A panel for a political forum is made up of 11 people from three parties, all seated in a row. The panel consists of 5 Republicans, 5 libertarians, and I GreenParty member. In how many distinct orders can they be seated if two people of the same party are considered identical (not distinaX?
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So,
Here we have the following table:
We want to find the probability to choose a man. So, there are 7+21 = 28 men in total.
The total number of people is 70, so this probability is:
[tex]P(\text{male)}=\frac{28}{70}=0.4[/tex]b) The probability that the person is a man who doesn't practice sport.
If we look at the table, there are 7 men who doesn't practice sport, so:
[tex]P(no\text{ sport and male)=7/70}[/tex]7/70 = 0.1, so this probability is 0.1
c) Finally, remember that:
[tex]P(A|B)=\frac{P(A\cap B)}{P(B)}[/tex]We want the to find the probability that the person doesn't practice sport given that it is a man.
If we replace:
[tex]P(\text{No sport | male )=}\frac{P(No\text{ sport and male)}}{P(male)}=\frac{0.1}{0.4}=0.25[/tex]
Related Questions
y + 2x = 5; x = -1, 0, 3 Solve for y then find the value of y for each value of x.Uh how do I do that?
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'Solve for y' means that you have to clear 'y' from the equation:
[tex]y+2x=5[/tex]Clearing 'y':
[tex]y=5-2x[/tex]Now, to find the value of 'y' for each value of 'x' you just have to replace 'x' in the expression above by each of the given values. This is:
For x = -1
[tex]y=5-(2\times(-1))[/tex][tex]y=5+2=7[/tex]When x = -1, y = 7.
For x = 0:
[tex]y=5-(2\times0)[/tex][tex]y=5-0=5[/tex]When x = 0, y = 5
For x = 3:
[tex]y=5-(2\times3)[/tex][tex]y=5-6=-1[/tex]When x = 3, y = -1
In 3 Years ago Mateo wants to buy a bicycle that costs 700.00. if he opens a savings account that earns 10% interest compounded quarterly how much will he have to despoit as principal to have enough money in 3 years to buy the bike
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Answer:
He have to deposit $520.49 as Principal to have enough money in 3 years to buy the bike.
[tex]\text{ \$520.49}[/tex]Explanation:
The formula for calculating the Future value of Compound interest is;
[tex]A=P(1+\frac{r}{n})^{nt}[/tex]Where;
A = Future Value/Amount
P = Principal
r = Interest rate (decimal)
n = number of times the interest is compounded per unit time "t"
t = Time
Making the Principal P the subject of formula;
[tex]P=\frac{A}{(1+\frac{r}{n})^{nt}}[/tex]Given;
A = $700.00
r = 10% = 0.10
n = compounded quarterly (4 times a year) = 4
t = 3 years
substituting the given values;
[tex]\begin{gathered} P=\frac{\text{ \$700.00}}{(1+\frac{0.10}{4})^{4(3)}}=\frac{\text{ \$700.00}}{(1.025)^{12}} \\ P=\text{ \$520.49} \end{gathered}[/tex]Therefore, he have to deposit $520.49 as Principal to have enough money in 3 years to buy the bike.
[tex]\text{ \$520.49}[/tex]simplify 2 1/5 - 3/5
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Rotate the yellow dot to a location of pie radians. After you rotate the angle, determinethe value of cos(pie). to the nearest hundredth.-i already figured out the rotation
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Okay, here we have this:
Considering the provided angle, we are going to calculate the requested cosine, so we obtain the following:
Then to obtain the cosine we will review the following image of the unit triangle:
So since pi radians is equal to 180°, we can see in the image that the cosine of 180 degrees is equal to -1, so we finally get that the cosine of the angle is -1.
A total of $7000 is invested: part at 6% and the remainder at 10 %. How much is invested at each rate if the annual Interest is $520?
