Answer:
"322.5 N" is the appropriate solution.
Explanation:
The given values are:
Mass,
m = 3 kg
Length of forearm,
= .38 meters
Angle,
= 60°
As we know,
⇒ [tex]FSin60^{\circ}\times 0.04=mg\times 0.38[/tex]
⇒ [tex]F =\frac{mg\times 0.38}{Sin60^{\circ}\times 0 .04}[/tex]
On substituting the values, we get
⇒ [tex]=\frac{3\times 9.8\times 0.38}{0.04\times \frac{\sqrt{3}}{2}}[/tex]
⇒ [tex]=\frac{11.172}{0.0346}[/tex]
⇒ [tex]=322.5 \ N[/tex]
To determine the pressure in a fluid at a given depth with the air-filled cartesian diver, we can employ Boyle's law, which states that the pressure in an ideal gas (held at constant temperature) is inversely proportional to its volume. At a fluid's surface, the pressure of the fluid is the same as the pressure of the atmosphere just above it, which we'll denote as LaTeX: P_{atm}P a t m. If the volume of air, which can be treated as an ideal gas here, in the cartesian diver decreases by 19% as it is lowered to a specific depth in the fluid, the pressure of the fluid at this depth, in terms of atmospheric pressure, is
Answer:
The pressure at this depth is [tex]1.235\cdot P_{atm}[/tex].
Explanation:
According to the statement, the uncompressed fluid stands at atmospheric pressure. By Boyle's Law we have the following expression:
[tex]\frac{P_{2}}{P_{1}} = \frac{V_{1}}{V_{2}}[/tex] (1)
Where:
[tex]V_{1}, V_{2}[/tex] - Initial and final volume.
[tex]P_{1}, P_{2}[/tex] - Initial and final pressure.
If we know that [tex]V_{2} = 0.81\cdot V_{1}[/tex], then the pressure ratio is:
[tex]\frac{P_{2}}{P_{1}} = 1.235[/tex]
If [tex]P_{1} = P_{atm}[/tex], then the final pressure of the gas is:
[tex]P_{2} = 1.235\cdot P_{atm}[/tex]
The pressure at this depth is [tex]1.235\cdot P_{atm}[/tex].
The pressure of the fluid at this depth will be "1.16 [tex]P_{atm}[/tex]".
Pressure and VolumeAccording to the question,
Let,
The volume of surface be "100 units".
then,
The volume of depth be:
= 100 - 14
= 86 units
We know the relation,
P ∝ [tex]\frac{1}{V}[/tex]
here, PV = Constant
By using Boyle's law,
→ P₁ V₁ = P₂ V₂
or,
→ P₂ = [tex]\frac{P_1 V_1}{V_2}[/tex]
By substituting the values, we get
= [tex]\frac{P_{atm}\times 100}{86}[/tex]
= 1.16 [tex]P_{atm}[/tex]
Thus the above answer is appropriate.
Find out more information about pressure here:
https://brainly.com/question/2117709
explain why radiation is dangerous for humans
Answer:
because it affects the attom in living things
Help me with both questions please?
Answer:
1. They all accelerate at the same rate.
2.The object travels at a constant velocity throughout the fall.
Explanation:
Earths gravitational pull is at a constant 9.08 m/s^2. so when objects are free falling, the objects in question can only fall so fast before it would break gravity so to speak.
Which materials do you wrap the egg in to prevent it from breaking at 5m?
Site: (https://www.healthinteractives.studio/bydesign/egg-drop/)
Answer:
If you do not have bubble wrap but do have other packing materials, like packing peanuts, inflated plastic packing packets, packing paper, cotton balls, or crumpled newspaper, you can use these materials to cushion the egg, as well.
Sound waves rely on matter to transmit their energy. They cannot ravel in a vacuum. True or false
Answer:
false
Explanation:
Hello,
QUESTION)True,Sound travels in a material medium, in space, there is no matter, so sound cannot propagate.
.HOW DOES PHYSICAL EDUCATION BENEFIT YOUR EMOTIONAL HEALTH ?
Answer: reduce anxiety, depression, and negative mood and by improving self-esteem and cognitive function.
