A piston-cylinder device initially contains 0.6 kg of water with a volume of 0.1 m3 . The mass of the piston is such that it maintains a constant pressure of 1000 kPa. The cylinder is connected through a valve to a supply line that carries steam at 5 MPa and 500 o C. Now the valve is opened and steam is allowed to flow slowly into the cylinder until the volume of the cylinder doubles and the temperature in the cylinder reaches 280 o C, at which point the valve is closed. The pressure remains constant during the process. Determine:

Answers

Answer 1

Answer: Hello the missing piece of your question is attached

question : Determine mass of steam that has entered ( in kg )

answer : 0.206 kg

Explanation:

V1 = 0.1 m^3 ,

v' = V1 / m1 = 0.1 / 0.6 = 0.167 m^3/kg

V2 = 0.2 m^3

using the steam tables

at ; P = 1000 kPa, v' = 0.167 m^3/kg

U1 = 2321  KJ/kg

at ; P = 1000 kPa , T2 = 280°C

v'2= 0.2481 m^3kg

U2 = 2760.6

at ; P = 5MPa ,  T = 500°C

h1 = 3434.7 KJ/Kg

calculate final mass ( m2 )

M2 = V2 / v'2

      = 0.2 / 0.2481 =  0.806 kg

therefore the mass added =  m2 - m1

                                            = 0.806 - 0.6 =  0.206 kg

A Piston-cylinder Device Initially Contains 0.6 Kg Of Water With A Volume Of 0.1 M3 . The Mass Of The

Related Questions

Which best explains why we are able to accelerate forward when starting to run? A) The runner's upper body quickly leans forward, causing the entire body to begin accelerating forward. B) As one leg moves backward, it provides an opposite force for the other foot to move forward. C) The foot not touching the ground propels the entire body as it swings forward. D) The striking foot pushes backward against the ground. The friction with the ground provides an equal and opposite force forward.

Answers

Answer:

D.The striking foot pushes backward against the ground. The friction with the ground provides an equal and opposite force forward

Answer:

d

Explanation:

Badll
Which of the following is an example of
the Law of Inertia?
A. Sitting in a chair and breaking it
B. Throwing a ball in outer space and it goes on forever
unless acted upon by another force
C. Eating a salad to bring chemical energy into the body
D. Driving a car on a track

Answers

Answer: B

Explanation: an object keeps moving unless it’s acted or interrupted by another force
Badll
Which of the following is an example of
the Law of Inertia?
A. Sitting in a chair and breaking it
B. Throwing a ball in outer space and it goes on forever
unless acted upon by another force
C. Eating a salad to bring chemical energy into the body
D. Driving a car on a track.
Answer is B

Match the descriptions with the graphs !

Answers

Answer:

Graph 1 matches with B, 2 with A, and 3 with C.

Explanation:

Graph 2 shows a car whose distance part of the graph is not going up or down, while the time going up. That means that the car is stopped. Graph 1 shows a straight line, meaning that the car is traveling at a constant speed. Graph 3 is a curved line, meaning the speed of the car is changing somehow, and since the line is becoming more horizontal, the car is getting slower.

A 744 N force is applied to an object to reach an acceleration of 24 m/s2. What is the objects mass?

Answers

31kg

Explanation:

F = ma

m = F/a

m = 744N/24m/s^2

m = 31kg

(*Newton's Second Law*)

What is law of conservation of energy?​

Answers

Energy can neither be created nor be destroyed.

Answer:

the law of conservation of energy states that the total energy of an isolated system remains constant.

3. A record 0.30 cm in diameter rotates 33.5 times per minute.
a. What is its frequency?

b. What is its period?

c. What is the linear speed of a point on its rim?

d. What is the centripetal acceleration of a point on its rim?

Answers

Explanation:

The diameter of a record, d = 0.3 cm

Radius, r = 0.15 cm

It rotates 33.5 times per minute.