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total interest = $520
Therefore,
let
x = amount invested in 6%
y = amount invested in 10%
[tex]\begin{gathered} x+y=7000 \\ y=7000-x \end{gathered}[/tex]Interest total
[tex]\begin{gathered} 520=\frac{x\times6\times1}{100}+\frac{y\times10\times1}{100} \\ 520=0.06x+0.1y \end{gathered}[/tex][tex]\begin{gathered} 520=0.06x+0.1(7000-x) \\ 520=0.06x+700-0.1x \\ 520-700=0.06x-0.1x \\ -180=-0.04x \\ x=\frac{-180}{-0.04} \\ x=\text{ \$4500} \end{gathered}[/tex]y = 7000 - 4500 = $2500
$4500 was invested at a 6% rate
$2500 was invested at a 10% rate
match the steps to find the equation of the parabola with Focus (-1, 2), and directrix x=5,find the distance from the focus to the point on the parabola write te equation of the parabolachoose a point on the parabola square both sides and simplifyset the distance from the focus to the point equal to the distance from directrix to the point find the distance from the point on the parabola to the directrix
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1. Choose a point on the parabola
[tex](x,y)[/tex]2. Find the distance from the focus to the point on the parabola.
[tex]\sqrt[]{(x+1)^2+(y-2)^2}[/tex]3. Find the distance from the point on the parabola to the directrix.
[tex]\sqrt[]{(x-5)^2}[/tex]4. Set the distance from the focus to the point equal to the distance from directrix to the point.
[tex]\sqrt[]{(x+1)^2+(y-2)^2}=\sqrt[]{(x-5)^2}[/tex]5. Square both sides and simplify
[tex]\begin{gathered} (x+1)^2+(y-2)^2=(x-5)^2 \\ \end{gathered}[/tex]6. Write the equation of the parabola.
[tex]x=-\frac{y^2}{12}+\frac{y}{3}+\frac{5}{3}_{}[/tex]How do I do this? What do I do with the 68 and 79 on each?
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hello
solve the first problem, we are to find the missing angle
to solve for x, i had to make up new characters to find missing sides
first of all, let's solve for y
[tex]\begin{gathered} 45+y=180 \\ \text{reason:angle on a straight line is equal to 180 degr}e \\ y=180-45=135^0 \end{gathered}[/tex]let's use this knowledge to solve for z
[tex]\begin{gathered} y+z=180 \\ \text{reason: angles on a straight line = 180} \\ 135+z=180 \\ z=45^0 \end{gathered}[/tex]note: z= 45, we can as well use opposite angles are equal theorem
we should solve for angle a now
[tex]\begin{gathered} 60+z+a=180^0 \\ \text{reason:sum of angles in a triangle is equal to 180 degre}es \\ 60+45+a=180 \\ 105+a=180 \\ a=180-105 \\ a=75^0 \end{gathered}[/tex]we ca use the knowledge of a to solve for b
[tex]\begin{gathered} a+68+b=180^0 \\ \text{reason:angles on a straight line is equal to 180 degr}ees \\ 75+68+b=180_{} \\ 143+b=180 \\ b=180-143 \\ b=37^0 \end{gathered}[/tex]let's use the value of b to solve for c
[tex]\begin{gathered} b+100+c=180^0 \\ \text{reason:sum of angles in a triangle is equal to 180 degre}e \\ 37+100+c=180 \\ 137+c=180 \\ c=180-137 \\ c=43^0 \end{gathered}[/tex]finally, we can solve for x
[tex]\begin{gathered} c+x=180^0 \\ c=43^0 \\ 43+x=180 \\ x=180-43 \\ x=137^0 \end{gathered}[/tex]the value of the unknown angle is equal to 137 degrees
Find g(4a + 2) for the following polynomial.8(x) = - 3x + 14Answer8(4a + 2) =
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SOLUTION
[tex]\begin{gathered} g(x)=-3x+14 \\ We\text{ want to find } \\ g(4a+2) \end{gathered}[/tex]To do this wherever you see x, put 4a + 2, we have
[tex]\begin{gathered} g(x)=-3x+14 \\ g(4a+2)=-3(4a+2)+14 \\ \text{expanding we have } \\ g(4a+2)=-12a-6+14 \\ =-12a-6+14 \\ =-12a+8 \end{gathered}[/tex]hence the answer is -12a + 8
In a board game, a certain number of points is awarded to a player upon rolling a sixsided die (labeled 1 to 6) according to the function f(x) = 4x +3, where x is thevalue rolled on the die. Find and interpret the given function values and determine anappropriate domain for the function.
