A particular circuit is made up of a battery, a switch, a buzzer, and wires connecting the components. All of the components
e in working order, but the buzzer does not make noise. Which statement explains this observation? (1 point)
The circuit lacks a power source.
The load cannot convert electrical energy
The switch is open
The conductors are not attached
Answers
If the buzzer in this connection fails to make a sound, it follows that the switch or the key is open.
What is a circuit?A circuit is a path designed for the flow of current. We have to take note of the fact that the switch or key must be closed before electric current can pass through the circuit and the buzzer will make a sound.
Therefore, were the buzzer in this connection fails to make a sound, it follows that the switch or the key is open.
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Answer:
C
- CONNECTIONS
--------------------------------
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Related Questions
What is the length of a pendulum that has a period of 4. 89 seconds?
Answers
Hi there!
We can use the following equation for a simple pendulum:
[tex]T = 2\pi \sqrt{\frac{L}{g}}[/tex]
T = Period (4.89 s)
L = length (? m)
g = acceleration due to gravity (9.8 m/s²)
Rearrange the equation to solve for L.
[tex]T^2 = 4\pi ^2 \frac{L}{g}\\\\L = \frac{gT^2}{4\pi ^2}[/tex]
[tex]L = \frac{(9.8)(4.89^2)}{4\pi^2} = \boxed{5.936 \frac{m}{s}}[/tex]
A pendulum is a body hanging from a fixed point that swings back and forth under the effect of gravity. The length of a pendulum that has a period of 4.89 seconds is 5.936 meters.
What is a pendulum?A pendulum is a body hanging from a fixed point that swings back and forth under the effect of gravity. Pendulums are employed to govern the movement of clocks because the time interval for each full oscillation, known as the period, remains constant.
Given that the time period is 4.89 seconds, therefore, the length of the pendulum can be written as,
[tex]\rm T = 2\pi \sqrt{\dfrac{L}{g}}\\\\4.89 = 2\pi \sqrt{\dfrac{L}{9.81}}\\\\L = 5.936\ m[/tex]
Hence, the length of a pendulum that has a period of 4.89 seconds is 5.936 meters.
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two cars have the same mass, but one is traveling 3 times as fast as the other. how much more kinetic energy does the faster car have
Answers
Answer:
9 times the KE
Explanation:
KE = 1/2 mv^2 now triple 'v'
KE = 1/2 m 9 v^2
Students in science are studying solutions and the dissolving rate of solids. One group was given some instant lemonade mix to dissolve. They used a packet of lemonade crystals and a packet of lemonade powder. The students dissolved the same amount of each solid into 100 ml of water. They varied the water temperature. List ALL the possible conclusions based the data the students collected?
Answers
Answer:
a-d
Explanation:
hope this helps
A crane lifts a 450 kg concrete to the top of a 50 m building in 5 s.
Assuming g= 10 m/s
)
2
a) The potential energy of the concrete.
, calculate;
b) The power developed by the crane
Answers
Explanation:
Given : m=600kg h=20 m
Time of operation t=2 min =120 s
Work done in lifting a box W=mgh=600×10×20=120000
Power required P=
t
W
=
120
120000
=1000 watts
What phase of the moon would someone
on Earth see when the moon is at
Positions A through F?
Answers
First quarter is the phase of the moon would someone on Earth will see when the moon is at Positions A through F.
What is First Quarter?This is the phase which occurs when the moon is 90 degrees away from the sun in the sky and is half-illuminated from our point of view.
When looking it at the moon from point F it's half-illuminated which depicts the First quarter moon phase.
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By what means can the internal energy of a closed system increase?.
Answers
Answer:
when work is done on the system or heat comes into the system
17. Suppose you attach the object with mass m to a vertical spring originally at rest, and let it bounce up and down. You release the object from rest at the spring’s original rest length. (a) Show that the spring exerts an upward force of 2.00mg on the object at its lowest point. (b) If the spring has a force constant of 10.0N/m and a 0.25-kg-mass object is set in motion as described, find the amplitude of the oscillations. (c) Find the maximum velocity.
Please show all of your work.
