a proton is near a charged plate and feels a force of 4.5x10^-16 N if the oroton is 1.3x1^-6 m away from the charged plate what is the charge of the plate

Answers

Answer 1
The charge of the plate is negative 37 or -37 bye the plate charges pro Ton

Related Questions

#10. When the weightlifter in question #9 stands, his feet make contact with the floor over an area of 250 square centimeters. What is the area of contact between his feet and the floor in *square meters (picture of question 9 for reference)​

Answers

The weight is 1372 N

How do we calculate the weight of an object on earth?

The weight of an object on Earth can be calculated by using the following formula:

Weight = Mass x Acceleration due to Gravity

Where:

Weight is measured in Newtons (N)

Mass is measured in kilograms (kg)

Acceleration due to Gravity is a constant value

Weight = mass * acceleration due to gravity

Weight = 140 Kg * 9.8

= 1372 N

To calculate the weight of an object on Earth, you need to know its mass.

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Which statement describes the location of an earthquake’s epicenter?

It is located using a single set of data.
It is determined by the Mercalli Scale.
It is determined by the arrival time of surface waves.
It is located at the point directly above the focus

Answers

Answer:

it is located at the point directly above the focus

Answer:

D

Explanation:

what is the magnitude of the force between two wires separated by 9.30 cm and each carrying 128 a? one wire is very long and the other is 35.0 m long

Answers

The magnitude of the force between the wires is 0.00156 N

The magnitude of the force between two parallel wires can be calculated using the formula:

F = (μ₀ * I₁ * I₂ * ℓ) / (2 * π * r)

where F is the force

, μ₀ is the permeability of free space (4π × 10⁻⁷ T·m/A),

I₁ and I₂ are the currents in the wires,

ℓ is the length of the shorter wire, and

r is the separation distance between the wires.

In this case, we have:

I₁ = I₂ = 128 A

ℓ = 35.0 m

r = 9.30 cm = 0.0930 m

So, the force between the wires is:

F = (4π × 10^⁻⁷ T·m/A) * (128 A)² * (35.0 m) / (2 * π * 0.0930 m)

F = 0.00156 N

Therefore, the magnitude of the force between the wires is 0.00156 N.

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a simple machine is able to move a 400N load a distance of 20cm when a force of 20N is moved through a distance of 5m calculate work input​

Answers

The work input required is 180 J.

The formula gives the work input:

Work input = Force x Distance

In this instance, a force of 20 N is used, and 5 m is moved. As a result, the force's work is:

Work done by force = 20 N x 5 m = 100 J

A 400 N weight can be moved by the machine 20 cm (or 0.2 m) away.

Using the following formula, we can estimate the work performed by the machine:

Work done by machine = Load x Distance moved by the load

Work done by machine = 400 N x 0.2 m = 80 J

As a result, the amount of work needed to move the load with the machine is:

Work input = Work done by force + Work done by machine

Work input = 100 J + 80 J = 180 J

Therefore, the work input required is 180 J.

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Can someone answer this question:
What is a period on the periodic table?

Answers

Answer:

A period in the periodic table is a row of chemical elements

Explanation:

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Answer:

Horizontal rows in a periodic table are called periods

Explanation:

There are 7 periods in the periodic tableIn periods, chemical properties of elements changeIn periods, physical properties of elements remain the samePeriod number also indicates number of shells an element will have.

For example: Na (sodium) is in the third period, hence it will have 3 shells

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A man fires a shot while in a deep canyon with parallel cliff walls. The temperature in the canyon is 27.0°C. If the echo from one wall is heard in 1.50 seconds, and the echo from the other wall is heard 1.00 second later, how wide is the canyon?

Answers

The canyon is approximately 258 meters wide.

What is the width of the canyon?

The speed of sound in air depends on the temperature, and we can use the formula:

v = 331.4 + 0.6T

where;

v is the speed of sound in meters per second, and T is the temperature in Celsius. At a temperature of 27.0°C,

The speed of sound is:

v = 331.4 + 0.6(27.0)

v = 343.8 m/s

Let's call the distance to one wall "d". When the man fires the shot, the sound travels to the wall, reflects, and returns to the man.

