Answer:
they will repel, moving in opposite,
Explanation
a wire with a current of 4 amps is in a magnetic field of 2 tesla. the magnetic field is oriented perpendicular to the wire. what is the magnitude of the force per unit length on the wire?
The magnitude of the force per unit length on the wire carrying a current of 4 amps in a magnetic field of 2 Tesla, oriented perpendicular to the wire will be 8 N/m.
It can be determined using the formula F = BIL,
where F is the force per unit length,
B is the magnetic field,
I is the current and
L is the length of the wire.
For the given data, B = 2 T, I = 4 A, L = 1 meter.
Therefore, F = BIL= 2 T x 4 A x 1 m= 8 N/m. Thus, the magnitude of the force per unit length on the wire is 8 N/m.
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a car is traveling at 40 m/s as it enters a turn of radius 25 meters. what minimum coefficient of friction must be maintained between the road and tires to make sure the car does not slide out of the turn?
The minimum coefficient of friction required for a car travelling at 40 m/s to not slide out of a turn of radius 25 meters is 0.21.
This is determined using the equation for the maximum centripetal force that the car can withstand. This equation states that the maximum centripetal force is equal to the mass of the car times its speed squared divided by the radius of the turn multiplied by the coefficient of friction. Using this equation, 0.21 is the coefficient of friction that is required to make sure the car does not slide out of the turn.
The equation for maximum centripetal force can be written as:
F = m*v2/r * μ Where m is the mass of the car, v is the velocity of the car, r is the radius of the turn, and μ is the coefficient of friction.
Since we are solving for the coefficient of friction (μ), we can solve this equation for μ:
μ = m*v2/r * F
Plugging in the given values, we get:
μ = (1000 kg) * (40 m/s)2 / (25 m) * (10000 N) = 0.21
Therefore, the minimum coefficient of friction required for a car travelling at 40 m/s to not slide out of a turn of radius 25 meters is 0.21.
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magnus has reached the finals of a strength competition. in the first round, he has to pull a city bus as far as he can. one end of a rope is attached to the bus and the other is tied around magnus's waist. if a force gauge placed halfway down the rope reads out a constant 1400 newtons while magnus pulls the bus a distance of 1.55 meters, how much work does the tension force do on magnus? the rope is perfectly horizontal during the pull.
The work done by the tension force on Magnus is 2170 J.
What is work?
Work is the product of the force acting on an object and the distance through which the object moves. In other words, work is accomplished when a force is used to transfer energy to an object, causing the object to move some distance as a result.
The force of 1400 N, Distance of 1.55 meters, and a rope tied around Magnus's waist.
The work done by the tension force on Magnus is the product of the force exerted by the tension force and the distance through which Magnus is moved.
W = Fd
where W = Work done by the tension force on Magnus
F = Force of tension force
= 1400 Nd
= Distance moved by Magnus
= 1.55 m
Substituting these values:
W = 1400 N x 1.55 mW
= 2170 J
Hence, the work done by the tension force on Magnus is 2170 J.
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the event horizon of a black hole marks the boundary where the escape velocity reaches the speed of light. calculate the schwarzschild radius for the event horizon of a 2.30 msun black hole.
The event horizon of this black hole is located at a radius of 2.84 km from its center.
The event horizon of a black hole marks the boundary where the escape velocity reaches the speed of light.
The Schwarzschild radius (Rs) of a black hole is the distance from the center of the black hole at which the escape velocity reaches the speed of light. For a 2.30 msun black hole, the Schwarzschild radius is calculated as:
Rs = 2G*M/c2 = 2*(6.674x10-11 m3kg-1s-2) * (2.30x1030 kg) / (3x108 m/s)2 = 2.84 km
The Schwarzschild radius of a 2.30 msun black hole is 2.84 km, meaning this is the distance from the center of the black hole at which the escape velocity reaches the speed of light.
