Answer:
A.) 355 m/s
B.) 0.71 m
C.) 500Hz
Explanation:
Given that a police car is traveling due east at a speed of 15.0 m/s relative to the earth. You are in a convertible following behind the police car. Your car is also moving due east at 15.0 m/s relative to the earth, so the speed of the police car relative to you is zero. The siren of the police car is emitting sound of frequency 500 Hz. The speed of sound in the still air is 340 m/s
a.) What is the speed of the sound waves relative to you?
Since the car is moving away from the observer, the relative velocity will be:
Relative velocity = 340 + 15
Relative velocity = 355 m/s
b.) What is the wavelength of the sound waves at your location?
Using the wave speed formula
V = frequency × wavelength
Make wavelength the subject of formula.
Wavelength = Velocity / frequency
Wavelength = 355/500
Wavelength = 0.71 m
c.) What frequency do you detect?
Fo = Fs ( C + V ) / ( C + v )
Fo = Fs
That is, the frequency of the observer will be equal to the frequency of the source.
Therefore, Fo = 500Hz
A particle of mass M is moving in the positive x direction with speed v. It spontaneously decays into 2 photons, with the original particle disappearing in the process. One photon has energy 233 MeV and moves in the positive x direction, and the other photon has energy 21 MeV and moves in the negative x direction. (5) (a) Draw a picture of this process. What is the total relativistic energy of the particle before its decay
Solution :
Mass of the particle = M
Speed of travel = v
Energy of one photon after the decay which moves in the positive x direction = 233 MeV
Energy of second photon after the decay which moves in the negative x direction = 21 MeV
Therefore, the total energy after the decay is = 233 + 21
= 254 MeV
So by the law of conservation of energy, we have :
Total energy before the decay = total energy after decay
So, the total relativistic energy of the particle before its decay = 254 MeV
What is the equivalent resistance of the circuit pictured below?
Answer:
450 since in series we add the resistance
A 10v battery is connected in series with 2 resistors. R1 is 1 ohm and R2 is 4 ohms. What is the current that goes across R1?
Answer:
Current in circuit = 2 amp
Explanation:
Given:
Voltage of battery = 10 V
First Resistance R1 = 1 ohm
Second Resistance R2 = 4 ohm
Resistor connected in series
Find:
Current in circuit
Computation;
Resistor connected in series
So,
Total resistance R = First Resistance R1 + Second Resistance R2
Total resistance R = 1 ohm + 4 ohm
Total resistance R = 5 ohm
Current in circuit = V / R
Current in circuit = 10 / 5
Current in circuit = 2 amp
Which statement is true of a catalyst in a reaction?
A. It acts as a reactant, in place of the original reactant.
B. It gets used up in the reaction.
C. It changes the activation energy required for the reaction.
D. It makes a reaction faster by adding energy.
Answer:
Hello There!!
Explanation:
The answer is=>C. It changes the activation energy required for the reaction.
hope this helps,have a great day!!
~Pinky~
The true statement for a catalyst used in a reaction is that it makes a reaction faster by adding energy. The correct option is D.
What is a catalyst?A catalyst is a substance that increases the chemical reaction rate without undergoing any permanent chemical change in itself. It makes the reaction faster.
The correct option is D.
Learn more about catalyst.
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PLEASE HELP MEE PLEASE!
Answer;
gram
Explanation
Dominant alleles are _____.
Only expressed if paired with a recessive allele
Only expressed if paired with another dominant allele
Always expressed
Never expressed
They're always expressed.
really simple science packet, i just need help it’s due tomorrow. thank y’all :)
Answer:
13: (Im not sure sorry)
14: C
15: B
16: B
17: B
18: B
A coin is resting on the bottom of an empty container. The container is then fi lled to the brim three times, each time with a diff erent liquid. An observer (in air) is directly above the coin and looks down at it. With liquid A in the container, the apparent depth of the coin is 7 cm, with liquid B it is 6 cm, and with liquid C it is 5 cm. Rank the indices of refraction of the liquids in descending order (largest fist).
a. nC, nA, nB
b. nA, nB, nC
c. nB, nA, nC
d. nC, nB, nA
e. nA, nC, nB
when we placed in the container of real depth assuming = d
if the container filled with liquid A then its apparent depth d' = 7cm
so the refractive index nA = real depth / apparent depth
= d/7cm = 0.1428d
if the container filled with liquid B then its apparent depth d' = 6cm
so the refractive index nB = real depth / apparent depth
= d/6cm = 0.166d
if the container filled with liquid C then its apparent depth d' = 5cm
so the refractive index nC = real depth / apparent depth
= d/5cm = 0.2d
Since the refractive index is inversely proportional to the apparent depth
then the refractive indices are nC > nB > nA
1: Which person is not doing work?