Answers
Answer:
See below ↓
Explanation:
Step 1 : Diagram
In attachmentStep 2
We choose the system to be the spring, the block, and the Earth and it is isolatedWe put all the data in the figure we have created and create a zero level (initial height) of the block to be yₓ = 0 and the final position, when it stops and moves upwards again, to be yₙ = -ANo external forces are exerted on the system and no energy comes in or out of the systemHence,⇒ ΔE = 0
⇒ Eₙ - Eₓ = 0
⇒ Eₙ = Eₓ
⇒ Kₙ + Uₙ + Pₙ = Kₓ + Uₓ + Pₓ
Final kinetic energy is 0 at the lowest point⇒ Uₙ + Pₙ = Uₓ + Pₓ
Step 3
Initial potential energy is 0 [zero level = initial height]⇒ Uₙ + Pₙ = Uₓ
And we know that spring was originally at normal length, so initial spring energy is also 0⇒ Uₙ + Pₙ = 0
⇒ 1/2kxₙ² + mgyₙ = 0
⇒ 1/2kxₙ² = -mgyₙ
We know xₙ = A and yₙ = -A from the diagram⇒ 1/2kA² = -mg(-A)
⇒ 1/2kA² = mgA
⇒ [1/2kA = mg]
Step 4
Spring force is given by : F = -kxNote : x = A⇒ F = kA
⇒ k = F/A
⇒ Plug 'k' into the equation found at the end of Step 3
⇒ 1/2(F/A)(A) = mg
⇒ 2F = mg
⇒ F = 2mg (a)
Step 5
We know the spring will stop oscillating and be at rest at the new equilibrium position of the system⇒ F - mg = 0
⇒ F = mg
We know that :⇒ F = -kx
In the case x = yₙ⇒ kyₙ = mg
⇒ yₙ = mg/k
⇒ yₙ = 0.25 x 9.8 / -10
⇒ yₙ = -0.245 m
⇒ yₙ = A
⇒ yₙ = 0.245 m (b)
Step 6
v(max) = Aωv(max) = A√k/mv(max) = 0.245 x √(10/0.25)v(max) = 1.55 m/s (c)Which red line shows the same action spectrum corrected for the unequal number of photons emitted across the visible spectrum?.
Answers
The visible spectrum is composed of red, orange,yellow, green, blue, violet, indigo.
What is visible spectrum?The visible spectrum refers to the portion of the electromagnetic spectrum that can be seen with the eyes. All other portions of the electromagnetic spectrum are invisible.
The question is incomplete as the details are missing. The visible spectrum is composed of red, orange,yellow, green, blue, violet, indigo.
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A 0.105- kg hockey puck moving at 24 m/s is caught and held by a 75-kg goalie at rest. With what speed does the goalie slide on the ice after catching the puck? Define the puck and the goalie as a system.
please show work, help
Answers
Answer:
0.03 m/s
Explanation:
Applying law of conservation of momentum,
m₁v₁ + m₂v₂ = (m₁ + m₂)v0.105(24) + 75(0) = (0.105 + 75)v75.105v = 2.52v = 2.52/75.105v = 0.03 m/sif a solution contains 30 g of
potassium chloride (KCI) per 100 mL of water at 60°C, the
solution would be considered saturated.
true
false
Answers
A boy walks up a hill. His displacement from his starting point is (800, 150) m. How much gravitational potential energy has he gained?
Answers
Answer:
The potential energy gained is 1500m joule.
Explanation:
Hope this helps!
Answer:
Answer: He 1500m joule amount of gravitational potential energy
Explanation:
Good Luck
hope it helps
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Which of the following is true about the horizontal component of a
projectile?
A: There is no acceleration
B: The change in displacement is always negative
C:The time is different than the vertical component
D:There is no initial velocity
Answers
Answer:
a
Explanation:
Question 4 of 5
The picture shows a model of a cell.
W
What is the main function of the part labeled Win the model?
Answers
Explanation:
it is not clear. I can't see w.
do you think your real?
Answers
Answer: Yes I am alive.
if i were to (HYPOTHETICALLY) punt a small child off of a building, (HYPOTHETICALLY) how long would it take for the (VERY HYPOTHETICAL) child to reach maximum velocity?
(HYPOTHETICALLY) the child would weigh 88 pounds, have blond hair and blue eyes, and (HYPOTHETICALLY) be named "Jacob."
THIS QUESTION IS HYPOTHETICAL AND I AM TOTALLY NOT PLANNING TO COMMIT AN ATROCITY!
Answers
Answer:
Around 190-ish miles per hour when it hit the ground maybe
Explanation:
A bus start moving from rest .If its velocity after 5 seconds becames 10 m/s ,find acceleration
Answers
Answer:
2 [tex]m/s^{2}[/tex]
Explanation:
acceleration = (final-initial velocity) / time
= (10-0)/5
=2
If a number of coplanar forces acting on a particle are in equilibrium, then
Answers
Explanation:
Then the algebraic sum of the moment of all the forces about any point is equal to the moment of the resultant force about the same point
If a number of coplanar forces acting on a particle are in equilibrium. then the moment of their resultant is equal to the sum of their individual moment.
