A simple random sample of 44 adults is obtained from a normally distributed​ population, and each​ person's red blood cell count​ (in cells per​ microliter) is measured. The sample mean is 5.31 and the sample standard deviation is 0.51 . Use a 0.05 significance level and the given calculator display to test the claim that the sample is from a population with a mean less than 5.4 comma which is a value often used for the upper limit of the range of normal values. What do the results suggest about the sample​ group?

Answers

Answer 1

Answer:

There is not enough evidence to support the claim that the population mean is significantly less than 5.4.

This result suggest we may be making a Type II error, where a true alternative hypothesis does not have enough evidence to be supported.

If the same outcome would have been obtained with a bigger sample size, the power of the test is bigger and there is a higher probability of rejecting the null hypothesis.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the population mean is significantly less than 5.4.

Then, the null and alternative hypothesis are:

[tex]H_0: \mu=5.4\\\\H_a:\mu< 5.4[/tex]

The significance level is 0.05.

The sample has a size n=44.

The sample mean is M=5.31.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=0.51.

The estimated standard error of the mean is computed using the formula:

[tex]s_M=\dfrac{s}{\sqrt{n}}=\dfrac{0.51}{\sqrt{44}}=0.077[/tex]

Then, we can calculate the t-statistic as:

[tex]t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{5.31-5.4}{0.077}=\dfrac{-0.09}{0.077}=-1.171[/tex]

The degrees of freedom for this sample size are:

[tex]df=n-1=44-1=43[/tex]

This test is a left-tailed test, with 43 degrees of freedom and t=-1.171, so the P-value for this test is calculated as (using a t-table):

[tex]\text{P-value}=P(t<-1.171)=0.124[/tex]

As the P-value (0.124) is bigger than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the population mean is significantly less than 5.4.

This result suggest we may be making a Type II error, where a true alternative hypothesis does not have enough evidence to be supported.

If the same outcome would have been obtained with a bigger sample size, the power of the test is bigger and there is a higher probability of rejecting the null hypothesis.


Related Questions

Suppose that a certain brand of light bulb has a mean life of 450 hours and a standard deviation of 73 hours. Assuming the data are bell-shaped: (Show work to get full credit)
a. Would it be unusual for a light bulb to have a life span of 320 hours? 615 hours? Justify each response.
b. According to the Empirical Rule, 99.7% of the light bulbs have a lifetime between what two values?
c. Determine the percentage of light bulbs that will have a life between 304 and 596 hours.

Answers

Answer:

yes it is correct

Step-by-step explanation:

plz give brainliest.

Average rate of change from G from x=1 to x=4 is

Answers

Answer:

3

Step-by-step explanation:

minus the variable, 4-1 is 3.

A chemist wishes to test the effect of four chemical agents on the strength of a particular type of cloth. Because there might be variability from one bolt to another, the chemist decides to use a randomized block design, with the bolts of cloth considered as blocks. She selects five bolts and applies all four chemicals in random order to each bolt. The resulting tensile strengths follow. Analyze the data from this experiment (use α = 0.05) and draw appropriate conclusions.



Bolt


Chemical 1 2 3 4 5


1 73 68 73 71 67


2 73 67 75 72 70


3 75 68 78 73 68


4 73 71 75 75 69

Answers

Answer:

p > α

0.7038 > 0.05

Also since F < F critical

0.475 < 3.238

We failed to reject H₀

We do not have significant evidence at the given significance level to show that there is a difference among the four chemical agents on the strength of a particular type of  cloth.

Step-by-step explanation:

We are given that a chemist wishes to test the effect of four chemical agents on the strength of a particular type of  cloth.

Since we are given data for four independent chemical agents to determine the effect on the strength of a particular type of cloth, therefore, a one-way analysis of variance may be used for the given problem.

ANOVA:

The one-way analysis of variance (ANOVA) may be used to find out whether there is any significant difference between the means of two or more independent categories of data.

Set up hypotheses:

Null hypotheses = H₀: μ₁ = μ₂ = μ₃ = μ₄

Alternate hypotheses = H₁: μ₁ ≠ μ₂ ≠ μ₃ ≠ μ₄

Set up decision rule:

We Reject H₀ if p ≤ α

OR

We Reject H₀ if F > F critical

ANOVA in Excel:

Step 1:

In the data tab, select data analysis

Step 2:

Select "Anova single factor" from the analysis tools

Step 3:

Select the destination of input data in the "input range"

Step 4:

Select "rows" for the option "Group By"

Step 5:

Tick the option "labels in first row"

Step 6:

Set alpha = 0.05

Step 7:

Select the destination of output data in the "output options"

Conclusion:

Please refer to the attached results.

