The normal force on the car when it is at the bottom of the track is 22 N.
A frame revolves in a vertical circle such that its motion at unique points is one-of-a-kind then the motion of the frame is said to be vertical circular movement. recollect an item of mass tied at one give up of a mass m tied at one stop of an int extensible string and whirled in a vertical radius of radius r.
Calculation:-
At the inside of the track
N + mg = mv²/r
6 + 0.8 × 10 = m (v²/r)
14 = 0.8 ( acceleration)
acceleration = 17.5 m/sec² towards centre.
Again,
a = v²/r
ar = v²
v = √ar
v = √17.5 ×5
= 9.35 m/s²
For Normal force
N = mv²/r + mg
N = 0.8 × 1.75 + 0.8 × 10
= 14 + 8
= 22 N
A frame spins in a vertical circle in such a way that its movement at exclusive factors differs from the frame's motion, which is assumed to be vertical circular motion. keep in mind a mass m item wrapped in a stretchable string at one end and whirled in a vertical circle with radius d.
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what is the de broglie wavelength (in meters) of a 148 g baseball thrown at a velocity of 35.1 meters per second?
The de-Broglie wavelength of the baseball is 1.27×10⁻²⁵nm
λ=h/m
h is the Planck Constant =6.63×10⁻³⁴Js
m = mass = 148×10⁻³
=0.148kg
v= velocity =35.1m/s
λ=6.63×10⁻³⁴/0.148×35.1
λ=1.27×10⁻³⁴m
λ=1.27×10⁻²⁵nm
When learning about quantum mechanics, the de Broglie wavelength is a crucial idea. De Broglie wavelength is the wavelength that is connected to an object in relation to its momentum and mass. Typically, a particle's force and de Broglie wavelength are inversely related.
Some people believe that matter has both a wave- and a particle-like nature. De Broglie wavelength, so named after the discoverer Louis de Broglie, are the characteristics of a physical object that fluctuate in time or space while acting like waves. Matter waves are another name for it. It is strikingly reminiscent of the experimentally demonstrated dual nature of light, which exhibits both particle and wave behavior.
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a student slides her 80.0-kg desk across the level floor of her dormitory room a distance 5.00 m at constant speed. if the coefficient of kinetic friction between the desk and the floor is 0.400, how much work did she do? a student slides her 80.0-kg desk across the level floor of her dormitory room a distance 5.00 m at constant speed. if the coefficient of kinetic friction between the desk and the floor is 0.400, how much work did she do? 20.4 j 9.41 j 23.5 j 1.57 kj 15.7 j
Work she did 1.57kj.
Option d is correct
How do kinetic and static friction differ?Kinetic and Static Friction The friction that exists between two systems when they are in touch and immobile with respect to one another is known as static friction. Kinetic friction is the friction that occurs when two systems are in contact and moving in relation to one another.
F(net) = F(applied) - F(friction)
0 = F(applied) - F(friction)
F(applied) = F(friction) (1)
Work done = F(applied) *(desk travel distance)
From 1
Work done = F(friction)*(desk travel distance)
W = µNd
W = µmgd
W = (0.400)(80.0 kg)(9.81 m/s²)(2.00 m)
W =1568 J ← work done to move the desk.
W = 1.57kj
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If the gravity of the moon is 1/6 of Earth’s gravity, what is the mass of an object that has a weight of 115N on the moon? a)89 b)71.9 c)30.2 d)20
it's 115/6 which is 19.1667
Explanation:
The weight would be 115/6 because the moon has one sixth of the gravity on earth so the weight would be on sixth of that on earth.
A wheel with rotational inertia I is mounted on a fixed, frictionless axle. The angular speed ω of the wheel is increased from zero to ωf in a time interval T.
What is the average power input to the wheel during this time interval (hint: power = work / time)?
A:[tex]\frac{I^{2}\omega_{f} }{2T^{2} }[/tex]
B: [tex]\frac{I\omega^{2}_{f} }{2T^{2} }[/tex]
C: [tex]\frac{I\omega_{f}} {2T}[/tex]
D: [tex]\frac{I\omega^{2}_{f} }{2T}[/tex]
The average power input to the wheel during this time interval is (Iω²) / (2T).
option D is the correct answer
What is average power?The average power input to the wheel during this time interval is the rate at which work is done by the wheel or the rate at which energy is expended.
