Given: A recent survey of 2,400 people found that out of all 2,400 respondents, only 418 clip coupons.
Find:(a)the ratio of those who clip coupons to the total as a decimal rounded to the thousandths place.
(b) answer in a sentence explaining the meaning.
Explanation: (a) the ratio of those clip coupons to the total is
[tex]\begin{gathered} \frac{418}{2400} \\ =0.174 \end{gathered}[/tex](b) ratio is a relation between two numbera which shows how much better one quantity is than another.
in this we have to find ratio who clip coupons to the total.
Find the perimeter of a triangle with vertices of (-8,-1),(4,-1), and (4,4). Write exact answer don't round.
The given points are:
the distance between A and B is 5
the distance from C to B is 12
then using the pythagorean theorem we obtain that the distance between A and C is:
[tex]undefined[/tex]if I say 5/8 in in Magna to take to make a desk magnet how many deaths magnets can be made 12 and 1/2 of a magnet tape
if I say 5/8 in in Magna to take to make a desk magnet
i.e 5/8 magnet require= to make 1 desk magnet
Thus,
[tex]\begin{gathered} \text{ 1 magnet we make =}\frac{1}{\frac{5}{8}}\text{ desk magnet} \\ \text{ 1 magnet can make =}\frac{8}{5}\text{ desk magnet} \end{gathered}[/tex]We need to find the number of desk magnet can make with the help of 12 1/2 magnet tape
[tex]\begin{gathered} \text{ Since,} \\ \text{ With the help of 1 magnet tap we can make=}\frac{8}{5}Desk\text{ magnet} \\ \text{ then with the help of 12}\frac{1}{2}\text{ magnet tape we can make=12}\frac{1}{2}\times\frac{8}{5}\text{ Desk magnet} \\ \text{ Simplify : 12}\frac{1}{2}\times\frac{8}{5} \\ \text{12}\frac{1}{2}\times\frac{8}{5}=\frac{(12\times2)+1}{2}\times\frac{8}{5} \\ \text{12}\frac{1}{2}\times\frac{8}{5}=\frac{25}{2}\times\frac{8}{5} \\ \text{12}\frac{1}{2}\times\frac{8}{5}=5\times4 \\ \text{12}\frac{1}{2}\times\frac{8}{5}=20 \\ \text{ Thus, } \\ \text{with the help of 12}\frac{1}{2}\text{ magnet tape we can make=20 Desk magnet} \end{gathered}[/tex]If a 48-pound beef round is roasted, and 9 pounds are lost through shrinkage, what percent of the round is lost through shrinkage?
we can write an equation
you multiply the total pounds by the percent lost to find the lost pounds
then
[tex]48\times x=9[/tex]where x is the percent lost, then solve for x
[tex]\begin{gathered} x=\frac{9}{48} \\ \\ x=\frac{3}{16}=0.1875 \end{gathered}[/tex]multiply by 100 to find on percent form
[tex]0.1875\times100=18.75[/tex]Percent is 18.75%
I need help with part C and with the following question: Does the volume support the answer you gave in part b?
The volume of the Joes's cylindrical cups can be determined as,
[tex]\begin{gathered} V=\pi r^2h^{} \\ =\pi\times(\frac{5\text{ in}}{2})^2\times6\text{ in} \\ =117.809in^3 \end{gathered}[/tex]Thus, the required value of volume of the cylindrical cups is 117.81 cubic inch.
Simplify the following expression.(3x-5)-4(x-2)
Given the expression:
[tex]\mleft(3x-5\mright)-4\mleft(x-2\mright)[/tex]You need to remember the following:
- The Sign Rules for Multiplication:
[tex]\begin{gathered} +\cdot+=+ \\ -\cdot-=+ \\ -\cdot+=- \\ +\cdot-=- \end{gathered}[/tex]- The Distributive Property:
[tex]\begin{gathered} a(b+c)=ab+ac \\ \\ a(b-c)=ab-ac \end{gathered}[/tex]Then, the steps to simplify the expression are:
1. Apply the Distributive Property:
[tex]\begin{gathered} =(3x-5)-(4)(x)+(4)(2) \\ =3x-5-4x+8 \end{gathered}[/tex]2. Finally, add the like terms:
[tex]=-x+3[/tex]Therefore, the answer is:
[tex]-x+3[/tex]A silo is a building shaped like a cylinder used to store grain. The diameter of a particular silo is 6.5 meters, and the height of the silo is 12 meters. 6.5 m 12 m Which equation can be used to find the volume of this sito in cubic meters? CAVE (3.25 (12) V = *(6.5) (12) Cy=+(12)? 3.25) DV=(6) (6.5)
ANSWER
A) V = π (3.25)² (12)
EXPLANATION
The volume of a cylinder is:
[tex]V=B\cdot h[/tex]Where B is the area of the base and h is the heigth. The area of the base is:
[tex]B=\pi r^2[/tex]r is the radius of the base. If we replace this into the expression for the volume we get:
[tex]V=\pi r^2h[/tex]In this problem the heigth of the cylinder is 12m. The diameter is 6.5m and the radius - which is half the diameter - is 3.25m. Then the volume is:
[tex]V=\pi(3.25)^2(12)[/tex]Josephine is looking for a new part-time job as a plumber. She responds to a classified ad for a position that pays $44.5K. What would be her semimonthly salary?