Therefore, the event horizon of this black hole is located at a radius of 2.84 km from its center.
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if you hold a 1.85 kg k g package by a light vertical string, what will be the tension in this string when the elevator accelerates as in the previous part?
The tension in the string of a 1.85 kg package held by a light vertical string will depend on the acceleration of the elevator. When the elevator accelerates, the force of acceleration on the package will be equal and opposite to the tension in the string, causing the tension to increase.
The equation for tension in a string is:
Tension = Mass x Acceleration
Therefore, in this case, the tension in the string is equal to 1.85 kg x Acceleration.
If we assume that the acceleration of the elevator is a constant rate, then the tension in the string can be calculated by multiplying the mass of the package by the acceleration of the elevator.
To sum up, the tension in the string of a 1.85 kg package held by a light vertical string will depend on the acceleration of the elevator. If the acceleration of the elevator is a constant rate, then the tension in the string can be calculated by multiplying the mass of the package by the acceleration of the elevator.
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two students sit on a seesaw in a way that makes it balance and not move. when a third person pushes down on one side, that side moves down. what caused the seesaw to move?
The seesaw moved when a third person pushed down on one side. This is because the seesaw is a simple machine that consists of a long plank balanced in the middle with a pivot point that allows it to move up and down.
When the two students sit on the seesaw in a way that makes it balance and not move, they are evenly distributed on each end. However, when the third person pushes down on one side, this distribution of weight becomes unequal, and the seesaw moves in the direction of the heavier side.
The heavier end of the seesaw moves down while the lighter end moves up. This is because the heavier side creates more force, or torque, on the pivot point, causing the seesaw to tilt towards that side.
As a result, the seesaw moves and is no longer in balance.
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a cat, also of weight 36.9 n , falls asleep on top of block a. if block b is now set into downward motion, what is its acceleration direction?
Deceleration with steady pace way equilibrium of forces is WB/WA. Write equations by Newton's second law for the scenario with cat is -g(WB/(WA+ WB)).
A) Deceleration with steady pace way equilibrium of forces:
B:WB=T,
A:T=μN=μWA.
μ= T/WA= WB/WA.
B) Write equations by using Newton's 2nd regulation for the scenario with cat:
B:T−WB =−(WB/g)a,
A:T−2μWA = (WA/g)a.
T = WB - (WB/g)a,
WB - (WB/g)a - 2(WB/WA)WA = (WA/g)a,
a(WA/g + WB/g)= -WB,
a=-g(WB/(WA+ WB)).
Deceleration refers to the act of slowing down or reducing speed. It is the opposite of acceleration, which is the increase in speed or velocity. Deceleration can occur in various contexts, including physics, engineering, and daily life.
In physics, deceleration is the rate at which an object slows down or changes its direction. It is measured in meters per second squared (m/s^2) or feet per second squared (ft/s^2). Deceleration is caused by forces such as friction, air resistance, or braking. In engineering, deceleration is an important factor in the design and safety of vehicles and machines. Proper deceleration systems, such as brakes or airbags, are essential to prevent accidents and protect occupants.
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Complete Question: -
Consider the system shown in the figure. Block A has a weight and block B has a weight . Once block B is set into downward motion, it descends at a constant speed.
a) Calculate the coefficient of kinetic friction between block A and the tabletop.
b) A cat, also of weight , falls asleep on top of block A. If block B is now set into downward motion, what is its acceleration (magnitude and direction)?
Is elasticl energy a type of
potential energy or kinetic
energy?
Elastic energy is a type of potential energy. It is the energy stored in an elastic material when it is stretched or compressed.
Potential energy explained.
Potential energy is a type of energy that is stored within an object due to its position or configuration. It is the energy that an object possesses by virtue of its position, shape, or state, and has the potential to do work.
Potential energy can be converted into kinetic energy, which is the energy of motion, when the object is allowed to move or fall. The total energy of a system, including both potential and kinetic energy, is conserved, meaning it remains constant unless acted upon by external forces.
