The wavelength of the radio broadcast is 2.93 meters. The photon energy of the radio broadcast is 6.79 x [tex]10^{26}[/tex] joules.
The wavelength of the radio broadcast can be calculated using the formula:
wavelength = speed of light / frequency
The speed of light in a vacuum is approximately 3.00 x [tex]10^8[/tex] meters per second. We need to convert the frequency from megahertz (MHz) to hertz (Hz):
102.3 MHz = 102.3 x [tex]10^6[/tex] Hz
Plugging in the values, we get:
wavelength = (3.00 x [tex]10^8[/tex]m/s) / (102.3 x [tex]10^6[/tex] Hz)
wavelength = 2.93 meters
Therefore, the wavelength of the radio broadcast is 2.93 meters.
b. The photon energy of the radio broadcast can be calculated using the formula:
energy = Planck's constant x frequency
Planck's constant is approximately 6.63 x [tex]10^{34}[/tex] joule-seconds. Again, we need to convert the frequency from megahertz to hertz:
102.3 MHz = 102.3 x [tex]10^6[/tex] Hz
Plugging in the values, we get:
energy = (6.63 x [tex]10^{34}[/tex] J·s) x (102.3 x [tex]10^6[/tex] Hz)
energy = 6.79 x [tex]10^{26}[/tex] joules
Therefore, the photon energy of the radio broadcast is 6.79 x [tex]10^{26}[/tex]joules.
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Potable water is ____.
A. also known as industrial wastewater
B. also known as irrigation water
C. also known as sewage
D. also known as groundwater
E. fit for drinking
Potable water is fit for drinking. Option E
What is portable water?Potable water is water that is safe for human consumption and considered fit for drinking. It is free from harmful bacteria, viruses, chemicals, and other contaminants that can cause health problems.
Potable water can come from different sources such as groundwater, surface water, or treated wastewater, and it is typically treated and disinfected to ensure its safety before being distributed to consumers.
Portable water isn't known as industrial wastewater, irrigation water, groundwater and sewage.
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after a sci a patient may experience all of the following except: a. spasticity b. resting tremor c. autonomic dysreflexia d. orthostatic hypotension
The right response is resting tremor (option b). A patient may have spasticity, autonomic dysreflexia, and orthostatic hypotension following a spinal cord injury (SCI). SCI is not often linked to resting tremor.
SCI can interfere with the body's ability to communicate with the brain, leading to a variety of physical symptoms. Spasticity, which manifests as stiffness, muscle spasms, and increased muscle tone, is a frequent consequence. Patients with SCI at or above the T6 level may develop autonomic dysreflexia, a potentially fatal illness that is characterised by an abrupt rise in blood pressure. When someone stands up, their blood pressure drops, causing lightheadedness and dizziness. This condition is known as orthostatic hypotension.
While essential tremor, Parkinson's disease, and other neurological illnesses are frequently linked to resting tremor, SCI is not typically one of them.
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The right response is resting tremor (option b). A patient may have spasticity, autonomic dysreflexia, and orthostatic hypotension following a spinal cord injury (SCI). SCI is not often linked to resting tremor.
SCI can interfere with the body's ability to communicate with the brain, leading to a variety of physical symptoms. Spasticity, which manifests as stiffness, muscle spasms, and increased muscle tone, is a frequent consequence. Patients with SCI at or above the T6 level may develop autonomic dysreflexia, a potentially fatal illness that is characterised by an abrupt rise in blood pressure. When someone stands up, their blood pressure drops, causing lightheadedness and dizziness. This condition is known as orthostatic hypotension.
While essential tremor, Parkinson's disease, and other neurological illnesses are frequently linked to resting tremor, SCI is not typically one of them.
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a pendulum is swinging upward and is halfway toward its highest position, as shown, when the string breaks. which of the paths shown best represents the one that the ball would take after the string breaks?
The option A is best representation of the path that the ball would take after the string breaks.