What is the law of moments?If a number of co-planar forces operating on a particle are in equilibrium, the algebraic sum of their moments about any point equals the moment of their resultant force about the same point, according to the law of moments.
Hence If a number of coplanar forces acting on a particle are in equilibrium. then the moment of their resultant is equal to the sum of their individual moment.
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If the two blocks are touching, what will happen to the thermal energy in this system?
Answers
Explanation:
What are the integers between -4 and +4?
Two blocks each of mass m are attached to the ends of a massless rod
Answers
The net torque on this system is (ml2g-ml1g)k
What is Torque?
This refers to the type of force that causes rotation in objects which has mass and is a twisting force
Based on the complete question, we can see the given parameters:
The torque due to farther mass above the pivot is ml2gk
The torque due to nearer mass about the pivot is ml1gk
Therefore, the net torque is (ml2g-ml1g)k
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The net torque on this system in which two blocks each of mass m are attached to the ends of a massless rod, above pivot, is (ml₂g-ml_₁g)\hat k.
What is torque?The torque of a body is the rate of change of angular momentum of the body. Torque is the product of moment of inertia and the angular acceleration.[tex]\tau =I\times \alpha[/tex][tex]\tau=mlg[/tex]
Here, (I) is the moment of inertia and (α) is the angular acceleration.
Two blocks each of the mass m are attached to the ends of a massless rod which pivots as shown in fig.
Initially, the rod is held in the horizontal position and then released. When, the mass was kept at farther to pivot, then the value of torque is,
[tex]\tau=ml_2g\hat k[/tex]
When, the mass was kept at nearer to pivot, then the value of torque is,
[tex]\tau=-ml_1g\hat k[/tex]
Thus, the net torque on this system above pivot is,
[tex]\tau=ml_2g\hat k+(-ml_2g\hat k)\\\tau=(ml_2g-ml_1g)\hat k[/tex]
Thus, the net torque on this system in which two blocks each of mass m are attached to the ends of a massless rod, above pivot is (ml₂g-ml_₁g)\hat k.
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what is the ionic compound of Ba(NO3)2
Answers
Answer:
Barium nitrate
Infrared light and visible light are both waves on the electromagnetic spectrum. Identify two
other similarities between infrared and visible light.
Answers
Answer:
Both travel in straight line
Where are globular clusters located in the milky way?.
Answers
Answer:
Globular star clusters are located in the great spherical halo.
Explanation:
Hope this helps! :)
A current in a wire increases from 2 a to 6 a. how will the magnetic field 0.01 m from the wire change? it increases to four times its original value. it increases to three times its original value. it decreases to one-fourth its original value. it decreases to one-third its original value.
Answers
Answer:
It increases to three times it's original value.
Explanation:
B
Hi there!
Recall the equation for the magnetic field of a wire (assuming infinite):
[tex]B = \frac{\mu _0 i_{encl}}{2\pi r}[/tex]
B = Magnetic field (T)
μ₀ = Permeability of Free Space (Tm/A)
i = enclosed current (A)
r = distance from wire (m)
From the equation, we can see that there is a DIRECT relationship between the current and the magnetic field.
Therefore, if the current is increased by a factor of 3, the FIELD will also be increased by a factor of three.
When you serve the ball, if the ball does not land in the opposite side rectangle this is called a ______. question 2 options: fault miss volley foul
Answers
Answer:
its called a fault
Explanation:
Its when u mess up
The key differences between rotational kinematics and translational kinematics is: A. Rotational kinematics must specify an axis of rotation and objects return to their initial position with successive revolutions. B. Rotational kinematics must specify an axis of rotation and is only applied to rigid objects, not particles. C. Rotational kinematics analyzes both the tangential acceleration as well as the centripetal acceleration and translational kinematics analyzes only the tangential acceleration. D. Rotational kinematics must specify an axis of rotation and uses only dimensionless units
Answers
In Translational motion, the body moves in a straight line whereas in Rotational motion, the body moves in a circular path.
Differences between rotational kinematics and translational kinematicsIn Translational motion, the body moves in a straight line and the body same displacement in equal interval of time while on the other hand, in Rotational motion, the body moves in a circular path and the body travels same angular displacement in equal interval of time..
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A 10-A current is maintained in a simple circuit with atotal resistance of 209 ohm. What net charge passes through any point in a circuit during a 1-minute interval?