O A. A person climbing a hill
O B. Someone climbing stairs
O C. A person lifting a bag of sand
O D. A person holding a baby
Answer:
D
Explanation:
provides some pertinent background for this problem. A pendulum is constructed from a thin, rigid, and uniform rod with a small sphere attached to the end opposite the pivot. This arrangement is a good approximation to a simple pendulum (period = 0.61 s), because the mass of the sphere (lead) is much greater than the mass of the rod (aluminum). When the sphere is removed, the pendulum no longer is a simple pendulum, but is then a physical pendulum. What is the period of the physical pendulum?
Answer:
the period of the physical pendulum is 0.498 s
Explanation:
Given the data in the question;
[tex]T_{simple[/tex] = 0.61 s
we know that, the relationship between T and angular frequency is;
T = 2π/ω ---------- let this be equation 1
Also, the angular frequency of physical pendulum is;
ω = √(mgL / [tex]I[/tex] ) ------ let this equation 2
where m is mass of pendulum, L is distance between axis of rotation and the center of gravity of rod and [tex]I[/tex] is moment of inertia of rod.
Now, moment of inertia of thin uniform rod D is;
[tex]I[/tex] = [tex]\frac{1}{3}[/tex]mD²
since we were not given the length of the rod but rather the period of the simple pendulum, lets combine this three equations.
we substitute equation 2 into equation 1
we have;
T = 2π/ω OR T = 2π/√(mgL/[tex]I[/tex]) OR T = 2π√([tex]I[/tex]/mgL)
so we can use [tex]I[/tex] = [tex]\frac{1}{3}[/tex]mD² for moment of inertia of the rod
Since center of gravity of the uniform rod lies at the center of rod
so that L = [tex]\frac{1}{2}[/tex]D.
now, substituting these equations, the period becomes;
T = 2π/√([tex]I[/tex]/mgL) OR T = [tex]2\pi \sqrt{\frac{\frac{1}{3}mD^2 }{mg(\frac{1}{2})D } }[/tex] OR T = 2π√(2D/3g ) ----- equation 3
length of rod D is still unknown, so from equation 1 and 2 ( period of pendulum ),
we have;
ω[tex]_{simple[/tex] = 2π/[tex]T_{simple[/tex] OR ω[tex]_{simple[/tex] = √(g/D) OR ω[tex]_{simple[/tex] = 2π√( D/g )
so we simple solve for D/g and insert into equation 3
so we have;
T = √(2/3) × [tex]T_{simple[/tex]
we substitute in value of [tex]T_{simple[/tex]
T = √(2/3) × 0.61 s
T = 0.498 s
Therefore, the period of the physical pendulum is 0.498 s
Look at the distance-time graph below. It shows Angela's journey as she walks to the end of the road and back. The gradient represents Angela's __________. What one word completes the sentence?
Answer:
The gradient here represents Angela's Velocity.
Explanation:
A distance-time graph has distance on its y-axis and time on its x-axis. Therefore, the gradient of the distance-time graph is given by the following formula:
[tex]Gradient = \frac{Change\ on\ y-axis}{Change\ on\ x-axis} \\\\Gradient = \frac{Distance\ Covered\ by\ Angela}{Time\ taken\ to\ cover\ the\ distance}\\\\Gradient = Angela's\ Velocity[/tex]
Since the rate of change of distance is called the velocity.
Therefore, the gradient here represents Angela's Velocity.
A 25 MGD surface water drinking plant has four circular clarifiers (aka sedimentation basin), operated in parallel with each basin receiving equal flow, that all have a diameter of 16 meters and are 3 m deep. Assume that all particles entering the clarifiers have the same particle density of 1.2 mg/mL and the average water temperature is 20 oC with an average viscosity of 1 g/(m*s) and an average density of 998.2 kg/m3.
