A nurse practitioner prepares an injection of promethazine, an antihistamine used to treat allergic rhinitis. If the stock bottle is labeled 30. mg/mL and the order is a dose of 14.0 mg , how many milliliters will the nurse draw up in the syringe?

Answer:

98.42 L of a gas

Explanation:

So we'll use the  formula:

PV=nRT

To find the volume:

v=(nRT)/P

n=1.2 moles

R=0.08206 Latm/K.mol

-A small side note: It is good to check the units of the quantities that you've been provided ,in order to determine which R value to use.

T=350K

P=0.35 atm

V=(1.2 x 0.08206 x 350)/(0.35)

V=98.472L

 =98.42 L

Hope it helps:)

Answer:

58.8 grams.

Explanation:

First we calculate how many HNO₃ grams are there in 400.0 g of a 10.0% solution:

Then we calculate the mass of a 68.0% solution that would contain 40 grams of HNO₃:

Answer:

2.24 g

Explanation:

First we use the PV=nRT formula to calculate the number of moles of the gas:

Then we can use the given molar mass to calculate the mass:

Which best compares kinetic energy and temperature?

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A. Kinetic energy is energy of motion, while temperature is a measure of that energy in substances. ✅

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Answer:

A. Kinetic energy is energy of motion, while temperature is a measure of that energy in substances.

Explanation:

got it right on edge 2021

Answer:

5.53 mL of hydrogen will produce 3.6867 mL of Ammonia

Explanation:

The complete balance equation for the given reaction is

N2 + 3H2 --> 2 NH3

Thus, 3 moles of hydrogen produces 2 moles of NH3

Hence, the volume of ammonia produced = 5.53 * (2/3) = 3.6867 mL

Hence, 5.53 mL of hydrogen will produce 3.6867 mL of Ammonia

Answer:

92.9 °C

Explanation:

Step 1: Given data

Step 2: Convert 55.0 °C to Kelvin

We will use the following expression.

K = °C + 273.15 = 55.0 + 273.15 = 328.2 K

Step 3: Calculate the final temperature of the gas

If we assume constant pressure and ideal behavior, we can calculate the final temperature of the gas using Charles' law.

T₁/V₁ = T₂/V₂

T₂ = T₁ × V₂/V₁

T₂ = 328.2 K × 502 mL/450. mL = 366 K = 92.9 °C

Answer:

The change in entropy is -1083.112 joules per kilogram-Kelvin.

Explanation:

If the water is cooled reversibly with no phase changes, then there is no entropy generation during the entire process. By the Second Law of Thermodynamics, we represent the change of entropy ([tex]s_{2} - s_{1}[/tex]), in joules per gram-Kelvin, by the following model:

[tex]s_{2} - s_{1} = \int\limits^{T_{2}}_{T_{1}} {\frac{dQ}{T} }[/tex]

[tex]s_{2} - s_{1} = m\cdot c_{w} \cdot \int\limits^{T_{2}}_{T_{1}} {\frac{dT}{T} }[/tex]

[tex]s_{2} - s_{1} = m\cdot c_{w} \cdot \ln \frac{T_{2}}{T_{1}}[/tex] (1)

Where:

[tex]m[/tex] - Mass, in kilograms.

[tex]c_{w}[/tex] - Specific heat of water, in joules per kilogram-Kelvin.

[tex]T_{1}[/tex], [tex]T_{2}[/tex] - Initial and final temperatures of water, in Kelvin.

If we know that [tex]m = 1\,kg[/tex], [tex]c_{w} = 4190\,\frac{J}{kg\cdot K}[/tex], [tex]T_{1} = 373.15\,K[/tex] and [tex]T_{2} = 288.15\,K[/tex], then the change in entropy for the entire process is:

[tex]s_{2} - s_{1} = (1\,kg) \cdot \left(4190\,\frac{J}{kg\cdot K} \right)\cdot \ln \frac{288.15\,K}{373.15\,K}[/tex]

[tex]s_{2} - s_{1} = -1083.112\,\frac{J}{kg\cdot K}[/tex]

The change in entropy is -1083.112 joules per kilogram-Kelvin.

Answer:

Explanation:

Change in entropy,

[tex]\delta S = mCp * In[\frac{T2}{T1}][/tex]

The initial temperature,

[tex]T1 = 100^oC\\\\T1 = 100+273\\\\T1 = 373k[/tex]

Final value of temperature,

[tex]T2 = 15^oC\\\\T2 = 15+273\\\\T2 = 288k[/tex]

where,

[tex]m = 1kg\\\\Cp = 4190 J/kg.k[/tex]

Substitute into [tex]\delta S[/tex]

[tex]\delta S = mCp * In[\frac{T2}{T1}]\\\\\delta S = 1 * 4190 * In[\frac{288}{373}]\\\\\delta S = 4190 * In[0.7721]\\\\\delta S = 4190 * [-0.2586]\\\\\delta S = -1083.534 J/k[/tex]

The negative sign exists because the change in entropy will be decreasing due to cooling.

