(a) For the first 50 m:
h1 = 0.5 x a x t12
50 m = 0.5 x 9.8 m/s2 x t12
t1 = 3.19 s
Time to fall first 50 m = 3.19 s
(b) For the full 100 m:
h2 = 0.5 x a x t22
100 m = 0.5 x 9.8 m/s2 x t22
t2 = 4.52 s
Time to fall second 50 m = t2 - t1 = 1.33 s
Dropped rocks and other objects gain speed rapidly as they fall. Velocity defines the direction in which a body or object is moving. Velocity is primarily a scalar quantity. Velocity is basically a vector quantity. Rate of change of distance.
If our planet loses gravity for even 5 seconds it means the end of life on Earth as we know it. Gravity pulls objects together. The greater the mass of an object, the stronger its gravitational pull. Any submarine you choose for skydiving should be designed with movement in mind. If the weather is cool on the day of skydiving, you should choose pants that cover the entire leg. We recommend wearing sweatpants or sweatpants.
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An inclined plane make an angle of 30 degree with the horizontal. Find the contant force applied parallel to the plane required to caue a 15kg box to lide up the plane with anm acceleration of 1. 2m/^2 and down thge incline with an acceleration o1. 2m/^2. Neglect friction force
The constant force applied parallel to the plane required to cause a 15kg box to line up is 127.31 N.
Acceleration is the rate of change of the velocity of an item with appreciation to time. Accelerations are vector portions. The orientation of an item's acceleration is given by the orientation of the net pressure appearing on that object.
Calculation:-
mass =15 kg
Normal force = mgCos30°
parallel force = mgsin30°
acceleration required = 1.2 m/s²
Contact force = 15 × 9.8 × √3/2
= 127.31 N
Acceleration is the charge at which velocity modifications with time, in terms of each speed and route. A factor or an object moving in a straight line is accelerated if it quickens or slows down. Movement on a circle is extended despite the fact that the rate is consistent because the course is continually changing.
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A quantity of 100g of ice at 0c and 50g steam at 100 c are added to a container that has 150 g water at 30c. Determine the final temperature in the container. Ignore the container itself in your calculations.
Answer:90g for 70km
Explanation:
a wooden bucket filled with water has a mass of 56 kg and is attached to a rope that is wound around a cylinder with a radius of 0.060 m. a crank with a turning radius of 0.35 m is attached to the end of the cylinder. what minimum force directed perpendicularly to the crank handle is required to raise the bucket? the acceleration of gravity is 9.81 m/s 2 . answer in units of n.
The acceleration of gravity is 9.81 m/s 2 . answer in units of n. The minimum force required was 93.20N.
What is force?
Force is a quantitative representation of an interaction that creates a change in the motion of an item. In reaction to a force, an item may accelerate, slow down, or change direction. In other words, force is any action that tends to maintain or alter the motion of a body or distort it.
Total mass=56Kg
tied radius=0.060m
turning radius=0.35m
g=9.81m/s2
T=0.35F
where F is the force that we want
W=mg
=68Kg
W(0.060)=T=0.35F
0.060/0.35=0.171
F=0.171W
0.171(56)=9.576Kg
=93.20N
So here by the force required is=93.20N
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if you use a horizontal force of 30 n to slide a 12 kg wooden crate across a floos at a constant velocity, what is the coefficient of kinetic friction betweem the crate and the floor?
To use the kinetic friction force formula.
What is kinetic coefficient friction?
The proportion of contacting surfaces' kinetic friction forces to normal forces is known as the coefficient of kinetic friction.
What is acceleration?
Any process that causes a change in velocity is referred to as an acceleration. Since velocity depends on both speed and direction, you can only accelerate by changing either one or both.
Fn = 12kg* 9.81 m/s^2 = 117.7 N
since there is no acceleration, friction must equal the horizontal force
30N = 117.7*μ
μ = .255
Therefore, the coefficient of kinetic friction between the crate and the floor is 255.
