A Or b
Question in picture

Answer:

Work done gets doubled.

Explanation:

The work done by a force is given by :

W = Fd

Where

F is force and d is distance move

If the force is doubled and the distance moved remain the same, it would mean that the work done becomes double of the initial work done.

At the time when force is doubled and distance moved remain the same so Work done gets doubled.

The following information should be considered:

W = Fd

Where

F is force and d is distance move

In the case when the force is doubled and the distance moved remain the same, it would mean that the work done becomes double of the initial work done.

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Answer:

Ice is the solid state of water, a normally liquid substance that freezes to the solid state at temperatures of 0 °C (32 °F) or lower and expands to the gaseous state at temperatures of 100 °C (212 °F) or higher.

Explanation:

Answer:

boiling water - When water heats, the heat from the burner is transferred to the container, heating the water at the bottom. This hot water rises, creating a circular motion, as colder water descends to replace it.

Answer:

b

Explanation:

is correct .....................

i think

B IS YOUR ANSWER.

Soft sound has small amplitude and louder sound has large amplitude. Since, the second wave has large amplitude, it will have the loudest sound.

Answer: Energy dissipation

As water passes over a spillway and down the chute, potential energy converts into increasing kinetic energy. Failure to dissipate the water's energy can lead to scouring and erosion at the dam's toe (base).

HOPE THIS HELPS

Answer: Energy dissipation

Explanation: As water passes over a spillway and down the chute, potential energy converts into increasing kinetic energy. Failure to dissipate the water's energy can lead to scouring and erosion at the dam's toe (base). Hope this helps. Can u give me brainiliest

Answer:

Recessive, dominant

Explanation:

umm thats the answer

Answer: i may not be 100% accurate but i believe it is iron, there is a fire work that uses iron to shine a certain way and is found on stars.

Volumes can be transfered to liters only when their measurement units are dm³. a) Which means that: 0.45m³=450dm³ you move the decimal place three places to the right because m³ is larger measurement unit than dm³. 375 cm³ = 0.375 dm³; 75cl = 0.75l because of the prefix centi. 0.6dm³ = 0.6 dm³

So it will be 450l; 0.375l; 0.75l; 0.6l

b) 450l>0.75l>0.6l>0.375l

0.45m³>75cl>0.6dm³>375cm³

I hope i didn't make a mistake, but it would be good if somebody else answered too, so you can compare the answers and see if i made a mistake

The given volumes in liter will be 450 L, 0.375 L, 0.75 L, 0.6 L and the arrangement in descending order will be 450 L > 0.75 L > 0.6 L > 0.37 L .

Every three-dimensional item takes up space in some way. The volume of this area is what is used to describe it. The area covered within an entity's three-dimensional bounds is referred to as its volume. The object's size is another name for it.

As per the given information in the question,

a.

The given volume in a meter cube is 0.45.

Unit conversion:

1 m³ = 1000 L

So, 0.45 m³ = 0.45 × 1000

= 450 L

The given volume in a centimeter cube is 375.

Unit conversion:

1 cm³ = 0.001 L

375 cm³ = 0.001 × 375

= 0.375 L.

The given volume in a centiliter cube is 75.

Unit conversion:

1 cl³ = 0.01 L

75 cl³ = 75 × 100

= 0.75 L

The given volume in the decimeter cube is 0.6.

1 dm³ = 1 L

0.6 dm³  = 0.6 L

b.

So, the volumes in descending order will be,

450 L > 0.75 L > 0.6 L > 0.37 L or,

0.45 m³ > 75 cl³ > 0.6 dm³ > 375 cm³

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Explanation:

1200 is your answer for this question

Answer:

the answer is  C

Explanation:

i took the test just now so i am glad i can help someone in the future❣❣❣❣

Also here is the explanation

Note that the magnitude of acceleration (a) is given by a =  

v2

R

, where v is the speed and R is the radius. Because acceleration is the same for both bikers, the ratio 

v2

R

, also has to be the same for both. Given that Kevin’s speed is higher, the radius of his path must also be higher to maintain the same ratio. Therefore, Kevin’s circular path has a bigger radius than Linda’s path.

Answer:

well

Explanation:

basically it's like

Answer:

It accelerate but will not spin.

Explanation:

If an irregular shaped object is dropped from rest without feeling any form of air resistance it will accelerate without spinning and this is due to the fact that there is no Torque around  the center of gravity

Answer:

In my opinion, ''A" would be the longest wavelength.

