A Ring, a solid Cylinder and a solid sphere all having the same mass and the Same radius are held at the top of an inclined plane if the objects are roll without slipping and the (see the picture)between each object and the plane is 0.3 if they are released from an incloed plane at the same time which wal bee reach the bottom first?​

Answer:

R = v^2 sin 2 theta / g

The range provides the distance a projectile can travel

R(max) = v^2 / g    if theta = 45 deg

R = 2.7^2 / 9.8 = .74 m

Answer:

Δx = 6.33 x 10⁻³ m = 6.33 mm

Explanation:

We can use the Young's Double Slit Experiment Formula here:

[tex]\Delta x = \frac{\lambda L}{d}\\\\[/tex]

where,

Δx = distance between consecutive dark fringes = width of central bright fringe = ?

λ = wavelength of light = 633 nm = 6.33 x 10⁻⁷ m

L = distance between screen and slit = 3.7 m

d = slit width = 0.37 mm = 3.7 x 10⁻⁴ m

Therefore,

[tex]\Delta x = \frac{(6.33\ x\ 10^{-7}\ m)(3.7\ m)}{3.7\ x \ 10^{-4}\ m}[/tex]

Δx = 6.33 x 10⁻³ m = 6.33 mm

Answer:

C, Red has the longest one

c red

red has longest wavelength

amnh dot org

Solution :

Mass is varied keeping frequency constant.

Wavelength, λ  [tex]$=\frac{2l}{n}$[/tex]

where length of spring = l

           number of segments = n

Velocity, v = λ x f

                 = [tex]$\sqrt{\frac{T}{\mu}}$[/tex]

[tex]$\mu $[/tex] =  mass density, T = tension in string

[tex]$T=\frac{4 \mu l^2f^2}{n^2}$[/tex]

[tex]$T=mg = \frac{4 \mu l^2f^2}{n^2}$[/tex]  , n = 2

[tex]$T = (m-2.2)g = \frac{4 \mu l^2f^2}{n^2}, n = 5$[/tex]

[tex]$\Rightarrow \frac{m}{m-2.2}=\frac{25}{4}$[/tex]

[tex]$\Rightarrow m = 2.619\ kg$[/tex]

Therefore, μ = 0.002785 kg/ m

Frequency is varied keeping T constant

[tex]$T=\frac{4 \mu l^2f^2}{n^2}, f=60 , \ \ n = 2$[/tex]

[tex]$T=\frac{4 \mu l^2f^2}{n^2}, f=? , \ \ n = 7$[/tex]

[tex]$\Rightarrow \frac{60^2}{4}=\frac{f^2}{49}$[/tex]

f = 210 Hz

Answer:

b

Explanation:

Answer:

the maximum allowable current is 7302.967  amperl

Explanation:

The computation of the maximum allowable current is shown below;

Force F = mean ÷ 4π 2 I_1 I_2 ÷d  × ΔL

200 N = (10)^-7 (2I × I) ÷ 0.08 × 1.5

200 = 3.75 × 10^-6 I^2

I = √200 ÷ √ 3.75 × 10^-6

= 7302.967  amperl

Hence, the maximum allowable current is 7302.967  amperl

Basically we applied the above formula

Answer:

34.24 %

Explanation:

Since I₀ is the intensity of the un-polarized light, the intensity I₁ of the light polarized by the 1st sheet is (by the one-half rule) I₁ = I₀/2.

The intensity of polarized light I from a polarized source I' is I = I'cos²Ф where Ф is the angle between the direction of I' and I. Since the second sheet has its transmission axis at 25° with respect °o the 1st sheet, the intensity of light I₂ from the second sheet is I₂ = I₁cos²25°.

Also, the 3rd sheet has its transmission axis 47° with respect to the 1st sheet. So, the angle between the transmission axis of the 2nd sheet and 3rd sheet is 47° - 25° = 22°. So, the intensity I₃ from the 3rd sheet is I₃ = I₂cos²22°

Finally, the 4th sheet has its transmission axis 10° with respect to the 3rd sheet. So, the intensity I₄ from the 4th sheet is I₄ = I₃cos²10°.