The total distance traveled is 2d. The time it takes for the sound to travel this distance is:

t = 2d/v

Similarly, for the other wall, the total distance traveled is 2(D - d)

where;

D is the width of the canyon.

The time it takes for the sound to travel this distance is:

t + 1.00 = 2(D - d)/v

We can solve these equations for d and D:

d = vt/2

D = (v/2)(t + 1.00)

Substituting in the values we have:

d = (343.8 m/s)(1.50 s)/2 = 257.85 m

D = (343.8 m/s/2)(1.50 s + 1.00 s) = 515.70 m

Therefore, the width of the canyon is:

D - d = 515.70 m - 257.85 m = 257.85 m

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The reactants of a chemical equation have 1 S atom and 4 O atoms. Which set of atoms must also be founding the equations products so that the equation models the law of conservation of mass


A. 1 S and 4 O

B. 1 S and 1 O

C. 4 S and 1 O

D. 4 S and 4O

Answers

The set of atoms must also be founding the equations products so that the equation models the law of conservation of mass is option (A) 1 S and 4 O

The law of conservation of mass is a fundamental principle in chemistry that states that the mass of the reactants in a chemical reaction must be equal to the mass of the products. This principle is based on the fact that atoms cannot be created or destroyed in a chemical reaction, and therefore, the number of atoms of each element on both sides of the equation must be the same.

In order to balance a chemical equation and satisfy the law of conservation of mass, it is necessary to adjust the coefficients of the reactants and products to ensure that the number of atoms of each element is equal on both sides of the equation.

Therefore, the correct option is (A) 1 S and 4 O

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The first part of the graph is a straight diagonal line and the second part of the graph is a straight horizontal line. The slope of the first part of the graph is positive, indicating that the cart increased in speed, and was therefore accelerating for the first four seconds. After the fourth second, the slope of the line is zero, indicating that the cart moved at a constant speed and did not accelerate any more because the fan was turned off.

Answers

Answer:

This description is likely referring to a graph that shows the velocity of a cart over time. The first part of the graph shows a positive slope, indicating that the velocity is increasing over time, and the second part of the graph shows a horizontal line, indicating that the velocity is constant. The fact that the slope of the first part of the graph is positive means that the cart is accelerating, since acceleration is defined as a change in velocity over time. The fact that the slope of the second part of the graph is zero means that the cart is not accelerating, since its velocity is not changing. The explanation suggests that the change in velocity is due to a fan being turned on and then off, which is causing the cart to accelerate and then move at a constant velocity.

Which property of the Sun most affects the
strength of gravitational attraction between
the Sun and Earth?

A mass
B radius
C shape
D temperature

Answers

Answer:

mass

Explanation:

The property of the Sun that most affects the strength of gravitational attraction between the Sun and Earth is A) mass. The greater the mass of an object, the stronger its gravitational pull. The Sun has a mass that is more than 300,000 times that of Earth, so its gravitational force is strong enough to keep the Earth in orbit around it.

how much voltage is available to operate an overvoltage relay 59g when connected across the grounding resistor? what is the multiple of pickup if 59g minimum operating value is 5.4 v.

Answers

The voltage available to operate an overvoltage relay 59G when connected across the grounding resistor is 54 V. The multiple of pickup if 59G minimum operating value is 5.4 V is 10.

An overvoltage relay is a type of protective relay that is used to detect overvoltage conditions on an electrical network. The purpose of this relay is to detect if the voltage on the network exceeds a certain level, which could result in damage to equipment or electrical systems connected to the network. The overvoltage relay is connected to the electrical network in such a way that it monitors the voltage level on the network and is capable of tripping a circuit breaker or other protective device if the voltage level exceeds a preset value.

The voltage available to operate an overvoltage relay 59G when connected across the grounding resistor is 54 V. This is because the grounding resistor limits the voltage to a maximum of 54 volts. If the voltage level on the network.

The multiple of pickup if 59G minimum operating value is 5.4 V is 10. This means that the overvoltage relay will trip if the voltage on the network exceeds 54 volts. If the voltage level on the network is between 5.4 volts and 54 volts, the overvoltage relay will not trip, since the voltage is below the pickup level. However, if the voltage level on the network exceeds 54 volts, the overvoltage relay will trip and disconnect the circuit.