Elastic energy is a type of potential energy. It is the energy stored in an elastic material when it is stretched or compressed. When an elastic material such as a spring is stretched or compressed, work is done on it, and this work is stored in the form of elastic potential energy. This potential energy can be released when the material returns to its original shape, causing it to vibrate or move.
Therefore, elastic potential energy is a type of potential energy that can be converted into kinetic energy as the material moves back to its original shape.
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An object in free fall is accelerating downwards, so its velocity is continually increasing. Because of this, its momentum is continually increasing as well, apparently contradicting the principle of conservation of momentum. Which of Newton's laws can we use to show that momentum is actually being conserved for an appropriately defined system?
Momentum may be demonstrated to be conserved for a properly described system using Newton's third law.
Newton's third law may be used to show that momentum is preserved for a system that is adequately defined. The Earth is being drawn towards the item in an equal and opposing force to that of gravity acting on the object while it is in free fall. As a result, the object's momentum is transferred to the Earth, which has a considerably higher mass and is hence more difficult to detect. The system's overall momentum—that of the Earth and the object—remains preserved. An open system like this one allows momentum to be shared with the environment while yet adhering to conservation standards.
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Find the change in temperature of each sample after the hot water was added. Fill in the table with the data you collected in parts C and D. To find the change in a sample’s temperature, subtract the starting temperature from the ending temperature.
Sample Starting Temperature Ending Temperature Change in Temperature
50 g sand
50 g water
100 g water
The change in temperature of 50 g sand :50 g water and 100 g water is
10°C ;15°C and 15.1°C
The change in temperature of each sample after the hot water was added can be found by subtracting the starting temperature from the ending temperature. For the 50 g sand sample, the starting temperature was 23.4°C and the ending temperature was 33.4°C, so the change in temperature was 10°C. For the 50 g water sample, the starting temperature was 22.7°C and the ending temperature was 37.7°C, so the change in temperature was 15°C. For the 100 g water sample, the starting temperature was 21.5°C and the ending temperature was 36.6°C, so the change in temperature was 15.1°C.
Sample Starting Temp Ending Temp Change in Temp
50 g sand 23.4°C 33.4°C 10°C
50 g water 22.7°C 37.7°C 15°C
100 g water 21.5°C 36.6°C 15.1°C
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a coil is placed in a changing magnetic field and an emf is induced. what happens to the induced emf if the rate of change of magnetic field quadruples?
The induced EMF increases to four times its initial value if the rate of change of the magnetic field quadruples.
Faraday's law of electromagnetic induction specifies that an emf (electromotive force) is induced in a closed conductor or coil whenever there is a change in magnetic flux associated with it.
EMF = − d(ΦB) /dt
ΦB = BAcosθ
This equation suggests that emf is proportional to the rate at which magnetic flux ΦB is changing with respect to time. As a result, if the rate of change of the magnetic field quadruples, the induced EMF increases to four times its initial value.
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calculate the average force on the person if he is stopped by a padded dashboard that compresses an average of 1.00 cm. calculate the average force on the person if he is stopped by an air bag that compresses an average of 15.0 cm.
The average force on the person if they are stopped by an airbag that compresses an average of 15.0 cm is approximately 70,000 N.
To calculate the average force on a person,
Average force = (change in momentum) / (time interval)
Assuming that the person's initial velocity is constant, we can simplify the formula to,
Average force = (mass of the person) x (change in velocity) / (time interval)
Now, let's consider the two scenarios,
Stopped by a padded dashboard that compresses an average of 1.00 cm:
Assuming the person's initial velocity is known and constant, we need to know the time interval it takes for the person to stop after hitting the dashboard. Without this information, we cannot calculate the average force.