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Answer:

[tex]V=2.9L[/tex]

Explanation:

Hello there!

In this case, by considering the given information in this problem, it is possible  for us to infer that this problem is solved by using the ideal gas equation:

[tex]PV=nRT[/tex]

Next, since we are given the moles, pressure and temperature, we proceed as follows:

[tex]V=\frac{nRT}{P}[/tex]

Then, we plug in the given data to obtain:

[tex]V=\frac{0.108mol*0.08206\frac{atm*L}{mol*K}*315K}{0.96atm}\\\\V=2.9L[/tex]

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percentage yield =(actual yield/theoretical yield) ×100/1

chlorine is the limiting reagent hence would be the major determinant of the product

71[Cl2]=2×58.5[NaCl]

200[Cl2]=x[NaCl]

x=(200×58.5×2)/(71)

x=329.58g(theoretical yield of NaCl)

percentage yield = (240/329.58) ×100

percentage yield= 72.8℅

The answer is that the percentage yield is 72.8 % .

Chemical reactions in the real world do not always go exactly as planned on paper.

In the course of an experiment, many things will contribute to the formation of less product than would be predicted.

Besides spills and other experimental errors, there are often losses due to an incomplete reaction, undesirable side reactions, etc.

Chemists need a measurement that indicates how successful a reaction has been. This measurement is called the percent yield.

Percentage yield =(actual yield/theoretical yield) ×100 %

Chlorine is the limiting reagent hence would be the major determinant of the product

Molecular weight of Cl₂ is 71

Molecular weight of NaCl is 58.5

For 1 mole of Cl₂ 2 moles of NaCl is produced

so it is given that Cl₂ is 200 grams

= 200/71

=2.82 moles.

=5.63 moles of NaCl

=5.63* 58.5 grams

=329.58 g of Nacl

So , 329.58g is theoretical yield of NaCl

percentage yield = (240/329.58) ×100

percentage yield= 72.8℅

Therefore the percentage yield = 72.8%

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Answer:

"23.896%" is the right answer.

Explanation:

The given values are:

Mass of NaCl,

= 51.56 g

Mass of H₂O,

= 165.6 g

As we know,

⇒  Mass of solution = [tex]Mass \ of \ (NaCl+H_2O)[/tex]

                                 = [tex]51.56+164.2[/tex]

                                 = [tex]215.76 \ g[/tex]

hence,

⇒ [tex]Mass \ percent =\frac{Mass \ of \ NaCl}{Mass \ of \ solution}\times 100[/tex]

                           [tex]=\frac{51.56}{215.76}\times 100[/tex]

                           [tex]=23.896 \ percent[/tex]

Answer:

42.9%

Explanation:

Step 1: Write the balanced decomposition reaction

PbO₂ ⇒ Pb + O₂

Step 2: Calculate the theoretical yield of O₂ from 5.77 g of PbO₂

According to the balanced equation, the mass ratio of PbO₂ to O₂ is 239.2:32.00.

5.77 g PbO₂ × 32.00 g O₂/239.2 g PbO₂ = 0.772 g O₂

Step 3: Calculate the percent yield of O₂

The real yield of O₂ is 0.331 g. The percent yield of O₂ is:

%yield = real yield / theoretical yield × 100%

%yield = 0.331 g / 0.772 g × 100% = 42.9%

Answer:

Mountains are built by tectonic processes that cause portions of the Earth's crust to rise. These processes are fueled by the escape of heat from the interior of the Earth, causing crustal uplift by volcanic activity and by movement along faults that, in turn, is responsible for the formation of mountains.

Explanation:

Answer:

a. Does not obey Conservation of Mass law

Explanation:

An example of an unbalanced chemical equation is:

As you can see, there are two Na atoms on the right side of the equation, while only one on the left side, causing the masses on both sides of the equation to not be equal. In other words, not fulfilling the Conservation of Mass law.

Compare with the correctly balanced equation:

Now both sides of the equation possess the same number of atoms for each element.

Answer:

CH3NH2

Explanation:

Hydrogen bonding is a bond that occurs between hydrogen and a highly electronegative element. It is a kind of dipole - dipole interaction. Hydrogen bonding only occurs when hydrogen is bonded to a highly electronegative element.

If we look at the options stated, it is only in CH3NH2  that hydrogen is bonded to a very electronegative element (nitrogen). Hence, CH3NH2  exhibits hydrogen bonding as its strongest intermolecular force among other intermolecular forces.

Answer:

CH3NH2

Explanation:

To form hydrogen bondings between the molecules, the compound needs a highly electronegative atom (usually N, O, or F) bonded with a hydrogen atom;

Answer:

Acids taste sour while bases taste bitter. An acid reacts with metals to produce bubbles of hydrogen gas while a base feels slimy to the touch. Acids turn blue litmus paper red while bases turn red litmus paper blue.

