Answer:
A) it is not an experiment it is an observational study/analysis
B) i)Foods high in fats and sugar affects IQ (ii)Foods that contain the required classes of food affects IQ positively
Step-by-step explanation:
A) An analysis carried out on 400 children using the data derived from the long term investigation can not be said to be an experiment but an observational analysis this is because the complete data has been provided already from the long term investigation already. hence it can only be observed
B ) i) foods high in fats and sugar affects The IQ of children later in life as seen from the results of the observational study that children whom had processed foods had a significant negative difference in IQ when compared with children who had health-conscious diets
ii) following health conscious diets early in childhood will have a positive effect on one's IQ later in life .
Brainliest for the correct awnser!!! Which of the following is the product of the rational expressions shown below?
Answer:
[tex] \frac{ {x}^{2} - 1 }{ {x}^{2} - 25 } [/tex]Step-by-step explanation:
[tex] \frac{x - 1}{x + 5} \times \frac{x + 1}{x - 5} [/tex]
To multiply the fraction, multiply the numerators and denominators separately
[tex] \frac{(x - 1) \times (x + 1)}{(x + 5) \times (x - 5)} [/tex]
Using [tex] {a}^{2} - {b}^{2} = (a - b)(a + b)[/tex] simplify the product
[tex] = \frac{ {x}^{2} - 1 }{ {x}^{2} - 25 } [/tex]
Hope this helps..
Best regards!!
An entertainment company specifies that its employees must weigh between 40 kgs - 50 kgs. If X is the random variable denoting the weights of employees, X is a __________ random variable.
Answer: Continuous
If X is the random variable denoting the weights of employees, X is a continuous random variable.
Step-by-step explanation:
Given: An entertainment company specifies that its employees must weigh between 40 kgs - 50 kgs.
here weights of the employees vary.
Also, weight is measured not counted , that means weight is a continuous variable.
If X is the random variable denoting the weights of employees, X is a continuous random variable.
The weights of employees, X, is a: continuous random variable.
Facts about Random Continuous VariableA continuous variable is obtained simply through measuring.Examples of continuous variable are: weight of students, distance travelled.A continuous random variable are values given for an interval of numbers.Therefore, the weights of employees, X, is a: continuous random variable.
Learn more about continuous random variable on:
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Mike can stitch 7 shirts in 42 hours
He can stitch 1 shirt in hours, and in 1 hour he can stitch of a shirt
Answer:
He stitched 1 shirt in 6 hours.
He can stitch 1/6 of a shirt in one hour
Step-by-step explanation:
Given Mike can stitch 7 shirts in 42 hours
No. of shirt stitch in one hour = total no of shirt stitch/total time taken
No. of shirt stitch in one hour = 7/42 = 1/6
Thus, he can stitch 1/6 of a shirt in one hour
Time taken to stitch 1 shirt = total time taken by him to stitch 7 shirts/ total no. of shirt stitch(i.e 7) = 42/6 = 6 hours.
Thus, he stitched 1 shirt in 6 hours.
Answer:
He can stitch 1/6 of a shirt in one hour
Step-by-step explanation:
Because he stitched 7 shirts in 42 hours
42/7 = 6
so 6 hours per shirt
In one hour:
1/6
One bag of dog food has 13kg. Vet order dog to eat 683 grams a day. How many bags of dog for will you need to buy for 1yr.
Answer:
20 bags
Step-by-step explanation:
683✖️19=12977
683✖️365=249295
249295/13000=19.17
--> 20 bags
Please help. I’ll mark you as brainliest if correct!
Answer:
y=10000 at rate 0.12 or 12%
x=8500 at rate 0.14 0r 14 %
Step-by-step explanation:
x+y=18500 ⇒ x=18500-y
0.14x+0.12y=2390 ( solve by substitution)
0.14(18500-y)+0.12y=2390
2590-0.14y+0.12y=2390
-0.02y=2390-2590
-0.02y=-200
y=-200/0.02
y=10000 at rate 0.12
x=18500-y
x=18500-10000=8500
x=8500 at rate 0.14
check : 0.14(8500)+0.12(10000)=2390 ( correct)
Answer:
Amount invested at 14% = 8500
Amount invested at 12% = 10000
Step-by-step explanation:
Assume money was invested for one year.