Mathematically, the formula for average power is given as;
P = energy / time
Based on work - energy theorem,
work done by the wheel = change in energy of the wheel
Energy of the wheel due to the rotational torque is given as;
E = ¹/₂Iω²
where;
I is the moment of inertia of the wheelω is the angular speed of the wheelPower = E/T
power = (Iω²) / (2T)
where;
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please I'm so hurry
What is it answer this question ?
A disk rotates with rotational kinetic energy is 70J and the angular momentum is 30 kg.m2/s .what is the value moment of inertia the disk?
A) 6.4 kg.m2
C) 40 kg.m2
B) 2.3 kg.m2
D) 0.43 kg.m2
Answer:
The value moment of inertia the disk:
I = 6.4 kg·m²
Explanation:
Given:
Tk = 70 J
L = 30 kg·m² / s
_____________
I - ?
Rotational kinetic energy:
Tk = I·ω²/2
Angular velocity:
ω = √ (2·T / I)
Angular moment of a rotating body
L = I·ω = I·√ (2·T / I) = √ (2·T·I² / I ) = √ (2·T·I )
Raising to the second degree:
L² = 2·T·I
The value moment of inertia the disk:
I = L² / (2·T)
I = 30² / (2·70) ≈ 6.4 kg·m²
А) 6.4 кг·м²
an engineer cuts a 1.0-m-long, 0.33-mm-diameter piece of wire, connects it across a 1.5 v battery, and finds that the current in the wire is 8.0 a. of what material is the wire made?
The resistivity rho of the piece of the wire will be 1.60 × 10⁻⁸ Ωm. So, the material is copper wire.
Copper is the electrical conductor in many categories of electrical wiring. Copper wire is used in power generation, power transmission, power distribution for telecommunications, electronics circuitry, and countless types of electrical equipment.
The resistivity of a material is the resistance of a wire of that material of unit length and unit area of cross-section. Its S.I. unit is ohm-metre.
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A rocket is burning fuel at the rate of 300g/s and electing all the gas. In one direction of the rate of 500m/s what is maximum weight the rocket burn have if it going to move Vertically upward.
Correct option is D)
Overall momentum of the system is conserved.
Therefore, change in momentum of the rocket will be equal to that of the fuel.
Change in momentum of the fuel will be
Δmv=60000
Hence, change in momentum of the rocket will also be:
△P=60000
Thrust force F=
△t
△p
F=60000 N
ssm a warehouse worker exerts a constant horizontal force of magnitude 85 n on a 40 kg box that is initially at rest on the horizontal floor of the warehouse. when the box has moved a distance of 1.4 m, its speed is 1.0 m/s. what is the coefficient of kinetic friction between the box and the floor?
The coefficient of the kinetic friction between the box and the floor is μk 0.21.
Friction is the force resisting the relative motion of strong surfaces, fluid layers, and fabric elements sliding against every different. There are several sorts of friction: Dry friction is a pressure that opposes the relative lateral movement of two solid surfaces in touch.
Calculation:-
Given,
mass = 40 Kg
Applied force F = 85 N
initial velocity u = 0 (rest)
distance moved = 1.4 meter
Final velocity = 1 m/s
coefficient of kinetic friction =?
Normal force = N = mg = 400 N
v² = u² +2as
a = v²/2s
= 1/2×1.4
= 0.36 m/s²
F = μkN
μk = F/N
= 85/400
0.21
Friction is a shape of touch pressure. It exists between the surfaces which are in touch. The frictional force relies upon on the person of the surface in contact. The rougher the floor, the greater the friction is involved. The frictional force is proportional to the urgent pressure, this is the weight of the body. it's far impartial of the place of the touch.
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forces and newton’s laws 3.1 Essential Questions How are force and motion related?
According to Newton's law of motion, the direction of motion of an object depends on the direction of the applied force.
