A rectangle is inscribed in a circle with a diameter of 10 centimeters (cm). The side lengths of the rectangle
are shown.
OF
8 cm
T6 cm1
What is the total area, in square centimeters, of the shaded sections? Round your answer to the nearest tenth.

The lateral surface area of the triangular prism is 128 square centimeters. The correct answer would be an option (G) 128 cm².

Given, we have dimension are:

side length of base  = 6 cm, 5 cm, and 5 cm

height = 8 cm

Lateral surface area = (a+b+c)h

Substitute the values and we get

Lateral surface area = (6+5+5)8

Lateral surface area = 16 × 8

Lateral surface area = 128 cm².

Hence, the lateral surface area of the triangular prism is 128 square centimeters.

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The missing figure has been attached below.

Answer:

--------------------------

Using the pair (10, 460) on the graph find the speed per hour:

Find the distance after 13 hours:

The matching choice is D.

The most worrying factor for the validity of the 95% confidence interval in this case is option C) the presence of a clear outlier in the data for the average.

Let's consider each option and assess which one would cause the most worry about the validity of a 95% confidence interval calculated using the given information (mean estimate = $45,000 and standard deviation s = $15,000).

A) A mild right-skew in the stemplot indicates a slightly non-normal distribution of the data. However, since the sample size is 25, the Central Limit Theorem states that the sampling distribution of the mean should be approximately normal. So, a mild right-skew shouldn't be a significant concern for the validity of the 95% confidence interval.

B) Not knowing the population standard deviation (σ) can be a concern. However, when the sample size is large enough (which is the case here with 25 respondents), using the sample standard deviation (s) as an estimate of σ is acceptable, and the confidence interval calculation can still be valid.

C) A clear outlier in the data can greatly influence the mean estimate and the standard deviation, which may result in an inaccurate confidence interval. Outliers can cause the interval to be wider or narrower than it should be, affecting the validity of the 95% confidence interval.

Given these explanations, the most worrying factor for the validity of the 95% confidence interval in this case is option C) the presence of a clear outlier in the data. This outlier can significantly affect the accuracy and reliability of the confidence interval calculation.

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1. 1430 people were surveyed.

2. 150 people like fish but not meat.

3. 330 people are vegetarians.

1. 650 (total who like meat) - 250 (who like meat but not fish) = 400 (who like both meat and fish)

Now, we know that 550 people don't like meat, and 480 people don't like fish. Since 400 people like both meat and fish, the total number of people surveyed is:

550 (don't like meat) + 480 (don't like fish) + 400 (like both meat and fish) = 1430

So, 1430 people were surveyed.

2. 550 (don't like meat) - 400 (like both meat and fish) = 150

So, 150 people like fish but not meat.

3. 480 (don't like fish) - 150 (like fish but not meat) = 330

So, 330 people are vegetarians.

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Answer:

"Then I stopped the machine, and saw about me again the old familiar laboratory, my tools, my appliances just as I had left them. I got off the thing very shakily and sat down upon my bench. For several minutes I trembled violently. Then I became calmer. Around me was my old workshop again, exactly as it had been. I might have slept there, and the whole thing have been a dream.

Step-by-step explanation:

The length of v is given as follows:

v = 267.1 cm.

The law of sines is used in the context of this problem as we have two sides and two opposite angles, hence it is the most straightforward way to relate the side lengths.

Each side length is related with the sine of the opposite angle as follows:

sin(A)/a = sin(B)/b = sin(C)/c.

The relation for this problem is given as follows:

sin(26º)/v = sin(80º)/600

Hence we apply cross multiplication to obtain the length v is obtained as follows:

sin(26º)/v = sin(80º)/600

v = 600 x sine of 26 degrees/sine of 80 degrees

v = 267.1 cm.

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(a) G = N; addition

To show that G = N (the set of natural numbers) under addition is a group, we need to verify the four group axioms:

Closure: For any a, b in N, a + b is also in N.

Associativity: For any a, b, c in N, (a + b) + c = a + (b + c).

Identity element: There exists an element 0 in N such that for any a in N, a + 0 = a.

Inverse element: For any a in N, there exists an element -a in N such that a + (-a) = 0.

Closure and associativity hold for addition on N, so we only need to verify the identity and inverse elements.