When the string of a pendulum breaks, the ball's path will follow the laws of motion, specifically the law of conservation of energy. As the ball was halfway to its highest position, it had a certain amount of potential energy.
When the string broke, this potential energy would convert to kinetic energy, causing the ball to move in a straight line tangent to the point where the string broke.
Therefore, the path that the ball would take after the string breaks would be a straight line away from the pivot point of the pendulum, as shown in option A. The other paths shown do not follow the laws of motion and do not account for the conservation of energy. Option (A) is the correct answer.
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Note the full question is
A pendulum is swinging upward and is halfway toward its highest position, as shown, when the string breaks. which of the paths shown best represents the one that the ball would take after the string breaks?
A) A
B) B
C) C
D) D
E) E
The melting of methane hydrates on the seafloor can lead to a sharp rise in global temperatures because methane is a powerful greenhouse gas (true or false)
The melting of methane hydrates on the seafloor can lead to a sharp rise in global temperatures because methane is a powerful greenhouse gas. The statement is true.
Methane is a powerful greenhouse gas, with a global warming potential that is estimated to be about 25 times greater than that of carbon dioxide over a 100-year time horizon. Methane hydrates are solid, crystalline compounds that contain a large amount of methane gas trapped within water molecules. These hydrates are stable under certain temperature and pressure conditions, but if they become destabilized, they can release large amounts of methane into the atmosphere.
The melting of methane hydrates on the seafloor is a concern because it has the potential to release vast amounts of methane into the atmosphere, which could significantly contribute to global warming and climate change. This process could be triggered by rising ocean temperatures, changes in ocean currents, or other factors that alter the stability of the hydrates. While the exact extent and impact of this phenomenon are still uncertain, it is an area of active research and concern among climate scientists.
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a wire of length 4.35 m and mass 137 g is under a tension of 125 n. a standing wave has formed which has seven nodes including the endpoints. a. draw the wave pattern b. what is the frequency of this wave? c. which harmonic is it? d. what is the fundamental frequency
The standing wave's fundamental frequency is the frequency of the first harmonic, which has one node and two antinodes, whereas the number of nodes determines the standing wave's harmonic number.
A 4.35 metre long, 137 gramme wire is being pulled at 125 newtons of force. With seven nodes total, including the endpoints, a standing wave has developed.
A collection of dots and dashes can be used to represent the wave pattern. The relationship between wave speed and wavelength is used to compute the standing wave's frequency. The tension in the wire and its linear mass density are used to calculate the wave speed.
The standing wave's fundamental frequency is the frequency of the first harmonic, which has one node and two antinodes, whereas the number of nodes determines the standing wave's harmonic number.
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a merry-go-round accelerates from rest to 0.63 rad/s in 27 s . assuming the merry-go-round is a uniform disk of radius 7.5 m and mass 29000 kg , calculate the net torque required to accelerate it.
The net torque required to accelerate is 28496 Nm.
What is the net torque required to accelerate it?The net torque required to accelerate a uniform disk of radius 7.5 m and mass 29000 kg from rest to 0.63 rad/s in 27 s is needed.
The problem is asking for the net torque required to accelerate a merry-go-round from rest to a final angular velocity of 0.63 rad/s in 27 seconds. The merry-go-round is assumed to be a uniform disk, which means that its mass is evenly distributed across its entire radius. We are also given the radius of the merry-go-round (7.5 m) and its mass (29000 kg).