The p-value is found to be

p = 0.7038

The F value is found to be

F = 0.475

The F critical value is found to be

F critical = 3.238

Since p > α

0.7038 > 0.05

We failed to reject H₀

Also since F < F critical

0.475 < 3.238

We failed to reject H₀

We do not have significant evidence at the given significance level to show that there is a difference among the four chemical agents on the strength of a particular type of cloth.

The steps to prove the Law of Sines with reference to ∆ABC are given. Arrange the steps in the correct order.

Answers

1). Draw a perpendicular from point A to side BC. Let AD = h

2). sin A = h/c and sin C = h/a

3). h = c Sin A, h = a sin C

4). c Sin A =a sin C

5). Divide both side by Sin A * Sin C

6). c Sin A/(Sin A * Sin C) =a sin C/(Sin A * Sin C)

7). c/sin C = a/Sin A

8). Similarly prove that,  c/sin C = b/Sin B

9).  c/sin C =  b/Sin B = a/Sin A

correct on plato

15 3/4 is what decimal

Answers

The answer is 15.75
3/4 = .75
15 + .75 = 15.75!
Hope this helped!

Brainly is much appreciated!

━━━━━━━☆☆━━━━━━━

▹ Answer

15.75

▹ Step-by-Step Explanation

3 ÷ 4 = .75

15 + .75 = 15.75

Hope this helps!

- CloutAnswers ❁

Brainliest is greatly appreciated!

━━━━━━━☆☆━━━━━━━

8716 no es divisible por 4

Answers

Answer:

False

Step-by-step explanation:

No esta verdad.

8716/4 = 2179 (divisible por 4)

the bus fare in a city is $2.00. people who use the bus have the option of purchashing a monthly coupoun book is $20.00. with the copoun bok, the fare is reduced to $1.00 Determine the number of times in a month the bus be used so that the total monthly cost without the coupon book is the same as the total monthly cost with the coupon book

Answers

Answer:

but I can do it if you want but I don't you too too y u your help and you have time can you

Step-by-step explanation:

guy who was it that you are not going to be able to make it to the meeting tonight but I can tomorrow if you have time can you come to my house

Identify the slope and y-intercept of the line −2x+5y=−30.

Answers

Answer:

slope = 2/5   ,    y-intercept = -30

Step-by-step explanation:

-2x + 5y = -30

5y  = 2x - 30

y = 2/5x - 6

we know that the general form is:

y = (slope)*x + (y- intercept)

so, from our equation, we can say that...

slope = 2/5

y- intercept = -30

: Bobby's Burger Palace had its
grand opening on Tuesday,
They had 164 1/2 lb of ground
beef in stock. They had 18 1/4
Ib left at the end of the day.
Each burger requires 1/4 lb of
ground beef. How many
hamburgers did they sell?

Answers

Answer: 585 burgers

Explanation:
164 1/2 = 329/2
18 1/4 = 73/4

Find the amount used:
329/2 - 73/4
= 658/4 - 73/4
= 585/4

Find the amount of burger made:

585/4 divide by 1/4
= 585/4 x 4/1
= 585

g Steel used for water pipelines is often coated on the inside with cement mortar to prevent corrosion. In a study of the mortar coatings of the pipeline used in a water transmission project in California, researchers noted that the mortar thickness was specified to be 7/16 inch. A very large sample of thickness measurements produced a mean equal to 0.635 inch and astandard deviation equal to 0.082 inch. If the thickness measurements were normally distributed, approximately what proportion were less than 7/16 inch?

