A small person was running way faster than a bigger person that weighed more collided in a football game. Who would be pushed back or down?

:

Please give me brainly,

The thermal energy of an object depends on three things: 4 the number of molecules in the object 4 the temperature of the object (average molecular motion) 4 the arrangement of the object's molecules (states of matter). The more molecules an object has at a given temperature, the more thermal energy it has.

Mass and Temperarture

I am pretty sure that is right if Not sorry

Have a great day.

Answer:

B is the answer!!

Explanation:

Answer:

w = 1,662 rad / s,    v = 33.25 m / s

Explanation:

This this exercise indicates that the acceleration felt by the astronauts is

         a = 5.64 g

in a circular motion the centripetal acceleration is

        a_c = v²/ r

angular and linear variables are related

         v = w r

we substitute

        a_c = w² r

we finally have

         5.64 g = w² r

         w² = 5.64 g / r

let's calculate

         w = [tex]\sqrt{ \frac{5.64 \ 9.8}{20.0} }[/tex]

         w = 1,662 rad / s

linear velocity is

        v = w r

        v = 1,662 20

         v = 33.25 m / s

Answer: I do not know (is this an RP question? ;-;)

Explanation:

Answer:

Applications in which ionizing radiation are not used are  

MRI

ultrasound

laser surgery

Explanation:

hope its right

bestfriend

Sound waves requires a medium (material) to vibrate in order to produce a sound. So sound waves cannot travel in outer space as it is vacuum.

Answer:

Nebulas

Explanation:

Nebulae are made of dust and gases—mostly hydrogen and helium. ... Eventually, the clump of dust and gas gets so big that it collapses from its own gravity. The collapse causes the material at the center of the cloud to heat up-and this hot core is the beginning of a star.

Ans the answer is 0.25J

Explanation

i guess

Answer:

the velocity of the bullet-wood system after the collision is 2.48 m/s

Explanation:

Given;

mass of the bullet, m₀ = 20 g = 0.02 kg

velocity of the bullet, v₀ = 250 m/s

mass of the wood, m₁ = 2 kg

velocity of the wood, v₁ = 0

Let the velocity of the bullet-wood system after collision = v

Apply the principle of conservation of linear momentum to calculate the final velocity of the system;

Initial momentum = final momentum

m₀v₀ + m₁v₁ = v(m₀ + m₁)

0.02 x 250  + 2 x 0    =    v(2  + 0.02)

5 + 0 = v(2.02)

5 = 2.02v

v = 5/2.02

v = 2.48 m/s

Therefore, the velocity of the bullet-wood system after the collision is 2.48 m/s

Explanation:

on the left side the forces add to 150N

on the right side the forces add to 300

you then take away 150 from 300

=150N to the right

answer Is C

Answer:

144 kg m^2/s

Explanation:

Answer:

Answer 4, 11k/min

Explanation:

From 0 - 1 km, it took 12 minutes

From 1 - 2 km, it took 10 minutes.

10 + 12 = 22

Divide the time by 2 km. 22/2 = 11

Answer:

its the last question

Explanation:

Thats because erosion takes away stuff

Higher Power Efficiency  and Eliminates Risk of Compressor Breakdown

Answer:

A distance-time graph shows how far an object has travelled in a given time. It is a simple line graph that denotes distance versus time findings on the graph. Distance is plotted on the Y-axis. Time is plotted on the X-axis

Explanation:

Answer:

Maybe A. waving your arms?

Answer:

Explanation:

Its resistor

Answer:

The radius will be "100.31 m". A further solving is given below.

Explanation:

The given values are:

Time,

T = 2 minutes

i.e.,

 = 120 seconds

Speed,

V = 5.25 m/s

As we know

⇒  [tex]T=\frac{2 \pi R}{V}[/tex]

then,

⇒  [tex]R=\frac{TV}{2 \pi}[/tex]

On substituting the given values, we get

⇒      [tex]=\frac{120\times 5.25}{2\times 3.14}[/tex]

⇒      [tex]=\frac{630}{6.28}[/tex]

⇒      [tex]=100.31 \ m[/tex]

Question: A 2.0 kg sphere with a velocity of 6.0 m/s collides head-on and elastically with a stationary 10 kg sphere, What is thier velocities after collision.

Answer:

v = 6 m/s, v' = 0 m/s

Explanation:

From the question,

For Elastic collision,

mu+m'u' = mv+m'v'......................... Equation 1

Where m = mass of the first sphere, m' = mass of the second sphere, u = initial velocity of the first sphere, u' = initial velocity of the second sphere, v = final veolocity of the first sphere, v' = final velocity of the second sphere.

Also,

The relative velocity before collision = relative velocity after collision

u-u' = v-v'............................ Equation 2

Given:  m = 2 kg, m' = 10 kg, u = 6 m/s, u' = 0 m/s

Substitute into equation 1 and 2

2(6)+10(0) = 2v+10v'

2v+10v' = 12.............. Equation 3

6-0 = v-v'

v-v' = 6 ................... Equation 4

Solve equation 3 and 4 simultaneously.

v = 6+v'............. Equation 5

Substitute equation 5 into equation 3

2(6+v')+10v' = 12

12+2v'+10v' = 12

12v' = 12-12

v' = 0/12

v' = 0 m/s.

Also substitute the value of v' into equation 5

v = 6+0

v = 6 m/s

Answer:

-7.5

Explanation:

edge 2021

Answer:

 t_man = 10.16 s,   t_horse = 10.73 s,  the winner is the man

Explanation:

To solve this problem we are going to find the time of each one separately.

Man we look for distance and time during acceleration

         x₁ =  v₀ t₁ + ½ a₁ t₁²

as it comes out of rest its initial velocity is zero

        x₁ = ½ a₁ t₁²

        x₁ = ½ 6.0 1.8²

        x₁ = 9.72 m

at this point its speed is

        v₁ = v₀ + a t

        v₁ = 0 + 6  1.8

        v₁ = 10.8 m / s

From here on it continues at constant speed, the distance that the man needs to travel from the point where the man leaves at 100m is

        x₂ = 100 - x₁

        x₂ = 100- 9.72

        x₂ = 90.28 m

the time for this part is

        v₁ = x₂ / t₂

         t₂ = x₂ / v₂

         t₂ = 90.28 / 10.8

         t₂ = 8.36 s

the total time for the man is

        t_man = t₁ + t₂

        t _man = 1.8 + 8.36

        t_man = 10.16 s

We repeat the calculation for the horse

distance traveled during the acceleration period

         x₃ = v₀ t + ½ a₂ t₃²

as part of rest its initial velocity is zero

        x₃ = ½  a₂ t₃²

        x₃ = ½  5.0  4.8²

        x₃ = 57.6 m

the velocity at this point is

         v₃ = v₀ + a₂ t₃

         v₃ = 0 + 5  4.8

         v₃ = 24 m / s

the rest of the route is at constant speed, the remaining distance

         x₄ = 200 - x₃

         x₄ = 200 - 57.6

         x₄ = 142.4 m

the time to go through it is

         t₄ = x₄ / v₃

         t₄ = 142.4 / 24

         t₄ = 5.93 s

the total time for the horse is

         t_horse = t₃ + t₄

         t_horse = 4.8 + 5.93

         t_horse = 10.73 s

when we compare the times we see that the man arrives a little before the horse, the winner is the man

Answer: San diego

Because it is closer to the ocean

Answer:

p = 4000 kg-m/s

Explanation:

Given that,

The mass of a truck, m = 200 kg

Speed of the truck, v = 20 m/s

We need to find the momentum of the truck. The formula for momentum is given by :

p = mv

so,

[tex]p=200\times 20\\\\p=4000\ kg-m/s[/tex]

So, the momentum of the truck is equal to 4000 kg-m/s.

Answer:

(a) The weight of the wood is approximately 5,886 N

(b) The weight of the stone is approximately 1,962 N

Explanation:

The given parameters are;

The base area of the wood, A = 1 m × 1 m = 1 m²

The depth to which the wood is submerged below the water, d = 0.6 m

The depth further the wood sinks when a stone is placed on the wood, Δd = 0.2 m

The density of water, ρ = 1,000 kg/m³

(a) Archimedes' principle states that the up-thrust, or upward force acting on an object submerged in a fluid, is equal to the weight of the displaced fluid.

For a floating object such as the wood, the up-thrust is equal to the weight of the object

The weight of the water displaced, W = The volume of the displaced water, V × The density of the water, ρ × The acceleration due to gravity, g

W = V × ρ × g

'V' is the same as the volume of the submerged wood, therefore;

V = A × d = 1 m × 1 m × 0.6 m = 0.6 m³

g ≈ 9.81 m/s²

Therefore;

W = 0.6 m³ × 1,000 kg/m³ × 9.81 m/s² ≈ 5,886 Newtons

The weight of the water displaced, W ≈ 5,886 N = The up-thrust = The weight of the wood

∴ The weight of the wood, W ≈ 5,886 N

(b) Similarly, the weight of the stone, [tex]W_{stone}[/tex] is equal to the weight of the additional volume of water displaced

∴ [tex]W_{stone}[/tex] = A × Δd × ρ × g

By plugging in the values, we get

[tex]W_{stone}[/tex] ≈ 1 m² × 0.2 m × 1,000 kg/m³ × 9.81 m/s² = 1,962 N

The weight of the stone, [tex]W_{stone}[/tex] ≈ 1,962 Newtons

Answer:

45 degrees༼ つ ◕_◕ ༽つ

Explanation:

Answer:

Force = 19.62 Newton

Explanation:

Given the following data;

Mass = 2kg

Acceleration = 9.81 m/s²

To find the force;

Newton's Second Law of Motion states that the acceleration of a physical object is directly proportional to the net force acting on the physical object and inversely proportional to its mass.

Mathematically, it is given by the formula;

Force = mass * acceleration

Substituting into the formula, we have;

Force = 2 * 9.81

Force = 19.62 Newton