1. What is the diameter of the smallest particles (in mm) that can be removed by these clarifiers?
2. If the each of the four clarifiers is to be rectangular in shape with a length to width ratio of 5:1, what is the minimum width that each clarifier can be (in meters)?
Answer:
can y
Explanation:
jj
The smallest particles that can be removed by these clarifiers have a diameter of 0.0257 mm, and the minimum width of a rectangular clarifier with a length-to-width ratio of 5:1 is 0.023 times the length.
What is the equation for the settling velocity of a particle?The equation for the settling velocity of a particle:
V_s = (2/9) * (ρ_p - ρ_w) * g * r^2 / η
where V_s is the settling velocity, ρ_p is the particle density, ρ_w is the water density, g is the acceleration due to gravity, r is the particle radius, and η is the water viscosity.
1. We can rearrange the equation to solve for the particle radius:
r = [9ηV_s / (2(ρ_p - ρ_w)g)]^(1/2)
We want to find the particle diameter, which is twice the radius, so we can substitute 2r for d in the following equation:
d = 2r = 2[9ηV_s / (2(ρ_p - ρ_w)g)]^(1/2)
To remove the smallest particles, we want to use the smallest settling velocity possible, which corresponds to a particle just barely settling to the bottom of the clarifier. Therefore, we can set V_s equal to the minimum settling velocity required for particles to be removed:
V_s = Q / (A * X)
where Q is the flow rate (25 MGD), A is the surface area of one clarifier (πr^2), and X is the overflow rate, which is the flow rate per unit area of the clarifier. A typical overflow rate for a sedimentation basin is 600-1200 gallons per day per square foot (gpd/ft^2), or 2.5-5 m^3/day/m^2. We will use the lower end of this range, 2.5 m^3/day/m^2.
Substituting in the values for Q, A, and X, we get:
V_s = (25 MGD) / (π(8 m)^2 * 2.5 m^3/day/m^2) = 0.00159 m/s
Now we can substitute the values for η, ρ_p, ρ_w, g, and V_s into the equation for the particle diameter:
d = 2[9(1 g/(m*s))(0.00159 m/s) / (2(1200 kg/m^3 - 998.2 kg/m^3)(9.81 m/s^2))]^(1/2) = 0.0257 mm
So, the smallest particles that can be removed by these clarifiers have a diameter of approximately 0.0257 mm.
2. To find the minimum width of a rectangular clarifier with a length-to-width ratio of 5:1, we can use the same overflow rate and flow rate as before, and we can assume a depth of 3 m. The surface area of one clarifier must still be the same as before, so we can use the equation for the surface area of a rectangle:
A = L * W
where L is the length and W is the width.
Substituting in the values for Q, X, and A, we get:
W = (25 MGD) / (5 * 24 hr/day * 60 min/hr * 60 s/min * 2.5 m^3/day/m^2 * 5 * L)
Simplifying, we get:
W = 0.023 L
So, the minimum width of a rectangular clarifier with a length-to-width ratio of 5:1 is 0.023 times the length.
Therefore, The smallest particles that can be removed by these clarifiers have a diameter of 0.0257 mm, and a rectangular clarifier's minimum width is 0.023 times the length when the length-to-width ratio is 5:1.
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What is the name of the scientist and science fiction writer: *
A friend of yours who is traveling the world reports that she recently experienced a day on which the surface wind blew from the southeast while simultaneously the clouds overhead were moving from east to west. Independently, she is made aware of the fact that on that day the PGF was the same at the surface and at the cloud height. What hemisphere was she in at the time
Answer:
At that time, she was in the southern hemisphere
Explanation:
She is witnessing the southeastern trade breeze because the cloud is passing from east to west and she is also witnessing a storm from the southeast.
Because of the Coriolis effect, which deviates the atmosphere in the left-hand side of the southern hemisphere and generates a southeastern wind, this wind did not blow directly from south to east.
If distance between particle become half, the electric force
The force between the two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. Hence, if distance between charges is halved (charges remaining kept constant), the force between the two charges is quadrupled.
____ is the amount of matter an object and the mass of an _____ does not change location.
Answer:
Mass
Object
Explanation:
Answer:
Mass is the amount of matter in an object and the mass of an object does not change location.