To solve the problem, we can use the formula:
[tex]τ = Iα[/tex]
where τ is the net torque applied to the merry-go-round, I is its moment of inertia, and α is its angular acceleration. Since the merry-go-round is initially at rest, its initial angular velocity is zero. Using the formula for angular acceleration, we can find that:
[tex]α = Δω/Δt = (0.63 rad/s - 0 rad/s) / 27 s = 0.0233 rad/s^2[/tex]
To find the moment of inertia of the merry-go-round, we can use the formula for the moment of inertia of a uniform disk:
[tex]I = (1/2)mr^2[/tex]
where m is the mass of the disk and r is its radius. Substituting the given values, we get:
[tex]I = (1/2)(29000 kg)(7.5 m)^2 = 1220625 kg m^2[/tex]
Finally, we can use the formula [tex]τ = Iα[/tex] to find the net torque required to accelerate the merry-go-round:
[tex]τ = (1220625 kg m^2)(0.0233 rad/s^2) = 28496 Nm[/tex]
Therefore, the net torque required to accelerate the merry-go-round is 28496 Nm.
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a space station, which has a ringed compartment is rotating with initial velocity 0.10 r a d / s 0.10rad/s and angular acceleration 0.01 r a d / s 2 0.01rad/s 2 . what is the space station's angular velocity after 960 960 seconds?
The space station's, which has a ringed compartment is rotating with initial velocity 0.10rad/s and angular acceleration of 0.01rad/s², angular velocity after 960 seconds is 9.7 rad/s.
To find the space station's angular velocity after 960 seconds, we can use the following equation that relates initial angular velocity, angular acceleration, and time:
Final angular velocity (ωf) = Initial angular velocity (ωi) + (angular acceleration × time)
Given:
Initial angular velocity (ωi) = 0.10 rad/s
Angular acceleration = 0.01 rad/s²
Time = 960 seconds
Now, we can plug these values into the equation:
ωf = 0.10 rad/s + (0.01 rad/s² × 960 s)
ωf = 0.10 rad/s + (9.6 rad/s)
ωf = 9.7 rad/s
So, the space station's angular velocity after 960 seconds is 9.7 rad/s.
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when does a star become a main-sequence star? when the rate of hydrogen fusion within the star's core is high enough to maintain gravitational equilibrium when hydrogen fusion is occurring throughout a star's interior when the protostar assembles from a molecular cloud when a star becomes luminous enough to emit thermal radiation the instant when hydrogen fusion first begins in the star's core
Answer: hope it helps
Explanation:
A protostar becomes a main sequence star when its core temperature exceeds 10 million K. This is the temperature needed for hydrogen fusion to operate efficiently.
although protons repel each other because each one has a positive charge, protons are stable in a nucleus because of group of answer choices the neutrons, which have a counterbalancing negative charge. the strong force. the weak force. the gravitational force. the electrons, which have a counterbalancing negative charge. neutrons getting between protons, separating the protons from each other.
The stability of the nucleus is maintained through the combined effects of the strong force and neutrons.
Although protons repel each other due to their positive charge, they are stable in a nucleus because of the strong force, which is a fundamental force that binds the particles together.
The strong force is the strongest force in nature and overcomes the electromagnetic force that causes the protons to repel each other. Neutrons, which have no charge, also play a significant role in stabilizing the nucleus.
The neutrons act as a buffer between the positively charged protons, separating them from each other and reducing the electrostatic repulsion. Electrons, which have a negative charge, are not involved in stabilizing the nucleus as they are located outside the nucleus in orbitals around the nucleus.
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catching a wave, a 73.2-kg surfer starts with a speed of 1.44 m/s, drops through a height of 1.84 m, and ends with a speed of 8.89 m/s. how much nonconservative work was done on the surfer?
The nonconservative work done on the surfer is 2845.5 J.
We can use the work-energy theorem to solve this problem. The work-energy theorem states that the net work done on an object is equal to its change in kinetic energy. In this case, we can calculate the initial and final kinetic energies of the surfer and find the difference, which will give us the net work done.