In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data:
annual salary = $44.5K
semimonthly salary = ?
Step 02:
semimonthly salary:
semimonthly salary = annual salary / 24
= $44500 / 24 = $1854.167
The answer is:
semimonthly salary = $1854.167
How do I solve interval notation and graph it? l3y+7I < 10[tex] |3y + 7| \ \textless \ 10[/tex]
We have the next inequality:
[tex]l3y+7l=10[/tex]Apply the absolute value properties:
[tex]\text{lal}=0\text{ so }-aWhich means :[tex]-10<3y+7<10[/tex]3y+7>-10 and 3y+7<10
Solve the inequalities:
for 3y+7>-10
3y>-10-7
y>-17/3
Now, for 3y+7<10
3y<10-7
3y< 3
y< 3/3
y< 1
So the solution is -17/3 < y < 1
Interval notation (-17/3, 1)
Now, the graph:
x can take any real value
y has the interval (-17/3, 1)
-17/3 = -5.6
on y -axis -5.6 and 1 are asymptotes.
Find the product of (-5-4i) and its conjugate.product =
The complex expression is given
-5-4i.
ExplanationTo determine the conjugate of the complex number.
[tex]a+bi=a-bi[/tex]Then the conjugate of -5-4i is
[tex]-5+4i[/tex]The product is
[tex]\begin{gathered} (-5-4i)(-5+4i)=25-20i+20i-16i^2 \\ 25-20i+20i-16i^2=25+16=41 \end{gathered}[/tex]AnswerHence the conjugate is
[tex]-5+4i[/tex]The product is 41.
help with algebra 1 chapter 12 chapter wrap up Find the indicated outputs for these functions. 3. f ( x ) = 3x - 4 ; find f ( 2 ) , f ( 0 ) , and f ( -1 )
Given the function:
[tex]f(x)=3x-4[/tex]• You need to substitute this value of "x" into the function and then evaluate:
[tex]x=2[/tex]In order to find:
[tex]f(2)[/tex]Then, you get:
[tex]f(2)=3(2)-4=6-4=2[/tex]• Substitute this value of "x" into the function and then evaluate:
[tex]x=0[/tex]In order to find:
[tex]f(0)[/tex]You get:
[tex]f(0)=3(0)-4=-4[/tex]• Now you need to substitute this value of "x" into the function and then evaluate:
[tex]x=-1[/tex]In order to find:
[tex]f(-1)[/tex]You need to remember the Sign Rules for Multiplication:
[tex]\begin{gathered} (+)(+)=+ \\ (-)(-)=+ \\ (-)(+)=- \\ (+)(-)=- \end{gathered}[/tex]Then, you get:
[tex]f(-1)=3(-1)-4=-3-4=-7[/tex]Hence, the answer is:
[tex]\begin{gathered} f(2)=2 \\ f(0)=-4 \\ f(-1)=-7 \end{gathered}[/tex]Can you please help me with this question thank you
The correct option is B
16% = 4/25
Explanation:Given 16%, to convert this to fraction, we do the folowing:
16/100 = 8/50 = 4/25
In the diagram, OC AD. If m
It is given that:
[tex]m\angle\text{AOB}=(3x)^{\circ},m\angle BOC=(5x-6)^{\circ}[/tex][tex]\text{By the geometry of the figure since }OC\perp AD,\angle AOC=90^{\circ}\text{ }[/tex]Therefore it follows:
[tex]\begin{gathered} \angle AOC=\angle AOB+\angle BOC \\ 90=3x+5x-6 \\ 96=8x \\ x=12 \end{gathered}[/tex]Hence the value of x is 12 units.