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the only force acting on a 3.5 kg canister that is moving in an xy plane has a magnitude of 7.2 n. the canister initially has a velocity of 3.2 m/s in the positive x direction, and some time later has a velocity of 4.5 m/s in the positive y direction. how much work is done on the canister by the 7.2 n force during this time?
Answer:
17.5175J
Explanation:
By the work-kinetic energy theorem,
[tex]W=\frac{1}{2} m{v_{f} }^{2} -\frac{1}{2} m{v_{i} }^{2}[/tex]
where [tex]v_{i}[/tex] is initial velocity and [tex]v_{f}[/tex] is final velocity. Note that their directions make no impact on the problem.
We can simplify this to:
[tex]W=\frac{1}{2} m({v_{f} }^{2} -{v_{i} }^{2})[/tex]
Now sub in our values:
[tex]W=\frac{1}{2} (3.5)({4.5 }^{2} -{3.2 }^{2})[/tex]
W= (1.75)(20.25-10.24)=17.5175J
How can gravity's role in tectonic plate motion be described? question 6 options: earth's magnetic field reverses ridge push and slab pull circulating material in the mantle earth's internal heating
Gravity's role in the tectonic plate motion can be described on the basis of ridge push and slab pull of tectonic plates.
What are ridge push and slab pull?Ridge push refers to gravitational sliding. It is a driving force for plate motion in plate tectonics, occurring at mid-ocean ridges as the result of the rigid lithosphere sliding down the hot and raised asthenosphere below mid-ocean ridges.
Slab pull is a pulling force that is exerted by a cold and dense oceanic plate plunging into the mantle. The term for the process of a tectonic plate descending into the mantle is subduction. Subduction may emerge due to gravity.
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(ii) a spring with hangs vertically next to a ruler. the end of the spring is next to the 15-cm mark on the ruler. if a 2.5-kg mass is now attached to the end of the spring, and the mass is allowed to fall, where will the end of the spring line up with the ruler marks when the mass is at its lowest position?
If a 2.5 kg mass is attached to a spring with k = 53 N/m, the spring will stretch to 61 cm.
Missing data from the problem:
A spring with spring constant (k) 53 N/m is hang vertically.
Original length of the spring = 15 cm = 0.15 m
A mass of 2.5 kg is attached to the end of the spring.
According to the Hooke's Law:
F = - kx
Where:
F = force applied on the spring
x = spring displacement
From the problem, the only force is the weight of the mass:
F = w = m . g (g = 9.8 m/s²)
F = 2.5 . 9.8 = 24.5 N
Substitute k = 53 N/m,
24.5 = 53 . x
x = 24.5/53 = 0.46 m = 46 cm
Therefore the final length of the spring = 15 + 46 = 61 cm
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in a double-slit experiment, the slit separation d is 2.00 times the slit width w. how many bright interference fringes are in the central diffraction envelope
The number of bright interference fringes in the central diffraction envelope is 3.
To determine the number of bright interference, we need to understand the equation of first minima in the diffraction pattern, and the equation of angular locations of the double slit interference pattern.
For the equation of first minima in the diffraction pattern is:
[tex]W[/tex]·[tex]Sin[/tex]θ = [tex]m_{1}[/tex]·λ
For the equation of angular locations of the double slit interference pattern is:
[tex]d[/tex]·[tex]Sin[/tex]θ = [tex]m_{2}[/tex]·λ..... (1)
Here, W is single slit width while d is slit separation
Next, we need to determine the number of bright interference fringes in the central diffraction envelope.
For the first minima, [tex]m_{1} = 1[/tex], then rewrite the equation (1) as follows.
=[tex]a[/tex]·[tex]Sin[/tex]θ = [tex]m_{1}[/tex]·λ
=[tex]a[/tex]·[tex]Sin[/tex]θ = [tex]1[/tex]·λ
=[tex]a[/tex]·[tex]Sin[/tex]θ = λ..... (2)
Then, from the equations (1) and (2)
[tex]=m_{2}=\frac{d}{w} \\=m_{2}=\frac{2w}{w}\\=m_{2}=2[/tex]
Therefore, there are 3 bright fingers, 1 at the centre and 2 in each side.