Answers

Answer:

[tex]P(X<0.4375)=P(\frac{X-\mu}{\sigma}<\frac{0.4375-\mu}{\sigma})=P(Z<\frac{0.4375-0.635}{0.082})=P(z<-2.41)[/tex]

And we can find this probability using the z table and we got:

[tex]P(z<-2.41)=0.0080[/tex]

Step-by-step explanation:

Let X the random variable that represent the thickness of a population, and for this case we know the distribution for X is given by:

[tex]X \sim N(0.635,0.082)[/tex]  

Where [tex]\mu=0.635[/tex] and [tex]\sigma=0.032[/tex]

We are interested on this probability

[tex]P(X<0.4375)[/tex]

And the best way to solve this problem is using the normal standard distribution and the z score given by:

[tex]z=\frac{x-\mu}{\sigma}[/tex]

If we apply this formula to our probability we got this:

[tex]P(X<0.4375)=P(\frac{X-\mu}{\sigma}<\frac{0.4375-\mu}{\sigma})=P(Z<\frac{0.4375-0.635}{0.082})=P(z<-2.41)[/tex]

And we can find this probability using the z table and we got:

[tex]P(z<-2.41)=0.0080[/tex]

A statistics tutor wants to assess whether her remedial tutoring has been effective for her five students. She decides to conduct a related samples t-test and records the following grades for students prior to and after receiving her tutoring.
Tutoring
Before After
2.4 3.1
2.5 2.8
3.0 3.6
2.9 3.2
2.7 3.5
Test whether or not her tutoring is effective at a 0.05 level of significance. State the value of the test statistic. (Round your answer to three decimal places.)
t =
Compute effect size using estimated Cohen's d. (Round your answer to two decimal places.)
d =

Answers

Answer:

The test statistic value is, t = -5.245.

The effect size using estimated Cohen's d is 2.35.

Step-by-step explanation:

A paired t-test would be used to determine whether the remedial tutoring has been effective for the statistics tutor's five students.

The hypothesis can be defined as follows:

H₀: The remedial tutoring has not been effective, i.e. d = 0.

Hₐ: The remedial tutoring has been effective, i.e. d > 0.

Use Excel to perform the Paired t test.

Go to Data → Data Analysis → t-test: Paired Two Sample Means

A dialog box will open.

Select the values of the variables accordingly.

The Excel output is attached below.

The test statistic value is, t = -5.245.

Compute the effect size using estimated Cohen's d as follows:

[tex]\text{Cohen's d}=\frac{Mean_{d}}{SD_{d}}[/tex]

                [tex]=\frac{0.54}{0.23022}\\\\=2.34558\\\\\approx 2.35[/tex]

Thus, the effect size using estimated Cohen's d is 2.35.

A farmer is tracking the number of soybeans his land is yielding each year. He finds that the function f(x) = −x2 + 20x + 100 models the crops in pounds per acre over x years. Find and interpret the average rate of change from year 10 to year 20.

Answers

Answer:

The farmer should expect to LOSE 10 pounds of soybeans per acre per year

Step-by-step explanation:

f(x)=-x^2 + 20x + 100

just find how many soybeans his land will yield (per acre) after 10 and 20 years:

After 10: 200 pounds of soybeans/acre

After 20: 100 pounds of soybeans/acre

Because 10 years have passed and they lost 100 pounds of soybean production per acre, the farmer should expect to lose 10 pounds of soybeans per acre per year (-10 pounds of soybeans per acre/year)

pls help me pls pls​

Answers

Answer:

B

Step-by-step explanation:

the slope of parallel lines are equal

Which equation should be used to find the volume of the figure?

V=1/3(10)(6)(12)
V=1/2(10)(6)(12)
V=1/3(10)(6)(13)
V=1/2(10)(6)(13)

Answers

Answer:

The answer is option 1.

Step-by-step explanation:

Given that the volume of pyramid formula is:

[tex]v = \frac{1}{3} \times base \: area \times height[/tex]

The base area for this pyramid:

[tex]base \: area = area \: of \: rectangle[/tex]

[tex]base \: area = 10 \times 6[/tex]

Then you have to substitute the following values into the formula:

[tex]let \: base \: area = 10 \times 6 \\ let \: height = 12[/tex]

[tex]v = \frac{1}{3} \times 10 \times 6 \times 12[/tex]

Answer:

A. V = 1/3 (10)(6)(12)

Step-by-step explanation:

Just took the test and got it right

Someone pls help me

Answers

The slope greater than one would be the last image, because for every step in x, you get more than one y step.

The slope between 1 and 0 would be the second image

And the slope less than 0 would be the third image

What is the equation of the line that is parallel to the given line and passes through the point (12, -2)? A) y = -6/5x + 10 B) y= -6/5x + 12 C) y = -5/6x -10 D) y = 5/6x - 12

Answers

Answer:

D

Step-by-step explanation:

Parallel lines are those that have the same slope, or coefficient of x.