18500 at 14% = 18500*0.14 = 2590
18500 at 12% = 18500*0.12 = 2220
actual interest earned = 2390
Let
x = ratio of money invested at 14%
1-x = ratio of money invested at 12%
Then
18500*x * 0.14 + 18500 * (1-x)*0.12 = 2390
0.14x - 0.12x = 2390/18500-0.12
0.02x = 0.1291892-0.12 = 0.0091892
x = 0.0091892/0.02 = 0.4594595
Amount invested in 14% = 18500 * x = 8500
Amount invested in 12% = 18500 * (1-x) = 10000
Of 10 girls in a class, three have blue eyes. Two of the girls are chosen at random. Find the probability that: (a) both have blue eyes; (c) at least one has blue eyes; (b) neither has blue eyes; (d) exactly one has blue eyes.
Answer:
C.
Step-by-step explanation:
It's the most reasonable answer.
What is the correct slope and y-intercept for the following: y=-3x+8
━━━━━━━☆☆━━━━━━━
▹ Answer
Slope = -3
Y-intercept = 8
▹ Step-by-Step Explanation
y = mx + b
mx represents the slope.
b represents the y intercept.
therefore,
y = -3x + 8
Hope this helps!
CloutAnswers ❁
Brainliest is greatly appreciated!
━━━━━━━☆☆━━━━━━━
Answer:
[tex]\boxed{\mathrm{Slope:}-3 \: \: \: \:\: \mathrm{Y \: intercept:}8}[/tex]
Step-by-step explanation:
The general form of slope-intercept:
[tex]y=mx+b[/tex]
[tex]m:slope\\b:y \: intercept[/tex]
[tex]y=-3x+8[/tex]
[tex]m=-3\\b=8[/tex]
The slope is -3.
The y-intercept is (0, 8) or 8.
What is the vertex of the graph of the function f(x) = x2+8x-2?
Answer:
the answer is (-4,-18)
Answer:
The vertex is at (-4, -18).
Step-by-step explanation:
f(x) = x^2 + 8x - 2
Covert to vertex form:
f(x) = (x + 4)^2 - 16 - 2
f(x) = (x + 4)^2 - 18.
So the
vertex is (-4,18
The center of a circle is at the origin on a coordinate grid. A line with a positive slope intersects the circle at (0,7).
Which statement must be true?
The circle has a radius greater than 7.
The circle has a radius equal to 7.
The slope of the line is equal to 7.
The slope of the line is not equal to 7.
Save and Exit
Next
Submit
Answer:
the radius of the circle =7
Step-by-step explanation:
the function of a circle:(x – h)^2 + (y – k)^2 = r^2
center(0,0) because the center of a circle is at the origin (h,k)
a line intersect at (0,7)
(0-0)^+7-0)^2=r^2
r^2=49 , r=√49
radius r=7
Transformations of exponential functions
Answer:
It's the last one. We know it's to the right because the -8 is in the exponent and also, it's -8 not +8.
6th-grade math help me, please
Answer:
Question (2). Option (D)
Question (3). (a). 56
(b). 84
Step-by-step explanation:
Question (2).
Since, a% of b = [tex]\frac{a}{100}\times b[/tex]
42% of 350 = [tex]\frac{42}{100}\times 350[/tex]
Therefore, Option (d) is the correct option.
Question (3).
Total number of people who attended the music concert = 700
a). Percentage of people who arrived late in the concert = 8%
Therefore, number of people who attended the concert = 8% of 700
= [tex]\frac{8}{100}\times 700[/tex]
= 56
b). Percentage of people who bought the shirt = 12%
Number of people who bought the shirt = 12% of 700
= [tex]\frac{12}{100}\times 700[/tex]
= 84
Which of these descriptions matches the graph?
Jimmy is walking to a friend's house at a constant
rate.
Jimmy is running late, so he starts to run to school
but needs to take breaks.
Jimmy is riding the bus to school at a decreasing
rate.
Jimmy's bus drives at the same speed for parts A
and C.
Answer:
Step-by-step explanation:
121212121211212 its B
Answer:
answer is B
Step-by-step explanation:
4 divided by 54.40
[tex]4 \div 54.40 = [/tex]
Global Airlines operates two types of jet planes: jumbo and ordinary. On jumbo jets, 25% of the passengers are on business while on ordinary jets 30% of the passengers are on business. Of Global's air fleet, 40% of its capacity is provided on jumbo jets. (Hint: The 25% and 30% values are conditional probabilities stated as percentages.) What is the probability a randomly chosen business customer flying with Global is on a jumbo jet?