Stopped by an airbag that compresses an average of 15.0 cm:
The time interval for an airbag to deploy and cushion the person's impact is typically very short (about 0.03 seconds), so we can assume that the time interval is negligible in this case. Therefore, we can use the simplified formula above.
Let's assume the mass of the person is 70 kg and their initial velocity is 30 m/s. The change in velocity is the final velocity (0 m/s) minus the initial velocity (30 m/s), which is -30 m/s. The negative sign indicates that the person's velocity is decreasing.
Using the formula,
Average force = (mass of the person) x (change in velocity) / (time interval)
= (70 kg) x (-30 m/s) / (0.03 s)
= -70,000 N
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a brick is falling from the roof of a three-story building. how many force vectors would be shown on a free-body diagram? name them
A brick is falling from the roof of three story building then free-body diagram would show only one force vector, which is the force of gravity acting on the brick.
A free-body diagram is used to graphically represent the forces acting on an object. It shows all of the forces acting on an object and can be used to analyze the motion of an object.
A free-body diagram for a falling brick would include two force vectors: Gravity or Weight.
If we consider only the brick and neglect air resistance, then there are two force vectors that would be shown on a free-body diagram of the brick:Force of gravity: The force of gravity, which pulls the brick downwards with a magnitude of its weight. This force is always present and directed downwards towards the center of the Earth. Normal Force: The normal force, which is the force exerted by the roof or any surface in contact with the brick that prevents it from falling through the surface. As the brick is falling, there is no contact force from the roof, so the normal force is zero.So, in this scenario, the free-body diagram would show only one force vector, which is the force of gravity acting on the brick.
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old faithful geyser in yellowstone national park shoots water every hour to a height of 40.0 m. with what velocity does the water leave the ground?
The velocity with which the water leaves the ground is 28.0 m/s (downward).
The Old Faithful Geyser in Yellowstone National Park shoots water every hour to a height of 40.0 meters.
To find the velocity with which the water leaves the ground, we can use the following kinematic equation:
v² = u² + 2as
Here,
v = final velocity
u = initial velocity
a = acceleration due to gravity
s = distance traveled by the object
The initial velocity of the water when it leaves the ground is 0 m/s.
Also, we can assume the final velocity of the water when it reaches the maximum height to be 0 m/s.
We know that the acceleration due to gravity is -9.8 m/s² (negative due to the direction).
The distance traveled by the water is the height to which it rises, i.e., 40.0 meters.
Using the above values in the kinematic equation, we get:
v² = 0² + 2*(-9.8)*40.0v² = -784v = √(-784)
Since the answer is coming out to be negative, it indicates that the velocity is in the downward direction.
So, the velocity with which the water leaves the ground is 28.0 m/s (downward).
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an n-type piece of silicon experiences an electric field equal to 0.1v/m. (a) calculate the velocity of electrons and holes in this material
In an n-type piece of silicon, the electric field causes the electrons to accelerate due to the attractive force between the negatively charged electrons and the positively charged electric field. This acceleration causes the electrons to reach a velocity of V = E/μ, where E is the electric field (0.1V/m) and μ is the mobility of electrons in silicon (1350 cm2/V⋅s). Therefore, the velocity of electrons in this material would be equal to 0.1V/m/1350cm2/V⋅s = 0.0741 cm/s.
The holes, on the other hand, experience a repulsive force due to the positive electric field. This causes the holes to decelerate, with a velocity of V = -E/μ. Therefore, the velocity of holes in this material would be equal to -0.1V/m/1350cm2/V⋅s = -0.0741 cm/s.
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a spherical capacitor has vacuum between its conducting shells and a capacitance of 125 pf . the outer shell has inner radius 9.00 cm . what is the outer radius of the inner shell? express your answer with the appropriate units.
For a spherical capacitor with a capacitance of 125 and a vacuum between its conducting shells, the outer radius of the inner shell is around 5.60 cm.
