being shared between the atoms in the H-H bond diagram. It is important to note that hydrogen forms a single covalent bond with another hydrogen atom, resulting in a stable H2 molecule.
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If someone gets pushed through a small opening and hits someone else, whose fault is it, the person who got pushed or the person who pushed?
A rod with a length of L = 1 m is held vertically so that one end rests on the floor. After that
let go of the stick and fall. Let us assume that the supported end does not slip and that the thickness of the bar is very small compared to its length (that is, its moment of inertia with respect to the center of gravity is IT = 1/12mL^2
(a) With what speed does the other end of y hit the floor?
(b) How much does the end impact speed increase if it were a 100 m tall object that was originally
blasted off (and not broken when falling)?
Hint: Use the law of conservation of mechanical energy. Kinetic energy can be written in two ways:
1. Pure rotary movement around the end of the rod. 2. Rotary movement around the center of gravity + movement of the center of gravity. Both procedures,
of course, give the same result (you can try both and see for yourself).
Explanation:
(a) Let's use the law of conservation of mechanical energy to determine the speed with which the other end of the rod hits the floor. When the rod is released, it begins to rotate around its center of gravity and falls to the floor. At the moment of release, the rod has no kinetic energy or potential energy, but it has potential energy when it reaches the floor. The energy is conserved, so we can equate the initial potential energy to the final kinetic energy.
The initial potential energy of the rod is given by:
U_i = mgh
where m is the mass of the rod, g is the acceleration due to gravity, and h is the height of the center of gravity above the floor. Since the rod is vertical, h = L/2. The mass of the rod can be calculated using its density ρ and cross-sectional area A:
m = ρAL
The final kinetic energy of the rod is given by:
K_f = (1/2)Iω^2 + (1/2)mv^2
where I is the moment of inertia of the rod with respect to its center of gravity, ω is the angular velocity of the rod, and v is the linear velocity of the center of gravity. At the moment when the rod hits the floor, the angular velocity is zero, so the first term in the above equation is zero. We can simplify the equation to:
K_f = (1/2)mv^2
We can equate the initial potential energy and final kinetic energy to get:
mgh = (1/2)mv^2
Solving for v, we get:
v = sqrt(2gh)
Substituting the given values, we get:
v = sqrt(2gL/2) = sqrt(gL/2)
Now, we can substitute the values of g and L to get:
v = sqrt(9.81 m/s^2 x 1 m/2) = sqrt(4.905) m/s
Therefore, the other end of the rod hits the floor with a speed of approximately 2.216 m/s.
(b) If the length of the rod were 100 m instead of 1 m, the speed with which the end hits the floor would increase significantly. The potential energy of the rod when it is released is proportional to its height above the floor, so when the length of the rod is increased by a factor of 100, the potential energy increases by a factor of 100 as well. Therefore, the final speed of the end hitting the floor would be:
v' = sqrt(2gh') = sqrt(2g(100L)/2) = sqrt(100gL/2) = 10sqrt(gL/2)
Substituting the given values, we get:
v' = 10sqrt(9.81 m/s^2 x 100 m/2) = 10sqrt(490.5) m/s
Therefore, the end of the 100 m tall object would hit the floor with a speed of approximately 70.0 m/s, which is a significant increase compared to the initial speed of the 1 m rod.
Shoshauna and Tamir are students who have
been investigating whether a material reflects blue
light. Read and compare their arguments, then
answer the questions below.
Shoshauna's Argument
The material does not reflect blue light. The
material appears green, not blue. This is evidence
that it does not reflect blue light.
Tamir's Argument
The material does not reflect blue light. A material
appears a certain color when that color of visible
light reflects off the material and into someone's
eyes. This material appears green and not blue, so
it must reflect green light, not blue light.
Which argument is more convincing? (highlight
one)
Shoshauna's argument
Tamir's argument
What makes one argument more convincing than
the other?
From the arguments, Tamir's argument is more convincing than Shoahauna's argument after the reflection of light.
Reflection of light defines the bouncing back off the light when the light ray is incident on the shining surface. The reflected ray changes the path of light changes with a constant speed of light. Objects appear colored when the object reflects sunlight. The object appears colored depending on the wavelength of light that it reflects.
When sunlight or white light incident on the object, the object absorbed all the wavelengths except the particular wavelength depending on the arrangement of atoms and re-emits the photons of a particular wavelength.
Hence, Tamir's argument is most convincing than Shoahauna's argument based on the reflection of color.
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Where can I find the earthquakes?
Answer:
Hokkaido, Japan
Explanation:
earth quakes are natural there
You add 50 mL of water at 10°C to 50 mL of water at 80°C. What is the most likely final temperature of the mixture?
The final temperature of the mixture formed by adding the water is most likely 30°.
The rule of conservation of energy is demonstrated by the calorimetric principle, which states that the total amount of heat lost by a hot body is equal to the total amount of heat acquired by a cool body.