Option B is correct.
solve the order of operations. The number 1 is done for you.2. 3+2x (4²+ 1 ) =3. 5² + 6 x 2 =4. 24 – (8 ÷ 2)² =
Given:
[tex]\begin{gathered} 3+2\times(4^2+1) \\ 5^2+6\times2 \\ 24-(8\div2)^2 \end{gathered}[/tex]Required:
To solve the given equation.
Explanation:
Consider
[tex]\begin{gathered} 3+2\times(4^2+1) \\ =3+2\times(16+1) \\ =3+2\times(17) \\ =3+34 \\ =37 \end{gathered}[/tex][tex]\begin{gathered} 5^2+6\times2 \\ =25+12 \\ =37 \end{gathered}[/tex][tex]\begin{gathered} 24-(8\div2)^2 \\ =24-4^2 \\ =24-16 \\ =8 \end{gathered}[/tex]Final Answer:
[tex]\begin{gathered} 3+2(4^2+1)=37 \\ 5^2+6\times2=37 \\ 24-(\frac{8}{2})^2=8 \end{gathered}[/tex]A ball is dropped from a height of a little over 5 feet, and the height is measured at small intervals. The table below shows the results.Time (seconds) Height (feet)0.00 5.2350.04 5.1600.08 5.0270.12 4.8510.16 4.6310.20 4.3570.24 4.0300.28 3.6550.32 3.2340.36 2.7690.40 2.2580.44 1.635(a) Use a graphing calculator or spreadsheet program to find a quadratic model that best fits this data, using time as t and height as Pt. Round each coefficient to two decimal places.Pt=(b) Based on this model, what height is expected after 0.30 seconds? Round your answer to two decimal places.feet(c) What height is expected after 0.52 seconds? Round your answer to two decimal places.feet(d) Which of the two previous predictions is likely to be more reliable?0.52 seconds0.30 seconds(e) When do you expect the height of the ball to be 1 foot? Round your answer to the nearest hundredth of a second.After seconds
a)
From the graph, the coefficient of a, b, and c are:
a = -15.19
b = -1.39
c = 5.24
[tex]\begin{gathered} \text{The quadratic model is} \\ h=-15.19t^2\text{ - 1.39t + 5.24} \end{gathered}[/tex]b)
To find the height after 0.30 seconds, you will substitute t = 0.30
[tex]\begin{gathered} h\text{ = -15.19 }\times0.3^2\text{ - 1.39 }\times\text{ 0.3 + 5.24} \\ h\text{ = -1.3671 - 0.417 + 5.24} \\ h\text{ = 3.4559} \\ h\text{ = 3.46 feet} \end{gathered}[/tex]c)
To find the height after 0.52 seconds, you will substitute t = 0.52
[tex]\begin{gathered} h\text{ = -15.19 }\times0.52^2\text{ - 1.39 }\times\text{ 0.52 + 5.24} \\ h\text{ = -4.11 - 0.723 + 5.24} \\ \text{h = 0.417} \end{gathered}[/tex]d)
0.30 seconds is more reliable.
e)
[tex]\begin{gathered} h=1foot_{} \\ h=-15.19t^2\text{ }-\text{ 1.39t + 5.24} \\ 1=-15.19t^2\text{ - 1.39t + 5.24} \\ 15.19t^2\text{ + 1.39t + 1 - 5.24 = 0} \\ 15.19t^2\text{ + 1.39t - 4.24 = 0} \end{gathered}[/tex]t = 0.48455
Final answer
t = 0.48 seconds
Solve for x.X490X =degrees
X = 2(49) ( angle subtended by an arc at the center of a circle is twice that subtended at the circumference of a circle )
X = 98 degrees
The answer is 98 degrees
Write a system of equations to describe the situation below, solve using any method, and fill in the blanks.Mr. Larsen and Ms. Ortega are teaching their classes how to write in cursive. Mr. Larsen has already taught his class 5 letters. The students in Ms. Ortega's class, who started the unit later, currently know how to write 12 letters. Mr. Larsen plans to teach his class 2 new letters per week, and Ms. Ortega intends to cover 1 new letter per week. Eventually, the students in both classes will know how to write the same number of letters. How long will that take? How many letters will the students know?