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ANSWER:
11, 2, 11, makes sense
25, 5.5, 25, does not makes sense
31, 7, 31, does not makes sense
Intergers in a <= x <= b
a = 1 and b = 6
STEP-BY-STEP EXPLANATION:
We have the following function:
[tex]f(x)=4x+3[/tex]where x is the value rolled on the die
The die can land on the numbers 1, 2, 3, 4, 5 and 6.
Therefore:
when x is 2:
[tex]\begin{gathered} f(2)=4\cdot2+3=8+3=11 \\ f(2)=11 \end{gathered}[/tex]f(2) = 11, meaning when a 2 is rolled on the die, the player is awarded 11 points. This interpretation makes sense in the context problem.
when x is 5.5:
[tex]\begin{gathered} f(5.5)=4\cdot5.5+3=22+3=25 \\ f(5.5)=25 \end{gathered}[/tex]f(5.5) = 25, meaning when a 5.5 is rolled on the die, the player is awarded 25 points. This interpretation does not makes sense in the context problem.
when x is 7:
[tex]\begin{gathered} f(7)=4\cdot7+3=28+3=31 \\ f(7)=31 \end{gathered}[/tex]f(7) = 31, meaning when a 7 is rolled on the die, the player is awarded 31 points. This interpretation does not makes sense in the context problem.
Based on the observations above, it is clear that an appropiate domain for the funcion is intergers in a <= x <= b
a = 1 and b = 6
Find the area under the standard normal curve to the left of z=-0.89 and to the right of z= 2.56Round your answer to four decimal places of necessary
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We want to find
P(z < - 0.89 U z > 2.56)
= P(z < - 0.89) + P(z > 2.56)
P(z > 2.56) = 1 - P(z ≤ 2.56)
From the normal distribution table, the area to the left of z = - 0.89 = 0.1867
Thus,
P(z < - 0.89) = 0.1867
From the normal distribution table, the area to the left of z = 2.56 = 0.9948
P(z > 2.56) = 1 - 0.9948 = 0.0052
Thus,
P(z < - 0.89 U z > 2.56) = 0.1867 + 0.0052
P(z < - 0.89 U z > 2.56) = 0.1919
The area is 0.1919
Use the picture below to answer questions 9-12. F D D M, M to 9. Three collinear points are: A. DEB B.FE.D С. В.Е.М D. ADF
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1) Collinear points are by definition, points that belong to the same line.
So, examining the picture we can state the 3 collinear points are:
b) FED
Note that these points are in the same line "j" so we can call them collinear.
In the diagram, es and PR bisect each other at point T. Find the measure of
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Since QS and PR bisect each other at point T, triangles QTP and RTS are similar. Hence, we ca draw the following picture:
and we can see that x+48 must be equal to 2x:
[tex]2x=x+48[/tex]and we can solve this equation for the unknow x as
[tex]\begin{gathered} 2x-x=48 \\ x=48 \end{gathered}[/tex]Now, with the value x, the angle P is equal to
[tex]\begin{gathered} P=48+48 \\ P=96 \end{gathered}[/tex]and the answer is a.
Which rate is greater?35 points in 20 minutes or 49 points in 35 minutes
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35 ÷ 20 = 1.75
49 ÷ 35 = 1.4
35 points in 20 minutes is greater than 49 points in 35 minutes.
