Answer: Initial Velocity = 2.8 km/h
Final Velocity = 32 km/h
Explanation:
What are the relationships between the different wave properties (frequency, wavelength, wave speed, period, amplitude)
Ex) As ___ increases, ___ increases/decreases/remains the same.
Answer:
As frequency (cycles per second) increases the wavelength decreases.
As frequency increases the period also decreases
If wave speed or velocity increases, so too does the frequency
Amplitude of a wave is totally independent of frequency, period etc. So it remains the same as frequency shifts. Like FM radio the amplitude remains the same as the frequency of the broadcast modulates.
Explanation:
F= 1/t Frequency is inversely proportional to time (wavelength)
Period is the time it takes for one wave cycle to complete Period is 1/f
++++++++++++++++++++++++++++++++++++
vw=λT Speed of propagation vw= wavelength x T time
vw=fλ Knowing frequency multiply times wavelength to get wave speed.
++++++++++++++++++++++++++++++++
Amplitude varies only as the energy applied varies. Like transmission power, in a 60 hz power feed the amplitude can be 120, 230, 460 volts (note these nominal amplitudes are RMS root mean squared or .707 of the peak of the waveform).
See link below, images are much easier to process, than plain text of course. Hope this helps.
Oops not allowed to post a link, it appears. so try the snippet of URL as attached.
Answer:
Im no expert buh its Wave length. :)
Explanation:
Im taking a test about it hope it helps.
A boy is going down a slide. As he reaches the bottom, friction causes him to slow down and stop. Which one of Newton's laws is this?
2nd law
3rd law
1st law
4th law
The given condition satisfies the Newton's First Law of motion. Hence, option (C) is correct.
Given data:
A boy slides down and friction causes him to slow down and stop.
In the given problem, when boy was sliding down, then he was in the state of motion, such that the when the he reaches at the bottom of hill, the friction plays the role of external agent to stop its motion.
This shows that the first law of motion is clearly followed which says that, "If an object is in motion, then it will be in motion until and unless any external force is applied on it". This is also known as law of inertia.
Thus, we can conclude that the given condition satisfies the Newton's First Law of motion. Hence, option (C) is correct.
Learn more about the Newton's first law of motion here:
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whu is it important to mave regular supervision of weights and measurements in the market
Answer:
Hope the answer helped you. if yes pls follow me
Explanation:
the fundamental answer is without regular supervision of definition of weights and measures,commerce exchange will be impossible and there would be no market whatsoever for anything.
Answer:
the fundamental answer is without regular supervision of definition of weights and measures,commerce exchange will be impossible and there would be no market whatsoever for anything.
Explanation:
"who"
Which of the following individuals would be best classified as being in identity diffusion?
A.
Pauline isn’t interested in politics because she’d like to enjoy being a kid longer.
B.
Richard has decided to become a Democrat after much soul searching.
C.
Maria has adopted her parents’ identification as Protestant without considering other options.
D.
Pierce is trying many different identities but hasn’t decided on one yet.
Answer: C
Explanation: after reading it over and over shes the most reasonable. But I could be wrong so be cautious.
According to the question, Maria would be best classified as being in identity diffusion. So, option (C) is correct answer.
What is identity diffusion?
People who are experiencing identity diffusion haven't chosen an ideological or occupational route for the future and aren't making any effort to do so. Identity diffusion occurs during adolescence, a time when individuals are attempting to define their identities, but it can also last into adulthood.
When a person isn't actively forming an identity or committing to one, identity diffusion happens.Many people go through a phase of identity diffusion in their early years of adolescence or in childhood, which they eventually grow out of. Long-term identity diffusion is yet conceivable.James Marcia created four "identity statuses" in the 1960s, and identity diffusion is one of them. These identity statuses are a continuation of Erik Erikson's research on the formation of teenage identities.In the question, Maria has adopted her parents’ identification as Protestant without considering other options. She haven't chosen an ideological or occupational route for the future and aren't making any effort to do so. So, Maria would be best classified as being in identity diffusion.
To learn more about identity diffusion, refer the link:
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The Earth’s ________________ on its ________ causes day and night.