Explanation:
The toadfish makes use of resonance in a closed tube to produce very loud sounds. The tube is its swim bladder, used as an amplifier. The sound level of this creature has been measured as high as 100 dB. (a) Calculate the intensity of the sound wave emitted. W/m2 (b) What is the intensity level if three of these toadfish try to make a sound at the same time
Answer:
a) I = 10⁻² W / m², b) β = 104.8 db
Explanation:
a) For this exercise we use the definition of decibels
β = 10 log [tex]\frac{I}{I_o}[/tex]
where I and Io are the intensities produced and the sound threshold
I₀ = 10⁻¹² W / m²
log \frac{I}{I_o} = β / 10
I = Io [tex]10^{\beta /10}[/tex]
let's calculate
I = 10⁻¹² [tex]10^{100/10}[/tex]
I = 10⁻² W / m²
b) each toad produces the same sound for which the total intensity is
I_total = 3 I
I_total = 3 10⁻² W / m²
expressed in decibels
β = 10 log ([tex]\frac{3 \ 10^{-2} }{10^{-12} }[/tex])
β = 104.8 db
The toadfish make sue of the resonance on the closed system tube to make a very loud noise and fish tube is the bladder which us used for amplifying the sounds. The sound level of the creatures has been taken as 100DB.
The intensity of the sound waves emitted by the fish is I = 10⁻² W / m², The intensity of he waves and level of the three of these toadfish is make a sound at the same time is that of β = 104.8 DB.Learn more about the use of resonance in a closed tube to produce.brainly.com/question/14700223.
A light string is wrapped around the edge of the smaller disk, and a 1.50 kgkg block is suspended from the free end of the string. If the block is released from rest at a distance of 2.40 mm above the floor, what is its speed just before it strikes the floor
Answer:
The speed of the block before it strikes the floor is 0.217 m/s.
Explanation:
Given;
mass of the block, m = 1.5 kg
height above the ground through the block was released, h = 2.4 mm = 2.4 x 10⁻³ m
The speed of the block before it strikes the floor will be maximum.
Let the speed of the block before it strikes the floor = v
Apply the principle of conservation of mechanical energy to determine the speed of the block.
K.E = P.E
¹/₂mv² = mgh
¹/₂v² = gh
v² = 2gh
v = √2gh
v = √(2 x 9.8 x 2.4 x 10⁻³)
v = 0.217 m/s
Therefore, the speed of the block before it strikes the floor is 0.217 m/s.
A 40.0 kg block of lead is heated from -25°C to 200°C.
How much heat is absorbed by the lead block?
A. 2,354,000 J
B. 1,170,000 J
C. 56,891 J
D. 10,650 J
Answer:
B. 1,170,000 J
Explanation:
Given;
mass of lead block, m = 40 kg
initial temperature, t₁ = -25 ⁰C
final temperature, t₂ = 200 ⁰C
The heat absorbed the lead block is calculated as;
H = mcΔt
where;
c is the specific heat capacity of lead = 130 J/kg⁰C
H = 40 x 130 x (200 - (-25))
H = 40 x 130 x (200 + 25)
H = 40 x 130 x 225
H = 1,170,000 J
Therefore, the heat absorbed the lead block is 1,170,000 J
In the “Elastic Collision" part of this activity, what happened to the momentum of the red cart after the collision? What happened to the momentum of the blue cart after the collision?
Explanation:
Elastic collision between balls of equal mass viimis 1.5 mys 1.5m/s 1! mis ... Make a data table for the following: mass, velocity and momentum of each ball before ... Part 2 moving faster. ... Summary: Describe the main ideas learned in this activity regarding initial and ... Collision 2: Blue Cart Moving Slower than the Red Cart.
A 70 kg bicyclist rides his 9.8 kg bicycle with a speed
of 16 m/s.
How much work must be done by the brakes to bring the bike and rider to a stop?
Hello,
QUESTION)✔ We have Ek = 1/2m x v²
Ek = 1/2 x 79.8 x 16²Ek = 10 214.4 JIn order to come to a complete stop, the cyclist must convert all his kinetic energy into thermal energy. Given that the braking force opposes movement, the work is therefore resistant, i.e. W = -10 214.4 J.
Prior Knowledge Questions (Do these BEFORE using the Gizmo.) Strings of holiday lights can be designed in one of two ways. In some strings of lights, each light is connected to the others along a single wire (in series). In others, each light is attached to its own wire (in parallel). Suppose a single light bulb burns out. How do you think this will affect lights that are strung along a single wire
Answer:
They would go out
Explanation:
This is because, in a series connection, the same current passes through each light. Since the current is the same, if one light burns out, it cuts off the rest of the other lights and thus, no current flows in the string again.
Whereas, in a parallel connection, each light is attached to its own wire and thus has a different current flowing through it than the rest of the other wires. If one of the lights goes out, current stops flowing through it but, it doesn't affect the other lights.
Evaluate for f(-4)
F(x) =3x2 -5 +7
Answer: -4f=8
Explanation:
Most stars are _____ compared to the sun.
slightly smaller
much bigger
much smaller
slightly bigger
What impact could lowering the pH of ocean water have? choose all that apply
O sea level rise
O shellfish decreasing
O decreasing amount of coral
Ofish being "burned by the acid"
A 100 W engine generates 1000 J of energy. How long did it run for?