The initial kinetic energy of the surfer is:
[tex]K_i = (1/2) * m * v_i^2[/tex]
[tex]K_i = (1/2) * 73.2 kg * (1.44 m/s)^2[/tex]
K_i = 75.7 J
The final kinetic energy of the surfer is:
[tex]K_f = (1/2) * m * v_f^2[/tex]
[tex]K_f = (1/2) * 73.2 kg * (8.89 m/s)^2[/tex]
K_f = 2921.2 J
The change in kinetic energy is:
ΔK = K_f - K_i
ΔK = 2921.2 J - 75.7 J
ΔK = 2845.5 J
According to the work-energy theorem, this change in kinetic energy must be equal to the net work done on the surfer. Therefore, the nonconservative work done on the surfer is:
W_nc = ΔK
W_nc = 2845.5 J
So, the nonconservative work done on the surfer is 2845.5 J.
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what is the typical voltage drop (in volts) across the collector and emitter (vce) of a bjt when in saturation?
The VCE voltage drop in saturation for a typical BJT can be assumed to be between 0.1V and 0.3V.
How VCE voltage drop in saturation for a typical BJT?The voltage drop across the collector and emitter (VCE) of a bipolar junction transistor (BJT) when it is in saturation depends on several factors such as the type of BJT, the collector current, and the biasing conditions.
However, as a general rule of thumb, the VCE voltage drop in saturation for a typical BJT can be assumed to be between 0.1V and 0.3V, depending on the specific characteristics of the transistor. This value may vary based on the operating conditions and the specific transistor used.
It's worth noting that the VCE voltage drop in saturation is typically lower than the voltage drop in the active region, where the BJT behaves as a current amplifier. In the active region, the VCE voltage drop can range from a few tenths of a volt up to several volts, depending on the transistor's characteristics and operating conditions.
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A planet has mass M = 8.00 × 1023 kg. At what distance will the centripetal acceleration of an orbiting space station be equal to the gravitational acceleration on Earth’s surface? (G = 6.67 × 10–11 m3·kg–1·s–1)answer is 2.33 x10^6 m. Can someone show the work on how to get this answer?
To find the distance at which the centripetal acceleration of an orbiting space station around a planet is equal to Earth's gravitational acceleration, we need to set up an equation involving the planet's mass (M), gravitational constant (G), and Earth's gravitational acceleration (g).
Given:
M = 8.00 × 10²³ kg
G = 6.67 × 10^(-11) m³·kg^(-1)·s^(-1)
g = 9.81 m/s² (Earth's gravitational acceleration)
Centripetal acceleration (a_c) is given by the formula:
a_c = (G * M) / r²
where r is the distance from the planet's center.
We want the centripetal acceleration to be equal to Earth's gravitational acceleration, so we can set them equal:
g = (G * M) / r²
Now, we need to solve for r:
r² = (G * M) / g
r² = (6.67 × 10^(-11) m³·kg^(-1)·s^(-1) * 8.00 × 10²³ kg) / 9.81 m/s²
r² ≈ 5.42 × 10¹² m²
Now, take the square root of both sides to find r:
r ≈ 2.33 × 10^6 m
So, at a distance of 2.33 x 10^6 meters from the planet's center, the centripetal acceleration of an orbiting space station will be equal to the gravitational acceleration on Earth's surface.
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The following formula can be used to determine the distance from the planet's centre at which the centripetal acceleration of an orbiting space station equals the gravitational acceleration on Earth's surface:
[tex]r = (GM/g)^(1/3)[/tex]
where the gravitational constant, G, equals 6.67 1011 m3 kg-1 s-1.
M is equal to 8.00 1023 kg (the planet's mass).
Gravitational acceleration on Earth's surface is equal to 9.81 m/s2.
When we change the values, we obtain:
[tex]r = [(6.67 × 10^-11) × (8.00 × 10^23) / 9.81]^(1/3)[/tex]
[tex]r = 2.33 × 10^6 m[/tex]
Therefore, 2.33 x 106 m is the necessary distance.
F = G (m1m2 / r2), where G is the gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between them, can be used to express the gravitational force between two objects. When a planet and a satellite are involved, the centripetal force that holds the satellite in orbit around the planet is produced by the gravitational force. As a result, we may compare the centripetal force to gravity and find r. This results in the formula above, which we can use to calculate the necessary distance.