Answer:
Answer:
The probability is [tex]P(J|B) = 0.36[/tex]
Step-by-step explanation:
B =business
J=jumbo
Or =ordinary
From the question we are told that
The proportion of the passenger on business in the ordinary jet is [tex]P(B| Or) = 0.25[/tex]
The proportion of the passenger on business in the jumbo jet is [tex]P(B|J) = 0.30[/tex]
The proportion of the passenger on jumbo jets is [tex]P(j) = 0.40[/tex]
The proportion of the passenger on ordinary jets is evaluated as
[tex]1 - P(J) = 1- 0.40 = 0.60[/tex]
According to Bayer's theorem the probability a randomly chosen business customer flying with Global is on a jumbo jet is mathematically represented as
[tex]P(J|B) = \frac{P(J) * P(B|J)}{P(J ) * P(B|J) + P(Or ) * P(B|Or)}[/tex]
substituting values
[tex]P(J|B) = \frac{ 0.4 * 0.25}{0.4 * 0.25 + 0.6 * 0.3}[/tex]
[tex]P(J|B) = 0.36[/tex]
Step-by-step explanation:
Which inequality has -12 in its solution set?
A
B
С
D
X+6 <-8
X+42-6
X-3 >-10
X+55-4
ОА
B
D
Answer:
D) [tex]x+5\leq -4[/tex]
Step-by-step explanation:
We solve each of the inequalities
Option A
[tex]x+6<-8\\x<-8-6\\x<-14[/tex]
Option B
[tex]x+4\geq -6[/tex]
[tex]x\geq -6-4\\x\geq-10[/tex]
Option C
[tex]x-3>-10\\x>-10+3\\x>-7[/tex]
Option D
[tex]x+5\leq -4[/tex]
[tex]x\leq -4-5\\x\leq -9[/tex]
Therefore, only option D has -12 in its solution set.
According to the World Health Organization (WHO) Child Growth Standards, the head circumference for boys at birth is normally distributed with a mean of 34.5cm and a standard deviation of 1.3cm. What is the probability that a boy has a head circumference greater than 36.32cm at birth
Answer:
0.081
Step-by-step explanation:
To solve this question, we would use the z score formula
z score = (x-μ)/σ, where
x is the raw score = 36.32cm
μ is the population mean = 34.5 cm
σ is the population standard deviation = 1.3cm
z score = (36.32cm - 34.5cm)/1.3cm
z = 1.4
Using the normal distribution to find the z score for 1.4
P(z = 1.4) = 0.91924
Therefore, the probability that a boy has a head circumference greater than 36.32cm at birth is
P(x>36.32) = 1 - P(z = 1.4)
= 1 - 0.91924
= 0.080757
Approximately ≈ 0.081
A large sample of men, aged 48 was studied for 18 years. For unmarried men, approximately 70% were alive at age 65. For married men 90% were alive at 65%. Is this a sample or population?
Can Someone plz help me with the question??
Answer:
[tex]\boxed{x^2+y^2 = 49}[/tex]
Step-by-step explanation:
First, we'll find the length of the radius using distance formula and the coordinates (0,0) and (7,0)
Distance Formula = [tex]\sqrt{(x2-x1)^2+(y2-y1)^2}[/tex]
R = [tex]\sqrt{(7-0)^2+(0-0)^2}[/tex]
R = [tex]\sqrt{7^2}[/tex]
Radius = 7 units
Now, Equation of circle:
[tex](x-a)^2+(y-b)^2 = R^2[/tex]
Where (a,b) = (0,0) So, a = 0, b = 0 and R = 7 units
=> [tex](x-0)^2+(y-0)^2 = (7)^2[/tex]
=> [tex]x^2+y^2 = 49[/tex]
This is the required equation of the circle.