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A storage tank at STP contains 27. 8 kg of nitrogen (N2).

What is the volume of the tank?

What is the pressure if an additional 31. 1 kg of nitrogen is added without changing the temperature?

Answers

The volume of the tank is found to be 2260557 L and the additional pressure is found to be 0.85 atm.

A storage tank at STP contains 27. 8 kg of nitrogen N₂. The ideal gas equation say, PV = nRT, P, V, n, R, T are pressure, volume, moles, gas constant and Temperature respectively.

At STP, pressure is 1 atm and Temperature is 272 K.

Putting all the values,

1 x V = 27800/28(8.34)(273)

V = 2260557 Liters.

If the mass of the gas is 31.1 Kg the volume using the same equation will be 2528896.5 L.

If the temperature is constant but the volume is increases,

P₁V₁(Initially) = P₂V₂(Finally)

Putting values, we get,

1 x 2260557 = 2528896.5 x P₂

P₂ = 0.85 atm

So, the additional pressure will be 0.85 atm.

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An object has an access of 50 electrons what is the charge on the object

Answers

The charge on the object is 8.01 x 10^-18 Coulombs.

Q = Ne

where Q is the charge, N is the number of excess or deficit electrons on the object, and e is the elementary charge, which is approximately 1.602 x 10^-19 Coulombs.

Q = 50 x 1.602 x 10^-19 C/electron

Q = 8.01 x 10^-18 C

A charge is a fundamental property of matter that describes the amount of electric energy that a particle possesses. It is a scalar quantity, meaning it has only magnitude and no direction. The charge can be either positive or negative and is measured in Coulombs (C).

Charged particles can interact with each other through electromagnetic force, which is one of the four fundamental forces of nature. Like charges repel each other while opposite charges attract. Electric fields are generated by charged particles, and the force they exert on other charged particles is proportional to the magnitude of their charges.

A charge is conserved in isolated systems, meaning that the total amount of charge in a closed system cannot be created or destroyed, but can only be transferred from one object to another.

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Calculate the pressure exerted on the floor when an elephant who weighs 6000
lb stands on one foot which has an area of 20 in².

Answers

Answer:

Explanation:

To calculate the pressure exerted on the floor, we need to use the formula:

pressure = force / area

where force is the weight of the elephant and area is the area of the foot in contact with the floor.

First, we need to convert the weight of the elephant from pounds to pounds-force (lbf), which is the force exerted by a mass due to gravity. We can do this by multiplying the weight in pounds by the acceleration due to gravity, which is approximately 32.2 ft/s²:

force = weight x acceleration due to gravity

= 6000 lb x 32.2 ft/s²

= 193200 lbf

Now we can calculate the pressure:

pressure = force / area

= 193200 lbf / 20 in²

≈ 9660 psi

Therefore, the pressure exerted on the floor by the elephant standing on one foot is approximately 9660 pounds per square inch (psi). This is a very high pressure and could cause damage to some types of flooring.

10. You weigh yourself on a scale and find that your weight is about 126 pounds.

a) Multiply your weight in pounds times 4.45. This is your weight in Newtons.

b) What is your mass in kilograms?

c) If you went to the moon, how much would you weigh?

Answers

(a) Your weight in Newtons is 560.7 N.

(b)  Your mass in kilograms is 57.12 kg.

(c) Your weight on the moon is 93.45 N.

What is the measure of your weight in Newtons?

a) To convert your weight from pounds to Newtons, we can use the conversion factor that 1 pound is equal to 4.45 Newtons.

Therefore, your weight in Newtons would be:

126 pounds x 4.45 Newtons/pound = 560.7 Newtons

b) To find your mass in kilograms, we can use the formula:

mass (kg) = weight (N) / acceleration due to gravity (m/s²)

The acceleration due to gravity on Earth is approximately 9.81 m/s². Therefore, your mass in kilograms would be:

mass (kg) = 560.7 N / 9.81 m/s² = 57.12 kg

c) The gravitational force between two objects depends on their masses and the distance between them. The gravitational force on the moon is about 1/6th the gravitational force on Earth.