A. 1 s
B. 10 s
C. 5 s
D. 100 s
Answer:
B. 10 s
Explanation:
Given the following data;
Power = 100 Watts
Energy = 1000 Joules
To find the time;
Power can be defined as the energy required to do work per unit time.
Mathematically, it is given by the formula;
[tex] Power = \frac {Energy}{time} [/tex]
Making time the subject of formula, we have;
[tex] Time = \frac {Energy}{Power} [/tex]
Substituting into the formula, we have;
[tex] Time = \frac {1000}{100} [/tex]
Time = 10 seconds
Read the following statements. Which statement provides the correct definition of weather? Select your answer from the options below. * 1 point
Atmospheric conditions at a specific time in a specific area
Atmospheric conditions over a period of time in a specific area
Average atmospheric conditions over a period of time in a region
Average atmospheric conditions across the world
Answer:
In one day, a store sells 14 pairs of jeans. The 14 jeans represent 20% of the total number of items sold that day. How many items did the store sell in one day? Explain or show how you got your answer.
plz help with the qsn
Explanation:
Select the correct answer.
In general, how does an increase in distance from the Sun affect a planet?
ОА. .
The amount of sunlight the planet receives decreases.
OB.
The gravitational force exerted by the Sun increases.
ОС.
The thickness of a planet's atmosphere increases.
OD. The planet's atmosphere absorbs more heat.
Answer:
a.
gravity decreases by distance
thickness doesn't change
Less heat.
Two long, straight wires are parallel and 20 cm apart. One carries a current of 2.2 A, the other a current of 5.9 A. (a) If the two currents flow in opposite directions, what is the magnitude (in N/m) and direction of the force per unit length of one wire on the other
Answer: [tex]1.298\times 10^{-5}\ N/m[/tex]
Explanation:
Given
Current in the first wire [tex]I_1=2.2\ A[/tex]
Current in the second wire [tex]I_2=5.9\ A[/tex]
wires are [tex]20\ cm[/tex] apart
Force per unit length between the current-carrying wires is
[tex]\Rightarrow \dfrac{F}{l}=\dfrac{\mu_oI_1I_2}{2\pi r}[/tex]
Force exerted by the wires is the same
Put the values
[tex]\Rightarrow \frac{F}{l}=f=\dfrac{4\pi \times 10^{-7}\times 2.2\times 5.9}{2\pi \times 0.2}=1.298\times 10^{-5}\ N/m[/tex]
This force will be repulsive in nature as the current is flowing opposite
104in rotational kinetic energy is equals to 1 by 2 I w2 that is equals to 2 by 2 I what does w represent
Answer:
I is the moment of inertia which is a scalar
w is the angular velocity
Explanation:
Kinetic energy has the Formula
K = ½ m v²
if the system is rotating, the linear velocity is related to the angular velocity
v = wr
we substitute
K = ½ m w² r²
K = ½ (m r²) w²
If we consider the body as punctual
I = m r²
we substitute
K = ½ I w²
we can see that
I is the moment of inertia which is a scalar
w is the angular velocity
K is called the rotational kinetic energy
A closed pipe creates a fifth
harmonic frequency of 125 Hz.
What is the next lower frequency
that will create a standing wave in
the pipe?
(Speed of sound = 343 m/s)
(Unit = Hz)
PLEASE HELP QUICKLY, WILL GIVE BRAINLIEST
Answer:
75 hz
Explanation:
Trust
The next frequency will be 75.0 Hertz
Wait, how do you know if it is correct?!
Well, it is correct for Acellus:)
Try it in other schools/academies:)
Which of the following situations would cause the greatest decrease in the
motion of molecules in a system?
A
Explanation:
hindi ako sure kung tama ba yan
Oil having a density of 926 kg/m3 floats on water. A rectangular block of wood 3.69 cm high and with a density of 974 kg/m3 floats partly in the oil and partly in the water. The oil completely covers the block. How far below the interface between the two liquids is the bottom of the block
Answer:
the position of the wood below the interface of the two liquids is 2.39 cm.
Explanation:
Given;
density of oil, [tex]\rho _o[/tex] = 926 kg/m³
density of the wood, [tex]\rho _{wood}[/tex] = 974 kg/m³
density of water, [tex]\rho _w[/tex] = 1000 kg/m³
height of the wood, h = 3.69 cm
Based on the density of the wood, it will position across the two liquids.
let the position of the wood below the interface of the two liquids = x
Let the wood be in equilibrium position;
[tex]F_{wood} - F_{oil} - F_{water} = 0\\\\\rho _{wood} .gh - \rho _o .g(h-x) - \rho_w .gx = 0\\\\\rho _{wood} .h - \rho _o (h-x) - \rho_w .x = 0\\\\\rho _{wood} .h -\rho _o h + \rho _o x - \rho_w .x =0\\\\h (\rho _{wood} -\rho _o ) = x( \rho_w - \rho _o)\\\\x =h[\frac{ \rho _{wood} -\rho _o }{\rho_w - \rho _o} ]\\\\x = 3.69\ cm \times [\frac{974 - 926}{1000-926} ]\\\\x = 2.39 \ cm[/tex]
Therefore, the position of the wood below the interface of the two liquids is 2.39 cm.