Given:
5 letters were completed in Mr. Larsen's class.
12 letters were completed in Ms. Ortega's class.
Mr. Larsen plans to teach his class 2 new letters per week, and Ms. Ortega intends to cover 1 new letter per week.
Mr. LarsenLet x be the number of letters learned in Mr. Larsen's class.
Let y be the number of letters learned in Ms. Ortega's class.
Let t be the number of weeks.
[tex]x=5+2t[/tex][tex]y=12+(1)t[/tex]
The same number of letters learned after t weeks. So x=y.
Set x=y, to find the value for t.
[tex]5+2t=12+t[/tex]Subtracting t from both sides, we get
[tex]5+2t-t=12+t-t[/tex][tex]5+t=12[/tex]Subtracting 5 from both sides, we get
[tex]5+t-5=12-5[/tex][tex]t=7\text{ w}eeks[/tex]After 7 weeks the students in both classes will know how to write the same number of letters
Substitute t=7 in x to find the number of letters.
[tex]x=5+2\times7[/tex][tex]x=5+14[/tex][tex]x=19\text{ letters}[/tex]The students know 19 letters.
Hence after 7 weeks, the students in both classes will know how to write 19 letters.
which one has the highest value? 1/8 1/9 8 9
A fraction has the following form:
[tex]\frac{a}{b}[/tex]Where "a" is the numerator and "b" is the denominator. Both are Integers.
In order to write a fraction as a decimal number, you must divide the numerator by the denominator. So, you have that the given fractions expressed as decimal numbers, are:
[tex]\begin{gathered} \frac{1}{8}=0.125 \\ \\ \frac{1}{9}=0.111 \end{gathered}[/tex]Knowing this, you
Julia is saving money each week. At the end of the first week, she saves $10. At the end of the second week, she has a total of $25.She continues saving 515 each week. Which of the following is a correct way of mathematically describing the sequence? (1 point)f(1) = 10. f(x) = f(n-1) + 15. for > 1of(1) = 10. f(n) = f(n-1) + 10. for n > 1fin) = 10 + 15fim - 10 - 10
For this problem we know that at the end of the first week she saves 10 so then we have:
[tex]f(1)=10[/tex]Then at the end of the second week the total is 25 so we have:
[tex]f(2)=10+15=25[/tex]She continues saving $15 each week. So then the best way to represent this situation is:
[tex]f(1)=10,f(n)=f(n-1)+15[/tex]And the best option would be:
f(1)=10, f(n) = f(n-1)+15, n>1
write -3x+5+7x to the power of 2 In standard form
The given expression is-
[tex]-3x+5+7x^2[/tex]This expression has a grade of 2, its constant is 5 (since it doesn't have any variable), and the standard form of this expression would be
[tex]7x^2-3x+5[/tex]Remember that, standard form to organize the expression from greatest exponent to least.
Select the exact value of x that can be approximated to x≈0.41 when rounded to the nearest hundredth.
In order to find the correct option, let's calculate the value of x in each option and round it to the nearest hundredth:
[tex]\begin{gathered} x=\frac{log94}{5log9} \\ x=\frac{1.9731278}{5*0.9542425} \\ x=\frac{1.9731278}{4.7712125} \\ x=0.41 \\ \\ x=\frac{log65}{12log14} \\ x=\frac{1.8129}{12*1.146128} \\ x=\frac{1.8129}{13.753536} \\ x=0.13 \\ \\ x=\frac{log450}{22} \\ x=\frac{2.6532}{22} \\ x=0.12 \\ \\ x=\frac{3log66}{log7} \\ x=\frac{3*1.81954}{0.8451} \\ x=\frac{5.45862}{0.8451} \\ x=6.46 \end{gathered}[/tex]Therefore the correct option is the first one.