MAT 115 StatisticsWhich of the following probabilities for the sample points A, B, and C could be true if A, B, and C are the only sample points in an experiment?Explain why each of the other 3 answers are wrong.1) P(A) = 5/10, P(B) = 2/10, P(C) = 1/102) P(A) = 0, P(B) = 1/2, P(C) = 1/23) P(A) = 1/5, P(B) = 1/6, P(C) = 1/34) P(A) = -1/10, P(B) = 1/2, P(C) = 6/10
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The addition of the 3 probabilities must be equal to 1.
1) P(A) + P(B) + P(C) = 5/10 + 2/10 + 1/10 = 4/5 ≠ 1
2) P(A) + P(B) + P(C) = 0 + 1/2 + 1/2 = 1
3) P(A) + P(B) + P(C) = 1/5+ 1/6 + 1/3 = 7/10 ≠ 1
4) a probability can't be negative
Then, the correct option is option 2
A honeybee sitting on a tulip wanted to fly to a daffodil located 100 meters due east. Although the honeybee flew in a straight line, it mistakenly flew in a direction 5° south of east. When the bee was directly south of the daffodil, how many meters from the bee was the daffodil? Enter your answer to 2 decimal places.
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Let's begin by listing out the given information:
Let the initial location of the honeybee be represented as B
Let the location of the honeybee be represented as C
Let the location of the daffodil be represented as D
[tex]\begin{gathered} BC(adjacent)=100m \\ \angle B=5^{\circ} \\ CD(opposite)=? \end{gathered}[/tex]We will calculate for CD using the Trigonometric ratio (SOHCAHTOA). We will use TOA:
[tex]\begin{gathered} Tan\theta=\frac{opposite}{adjacent}=\frac{CD}{BD} \\ \theta=5^{\circ},BD=100m \\ Tan5^{\circ}=\frac{CD}{100} \\ CD=100\cdot Tan5^{\circ} \\ CD=8.78\approx8.8 \\ CD=8.8m \end{gathered}[/tex]Find c for the inequality two thirds times c plus 7 is less than or equal to one third
A c ≤ −6
B c ≥ −6
C c ≤ −10
D c ≥ −10
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The inequality has its solution to be option (c) c ≤ -10
How to solve the inequality?From the question, the inequality expression is given as
two thirds times c plus 7 is less than or equal to one third
Rewrite properly as
2/3c + 7 ≤ 1/3
To start with, we subtract 7 from all sides of the inequality
This is represented as
2/3c + 7 - 7 ≤ 1/3 - 7
Evaluate the difference
So, we have
2/3c ≤ -20/3
Multiply through by 3
2c ≤ -20
Divide through by 2
c ≤ -10
Hence, the solution to the inequality is c ≤ -10
Read more about inequality at
https://brainly.com/question/25275758
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Emily is making a quilt and she has determined she needs 523 square inches of gray fabric and 1318 square inches of burgundy. How many square yards of each material will she need? Round your answers up to the nearest quarter yard. a.) The gray fabric: b.) The burgundy fabric: c.) How many total yards of fabric will she have to buy?
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Before we can determine what are being asked, let's first identify the equivalent of an inch to a yard. We get,
[tex]\text{ 1 yard = }36\text{ inches}[/tex][tex]\text{ 1 square yard}^{}=1296\text{ square inches}[/tex]Since we are asked to answer in yards, let's convert the given measures of Gray Fabric and Burgundy.
[tex]\text{Gray Fabric = 523 (in}^2)\text{ x }\frac{1\text{ y}d^2}{1296(in^2)}\text{ = }\frac{523}{1296}=0.40yd^2^{}[/tex][tex]\text{ Burgundy Fabric = 1318 (in}^2)\text{ x }\frac{1yd^2}{1296(in^2)}\text{ = }\frac{1318}{1296}=1.02yd^2[/tex]a.) Gray Fabric = 523 in.^2 = 0.40 yd.^2
b.) Burgundy Fabric = 1318 in.^2 = 1.02 yd.^2
c.) Total yards of fabric Emily will buy = 0.40 yd.^2 + 1.02 yd.^2 = 1.42 yd.^2
Perform the indicated operation. Assume all variables are positive.[tex]3 \sqrt[5]{x} + 9 \sqrt[5]{x} [/tex]
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write the radicals as a power
[tex]3\cdot x^{\frac{1}{5}}+9\cdot x^{\frac{1}{5}}[/tex]factor the common term
[tex]\begin{gathered} x^{\frac{1}{5}}\cdot(3+9) \\ 12\cdot x^{\frac{1}{5}} \\ \text{write as a radical} \\ 12\sqrt[5]{x} \end{gathered}[/tex]What will the new equation 2 be whenmultiplying everything by-2?