Therefore, if you went to the moon, your weight would be about 1/6th of what it is on Earth.

Your weight on the moon would be:

126 pounds / 6 = 21 pounds

To convert this to Newtons, we can use the conversion factor:

1 pound = 4.45 Newtons

So your weight on the moon in Newtons would be:

21 pounds x 4.45 Newtons/pound = 93.45 Newtons

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A fan turns a rate 900 rpm. Find the angular speed of any point on one of the fan blades and find the tangential speed of the tip of a blade if the distance from the center to the tip is 20 cm.

a. 15 rad/s & 3 m/s
b. 15 rad/s & 30 m/s
c. 94.2 rad/s & 18.8 m/s
d. 900 rad/s & 180 m/s

Answers

At 900 rpm, a fan spins. angular speed of the any point on a fan blade and tangential speed of a blade's tip if there is a 20 cm gap between the centre and the tip. 9.4 rads and 18.8 m/s.

Correct option is, C.

What is the formula for angular velocity?

A amount or angle rotated (and angular displacement) by a rotating body in a given length of time is known as the angular velocity of the body. The symbol for it is omega (). The formula for angular velocity is rad/s = dtd. Radian per second serves as its SI unit.

What is the SI unit for angular momentum?

The product of a moment of inertia (I) as well as the angular velocity () of the an object in rotation is the angular momentum. A vector quantity is angular momentum. Kg. m2 is the SI unit for angular momentum.

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A string attached to an airborne kite has a eastward horizontal vector of 72 m. The kite also has a northward vertical vector of 150 m. What is the resultant vector of the actual kite string?

Answers

Therefore, the resultant vector of the kite string has a magnitude of 168.5 meters and makes an angle of 65.5 degrees with the horizontal axis.

What is vector?

In physics, a vector is a quantity that has both magnitude and direction. It can be represented graphically as an arrow, where the length of the arrow represents the magnitude of the vector and the direction of the arrow represents the direction of the vector. Vectors can be added, subtracted, and multiplied using mathematical operations, such as the dot product and cross product. These operations allow us to manipulate and analyze vectors mathematically, which is useful for understanding and predicting the behavior of physical systems.

Here,

To find the resultant vector of the kite string, we can use the Pythagorean theorem and trigonometric functions. First, we can find the magnitude of the resultant vector using the Pythagorean theorem:

magnitude = √((72 m)² + (150 m)²)

magnitude = 168.5 m

Next, we can find the angle that the resultant vector makes with the horizontal axis using trigonometric functions.

tan(theta) = opposite / adjacent

tan(theta) = (150 m) / (72 m)

theta = tan⁻¹(150 m / 72 m)

theta = 65.5 degrees

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Learning Goal: To practice Problem-Solving Strategy 27. 1: Magnetic Forces. A particle with mass 1. 81×10−3 kg and a charge of 1. 22×10−8 C has, at a given instant, a velocity v⃗ =(3. 00×104m/s)j^. What are the magnitude and direction of the particle’s acceleration produced by a uniform magnetic field B⃗ =(1. 63T)i^+(0. 980T)j^?

Answers

The magnitude of the particle's acceleration is 0.202 m/s² and its direction is upward (in the positive z-direction).

The force on a moving charged particle in a magnetic field is given as follows:

F= q×v

Therefore, the acceleration of the charged particle is given as follows:

ā = q/m (v×B)

F = [tex]{(1.22*10^-8 C)(3.00*10^4 m/s)j^}*(1.63T)i^ + (0.980T)j^[/tex]

F= (3.66×10^-4 N)k^

F= ma

a=[tex]\frac{F}{m}[/tex] =  [tex]\frac{(3.66*10^-4 N)}{(1.81*10^-3 kg)}[/tex] = 0.202 m/s²

Acceleration is an important concept in physics and is used to describe the behavior of objects in motion. The magnitude of the acceleration is measured in units of meters per second squared (m/s²) in the International System of Units (SI).

An object accelerates when there is a net force acting upon it. This net force can be caused by many factors such as gravity, friction, or applied forces. If the net force is in the same direction as the object's velocity, the object will speed up; if it is in the opposite direction, the object will slow down. If the direction of the force is perpendicular to the direction of the velocity, the object's path will curve.