Identity element: The only possible identity element is 0, since adding any natural number to 0 gives that number. Thus, 0 is the identity element of (N, +).

Inverse element: For any a in N, there is no element -a in N such that a + (-a) = 0. Therefore, G = N under addition is not a group, because the inverse element axiom fails.

(b) G = R; a · b = a + b + 1

To show that G = R (the set of real numbers) under the given operation is a group, we need to verify the four group axioms:

Closure: For any a, b in R, a + b + 1 is also in R.

Associativity: For any a, b, c in R, (a + b + 1) + c = a + (b + c) + 1.

Identity element: There exists an element e in R such that for any a in R, a + e + 1 = a. Solving for e, we get e = -1, so -1 is the identity element of (R, ·).

Inverse element: For any a in R, there exists an element b in R such that a · b = e. Solving for b, we get b = -a - 2. Thus, for any a in R, -a - 2 is the inverse element of a.

Therefore, G = R under the given operation is a group.

(c) G = {16, 12, 8, 4}; multiplication in Z20

To show that G under multiplication modulo 20 is a group, we need to verify the four group axioms:

Closure: For any a, b in G, ab mod 20 is also in G.

Associativity: For any a, b, c in G, (ab)c mod 20 = a(bc) mod 20.

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The surface area of the given prism is 386 square inches.

To find the surface area of a prism, we need to find the area of all its faces and add them up.

The given prism has a rectangular base with dimensions of 7 inches by 15 inches, and a height of 4 inches.

The two rectangular faces (front and back) have dimensions of 7 inches by 4 inches,

so each has an area of 7 x 4 = 28 square inches.

The two rectangular faces (sides) have dimensions of 15 inches by 4 inches,

so each has an area of 15 x 4 = 60 square inches.

The top and bottom faces are both rectangles with dimensions of 7 inches by 15 inches,

so each has an area of 7 x 15 = 105 square inches.

Therefore, the total surface area of the prism is:

2(28 sq in) + 2(60 sq in) + 2(105 sq in) = 56 sq in + 120 sq in + 210 sq in

                                                               = 386 sq in.

So, the surface area of the given prism is 386 square inches.

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Georgia's average speed expressed in meter per seconds is 4m/s

To find the average speed in meters per second, we need to convert the distance and time to the appropriate units.

Converting distance from kilometers to meters :

1km = 1000m

2.4 km = (2.4 × 1000) = 2400 m

Converting time from minutes to seconds ;

1 minute = 60 seconds

10 minutes = (60 × 10) = 600 seconds

The average speed can be calculated using the formula:

Average speed = distance / time

Average speed = 2400/60 = 4

Therefore, Georgia's average speed is 4 meters per second.

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Answer:

x = 0 and x = 4/3

Step 1:  First, we must find the derivative of f(x), noted by f'(x)

When you have a polynomial in the form x^n, we take the derivative of each polynomial using the following formula:

[tex]f'(x)=nx^n^-^1[/tex]

This means that the exponent becomes a coefficient and we subtract from the exponent.

We can do take the derivatives of x^3 and -2x^2 separately and combine them at the end:

x^3:

[tex]x^3\\3x^3^-^1\\3x^2[/tex]

-2x^2

[tex]-2x^2\\-2(2x^2^-^1)\\-4x[/tex]

Thus, f'(x) is 3x^2 - 4x

Step 2:  Critical points are found when f'(x) = 0 or when f'(x) = undefined.  There are no values for x which would make 3x^2 - 4x undefined, so we can set the function equal to 0 and solving will give us our critical points

We see that we can factor out x from 3x^2 - 4x to get

x(3x - 4) = 0

Now, we can set the two expressions equal to 0 to solve for x:

Setting x equal to 0:

x = 0

Setting 3x - 4 equal to 0:

3x - 4 = 0

3x = 4

x = 4/3

Therefore, the two critical points of the function are x = 0 and x = 4/3

The expanded total sales for 200 plums, each weighing 80 grams, at a price of $3.27 per plum is $52.32.