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5. Explain the law of conservation of energy using a relevant example from every day life.
The law of conservation of energy states that energy is neither created nor destroyed but is transformed from one form to another.
What is law of conservation of energy?The law of conservation of energy is the law that states that energy is neither created nor destroyed but is transformed from one form to another.
Examples of activities of everyday life that shows the conservation of energy include the following:
For loudspeaker, electrical energy is converted into sound energy.For a microphone, sound energy is converted into electrical energy.For a generator, mechanical energy is converted into electrical energy.When fuels are burnt, chemical energy is converted into heat and light energyLearn more about energy here:
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An example of the law of conservation of energy is a roller coaster.
What is the law of conservation of energy?The law of conservation of energy states that energy cannot be created or destroyed, only transferred or transformed from one form to another. This means that the total amount of energy in a closed system remains constant over time.
A roller coaster car gains kinetic energy as it moves down the track, but it also loses potential energy. At the bottom of the track, the car has the most kinetic energy and the least potential energy, while at the top of the track, it has the most potential energy and the least kinetic energy. However, the total amount of energy in the system remains constant.
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18. what do we mean when we say that two light rays striking a screen are in phase with each other? a) when the electric field due to one is a maximum, the electric field due to the other is also a maximum, and this relation is maintained as time passes. b) they are traveling at the same speed. c) they have the same wavelength. d) they alternately reinforce and cancel each other.
The correct option is option a) "When the electric field due to one is a maximum, the electric field due to the other is also a maximum, and this relation is maintained as time passes.".
When we say that two light rays striking a screen are in phase with each other, we mean that their electric fields are synchronized, and the electric field due to one is a maximum when the electric field due to the other is also a maximum, and this relation is maintained as time passes.
This synchronization occurs because they have the same wavelength and are traveling at the same speed.
As a result, they alternately reinforce and cancel each other, creating a pattern of light and dark bands on the screen. Therefore, the correct answer is a) when the electric field due to one is a maximum, the electric field due to the other is also a maximum, and this relation is maintained as time passes.
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A highway curve is banked (inclined) in such a way that a car travelling at a speed of 18.0m/s can round the curve without skidding, in the absence of friction. If the banking angle is 37°, what is the radius of the curve?
In order for a vehicle travelling at 18.0 m/s to negotiate highway bend without sliding, curve must be banked (inclined). The radius of curve approximately 33.1 metres.
What is the formula for the radius of a road curve?The coefficient of side friction is found to be 0.10, and the superelevation at one horizontal curve has been set at 6.0%.the formula for calculating a road curve's radiusFind the shortest curve radius necessary to ensure safe vehicle operation.
speed of the car v = 18.0 m/s
angle of banking of the curve θ = 37°
acceleration due to gravityg = 9.81 m/s²
radius of the curve = r
N = mg * cos(θ).........1
also
N = mv² / r...........2
from equation 1 and 2 we get
mg * cos(θ) = mv² / r
r = v² / (g * cos(θ))
r = (18.0 m/s)² / (9.81 m/s² * cos(37°)) ≈ 33.1 m
Therefore, radius of the curve is approximately 33.1 meters.
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the reason that evaporation is a cooling process is group of answer choices due to conduction and convection. the more energetic molecules escape the liquid. radiation of heat during the process. all of the above none of the above
Evaporation is a cooling process because more energetic molecules escape the liquid, carrying away heat through radiation. Answer: "None of the above".
The release of more energising molecules from the liquid during evaporation causes cooling. The heat energy that these molecules bring with them when they go lowers the liquid's temperature. Not conduction or convection, but heat radiation throughout the operation is mostly to blame for this cooling impact.
Therefore, "none of the above" is the appropriate response. In general, the energy needed to break the intermolecular bonds in the liquid, which lowers the temperature overall, is responsible for the cooling impact of evaporation.