Answer:
1. rotation. 2. axis
Explanation:
The Earths rotation on its axis causes day and night
A car traveling 60 miles west (-) stops and then travels another 20 miles
west (-). The car then loops around and travels back to the east (+) a total
of 10 miles. What is the displacement of the car?*
Answer:
128
Explanation:
One clomiter is 1.06 multipled by 80
An object is dropped from 20. meters above the moon. The acceleration due to gravity on the moon is 1.62 m/s^2
a. How long does it take for the object to impact the moon?
b. At what speed does it impact the moon?
Answer:
a. Approximately 3.21 seconds
b. Approximately 5.196 m/s
Explanation:
a. The height from which the object is dropped = 20 meters
The location of the occurrence = The moon
The acceleration due to gravity on the moon = 1.62 m/s²
The time it took the object to to impact the moon is given by the equation of free fall as follows;
h = 1/2·a·t²
Where;
h =The height from which the object is allowed to freely fall = 20 meters
a = The acceleration due to gravity on the moon = 1.62 m/s²
t = The time of motion of the object
Substituting the values, gives;
20 = 1/2 × 1.62 × t²
t² = 20/(1.2 × 1.62) ≈ 10.23 s²
t = √ 10.23 ≈ 3.21 s
The time in motion of the object before impact, t = 3.21 seconds
b. The final speed, v is given from the equation for speed under free fall, which is presented as follows;
v = u + a·t
Where
u = The initial vertical velocity = 0
Substituting the values gives;
v = 0 + 1.62 × 3.21 ≈ 5.196 m/s
The final speed, v with which the object impacts the moon ≈ 5.196 m/s
III.
Solve:
1. An elephant puts a force of 30000N on its four feet, which have a total area of
750cm. What is the pressure exerted by the elephant on the
ground?
please explain T-T
A 5000 kg truck and a 1000 kg car are traveling at constant speeds when they collide. What is true about the forces and accelerations on each?
Force is the physical action that can give acceleration to a body upon which it is applied
The true statements about the forces and accelerations of each when they collide are;
The force acting on the truck is equals the reactive force of the car The acceleration of the car is five times the acceleration of the truckThe reasons why the above statements are true are given as follows:
Known:
Mass of the truck, m₁ = 5,000 kg
Mass of the car, m₂ = 1,000 kg
Velocity of the truck = [tex]v_t[/tex]
Velocity of the car = [tex]v_c[/tex]
According to Newton's third law of motion, action and reaction are equal and opposite
The force applied by the truck, F = The reactive force by the carForce, F = Mass, m × Acceleration, a
Let a₁ represent the acceleration of the truck and let a₂ represent the acceleration of the car, we have;
F = 5,000 × a₁ = 1,000 × a₂
[tex]a_2 = \dfrac{5,000 \ kg}{1,000 \ kg} \times a_1 = 5 \cdot a_1[/tex]
Therefore;
The acceleration (rate of change of velocity) of the car, a₂ due to the collision is five times the acceleration of the truck due to the collisionLearn more about the about force and acceleration here:
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a child riding a bicycle at 15 meters per second accelerates at -3,0 meters per second? for 4.0 seconds. What is the child's speed A at the end of this 4.0-second interval? (with work, all steps))
Answer:
27m/sExplanation:
Given data
initital velocity u=15m/s
deceleration a=3m/s^2
time t= 4 seconds
final velocity v= ?
Applying the expression
v=u+at------1
substituting our data into the expression we have
v=15+3*4
v=15+12
v=27m/s
The velocity after 4 seconds is 27m/s
5.Projectile motion is free fall with an initial horizontal velocity. True or false
Explanation:
One of the interesting things about projectile motion is that the horizontal motion is independent of the vertical motion. Recall that in freefall, an object continually experiences a downward acceleration of 9.80ms2 but has no horizontal acceleration.
Remi travels 160 meters in 4 seconds. What was Remi's initial speed if her final velocity was 6.9 m/s?
Answer:
73.1 m/s
Explanation:
Given:
Δx = 160 m
v = 6.9 m/s
t = 4 s
Find: v₀
Δx = ½ (v + v₀) t
160 m = ½ (6.9 m/s + v₀) (4 s)
v₀ = 73.1 m/s
When converting from smaller to larger units the decimal point travels right *
Answer:
False, it travels left.