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It is typical for people in hypnotic trances to temporarily __________. a. begin speaking languages they do not know b. lose track of their immediate surroundings c. become aware of past lives and buried memories d. feel completely paralyzed and unable to act please select the best answer from the choices provided a b c d
It is typical for people in hypnotic trances to temporarily begin speaking languages they do not know .
Option a is correct
Who are people when they are hypnotized?Although hypnosis is frequently described as a sleep-like condition, it is actually better described as a state of sharpened focus, increased suggestibility, and vivid fantasies. People who are hypnotized frequently appear tired and disoriented, yet they are actually hyperaware.
What transpires while a person is tranced?Our brain waves must slow down in order to enter a trance. Throughout the course of the day, people alternate between several brain wave states. Different stages of the brain wave include sleeping, daydreaming, and being fully alert and focused.
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the x, y, and z components of a magnetic field are bx = 0.088 t, by = 0.13 t, and b, = 0.15 t. a 37-cm wire is oriented along the z axis and carries a current of 3.4 a. what is the magnitude of the magnetic force that acts on this wire?
The magnitude of the magnetic force that acts on this wire is 0.2298 N.
The Magnetic Fields is an American band founded and led with the aid of Stephin Merritt. Merritt is the organization's number-one songwriter, producer, and vocalist, as well as a frequent multi-instrumentalist. A magnetic subject is the vicinity around a magnet, magnetic item or an electric powered price wherein magnetic pressure is exerted.” Huh? allow's put it this way.
The magnetic field is the location around a magnet wherein the effect of magnetism is felt. We use the magnetic field as a device to describe how the magnetic pressure is distributed within the space around and within something magnetic in nature.
Calculation:-
Magnetic field B = 0.13 i +0.13 j +0.17 k
length L = 25 k cm =0.25 km
current i = 5 A
the magnetic force acts on the wire F = i ( L X B )
F = 5 [ 0.25 k X ( 0.13 i + 0.13 j + 0.17 k ) ]
= 5 [ (0.25 *0.13) (kXi) + (0.25 *0.13) ( k X j ) + ( 0.25 *0.17 ) ( k X k ) ]
= 5 [ -0.0325 j - 0.0325 I + 0 ]
= -0.1625 I -0.1625 j
magnitude of F = sqrt [ (-0.1625)^2 + (-0.1625)^ 2 ]
= 0.2298 N
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What about the Model of Static Electricity makes it mechanistic?
The material that is attracted to the electron which is negatively charged and the material from which the electron was lost is considered as positively charged that makes the Mechanism of Static Electricity.
What is Model of Static Electricity?Static Buildup apparatus. The static build up is the phenomenon in which electric charges are traded between the surfaces of two objects that come into contact with each other. In this procedure, one object static takes on a positive charge and the other a negative charge. The material that interested the electron is negatively charged and the material from which the electron was lost is positively charged. This is the appliance for the Generation of Static Electricity. Static electricity is the result of a disparity between negative and positive charges in an object.
So we can conclude that Static electricity is an variance of electric charges within or on the surface of a material or between materials.
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a piece of wood from a nearby construction site floats near the shore of a lake. it floats in very calm water with half of its volume just above the surface. what is the density of this piece of wood? the density of water is 1000 kg/m3 .
A piece of wood from a nearby construction site floats near the shore of a lake. it floats in very calm water with half of its volume just above the surface. The density of this piece of wood will be 500 kg/[tex]m^{3}[/tex]
The floatation principle states that when an object floats in a liquid, the buoyant force acting on the object is equal to the object's weight.
since ,
buoyant force = rho * g * V
= 1000 * g * (V/2) equation 1
objects weight = mg equation 2
equating equation 1 and equation 2
500 * g * V = mg
mass = 500 V
density = mass / volume = 500 V / V
= 500 kg/[tex]m^{3}[/tex]
The density of this piece of wood will be 500 kg/[tex]m^{3}[/tex]
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To open a box, you apply 50 N of force to a crowbar. the crowbar applies 450 N of force to the lid of the chest. What is the mechanical advantage of the crowbar?