The capacitance of a spherical capacitor is given by:
C = 4πε₀[(r₁r₂)/(r₂-r₁)]
where C is the capacitance, ε₀ is the electric constant (8.85 x [tex]10^{-12}[/tex] F/m), r₁ is the radius of the inner shell, and r₂ is the radius of the outer shell.
In this case, we know that the capacitance C = 125 pF (picoFarads), r₂ = 9.00 cm, and we want to find r₁.
We can rearrange the equation to solve for r₁:
r₁ = (C × r₂)/(4πε₀ + C)
Substituting the values:
r₁ = (125 x [tex]10^{-12}[/tex] F × 0.09 m) / (4π × 8.85 x [tex]10^{-12}[/tex] F/m + 125 x [tex]10^{-12}[/tex] F)
r₁ ≈ 5.60 cm
Therefore, the outer radius of the inner shell is approximately 5.60 cm.
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in u.s. customary units, air pressure is measured in pounds per square inch. in the metric system, it is measured in pascals, and one pascal is equal to
In the metric system, air pressure is measured in pascals. One pascal is equal to a force of one newton per square meter.
Air pressure can be measured using different units. Pascal is a unit of pressure, defined as one newton per square meter. This unit is named after Blaise Pascal, a French mathematician, physicist, and philosopher who made important contributions to the fields of hydrodynamics and hydrostatics.
In the US customary system, air pressure is measured in pounds per square inch (psi), while in the International System of Units (SI), it is measured in pascals (Pa). The unit psi is used to measure pressure in liquids and gases, and it is defined as the amount of pressure exerted by a force of one pound-force per square inch.
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7) you drop a stone down a well that is 9.5 m deep. how long is it before you hear the splash? the speed of sound in air is 343 m/s and air resistance is negligible
If you drop a stone down a well that is 9.5 m deep, it will take approximately 0.028 seconds for you to hear the splash. This is because the speed of sound in air is 343 m/s, and air resistance is negligible.
The question is about finding the time it will take for the sound of the splash to reach the surface of the well. Given data:
Depth of the well = 9.5 m
Speed of sound in air = 343 m/s
We have to find the time it will take for the sound of the splash to reach the surface of the well.
Let's assume that "t" is the time that the sound of the splash takes to reach the surface of the well.
Using the formula:
t = Distance/Speed
Using the above formula, let's find the time it will take for the sound of the splash to reach the surface of the well.
Distance = Depth of the well = 9.5 m
Speed = Speed of sound in air = 343 m/s
So, the time is:
t = Distance/Speed
t = 9.5/343
t = 0.0277 s ≈ 0.028 s
Therefore, the time it will take for the sound of the splash to reach the surface of the well is 0.028 s
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a 7.6 nc point charge and a - 2.6 nc point charge are 3.1 cm apart. what is the electric field strength at the midpoint between the two charges?
The electric field strength at the midpoint between a 7.6 nc point charge and a -2.6 nc point charge which are 3.1 cm apart is 279.8 N/C.
What is an electric field?An electric field refers to a field surrounding a charged object, through which another charged object would feel a force. A charge placed in an electric field is subjected to a force depending on the charge and distance from the source of the field.
The electric field intensity or strength may be calculated using Coulomb's law by taking the charge 'Q' as a point charge and then determining the value of the electric field at a distance 'r' from the charge.
The magnitude of the electric field due to a point charge Q at a distance r is
E=kQ/r²,
where k is Coulomb's constant,
k=9×10⁹ Nm²/C².
So, the electric field at the midpoint is due to the combined effect of both charges. The charges are located 3.1 cm apart, so the midpoint is 1.55 cm from each of the charges. Therefore, we need to calculate the electric field due to each of the charges separately and add them up. The electric field at the midpoint due to a 7.6 nc point charge E₁=kQ₁/r₁²
=(9×10⁹ Nm²/C²)(7.6×10⁻⁹ C)/(0.0155 m)²
=294.47 N/C.