Answer:

3

Explanation:

Answer:

whether a net force acts on the object

Answer:

the required current is 0.12 A

Option b) 0.12 A is the correct answer

Explanation:

Given the data in the question,

to determine the current needed in the wire, we use the following relation;

B = μ₀n[tex]I[/tex]

[tex]I[/tex] = B / μ₀n

where μ₀ is the magnetic constant   ( 4π × 10⁻⁷ T.m/A )

n is the number of turns ( 1 / 1mm[tex]\frac{10^{-3}m}{1 mm}[/tex]) = 1000 m⁻¹

B is magnitude ( 150μT ( [tex]\frac{10^{-6}m}{1uT}[/tex]) )

so we substitute

[tex]I[/tex] =  [ 150μT ( [tex]\frac{10^{-6}m}{1uT}[/tex]) ] / [ ( 4π × 10⁻⁷ T.m/A ) × 1000 m⁻¹ ]

[tex]I[/tex] =  [ 0.00015 ] / [ 0.00125 ]

[tex]I[/tex] = 0.12 A

Therefore, the required current is 0.12 A

Option b) 0.12 A is the correct answer

Answer:

greater speed will be obtained for the elastic collision,

Explanation:

To answer this exercise we must find the speed that the sail acquires after each impact.

Let's start by hitting a ball of clay.

The system is formed by the candle and the clay balls, therefore the forces during the collision are internal and the moment is conserved.

initial instant. before the crash

         p₀ = m v₀

where m is the mass of the ball and vo its initial velocity, we are assuming that the candle is at rest

final instant. After the crash

the mass of the candle is M

         p_f = (m + M) v

the moment is preserved

          p₀ = p_f

          m v₀ = (m + M) v

          v = [tex]\frac{m}{m+M} \ v_o[/tex]

for when n balls have collided

          v = [tex]\frac{m}{n \ m + M}[/tex]  v₀

Now let's analyze the case of the bouncing ball (elastic)

initial instant

        p₀ = m v₀

final moment

        p_f = m v_{1f} + M v_{2f}

        p₀ = p_f

        m v₀ = m v_{1f} + M v_{2f}

       m (v₀ - v_{1f}) = M v_{2f}

this case corresponds to an elastic collision whereby the kinetic energy is conserved

        K₀ = K_f

        ½ m v₀² = ½ m v_{1f}² + ½ M v_{2f}²

        v₁ = v_{1f}            v₂ = v_{2f}

        m (v₀² - v₁²) = M v₂²

let's use the identity

         (a² - b²) = (a + b) (a-b)

we write our equations

         m (v₀ - v₁) = M v₂                       (1)

         m (v₀ - v₁) (v₀ + v₁) = M v₂²

let's divide these equations

         v₀ + v₁ = v₂

Let's look for the final speeds

we substitute in equation 1

          m (v₀ - v₁) = M (v₀ + v₁)

          v₀ (m -M) = (m + M) v₁

          v₁ = [tex]\frac{m-M}{m + M}[/tex]   v₀

we substitute in equation 1 to find v₂

            [tex]\frac{M}{m}[/tex]  v₂ = v₀ -  [tex]\frac{m-M}{m+M}[/tex]   v₀

            v₂ = [tex]\frac{m}{M} ( 1 - \frac{m-M}{m+M} ) \ v_o[/tex]

            v₂ = [tex]\frac{m}{M} ( \frac{2M}{m+M} ) \ \ v_o[/tex]

            v₂ = [tex]\frac{2m}{m +M} \ v_o[/tex]  

Let's analyze the results for inelastic collision with each ball that collides with the sail, the total mass becomes larger so the speed increase is smaller and smaller.

In the case of elastic collision, the increase in speed is constant with each ball since the total mass remains invariant.

Consequently, greater speed will be obtained for the elastic collision, that is, the ball will bounce.

Answer:

A.  Kepler's second law says that the radius vector sweeps equal areas in             equal times.

Answer:

Asch's experiment showed that about 75% of people were "yielders" who conformed and 25% were "independent" who didn't conform. Asch concludes that people ignored reality and gave an incorrect answer in order to follow the rest of the group.

Answer:

Mass doubles

Explanation:

Since F = ma, and given that the acceleration stayed constant, the mass must have changed. (Assuming thatt when the problem states the force doubles, they mean the net force doubles). Note, that the mass does not have to change if the acceleration is zero.

Answer:

Isopropyl alcohol would form smaller droplets because it has a lower surface tension than water has.

Explanation:

Answer:

its d

Explanation:

Answer:

explanation

Explanation:

1 = C

2 = A

3 = D

4 = E

5 = B

Answer:

yes, because you dont want to be mean and make her feel worse about it and hiv has something do with s3x not germs so yes go

Explanation:

Answer:

19 protons, 20 neutrons and 18 electrons.