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In order to calculate the new equation, we just need to multiply every term in the equation by (-2). So we have that:
[tex]\begin{gathered} (2a+3b=5)\cdot(-2) \\ 2a\cdot(-2)+3b\cdot(-2)=5\cdot(-2) \\ -4a-6b=-10 \end{gathered}[/tex]So the answer is the first option.
How many cans of corn does he buy?Enter the correct answer.Alex stocks up for winter. He buys 24cans of vegetables. He pays 80 cents percan for tomatoes and 40 cents per canfor corn, for a total cost of $12.8.OOBDONEClear all3
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From the question, the two vegetables involved are tomatoes and corn
We have to generate some sets of simultaneous linear equations from the information given in the question.
Let the number of cans of tomatoes be represented by x
and the number of cans of corn be represented by y
Alex bought 24 cans of vegetables. This means;
x + y = 24 ..................................................... equation 1
He paid 80cents ($0.80) for 1 can of tomato.
This means for x cans of tomatoes, he would pay $0.80x
He paid 40cents ($0.40) for 1 can of corn.
This means for y cans of corn, he would pay $0.40x
Alex paid a total cost of $12.8. This means;
0.8x + 0.4y = 12.8 ........................................... equation 2
Hence, we have derived two equations out from the question and we solve them simultaneously
x + y = 24 ........................................................(equation 1)
0.8x + 0.4y = 12.8..........................................(equation 2)
Using substitution method, if x + y = 24
x = 24 - y
Substituting x = 24 - y in equation 2, we have;
0.8(24-y) + 0.4y = 12.8
19.2 - 0.8y + 0.4y = 12.8
Collecting like terms,
19.2 - 12.8 = 0.8y - 0.4y
6.4 = 0.4 y
[tex]\begin{gathered} y=\frac{6.4}{0.4} \\ y=16 \end{gathered}[/tex]Since x + y = 24
x + 16 = 24
x = 24 - 16
x = 8
Therefore, x = number of tomato can = 8
y = number of corn can = 16
Hence, the cans of corn he bought are 16cans.
Simple probability see photo
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Sample space for rolling a standard cube:
[tex]\lbrace1;2;3;4;5;6\rbrace[/tex]Rolling a two:
[tex]p\text{ = }\frac{1}{6}[/tex]Rolling an odd number:
[tex]\begin{gathered} Odd\text{ numbers }\lbrace1;3;5\rbrace \\ p\text{ = }\frac{3}{6} \\ p\text{ = }\frac{1}{2} \end{gathered}[/tex]Rolling an even number
[tex]\begin{gathered} Even\text{ numbers \textbraceleft2;4;6\textbraceright} \\ p\text{ = }\frac{1}{2} \end{gathered}[/tex]Rolling a number greater than two:
[tex]\begin{gathered} >2\text{ \textbraceleft3;4;5;6\textbraceright} \\ p=\frac{2}{3} \end{gathered}[/tex]Rolling a number less than three
[tex]\begin{gathered} <3\text{ \textbraceleft1;2\textbraceright} \\ p\text{ = }\frac{1}{3} \end{gathered}[/tex]Rolling a two or a five:
[tex]\begin{gathered} 2\text{ or 5 } \\ p\text{ = }\frac{1}{3} \end{gathered}[/tex]Rolling a one:
[tex]p\text{ = }\frac{1}{6}[/tex]Rolling a number less than five:
[tex]\begin{gathered} <5\text{ \textbraceleft1;2;3;4\textbraceright} \\ p\text{ = }\frac{2}{3} \end{gathered}[/tex]In 2020, 51.3% of voters voted for Joe Biden. There were a total of 158,418,955 votes cast.a) How many people voted for Biden?