Answer:
x^2 + y^2 = 49
Step-by-step explanation:
We can write the equation of a circle as
( x-h) ^2 + ( y-k) ^2 = r^2
where ( h,k) is the center and r is the radius
The radius is the distance from the center to a point on the circle
(0,0) to (7,0) is 7 units
so the the radius is 7
( x-0) ^2 + ( y-0) ^2 = 7^2
x^2 + y^2 = 49
Find the least common multiple of $6!$ and $(4!)^2.$
Answer:
The least common multiple of $6!$ and $(4!)^2.$
is 6×4! or 144
For which positive integer values of $k$ does $kx^2+20x+k=0$ have rational solutions? Express your answers separated by commas and in increasing order.d
When you solve this equation using the quadratic formula, you will get [tex]x = \frac{-20\pm \sqrt{400-4k^2}}{2k}[/tex]. The only way for this number to be irrational is for [tex]\sqrt{400-4k^2}[/tex] to be irrational. The square root of any number that is not a perfect square is irrational*, so the solutions of the quadratic are rational if and only if [tex]400-4k^2[/tex] is a perfect square. We can factor out the 4 (which is already a perfect square), which means that [tex]100-k^2[/tex] must be a perfect square. This occurs exactly when k is equal to one of the following:[tex]\sqrt{100},\sqrt{99},\sqrt{96},\sqrt{91},\sqrt{84},\sqrt{75},\sqrt{64},\sqrt{51},\sqrt{36},\sqrt{19}, \sqrt{0}[/tex].
Of these, the only positive integer values of k are: [tex]\sqrt{100}, \sqrt{64}, \sqrt{36}[/tex], or simply 6, 8, and 10.
* This is quite simple to show: Take any rational number, a/b. Without loss of generality, we can assume that a/b is in reduced form, that is, a and b have no common factors. (a/b)^2 is a^2/b^2, and since a and b have no common factors, neither do a^2 and b^2. Therefore, a^2/b^2 cannot be an integer. In the event that a/b is an integer, b would equal 1, and this proof would not hold.
Please help. I’ll mark you as brainliest if correct!
Answer:
The cheap one is 8 while the costly one is 17.5
Step-by-step explanation:
Let the cheaper candle be x
And the costly candle b y
X+y = 25.5.... equation one
2.20x +7.3y = 25.5(5.7)
2.2x + 7.3y = 145.35....equation two
Solving simultaneously
X+y = 25.5
2.2x + 7.3y = 145.35
2.2X+2.2y = 56.1
2.2x + 7.3y = 145.35
5.1y= 89.25
Y= 17.5
X+y = 25.5
X+ 17.5 = 25.5
X= 25.5-17.5
X= 8
The cheap one is 8 while the costly one is 17.5
In circle O, radius OQ measures 9 inches and arc PQ measures 6π inches. Circle O is shown. Line segments P O and Q O are radii with length of 9 inches. Angle P O Q is theta. What is the measure, in radians, of central angle POQ?
Answer:
2π/3 radStep-by-step explanation:
To get theta, we will apply the formula for calculating the length of an arc as shown;
Length of an arc = theta/360 * 2πr
theta is the central angle (required)
r is the radius of the circle
Given r = 9 inches and length of the arc PQ = 6π in
Substituting this given values into the formula to get the central angle theta;
6π = theta/360 * 2πr
Dividing both sides by 2πr
theta/360 = 6π/2πr
theta/360 = 3/r
theta/360 = 3/9
theta/360 = 1/3
cross multiplying;
3*theta = 360
theta = 360/3
theta = 120°
Since 180° = π rad
120° = x
x = 120π/180
x = 2π/3 rad
Hence the measure of the central angle in radians is 2π/3 rad
For the following information, determine whether a normal sampling distribution can be used, where p is the population proportion, is the level of significance, p is the sample proportion, and n is the sample size.
Claim: p >=0.28; α:0.08. Sample statistics: p=0.20, n= 180
Required:
If a normal sampling distribution can be used, decide whether to reject or fail to reject the null hypothesis and interpret the decision.
Answer:
The Central Limit Theorem says that if the sample size is more than 30, the data follows a normal sampling distribution. Since the sample size is 180, and that is more than 30, a Normal sampling distribution can be used.
Since a normal sampling distribution can be used, we should FAIL TO REJECT the null hypothesis because p = 0.20, which is more than the significance level of α = 0.08. There is NOT sufficient evidence to suggest that the alternative hypothesis is true.
Hope this helps!
Use the Quadratic Formula to solve the equation ? x^2-2x=-9
Answer:
x=(2+ √-32)/2 or x=(2- √-32)/2
Step-by-step explanation:
x^2 - 2x = -9
x^2 - 2x + 9 =0
x = 2± (√(-2)^2 - 4*1*9)/2*1
Use the quadratic formula in the expression using a=1, b= -2, c=9
x = 2±√4-36 /2
x = 2+√4-36 or x = 2 - √4 - 32 /2
x = (2+√-32) /2 or x=( 2 - √-32 )/2
The solution for the given quadratic equation are (2+i5.7)/2 or (2-i5.7)/2.