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A test charge Is Introduced Into the electric field of a charge. It feels a force of 2F where the electric field is 2E. What
would the force on the test charge be where the electric field is 8E?

Answers

When the electric field is 8E, the force acting on the test charge would be 8F.

What power does an electric field exert on a test charge?

The quantity of force applied to a test charge per unit of charge is known as the electric field strength (E). (q). As a result, E = F / q. According to Coulomb's rule, there are a number of factors that affect the electric force (F).

In line with the formula:

Force (F)=Charge x Electric Field

We can use this knowledge to determine the charge on the test charge if it experiences a force of 2F where the electric field is 2E:

2F = q × 2E

q = 2F / 2E

q = F / E

The force acting on the test charge where the electric field is 8E can now be determined using the charge number mentioned above:

Force (F') = Charge (q) x Electric Field (E')

F' = q × E'

F' = (F / E) × 8E

F' = 8F.

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Un bouteille de jus d’orange contient 100 g de sucre. Une cannette de 33 cL de soda contient 34 g de sucre.
1. Quelle est la concentration en sucre dans un verre de 20 cL de jus d’orange ? 2. Quelle est la masse de sucre dans un verre de 20 cL de jus d’orange ?
3. Comparer les concentration en sucre du soda et du jus d’orange.

Answers

Answer:

Does sugar make us sick? For his film Sugar Land , in theaters on Wednesday January 24, director Damon Gameau tested the effects of a high-sugar diet on his body, which was apparently in good health before the start of the experiment. According to a study published by the Harvard School of Public Health, people who consume one to two cans of sugary drinks a day are 26% more likely to develop type 2 diabetes than those who rarely consume them. This disease usually occurs in adults aged 40 and over, and affects more overweight people.

The Openfoodfacts site, which lists food products and their nutritional information, presents more than 1,300 references in its sugary drinks section , with an average sugar intake of 20 g per drink. We have selected 22 drinks, from the best-known sodas to refreshing drinks recently released on the French market, and we have measured the number of sugar cubes of caliber 4 (6 g per piece) that each of them contains. Find out how many pieces are hiding in our cans.

A rectangular block with dimensions 6.0 cm x 8.0 cm x 12.0 cm is made of aluminium of density 2700 kg m¹. Find the maximum pressure it can exert when placed on one of its faces on a horizontal surface.​

Answers

The maximum pressure the rectangular block can exert on a surface when placed on one of its faces on a horizontal surface is 317.71 Pa.

What is the maximum pressure of the block?

The maximum pressure the rectangular block can exert on a surface occurs when it is placed on one of its smallest faces.

To calculate the maximum pressure, we need to find the weight of the block, which is equal to its mass multiplied by the acceleration due to gravity. The mass of the block can be calculated as follows:

mass = density x volume

The volume of the block is:

volume = length x width x height

volume = 6.0 cm x 8.0 cm x 12.0 cm

volume = 576 cm³

Converting to meters:

volume = 0.006 m x 0.008 m x 0.12 m

volume = 5.76 x 10^-5 m³

Therefore, the mass of the block is:

mass = density x volume

mass = 2700 kg/m³ x 5.76 x 10^-5 m³

mass = 0.1555 kg

The weight of the block is:

weight = mass x acceleration due to gravity

weight = 0.1555 kg x 9.81 m/s²

weight = 1.526 N

When the block is placed on one of its smallest faces, the area of contact with the surface is:

area = length x width

area = 6.0 cm x 8.0 cm

area = 48 cm²

Converting to meters:

area = 0.06 m x 0.08 m

area = 0.0048 m²

Therefore, the maximum pressure the block can exert on the surface is:

pressure = weight / area

pressure = 1.526 N / 0.0048 m²

pressure = 317.71 Pa

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The speed of a wave is equal to the frequency multiplied by... what?

Answers

Answer: The wavelength

Explanation:

The speed of a wave is calculated as the product of the frequency times the wavelength.