We can calculate the total weight of the plums as follows:

Total weight of plums = Weight per plum * Number of plums

Total weight of plums = 80 grams * 200 plums

we need to convert the total weight from grams to kilograms since the price is given per plum. There are 1000 grams in a kilogram, so:

Total weight of plums (in kilograms) = (Total weight of plums in grams) / 1000

Total sales = Total weight of plums (in kilograms) * Price per plum

Let's plug in the values and calculate the total sales:

Total weight of plums = 80 grams * 200 plums = 16,000 grams

Total weight of plums (in kilograms) = 16,000 grams / 1000 = 16 kilograms

Price per plum = $3.27

Total sales = 16 kilograms * $3.27 = $52.32

Therefore, the expanded total sales for 200 plums, each weighing 80 grams, at a price of $3.27 per plum is $52.32.

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Answer:

-infinity < x < infinity

Step-by-step explanation:

it has none.

Answer: (-8, 8).

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

[tex]\lim_{x \to -2} \frac{x^{2}-4 }{x+2} \\\lim_{x \to -2} \frac{(x+2)(x-2)}{x+2}\\ \lim_{x \to -2} x-2\\= -4[/tex]

Answer:

First answer choice

[tex]- 4[/tex]

Step-by-step explanation:

[tex]\lim _{x\to \:-2}\left(\dfrac{x^2-4}{x+2}\right)\\\\\\\mathrm{Simplify}\:\dfrac{x^2-4}{x+2}\\\\\\\mathrm{Factor}\:x^2-4:\quad (x + 2)(x - 2)\\\\\lim _{x\to \:-2}\left(\dfrac{x^2-4}{x+2}\right) \\\\= \lim _{x\to \:-2}\left(\dfrac{x+2)(x-2)}{x+2}\right)[/tex]

The x+2 common factor cancels out

[tex]= \lim _{x\to \:-2}\left(x-2\right)\\\\\text{Plug in the value x= -2}\\\\= -2 - 2\\= -4[/tex]

Thus, the velocity of money in would be 3.5 .

The velocity of money is a measure of the rate at which money changes hands in an economy. It is calculated by dividing the nominal GDP by the money supply.

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The length of curve is approximately 6.511. Thus, the correct option is 6.511.

To find the length of the curve defined by the parametric equations x(t) = t^2 - 2t and y(t) = t^3 - 4t for 0 ≤ t ≤ 2, we need to use the arc length formula for parametric equations. The formula is:

Length = ∫(√((dx/dt)^2 + (dy/dt)^2)) dt, where the integral is evaluated from the lower limit to the upper limit.

First, find the derivatives dx/dt and dy/dt:
dx/dt = 2t - 2
dy/dt = 3t^2 - 4

Next, square and sum these derivatives:
(dx/dt)^2 + (dy/dt)^2 = (2t - 2)^2 + (3t^2 - 4)^2

Now, find the square root of this expression:
√((2t - 2)^2 + (3t^2 - 4)^2)

Finally, evaluate the integral of this expression from t = 0 to t = 2:
Length = ∫(√((2t - 2)^2 + (3t^2 - 4)^2)) dt, from 0 to 2

Using a calculator or numerical integration methods, the length of the curve is approximately 6.511. Therefore, the correct option is 6.511.

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Answer:

The correct table represents the situation is shown in Table J.

Step-by-step explanation:

Table J shows the appropriate chart that most accurately depicts the circumstance.

What is a line equation?

The line's equation in the form of a slope through the points

the formula for (x1, y1) and (x2, y2) with slope m is;

⇒ y - y₁ = m (x - x₁)

In this case, m = (y2 - y1) / (x2 - x1)

Knowing that;

60 gallons of water can be found in a typical bathtub.

12 gallons per minute are also drained from a full bathtub.

From table J, now

is the rate of change,

⇒ (24 - 12) / (2 - 1)

⇒ 12 / 1

more than 12 gallons per minute

In the given circumstance, which.

Thus, Table J is the appropriate table that most accurately depicts the situation.

The correct answer is E) Both A and C are true. In summary, the line integral jĚ.dr of a smooth, positive function f of two variables, where F = Vf, is positive for all smooth paths C and positive for all closed smooth paths C.

Explanation:

The line integral jĚ.dr represents the work done by the vector field F on a particle that moves along the path C. In this case, since F = Vf, we have jĚ.dr = VfĚ.dr. By the fundamental theorem of calculus for line integrals, we have:

jĚ.dr = VfĚ.dr = f(P) - f(Q)

where P and Q are the endpoints of the path C. Since f is positive everywhere, we have f(P) > f(Q), which implies that jĚ.dr is positive for all smooth paths C.