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The most popular grip in tennis is
the western grip
the eastern grip
the double handed grip
the continental grip
Answer:
The answer is Continental Grip
at 2.1 km from the transmitter, the peak electric field of a radio wave is 350 mv/m . what is the peak electric field 10 km from the transmitter?
The peak electric field 10 km from the transmitter is approximately 15.435 mV/m.
To find the peak electric field 10 km from the transmitter, we can use the inverse square law.
This law states that the intensity of a wave (such as the electric field in this case) is inversely proportional to the square of the distance from the source.
Here's a step-by-step explanation:
1. Note the initial distance (d1) and electric field (E1):
d1 = 2.1 km, E1 = 350 mV/m.
2. Convert d1 to meters:
d1 = 2100 m.
3. Note the final distance (d2):
d2 = 10 km.
4. Convert d2 to meters:
d2 = 10,000 m.
5. Use the inverse square law formula:
E2 = E1 * (d1²) / (d2²).
6. Plug in the values:
E2 = 350 * (2100²) / (10,000²).
7. Calculate E2:
E2 ≈ 15.435 mV/m.
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If a student thinks that the calorimeter has tap water in it, but it actually contains salt water (which has a lower specific heat than tap water), then
The calorimeter has tap water in it, but it actually contains salt water (which has a lower specific heat than tap water, then the student may make an error in their calorimetry calculation.
What is a calorimetry ?Calorimetry is the science of measuring the heat of chemical reactions or physical changes, and the study of the relationship between heat, temperature, and energy. It is used to measure the amount of heat energy released or absorbed in a chemical or physical change, and to calculate the enthalpy change of a reaction.
What is a reaction ?Reaction is a process that results in the transformation of one or more substances into different substances. Chemical reactions involve the breaking and formation of chemical bonds between atoms, ions, or molecules, and can be accompanied by the release or absorption of energy in the form of heat, light, or electricity.
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how far from the nut of the guitar must a fret (and your finger) be placed on this string to play g (392 hz )?
To play G note (392 Hz) on a guitar string, place the fret and your finger at a distance of approximately 40.4 cm (or 16 inches) from the nut of the guitar.
The distance that the fret and your finger must be placed from the nut of the guitar is determined by the length of the string that is allowed to vibrate when the string is plucked. The length of the vibrating string determines the frequency of the sound produced by the guitar string.
The distance from the nut of the guitar to the fret that must be placed to play a G note with a frequency of 392 Hz can be calculated using the formula:
[tex]L = (v / 2f) * (n^2 - 1)[/tex]
where L is the length of the string from the nut to the fret, v is the velocity of the wave (which is dependent on the tension and mass per unit length of the string), f is the frequency of the note, and n is the fret number (with n=1 corresponding to the distance from the nut to the first fret).
For a standard guitar tuning and using typical values for the velocity of the wave and string tension, the distance from the nut to the third fret would be approximately 40.4 cm to play a G note with a frequency of 392 Hz.
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How can we tell if a collision is elastic or inelastic?
Answer:
The type of collision, whether elastic or inelastic, can be determined by observing the behavior of the colliding objects before and after the collision. Here are some key characteristics that can help identify whether a collision is elastic or inelastic:
Conservation of Kinetic Energy: In an elastic collision, kinetic energy is conserved, while in an inelastic collision, some of the kinetic energy may be converted into other forms of energy.
Objects' Motion After Collision: In an elastic collision, objects bounce off each other and move independently, while in an inelastic collision, objects may stick together, deform, or move as a single mass.
Restitution Coefficient: In an elastic collision, the restitution coefficient is close to 1, indicating high bounce-back, while in an inelastic collision, the restitution coefficient is less than 1, indicating less bounce-back.
Conservation of Momentum: In both elastic and inelastic collisions, momentum is conserved, but the change in velocity of the objects after the collision can indicate whether the collision is elastic or inelastic.
in an rc circuit what teh range of c needed for the capacitor to be 99.3% charged within 10 ms of turning the voltage source on ?