(a) Frequency, f = 33.5 rotation/minute

= (33.5/60) rotation/second

= 0.55 rotation/second

(b) Time period,

T = 1/f

So,

[tex]T=\dfrac{1}{0.55}\\\\T=1.81\ s[/tex]

(c) Linear speed of a point on its rim,

[tex]v=r\omega\\\\v=0.15\times 10^{-2}\times 2\pi \times 0.55\\\\v=5.18\times 10^{-3}\ m/s[/tex]

(d) Centripetal acceleration,

[tex]a=\dfrac{v^2}{r}\\\\a=\dfrac{(5.18\times 10^{-3})^2}{0.15\times 10^{-2}}\\\\a=0.017\ m/s^2[/tex]

Hence, this is the required solution.

A beam of protons is directed in a straight line along the z direction through a region of space in which there are crossed electric and magnetic fields The electric field is 550 V m in the y direction and the protons move at a constant speed of 105 m s 1 What must be the magnitude of the magnetic field such that the beam of protons continues along its straight line trajectory Express your answer using two significant figures

Answers

Answer:

B = 5.23 T

Explanation:

Given that,

Electric field, E = 550 V/m

The speed of the proton, v = 105 m/s

We need to find the magnitude of the magnetic field such that the beam of protons continues along its straight-line trajectory.

To move in a straight line, the magnitude of the electric force from the field and the magnetic field must be equal i.e.

[tex]qE=qvB\\\\B=\dfrac{E}{v}\\\\B=\dfrac{550}{105}\\\\B=5.23\ T[/tex]

So, the magnitude of the magnetic field is equal to 5.23 T.

BRAINLEST FOR CORRECT ANSWER PLEASE

Which has more momentum: a 3 kg sledgehammer swung at 1.5 m/s OR a 4 kg sledgehammer swung at 0.9 m/s? SHOW YOUR WORK

Answers

Answer:

Sledgehammer A has more momentum

Explanation:

Given:

Mass of Sledgehammer A = 3 Kg

Swing speed = 1.5 m/s

Mass of Sledgehammer B = 4 Kg

Swing speed = 0.9 m/s

Find:

More momentum

Computation:

Momentum = mv

Momentum sledgehammer A = 3 x 1.5

Momentum sledgehammer A = 4.5 kg⋅m/s

Momentum sledgehammer B = 4 x 0.9

Momentum sledgehammer B = 3.6 kg⋅m/s

Sledgehammer A has more momentum

Would this be C ?? Please tell me if I’m wrong ..

Answers

Answer:

yes its c

Explanation:

took it already

Ashley decides to enter her pet turtle in a race. She knows her turtle can travel at a rate of 2 meters per hour. The race track measures 5 meters from start to finish. How long will it take Ashley’s turtle to finish the race?
A) 3 hours
B) 10 hours
C) .4 hours
D) 2.5 hours
Thanks for the help! And if it’s not a bother could you please explain how you got the answer? However it’s not necessary if you don’t want to.

Answers

It would probably be B

An airplane of mass 13300 kg is flying in a straight line at a constant altitude and with a speed of 560.0 km/hr. The force that keeps the airplane in the air is provided entirely by the aerodynamic lift generated by the wings. The direction of this force is perpendicular to the wing surface. Calculate the magnitude of the lift generated by the wings of this airplane.

Answers

Answer:

The magnitude of the lift generated by the wings of the airplane is 130,340 N.

Explanation:

Given;

mass of the airplane, m = 13,300 kg

speed of the airplane, v = 560 km/h = 155.56 m/s

The magnitude of the lift generated by the wings of the airplane is calculated as;

[tex]F_l = mg\\\\where;\\\\F_l \ is \ the \ magnitude \ of \ the \ lift \ generated\\g \ is \ acceleration \ due \ to \ gravity = 9.8 \ m/s^2\\\\F_l = 13,300 \times \ 9.8\\\\F_l = 130,340 \ N[/tex]

Therefore, the magnitude of the lift generated by the wings of the airplane is 130,340 N.