So,  I₄ = I₃cos²10°

I₄ = I₂cos²22°cos²10°

I₄ = I₁cos²25°cos²22°cos²10°

I₄ = (I₀/2)cos²25°cos²22°cos²10°

I₄/I₀ = cos²25°cos²22°cos²10°/2

I₄/I₀ = (cos25°cos22°cos10°)²/2

I₄/I₀ = (0.9063 × 0.9272 × 0.9848)²/2

I₄/I₀ = 0.8275²/2

I₄/I₀ = 0.6848/2

I₄/I₀ = 0.3424

So, as a percentage,

I₄/I₀ × 100% = 0.3424 × 100% = 34.24 %

Answer:

Hello! Your answer would be, A) True

Explanation:

Hope I helped! Ask me anything if you have any questions. Brainiest plz!♥ Hope you make a 100%. Have a nice morning! -Amelia♥

Answer:

When force and displacement are in the same direction, the work performed on an object is said to be positive work. Example: When a body moves on the horizontal surface, force and displacement act in the forward path. The work is done in this case known as Positive work.

Explanation:

Hope this helps you

Answer: 4.94cm³

Explanation:

Data;

ρ = 1.59g/cm³

mass = 7.85g

volume = ?

density = mass / volume

ρ = m / v

v = m / ρ

v = 7.85 / 1.59

v = 4.94cm³

Explanation:

if the current is 1A

V=iR

V= 1 × 8

V = 8volts

Answer:

a

because the mechanical wave is when it goes over and over again

Answer:

The answer is a like i said 3hrs ago i dont know if this guy copied me tbh

Explanation:

Answer:

hope u can understand the method

Answer:

V₁ = V = 120 V

Explanation:

Such a combination of capacitors in which;

1- Potential difference across each capacitor is the same

2- Total charge is distributed amongst the capacitors

; is called Parallel Combination.

Therefore, in this case, the potential difference across each capacitor will also be the same. Because the capacitors are connected in parallel here. So the voltage across 3 μF capacitor will be the same as the voltage across the 6 μF capacitor and they both will be equal to the total potential difference.

V₁ = V = 120 V

Answer:

h = 3.5 m

Explanation:

First, we will calculate the final speed of the ball when it collides with a seesaw. Using the third equation of motion:

[tex]2gh = v_f^2 - v_i^2\\[/tex]

where,

g = acceleration due to gravity = 9.81 m/s²

h = height = 3.5 m

vf = final speed = ?

vi = initial speed = 0 m/s

Therefore,

[tex](2)(9.81\ m/s^2)(3.5\ m) = v_f^2 - (0\ m/s)^2\\v_f = \sqrt{68.67\ m^2/s^2}\\v_f = 8.3\ m/s[/tex]

Now, we will apply the law of conservation of momentum:

[tex]m_1v_1 = m_2v_2[/tex]

where,

m₁ = mass of colliding ball = 3.6 kg

m₂ = mass of ball on the other end = 3.6 kg

v₁ = vf = final velocity of ball while collision = 8.3 m/s

v₂ = vi = initial velocity of other end ball = ?

Therefore,

[tex](3.6\ kg)(8.3\ m/s)=(3.6\ kg)(v_i)\\v_i = 8.3\ m/s[/tex]

Now, we again use the third equation of motion for the upward motion of the ball:

[tex]2gh = v_f^2 - v_i^2\\[/tex]

where,

g = acceleration due to gravity = -9.81 m/s² (negative for upward motion)

h = height = ?

vf = final speed = 0 m/s

vi = initial speed = 8.3 m/s

Therefore,

[tex](2)(9.81\ m/s^2)h = (0\ m/s)^2-(8.3\ m/s)^2\\[/tex]

h = 3.5 m

Answer:

the answer of this question is true

Answer:

12558 J

Explanation:

Please do mark as brainliest. Hope this helps! :)

Answer:

Explanation:

Dear Student, this question is incomplete, and to attempt this question, we have attached the complete copy of the question in the image below. Please, Kindly refer to it when going through the solution to the question.