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what is the speed of an object with a mass of 192 kg when it hits the ground if it is dropped from a height of 13 m

Answers

Answer:

V=15.96M/S OR ~16M/S

Explanation:

SINCE IT IS DROPPED, INITIAL VELOCITY WILL BE ZERO

U = 0

V = ?

S = 13M

ACCELERATION DUE TO GRAVITY

A = 9.8m/s²

USING KINEMATIC FORMULA

[tex]v {}^{2} = u {}^{2} + 2as[/tex]

[tex]v { }^{2} = 0 + 2(9.8)(13) \\ v {}^{2} = 254.8 \\ v = 15.96m/s[/tex]

3. show your calculations for the following quantities for 1.5 v. include formula and show all your work.

Answers

The calculation for the quantity for 1.5 V is simple: 1.5V = 1.5 x 1 = 1.5. The formula for this calculation is V = Voltage x 1, where V is the quantity. The calculation for 1.5V is shown below:

1.5V = 1.5 x 1 = 1.5, By multiplying 1.5 with 1, we get 1.5. This is the calculation for 1.5V.


To understand the calculation of 1.5V better, it is important to first understand the basic unit of electricity - volts. Volts measure the force of electricity in a circuit. It is the amount of electricity that flows through the circuit and is measured in terms of voltage. The higher the voltage, the more electricity is available in the circuit.


To calculate the quantity of electricity for 1.5V, we need to multiply 1.5 with 1. This is the calculation for 1.5V. By multiplying 1.5 with 1, we get 1.5, which is the quantity of electricity for 1.5V.

In conclusion, the calculation for the quantity of electricity for 1.5V is 1.5 x 1 = 1.5. This calculation can be represented using the formula V = Voltage x 1, where V is the quantity.

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A runner with a mass of 90 kg accelerates from 0 to 8 m/s in 4 s. Find the net force on the runner using the alternate form of newton's second law

Answers

Answer: 180 Newtons.

Explanation:

The alternate form of Newton's second law states that force (F) is equal to mass (m) multiplied by acceleration (a):

F = m x a

In this problem, the mass of the runner (m) is 90 kg, and the acceleration (a) can be found by dividing the change in velocity (8 m/s) by the time interval (4 s):

a = (8 m/s) / (4 s) = 2 m/s^2

Substituting the values into the equation for force:

F = 90 kg x 2 m/s^2

F = 180 N

Therefore, the net force on the runner is 180 Newtons.

Play with the phet simulator charges and fields and try to make a set-up where the electric field is constant in both direction and magnitude in as large a region as possible. Use the probe to check your set-up. Submit a screen shot of your result

Answers

As per the simulation, we can create a setup where the electric field is constant in both direction and magnitude by placing two charges of equal magnitude and opposite sign equidistant from the probe.

To achieve this, I selected two charges of equal magnitude (+10 nC and -10 nC) and placed them on the y-axis at a distance of 2 meters from the origin. The distance between the two charges was also 2 meters. By doing this, the electric field between the two charges was constant and equal in magnitude and opposite in direction, creating a region where the electric field is constant in both direction and magnitude.

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Each of the following diagrams shows a spaceship somewhere along the way between Earth and the Moon (not to scale); the midpoint of the distance is marked to make it easier to see how the locations compare. Assume the spaceship has the same mass throughout the trip (that is, it is not burning any fuel). Rank the five positions of the spaceship from left to right based on the strength of the gravitational force that Earth exerts on the spaceship, from strongest to weakest. The following diagrams are the same as those from Part A. This time, rank the five positions of the spaceship from left to right based on the strength of the gravitational force that the Moon exerts on the spaceship, from strongest to weakest. The following diagrams show five pairs of asteroids, labeled with their relative masses (M) and distances (d) between them. For example, an asteroid with M=2 has twice the mass of one with M=1 and a distance of d= 2 is twice as large as a distance of d = 1. Rank each pair from left to right based on the strength of the gravitational force attracting the asteroids to each other, from strongest to weakest.

Answers

A: The gravity between Earth and the spaceship decreases, B: Gravity obeys the inverse square law, C:   d=2; m=2; m=2,   d=1; m=1; m=2,   d=1; m=1;   m=1,   d=2; m=1; m=2,   d=2; m=1; m=1.