WILL REWARD 20 more pts once solved

4) If you have a diverging lens with a focal length of -15 cm and it produces an image that is 9
cm from the lens, what is the height of the image if the object was 4,5 cm tall?
b) Draw a ray tracing diagram of the situation below (label all points in cm) :

Answers

Explanation:

step 1. a diverging lens is "concave" on both side and always has a negative focal length

step 2. so 1/f = 1/s + 1/s' where f is the focal length, s is the object location, and s' is the image location (f, s, s' are all on the left side of the lens)

step 3. 1/-15 = 1/s + 1/-9 (image is virtual (negative))

step 4. 3/-45 = 1/s + 5/-45

step 5. s = 22.5cm (object is 22.5cm from lens)

step 6. s'/s = 9/22.5 ÷ 0.4 (magnification)

step 7. if the object is 4.5cm then the image is 4.5(0.4) = 1.8cm tall.

Which of the following would produce the most power?
b
ОООО
A mass of 10 kilograms lifted 10 meters in 10 seconds
A mass of 5 kilograms lifted 10 meters in 5 seconds
A mass of 10 kilograms lifted 10 meters in 5 seconds
A mass of 5 kilograms lifted 5 meters in 10 seconds
d

Answers

Answer:

A mass of 10 kilograms lifted 10 meters in 5 seconds.

Explanation:

Power can be defined as the energy required to do work per unit time.

Mathematically, it is given by the formula;

[tex] Power = \frac {Energy}{time} [/tex]

But Energy = mgh

Substituting into the equation, we have

[tex] Power = \frac {mgh}{time} [/tex]

Given the following data;

Mass = 10kg

Height = 10m

Time = 5 seconds

We know that acceleration due to gravity is equal to 9.8 m/s²

[tex] Power = \frac {10*9.8*10}{5} = 490 Watts [/tex]

Hence, a mass of 10 kilograms lifted 10 meters in 5 seconds would produce the most power.

Tom has a mass of 50,000 g and runs up a flight of stairs 4 m high in 12.5 seconds.
Calculate Tom’s power. (g = 10 m/s2)

Answers

Answer:

160 watts.

Explanation:

Remark

Power = Work / Time

Work = F * d

Note: Since he is running up stairs he is doing work against gravity.

Givens

m = 50000 g   kg / 1000 grmsm = 50000 / 1000 = 50 kgh = 4 mtime = 12.5 secondsg = 10 m/s^2

Formula

P = W * d/tW = m*g *d / t

Solution

P = 50kg * 10 m/s^2 * 4 m / 12.5 P = 160 watts.

If you wrap 150 coils of heavy wire around a big iron nail and attach the ends of the wire to a 6.0v battery, you have a A) radio B) electromagnet C) galvanometer D) ammeter​

Answers

Answer:

B

Explanation:

Because of the voltage attached to the iron nail

POSSIBLE POINTS: 1
After the Frisbee falls to the ground, you throw one of them back up into the tree, where it comes to rest on a branch.

Compared to when the Frisbee was on the ground, which of the following is true about the potential energy of the system?

Answers

Answer:

the effect on energy is due to the force applied to the frisbee to throw it back in the tree.

Explanation:

can someone help with me 1,2,3 please I will mark brainless .

Answers

Answer:

1) A. .33 hr

2) B. 6ft

3) A. 58mi/hr

A person drops a pebble of mass m1 from a height h, and it hits the floor with kinetic energy KE. The person drops another pebble of mass m2 from a height of 4h, and it hits the floor with the same kinetic energy KE. How do the masses of the pebbles compare

Answers

Answer:

Hello,

QUESTION)

✔ We have: KE = PE (potential energy)

PE = m x g x h

The potential energy that the pebble of mass 1 has is called PE1 and the potential energy that the pebble of mass 2 has is called PE2  

PE1 = PE2 ⇔ PE1/PE2 = 1

[tex]\frac{m_1\times g\times h}{m_2\times g\times 4h} = 1 \\ \\ \frac{m_1}{m_2\times 4} = 1 \\ \\ \frac{m_1}{m_2} = 4[/tex]

The mass m1 is therefore 4 times greater than that of the stone of mass m2.