The electric field at the midpoint due to a -2.6 nc point charge
E₂=kQ₂/r₂²
=(9×10⁹ Nm²/C²)(-2.6×10⁻⁹ C)/(0.0155 m)²
=-14.67 N/C.
The net electric field at the midpoint is given by
E=E₁+E₂=294.47 N/C-14.67 N/C
=279.8 N/C.
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how to find the minimum thickness of a film such that reflected light undergo constructive interference
The minimum thickness of the film for constructive interference of reflected light would be t = 3*600/(2*1.4) = 850 nm.
The minimum thickness of a film required for constructive interference of reflected light can be calculated using the formula t = m*λ/(2*n),
where t is the minimum thickness of the film, m is the order of interference, λ is the wavelength of the light, and n is the index of refraction of the film.
For example, if the order of interference is 3, the wavelength of the light is 600 nm, and the index of refraction is 1.4,
the minimum thickness of the film for constructive interference of reflected light would be t = 3*600/(2*1.4) = 850 nm.
Constructive interference of reflected light occurs when the phase difference between the two waves is equal to an integral multiple of 2π.
This can be determined using the formula Δφ = (2π*m)/(λ*n), where Δφ is the phase difference, m is the order of interference, λ is the wavelength of the light, and n is the index of refraction of the film.
To achieve constructive interference, the minimum thickness of the film can be determined by ensuring that the phase difference is equal to an integral multiple of 2π.
The minimum thickness of a film required for constructive interference of reflected light can be calculated using the formula t = m*λ/(2*n),
where t is the minimum thickness of the film, m is the order of interference, λ is the wavelength of the light, and n is the index of refraction of the film.
Constructive interference can be achieved by ensuring that the phase difference between the two waves is equal to an integral multiple of 2π.
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a 100 ohm resistor is connect in parallel with a 300 ohm resistor. what is the equivalent resistance?
The equivalent resistance of the two resistors in parallel is 75 ohms.
To calculate the equivalent resistance of a 100-ohm resistor and a 300-ohm resistor connected in parallel, the following formula can be used:
Req = 1 / ((1/R1) + (1/R2))
where Req is the equivalent resistance, R1 is the resistance of the first resistor, and R2 is the resistance of the second resistor.
In this situation, the values of R1 and R2 are 100 ohms and 300 ohms, respectively.
Therefore, we can substitute these values into the equation as follows:
Req = 1 / ((1/100) + (1/300))= 1 / (0.01 + 0.00333)= 1 / 0.01333= 75 ohms
Therefore, the equivalent resistance of the two resistors in parallel is 75 ohms.
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why do the phases of venus show that the solar system is in a heliocentric model instead of a geocentric model?
The phases of Venus show that the solar system is in a heliocentric model instead of a geocentric model because the heliocentric model states that the Sun is at the center of the solar system, while the geocentric model states that Earth is at the center of the universe.
The phases of Venus can only be explained in the heliocentric model because the planet is orbiting the Sun.The phases of Venus are an important piece of evidence supporting the heliocentric model proposed by Nicolaus Copernicus. The geocentric model was the widely accepted model of the universe until the 16th century when Copernicus proposed the heliocentric model, which suggested that the Sun is at the center of the solar system and the Earth and other planets orbit around it.
The phases of Venus show that it orbits the Sun and not the Earth because, as it orbits the Sun, different portions of the planet's sunlit side are visible from Earth. This can only occur in a heliocentric model because Venus is between the Earth and the Sun in its orbit, which causes it to pass through phases. Therefore, the phases of Venus are not consistent with a geocentric model, which suggests that Venus orbits the Earth.
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what is the angular momentum of a 0.205 kg k g ball rotating on the end of a thin string in a circle of radius 1.45 m m at an angular speed of 11.6 rad/s r a d / s ?
The angular momentum of the ball rotating on the end of a thin string in a circle of radius 1.45 m m at an angular speed of 11.6 rad/s r a d / s is 6.07 × 10⁻⁶ kg m²/s.