Here, let's calculate the slope of the given line. Slope is the difference in the y-coordinates divided by the difference in the x-coordinates, so given the two coordinates (12, 6) and (0, -4):

slope = m = (-4 - 6) / (0 - 12) = -10 / (-12) = 10/12 = 5/6

So the slope is 5/6. That means the equation we want should also have a slope of 5/6. Already, we can eliminate A, B, and C, leaving D as our answer. But, let's check.

The equation of a line can be written as [tex]y-y_1=m(x-x_1)[/tex], where m is the slope and [tex](x_1,y_1)[/tex] is the coordinates of a given point.

Here, our slope is 5/6 and our given point is (12, -2). So plug these in:

[tex]y-y_1=m(x-x_1)[/tex]

[tex]y-(-2)=(5/6)(x-12)[/tex]

[tex]y+2=\frac{5}{6} x-10[/tex]

[tex]y=\frac{5}{6} x-12[/tex]

This matches D, so we know that it's the correct answer.

~ an aesthetics lover

The answer is D I just took the test

What is the distance between (−11, −20) and (−11, 5)?

−25 units

−15 units

15 units

25 units

Answers

-15 units
Because -11 and -20 has a difference if -9 and -11 and 5 has a difference of 6 but it’s asking for difference so it’s -6 and when those are combined it’s -15.

Answer:

IT'S NOT -15 FOR SUREEE

Step-by-step explanation:

I Believe it's 15

Pls help me help me​

Answers

Answer:

C.

Step-by-step explanation:

When two lines are parallel, their slopes are the same.

Since the slope of line l is 2/7, the slope of its parallel line m must also be 2/7.

The answer is C.

Answer:

C. 2/7

Step-by-step explanation:

Parallel lines are lines that have the same slopes.

We know that line l is parallel to line m.

Therefore, the slope of line l is equal to the slope of line m.

[tex]m_{l} =m_{m}[/tex]

We know that line l has a slope of 2/7.

[tex]\frac{2}{7} =m_{m}[/tex]

So, line m also has a slope of 2/7. The answer is C. 2/7

3. Your friend is solving a system of linear equations and finds the following solution:
0=5
What is the solution of the system? Explain your reasoning.

Answers

Answer:

No solution.

Step-by-step explanation:

Because the equations are combined but the final answers are not equal, the equations have no solution. This is because "no matter what value is plugged in for the variable, you will ALWAYS get a contradiction".

Hope this helps!

g red bell pepper seeds germinates 85% of the time. planted 25 seeds. What is the probability that 20 or more germinate

Answers

Answer:

[tex] P(X\geq 20)= P(X=20)+P(X=21)+P(X=22)+P(X=23)+P(X=24)+P(X=25)[/tex]

And replacing using the mass function we got:

[tex]P(X=20)=(25C20)(0.85)^{20} (1-0.85)^{25-20}=0.156[/tex]  

[tex]P(X=21)=(25C21)(0.85)^{21} (1-0.85)^{25-21}=0.211[/tex]  

[tex]P(X=22)=(25C22)(0.85)^{22} (1-0.85)^{25-22}=0.217[/tex]  

[tex]P(X=23)=(25C23)(0.85)^{23} (1-0.85)^{25-23}=0.161[/tex]  

[tex]P(X=24)=(25C24)(0.85)^{24} (1-0.85)^{25-24}=0.0759[/tex]  

[tex]P(X=25)=(25C25)(0.85)^{25} (1-0.85)^{25-25}=0.0172[/tex]  

And adding the values we got:

[tex] P(X\geq 20) = 0.8381[/tex]

Step-by-step explanation:

Let X the random variable of interest, on this case we now that:  

[tex]X \sim Binom(n=25, p=0.85)[/tex]  

The probability mass function for the Binomial distribution is given as:  

[tex]P(X)=(nCx)(p)^x (1-p)^{n-x}[/tex]  

Where (nCx) means combinatory and it's given by this formula:  

[tex]nCx=\frac{n!}{(n-x)! x!}[/tex]  

We want to find the following probability:

[tex] P(X\geq 20)= P(X=20)+P(X=21)+P(X=22)+P(X=23)+P(X=24)+P(X=25)[/tex]

And replacing using the mass function we got:

[tex]P(X=20)=(25C20)(0.85)^{20} (1-0.85)^{25-20}=0.156[/tex]  

[tex]P(X=21)=(25C21)(0.85)^{21} (1-0.85)^{25-21}=0.211[/tex]  

[tex]P(X=22)=(25C22)(0.85)^{22} (1-0.85)^{25-22}=0.217[/tex]  

[tex]P(X=23)=(25C23)(0.85)^{23} (1-0.85)^{25-23}=0.161[/tex]  

[tex]P(X=24)=(25C24)(0.85)^{24} (1-0.85)^{25-24}=0.0759[/tex]  

[tex]P(X=25)=(25C25)(0.85)^{25} (1-0.85)^{25-25}=0.0172[/tex]  

And adding the values we got:

[tex] P(X\geq 20) = 0.8381[/tex]

A school is 16km due west of a school q.
What is the bearing of q from p?