Moreover, since f is positive everywhere, we have f(P) > f(Q) for any two points P and Q on a closed path C. Therefore, jĚ.dr is positive for any closed smooth path C. This means that the vector field F is "circulation-preserving", meaning that the work done by F on a particle that moves around a closed loop is always positive.

In conclusion, both A and C are true, as jĚ.dr is positive for all smooth paths C and positive for all closed smooth paths C.

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The individual events of drawing and eating two red pieces of candy in a row from a bag are dependent. The probability of the second event is influenced by the outcome of the first event, since one red candy has already been removed from the bag.

The probability of drawing a red candy from the bag on the first attempt is 6/37. Once the first red candy has been drawn and eaten, there are now 5 red candies left in the bag out of 36 total candies. Therefore, the probability of drawing and eating a second red candy from the bag is now 5/36.

The probability of the combined event of drawing and eating two red candies in a row can be found by multiplying the probability of the first event by the probability of the second event, since the events are dependent:

P(drawing and eating two red candies in a row) = P(drawing a red candy on the first attempt) x P(drawing a red candy on the second attempt, given that a red candy was drawn on the first attempt)

P(drawing and eating two red candies in a row) = (6/37) x (5/36)

P(drawing and eating two red candies in a row) = 5/222

Therefore, the probability of drawing and eating two red candies in a row from the bag is 5/222 or approximately 0.0226.

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The solution to Laplace's equation for the bottom side of the plate is u(x, y) = ∑[n=1 to ∞] 4/(nπ sinh(nπ)) [1 - cos(nπ)] sinh(nπ(T-y)/T) sin(nπx/T)

Let's start with the left side of the plate, where u(0, y) = 1. Since this is a constant potential, the solution to Laplace's equation is simply u(x, y) = 1.

Next, let's consider the right side of the plate, where u(TT, y) = 1. Again, the solution to Laplace's equation is u(x, y) = 1.

Moving on to the top side of the plate, where u(x, 0) = 0. We can use separation of variables to find the solution to Laplace's equation in terms of a Fourier series:

u(x, y) = ∑[n=1 to ∞] Bn sin(nπx/T) [tex]e^{-n\pi y/T}[/tex]

where T is the length of the side, and Bn are constants that depend on the boundary conditions. Since u(x, 0) = 0, we have:

Bn = 2/T ∫[0 to T] 0 sin(nπx/T) dx = 0

Therefore, the solution to Laplace's equation for the top side of the plate is:

u(x, y) = 0

Finally, let's consider the bottom side of the plate, where u(x, 7) = 1. Using separation of variables again, we find:

u(x, y) = ∑[n=1 to ∞] An sinh(nπ(T-y)/T) sin(nπx/T)

where An are constants that depend on the boundary conditions. Since u(x, 7) = 1, we have:

An = 2/ sinh(nπ) ∫[0 to T] sin(nπx/T) dx

Using trigonometric identities, we can evaluate this integral and obtain:

An = 4/(nπ sinh(nπ)) [1 - cos(nπ)]

Now, we can add these four solutions together to obtain the solution for the entire plate:

u(x, y) = 1 + ∑[n=1 to ∞] 4/(nπ sinh(nπ)) [1 - cos(nπ)] sinh(nπ(T-y)/T) sin(nπx/T)

This is the solution to Laplace's equation for a square plate with the given boundary conditions.

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There is no requirement for supplemental oxygen.

All 20 occupants can fly without oxygen supply.

As the altitude increases, the atmospheric pressure decreases, which in turn reduces the partial pressure of oxygen in the air. This reduction in oxygen availability can cause hypoxia, which can lead to impaired judgment, vision, and coordination, and can be fatal in extreme cases.

The calculation of oxygen requirements can involve estimating the total oxygen consumption based on the number of occupants, their age, and their physical condition, and then determining the appropriate type and quantity of oxygen delivery systems to be carried on board the aircraft.

Here we have

An unpressurized aircraft with 20 occupants other than the pilots will be cruising at 14,000 feet msl for 25 minutes.

According to the Federal Aviation Regulations, if an aircraft is flying at an altitude above 12,500 feet MSL for more than 30 minutes,

then oxygen must be supplied to the occupants if:

The cabin pressure altitude exceeds 14,000 feet MSL, or

The cabin pressure altitude exceeds 15,000 feet MSL for any period of time.