Angular momentum is the quantity of motion that describes the rotation of a body about a fixed axis. It is a vector quantity that is the cross product of the position vector and the momentum vector.
The angular momentum of a 0.205 kg k g ball rotating on the end of a thin string in a circle of radius 1.45 m m at an angular speed of 11.6 rad/s r a d / s can be calculated as follows:
L = IωL = Iω
Here, L is angular momentum,
I is the moment of inertia of the ball, and
ω is the angular velocity of the ball.
The moment of inertia of a uniform sphere can be calculated as follows:
I= (2/5)mr²I = (2/5)mr²
Here, m is the mass of the sphere, and r is the radius of the sphere.
Therefore, the moment of inertia of the ball is given by:
I = (2/5)mr²I = (2/5) × 0.205 × (0.00145)²I = 5.23 × 10⁻⁷ kg m²
Substituting this value into the expression for angular momentum:
L = IωL = 5.23 × 10⁻⁷ × 11.6L = 6.07 × 10⁻⁶ kg m²/s.
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A dog can hear sounds in the range from 15
to 50,000 Hz.
What wavelength corresponds to the lower
cut-off point of the sounds at 20◦C where the
sound speed is 344 m/s?
Answer in units of m.
Explanation:
Speed of sound is 344
The frequency corresponding to the lower cut-off point is the lowest frequency which his 15Hz
F=15Hz
The relationship between the wavelength, speed and frequency is given as
v=fλ
Then,
λ=v/f
λ=v/f
λ=344/15
λ=22.93m
Worked Calculate the number of electrons that a positively charged object gains if its charge decreases by 3,2 x 10-18 C.
The positively charged object gains 20 electrons when its charge decreases by 3.2 x 10^-18 C.
What is Positive Charge?
A positive charge is an electrical property of matter that describes the presence of more positively charged protons than negatively charged electrons in an atom or molecule. In other words, an object with a positive charge has lost one or more electrons, resulting in a net charge that is greater than zero.
We know that the charge on a single electron is 1.602 x 10^-19 C.
To calculate the number of electrons gained by a positively charged object when its charge decreases by 3.2 x 10^-18 C, we can use the formula:
number of electrons = (magnitude of charge lost) / (charge on a single electron)
number of electrons = (3.2 x 10^-18 C) / (1.602 x 10^-19 C)
number of electrons = 20
Therefore, the positively charged object gains 20 electrons when its charge decreases by 3.2 x 10^-18 C.
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the intensity of the sound of a television commercial is 10 times greater than the intensity of the television program it follows. by how many decibels does the loudness increase?
The television commercial loudness increases by 10 decibels.
Increase in the Intensity of soundThe decibel (dB) scale is a logarithmic measure of sound intensity. The intensity of a sound is measured in watts per square meter and the decibel scale is a way to express the relative loudness of a sound, compared to a reference level.
A 10 dB increase in intensity is a 10-fold increase in sound power. This means that a sound with an intensity of 10 watts per square meter is 10 times louder than a sound with an intensity of 1 watt per square meter.
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which of the following are waves that can travel without a medium? select all that apply. visible light seismic waves x-rays waves on a lake sound waves radio waves
The following waves can travel without a medium: visible light, x-rays, and radio waves. Seismic waves and waves on a lake require a medium, such as air or water, to travel through.
Visible light is a form of electromagnetic radiation that is composed of various colors. It can travel through a vacuum, such as the space between planets, and does not require a medium to travel through. X-rays are also electromagnetic radiation, but with a higher frequency than visible light, allowing them to pass through objects that visible light cannot. Radio waves are also a form of electromagnetic radiation, and can travel through a vacuum. Seismic waves, on the other hand, require a medium, such as air or rock, to travel through. These waves are used to measure earthquakes and are created when energy is released from the ground. Similarly, waves on a lake require a medium, such as water, to travel through.