Find the area of the right triangle. Be sure to include the correct unit in your answer. 25 cm 15 cm
The area of the traingle can be represented with the following formular
[tex]\begin{gathered} \text{area of triangle = }\frac{1}{2}\times b\times h \\ \text{where} \\ b=\text{base of triangle} \\ h=\text{height of the triangle} \\ \text{if } \\ h=15\text{ cm} \\ b=25\text{ cm } \\ \text{therefore} \\ \text{area = }\frac{1}{2}\times25\times15=\frac{375}{2}=187.5cm^2 \end{gathered}[/tex]Name Date Core Writing Linear Equations 1. An airplane 30,000 feet above the ground begins descending at the rate of 2000 feet per minute. Assume the plane continues at the same rate of descant. The plane's helght and minutes above the ground are related to each other Identify the variables in this situation: xa minutes ya height What is the glven Information in this problem (find all that apply)? y-intercept 30.000 slope2000, one point a second point ) 3. Write an equation to model the situation. y2000x130.000 b. Use your equation to find the altitude of the plane after S minutes, Suppose you receive $100 for a graduation present, and you deposit it in a savings account. Then each week thereafter, you add $5 ta the account but no interest is earned. The amount in the account is a function of the number of weeks that have passed. you Identify the variables in this situation: x- What is the given information in this problem (And all that apply)? pintercept slope _- one point ) a second point ) a Find an equation for the amounty you have afterx weeks,
1) So writing in terms of x, we have: y=30,000-2000x or f(x) = -2000x +30,000
Hence, the y intercept is the point 30,000 ( 0, 30000) and the slope is -2000 for it is a decreasing function.
2) Identifying the variables we have, setting a table
I don’t know this and I am really confused right now can some one please help me
Answer:
The arc length is;
[tex]\frac{5\pi}{3}\text{ in}[/tex]Explanation:
Given that the central angle of the arc is;
[tex]\theta=\frac{\pi}{6}[/tex]Recall that the formula for the length of an arc is;
[tex]\begin{gathered} l=\frac{\theta}{360}\times2\pi r=\frac{\theta}{2\pi}\times2\pi r=\theta r \\ \theta\text{ (in rad)} \end{gathered}[/tex]substituting the central angle and radius;
[tex]\begin{gathered} l=\theta r=\frac{\pi}{6}\times10 \\ l=\frac{5}{3}\pi\text{ in} \end{gathered}[/tex]Therefore, the arc length is;
[tex]\frac{5\pi}{3}\text{ in}[/tex]For the polynomial below, 1 is a zero of multiplicity twog(x) = x^4+ 4x^3 +47x^2 - 110x+ 58 Express g (x) as a product of factors. g(x) = ?
Given:
The given polynomial is
[tex]g(x)=x^4+4x^3+47x^2-110x+58[/tex]1 is a zero of multiplicity two.
Required:
We have to express g(x) as a product of linear factors.
Explanation:
Since 1 is a zero of multiplicity two,
[tex](x-1)^2[/tex]is a factor of g(x).
So we can divide g(x) by
[tex](x-1)^2=x^2-2x+1.[/tex][tex]g(x)=\text{ \_\_\_}(x^2-2x+1)+\text{ \_\_\_}(x^2-2x+1)+\text{ \_\_\_\_}[/tex]We will fill the blanks with suitable terms.
[tex]\begin{gathered} g(x)=x^2(x-2x^2-1)+6x(x-2x^2-1)+58(x-2x^2-1) \\ g(x)=(x-2x^2-1)(x^2+6x+58) \end{gathered}[/tex]Final answer:
Hence the final answer is
[tex]g(x)=(x-2x^{2}-1)(x^{2}+6x+58)[/tex]find the values of the variables x , y and z in the parallelogram
Answer:
The image below will be used to explain the question
From the image above,
We will have the following relationships
[tex]\begin{gathered} \angle\text{BCD}=\angle CDF(alternate\text{ angles ar equal)} \\ \angle\text{BCD}=35^0 \\ \angle CDF=x \end{gathered}[/tex]With the relation above, we can conclude that
[tex]x=33^0[/tex]Hence,
The value of x = 33°
Step 2:
The following relation below will be used to calculate the value of y
[tex]\begin{gathered} \angle CBD=\angle BDE(alternate\text{ angles are equal)} \\ \angle CBD=109^0 \\ \end{gathered}[/tex]By applying this, we will conclude that