 

At the end of the previous experiment, aclumsy scientist drops the coil, while still in the magnetic field, and still oriented with its plane perpendicular to the magnetic field, denting it and changing its shape to a semi-circle. The new shape has the same perimeter, but a different area, and it takes 0.036s to deform. What isthe average induced EMF during this mishap

Answers

Answer:

hello your question has some missing parts below are the missing parts

A Circular, 10-turn coil has a radius of 10.7 cm and is oriented with its plane perpendicular to a 0.2-T magnetic field.

answer : 1 volt

Explanation:

Determine the Average induced EMF during this mishap

A' = A/2  ( for a semi circle )

where A = [tex]\frac{\pi r^2}{2}[/tex]

To determine the Average induced EMF apply the relation below

| E | =  η * [tex]\frac{\beta A}{T}[/tex]   ----- ( 1 )

Replace A in equation 1 with  A = [tex]\frac{\pi r^2}{2}[/tex]

hence equation becomes : | E | =  η * βπr^2 / 2T'

where : T' = 0.0365 ,  β = 0.2 , η = 10 , r = 0.107

∴| E |  = 0.999 ≈ 1volts

Calculate the amount of torque of an object being pushed by 6 N force along a circular path of a radius of 1x10^-2 mat 30 degree angle.

Answers

Answer:

The amount of torque is 0.03 N.m.

Explanation:

To find the amount of torque we need to use the following equation:

[tex] \tau = \vec {r} \times \vec{F} = rFsin(\theta) [/tex]   (1)

Where:

r: is the radius = 1x10⁻² m

F: is the force = 6 N

θ: is the angle = 30°

By entering the above values into equation (1) we have:

[tex]\tau = 1 \cdot 10^{-2} m*6 N*sin(30) = 0.03 N.m[/tex]  

Therefore, the amount of torque is 0.03 N.m.

I hope it helps you!

The velocity of a car changes from 15 m/s south to 5 m/s south in 2
seconds. What is the acceleration of the car?
A. 5 m/s2 north
B. 10 m/s2 north
C. 10 m/s2 south
D. 5 m/s2 south

Answers

Answer:

Acceleration of car = -5 m/s south

Explanation:

Given:

Initial velocity = 15 m/s

Final velocity = 5 m/s

Time taken = 2 sec

Find:

Acceleration of car

Computation:

Acceleration = Change in velocity / time

Acceleration of car = [5-15] / 2

Acceleration of car = -5 m/s south

The resistances of the primary and secondary coils of a transformer are 76 and 13 Ohms, respectively. Both coils are made from lengths of the same copper wire. The circular turns of each coil have the same diameter. Find the turns ratio Ns/Np.

Answers

Answer:

Ns/Np = 0.171

Explanation:

First, we will find the ratio of lengths of each wire:

[tex]R_{p} = \frac{\rho L_{p}}{A}\\\\R_{s} = \frac{\rho L_{s}}{A}\\[/tex]

where,

Rs = Resistance of secondary coil

Rp = Resistance of Primary Coil

ρ = resistivity of copper

Ls = Length of the secondary coil

Lp = Length of theprimary coil

A = Area of cross-section of wie

Since the material and wire are the same. Therefore, dividing both equations, we get:

[tex]\frac{R_{s}}{R_{p}} = \frac{L_{s}}{L_{p}} \\\\\frac{L_{s}}{L_{p}} = \frac{13}{76}\\\\\frac{L_{s}}{L_{p}} = 0.171\\[/tex]

The number of turns are given as:

[tex]N_{s} = \pi DL_{s}\\N_{p} = \pi DL_{p}\\[/tex]

where,

Ns = No. of turns in the secondary coil

Np = No. of turns in the primary coil

D = Diameter of circular turns

D is the same for both coils. Therefore, dividing both equaions:

[tex]\frac{N_{s}}{N_{p}} = \frac{L_{s}}{L_{p}}\\\\[/tex]

Ns/Np = 0.171

a kite is a 150 feet high and 200 feet of string are out. if the kite starts drifting away horizontally at the rate of 4 miles an hour how fast is a string being paid out at the start​

Answers

Answer:

Let z = 200 ft and y = 150 ft

Also since 60 mph = 88 ft/sec then 4 mph = 88/15 = 5.87 ft.sec

Now   x^2 + y^2 = z^2

x dx/dt + y dy/dt = z dz/dt       differentiate wrt t

Or x dx/dt = z dz/dt    since dy/dt = zero

x = (200^2 - 150^2)^1/2 = 132.3 ft

dz/dt = x / z * dx/dt = 132.3 / 200 * 5.87 = 3.88 ft/sec

In which regions can the gravitational field strength due to the two planets be zero? Explain.