The given quadratic equation is x²-2x=-9.
What is the quadratic formula?Quadratic formula is the simplest way to find the roots of a quadratic equation.
The roots of a quadratic equation ax² + bx + c = 0 are given by x = [-b ± √(b² - 4ac)]/2a.
By comparing x²-2x+9=0 with ax² + bx + c = 0, we get a=1, b=-2 and c=9
Substitute a=1, b=-2 and c=9 in the quadratic formula, we get
x = [2±√(-2)²-4×1×9)]/2×1
= [2±√4-36]/2
= (2±i5.7)/2
x = (2+i5.7)/2 or (2-i5.7)/2
Therefore, the solution for the given quadratic equation are (2+i5.7)/2 or (2-i5.7)/2.
To learn more about the quadratic formula visit:
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Please help. I’ll mark you as brainliest if correct
Answer:
1,-1,3,4
1,6,-2,-4
-4,6,-6,6
Step-by-step explanation:
I believe you just put in the values into the box. Watch the video to see how they did it to make sure it looks like how I did it.
Solve.
1/3-6<24
{s | s<6}
O {S | s < 10}
O {S | s < 54}
O {S | s < 90}
Answer:
The answer is:
The fourth option,
{s | s <90}
Step-by-step explanation:
yes
Answer:
[tex]\boxed{s|s<90}[/tex]
Step-by-step explanation:
1/3s-6<24
Add 6 on both sides.
1/3s<30
Multiply both sides by 3.
s<90
a student showed the steps below while solving the equation 14=log5(2x-3) by graphing. which step did the student make the 1sr error
Answer:
[tex]x= \frac{5^{14}+3}{2}[/tex]
Step-by-step explanation:
The correct steps to solve the equation are:
[tex]14=log_5(2x-5)[/tex]
[tex]5^{14}=5^{log_5(2x-3)}[/tex]
Because [tex]a^{log_am}=m[/tex]
So, solving we get:
[tex]5^{14}=2x-3[/tex]
Sum 3 on every side:
[tex]5^{14}+3=2x-3+3\\5^{14}+3=2x[/tex]
Dividing by 2 into both sides:
[tex]\frac{5^{14}+3}{2}=\frac{2x}{2}\\\frac{5^{14}+3}{2}=x[/tex]
So, the answer is [tex]x= \frac{5^{14}+3}{2}[/tex]
Answer: Step 2
Step-by-step explanation:
This is correct according to Edge 2021
Find the number of four-digit numbers which are not divisible by 4?
Answer: without trying each calculation individually, 6750 4-digit numbers are not divisible by 4
Step-by-step explanation: From 1000 to 9999 there are 9000 4-digit numbers 9999 - 999 = 9000.
Eliminate all the odd numbers 9000/2 = 4500
Eliminate the even numbers divisible by 2 but not by 4. 4500/2 = 2250
9000 - 2250 = 6750.
The temperature is 58° F. It gets warmer by h degrees and reaches to 65° F. Find h.
Answer:
h = 7 degrees
Step-by-step explanation:
To find h, we know that it is positive because it increases in value, not decreases:
h = 65 - 58
h = 7
Answer:
h = 7°F
Step-by-step explanation:
58 + h = 65
h = 65 - 58
h = 7
Check:
68 + 7 = 65
A rectangular garden is 20 ft longer than it is wide. Its area is 3500 ft?. What are its dimensions?
Its width equals
Preview
and its length equals
Answer:
width of the garden is 50 ft and the length is 70 ft
Step-by-step explanation:
Solution:-
- We will denote the width and and the length of the rectangular garden as:
Width: x
Length: x + 20
- We are given the area ( A ) of the garden is 3500 ft^2. We are to determine for what dimensions is the area A = 3500 ft^2.
- Recall that the area ( A ) of a rectangle is the product of length and width as follows:
A = Length * width
A = x*( x + 20 )
3500 = x^2 + 20x
x^2 + 20x - 3500 = 0
- Use the quadratic formula to determine the value of ( x ):
[tex]x = \frac{-b +/- \sqrt{b^2 - 4ac} }{2a} \\\\x = \frac{-20 +/- \sqrt{20^2 - 4*-3500} }{2}\\\\x = \frac{-20 +/- 120 }{2} = -10 +/- 60\\\\x = -70 , 50[/tex]
- Ignore the negative value of ( - 70 ft ). Physical impractical to have a negative value. Hence, the width of the garden is 50 ft and the length is 70 ft