Answer: The mechanical advantage of the crowbar 9
Answer:
9
Explanation:
50N-load
450N-effort
m.a=load÷effort
450÷50=9
a service elevator takes a load of garbage, mass 20.7 kg, from a floor of a skyscraper under construction down to ground level, accelerating downward at a rate of 1.7 m/s2. find the magnitude of the force (in n) the garbage exerts on the floor of the service elevator.
The magnitude of the force that the garbage exert on the floor of the service elevator is equal to 238.05 Newtons.
The mass of the garbage in the elevator is 20.7 kg. The elevator is accelerated downward at a rate of 1.7 m/s².
The acceleration due to gravity is g.
As the elevator accelerator downward then the total net acceleration of the elevator in the download direction is
A = (1.7 + 9.8) m/s².
A = 11.5 m/s².
The force that the garbage exert on the floor of the service elevator will be equal to the product of the mass of the garbage and the net acceleration with which the elevator is going downward,
F = 20.7 × 11.5
F = 238.05 N.
So, the force exerted by the garbage on the floor is 238.09 Newton.
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calculate the height (in m) of a cliff if it takes 2.21 s for a rock to hit the ground when it is thrown straight up from the cliff with an initial velocity of 8.01 m/s. (enter a number.) (b) how long (in s) would it take to reach the ground if it is thrown straight down with the same speed? (enter a number.)
The height of the cliff is 6.22 meters and the time taken by the rock to hit the ground if thrown with same speed is 0.81 seconds.
The time taken by the rock to hit the ground when it is thrown up from the the cliff with an initial velocity of 8.01 m/s.
(a) From the equation of motion,
H = ut+1/2at²
H is the height of the cliff,
u is the the initial velocity,
t is the time taken by the rock,
g is the acceleration due to gravity.
Putting values,
H = (8.01)(2.21) + 1/2(-9.8)(2.21)²
H = -6.22m.
The height of the cliff is 6.22 m.
(b) If the rock is thrown down with the same speed,
Then the time taken by it to reach the ground is,
t = u/g
Putting values,
t = 8.01/9.8
t = 0.81 seconds.
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a car company wants to ensure its newest model can stop in 50 m when traveling at 30 m/s (which is about 108 km/h). if we assume constant deceleration, find the value of deceleration that accomplishes this
A decrease in velocity is referred to as deceleration. If car is moving at 30 m/s and stop in 50 m .The value of deceleration is 11.56 ms−2.
How to calculate deceleration ?While acceleration is motion in which an object's speed varies every second, deceleration is motion that causes an object to slow down.
We are aware that acceleration refers to an object's rate of increase in speed, and deceleration refers to an object's rate of decrease in speed. For instance, when we apply the brakes while driving, we benefit from the vehicle's ability to decelerate and slow down.
The Deceleration Formula is the final velocity minus the initial velocity, with a negative sign in the result because the velocity is decreasing, if starting velocity, final velocity, and time taken are given.
velocity of car = 30 m/s
car need to stop in 50m
Deceleration a = v^2 – u^2 / 2s
= 0^2 - 50^2 / 2*30
= 11.56
Deceleration of the care = 11.56 ms−2
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A linear track begins at 0 meters and has a total distance of 100 meters to the finish line. Juliet starts at the 10-meter mark while practicing for a race.
A linear track beings at 0 meters and has a total distance of 100 meters, then she will go 55 meters. Hence, option D is correct.
What is speed?The pace at which the distance a moving item travels changes is measured as speed. Since speed is a scalar, it has quantity but no orientation as a unit of measurement.
Let A represent Juliet's position. O is the starting point with OA = 10, AB = 45, and OP = 100 as its coordinates.