Answers

Answer:

16 km due west

Step-by-step explanation:

The bearing of the school p from school q is 16 km due west.

To find the bearing of school q from school p, we have to find the direction that the school q is with respect to school p.

Since p is directly west of q, then it implies that q must be directly east of p.

We now know the direction.

Since the distance from q to p is exactly the same as the distance from p to q, then, the distance from p to q is 16 km.

Hence, the bearing of q from p is 16 km due west.

The left and right page numbers of an open book are two consecutive integers whose sum is 389.  Find these page numbers

Answers

Step-by-step explanation:

Maybe the page numbers can be 143 and 246

143 + 246 = 389

Answer:

194 and 195

Step-by-step explanation:

x = 1st page

x + 1 = 2nd page

x + x + 1 = 389

2x + 1 = 389

2x = 388

x = 194

x + 1 = 195

Choose the equation of the horizontal line that passes through the point (−5, 9). y = −5 y = 9 x = −5 x = 9

Answers

Answer:

y = 9

Step-by-step explanation:

Since we are trying to find a horizontal line, our line would have to be y = [a number]. That takes our x = -5 and x = 9 out as answer choices. We are left with y = -5 and y = 9. y = 9 is correct because the horizontal line is the y-values, and since in (-5, 9), our y-value is 9, our line is y = 9.

A square with side lengths of 3 cm is reflected vertically over a horizontal line of reflection that is 2 cm below the bottom edge of the square. What is the distance between the points C and C’? cm What is the perpendicular distance between the point B and the line of reflection? cm What is the distance between the points A and A’? cm

Answers

Answer:

a) 4 cm

b) 5 cm

c) 10 cm

Step-by-step explanation:

The side lengths of the reflected square are equal to the original, and the distance from the axis(2) also remains the same.  From there, it is just addition.

Hope it helps <3

Answer:

A) 4

B) 5

C) 10

Step-by-step explanation:

edge2020

pls help me hepl me ​

Answers

Answer:

b at most 199

Step-by-step explanation:so the total was 121 and there is a flat fee of 21.50 so you subtract that out and gat 99.5 since its .5 per mile its going to be divided giving 199 and that is the most she could have driven.

If Brooklyn College students have an IQ of 100, on average, with a standard deviation of 16 points, and I collect 48 BC Psychology students to see how Psych majors compare to all of BC, find the following:_______.
1. mu =
2. sigma =
3. mu _x bar =
4. sigma _x bar =

Answers

Answer:

1  [tex]\mu = 100[/tex]

2 [tex]\sigma = 16[/tex]

3 [tex]\mu_x = 100[/tex]

4 [tex]\sigma _{\= x } = 2.309[/tex]

Step-by-step explanation:

From the question

    The population mean is  [tex]\mu = 100[/tex]

    The standard deviation is [tex]\sigma = 16[/tex]

     The sample mean is  [tex]\mu_x = 100[/tex]

     The sample size is  [tex]n = 48[/tex]

     The mean standard deviation is  [tex]\sigma _{\= x } = \frac{\sigma }{\sqrt{n} }[/tex]

substituting values

     [tex]\sigma _{\= x } = \frac{16 }{\sqrt{48} }[/tex]

     [tex]\sigma _{\= x } = 2.309[/tex]

Find a parabola with equation y = ax2 + bx + c that has slope 5 at x = 1, slope −11 at x = −1, and passes through the point (2, 18).

Answers

By "slope" I assume you mean slope of the tangent line to the parabola.