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Given:
In 2020, 51.3% of voters voted for Joe Biden. There were a total of 158,418,955 votes cast.
To find: How many people voted for Biden?
Explanation:
The total number of voters = 158418955.
51.3% of voters voted for Joe Biden.
[tex]The\text{ number of people who voted for biden}=51.3\text{ \% }\times\text{ the total number of voters}[/tex]Therefore,
[tex]\begin{gathered} The\text{ number of people who voted for biden}=\frac{51.3}{100}\times158418955 \\ \\ The\text{ number of people who voted for biden}=51.3\times1584189.55 \\ \\ The\text{ number of people who voted for biden}=81268923.915 \end{gathered}[/tex]Thus, 81268923.915 people voted for Biden.
Is a square of an even number always even? In 1.2 you wrote the general term of sequences you wrote in 1.1.1-1.1.3 If a number is even, it can always be written as 2x another number Eg: 28 = 2 x 14 In symbols we write this as 2 x nor 2n Do you agree with the statement below? "A square of an even number is always even". Explain your answer
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5)
5.1
Given equation is
[tex]P=n^2-n+41[/tex]Replace n=1, we get
[tex]P=1-1+41=41[/tex]We know that a number divisible by one and itself is called a prime number.
Here 41 is divisible by 1 and 41 only.
Hence 41 is a prime number.
5.2.
Substitute n=37 in the equation of P, we get
[tex]P=(37)^2-37+41[/tex][tex]P=1369-37+41[/tex][tex]P=1373[/tex]The number 1373 is divisible by one and 1373 only.
So 1373 is a prime number.
Hence if n=37, then P is a prime number.
5.3.
We need to choose three numbers greater than 38.
Let n=39 and substitute in P, we get
[tex]P=(39)^2-39+41[/tex][tex]P=1521-39+41[/tex][tex]P=1523[/tex]The number 1523 is divisible by one and 1523.
Hence 1523 is a prime number.
Let n=40 and substitute in P, we get
[tex]P=(40)^2-40+41[/tex][tex]P=1600-40+41[/tex][tex]P=1601[/tex]The number 1601 is divisible by one and 1601.
Hence 1601 is a prime number.
Let n=41 and substitute in P, we get
[tex]P=(41)^2-41+41[/tex][tex]P=1681-41+41[/tex][tex]P=1681[/tex]The number 1681 is divisible by one and 1681.
Hence 1681 is a prime number.
We get that
When n=39,40 and 41 then P is prime.
5.4)
Yes, I believe that this conjecture is true.
we have chosen n=1, n=39 0dd number, n=40 even number, and n=41 prime number then we get the prime number for P.
So this conjectures is true for any value of n.
The equation P gives the prime number.
graph and check to solve the linear equations 2x-3y = 9 x=-3
Answers
Graph the linear equations.
The intersection point is (-3,-5).
Subtitute -3 for x and -5 for y in equation 2x-3y=9 to check the solution.
[tex]\begin{gathered} 2\cdot(-3)-3\cdot(-5)=9 \\ -6+15=9 \\ 9=9 \end{gathered}[/tex]The point (-3,5) satify the equation 2x-3y=9. The point (-3,-5) also lie on the line x=-3.
So point (-3,-5) is the solution of system of linear equation.
2. James went to Target and bought a new tv. He was so excited to find out they had anextra 35% off the already sale price. The TV was $135, but was on sale for $108.99.How much was James' final price with the 35% off discount?Original Cost:Discount:New Price
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%35 off the sale price
Original price: $135
Sale: $108.99
Multiply the sale price by the percentage off in decimal form:
108.99 x (35/100) = $38.15 (Discount)
Subtract that amount to the sale price:
108.99-38.15 = $70.84 (final price)
a scientist has two solutions which she has labeled solutions A and Solution B each contains salt she knows that solutions A is 30% salt and solution B is 80% salt. she wants to obtain 120 ounces of a mixture that is 60% salt how many ounces of each solution should she use
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Explanation:
Let's call A the ounces of solution A and B the ounces of solution B.