The location of Juliet following running 45 meters will therefore be 55 m, as may be seen from simple math. In the figure, it is OB.
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Your question is not complete, your question probably be :
A linear track begins at 0 meters and has a total distance of 100 meters to the finish line. Juliet starts at the 10-meter mar
while practicing for a race.
After running 45 meters, how far is she from the beginning of the track?
10 meters
35 meters
45 meters
55 meters
suppose radius of earth known to 3595 miles with tolerance of - 0.1 miles what effect does this have on calculation of surface area
The effect of - 0.1 miles tolerance on a 3595 miles radius of earth's surface area calculation is 0.00556 %
SA = 4 π r²
SA = Surface area of a sphere
r = Radius
Actual surface area,
r = 3595 mi
SA = 4 * 3.14 * 3595²
SA = 162325754 mi²
Surface area with tolerance,
r = 3595 - 0.1
r = 3594.9 mi
SA = 4 * 3.14 * 3594.9²
SA = 162316723.5 mi²
% error = ( Actual value - Error value ) / Actual value
% error = ( 162325754 - 162316723.5 ) / 162325754
% error = 9030.5 / 162325754
% error = 5.56 * [tex]10^{-5}[/tex]
% error = 0.00556 %
Therefore, the effect of - 0.1 miles tolerance on a 3595 miles radius of earth's surface area calculation is 0.00556 %
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a heat exchanger has an effective area of 2500 cm2 and cools 1 kg/min of blood from 37 degrees celsius to 30 degrees celsius with a lmtd of 5.4 degrees. what is the overall heat transfer coefficient of the exchanger if the specific heat capacity of blood is 4177 j/kg-c.
The answer is 361 W/m2-C.
This approach is most commonly used when the building manager or engineer is trying to determine the heat transfer coefficient and outflow fluid temperature and already knows the heat exchanger size and inflow temperature. Subtract the end temperature from the start temperature to get the difference.
You can calculate the efficiency of anything by dividing the energy input and energy output by 100%. We usually use this equation to express energy as heat or electricity. For relatively low-pressure equipment, if the design pressure on the low side is more than two-thirds of the design pressure on the high side a full pipe rupture is not a realistic scenario.
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Michael uses his bike to apply 456 N to himself and the bike by pedaling as he approaches a 1.4 m tall ramp which is 3.0 m away. He starts from rest to accomplish this feat. How fast will he be moving just before he hits the ramp? (Mike and the bike have a combined mass of 136 kg)
*WORK OUT AND USE UNITS*
The speed of Mike and his bike before hitting the ramp is 4.48 m/s.
What is the acceleration of Michael and his bike?The acceleration of Michael and his bike is determined by applying Newton's second law of motion as follows.
According this law, the force applied to an object is directly proportional to the product of mass and acceleration of the object.
F = ma
a = F/m
where;
a is the acceleration of Michaelm is mass of Michaela = (456) / (136)
a = 3.35 m/s²
The speed of Mike and his bike before hitting the ramp is calculated as follows;
v² = u² + 2as
where;
u is the initial speed of Mike = 0a is acceleration of Mikev is the final velocity of Mikes is the distance travelled by Mikev² = 0 + 2(3.35)(3)
v² = 20.1
v = √20.1
v = 4.48 m/s
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Which will be attracted to (or repelled by) a magnet?
Check all that apply.
A. An electromagnet
B. An iron pipe
C. A copper wire not carrying current
D. A negatively charged piece of silver
E. An aluminum wire carrying current
Things which will be attracted to (or repelled by) a magnet are
An iron pipe
A negatively charged piece of silver
An aluminum wire carrying current
What is a repelling and attracting ?According to the "rule of attraction of magnets," magnets will attract one another when their south poles are brought near together. According to the "rule of magnet repulsion," magnets repel one another when their respective north poles are brought close to one another.
Electrostatic forces are responsible for the attraction and repulsion between charged objects. When two bodies are not in contact, electrostatic force can still be present.Learn more about Magnet here:
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Answer:
the answer should be: An Electromagnet, An Iron Pipe, and An Aluminum Wire Carrying Current
Explanation:
took the test
a rollercoaster cart with a total mass of 1,000kg is at the top of a hill moving at 2ms. assuming no friction and neglecting air resistance, what is the speed of the cart when it reaches the bottom of the hill, 30m below?
Using the supposition that there is no friction and disregarding air resistance, the speed of the cart at the bottom of the hill is 24.6ms.
What kind of forces does friction produce?Small bumps collide with one another as surfaces move over one another. Friction acts as a resisting force on the surface's motion. Friction can be reduced by lubricants.
What exactly are the rules of friction?The friction caused by a moving item is inversely propotional and runs perpendicular to it. The type of surface the thing is in touch with determines the amount of friction it experiences. As long as there is a point of contact, friction remains independent of a area of contact.
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for a double slit experiment, what is the smallest separation (in nm) between two slits that will produce a second-order maximum for 652 nm visible light?
The smallest separation in terms of nm between two slits that will produce a second-order maximum for 652 nm visible light is 1.30 um
Since the relationship between wavelength and angle for minima and maxima in Young's double slit experiment is:
For constructive interference
d sinθ = n
for Destructive interference
d sinθ = (n+1/2)λ, where λ is the wavelength, n is the order of maxima and minima, Since here n = 2
So the separation, λ = 652 nm , and θ = 90
so, d sin90 = 2*652*10⁻⁹
=> d= 2*652*10⁻⁹/ sin90
= 1.30 X10⁻⁶
= 1.30 цm
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Evidence card 2: Repelling magnets it was harder to push the magnets together as they got closer together.
What affects the amount of potential energy stored in the magnetic field when a magnet is moved against a magnetic force?
The thing that affects the amount of potential energy stored in the magnetic field when a magnet is moved against a magnetic force is by the strength of the magnet as well as the distance that another magnet or magnetic object is said to be from it.
What aspects of magnetic potential energy affect it?Potential energy between two magnets will depend on their orientation as well as their proximity to one another and their distance from one another. If the opposing poles are kept apart, the potential energy will increase with increasing distance and decrease with increasing proximity.
More energy is transferred to the magnetic field when an object is moved against a stronger magnetic force. Near magnets, magnetic forces are stronger.
Therefore, The power of the magnet and the separation from other magnets or magnetic objects have an impact on how much potential energy is held in the magnetic field.
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two sounds waves are traveling through an opera house. one wave was produced by a soprano, while a baritone produced the other. which sound wave travels faster?
The speed of each wave is identical. The only factor that affects how fast sound travels is the property of the medium.
What is sound wave?An example of an energy type that propagates through a medium using adiabatic loading and unloading is acoustic waves. Acoustic pressure, particle velocity, particle displacement, and acoustic intensity are crucial parameters for defining acoustic waves. Because the air molecules oscillate back and forth as the sound travels, we refer to sound as a wave. The way the air behaves is similar to a compression or longitudinal wave on a spring.
A sound wave is a pressure wave, which can be conceptualized as variations in pressure over time. Transverse waves include sound waves. The tines of a tuning fork must transfer air from the fork to one's ear in order for one to hear the sound of the fork.
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you place a large pebble in a slingshot, pull the elastic band back to your chin, and release it, launching the pebble horizontally at a speed of vv. you then repeat the exact same procedure (pulling the elastic band back the same distance) with a smaller pebble. the smaller pebble leaves the slingshot with a speed of 5v5v. how does the mass of the larger pebble compare to that of the smaller pebble?
The smaller pebble leaves the slingshot with a speed of 500 m/s.The mass of the larger pebble 25 times more mass compare to that of the smaller pebble.