In terms of their location, what is the difference between subcutaneous fat and visceral fat
1.Briefly describe the wind motion of the stationary front
.
2.What is another name for stationary front.
Answer:
stationary front is when it is not moving that is why weather is the same in some areas
Explanation:quasi-stationary front
how does speed measure
Answer:
Speed has the dimensions of distance divided by time. The SI unit of speed is the metre per second, but the most common unit of speed in everyday usage is the kilometre per hour or, in the US and the UK, miles per hour. For air and marine travel the knot is commonly used.
Explanation:
Plz give brainliest!
You are tasked with calibrating the springs for a pinball machine. Your method of testing the springs is by attaching masses onto the end of the springs and measuring the stretch from initial position to final position. You hang a 14kg mass on a spring and notice that it stretches from 50 to 78cm. What is the spring constant for that spring
Answer:
[tex]490.5\ \text{N/m}[/tex]
Explanation:
m = Mass attached to spring = 14 kg
g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]
x = Displacement of spring = [tex]78-50=28\ \text{cm}[/tex]
k = Spring constant
The force balance of the system is given by
[tex]kx=mg\\\Rightarrow k=\dfrac{mg}{x}\\\Rightarrow k=\dfrac{14\times 9.81}{0.28}\\\Rightarrow k=490.5\ \text{N/m}[/tex]
The spring constant for that spring is [tex]490.5\ \text{N/m}[/tex].
A continental polar air mass forms in
a. the Pacific Ocean.
b. northern Canada.
c.
the Gulf of Mexico.
the desert Southwest.
d.
Please select the best answer from the choices provided
А
B
ОООО
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my uq xbbbnxnjjxjxusjhhhwhhhnn he c x. Yes suhsjjdhhehy yes eirui
M I was going ask m
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Answer:
B. Northern Canada
Explanation:
A continental polar air mass can form over the land during the winter months. In the Northern Hemisphere, it originates in northern Canada or Alaska. As it moves southward, it brings dry weather conditions to the United States. Temperature and humidity levels are both low. Hope this helps :)
3. How much work is necessary to lift 10 kg 5m in the air?
1) 10N
3) 490 J
2) 50 J
4) 4900 J
Answer:
I'm not 100 percent sure but I have had a question very similar to this and I think 2.)50 j
A physics class performs an experiment to determine the winner of a race. An empty can, a solid cylindrical battery and a marble roll, all with the same radius) without slipping down an inclined plane of vertical height H (they are all released at the same height). A box slides without friction on another inclined plane of the same height, H. Which object reaches the bottom of the incline first
Answer:
a) SPHERE must be the winner
b) BOX is most fastest
Explanation:
For this exercise we must use conservation of energy
starting point. Highest part of the plane
Em₀ = U = m g h
final point. Lowest part of the plane
Em_f = K = ½ m v² + ½ I w²
Note that as the objects roll, the kinetic energy of rotation is included. Energy is conserved
Em₀ = Em_f
mg h = ½ m v² + ½ I w²
the linear and rotational variables are related
v = w r
w = v / r
the moment of inertia of the bodies is tabulated
ring (empty can) I = m r²
cylinder I = ½ m r²
sphere (marbles) I = 2/5 m r²
mgh = ½ m v² + ½ I v²/r² = ½ mv² (+ I / mr²)
2gh / (1 + I / mr²) = v² (1)
Let's analyze the value of I / mr2
can I / mr² = mr² / mr² = 1
cylinder I / mr² = ½ mr² / mr² = ½
sphere I / mr² = 2/5 mr² / mr² = 2/5
we substitute in equation 1
v = [tex]\sqrt{ \frac{2gh}{ (1+ \frac{I}{m r^2}) } }[/tex]
can v = √(2gh / 2) = √ gh
v = √gh
cylinder v= [tex]\sqrt{ \frac{2gh}{ \frac{3}{2} } }[/tex] = √(4gh/3)
v = 1,155 √gh
sphere v = [tex]\sqrt{ \frac{2gh}{ \frac{7}{5} } }[/tex] = √(10gh/7)
v = 1.20 √gh
therefore the object with the highest speed is the one that takes less time, consequently the SPHERE must be the cattle.
b) for a box on a frictionless surface, there is no rotational kinetic energy
mgh = ½ m v²
v = √2gh
v = 1.41 √(gh)
When comparing with the latter, this would be the one that arrives first