To objective is to find the:

(i) required heat exchanger area.

(ii) flow rate to be maintained in the evaporator.

Given that:

water temperature = 300 K

At a reasonable depth, the water is cold and its temperature = 280 K

The power output W = 2 MW

Efficiency [tex]\zeta[/tex] = 3%

where;

[tex]\zeta = \dfrac{W_{out}}{Q_{supplied }}[/tex]

[tex]Q_{supplied } = \dfrac{2}{0.03} \ MW[/tex]

[tex]Q_{supplied } = 66.66 \ MW[/tex]

However, from the evaporator, the heat transfer Q can be determined by using the formula:

Q = UA(L MTD)

where;

[tex]LMTD = \dfrac{\Delta T_1 - \Delta T_2}{In (\dfrac{\Delta T_1}{\Delta T_2} )}[/tex]

Also;

[tex]\Delta T_1 = T_{h_{in}}- T_{c_{out}} \\ \\ \Delta T_1 = 300 -290 \\ \\ \Delta T_1 = 10 \ K[/tex]

[tex]\Delta T_2 = T_{h_{in}}- T_{c_{out}} \\ \\ \Delta T_2 = 292 -290 \\ \\ \Delta T_2 = 2\ K[/tex]

[tex]LMTD = \dfrac{10 -2}{In (\dfrac{10}{2} )}[/tex]

[tex]LMTD = \dfrac{8}{In (5)}[/tex]

LMTD = 4.97

Thus, the required heat exchanger area A is calculated by using the formula:

[tex]Q_H = UA (LMTD)[/tex]

where;

U = overall heat coefficient given as 1200 W/m².K

[tex]66.667 \times 10^6 = 1200 \times A \times 4.97 \\ \\ A= \dfrac{66.667 \times 10^6}{1200 \times 4.97} \\ \\ \mathbf{A = 11178.236 \ m^2}[/tex]

The mass flow rate:

[tex]Q_{H} = mC_p(T_{in} -T_{out} ) \\ \\ 66.667 \times 10^6= m \times 4.18 (300 -292) \\ \\ m = \dfrac{ 66.667 \times 10^6}{4.18 \times 8} \\ \\ \mathbf{m = 1993630.383 \ kg/s}[/tex]

Answer:

J = 1600 kg-m/s

Explanation:

Given that,

The mass of charging bull rams, m = 800 kg

Initial speed, u = 5 m/s

Final speed, v = 3 m/s

We need to find the impulse the bull  experience by smashing the fence. Let it is J. We know that, impulse is equal to the change in momentum such that,

J = m(v-u)

Put all the values,

J = 800(3-5)

= 800(-2)

= -1600 kg-m/s

Hence, the magnitude of impulse is equal to 1600 kg-m/s.

Answer:

(a) Energy Density = 160.94 J/m³

(b) Energy Stored = 0.192 J

Explanation:

(a)

The energy density of the magnetic field inside the solenoid is given by the following formula:

[tex]Energy\ Denisty = \frac{B^2}{2\mu_o}\\[/tex]

where,

B = magnetic field strength of solenoid = [tex]\frac{\mu_oNI}{l}[/tex]

Therefore,

[tex]Energy\ Density = \frac{\mu_oN^2I^2}{2l^2}[/tex]

where,

μ₀ = permeability of free space = 4π x 10⁻⁷ N/A²

N = No. of turns = 1300

I = current = 8.15 A

L = length = 66.2 cm = 0.662 m

Therefore,

[tex]Energy\ Density = \frac{(4\pi\ x\ 10^{-7}\ N/A^2)(1300)^2(8.15\ A)^2}{2(0.662\ m)^2}[/tex]