What is Newton's first law of motion?
Newton's first law of motion states that an object at rest or uniform motion in a straight line will continue in that path unless acted upon by an external force and it will move in the direction of the applied force.
The Newton's first law of motion is also called the law of inertia because it depends on the mass of the object. The more massive an object is, the more inertia the object will possess and vice versa.
Also, the Newton's second law of motion states that the force acting on an object is directly proportional to the product of mass and acceleration of the object.
Mathematically, Newton's second law of motion is given as;
F = ma
F = mv/t
Ft = mv
This law (Newton's second law of motion) is also states that the force applied on an object directly proportional to the rate of change of momentum of the object.
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a funny car accelerates from rest through a measured track distance in time t with the engine operating at a constant power p. if the track crew can increase the engine power by a differential amount dp, what is the change in the time required for the run? (use any variable or symbol stated above as necessary.)
dT = -T^4/(2mD^2)dP
P = W/T = FD/T = (m a)D/T
dP = -maD/T^2 dT
dT = -T^2/(maD)dP
V = aT
D = 1/2 a T^2
a = 2D/T^2
dT = -T^4/(2mD^2)dP
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Describe what is happening to the pressure and volume of the gas in the two diagrams below, assuming that the temperature of the gas does not change.
The pressure is increasing and accordingly the volume of the gas is decreasing when the temperature of the gas does not changes.
Continuous physical force acting on an object is termed as pressure.
Space occupied by any substance is termed as its volume.
As we know pressure and volume are inversely proportional to each other, this means that if the temperature and amount of any gas in a container is kept constant then the increase in pressure of the gas will cause decrease in the volume of the same gas in the container.
Pressure (P) ∝ [tex]\frac{1}{Volume (V)}[/tex]
When sign of proportionality '∝' is removed constant 'k' is added to the equation
i.e. P = [tex]\frac{k}{V}[/tex]
PV = k
So the given picture clearly depicts that the piston is creating pressure on the gas hence the pressure of the gas is increasing and therefore the volume of the gas is decreasing.
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according to the color code, the number of pairs of conductors in a cable that can be defined without repeating a color combination is?
According to the color code, the number of pairs of conductors in a cable that can be defined without repeating a color combination is 25 pairs
To identify individual conductors in a telecommunications twisted pair cable the 25-pair color code is used. These colours are marked on the conductor's insulation. The primary colours are white, red, black, yellow and violet. The secondary colours are blue, orange, green, brown and slate.
The primary colours are called as tip which is positive and the secondary colours are called as ring which is negative. In the pair only one colour from each group should be used. So the possible combinations are 25 pairs.
Therefore, according to the color code, the number of pairs of conductors in a cable that can be defined without repeating a color combination is 25 pairs
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how much work must be done by an external force on an object (sliding over a frictionless, horizontal surface) to accelerate the object from a speed vv to a speed 2v2v?
Using the concepts of work, we got that we need to work three times of the previous work to accelerate the object from a speed v to a speed 2v.
We know that to change the velocity of any object we need to do some work on it.
When an object having some mass m moving with velocity v, then the kinetic energy stored in that object is given by(KE₁) =(1/2)mv².
Now, When an object having some mass m moving with velocity 2v,then the kinetic energy stored in that object is given by(KE₂) =(1/2)m(2v)².
New kinetic energy is =4[(1/2)mv²] or 4KE₁
So, net work to accelerate the object is =KE₂-KE₁
W=4KE₁-KE₁=3KE₁.
Hence, the amount of work must be done by an external force on an object (sliding over a frictionless, horizontal surface) to accelerate the object from a speed v to a speed 2v is 3 times the energy stored on a object.
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the product of a force and the perpendicular distance from the force's line of action to the axis of rotation is known as
The product of a force and the perpendicular distance from the force's line of action to the axis of rotation is known as Torque.
Torque or moment of the force is the term used to describe a force's ability to turn.
The moment arm is the length that separates the line of action perpendicular to the axis of rotation. Torque is a mathematical combination of force F and moment arm L. Torque is equal to F times L. The moment arm affects torque. The torque will create more of an increase the longer the moment arm.