For any given value of x, the slope of the tangent to the parabola is equal to the derivative of y :

[tex]y=ax^2+bx+c\implies y'=2ax+b[/tex]

The slope at x = 1 is 5:

[tex]2a+b=5[/tex]

The slope at x = -1 is -11:

[tex]-2a+b=-11[/tex]

We can already solve for a and b :

[tex]\begin{cases}2a+b=5\\-2a+b=-11\end{cases}\implies 2b=-6\implies b=-3[/tex]

[tex]2a-3=5\implies 2a=8\implies a=4[/tex]

Finally, the parabola passes through the point (2, 18); that is, the quadratic takes on a value of 18 when x = 2:

[tex]4a+2b+c=18\implies2(2a+b)+c=10+c=18\implies c=8[/tex]

So the parabola has equation

[tex]\boxed{y=4x^2-3x+8}[/tex]

Using function concepts, it is found that the parabola is: [tex]y = 4x^2 - 3x + 14[/tex]

----------------------------

The parabola is given by:

[tex]y = ax^2 + bx + c[/tex]

----------------------------

Slope 5 at x = 1 means that [tex]y^{\prime}(1) = 5[/tex], thus:

[tex]y^{\prime}(x) = 2ax + b[/tex]

[tex]y^{\prime}(1) = 2a + b[/tex]

[tex]2a + b = 5[/tex]

----------------------------

Slope -11 at x = -1 means that [tex]y^{\prime}(-1) = -11[/tex], thus:

[tex]-2a + b = -11[/tex]

Adding the two equations:

[tex]2a - 2a + b + b = 5 - 11[/tex]

[tex]2b = -6[/tex]

[tex]b = -\frac{6}{2}[/tex]

[tex]b = -3[/tex]

And

[tex]2a - 3 = 5[/tex]

[tex]2a = 8[/tex]

[tex]a = \frac{8}{2}[/tex]

[tex]a = 4[/tex]

Thus, the parabola is:

[tex]y = 4x^2 - 3x + c[/tex]

----------------------------

It passes through the point (2, 18), which meas that when [tex]x = 2, y = 18[/tex], and we use it to find c.

[tex]y = 4x^2 - 3x + c[/tex]

[tex]18 = 4(2)^2 - 3(4) + c[/tex]

[tex]c + 4 = 18[/tex]

[tex]c = 14[/tex]

Thus:

[tex]y = 4x^2 - 3x + 14[/tex]

A similar problem is given at https://brainly.com/question/22426360

The surface area of an open-top box with length L, width W, and height H can be found using the
formula:
A = 2LH + 2WH + LW
Find the surface area of an open-top box with length 9 cm, width 6 cm, and height 4 cm.

Answers

Answer:

174 square cm

Step-by-step explanation:

2(9×4) + 2(6×4)+ 9×6

2(36) + 2(24) + 54

72 + 48 + 54

120 + 54

174

Compute the critical value z Subscript alpha divided by 2 that corresponds to a 86​% level of confidence.

Answers

Answer:

z = 1.476

Step-by-step explanation:

We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:

[tex]\alpha = \frac{1-0.86}{2} = 0.07[/tex]

Now, we have to find z in the Ztable as such z has a pvalue of [tex]1-\alpha[/tex].

So it is z with a pvalue of [tex]1-0.07 = 0.93[/tex], so [tex]z = 1.476[/tex]

The answer is z = 1.476

The head of maintenance at XYZ Rent-A-Car believes that the mean number of miles between services is 3639 3639 miles, with a variance of 145,161 145,161 . If he is correct, what is the probability that the mean of a sample of 41 41 cars would differ from the population mean by less than 126 126 miles

Answers

Answer:

96.6% probability that the mean of a sample would differ from the population mean by less than 126 miles

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

A reminder is that the standard deviation is the square root of the variance.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question:

[tex]\mu = 3639, \sigma = \sqrt{145161} = 381, n = 41, s = \frac{381}{\sqrt{41}} = 59.5[/tex]

Probability that the mean of the sample would differ from the population mean by less than 126 miles

This is the pvalue of Z when X = 3639 + 126 = 3765 subtracted by the pvalue of Z when X = 3639 - 126 = 3513. So

X = 3765

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{3765 - 3639}{59.5}[/tex]

[tex]Z = 2.12[/tex]

[tex]Z = 2.12[/tex] has a pvalue of 0.983

X = 3513

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{3513 - 3639}{59.5}[/tex]

[tex]Z = -2.12[/tex]

[tex]Z = -2.12[/tex] has a pvalue of 0.017

0.983 - 0.017 = 0.966

96.6% probability that the mean of a sample would differ from the population mean by less than 126 miles

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