Explanation:

The atomic number gives the number of protons 19

p

=

19

The atomic mass is the sum of the protons and neutrons

p

+

n

=

39

p

=

19

put p into the equation and solve for n the neutrons.

19

+

n

=

39

Subtract 19 from both sides

19

−

19

+

n

=

39

−

19

n

=

20

The number of electrons equals the number of protons in a neutral atom. The positive charge equals the negative charge. The negative charge is the number of electrons. This ion has a charge of +1. So solve for the negative charge.

−

19

+

1

=

−

18

The negative charge is -18 so

e

=

18

Complete question

To reduce the drag coefficient and thus to improve the fuel efficiency, the frontal area of a car is to be reduced. Determine the amount of fuel and money saved per year as a result of reducing the frontal area from 18 to 14 ft2. Assume the car is driven 12,000 mi a year at an average speed of 55 mi/h. Take the density and price of gasoline to be 50 lbm/ft3 and $3.10/gal, respectively; the density of air to be 0.075 lbm/ft3, the heating value of gasoline to be 20,000 Btu/lbm; and the overall efficiency of the engine to be 30 percent. Take the drag coefficient as CD=0.3 for a passenger car.

Answer:

22.22%

$57

Explanation:

From the question we are told that

Initial area of frontal area [tex]a_1=18ft^2[/tex]

Final area of frontal area [tex]a_2=14ft^2[/tex]

Distance covered a year [tex]D=12000mile[/tex]

Average speed a year [tex]V_{avg}=55mile/h[/tex]

Density [tex]\rho=50 lbm/ft3[/tex]

Price [tex]P= $3.10/gal[/tex]

Density of air [tex]\rho_{air} 0.075 lbm/ft3[/tex]

Heating value of gasoline [tex]Q=20,000 Btu/lbm[/tex]

Efficiency [tex]\eta=30\%[/tex]

Drag coefficient [tex]CD=0.3[/tex]

[tex]\triangle A=18-14ft^2=4ft^2[/tex]

Generally the equation for drag force [tex]C_D[/tex] is mathematically given as

[tex]F_D=\frac{C_DAPV^2}{2}[/tex]

[tex]F_D=\frac{0.3*18*0.075*(80.685^2)*A}{2}[/tex]

[tex]F_D=73.24Alb[/tex]

where [tex]v=55mil/h*1.467=80.685ft/s[/tex]

Generally the equation for work done W is mathematically given as[tex]W=F_D*L[/tex]

where [tex]L=12000mile*5280[/tex]

[tex]L=63360000[/tex]

[tex]W=73.24A*63360000[/tex]

[tex]W=4.6*10^9A[/tex]

Generally the equation for overall efficiency [tex]\eta[/tex] is mathematically given as

where

[tex]W_{req}=required\ gasoline\ power\ efficiency[/tex]

[tex]\eta=\frac{W}{W_{req}}[/tex]

[tex]W_{req}=\frac{W}{\eta}[/tex]

[tex]W_{req}=\frac{4.6*10^9}{0.3}[/tex]

[tex]W_{req}=1.55*10^{10}A[/tex]

Generally the equation for reduction fee with change in frontal area [tex]\triangle M[/tex] is mathematically given as

[tex]\triangle M =\triangle Vgasoline*cost[/tex]

Where

[tex]\triangle Vgasoline= volume\ reduction\ of\ gasoline[/tex]

[tex]\triangle Vgasoline=\frac{E_{req}}{H*P}[/tex]

[tex]\triangle Vgasoline=\frac{1.55*10^{10}A}{20000*778.169*32.2*50}[/tex]

if

[tex]20000btu/ibm=20000*778.169*32.2(1bm.ft^2/s)[/tex]

[tex]\triangle Vgasoline=\frac{1.55*10^{10}A}{20000*778.169*32.2*50}[/tex]

[tex]\triangle Vgasoline=0.61859A[/tex]

Therefore

[tex]\triangle M =0.61859A*3.10[/tex]

if [tex]1ft^2=7.48gal[/tex]

[tex]\triangle M =0.61859(4)*3.10*7.48[/tex]

[tex]\triangle M = \$ 57.671[/tex]

Generally the equation for reduction of fuel [tex]F_r[/tex]is mathematically given as

[tex]F_r=\frac{\triangle A}{\triangle i}*100[/tex]

where

[tex]\triangle i=18ft^2[/tex]

[tex]F_r=\frac{4}{18}*100[/tex]

Fuel reduction price by reducing front area is 22.22%

Money saved per year is $57