The range of capacitance needed for the capacitor to be 99.3% charged within 10 ms of turning the voltage source on is greater than or equal to 56.3 times the resistance in ohms.
To calculate the range of capacitance needed for the capacitor to be 99.3% charged within 10 ms of turning the voltage source on in an RC circuit, we can use the following formula:
Vc(t) = Vmax * (1 - e^(-t/RC))
where Vc(t) is the voltage across the capacitor at time t, Vmax is the maximum voltage of the source, e is the mathematical constant approximately equal to 2.718, R is the resistance in ohms, C is the capacitance in farads, and t is the time in seconds.
When the capacitor is 99.3% charged, the voltage across it is 0.993 * Vmax. Substituting this value into the formula and solving for C, we get:
C >= t / (R * ln(1 / (1 - 0.993)))
C >= 10 ms / (R * ln(1 / 0.007))
C >= 56.3 * R
Therefore, the range of capacitance needed for the capacitor to be 99.3% charged within 10 ms of turning the voltage source on is greater than or equal to 56.3 times the resistance in ohms.
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if you comb your hair on a dry day, the comb can become positively charged. can your hair remain neutral? explain. (
When you comb your hair on a dry day, the friction between your hair and the comb can lead to the transfer of electrons from one material to another.
Electrons are negatively charged particles that are present in all materials.
The material that loses electrons becomes positively charged, as it has lost negatively charged particles.
In this case, the comb is likely to become positively charged as it loses electrons to your hair during the combing process.
The material that gains electrons becomes negatively charged, as it has gained negatively charged particles.
In this case, your hair is likely to gain electrons from the comb during the combing process, making it negatively charged.
However, whether or not your hair remains neutral depends on the balance of electrons that are transferred during the process.
If the transfer of electrons is balanced, such that the comb loses an equal number of electrons to the hair and the hair gains an equal number of electrons from the comb, then the hair will remain neutral.
If the transfer of electrons is unbalanced, and the hair gains more electrons than the comb loses, then the hair will become negatively charged.
In practice, it is difficult to achieve a perfectly balanced transfer of electrons, so it is possible that your hair may become slightly negatively charged when you comb it on a dry day.
However, the charge imbalance is likely to be very small and may not be noticeable.
Overall, the process of combing your hair on a dry day can lead to the transfer of electrons between the comb and your hair, resulting in the comb becoming positively charged and your hair becoming slightly negatively charged.
However, whether or not your hair remains neutral depends on the balance of electrons that are transferred during the process.
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what does the technique of interferometry allow?what does the technique of interferometry allow?it allows two or more telescopes to obtain a total light-collecting area much larger than the total light-collecting area of the individual telescopes.it allows us to determine the chemical composition of stars.it allows two or more telescopes to obtain the angular resolution of a single telescope much larger than any of the individual telescopes.it allows the same telescope to make images with both radio waves and visible light.it allows astronomers to make astronomical observations without interference from light pollution.
The technique of interferometry allows two or more telescopes to obtain the angular resolution of a single telescope much larger than any of the individual telescopes.
This is achieved by combining the signals received by the telescopes to create a single image with a higher resolution. Interferometry is especially useful for studying objects with small angular sizes, such as stars and planets.
Additionally, interferometry allows astronomers to make astronomical observations without interference from light pollution, as it can separate the signals from the object being observed from the background light.
However, interferometry does not directly determine the chemical composition of stars, although it can provide information about their temperature and other physical properties.
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if the car rolls down the hill ( with engine off) with negligible friction and air resistance what will its kinetic energy be
Answer:
falling iirc
Explanation:
a 2.99 kg particle has a velocity of (2.95 i hat - 3.97 j) m/s.Find the magnitude and direction of its momentum.