In this case, the aircraft is flying at 14,000 feet MSL for 25 minutes, which is less than 30 minutes.

Therefore,

There is no requirement for supplemental oxygen.

All 20 occupants can fly without oxygen supply.

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The correct expressions are:

B. 5² × 5³ >[tex]5^5[/tex]

C. 3² × [tex]3^5 < 3^8[/tex]

Let's evaluate each expression:

A. 4³ × [tex]4^4 = 4^{12[/tex]

Simplifying the left side: [tex]4^3 \times 4^4 = 4^{(3+4) }= 4^7[/tex]

Comparing with the right side: [tex]4^7[/tex]≠ [tex]4^{12[/tex]

Therefore, expression A is not true.

B. 5² × 5³ > [tex]5^5[/tex]

Simplifying the left side: [tex]5^2 \times 5^3 = 5^{(2+3)} = 5^5[/tex]

Comparing with the right side: [tex]5^5 = 5^5[/tex]

Therefore, expression B is true.

C. 3² × [tex]3^5 < 3^8[/tex]

Simplifying the left side: [tex]3^2 \times 3^5 = 3^{(2+5) }= 3^7[/tex]

Comparing with the right side: [tex]3^7 < 3^8[/tex]

Therefore, expression C is true.

D. 5² × [tex]5^4 = 5^8[/tex]

Simplifying the left side: [tex]5^2 \times 5^4 = 5^{(2+4) }= 5^6[/tex]

Comparing with the right side: [tex]5^6[/tex] ≠ [tex]5^8[/tex]

Therefore, expression D is not true.

In conclusion, the correct expressions are:

B. 5² × 5³ >[tex]5^5[/tex]

C. 3² × [tex]3^5 < 3^8[/tex]

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The density of the cube is 0.08343 grams per cubic centimeter

The side of cube is 8 inches

and, We know that :

The formula of Density is :

D = mass/ volume

The weight of a cube is 700 gm.

First, we convert the side inches into cm

For conversion, We have to multiply by 2.54

=> 8 × 2.54

=> 20.32cm

Now, For finding the density

We have to calculate the volume of cube :

Volume of cube = [tex](side)^3[/tex]

Volume of cube = 8390.18[tex]cm^3[/tex]

And, plug all the values in the formula of density.

Density = 700/8390.18[tex]cm^3[/tex]

Density = 0.08343 grams per cubic centimeter

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(a) The location of the baseball field using rectangular coordinates is (-3,32).

(b) To find the location of the field using polar coordinates, we need to first find the distance r from the origin to the point (-3,32). Using the Pythagorean theorem, we have:

r = sqrt((-3)^2 + 32^2) = 32.28

Next, we need to find the angle theta between the positive x-axis and the line connecting the origin to the point (-3,32). Since the point is in the third quadrant, we know that theta is between 180 and 270 degrees. We can use the tangent function to find theta:

tan(theta) = (opposite side)/(adjacent side) = (-32)/(3)

theta = arctan(-32/3) = 276.87 degrees

Therefore, the location of the baseball field using polar coordinates is (32.28,276.87).
(c) The location of the different ballpark using rectangular coordinates is (-2,-28).
(d) To find the location of the different ballpark using polar coordinates, we need to first find the distance r from the origin to the point (-2,-28). Using the Pythagorean theorem, we have:

r = sqrt((-2)^2 + (-28)^2) = 28.06

Next, we need to find the angle theta between the positive x-axis and the line connecting the origin to the point (-2,-28). Since the point is in the fourth quadrant, we know that theta is between 270 and 360 degrees. We can use the tangent function to find theta:

tan(theta) = (opposite side)/(adjacent side) = (-28)/(-2) = 14

theta = arctan(14) = 83.66 degrees

Therefore, the location of the different ballpark using polar coordinates is (28.06,83.66).

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The Maclaurin series for f(x) is:[tex]f(x) = 1 - 6x + 36x^2 - 216x^3 + ...[/tex]

The associated radius of convergence for this Maclaurin series is infinite, which means the series converges for all values of x.

The Maclaurin series for the function [tex]f(x) = ( {e}^{-6x} )[/tex] can be found using the definition of a Maclaurin series. The Maclaurin series represents a function as an infinite sum of terms, each term being a derivative of the function evaluated at x = 0, multiplied by a power of x divided by the factorial of the power.

