Mass Heptane : 0.348 x 17 = 5.916 kg
mass C in Heptane (MW=100.21 g/mol) :
[tex]\tt \dfrac{7.12}{100.21}\times 5.916=4.959~kg[/tex]
Mass Nonane : 0.101 x 17 = 1.717 kg
mass C in Nonane (MW=128.2 g/mol) :
[tex]\tt \dfrac{9.12}{128.2}\times 1.717=1.446~kg[/tex]
Mass Octane : 0.551 x 17 = 9.367 kg
mass C in Otane (MW=114.23 g/mol) :
[tex]\tt \dfrac{8.12}{114.23}\times 9.367=7.872~kg[/tex]
Total mass produced :
4.959+1.446+7.872=14.277 kg
The branch of science which deals with chemicals is called chemistry.
The correct answer is 14.277 kg
The calculation part is as follows:-
Mass Heptane : [tex]0.348 * 17 = 5.916 kg[/tex] Mass C in Heptane (MW=100.21 g/mol) :[tex]\frac{7.12}{100.21} *5.916 = 4.959kg[/tex]
Mass Nonane : [tex]0.101 * 17 = 1.717 kg[/tex] Mass C in Nonane (MW=128.2 g/mol) :
[tex]\frac{9.12}{128.2} *1.717 =1.446kg[/tex]
Mass Octane : [tex]0.551 * 17 = 9.367 kg[/tex] Mass C in Otane (MW=114.23 g/mol) :
[tex]\frac{8.12}{114.23}*7.872 kg[/tex]
Total mass-produced is
[tex]4.959+1.446+7.872=14.277 kg[/tex]
Hence, the correct answer is - 14.277kg.
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If 4.25 grams of copper were plated out in the reaction:
3Cu2+ + 2Al ---> 3Cu + 2Al3+
What mass of aluminum would have dissolved?
Please show all work!
Answer:
gravwfewtu
Explanation:
ushifelllf
Silver nitrate and magnesium chloride react according to the following equation:
2AgNO3(aq) + MgCl2(aq) — 2AgCl(s) + Mg(NO3)2(aq)
What volume (in ml) of 0.247M MgCl2(aq) is required to react with 63.2 mL of 0.192M AgNO3(aq)?
Answer:
V=24,3mL
Explanation:
1)n(AgNO3)=Cm*V=0.063l*0.192M=0.012
2)n(AgNO3)/2=n(MgCl2) => MgCl2=0.012/2=0.006
3)V(MgCl2)=n/Cm=0.006/0.247=0.0243L=24,3ml
Which of the following is a simple definition of reduction?
A. the loss of electrons
B. the gain of electrons
C. an agent that oxidizes something
D. an agent that reduces something
The answer is B on Edg 2020
Answer:
B. the gain of electrons
Explanation:
An easy way to remember this concept is the pneumonic OIL RIG:
Oxidation is Loss (of electrons)
Reduction is Gain (of electrons)