The line of action of a force is the path it travels when exerting its power.
The moment arm of the force is the length that separates the force's path of action from its axis of rotation perpendicularly.
The newton meter is the torque SI unit (Nm). A force of 1 N operating perpendicular to the moment arm's length of 1 m produces a torque of 1 N m.
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A 900 kg coaster car is 13 m high traveling at 28 m/s at point C. If point E is 10 m high, how fast will the car be traveling assuming no frictional forces?
The velocity of the car at point E which is 10 m is determined as 24.2 m/s.
What is the final velocity of the coaster?The final velocity of the coaster car is calculated by applying the principle of conservation of energy.
total kinetic energy of the coaster = total potential energy of the coaster
K.E = P.E
-¹/₂mv₁² + ¹/₂mv₂² = -mgh
-v₁² + v₂² = -2gh
v₂² = v₁² - 2gh
where;
m is the mass of the coasterv₁ is the initial velocity of the coasterv₂ is the final velocity of the coasterh is the height of travel of the coaterg is acceleration due to gravityThe given parameters include;
initial velocity of the coaster = 28 m/sheight of travel = 10 mv₂² = v₁² - 2gh
v₂² = (28²) - (2 x 9.8 x 10)
v₂² = 588
v₂ = √588
v₂ = 24.2 m/s
Thus, the final velocity of the coaster car at the given height will be smaller than the initial velocity due to effect of gravity.
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Joe is using a crowbar to remove a tree stump. He applies 2066 J of work to the crowbar. The output work of the crowbar is 1240 J. What is the efficiency of the crowbar?
Joe is using crowbar to remove tree stump. When output and input work is given then the efficiency can be calculated as 60%.
How is efficiency defined ?Efficiency can be defined as how good a device is at transferring input energy to useful output energy . The efficiency of a device is the proportion of the energy supplied that is transferred for useful work. The efficiency is calculated as a decimal or a percentage.
Given output work as 1240 J
input work as 2066 J
Then efficiency can be calculated by using the formula :
Efficiency= (output work/ input work) * 100%
=( 1240/2066) * 100%
Efficiency = 60%
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an obstruction is just ahead on the shoulder. your front wheel leaves the roadway at high speed. when do you countersteer?
An obstruction is just ahead on the shoulder. Your front wheel leaves the roadway at a high speed. You countersteer when the front tire touches the roadway.
Countersteer is usually done by the cyclists and motorcyclists to turn at higher speeds. It is advisable to be done only on the race tracks. This is because the two wheels do not follow the same path during turning and it may affect other vehicles on normal roads. The rider must be leaned in the direction of turn in order to complete the turn. As the front wheel leaves at a higher speed, countersteering is done when the front wheel touches the ground.
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30.0-kg child sits on one end of a long uniform beam having a mass of 20.0 kg, and a 40.0-kg child sits on the other end. the beam balances when a fulcrum is placed below the beam a distance 1.10 m from the 30.0-kg child. how long is the beam? a 30.0-kg child sits on one end of a long uniform beam having a mass of 20.0 kg, and a 40.0-kg child sits on the other end. the beam balances when a fulcrum is placed below the beam a distance 1.10 m from the 30.0-kg child. how long is the beam? 2.07 m 1.93 m 2.12 m 2.20 m 1.98 m
The length of the beam on which the the two boys are lying is 1.01 m.
The mass of one kid is 30 kg and the mass of the beam is 20kg, the beam is balanced at a distance of 1.10 m from the 30 kg boy when a 40kg boy was sitting at the other end of the beam.
If the beam is balanced at 1.10 m from the 30kg boy it means that there lies the center of mass of the system.
So, let us assume the length of the beam to be X meters and the assume the center of mass to be at center.
So,
0 = M₁X₁ + M₂X₂/M₁+M₂
M₁ is 30kg and X₁ is 1.10m.
M₂ is 40kg and the X₂ is (X-1.10)m.
Putting values,
0 = 30 x 1.1 + 40 x (X-1.1)
(1.1 - X)40 = 3.3
X = 1.01 m.
So, the length of the Beam is 1.01 m.
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What does water's high specific heat capacity explain about water?
A) why water bonds with other molecules
B) why water is often used as a solvent
C) why water is unable to absorb energy
D) why water is liquid at room temperature
Water's high specific heat capacity explains why why water bonds with other molecules.
The correct answer choice is option a.
Why water bonds with other moleculesWater has the ability to easily attract other molecules simply because of the fact its hydrogen and oxygen components is made up of positive and negative ions respectively.
Technically, the bonds in hydrogen possess a form of electrostatic force which makes it very possible for water to bond with other molecules with its high specific heat capacity.
So therefore, we can now confirm and deduce that from the simple note given above that the hydrogen bonds presence in water molecule makes it easy for water to combine with other molecules.
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NEED HELP ASAP
What is the acceleration due to gravity on the surface of the planet Pluto if its mass is 1.2 x 10 22 kg and radius is 1.14 x 10 6 m?
9.8 m/s2
6.4 m/s2
0.62 m/s2
0.34 m/s2
The acceleration due to gravity on the surface of planet Pluto is 0.62 m/s²
How to determine the acceleration due to gravityFrom the Newton's law of universal gravity, the acceleration due to gravity is given by:
g = GM / R²
Where
g is acceleration due to gravity M is the mass G is the gravitational constantR is the radius.With the above formula, we can obtain the acceleration due to gravity. Details below
Mass of planet (M) = 1.2×10²² KgRadius (R) = 1.14×10⁶ mGravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²Acceleration due to gravity (g) =?g = GM / R²
g = (6.67×10¯¹¹ × 1.2×10²²) / (1.14×10⁶)²
g = 0.62 m/s²
Thus, the acceleration due to gravity is 0.62 m/s²
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if a cannonball were fired horizontally from a cannon atop a very high mountain what would its trajectory look like
The trajectory of the cannonball will be in parabolic motion.
A trajectory is an object that only gravity acts on. The downward force, gravity, accelerates the projectile downward. The vertical components of motion are independent of each other, so gravity does not change the object's horizontal velocity. A vertical force does not cause horizontal movement. A vertical force acting on a horizontally moving object causes the object to deviate from its linear trajectory.
When an object moving forward is affected by gravity, it falls in a parabolic arc. Since the projectile is an object affected only by gravity, the projectile's path forward from the initial thrust momentum is parabolic.
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3. (a) calculate the work done on a 1500-kg elevator car by its cable to lift it 40.0 m at constant speed, assuming friction averages 100 n. (b) what is the work done on the elevator car by the gravitational force in this process? (c) what is the total work done on the elevator car?
(a) Work done on the car by its cable will be 5.92 * [tex]10^{5}[/tex] J.
(b) Work done on the car by the gravitational force will be -5.92 * [tex]10^{5}[/tex] J.
(c) Total work done on the car will be 0 J.
Work done is the product of force and displacement.
Mathematically, Work-done = W = Force * DistanceMass of the car = m = 1500 kg
Distance lifted by the cable = d = 40 m
Frictional force experienced by the car = Fs = 100 N
(a) According to the Newton's second law of motion
F = Fcable - mg - Fs = ma
Fcable = mg + Fs
Work done by the same force = W1
W1 = Fcable * d
W1 = (mg + Fs) * d
W1 = (1500*9.8 + 100) * 40
W1 = 592600
W1 = 5.92 * [tex]10^{5}[/tex] J
(b) Work done by the gravitational force = W2 = mg * d
W2 = 1500*(-9.8)*40
Since the acceleration is acting downwards 'g' will be considered with a negative sign.
W2 = -5.88 * [tex]10^{5}[/tex] J
(c) The total work done on the lift is the work done by the net force exerted on the car during this process:
W3 = Fnet * d
Fnet = -5.88 * [tex]10^{5}[/tex] J + 5.92 * [tex]10^{5}[/tex] J
Fnet = 0
W3 = 0 * 40
W3 = 0 J
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If a car, with an initial velocity of 15 m/s, accelerates at a rate of 5 m/s^2 for 4 seconds, what will its final velocity be?
Answer:
35 m/s
Explanation:
vf = vo + at
vf = 15 + 5(4) = 35 m/s
two polarizers are oriented to each other by an angle of 75 degrees. polarized light with a polarization angle 25 degrees from the axis of the polarizer is incident on the first polarizer. how much of the light incident on the first polarizer (what percentage) makes it through the second?
82% of incoming polarized light with a polarization angle 25 degrees from the axis of the first polarizer will make it through the second polarizer.
We can use Snell's law to find out how much of the light makes it through the second polarizer.
Snell's law gives us:
sin(θ1)×sin(θ2)=n1×n2
Solving for n1, we get:
n1=(sinθ1cosθ2)/(sinθ1sinθ2)
We know that θ1 and θ2 are each 75 degrees, so we can put this into our equation:
n1=(0.5)(0.5)/(0.25)(0.75)=0.8333
This means that 82% of incoming polarized light with a polarization angle 25 degrees from the axis of the first polarizer will make it through the second polarizer.
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the system produces 80,176 watts, what is the energy worth per day? assume electricity costs of $0.08 per kwh
Electricity costs of the system at $0.08 per kwh for a day is $153.9
What is power?Power refers to the rate of work. It is work done per unit of time. The SI unit for power is the watt (W), which is the joule per second (J/s).
Power = Work / time
P = W / t
One kilowatt hour is said to be one thousand watts sustained for one hour i.e. KWh = (Watts × Hours) ÷ 1,000
For the given case,
Power = 80,176 watts
Rate = $0.08 per kwh
kWh = (watts × hrs) ÷ 1,000
kWh = (80,176 × 24)
= 1924.224 kWh
Total cost of the day is = 1924.224 × 0.08
= $ 153.9
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surface waves are caused primarily by what? question 6 options: frictional forces between wind and the ocean surface frictional forces at the level of the thermocline layer primarily gravitational forces of the moon large aquatic organisms breaching the ocean surface
Frictional forces between wind and the ocean surface are the primary cause of surface waves. This is the first option.
How are surface waves formed?The most common cause of waves is wind. Surface waves, also known as wind-driven waves, are formed by the frictional forces between wind and surface water. The continual disturbance creates a wave crest as wind blows across the surface of the ocean or a lake. Surface waves are found globally across the open ocean and along the coast.
There is also a type of waves called tidal waves. Tidal waves are caused by the gravitational pull of the Sun and Moon on Earth.
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A thick magnetic disk made of aluminum platters. Uses read/write heads to access data stored on the platters.
A thick magnetic disk made of aluminum platters and It uses read/write heads to access data stored on the platters, that is correct statement.
Hard disk drives are thick magnetic disks made of aluminum platters, They use read/write heads to access data stored on the platters. They have up to several TB in storage capacity and their cost per MB is cheap. Solid state drive is a flash device with storage capacity similar to a small hard drive.
For operation point of view, Hard disk drives are bit slower than solid state drive are faster. so using a solid state drives devices are booted up fast. In case of price point of view, SSD devices are more costly than HDD.
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If a ring particle survived for the age of the solar system, how many collisions would it undergo?.
Answer:
The answer is near 8 trillion
Explanation:
I hope this helps
Sound cannot travel without medium write on the basis of the following points (materials required) (procedure) (conclusion
Explanation:
Because it is a mechanical wave and it need material medium to travel through it.
you pull a box with a constant force of 250 n. the box moves 10 m along a straight path on a rough surface at a constant speed. how much thermal energy is generated in the system of the box and the rough surface?
The thermal energy of the box which is pulled with a force of 250 N to a distance of 10 meters is 2500 J
The force to pull the box = 250 N
The box is moved to a distance of 10 meters
The thermal energy can be found using the formula,
W = F x d
where W is the thermal energy
F is the Force
d is the distance moved
Let us substitute the known values in the above equation, we get
W = 250 x 10
= 2500 J
Therefore, the thermal energy of the box is 2500 J
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