Answers
Answer:
I = Q / t definition of current I
Q = i t = 10 Coul/sec * 60 sec = 600 Coul
A 10-A current is maintained in a simple circuit with a total resistance of 209 ohms, then the net charge passes through any point in a circuit during a 1-minute interval would be 6000 Coulombs.
What is an electric charge?Charged material experiences a force when it is exposed to an electromagnetic field due to the physical property of electric charge. You can have a positive or negative electric charge.
Electric current is defined as the charge per unit of time.
The mathematical relation between current and the electric charge
I =Q/T
Let us first convert the time period of minutes into seconds
1 min = 60 seconds
10 min = 10*60 seconds
=600 seconds
Q = I*t
=10*600
=6000 Amperes
Thus, the net charge that passes through any point in a circuit during a 1-minute interval would be 6000 Amperes.
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What is the speed of a wave that has a frequency of 440 Hz and a wavelength of 0.78 m? O A. 564 m/s m B. 0.003 m/s C. 343 m/s D. 0.002 m/s
Answers
Explanation:
velocity = frequency × wave length
velocity = 440 × 0.78
velocity = 343 m/sec
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HELP
1. Which of the following is most useful in determining the kinetic energy of a 50 g battery- powered car
traveling a distance of 10 m?
A) Beaker
B) Voltmeter
C) Thermometer
D) Stopwatch
Answers
The stopwatch will be the most useful in determining the kinetic energy of a 50 g battery- powered car traveling a distance of 10 m.
What is kinetic energy?Kinetic energy is the energy of a body possessed due to motion.
This means that for an object to possess kinetic energy, it must be in motion.
The kinetic energy is measured in Joules, which is a product of the mass of the substance and the time taken to travel a distance.
A stopwatch is an instrument used to measure time as one of the components of kinetic energy.
Therefore, the stopwatch will be the most useful in determining the kinetic energy of a 50 g battery- powered car traveling a distance of 10 m.
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A bungee cord with a spring constant of 800 StartFraction N over m EndFraction stretches 6 meters at its greatest displacement. How much elastic potential energy does the bungee cord have?
Answers
Answer:
14,400
Explanation:
I guessed and I think it's right Soo
22. What is the length of a pendulum that has a period of 0.500 s?
Please show all of your steps to find the solution.
Answers
6.21 cm
use the pendulum formula : [tex]\sf \bold{\mathrm{T}=2 \pi \sqrt{\frac{\mathrm{L}}{\mathrm{g}}}}[/tex]where
T is time or periodπ is pie = 22/7L is pendulum lengthg is acceleration due to gravityGiven:
T = 0.500 sg = 9.8 m/s²solving step-wise:
[tex]\dashrightarrow \mathrm{T}=2 \pi \sqrt{\dfrac{\mathrm{L}}{\mathrm{g}}}[/tex]
[tex]\sf \dashrightarrow \mathrm{0.5}=2 \pi \sqrt{\dfrac{\mathrm{L}}{\mathrm{9.8}}}[/tex]
[tex]\dashrightarrow \mathrm{\dfrac{0.5}{2 \pi } }=\sqrt{\dfrac{\mathrm{L}}{\mathrm{9.8}}}[/tex]
[tex]\dashrightarrow\sqrt{\dfrac{\mathrm{L}}{\mathrm{9.8}}}= \mathrm{\dfrac{0.5}{2 \pi } }[/tex]
[tex]\sf \dashrightarrow{\dfrac{\mathrm{L}}{\mathrm{9.8}}}= (\mathrm{\dfrac{0.5}{2 \pi } })^2[/tex]
[tex]\sf \dashrightarrow{{\mathrm{L}}= (\mathrm{\dfrac{0.5}{2 \pi } })^2*9.8[/tex]
[tex]\sf \dashrightarrow{{\mathrm{L}}=0.06205922 \ m[/tex]
1 m → 100 cm[tex]\sf \dashrightarrow{{\mathrm{L}}=6.2059\ cm[/tex]
[tex]\sf \dashrightarrow{{\mathrm{L}}=6.21\ cm[/tex] { rounded to nearest hundredth }
Let's see
[tex]\\ \rm\rightarrowtail T=2\pi \sqrt{\dfrac{l}{g}}[/tex]
[tex]\\ \rm\rightarrowtail 0.5=2\pi \sqrt{\dfrac{l}{9.8}}[/tex]
[tex]\\ \rm\rightarrowtail 0.783=\pi \sqrt{l}[/tex]
[tex]\\ \rm\rightarrowtail 0.2494=\sqrt{l}[/tex]
[tex]\\ \rm\rightarrowtail \ell=0.0622m[/tex]