In a city with an air-pollution problem, a bus has no combustion engine. It runs on energy drawn from a large, rapidly rotating flywheel under the floor of the bus. The flywheel is spun up to its maximum rotation rate of 4000 rev/min by an electric motor at the bus terminal. Every time the bus speeds up, the flywheel slows down slightly. The bus is equipped with regenerative braking so that the flywheel can speed up when the bus slows down. The flywheel is a uniform solid cylinder with mass 1600 kg and radius 0.650 m. The bus body does work against air resistance and rolling resistance at the average rate of 18.0 hp as it travels with an average speed of 40 km/h. How far can the bus travel before the flywheel has to be spun up to speed again
Answer:
the bus can travel 24.54 km before the flywheel has to be spun up to speed again
Explanation:
Given the data in the question;
mass of wheel m = 1600 kg
radius of the fly wheel r = 0.650 m
angular speed of the wheel ω = 4000 rev/min = 418.879 rad/s
Average speed of the bus v = 40 km/h = 11.1111 m/s
Power p = 18 hp = 13428 watt
So moment of inertia of the fly wheel is;
[tex]I[/tex] = [tex]\frac{1}{2}[/tex]mr²
we substitute
[tex]I[/tex] = [tex]\frac{1}{2}[/tex] × 1600 kg × (0.650 m)²
[tex]I[/tex] = 338 kgm²
So, the rotational energy of the bus will be;
[tex]E_r[/tex] = [tex]\frac{1}{2}[/tex][tex]I[/tex]ω²
we substitute
[tex]E_r[/tex] = [tex]\frac{1}{2}[/tex] × 338 kgm² × ( 418.879 rad/s )
[tex]E_r[/tex] = 29652675.212329 J
relation of power to energy
P = E / t
but we know that time t = distance / velocity
t = d/v
∴
P = E / ( d/v)
we solve for distance (d)
P = Ev / d
Pd = Ev
d = Ev / P
so we substitute
d = [( 29652675.212329 J )( 11.1111 m/s )] / [ 13428 W ]
d = 24536.33 m
d = 24.54 km
Therefore, the bus can travel 24.54 km before the flywheel has to be spun up to speed again
can the mass of an object is measured by a scale?
Answer: In physics, mass is not the same as weight, even though mass is often determined by measuring the object's weight using a spring scale, rather than balance scale comparing it directly with known masses.
Explanation:
In physics, mass is not the same as weight, even though mass is often determined by measuring the object's weight using a spring scale, rather than balance scale comparing it directly with known masses.
How could you prove that
through
rock layers in one area match rock layers
found in another area?
Answer:
An unconformity shows where some rock layers have been lost because of erosion. To date rock layers, geologists first give a relative age to a layer of rock at one location and then give the same age to matching layers at other locations. Certain fossils, called index fossils, help geologists match rock layers.
Explanation:
PLEASE HELP! I'LL GIVE BRAINLEST. PLEASE A RIGHT ANSWER
Answer:
The answer is a - is the amount of matter in this object
Explanation:
16. Using the formula P = V x I, find the amount of power flowing through a circuit carrying a current of 20 amperes at a potential difference of 120 volts.
O A 2400 Watts
B. 6 Watts
C. 1200 Watts
D. 24 Watts
From Coulomb's Law:
Electric force is:
A. directly proportional to distance.
B. inversely proportional to distance.
C. directly proportional to the square of the distance.
D. inversely proportional to the square of the distance.
Answer:
D
Explanation:
Coulomb's law states that the electrical force between two charged objects is directly proportional to the product of the quantity of charge on the objects and inversely proportional to the square of the separation distance between the two objects.
A Boulder drops in the water and creates a wave with a period of 2s/cycle and a wavelength of .75 m/cycle. How fast is the wave moving ?
Answer:
v = 0.375 m/s
Explanation:
Given that,
The wavelength of a wave is 0.75 m/cycle
The period of a wave is 2s/cycle
We need to find the speed of the wave. We know that,
[tex]v=\dfrac{d}{t}[/tex]
Substitute all the values,
[tex]v=\dfrac{0.75}{2}\\\\v=0.375\ m/s[/tex]
So, the speed of the wave is equal to 0.375 m/s.