Energy Density = 160.94 J/m³

(b)

Energy Stored = (Energy Density)(Volume)

Energy Stored = (Energy Density)(Area)(L)

Energy Stored = (160.94 J/m³)(0.0018 m²)(0.662 m)

Energy Stored = 0.192 J

This is true I think

It applies to Newton's Laws

it's true because it's a part of newtons law

Answer:

677 m

Explanation:

Using the definition of the sine of an angle, we can write

sin 14.1 = (height of mountain) / (slope length of mountain)

sin 14.1 = H / (2780 m) ---> H = (2780 m) x sin 14.1

= 677 m

The height of the mountain is 677.21 m

The given parameters;

length of the slope, L = 2780 m

angle of inclination, Ф = 14.1°

let the height of the mountain, = h

A simple sketch of the problem is given below;

                    ↓P

                    ↓

                    ↓ h

                    ↓                                            14.1°

                    ↓------------------------------------------------Q

A straight line  joining PQ  is  the hypotenuse of the right triangle.

The height of the right triangle is calculated as follows;

[tex]sin(14.1) = \frac{h}{PQ} \\\\\h = PQ \times sin(14.1)\\\\h = 2780 \times sin(14.1)\\\\h = 677.21 \ m[/tex]

Thus, the height of the mountain is 677.21 m

Learn more here: https://brainly.com/question/4326804

Answer:

B)   I₀ = I_f= 0, C) vₐ = [tex]\frac{m_w}{m_a} \ v_w[/tex] ,  D)      t = [tex]\frac{m_a}{m_w} \ \frac{L}{v_w}[/tex]

Explanation:

A) in the attachment you can see a diagram of the movement of the key and the astronaut that is in the opposite direction to each other.

B) Momentum equals the change in momentum in the system

          I = ∫ F dt = Δp

since the astronaut has not thrown the key, the force is zero, so the initial impulse is zero

           I₀ = 0

The final impulse of the two is still zero, since it is a vector quantity, subtracting the impulse of the two gives zero, since it is an isolated system

             I_f = 0

C) We define the system formed by the astronaut and the key, for which the forces during the separation are internal and the moment is conserved

initial instant.

         p₀ = 0

final instant

         p_f = [tex]m_a v_a - m_w v_w[/tex]

We used the subscript “a” for the astronaut and the subscript “w” for the key

the moment is preserved

        po = p_f

        0 = mₐ vₐ - m_w v_w

        vₐ = [tex]\frac{m_w}{m_a} \ v_w[/tex]

D) as the astronaut goes at constant speed we can use the uniform motion relationships

         vₐ = x / t

         t = x / vₐ  

         t = [tex]\frac{m_a}{m_w} \ \frac{L}{v_w}[/tex]

Answer:

(a) a = 2.44 m/s²

(b) s = 63.24 m

Explanation:

(a)

We will use the second equation of motion here:

[tex]s = v_it+\frac{1}{2}at^2[/tex]

where,

s = distance covered = 47 m

vi = initial speed = 0 m/s

t = time taken = 6.2 s

a = acceleration = ?

Therefore,

[tex]47\ m = (0\ m/s)(6.2\ s)+\frac{1}{2}a(6.2\ s)^2\\\\a = \frac{2(47\ m)}{(6.2\ s)^2}[/tex]

a = 2.44 m/s²

(b)

Now, we will again use the second equation of motion for the complete length of the inclined plane:

[tex]s = v_it+\frac{1}{2}at^2[/tex]

where,

s = distance covered = ?

vi = initial speed = 0 m/s

t = time taken = 7.2 s

a = acceleration = 2.44 m/s²

Therefore,

[tex]s = (0\ m/s)(6.2\ s)+\frac{1}{2}(2.44\ m/s^2)(7.2\ s)^2\\\\[/tex]

s = 63.24 m

Answer:

you need 7 points and the other team just needs to stop you from scoring

Explanation: