A sample of dry gas is found to occupy 3.650 L at 22.0°C and 740.0 mmHg. How many moles of gas are present?
will mark brainliest

Answers

Answer 1

Answer:

0.147

Explanation

PV/RT


Related Questions

According to the kinetic molecular theory which substances are made of particles ?

Answers

Answer:

The kinetic molecular theory of matter states that: Matter is made up of particles that are constantly moving. All particles have energy, but the energy varies depending on the temperature the sample of matter is in. This in turn determines whether the substance exists in the solid, liquid, or gaseous state.

Explanation:

Kinetic molecular theory explains the properties of solids, liquids and gases. As per this theory, matter is made of particles.

What is kinetic theory?

Kinetic molecular theory explains the properties of different states of matter. According to this theory matter is made up of particles. But the theory is mostly applies for gases.

According to kinetic theory  of gases, gaseous substances consists of tiny spherical particles which are located apart from each other and hence no intermolecular force acts between them. They are in random motion and gains kinetic energy.

The kinetic energy of particles are temperature dependant and it increase as temperature rises. The collision between the particles and the particle and wall of the container in which they are will be elastic collision.

These concepts are  applicable only for ideal gases. An less applicable for other states of matter.

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Which best describes the total mass of substances before and after a
combustion reaction?
A. The mass is the same because atoms are not created or
destroyed.
B. The mass is greater after the reaction because the number of
atoms increases.
C. The mass is the same because the molecules do not change.
D. The mass is less after the reaction because gases are produced.

Answers

Answer:

B. The mass is greater after the reaction because the number of

atoms increases.

How many moles of Oxygen atoms are contained in 45.9 mol CO2?

Answers

Answer:

Explanation:

10 moles of oxygen atoms.\ \textbf{b)} 91.8 moles of oxygen at

1. Arrange the following groups in order of decreasing priority that would allow you to determine E/Z, or R/S. Provide a string of letters (e.g. abcd) as an answer with the highest priority listed first, lowest priority last:a) -CH3
b) -CH2OH
c) -CH2NH2
d) -CH2BR2. Arrange the following groups in order of decreasing priority that would allow you to determine E/Z, or R/S. Provide a string of letters (e.g. abcd) as an answer with the highest priority listed first, lowest priority last:a) -F
b) -CH2OH
c) -CHO
d) -CH3

Answers

Answer:

1. CH₂Br > CH₂OH > CH₂NH₂ > CH₃

2. -F > -CHO > - CH₂OH > CH₃

Explanation:

The arrangement of the above atom is due to their atomicity and electronegativity of the given compounds.

From (1) we will realize that Bromine (Br) possesses the greatest priority because its atomic number is the highest. This is followed by oxygen (O) in CH₂OH since atomic no 8 is higher than that of Nitrogen N(7). Lastly, CH₃ has the only hydrogen attached to it with the atomic no of (1)

In the second part of the question>

The electronegativity of an element increases across the period and down the group. Fluorine is highly electronegative and contains the highest atomic number of oxygen in -CHO. The oxygen (O) in -CHO has a double bond which gives an edge over the (O) in CH₂OH. Lastly, CH₃ contains a substituted hydrogen atom

Which of the compounds shown are structural
isomers of this compound? Check all that apply.
A
B
С
D

Answers

Answer:

A & C

Explanation:

The next one is A Edge 2022

The compound which are the structural isomers of the given compound is compound A & C.

What are structural isomers?

Structural isomers are those isomers in which which are having the same molecular formula but different structural structures.

Compound A: A is the structural isomer of the given compound as they both have same number of carbon and hydrogen atoms present in that.Compound B: B is not the structural isomer of the given ompound as they have not equal number of carbon and hydrogen atoms in it.Compound C: C is the structural isomer of the given compound as they both have same number of carbon and hydrogen atoms present in that.Compound D: D is not the structural isomer of the given ompound as they have not equal number of carbon and hydrogen atoms in it.

Hence A & C are the structural isomers of given compound.

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12 moles of sodium into grams

Answers

Answer:

12 moles sodium= 275.87724000000003 grams

Explanation:

1 moles sodium = 0.043497607849056.

determine the maximum amount of NaN03 that was produced during the experiment. Explain how you determined the amount

Answers

Answer:

9 moles of NaNO3 is obtained

Explanation:

The balanced chemical reaction equation for the reaction is;

Al(NO3)3 + 3NaCl-------> 3NaNO3 + AlCl3

Now, we have to determine the limiting reactant. The limiting reactant yields the least amount of NaNO3.

1 mole of Al(NO3)3 yields 3 moles of NaNO3

4 moles of Al(NO3)3 yields 4 * 3/1 = 12 moles of NaNO3

Also,

3 moles of NaCl yields 3 moles of NaNO3

9 moles of NaCl yields 9 * 3/3 = 9 moles of NaNO3

Hence, NaCl  is the limiting reactant and 9 moles of NaNO3 is obtained.

9 moles of NaNO₃ is obtained.

Balanced chemical reaction:

[tex]Al(NO_3)_3 + 3NaCl-----> 3NaNO_3 + AlCl_3[/tex]

From the reaction, it is seen that the limiting reactant yields the least amount of NaNO₃.

1 mole of Al(NO₃)₃ yields 3 moles of NaNO₃

4 moles of Al(NO₃)₃ yields 4 * 3/1 = 12 moles of NaNO₃

Also,

3 moles of NaCl yields 3 moles of NaNO₃

9 moles of NaCl yields 9 * 3/3 = 9 moles of NaNO₃

Hence, NaCl  is the limiting reactant and 9 moles of NaNO₃ is obtained.

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What will be volume of 20.0 g of CH4 gas at a pressure of 0.950 atm and temperature of 21.0 oc?Question 1 options:

A. 21.8 L
B. 31.8 L
C. 2.27 L
D. 4.27 L

Answers

The answer is (C) or (D)

Ammonia will decompose into nitrogen and hydrogen at high temperature. An industrial chemist studying this reaction fills a 5.0L flask with 4.5 atm of ammonia gas, and when the mixture has come to equilibrium measures the amount of nitrogen gas to be 1.1 atm. Calculate the pressure equilibrium constant for the decomposition of ammonia at the final temperature of the mixture. Round your answer to 2 significant digits.

Answers

Answer:

Kp = 7.4727

Explanation:

Let's write the balanced equilibrium reaction:

2NH₃ <-------> N₂ + 3H₂     Kp = ??

Now, if we want to calculate the Kp, we need to write an ICE chart with this reaction, which is the following:

         2NH₃ <-------> N₂ + 3H₂  

I.         4,5                 0        0

C.       -2x                +x     +3x

E.        4,5-2x            x       3x

According to this chart, the Kp expression should be:

Kp = (PH₂)³ * (PN₂) / (PNH₃)²   (1)

The value of x, we already know it because the problem states that the amount of nitrogen gas is 1.1 atm, so replacing this value into (1) we have:

Kp = (3*1.1)³ * (1.1) / (4.5 - (2 * 1.1))²

Kp = 39.5307 / 5.29

Kp = 7.4727

Hope this helps

What is the mass, in grams, of a piece of aluminum if its temperature changes from 25.0 ºC to 31.5 ºC when it absorbs 42.2 joules of energy? The specific heat for aluminum is 0.89J/gºC

Answers

Answer:

m = 7.29 grams

Explanation:

Given that,

Initial temperature, T₁ = 25ºC

Final temperature, T₂ = 31.5ºC

The specific heat of the metal is 0.89 J/gºC.

We know that the heat released due to the change in temperature is given by :

[tex]Q=mc\Delta T\\\\m=\dfrac{Q}{c\Delta T}\\\\m=\dfrac{42.2 }{0.89\times (31.5-25)}\\\\m=7.29\ g[/tex]

So, the mass of the piece is equal to 7.29 grams.

Calculate the specific heat of a substance given that 49 joules of heat is required to raise the temperature of 25.0 g of the substance from 92.6 ºC to 99.4 ºC.

Answers

Answer:

0.29 J/g.°C

Explanation:

Step 1: Given data

Added heat (Q): 49 JMass of the substance (m): 25.0 gInitial temperature: 92.6 °CFinal temperature: 99.4 °C

Step 2: Calculate the temperature change (ΔT)

ΔT = 99.4 °C - 92.6 °C = 6.8 °C

Step 3: Calculate the specific heat of the substance (c)

We will use the following expression.

Q = c × m × ΔT

c = Q / m × ΔT

c = 49 J / 25.0 g × 6.8 °C = 0.29 J/g.°C

Determine the number of molecules of C2CI4 contained in 73.1g of C2CI4

Answers

Answer:

2.35x10²³ molecules of C2Cl4 are present

Explanation:

To solve this question we must convert, as first, the mass of C2Cl4 to moles using its molar mass (C2Cl4 = 165.83g/mol). Then, using Avogadro's number we can find the number of molecules:

Moles C2Cl4:

73.1g * (1mol / 165.83g) = 0.441 moles C2Cl4

Molecules:

0.441 moles C2Cl4 * (6.022x10²³molecules / 1mol) =

2.35x10²³ molecules of C2Cl4 are present

What is the percent yield of a reaction producing 26g Iridium V Sulfate from 30g Lithium Sulfate and 30g Iridium V Carbonate?

Answers

The sulphate solutions came from a recycling LIBs waste cathode materials, which were done by previous research; their content is shown in Table 1 [18]. Sodium carbonate (Na2CO3) was purchased from Nihon Shiyaku Reagent, Tokyo, Japan (NaCO3, 99.8%), for the chemical precipitation. CO2 was purchased from Air Product and Chemical, Taipei, Taiwan (CO2 ≥ 99%), to carry out the hydrogenation–decomposition method. Dowex G26 was obtained from Sigma-Aldrich (St. Louis, MO, USA) and was used as a strong acidic cation exchange resin, to remove impurities. Multi-elements ICP standard solutions were acquired from AccuStandard, New Haven, Connecticut State, USA. The nitric acid (HNO3) and sulfuric acid (H2SO4) were acquired from Sigma-Aldrich (St. Louis, MO, USA) (HNO3 ≥ 65%) (H2SO4 ≥ 98%) The materials were analyzed by energy-dispersive X-ray spectroscopy (EDS; XFlash6110, Bruker, Billerica, MA, USA), X-ray diffraction (XRD; DX-2700, Dangdong City, Liaoning, China), scanning electron microscopy (SEM; S-3000N, Hitachi, Tokyo, Japan), and inductively coupled plasma optical emission spectrometry (ICP-OES; Varian, Vista-MPX, PerkinElmer, Waltham, MA, USA). In order to

Appl. Sci. 2018, 8, 2252 3 of 10
control the hydrogenation temperature and heating rate, a thermostatic bath (XMtd-204;

What is the initial and final mass of the zinc and copper?

Answers

Answer:the final mass of copper is  3.84 g. There was an increase in mass of 1.84 g from the initial mass of 2.0 g.

Explanation:

what is the percent composition of calcium fluoride

Answers

Answer:

78.07

Explanation:

them seperatly is

Calcium Ca 51.333%

Fluorine F 48.667%

A balloon is inflated with 1.25 L of helium at a temperature of 298K. What is
the volume of the balloon when the temperature is 310K?

Answers

Answer:

What is

the volume of the balloon when the temperature is 310K?

To obtain pure lead, lead (II) sulfide is burned in an atmosphere of pure oxygen. The products of the reaction are lead and sulfur trioxide (SO3). Write a balanced chemical equation for this process. How many grams of lead will be produced if 2.54 grams of PbS is burned with 1.88 g of O2? Express your answer to the correct number of significant figures. Be sure to show all steps completed to arrive at the answer. (Hint: be sure to work the problem with both PbS and O2).

Answers

Answer: 2.20 g Pb

They gave us the masses of two reactants and asked us to determine the mass of the product. We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.

Mᵣ:       239.27   32.00        207.2

           2PbS   +   3O₂   ⟶  2Pb   +   2SO₃

m/g:      2.54        1.88

What is the IUPAC name for the following compound?

a. benzenecarbonitrile
b. benzenecyanide
c. phenylcyanide
d. cyanophenyl

Answers

Answer:

Option a. Benzenecarbonitrile

Explanation:

You are not providing the picture of the compound. However, I manage to find the picture of it, so I'm gonna answer this with the picture. Its attached here at the end.

As for the IUPAC name of this compound, it would be Benzenecarbonitrile, or simply, benzonitrile.

This compound has the molecular formula C₆H₅CN. It receives this name over the other ones, because this is a aromatic cyanide, and aromatic cyanide has nitriles behavior, (Strength of the nitrogen over the carbon), therefore, this group has priority over the whole molecule. As the principal chain is the benzene, the carbonitrile is the radical of the group, and when cyano groups are as radical and not as principal chains, it has a behavior of nitrile, and it's named as nitrile. therefore, option b, cannot be the name.

phenylcyanide is naming the phenyl as radical, but the benzene is the principal group in this compound, and the cyanide is the radical. It happens the same thing with cyanophenyl.

Hope this helps

A helium-filled balloon contains 0.16 mol He at 101 kPa and a temperature of 23°C. What is
the volume of the gas in the balloon?

Answers

V = 3.9 L

Explanation:

Given:

T = 23°C + 273 = 296K

n = 0.16 mol He

P = 101 kPa = 0.997 atm

R = universal gas constant = 0.08205 L-atm/mol-K

V = ?

Using the ideal gas law,

PV = nRT

V = nRT/P

= (0.16 mil He)(0.08205 L-atm/mol-K)(296K)/(0.997 atm)

= 3.9 L

What is [H⁺] in a 0.330 M solution of acrylic acid, CH₂CHCOOH (Ka = 3.16 × 10⁻⁵)?

Answers

Answer:

[H⁺] = 3.23x10⁻³ M

Explanation:

For a weak monoprotic acid, such as acrylic acid, we can calculate [H⁺] using the following formula if the solution concentration is significantly higher than the Ka:

[H⁺] = √(C * Ka)

Where C is the weak acid concentration.

We input the data:

[H⁺] = [tex]\sqrt{0.330 M * 3.16x10^{-5}}[/tex]

And solve for [H⁺]:

[H⁺] = 3.23x10⁻³ M

What volume is occupied by 2.0 mol of gas at 3.0 atm
and 27 °C?

Answers

STP conditions imply a temperature of 273.15 K and a pressure of 100 kPa. When tose conditions are met, 1 mole of any ideal gas will have a volume of 22.7 L. So, if 1 mole occupies a volume of 22.7 L, 2 moles will occupy a volume twice as big. Likewise, 0.5 moles will occupy half the volume 1 mole occupies.

can someone answer this

Answers

The correct answer is B 25

2+4 help please i will fail 6th grade

Answers

Answer:

6

Explanation:

lol

Suppose you needed to explain the concept of the mole to a junior high school student. What would you tell them?

Answers

Answer:

Explanation:

duehgjvcujhyeq bvckjfdsaeb gjdksghUIBGREQWMNHGTRE BAGTFEQA

On the basis of the information above, what is the approximate percent ionization of HNO2 in a 1.0 M HNO2 (aq) solution?

Answers

Answer:

The answer is "2%"

Explanation:

Equation:

[tex]HNO_2\ (aq) \leftrightharpoons H^{+} \ (aq) + NO_2^{-}\ (aq) \\\\\ K_a = 4.0\times \ 10^{-4}[/tex]

[tex]H^{+}=?[/tex]

Formula:

[tex]Ka = \frac{[H^{+}][NO_2^{-}]}{[HNO_2]}[/tex]

Let

[tex][H^{+}] = [NO_2^{-}] = x[/tex] at equilibrium

[tex]x^2 = (4.0\times 10^{-4})\times 1.0\\\\x = ((4.0\times 10^{-4})\times 1.0)^{0.5} = 2.0 \times 10^{-2} \ M\\\\[/tex]

therefore,

[tex][H^{+}] = 2.0\times 10^{-2} \ M = 0.02 \ M[/tex]

Calculating the % ionization:

[tex]= \frac{([H^{+}]}{[HNO_2])} \times 100 \\\\= \frac{0.02}{1}\times 100 \\\\= 2\%\\\\[/tex]

The approximate percent ionization of HNO₂ in a 1.0 M HNO₂ (aq) solution is 2%.

How we calculate the % ionization?

% ionization of any compound will be calculated as follow:

% ionization = ([ion]/[acid or base]) ₓ 100

Given chemical reaction with ICE table will be represented as:

                           HNO₂(aq) → H⁺(aq) + NO₂⁻(aq)

initial                          1                0             0

change                      -x               +x           +x

equilibrium              1-x                x             x

Equilibrium constant will be represented as:
Ka = [H⁺][NO₂⁻] / [HNO₂]

Acid dissociation constant for HNO₂ = 4×10⁻⁴

Putting all values in the above equation, we get

4×10⁻⁴ = x² / 1-x

Value of changeable quantity is very less, so we neglect from the concentration of HNO₂.

4×10⁻⁴ = x²

x = 2 × 10⁻²

So, the concentration of H⁺ ion = 2 × 10⁻²M

Now we put all these values in the % ionization equation, we get

% ionization = (0.02/1) × 100 = 2%

Hence , % ionization is 2%.

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What answer is it and how ? please help !!!!!! ill mark brainlyest if right

Answers

Answer:

The answer is B

Brainliest please!

A certain reaction has an activation energy of 51.02 kJ/mol. At what Kelvin temperature will the reaction proceed 4.50 times faster than it did at 365 K

Answers

Answer:

[tex]T_2=400.73K[/tex]

Explanation:

From the question we are told that:

Activation energy [tex]E_a= 51.02 kJ/mol.=>51.02*10^3J/mol[/tex]

Reaction Ratio [tex]\triangle K=4.50[/tex]

Initial Temperature [tex]T_1=365K[/tex]

Generally the equation for Final Temperature [tex]T_2[/tex] is mathematically given by

 [tex]log \triangle K=\frac{E_a}{2.303R}*(\frac{T_2-T_1}{T_1T_2})[/tex]

Where

 [tex]R=Gas constant[/tex]

 [tex]R =8.3143[/tex]

Therefore

 [tex]log 4.50=\frac{51.2*10^3}{2.303*8.31432}*(\frac{T_2-365}{365*T_2})[/tex]

 [tex]log 4.50=7.328*\frac{T_2-365}{T_2}[/tex]

 [tex]0.0892=\frac{T_2-365}{T_2}[/tex]

 [tex]0.0892T_2=T_2-365[/tex]

 [tex]365=T_2-0.0892T_2[/tex]

 [tex]365=0.91T_2[/tex]

 [tex]T_2=\frac{365}{0.91}[/tex]

 [tex]T_2=400.73K[/tex]



Read about reverse osmosis and multistage flash distillation .Then identify at least three advantages and three

disadvantages for each process

Answers

Answer:

Meaning, Advantages & Disadvantages of - Osmosis, Multiflash Distillatiob

Explanation:

Osmosis is movement of solvent (like water) through semi permeable membrane (like living cell) into solution of higher solute concentration.

Advantages - It assists equalising concentration of solute on two sides of membrane. Reverse Osmosis is used for efficient water softening, it is easy to maintain.

Disadvantages - It needs a lot of energy. A lot of pressure is required for deionisation. Water acidity level increases, as minerals get deionised.

Multistage flash distillation refers to desalination water distilling seawater, by flashing water portions in steams in various stages of concurrent heat exchangers.

Advantages - Its Cost efficient , distillation uses waste heat. It has High gain output ratio. Quality of feedwater is less significant, compared to reverse osmosis.

Disadvantages - It has high operating cost in case of waste heat unavailability. High temperature imply high corrosion & scale formation.

When 1 mol of a nonvolatile, nondissociating solute is dissolved in 3 mol of volatile solvent, the ratio of vapor pressure of the solution to that of the pure solvent (at the same temperature) is approximately:________

Answers

Answer:

[tex]\frac{P_{solution}}{P_{solvent}^{vap}} =0.75[/tex]

Explanation:

Hello there!

In this case, since the solvation of a nonvolatile-nondissociating solute in a volatile solvent is modelled via the Raoult's law:

[tex]P_{solution}=x_{solvent}P_{solvent}^{vap}[/tex]

Thus, we can calculate the ratio of the vapor pressure of the solution to that of the pure solvent, mole fraction, as shown below:

[tex]x_{solvent}=\frac{P_{solution}}{P_{solvent}^{vap}} =\frac{n_{solvent}}{n_{solute}+n_{solvent}}[/tex]

Thus, we plug in the moles of solvent and solute to obtain:

[tex]\frac{P_{solution}}{P_{solvent}^{vap}} =\frac{3}{3+1}\\\\ \frac{P_{solution}}{P_{solvent}^{vap}} =0.75[/tex]

Regards!



When calcium forms an ion that has the same number of outer electrons as which noble gas?
1. neon
2. helium
3. argon
4. krypton

BRAINLIEST FOR HELP ASAP!!!!

Answers

The answer is 4 krypton
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