On a part-time job, you are asked to bring a cylindrical iron rod of density 7800 kg/m3 , length 95.0 cm and diameter 2.00 cm from a storage room to a machinist. Calculate the weight of the rod, w. Assume the free-fall acceleration is g
Answer:
[tex]22.84\ \text{N}[/tex]
Explanation:
[tex]\rho[/tex] = Density = [tex]7800\ \text{kg/m}^3[/tex]
h = Length of rod = 95 cm
d = Diameter of rod = 2 cm
r = Radius = [tex]\dfrac{d}{2}=1\ \text{cm}[/tex]
g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]
V = Volume of rod = [tex]\pi r^2h[/tex]
Mass is given by
[tex]m=V\rho[/tex]
Weight is given by
[tex]w=mg=V\rho g\\\Rightarrow w=\pi r^2h\rho g\\\Rightarrow w=\pi\times (1\times 10^{-2})^2\times (95\times 10^{-2})\times 7800\times 9.81\\\Rightarrow w=22.84\ \text{N}[/tex]
The weight of the rod is [tex]22.84\ \text{N}[/tex].
an example of a household appliance with a low and high power rating
Answer:
Explanation:
There are countless household appliances in every single house. One appliance with a low power rating would be a ceiling fan. On average ceiling fans consume roughly 60w and are found in the majority of houses. On the other side of the spectrum, we have a high power-rating appliance such as a microwave. Microwaves use anywhere between 1000w to 1800w of power in order to function correctly. This is very large power consumption and one of the highest power ratings found for appliances in a household.
2. Compare and Contrast A fault cuts through
two layers of rock. Above sits a layer of sand-
stone. How does the age of the fault compare
to the ages of all three rock layers?
Explanation:
The principle of cross-cutting relationships states that a fault or intrusion is younger than the rocks that it cuts through. The fault labeled "E" cuts through all three sedimentary rock layers (A, B,and C) and also cuts through the intrusion (D). So the fault must be the youngest formation that is seen and known of.
The age of the fault A is in between rock B and intrusion D. Hence A is the youngest rock and C be the oldest rock here.
What are faults?A fault is a crack or region of cracks that separates two rock blocks. The blocks might move in relation to one another due to flaws. This movement may happen suddenly, like an earthquake, or it may happen gradually, like creep.
From a few millimeters to thousands of kilometers, faults can vary in length. Over geologic time, most faults cause recurrent displacements. The rock on one side of the fault abruptly shifts in relation to the other during an earthquake. The fault surface may be vertical, horizontal, or at any other arbitrary angle.
The principal of superposition states that, the oldest layer will be the bottom of the young rocks. Here, rock is A is above B and C. Hence, rock A is youngest than layer B and C.
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The related image is attached below:
Drag each tile to the correct box.
Adam takes a bus on a school field trip. The bus route is split into the five legs listed in the table. Find the average velocity for each leg of the trip. Then arrange the legs of the trip from highest velocity to lowest.
Leg Distance (km) Time (min)
A 18 9
B 25 15
C 24 8
D 48 12
E 15 7
What are fossil fuels composed of
Oxygen and carbon
Rocks under extreme pressure
Remains of living things
Answer:
C. Remains of living things
Explanation:
They are made up of dead animals or plants. Coal, Oil, and Natural Gas are the three types of fossil fuels and all of them come from dead organisms. Even the name Fossil Fuels, sounds like a name for something like this.
Hope this Helps ʕ•ᴥ•ʔ
Answer:
C
Explanation:
took the test
Sound is a longitudinal wave that travels at speed 343343m/s in dry air at room temperature and standard pressure. Your ear is capable of differentiating sounds that arrive at the ear just 1.00 milliseconds apart. What is the minimum distance between two speakers that produce sounds that arrive at noticeably different times
Answer:
d = 0.343 m
Explanation:
Given that,
The speed of a longitudinal wave, v = 343 m/s
Your ear is capable of differentiating sounds that arrive at the ear just 1.00 milliseconds apart.
We need to find the minimum distance between two speakers that produce sounds that arrive at noticeably different times.
Let the distance be d. So,
[tex]d=v\times t\\\\=343\times 10^{-3}\\\\=0.343\ m[/tex]
So, the required distance is equal to 0.343 m.
may anyone please help me with all of this side of the packet?:) ill give all my points for this :(
Answer: 4 is b 8 is c
Explanation: