A single phase, 50-KVA, 2400-240-volt, 60 Hz distribution transformer has the following parameters: •
Resistance of the 2400-volt winding Ri=0.75 ohm
Resistance of the 240-volt winding R=0.0075 ohm
Leakage reactance of the 2400-volt winding X:=1 ohm
Leakage reactance of the 240-volt winding X2=0.01 ohm
Core loss resistance on the 2400 side Rc=733.5 ohms
Magnetizing reactance on the 2400 side X=4890 ohms
a. Draw the equivalent circuit referred to the high voltage side and referred to the low- voltage side. Label the impedances numerically.
b. The transformer is used as a step-down transformer at the load end of a feeder having impedance of (0.5+j2.0) ohms. Determine the voltage V. at the ending end of the feeder when the transformer delivers rated load at rated secondary voltage and 0.8 laggin power factor. Neglect the "exciting current" l. of the transformer (this is the current into the parallel Rc/jXm combination), which is another way of saying that you should use what we called in class the "approximate circuit #2).

Answer:

  Research the company

Explanation:

It is a good idea to find out information about the company you are interviewing. Among other things, this will help you decide if you actually want to work for that company.

Telling your current boss can be risky to your job. A new outfit may be helpful for certain positions--especially those where manner of dress is important. Finishing school may or may not be an important requirement for the position you're seeking. Your company research will tell you.

Researching the company is one of the most important steps to take.

Answer:

Ribosomes 1

Explanation

Ribosomes are small structures where proteins are made. Although they are not enclosed within a membrane, they are frequently considered organelles. Each ribosome is formed of two subunits, like the one pictured at the top of this section. Both subunits consist of proteins and RNA

Answer:

C: Viscosity, the resistance to flow that fluids exhibit

Explanation:

Did it on Edge :)

Answer:

C: Viscosity, the resistance to flow that fluids exhibit

Explanation:

Answer:

The answer is below

Explanation:

Given that:

[tex]k_t=torque\ constant=0.075\ Nm/A\\\\k_v=voltage\ constant=0.12\ V/(rad/sec)\\\\R_a=armature \ resistance=2.5 \Omega\\\\V_t=terminal\ voltage=24\ V\\\\a)The \ starting\ current\ I_a\ is\ given \ as:\\\\I_a=\frac{V_t}{R_a} =\frac{24}{2.5} =9.6\ A\\\\The \ starting\ torque(T)\ is:\\\\T=k_tI_a=0.075*9.6=0.72\ N.m[/tex]

b) The maximum speed occurs when the terminal voltage and back emf are equal to each other i.e.

[tex]V_t=e_b=k_v\omega\\\\\omega=\frac{V_t}{k_v}=\frac{24}{0.12} =200\ rad/s[/tex]

c) The load torque is given as:

[tex]T_L=0.0125\Omega\\\\The\ motor\ torque \ is:\\\\T=k_t(\frac{V_t-k_v\omega}{R_a} )\\\\but\ T = T_L,hence:\\\\0.0125\omega=0.075(\frac{24-0.12\omega}{2.5} )\\\\0.03125\omega=1.8-0.009\omega\\\\0.04025\omega=1.8\\\\\omega=44.72\ rad/sec\\\\N=\frac{60\omega}{2\pi} =\frac{60*44.72}{2\pi} =427\ rpm[/tex]

Answer:

a) 25000 pcs/yr

b) cost per part produced is $ 1.84 per pc

c) Cpc = $ 1.365 per pcs

Explanation:

a)

the relation to calculate the number of parts produced annually by manual process is;

Q = Hw / Tc

Hw is the hourly rate ( 2000hr/yr) and Tc is the cycle time ( 4.8 min)

so we substitute

Q = (2000 × 60) / 4.8

= 120000 / 4.8

= 25000 pcs/yr

b)

cost per part produced

the relation to calculate the cost per part produced is expressed as;

Cpc = $23(Hw) / Q

Cpc is the cost per part produced

so we substitute

Cpc = $23(2000) / 25000

= 46000 / 25000

= $ 1.8 per pc

therefore cost per part produced is $ 1.84 per pc

c)

for the robot cell, at a service life of 4 years and a 10% rate of return , the factor is expressed as;

f = [r(1 + r)^t] /  [((1 + r)^t ) - 1 ]

our rate r = 10% = 0.1 and our t = 4

so we substitute

f = [0.1 (1 + 0.1)^4] /  [((1 + 0.1)^4 ) - 1 ]

f = 0.14641 / 0.4641

f = 0.3155

now we find the total cost

TC = 120000(0.3155) + 2000(0.3) + 2500

TC =  $ 40,960

next we find the parts produced annually

Q = (2000 × 60) / 4

Q = 120,000 / 4

Q = 30000 pcs/yr  

finally we find the cost per part produced;

Cpc = TC / Q

we substitute

Cpc = 40,960 / 30000

Cpc = $ 1.365 per pcs

Answer:

Colloids are very low diameter particles which are responsible for the turbidity or the color of surface water. Because of their very low sedimentation speed the best way to eliminate them is the coagulation-flocculation processes.

Answer:

[tex]\mathbf{\sigma_{max} =638.308 \ MPa}[/tex]

Explanation:

For any large steel plate with an infinite length and width and a center through the crack under tension, the stress intensity factor can be expressed as:

[tex]K_I = \sigma \sqrt{\pi a}[/tex]

where;

a = 2.5 mm/2

a = 1.25 mm

a = 1.25 × 10⁻³ m

Therefore; the maximum stress in tension capacity can be computed as;

[tex]\sigma_{max} = \dfrac{K_{I_C}}{\sqrt{\pi a_c}}[/tex]

[tex]\sigma_{max} = \dfrac{40}{\sqrt{\pi \times 1.25 \times 10^{-3}}}[/tex]

[tex]\mathbf{\sigma_{max} =638.308 \ MPa}[/tex]

Answer: a drafting engineer

Explanation:

Answer: Could you put this in english plz

Explanation:

Answer:D

Explanation:

Option D is correct. Balancing the crankshaft is NOT one of the functions of a flywheel.

A flywheel is part of an automobile. It is a heavy wheel that is attached to a rotating shaft of an automobile. Since there may be the presence of large forces within an automobile structure, the presence of a flywheel helps to balance the force evenly across it.  

Some of the functions of the flywheel are but are not limited to help in transferring power to the transmission, engaging the starter, and smoothing out of power pulses.

Hence based on the explanation above, balancing the crankshaft is NOT one of the function of a flywheel.

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Answer: the lifetime (75 years) CDI is 0.001393 mg/kg.day

Explanation:

Given that;

CA = Contaminant Concentration = 0.05 mg/m³

IR = Inhalation Rate = 15.2m³per day = 15.2 / 24 = 0.6333 m³/hr

ET = Exposure Time = 8 hour per day

ED = Exposure Duration = (65 - 18 years)  = 47

EF = Exposure Frequency = 5 day/week * 50 week/ year = 250 days/year

BW = Body Weight = 78 Kg

AT = Averaging Time = 75 years = (75 * 365 days) = 27375 days

Now to find the CDI (Chronic Daily Intake)' we say;

CDI = (CA×IR×ET×EF×ED) / ( BW×AT)

so we substitute;

CDI = (0.05 × 0.6333 × 8 ×250 × 47) / (78 × 27375)

CDI = 2976.51 / 2135250

CDI = 0.001393 mg/kg.day

therefore the lifetime (75 years) CDI is 0.001393 mg/kg.day

Answer:

speed and acceleration

Answer:

a

Explanation:

Answer:

Usually it can be changed by flipping a switch. If your machine does not have one, then you just need to exchange the cables to the electrode holder and ground clamp.

Explanation:

The things that must be done before you change the polarity on a welding machine are coarse and fine adjustment.

The heated tool assembly, with two exposed surfaces, and two fixtures for holding the component parts to be welded. The tooling is for bringing the component parts into contact with the heated tool and bringing the molten joint surfaces together to form the weld. And displacement stops on the platen and holding fixtures make up a heated tool welding machine.

Polarity refers to the fact that the electrical circuit formed when you turn on the welder contains a negative and a positive pole. When welding, polarity is crucial, since the weld's strength and quality are affected by the choice of polarity.

Therefore, before changing the polarity of welding equipment, coarse and fine adjustments must be made.

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Answer:

Design engineer

Explanation:

Answer:

k-1000

Explanation:

Answer:

k = 1;

total = 0;

do {

total = total + (k*k);

k++;

} while (k <= 50);

Explanation:

answer using Java

Answer:

T. J. should the file by GIF to his friend.

beeeeeeeeeeeeeeeeeeeeeeeeep its gif

Answer:

The relation between the discharge volume flow rate and the inlet volume flow rate is [tex]\frac{1}{5}[/tex].

Explanation:

No matter if fluid is compressible or not, mass throughout compressor, a device that works at steady state, must be conserved according to Principle of Mass Conservation:

[tex]\dot m_{in}-\dot m_{out} = 0[/tex] (Eq. 1)

Where [tex]\dot m_{in}[/tex] and [tex]\dot m_{out}[/tex] are mass flows at inlet and outlet, measured in kilograms per second.

After applying Dimensional analysis, we expand the equation above as follows:

[tex]\rho_{in}\cdot \dot V_{in} - \rho_{out}\cdot \dot V_{out} = 0[/tex] (Eq. 2)

Where:

[tex]\rho_{in}[/tex], [tex]\rho_{out}[/tex] - Fluid densities at inlet and outlet, measured in kilograms per cubic meter.

[tex]\dot V_{in}[/tex], [tex]\dot V_{out}[/tex] - Volume flow rates at inlet and outlet, measured in cubic meters per second.

After some algebraic handling, we find the following relationship:

[tex]\rho_{out}\cdot \dot V_{out} = \rho_{in}\cdot \dot V_{in}[/tex]

[tex]\frac{\dot V_{out}}{V_{in}} = \frac{\rho_{in}}{\rho_{out}}[/tex] (Eq. 3)

If we know that [tex]\rho_{in} = 1\,\frac{kg}{m^{3}}[/tex] and [tex]\rho_{out} = 5\,\frac{kg}{m^{3}}[/tex], then the relation between the discharge volume flow rate and the inlet volume flow rate is:

[tex]\frac{\dot V_{out}}{\dot V_{in}} = \frac{1\,\frac{kg}{m^{2}} }{5\,\frac{kg}{m^{3}} }[/tex]

[tex]\frac{\dot V_{out}}{\dot V_{in}} = \frac{1}{5}[/tex]

The relation between the discharge volume flow rate and the inlet volume flow rate is [tex]\frac{1}{5}[/tex].

Answer:

Beam of 25" depth and 12" width is sufficient.

I've attached a detailed section of the beam.

Explanation:

We are given;

Beam Span; L = 20 ft

Dead load; DL = 0.50 k/ft

Live load; LL = 0.65 k/ft.

Beam width; b = 12 inches

From ACI code, ultimate load is given as;

W_u = 1.2DL + 1.6LL

Thus;

W_u = 1.2(0.5) + 1.6(0.65)

W_u = 1.64 k/ft

Now, ultimate moment is given by the formula;

M_u = (W_u × L²)/8

M_u = (1.64 × 20²)/8

M_u = 82 k-ft

Since span is 20 ft, it's a bit larger than the average span beams, thus, let's try a depth of d = 25 inches.

Effective depth of a beam is given by the formula;

d_eff = d - clear cover - stirrup diameter - ½Main bar diameter

Now, let's adopt the following;

Clear cover = 1.5"

Stirrup diameter = 0.5"

Main bar diameter = 1"

Thus;

d_eff = 25" - 1.5" - 0.5" - ½(1")

d_eff = 22.5"

Now, let's find steel ratio(ρ) ;

ρ = Total A_s/(b × d_eff)

Now, A_s = ½ × area of main diameter bar

Thus, A_s = ½ × π × 1² = 0.785 in²

Let's use Nominal number of 3 bars as our main diameter bars.

Thus, total A_s = 3 × 0.785

Total A_s = 2.355 in²

Hence;

ρ = 2.355/(22.5 × 12)

ρ = 0.008722

Design moment Capacity is given;

M_n = Φ * ρ * Fy * b * d²[1 – (0.59ρfy/fc’)]/12

Φ is 0.9

f’c = 4,000 psi = 4 kpsi

fy = 60,000 psi = 60 kpsi

M_n = 0.9 × 0.008722 × 60 × 12 × 22.5²[1 - (0.59 × 0.008722 × 60/4)]/12

M_n = 220.03 k-ft

Thus: M_n > M_u

Thus, the beam of 25" depth and 12" width is sufficient.

Answer:

[a] False.

[b]. True

[c]. false.

[d]. true.

[e]. true.

Explanation:

NB: SDOF simply means Simple Degree Of Freedom, that is to say it is a system that can be solved by differential equation such as the second order and the single differential equation.

So, the question asked us to determine if each of the scenario is true or false.  

a. Consider a SDOF system with Coulomb damping. When displaced from the equilibrium position and released, the mass may not move at all.

ANSWER:  FALSE.

REASON: The mass moved a little bit When displaced from the equilibrium position and released.

b. Consider a SDOF system with an ideal viscous damper. When displaced from the equilibrium position and released, the mass will always undergo oscillatory motion.

ANSWER: TRUE

REASON:  for an ideal viscous damper. When displaced from the equilibrium position and released, the mass will always undergo oscillatory motion.

c. The damped natural frequency of a system is always greater than the undamped natural frequency

.

ANSWER:  FALSE

REASON:  The damped natural frequency of a system is always greater than the undamped natural frequency

d. For an undamped system undergoing a harmonic forcing, the amplitude of the response approaches zero as the forcing frequency becomes very high.

ANSWER: TRUE

REASON:  the amplitude of the response approaches zero as the forcing frequency becomes very high for  undamped system undergoing a harmonic forcing

e. The amplitude of free response of SDOF system with Coulomb damping decreases

ANSWER: TRUE

REASON:  amplitude of free response of SDOF system with Coulomb damping decreases

Answer: 11470.4 cubic yards

Explanation:

first we calculate the volume of the site;

V1 = Area × depth

V1 = 2.5 acre ×  (43560 ft² / 1 acre )×3ft

V1 = 326700 ft

next we is the relative compaction

RC = [γd(field) / γdmax(laboratory)] × 100

so we substitute

93 =  [γd(field) / 122 lb/ft³)] × 100

γd(field) = 113.46 lb/ft³

then the dry unit weight of the site

γday1 = γavg / ( 1 + w)

= 118 lb/ft³ / ( 1 + (9.6/100))

= 118 lb/ft³ /1.096

= 107.664 lb/ft³

finally we find the fill volume of the site

V2/V1 = γd / γd(field)

we substitute

V2/326700 = 107.664 / 113.46

V2 = 310010.83 ft³

we convert to cubic yards

= 310010.83 ft³ × (0.037 cubic yard / 1 ft³)

= 11470.4 cubic yards

Answer: maximum length of the nanowire is 510 nm

Explanation:

From the table of 'Thermo physical properties of selected nonmetallic solids at At T = 1500 K

Thermal conductivity of silicon carbide k = 30 W/m.K

Diameter of silicon carbide nanowire, D = 15 x 10⁻⁹ m  

lets consider the equation for the value of m

m = ( (hP/kAc)^1/2 )  = ( (4h/kD)^1/2 )  

m =  ( ((4 × 10⁵)/(30×15×10⁻⁹ ))^1/2 ) = 942809.04    

now lets find the value of h/mk    

h/mk = 10⁵ / ( 942809.04 × 30) =  0.00353

lets consider the value θ/θb by using the equation

θ/θb = (T - T∞) / (T - T∞)

θ/θb =  (3000 - 8000) / (2400 - 8000)

= 0.893

the temperature distribution at steady-state is expressed as;

θ/θb = [ cosh m(L - x) + ( h/mk) sinh m (L - x)]   / [cosh mL+  (h/mk) sinh mL]

θ/θb = [ cosh m(L - L) + ( h/mk) sinh m (L - L)]   / [cosh mL+  (h/mk) sinh mL]

θ/θb = [ 1 ]  / [cosh mL+  (h/mk) sinh mL]

so we substitute

0.893 =  [ 1 ]  / [cosh (942809.04 × L) +  (0.00353) sinh (942809.04 × L)]

L = 510 × 10⁻⁹m

L = 510 nm

therefore maximum length of the nanowire is 510 nm

Answer:

Fluid dynamics.

Materials science.

Robotics.

Manufacturing processes.

Thermodynamics and heat transfer.

Environmental science.

Explanation:

Answer:

  4800 watts

Explanation:

Power is the product of voltage and current:

  P = VI = (240 V)(20 A) = 4800 W

The wattage is 4800 watts.

Answer:

Using regional materials creates a sustainable program that breaks countries’ dependencies on other nations.

Explanation:

i did the assignment

Answer:

Using regional materials creates a sustainable program that breaks countries’ dependencies on other nations.

Explanation:

C

The phase identifying the need involves research to determine exactly what the client expects. The correct option is B.

Research is a systematic inquiry process that includes data gathering, documentation of important information, analysis, and interpretation of that data and information.

These all are in accordance with appropriate procedures established by particular academic and professional disciplines.

Action-informing research is its goal. As a result, your study should attempt to place its findings in the perspective of the wider body of knowledge. In order to develop knowledge that is usable outside of the research setting, research must constantly be of the highest calibre.

Research is done during the step of determining the need to ascertain the precise expectations of the client.

Thus, the correct option is B.

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Answer:

Quick Breads

Explanation:

I think this is correct. I am not for sure i just looked it up and it says word for word that this is the answer.

Answer:

Quick Breads

Explanation:

I got it right on my Plato test

Answer:

Aluminium, Timber, Fibreglass

Explanation:

Most ladders are made of aluminium to have resistance against oxidisation and avoid rust; aluminium also doesnt spark either and is non magnetic. Some ladders are made out of timber like Douglas Fir, Oak, and Hickory. Some ladders are made out of fibreglass because it is strong and sturdy. They are also very to carry and are electrically resistant and heat tolerant.