Answer:

0.25 M

Explanation:

First we convert 85.5 grams of sucrose into moles, using its molar mass:

Then we divide the number of moles by the number of liters to calculate the molarity:

Answer:

The temperature of the sample increase by 48 Kelvin

Explanation:

The sample is identical.

Hence the heat at constant pressure is equal to the heat at the constant Volume

Q1 = Q2

Q 1 = heat at constant pressure

Q2 = heat at the constant Volume

Substituting the given values, we get -

[tex]\frac{3}{2} nRT_1 = \frac{5}{2} nRT_2\\3 * 80 = 5 * T_2\\T_2 = 48[/tex]

The temperature of the sample increase by 48 Kelvin

SERIOUS flooding IN DELHI

Explanation:

Answer:

Option C, spontaneous or nonspontaneous depending upon the temperature of the surroundings and pressure

Explanation:

AT room temperature, the temperature is favorable for ice to melt and hence melting of ice at room temperature is spontaneous but when the temperature is below the melting point and even then the ice melts then it is called non spontaneous. In this case, the enthalpy and entropy together create a positive change in the free energy for melting.

Hence, option C is correct

Answer:

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Explanation:

A.

Sulfuric Acid, H2SO4 is a chemical compound made up of two hydrogen atom, one sulfer atom, and four oxygen atoms.

Answer:

Saturated organic compound has only single bonds between carbon atoms. An important class of saturated compounds are the alkanes. Many saturated compounds have functional groups, e.g., alcohols.

Unsaturated organic compound have double or triple covalent bonds between adjacent carbon atoms. The term "unsaturated" means more hydrogen atoms may be added to the hydrocarbon to make it saturated (i.e. consisting all single bonds).

Answer:

There won't be any equilibrium.

Explanation:

Because when we add a product to a system then the equilibrium will not be the same since the weight will be more on one system which will make it unstable.

Answer:

87.0%

Explanation:

Step 1: Write the balanced reaction

H₂O₂ ⇒ H₂O + 0.5 O₂

Step 2: Calculate the real yield of oxygen, in grams

We have 375 mL (0.375 L) of O₂ at 42 °C (315 K) and 1.52 atm. First, we will calculate the number of moles using the ideal gas equation.

P × V = n × R × T

n = P × V / R × T

n = 1.52 atm × 0.375 L / (0.0821 atm.L/mol.K) × 315 K = 0.0220 mol

The molar mass of oxygen is 32.00 g/mol.

0.0220 mol × 32.00 g/mol = 0.704 g

Step 3: Calculate the theoretical yield of oxygen, in grams

According to the balanced equation, the mass ratio of H₂O₂ to O₂ is 34.01:16.00.

1.72 g H₂O₂ × 16.00 g O₂/34.01 g H₂O₂ = 0.809 g O₂

Step 4: Calculate the percent yield of oxygen

We will use the following expression.

%yield = real yield / theoretical yield × 100%

%yield = 0.704 g / 0.809 g × 100% = 87.0%

Considering the reaction stoichiometry and the ideal gas law, the percent yield when 1.72 g of H₂O₂ decomposes and produces 375 mL of O₂ gas measured at 42 °C and 1.52 atm is 86.96%.

The balanced reaction is:

2 H₂O₂ → 2 H₂O +  O₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass, this is the amount of mass a substance contains in one mole, of H₂O₂ is 34 [tex]\frac{g}{mole}[/tex]. Then, the amount of moles of H₂O₂ that decomposes when 1.72 grams of H₂O₂ reacts is calculated as:

[tex]1.72 gramsx\frac{1 mole}{34 grams}= 0.0506 moles[/tex]

Then you can apply the following rule of three: if by stoichiometry 2 moles of H₂O₂ produce 1 moles of O₂, 0.0506 moles of H₂O₂ will produce how many moles of O₂?

[tex]amount of moles of O_{2} =\frac{0.0506 moles of H_{2} O_{2} x1 mole of O_{2} }{2 moles of H_{2} O_{2}}[/tex]

amount of moles of O₂= 0.0253 moles

On the other side, an ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of the gases:

P× V = n× R× T

In this case, for O₂ gas you know:

Replacing:

1.52 atm× 0.375 L = n× 0.082 [tex]\frac{atmL}{molK}[/tex]× 315 K

Solving:

[tex]n=\frac{1.52 atmx 0.375 L}{0.082\frac{atmL}{molK}x 315 K }[/tex]

n= 0.022 moles

The percent yield is calculated as

[tex]Percent yield= \frac{real yield}{theoretical yield} x100[/tex]

In this case, for oxygen the percent yield is calculated as

[tex]Percent yield of oxygen= \frac{0.022 moles}{0.0253 moles} x100[/tex]

Percent yield of oxygen= 86.96 %

Finally, the percent yield when 1.72 g of H₂O₂ decomposes and produces 375 mL of O₂ gas measured at 42 °C and 1.52 atm is 86.96%.

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Tungsten is the Largest

Having an atomic No of 74

Answer:

They tax the citizens and then provide them with relief efforts

Explanation:

Common disease protocol