Answer:
P (momentum) = M * V
V = (2.95^2 + 3.97^2)^1/2 = 4.95 m/s
P = 2.99 kg * 4.95 m/s = 14.8 kg-m/sec total momentum
tan θ = Vy / Vx = -3.97 / 2.95 = -1.35
θ = 53.4 deg below positive x-axis
a flat, square coil of 16 turns that has sides of length 16.0 cm is rotating in a magnetic field of strength 0.060 t. if the maximum emf produced in the coil is 28.0 mv, what is the angular velocity of the coil (in rad/s)? (enter the magnitude.)
The angular velocity of the coil is approximately 7.27 rad/s.
The formula for the maximum emf induced in a rotating coil is given by: emf = NABw, where N is the number of turns in the coil, A is the area of the coil, B is the strength of the magnetic field, and w is the angular velocity of the coil.
Solving for w, we get: w = emf/(NAB)
Substituting the given values, we get: w = (28.0 x 10^-3)/(16 x 16 x 16 x 0.060 x 2π) ≈ 7.27 rad/s.
Therefore, the angular velocity of the coil is approximately 7.27 rad/s.
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what is the magnetic field inside a coil with the following conditions: 636 number of turns, 0.487 a of current and a length of 2.12 cms.
The magnetic field inside the coil is 0.036 T.
As the area of the coil increases, the magnetic field strength increases, and as the length of the wire increases, the magnetic field strength decreases. Understanding the factors that affect the magnetic field inside a coil is important in designing and optimizing various devices that use electromagnetic fields, such as transformers, motors, and generators. The magnetic field inside a coil can be calculated using the formula:
B = (μ₀ * n * I * A) / L
where,
μ₀ = permeability of free space = 4π x 10^-7 T m/A
n = number of turns
I = current in amperes
A = area of the coil in square meters
L = length of the coil in meters
Substituting the given values,
B = (4π x 10^-7 T m/A * 636 turns * 0.487 A * (2.12 x 10^-2 m)^2) / (2.12 x 10^-2 m)
B = 0.036 T (Tesla)
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what are reasons that a promontory will be more vulnerable to wave erosion than a bay? multiple select question. waves bend around a promontory and strike it from both sides. larger waves enter into a bay than strike a promontory. a promontory will receive more wave action than a bay. powerful waves focus most of their energy at a promontory.
The reasons that a promontory will be more vulnerable to wave erosion than a bay;- Waves bend around a promontory and strike it from both sides,- Powerful waves focus most of their energy at a promontory and - A promontory will receive more wave action than a bay.
A promontory is more vulnerable to wave erosion than a bay due to the following reasons:
1. Waves bend around a promontory and strike it from both sides: This phenomenon, called wave refraction, concentrates the wave energy on the promontory, making it more prone to erosion.
2. A promontory will receive more wave action than a bay: Bays are generally more sheltered and have a lower exposure to waves, whereas promontories are exposed to the full force of waves, leading to more erosion.
3. Powerful waves focus most of their energy at a promontory: Due to the shape of the coastline, waves tend to focus their energy on the headlands, like promontories, which makes them more vulnerable to erosion compared to bays.
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A loose spiral spring carrying no current is hung from a ceiling. When a switch is thrown so that a current exists in the spring, do the coils move closer together move farther apart not move at all
The coils in the spring will move farther apart when a current is passed through it because of the solenoid effect.
The solenoid effect describes the way a loose spiral spring expands when a current is fed through it. An electric current flows through a coil of wire to create a solenoid, a type of electromagnet. A magnetic field is produced when current passes through the coil, and the magnetic field lines are parallel to the axis of the coil. The amount of current flowing through the coil and the number of wire turns within the coil determines how strong the magnetic field is.
Because a loose spiral spring behaves like a coil of wire, the solenoid effect is seen in this situation. The magnetic field that is created around a spring when a current is sent through it has lines that are parallel to the spring's axis. The interaction between the magnetic field and the spring's current produces a force that pushes the coils apart.
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