In Both the cases work done by the elastic band is same i.e
WLarger = WSmaller
(1/2)MLargerVLarger2 = (1/2)MSmallerVSmaller2
MLarger/MSmaller = (VSmaller/VLarger)2
MLarger/MSmaller =(500/100)2 =25
Teenagers, young adults, and others utilise various stimulant medications collectively referred to as "speed" to feel more focused and alert, and occasionally to get euphoric. Additionally, some people take various forms of speed to suppress their appetite. You lack brute force, intimidation, and might without speed. Simply for show and to assist friends who are moving large pieces of furniture, they are useless. The good news is that speed can be improved with the right physical preparation. The velocity of a body or object determines the direction of its motion. Speed is often measured as a scalar value. The most basic definition of a vector quantity is velocity. It gauges the rate at which a distance varies. It relates to the speed at which displacement is altering. Its velocity is the speed at which something is travelling in a particular direction.
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This is the third time I’m asking, please, On a wet road, is a higher coefficient of friction on the tires safer or a lower one and pls explain I don’t get it
Answer:
higher is safer
Explanation:
because it is a wet slippery surface, you would need more friction on the tires, to get more traction in the slippery wet road, if you had low friction you would not move anywhere and or could swerve off somewhere
a 5.4 kg cat and a 2.4 kg bowl of tuna fish are at opposite ends of the 4.0 m -long seesaw. how far to the left of the pivot must a 4.0 kg cat stand to keep the seesaw balanced?
0.88m to the left, where the 4.0 kg cat must be to keep the seesaw balanced.
The concept of Torque and the principle of moment are applied here to understand that the 4.0 kg cat and the bowl of tuna fish will balance the seesaw as long as the 4.0 kg cat stays on the left of the pivot.
m (big cat) = 5.4 kg
m (bowl) = 2.4 kg
m (small cat) = 4.0 kg
From the figure,
5.4 kg x (x m) = 2.4kg x (2m)
x = 4.8 / 5.4
=> 0.88m
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you launch a projectile horizontally from a height of 0.85 m. the projectile travels a horizontal distance 1.8 m. with what speed (m/s) did you launch the projectile?
Speed (m/s) required to launch the projectile is 5.94m/s.
What constitutes speed?Speed is defined as the product of distance and the amount of time it took to cover that distance.
Equations,
Vx = Vxo
x = Vx × t
Vy = Vyo + gt
Vyo = 0
Vy = gt
y = yo - Vyo - gt² / 2
yo - y = gt²/ 2
time to get to the ground,
0.85 = g t² / 2
t² = 0.85m × 2 / 9.81 m/s²
t² =0.1732 s²
t = 0.416s.
initial velocity,
Vxo = x / t = 1.8m/ 0.416s =4.32m/s
speed before it strikes the ground,
Vy = g*t = 9.81 m/s × 0.416 = 4.08m/s
V² = Vy² + Vx² = (4.32 m/s)² + (4.08 m/s)² = 35.3064m²/s²
V = [tex]\sqrt{35.3064}[/tex]= 5.94m/s.
Speed required to launch the projectile is 5.94m/s.
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a migrating robin flies due north with a speed of 12 m/s relative to the air. the air moves due east with a speed of 6.3 m/s relative to the ground.what is the robin's speed relative to the ground?
The robin's speed relative to the ground 62.3 degrees north of east, or tan(12/6.3).
How to calculate the speed relative to the ground?Think about the X-east-west axis's direction and the Y-north-south axis's direction.
V ra = 12 j m/s is the speed of a migratory robin relative to the air.
(In which "j" denotes a unit vector in the Y direction)
V ag = air speed in relation to the ground = 6.3 I m/s
(Where I is an X-direction unit vector)
V rg = speed of migratory robin in relation to the ground =
utilizing the formula
V rg = V ra + V ag
= 12 j + 6.3 I
= 6.3 I + 12 j
magnitude: (13.6 m/s = sqrt[tex](6.3)^{2}[/tex] + ([tex](12)^{2}[/tex])
direction: 62.3 degrees north of east, or tan(12/6.3).
The robin's speed relative to the ground 62.3 degrees north of east, or tan(12/6.3).
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