What is the gravitational equivalent of the inverse square law?

According to Newton's inverse square law, the force of gravity acting between any two objects is inversely equal to the square of the distance between their centres. Altering the separation distance (d) results in a modification in the force of gravity acting between the objects.

How did Newton arrive at the inverse square law?

The third law of planetary motion, which states that "the square of the time taken for a planet to orbit the sun is directly proportional to the cube of the semi-major axis of the orbit," is where Newton actually got the idea for his inverse square law.

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Help fast please…………

Answers

The answer is (c) N north-east 76.

What is a vector quantity?

A vector quantity is a physical quantity with magnitude as well as direction. Vector quantities include things like displacement, velocity, acceleration, force, and momentum. A vector is typically represented graphically as an arrow, with the length of the arrow representing the magnitude and the direction of the arrow representing the vector's direction.

To find the vector V, we need to combine its X and Y components. Using the given values:

X component = 44 N east

Y component = 62 N north

We can represent this as a vector V with the notation V = (44 N east) + (62 N north).

To find the magnitude of the resultant R, we can use the formula R = √(Rx² + Ry²), where Rx and Ry are the X and Y components of the resultant vector. In this case:

Rx = 44 N east

Ry = 62 N north

So, R = √((44 N east)² + (62 N north)²) = √(1936 N² + 3844 N²) = √(5780 N²) = 76 N.

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List down the forces you exert from the moment you wake up in the morning to the time you go to sleep. At least five and write or draw in a short bond paper

Answers

Here are at least five forces that people may exert from the moment they wake up in the morning to the time they go to sleep:

Gravitational force: This force is exerted on our bodies from the moment we wake up in the morning, keeping us grounded to the surface of the earth. Muscular force: As we move and perform daily activities, our muscles exert force to lift, carry, push, or pull objects. Frictional force: This force is exerted when we walk or run, helping us grip the ground and move forward. Air resistance force: As we move through the air, our bodies and clothing experience air resistance, which can affect our movement and speed. Electrical force: Our nervous system relies on electrical signals to communicate with our muscles and organs, which help us perform various actions throughout the day. These forces may vary depending on the activities a person engages in throughout their day, but they all play a role in the functioning of our bodies and the world around us.

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Simple Pendulum Shows Uniform or Non uniform Motion. Explain?

Answers

The speed of the bob in a simple pendulum changes every time from A to B. So, its motion can't be a uniform motion. Therefore, the motion of the bob in a simple pendulum is a non-uniform motion.

A simple pendulum is a weight (or bob) suspended from a string or rod, which is free to swing back and forth under the influence of gravity. It is an idealized model used to study the behavior of more complex pendulum systems and has been studied extensively in physics due to its simplicity and ubiquity in everyday life.

The motion of a simple pendulum can be described by a number of variables, including the length of the string, the mass of the bob, the angle at which the pendulum is released, and the amplitude and period of the pendulum's oscillations.

In the absence of friction, the motion of a simple pendulum is governed by the laws of conservation of energy and conservation of momentum.

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Compute the resistance of a 90-cm length of copper wire with a 0. 020 -cm^2 cross-sectional area. ( = 1. 8 x 10-6 ohm-cm)


R = ______ ohms

Answers

The resistance of a 90-cm length of copper wire with a 0. 020 -cm^2 cross-sectional area is  81 ohms.

The resistance of a wire is given by:

R = (rho * L) / A

where rho is the resistivity of the material, L is the length of the wire, and A is the cross-sectional area of the wire.

In this case, we are given that the length of the copper wire is 90 cm, the cross-sectional area is 0.020 cm^2, and the resistivity of copper is 1.8 x 10^-6 ohm-cm.

First, we need to convert the units of length and cross-sectional area to meters and square meters, respectively:

L = 90 cm = 0.9 m

A = 0.020 cm^2 = 2 x 10^-5 m^2

Now, we can substitute these values into the formula for resistance:

R = (rho * L) / A

R = (1.8 x 10^-6 ohm-cm * 0.9 m) / 2 x 10^-5 m^2

R = 81 ohms

Therefore, the resistance of the copper wire is 81 ohms.

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