[tex]\angle BDE=109^0[/tex]The relation below will be helpful to get the exact value of y
[tex]\begin{gathered} \angle BDE+\angle CDF+\angle CDB=180^0(SUM\text{ OF ANGLES ON A STRAIGHT LINE)} \\ \angle BDE=109^0 \\ \angle CDF=x=33^0 \\ \angle CDB=y \end{gathered}[/tex]By substituting the values, we will have
[tex]\begin{gathered} \angle BDE+\angle CDF+\angle CDB=180^0 \\ 109^0+33+y=1180^0 \\ 142^2+y=180^0 \\ y=180-142 \\ y=38^0 \end{gathered}[/tex]Hence,
The value of y= 38°
The relation below will be used to figure out the value of z
[tex]\begin{gathered} \angle BDE=\angle CFD(correspond\in g\text{ angles are equal)} \\ \angle BDE=109^0 \\ \angle CFD=z \\ z=109^0 \end{gathered}[/tex]Hence,
the value of z= 109°
Simplify the expression -16(a-b)
Answer:
[tex]\text{-16a +16b}[/tex]Explanation:
Here, we want to simplify the given expression
To do this, we have to multiply the value outside the parentheses by each of the values inside it
Mathematically, we have this as:
[tex]-16(a-b)\text{ = (-16}\times a)\text{ -(-16}\times b)\text{ = -16a +16b}[/tex]solve the system of linear equations by substitutionb) 3x - 4y = 102y + 4x = 6
3x - 4y = 10 (eq. 1)
2y + 4x = 6 (eq. 2)
Isolating y from the second equation:
[tex]\begin{gathered} 2y=6-4x \\ y=\frac{6-4x}{2} \\ y=\frac{6}{2}-\frac{4x}{2} \\ y=3-2x \end{gathered}[/tex]Substituting this equation into the first equation:
3x - 4(3 - 2x) = 10
3x - 4(3) + 4(2x) = 10
3x - 12 + 8x = 10
11x - 12 = 10
11x = 10 + 12
11x = 22
x = 22/11
x = 2
Then,
y = 3 - 2x
y = 3 - 2(2)
y = 3 - 4
y = -1
4. Adam used elimination to solve the system of equations to the right and found the solution x=9. What is the corresponding value for y that creates the solution to the system?
Since Adam has already found the value of x, We just need to replace x into any of the equations and solve for y. So, let's replace the value of x into the 1st equation:
[tex]\begin{gathered} -4x+9y=9 \\ -4(9)+9y=9 \\ -36+9y=9 \end{gathered}[/tex]Add 36 to both sides:
[tex]\begin{gathered} -36+9y+36=9+36 \\ 9y=45 \end{gathered}[/tex]Divide both sides by 9:
[tex]\begin{gathered} \frac{9y}{9}=\frac{45}{9} \\ y=5 \end{gathered}[/tex]Answer:
y = 5
Jeremiah is painting a fence. In total he needs to paint 36 square meters. If Jeremiah can paint four square meters in one hour how many square meters does he have left to paint after one hours of work?
Given:
Jeremiah is painting a fence. In total, he needs to paint 36 square meters.
Required:
If Jeremiah can paint for square meters in one hour. Find how many square meters he has left to paint.
Explanation:
Jeremiah can paint four square meters in one hour.
Time required to paint fence
[tex]=\frac{area\text{ of the fence}}{area\text{ painted in one hour}}[/tex]The required time to paint the fence
[tex]\begin{gathered} =\frac{36}{4} \\ =9\text{ hours } \end{gathered}[/tex]The left area after painting one hour = 36 - 4 = 32 square meters.
Final Answer:
The required time to paint the fence is 9 hours.
The left area after painting for one hour is 32 square meters.
Given f(x)=3x+5 and g(x)=2x^2-4x+8, find f(x)•g(x)
Answer:
The functions are given below as
[tex]f\lparen x)=3x+5,g\lparen x)=2x^2-4x+8[/tex]Concept:
To figure out f(x0.g(x), we will use the formula below
[tex]f\mleft(x\mright).g\mleft(x\mright)=f\mleft(x\mright)\times g\mleft(x\mright)[/tex]By substituting the values, we will have
[tex]f\mleft(x\mright).g\mleft(x\mright)=\left(3x+5\right?\left(2x^2-4x+8\right?[/tex]By expanding the brackets, we will have
[tex]\begin{gathered} f\mleft(x\mright).g\mleft(x\mright)=3x\left(2x^2-4x+8\right?+5\left(2x^2-4x+8\right? \\ f\mleft(x\mright).g\mleft(x\mright)=6x^3-12x^2+24x+10x^2-20x+40 \\ f\mleft(x\mright).g\mleft(x\mright)=6x^3-12x^2+10x^2+24x-20x+40 \\ f\mleft(x\mright).g\mleft(x\mright)=6x^3-2x^2+4x+40 \end{gathered}[/tex]Hence,
The final answer is
[tex]f\mleft(x\mright).g\mleft(x\mright)=6x^3-2x^2+4x+40[/tex]