Heat lost = Heat gain
50 x 4.18 x (T - 10) = 50 x 4.18 x (80 - T)
T - 10 = (80 - T)
T - 10 = 80 - 2T
3T = 90
Therefore, the final temperature of the mixture,
T = 90/3
T = 30°
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Can any one solve this question it’s urgent!!
r = √9/2(pg¹/₂) / (P-0)g. The expression is proved as follows:
How can we prove it?The following expression:
r = √9/2(pg¹/₂) / (P-0)g
where r is the radius of a cylindrical container filled with a liquid of density ρ, g is the acceleration due to gravity, and P is the pressure at the bottom of the container.
To prove this expression, express the equation for the pressure at a depth h in a fluid:
P = P0 + ρgh
where P0 is the pressure at the surface of the fluid, ρ is the density of the fluid, g is the acceleration due to gravity, and h is the depth of the fluid.
Supposing that the fluid is incompressible and that the pressure at the surface of the fluid is atmospheric pressure, P0 = 0. Rearrange the above equation to solve for h:
h = (P - P0) / (ρg)
Substituting the above expression for h into the formula for the volume V with height h and radius r:
V = πr²h
and simplifying using the expression for h derived above:
V = πr²(P - P0) / (ρg)
Solving for r:
r = √(V / (π(P - P0) / (ρg)))
= √(Vρg / π(P - P0))
Now, the mass of the fluid in the container is given by:
m = ρV
Substituting this expression into the equation for r above, we get:
r = √(mρg / π(P - P0))
Since the density of the fluid is given as ρ and the acceleration due to gravity is g, we can substitute these values to get:
r = √(mg / π(P - P0))
Finally, substitute the expression for P - P0 in terms of h and simplify to get:
r = √9/2(pg¹/₂) / (P-0)g
Therefore, we have proven the given expression for r.
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Which of the following can only be stopped by lead or concrete?
alpha particles
positrons
gamma rays
beta particles
Answer:
gamma rays (or x-rays)
Explanation:
Example when you get x-rays at the dentist and they put the lead vest over you to protect the rays from passing through your body.
a cart of mass 0.32 kg is placed on an air track and is oscillating on a spring. the position of the cart is given by the equation x=(12.4 cm) cos((6.35rad/s)t)
a) what is the spring constant of the spring?
b) what is the velocity (including direction) of the cart when the cart is first located at x=8.47 cm?
The spring constant of the spring is 20.78 N/m and the velocity of the cart when the cart is first located at x=8.47 cm is -0.082 m/s.
a) To find the spring constant of the spring, we can use the equation for the displacement of a mass undergoing simple harmonic motion on a spring.
x = A cos(ωt)
where x = displacement of the mass from its equilibrium position,
A = amplitude of the motion, and
ω = angular frequency of the motion.
Comparing this equation with the given equation, we can see that the amplitude of the motion is A = 12.4 cm = 0.124 m and the angular frequency is ω = 6.35 rad/s.
The equation for the displacement of a mass on a spring undergoing simple harmonic motion can also be written as:
[tex]x=\sqrt{m/k} *cos\omega t[/tex]
where m = mass of the object, and
k = spring constant.
Comparing this equation with the given equation, we can see that = [tex]\sqrt{m/k}[/tex] = 0.124 m.
Squaring both sides,
m/k = (0.124 m)² = 0.0154
Therefore, the spring constant of the spring is:
k = m / 0.0154
= (0.32)/(0.0154)
= 20.78 N/m
b) To find the velocity of the cart when it is first located at x = 8.47 cm, we need to take the derivative of the displacement equation w.r.t. time:
v = dx/dt
= d{A cos(ωt)}/dt
= -Aω sin(ωt)
Substituting the given values, we get:
v = -(0.124 m) * (6.35 rad/s) * sin(6.35t)
When the cart is located at x = 8.47 cm = 0.0847 m, using x = A cos(ωt):
0.0847 m = (0.124 m) * cos(6.35t)
cos(6.35t) = 0.6835
Taking the inverse cosine of both sides gives:
6.35t = 0.824 rad
t = 0.130 s
Substituting this value of t into the velocity equation gives:
v = -(0.124 m) * (6.35 rad/s) * sin(6.35 * 0.130 s) = -0.082 m/s
Therefore, the velocity of the cart when it is first located at x = 8.47 cm is -0.082 m/s, that is in the negative direction.
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A 20c coin has a mass of 6 grams. How much would €2.60 in 20c coins weigh? Show your work.
Hello!
20c = 0.2€
number coins = 2.6/0.2 = 13
1 coin => 6g
13 coins => 6g x 13 = 78g
The answer is 78 grams.
if a wave has a period of 30 seconds and then the frequency is cut to a quarter what is the new period?
name 2 of the most common ways by which heat energy can be transmitted?
Conduction and Convection is the two ways by which heat energy can be transmitted.
Heat energy can be transferred by the following ways-
Conduction is the exchange of heat between objects that are in direct contact with each other. In this handle, heat is exchanged from the hotter object to the colder object until they reach break-even with temperature. This may happen in solids, liquids, and gasses, but it is most proficient in solids. Convection is the exchange of heat through the development of a liquid, either a gas or a liquid. As the liquid moves, it carries heat vitality with it, exchanging the heat from one place to another. This strategy is capable of the development of heat within the environment, seas, and numerous mechanical forms that depend on the development of liquids.To learn more about heat energy,
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