To find the Maclaurin series for f(x),

we need to compute the derivatives of f(x) at x = 0.

Taking the derivatives of [tex]f(x) = ( {e}^{-6x} )[/tex]

we get:[tex]f'(x) ={ -6e}^{-6x} [/tex]

[tex]f''(x) = {36e}^{-6x} [/tex]

[tex]f'''(x) ={ -216e}^{-6x} [/tex]...

Evaluating these derivatives at x = 0,

we find:[tex]f(0) = e^0

= 1[/tex]f'(0)

= -6f''(0)

= 36f'''(0)

= -216...

Using these values,

the Maclaurin series for f(x) is:

[tex]f(x) = 1 - 6x + 36x^2 - 216x^3 + ...[/tex]

The associated radius of convergence for this Maclaurin series is infinite, which means the series converges for all values of x. This is because the exponential function [tex] {e}^{-6x} [/tex]converges for all real numbers x, and the series expansion captures the behavior of the function within that range.

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To write the given expression as a single integral, we can apply the linearity property of integration, which states that the integral of the sum of two functions is equal to the sum of their integrals.

Using this property, we get:

a^2 f(x) dx - 5 + 3 f(x) dx / 2 - (-3 f(x) dx / 5)

Now, we can simplify each term by multiplying and dividing by appropriate constants to get a common denominator of 10:

= (2a^2 f(x) - 50) / 10 + (15 f(x) - 6 f(x)) / 10 + (30 f(x) - (-3) f(x)) / 10

= (2a^2 f(x) + 9 f(x) + 33 f(x) - 50) / 10

= (2a^2 + 42) / 10

Therefore, the given expression can be written as the single integral:

∫ [(2a^2 f(x) + 9 f(x) + 33 f(x) - 50) / 10] dx

which simplifies to:

(2a^2 + 42) / 10 ∫ f(x) dx

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The correct answer is D. The flux of F across C is the sum of the components of F orthogonal or normal to C at each point of C.

The flux of a two-dimensional vector field F across a smooth oriented curve C represents the amount of the field that passes through the curve. In this context, the correct answer is: D. The flux of F across C is the sum of the components of F orthogonal or normal to C at each point of C. This means that the flux is calculated by considering the components of the vector field that are perpendicular to the curve at each point along C. By summing these orthogonal components, we can determine the overall quantity of the field that passes through the curve.

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Answer:

1/2

Step-by-step explanation:

We can use the unit circle and reference angle to find the exact value of sin(-5pi/6).

Starting from the positive x-axis (θ=0), we can rotate clockwise by 5pi/6 radians to get to the terminal side of -5pi/6.

The reference angle is pi/6 radians, which is the angle between the terminal side and the x-axis if we rotate counterclockwise instead.

At this angle, sin is negative and equal to -1/2, since the opposite side has length 1 and the hypotenuse has length 2.

Since sin is an odd function, we have sin(-5pi/6) = -sin(5pi/6) = -(-1/2) = 1/2.

Therefore, the exact value of sin(-5pi/6) is 1/2.

Answer:

length = 10 in.

Step-by-step explanation:

volume = 400 in.³

height = 5 in.

width = 8 in.

volume = length × width × height

V = LWH

400 = L × 8 × 5

400 = 40L

40L = 400

L = 400/40

L = 10

Answer: length = 10 in.

The Taylor series for f(x)=ex about x=2 is given by ∑n=0[infinity]cn(x−2)n where cn = fⁿ(2)/n! = e²/2! e²/3! ... e²/n!.

The Taylor series is a way to represent a function as an infinite sum of terms that involve the function's derivatives evaluated at a specific point.

In this case, we want to find the Taylor series for f(x)=ex about x=2. To do this, we first need to find the derivatives of f(x) at x=2.

We have fⁿ(x) = ex for all n, so fⁿ(2) = e² for all n. We can then use this to find the coefficients cn in the Taylor series.

We have cn = fⁿ(2)/n! = e²/2! e²/3! ... e²/n!.

We can then substitute these coefficients into the Taylor series to get ∑n=0[infinity]cn(x−2)n = ∑n=0[infinity] e²/2! e²/3! ... e²/n!(x−2)n, which is the Taylor series for f(x)=ex about x=2.

To learn more about Taylor series : brainly.com/question/28158012

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