Explanation:
Hello.
In this case, we can answer this with an example. If we have 200 g and we want that value in a larger unit, for instance, kilogram, the following conversion is performed since 1 kg equals 1000 g:
[tex]200g*\frac{1kg}{1000kg}=0.200g[/tex]
Whereas we needed to move the decimal point from right to left, which means that it travels left, that is why the statement is false.
Best regards.
The upward force on a car that is falling off a cliff is what?
a. air resistance
b. momentum
c. inertia
d. terminal velocity
Answer:
A. air resistance
Explanation:
I think so
A portable electric saw is used to cut through a wooden log. What happens to the pitch of the sound from the saw as the blade cuts farther into the log? Why?
PLEASE HELP ME FAST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Answer:
Basketball has a mass of 0.1kg
m = 0.1 kg
The basket ball is moving at constant speed, this shows that it is not accelerating. So, acceleration is zero
a = 0m/s²
The constant speed is 6m/s
v = 6m/s
So, force to keep it moving with this constant speed can be calculated using Newton second law of motion
F = ma
F = m × 0
F = 0N
So, since the basket ball is moving at constant speed, then, the force need to keep the ball moving is 0N.
Which quantity is a vector?
displacement
distance
19. Calculate the work done when a 30 N force pushes a rock 10 m. a) 3J b) 0.33 J c) 40 J d) 300 J
20. How far did a rock move if a force of 200 N moved it doing 100 J of work? a) 2 m b) 0.5 m c) 20,000 m d) 300 m
21. An explosion of gas from a Hawaiian volcano blows a rock into the sky. the rock has 2000J of kinetic energy. What was its mass if the rock had a velocity of 20m/s. a) 200Kg b) 20,000Kg c) 10Kg d) 200Kg
22. How much potential energy does a 2 kg book have if it is 2 meters from the ground? a) 39.2J b) 12 J c) 19.6 J d) 98 J
23. 45J of work were done on the object that moved 5M. How much force was applied to the object? a) 8N b) 9N c) 225N d) ON
24. If you do 40 joules of work lifting a 10N box, how high is the shelf you move it to. a) 400m b) 50m c) 40m d) 4m
25. A force of 100 newtons was necessary to lift a rock. A total of 150 joules of work was done. How far was the rock lifted? a) 1.5 m b) 15 m c) 0.15 m d) 150 m
19. Calculate the work done when a 30 N force pushes a rock 10 m. a) 3J b) 0.33 J c) 40 J d) 300 J
20. How far did a rock move if a force of 200 N moved it doing 100 J of work? a) 2 m b) 0.5 m c) 20,000 m d) 300 m
21. An explosion of gas from a Hawaiian volcano blows a rock into the sky. the rock has 2000J of kinetic energy. What was its mass if the rock had a velocity of 20m/s. a) 200Kg b) 20,000Kg c) 10Kg d) 200Kg
22. How much potential energy does a 2 kg book have if it is 2 meters from the ground? a) 39.2J b) 12 J c) 19.6 J d) 98 J
23. 45J of work were done on the object that moved 5M. How much force was applied to the object? a) 8N b) 9N c) 225N d) ON
24. If you do 40 joules of work lifting a 10N box, how high is the shelf you move it to. a) 400m b) 50m c) 40m d) 4m
25. A force of 100 newtons was necessary to lift a rock. A total of 150 joules of work was done. How far was the rock lifted? a) 1.5 m b) 15 m c) 0.15 m d) 150 m19. Calculate the work done when a 30 N force pushes a rock 10 m. a) 3J b) 0.33 J c) 40 J d) 300 J
20. How far did a rock move if a force of 200 N moved it doing 100 J of work? a) 2 m b) 0.5 m c) 20,000 m d) 300 m
21. An explosion of gas from a Hawaiian volcano blows a rock into the sky. the rock has 2000J of kinetic energy. What was its mass if the rock had a velocity of 20m/s. a) 200Kg b) 20,000Kg c) 10Kg d) 200Kg
22. How much potential energy does a 2 kg book have if it is 2 meters from the ground? a) 39.2J b) 12 J c) 19.6 J d) 98 J