A. None
B. A, B and C
C. A and C
D. B

Answers

Answer:

I believe its a and c but my notes are all kinds of messed up so im sorry if its wrong

Explanation:

None of the  regions can the gravitational field strength due to the two planets be zero.

What is gravitational field?

A gravitational field is a model used in physics to explain the effects that a large thing has on the area surrounding it, exerting a force on smaller, less massive bodies. Consequently, a gravitational field, which is measured in newtons per kilogram, is employed to describe gravitational processes.

Field due to given masses can not be zero in the given region they do not cancel each other.

None of the  regions can the gravitational field strength due to the two planets be zero.

To learn more about gravitational field refer to the link:

brainly.com/question/12324569

#SPJ2

An object that weighs 500 kg is rolling along the road at 3.5 m/s, what is the momentum of the object?

Answers

Answer:

momentum=mass x velocity= 500 x 3.5 = 1750kgm/s

50 points help please

Answers

Answer:

C?

Explanation:

Yep,It's C all right.

Answer:

Yep,It's C all right.

Explanation:

Currently accepted theories DO NOT predict single existing particles having electrical charge equal (Picture Provided)

Answers

tbm queria saber essa pergunta!!

Kyle lays a mirror flat on the floor and aims a laser at the mirror. The laser beam reflects off the mirror and strikes an adjacent wall. The plane of the incident and reflected beams is perpendicular to the wall. The beam from the laser strikes the mirror at a distance a=60.1 cm from the wall. The reflected beam strikes the wall at a height b=31.3 cmabove the surface of the mirror.Find the angle of incidence θiat which the laser beam strikes the mirror.

Answers

Answer:

62.5 °

Explanation:

✓From law of reflection, angle of incidence equals angles of reflection .

✓the angle between the reflected ray can be determined using trigonometry, we know that

horizontal distance x =60.1 cm

the vertical distance is y =31.3

Then

tan( θ) =( y / x)

If we substitute the values we have,

tan θ = 31.3 / 60.1

θ = tan⁻¹ (0.5208)

θ = 27.5°

This angle is been measured using x-axis (horizontal)BBut in optics we can measured with respect to y-axis then angle becomes

θ = 90 - 27.5

θr = 62.5 °

θr = θi= 62.5°

the angle of incidence θiat which the laser beam strikes the mirror is 62.5°

Snell's law describes the relationship between the angle a light ray makes as it leaves a surface, the angle it makes incident on the surface, and the indices of refraction on both sides of the surface. If light incident in air at angle of 30 degrees from the normal onto glass with an index of refraction of 1.5 --Pick those answers that applya) Inside the material, the light leaving the surface is closer to the surface, makes a bigger angle with the normal, than the entering light makes in air.b) The light inside the glass is closer to the normal, makes a bigger angle with the surface, than the incident lightc) There is light reflected back into the air from the surfaced) The angle is too steep for light to refract and it is all reflected.

Answers

Answer:

b) and c)

Explanation:

Snell's law states that there exists a fixed relationship between the sine of the angle that makes with the normal an incident ray on the separation surface of two transparent media, the sine of the angle that is refracted off the surface, and the indexes of refraction of both media, as follows:

       [tex]\frac{sin_{\theta i}}{sin_{\theta r} } =\frac{n_{2} }{n_{1} } (1)[/tex]

Givens: θi = 30º n₁ = 1 (air) n₂= 1.5 (glass)Since sin 30º = 0.5, we can solve for sin r, as follows:[tex]sin \theta r = \frac{sin_{\theta i}}{n_{2}} = \frac{0.5}{1.5} = 0.333 (2)[/tex]As the sin r is lower than sin i, this implies that the angle that makes with the normal is lower than i, which means that it makes a bigger angle with the surface, as stated by b).Also there is some light that is reflected by the surface, making an angle with the normal equal to the incident ray, as stated by c). So, b) and c) are the right choices.

The way you change the speed of a wave is to:

a
Change it's medium
b
Change it's energy
c
Transfer it to a new position
d
Apply a force

Answers

Answer:

transfer it to a new position

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