If the scientist wants to obtain 120 ounces, then:
A + B = 120
On the other hand, the final mixture should be 60% salt and solution A is 30% salt and solution B is 80% salt, so:
0.6(A + B) = 0.3A + 0.8B
So, we can solve for A as:
[tex]\begin{gathered} 0.6(A+B)=0.3A+0.8B_{}_{} \\ 0.6A+0.6B=0.3A+0.8B \\ 0.6A+0.6B-0.3A=0.3A+0.8B-0.3B \\ 0.3A+0.6B=0.8B \\ 0.3A+0.6B-0.6B=0.8B-0.6B \\ 0.3A=0.2B \\ \frac{0.3A}{0.3}=\frac{0.2B}{0.3} \\ A=\frac{2}{3}B \end{gathered}[/tex]Then, replacing A by (2/3)B on the first equation, we get:
[tex]\begin{gathered} A+B=120 \\ \frac{2}{3}B+B=120 \\ \frac{5}{3}B=120 \\ 3\cdot\frac{5}{3}B=3\cdot120 \\ 5B=360 \\ \frac{5B}{5}=\frac{360}{5} \\ B=72 \end{gathered}[/tex]Finally, A is equal to:
[tex]\begin{gathered} A=\frac{2}{3}B \\ A=\frac{2}{3}(72) \\ A=48 \end{gathered}[/tex]Therefore, she should use 48o
Let[
Which situation best represents the relationship between x and ypresented in the graph?An elevator starts at floor 4 and descends1 floor everysecond.Sarah had 0 bracelets and bought 1 new bracelet everyweek for 10 weeks.O 4 inches of rain fell every day for 10 days.A plant starts at 4 inches tall and grows 1 inch perweek.Help
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startsThe situation best represents the relationship between x and y presented in the graph is the last situation which states that "A plant starts at 4 inches tall and grows 1 inch per week.
Here if we take 1 inch as 1 unit of the y axis of the graph and 1 week as the 1 unit of the x-axis. Then the graph of this situation will look like the given graph.
In the graph it is start from 4 unit of the y-axis and in every increase of 1 unit of x-axis leads to 1 unit increase of y-axis. Which is exactly the same situation as the growing of the plant.
The Lions won 16 games last year. This yearthe Lions won 20 games. What is thepercent increase in the number of games theLions won from last year to this year?A. 20%B. 25%C. 80%D. 125%How is the question broken down?
Answers
The lions won 4 games more this year.
Let's use a rule of three to find the relative increase:
This way,
[tex]x=\frac{4\cdot100}{16}\rightarrow x=25[/tex]Thereby, the increment was 25%
Answer: B
what is the answer to 48? please show work i need it asap
Answers
we have the base 9+4=13
height
5. In this figure, triangle GHJ is similar to triangle PQR P Q 00 R G Based on this information, which ratio represents tan G? Sin G? Cos G?
Answers
In the given problem,
[tex]\begin{gathered} \Delta GHJ\approx\Delta PQR \\ \frac{GH}{PQ}=\frac{HJ}{QR}=\frac{GJ}{PR} \\ \angle G=\angle P \\ \angle H=\angle Q \\ \angle J=\angle R \end{gathered}[/tex]Thus value of tanG, sinG and cosG can be determined as,
[tex]\begin{gathered} \tan G=\tan P=\frac{QR}{PR}=\frac{15}{8} \\ \sin G=\sin P=\frac{QR}{QP}=\frac{15}{17} \\ \cos G=\cos P=\frac{PR}{QP}=\frac{8}{17} \end{gathered}[/tex]Thus, the above expression gives the requried value of tanG, sinG and cosG.