23. 45J of work were done on the object that moved 5M. How much force was applied to the object? a) 8N b) 9N c) 225N d) ON
24. If you do 40 joules of work lifting a 10N box, how high is the shelf you move it to. a) 400m b) 50m c) 40m d) 4m
25. A force of 100 newtons was necessary to lift a rock. A total of 150 joules of work was done. How far was the rock lifted? a) 1.5 m b) 15 m c) 0.15 m d) 150 m19. Calculate the work done when a 30 N force pushes a rock 10 m. a) 3J b) 0.33 J c) 40 J d) 300 J
20. How far did a rock move if a force of 200 N moved it doing 100 J of work? a) 2 m b) 0.5 m c) 20,000 m d) 300 m
21. An explosion of gas from a Hawaiian volcano blows a rock into the sky. the rock has 2000J of kinetic energy. What was its mass if the rock had a velocity of 20m/s. a) 200Kg b) 20,000Kg c) 10Kg d) 200Kg
22. How much potential energy does a 2 kg book have if it is 2 meters from the ground? a) 39.2J b) 12 J c) 19.6 J d) 98 J
23. 45J of work were done on the object that moved 5M. How much force was applied to the object? a) 8N b) 9N c) 225N d) ON
24. If you do 40 joules of work lifting a 10N box, how high is the shelf you move it to. a) 400m b) 50m c) 40m d) 4m
25. A force of 100 newtons was necessary to lift a rock. A total of 150 joules of work was done. How far was the rock lifted? a) 1.5 m b) 15 m c) 0.15 m d) 150 m
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where is the image located when an objectis placed 30cm from a convex lens with a focal length of 10cm?
Answer:
15 cm
Explanation:
using the thin lens formula for convex lens
[tex]\frac{1}{f} = \frac{1}{p} + \frac{1}{q}\\ \\where f = focal length \\ p = object distance \\ q = image distance\\[/tex]
so,
[tex]\frac{1}{q} = \frac{1}{f} - \frac{1}{p} \\\\\frac{1}{q} = \frac{1}{10} - \frac{1}{30} \\\frac{1}{q} = \frac{2}{30}\\\frac{1}{q} = \frac{1}{15cm}[/tex]
so,
q = 15 cm
Who is Josh Gibson write a short paragraph 3-5 sentences
Answer:
Hope this helps
Explanation:
Josh Gibson, (born December 21, 1911, Buena Vista, Georgia, U.S.—died January 20, 1947, Pittsburgh, Pennsylvania), American professional baseball catcher who was one of the most prodigious home run hitters in the game’s history. Known as “the black Babe Ruth,” Gibson is considered to be the greatest player who never played in the major leagues, there being an unwritten rule (enforced until the year of his death) against hiring black ballplayers
The drawing shows a 26.1-kg crate that is initially at rest. Note that the view is one looking down on the top of the crate. Two forces, and , are applied to the crate, and it begins to move. The coefficient of kinetic friction between the crate and the floor is k = 0.347. Determine the (a) magnitude and (b) direction (relative to the x axis) of the acceleration of the crate.
Answer:
(a). The magnitude of the acceleration of the crate is 1.44 m/s².
(b). The direction of the crate is 34.60°.
Explanation:
Given that,
Mass of crate = 26.1 kg
Coefficient of kinetic friction = 0.347
We need to calculate the resultant force
Using figure
[tex]F'=\sqrt{(F_{x}+F_{z})^2+F_{y}^2}[/tex]
Put the value into the formula
[tex]F'=\sqrt{(88\cos{55}+54)^2+(88\sin 54)^2}[/tex]
[tex]F'=126.4\ N[/tex]
(a). We need to calculate the acceleration of the crate
Using formula of sum of force
[tex]\sum{F}=F'-\mu N[/tex]
[tex]ma_{total}=F'-\mu mg[/tex]
[tex]a_{total}=\dfrac{F'}{m}-\mu g[/tex]
Put the value into thr formula
[tex]a_{total}=\dfrac{126.4}{26.1}-0.347\times9.8[/tex]
[tex]a_{total}=1.44\ m/s^2[/tex]
(b). We need to calculate the direction
Using formula of the direction
[tex]\theta=\tan^{-1}(\dfrac{F_{y}}{F_{x}+F_{z}})[/tex]
Put the value into the formula
[tex]\theta=\tan^{-1}(\dfrac{88\sin55}{88\cos55+54})[/tex]
[tex]\theta=34.60^{\circ}[/tex]
Hence, (a). The magnitude of the acceleration of the crate is 1.44 m/s².