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the resistance between the two ends must remain the same, so what diameter must be chosen for the new wire?
T diameter of the new wire must be 0.1572 m in order to maintain the same resistance between the two ends.
To determine the diameter of the new wire required to maintain the same resistance, we can use the equation
R = ρL/A,
where R is the resistance, ρ is the resistivity of the material, L is the length, and A is the cross-sectional area of the wire.
Since we know that the resistance must remain the same, we can rearrange the equation to solve for A:
A = ρL/R.
Plugging in the given values for resistivity, length, and resistance, we can calculate the required cross-sectional area of the wire:
A = ρL/R = (0.0005 Ω⋅m)(5 m)/(5 Ω) = 0.0025 m^2.
Since the cross-sectional area of the wire is circular, we can use the equation for the area of a circle A = πr^2 to solve for the radius r, and thus the diameter d of the new wire:
r = sqrt(A/π) = sqrt(0.0025 m^2/π) = 0.0786 m
d = 2r = 2 x 0.0786 m = 0.1572 m
Therefore, the diameter of the new wire must be 0.1572 m in order to maintain the same resistance between the two ends.
When the resistance between the two ends must remain the same, the diameter chosen for the new wire is directly proportional to the length of the wire. According to Ohm's law, resistance is directly proportional to length and inversely proportional to the cross-sectional area of the wire. Therefore, if the length of the wire doubles, the resistance doubles, and if the area of the wire doubles, the resistance is halved.This means that when the resistance between the two ends must remain the same, the diameter of the new wire must be such that the cross-sectional area of the wire is proportional to the length of the wire. In other words, if the new wire is half the length of the original wire, its diameter should be twice that of the original wire, and so on.
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a semi-circular gate on an inclined wall is in contact with water. calculate the resultant force of the water on the gate
The resultant force of the water on the semi-circular gate on an inclined wall can be calculated using the equations of hydrostatics.
R = √([tex]F1^2 + F2^2 - 2*F1*F2*cos[/tex])α, where 'R' is the resultant force and 'α' is the angle of the wall.
First, determine the pressure of the water at any given point along the gate. To do this, multiply the density of the water, 'ρ', by the acceleration of gravity, 'g', and then the vertical height of the water relative to the gate, 'h', to get the pressure 'p':
p = ρ*g*h
Second, determine the force acting on the gate. This is done by multiplying the pressure with the area of the gate, 'A':
F = p*A
Finally, find the resultant force, 'R', by adding the forces together and taking into account the angle of the wall:
R = √([tex]F1^2 + F2^2 - 2*F1*F2*cos[/tex])α
where α is the angle of the wall.
By following these steps, you can calculate the resultant force of the water on the semi-circular gate on an inclined wall.
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a wooden block has a volume of 12.5 liters and a mass of 5.0 kg. what volume of water must be displaced if the wooden block is to float?
A wooden block has a volume of 12.5 litres and a mass of 5.0 kg. 5.0 litres of water must be displaced if the wooden block is to float.
What volume of water must be displaced if the wooden block is to float?The density of wood is less than the density of water. As a result, to float on water, an object made of wood must displace an amount of water greater than its weight.
The formula for calculating the density of an object is:
density = mass/volume
Rearranging this equation gives: v
olume = mass/density
From the information given in the question, the mass of the wooden block is 5.0 kg, and the volume is 12.5 liters.
Density is the mass divided by the volume:
density = mass/volume = 5.0 kg / 12.5 L = 0.4 kg/L
To float on water, the density of the wooden block must be less than the density of water, which is 1 kg/L.
Applying the formula above, we can solve for the volume of water displaced by the wooden block, which is equal to the volume of the block:
volume = mass/density = 5.0 kg / 1 kg/L = 5.0 L
Thus, 5.0 liters of water must be displaced if the wooden block is to float.
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