The direction of the crate is 34.60°.
The cat quickly hopped from the floor onto the couch.
is an example of what? position, motion, speed, velocity or acceleration
Answer: Motion
Explanation:
what the difanshon of mass?
Answer:
Mass is a measure of the amount of matter in an object.
Explanation:
based on the information given, which part of inverstigation 2 is most likely the independent variable
Answer:
The independent variable is the variable that is changing.
Explanation:
I gave you this because you did not give us the work for use to see.
Can someone help me please, thanks.
Answer:
rotation
Explanation:
Im pretty sure. Please heart and mark brainliest
Answer:
cycle
Explanation:
either rotation or cycle. I would think.
An object falls from the Transco Tower in Houston and takes 15 seconds to reach the ground. How tall is the building:
Answer: 1102.5 meters
Explanation:
Dos masas de 8kg es tan unidas en el extremo de una varilla de aluminio de 400mm de longitud. La varilla está sostenida en su parte media hora en círculos y solo puede soportar una tensión máxima de 800 N ¿cuál es la frecuencia máxima de revolución
Answer:
The maximum frequency of revolution is 3.6 Hz.
Explanation:
Given that,
Mass = 8 kg
Distance = 400 mm
Tension = 800 N
We need to calculate the velocity
Using centripetal force
[tex]F=\dfrac{mv^2}{r}[/tex]
Where, F= tension
m = mass
v= velocity
r = radius of circle
Put the value into the formula
[tex]800=\dfrac{8\times v^2}{200\times10^{-3}}[/tex]
[tex]v^2=\sqrt{\dfrac{800\times200\times10^{-3}}{8}}[/tex]
[tex]v=4.47\ m/s[/tex]
We need to calculate the maximum frequency of revolution
Using formula of frequency
[tex]f=\dfrac{v}{2\pi r}[/tex]
Put the value into the formula
[tex]f=\dfrac{4.47}{2\pi\times200\times10^{-3}}[/tex]
[tex]f=3.6\ Hz[/tex]
Hence, The maximum frequency of revolution is 3.6 Hz.
To determine the height of a bridge above the water, a person drops a stone and measures the time it takes for it to hit the water. If the time is 2.3 s, what is the height of the bridge? Neglect air resistance.
a. 32 m
b. 52 m
c. 26 m
d. 14 m
e. 10 m
A stone dropped from a 26 m bridge, takes 2.3 s to reach the water.
A stone is dropped from a bridge and it experiences a uniformly accelerated rectilinear motion. It takes 2.3 s for the stone to reach the water.
We can calculate the height of the bridge, which is equal to the displacement of the stone, using the following kinematic equation.
[tex]s = ut + \frac{1}{2} a t^{2} = (0m/s)(2.3 s) + \frac{1}{2} (9.8m/s^{2} ) (2.3s)^{2} = 26 m[/tex]
where,
s: displacementu: initial speed (0 m/s)t: timea: acceleration due to gravity (9.8 m/s²)A stone dropped from a 26 m bridge, takes 2.3 s to reach the water.
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please type any energy transformation it will help a lot i would really appreciate it
prize: brainliest
Answer:
in electric lamp
Electric Energy to Heat and Light Energy
Explanation:
Answer:
Ex: an electric fan transforms electric energy to kinetic energy
Or
Chemical energy to heat and light energy
Explanation:
Hope this helps
A student stands on a spring scale. The scale reads that her weight is 600
Newtons. What is the student's approximate mass?
Answer:
61.2
Explanation:
F=g.m
<=> 600 = 9.8m
<=> m = 61.224489...