Suppose your class invites a person to give a speech. When you test out the sound system in the gym you find there are so many echoes the speaker cannot be understood. What needs to be done to fix this problem?
Answer:
You either need to lower the volume so the sounds intensity is lessened. Or you can pad the walls to absorb the sound rather than defect.
Explanation:
Sound intensity allows it to be heard further, but in an enclosed room it will start returning. Sound will deflect off of hard objects do to its interactions with solids. A softer and foamy material can dampen it.
What is the intensity of sound produced by an elephant's call if it has a power of 0.45 W and you are standing 32.5 m away from the lumbering beast
Answer:
I = 1.36 x 10⁻⁴ W/m²
Explanation:
The intensity of the sound produced by the Elephant can be calculated by using the following formula:
[tex]I = \frac{P}{A} \\\\[/tex]
where,
I = Intensity of sound = ?
P = power of sound = 0.45 W
A = area = πr² = π(32.5 m)² = 3318.3 m²
Therefore,
[tex]I = \frac{0.45\ W}{3318.3\ m^2} \\\\[/tex]
I = 1.36 x 10⁻⁴ W/m²
is a
The wire in a simple circuit
which forms an
unbroken pathway, allowing the
electric charges to flow.
A. switch
B. insulator
C. resistor
D. conductor
Answer:
I believe the answer is D: Conductor.
When 120 V is applied across a 20 m long wire, the magnitude of the current density was found to be 2 * 10 ^ 8 * A / (m ^ 2) . The resistivity of this wire is
Answer:
[tex]\rho=3\times 10^{-8}\ \Omega-m[/tex]
Explanation:
Given that,
Voltage, V = 120 V
The length of the wire, l = 20 m
The current density of the wire, [tex]\dfrac{I}{A}=2\times 10^8\ A/m^2[/tex]
We need to find the resistivity of this wire. We know that,
[tex]R=\rho \dfrac{l}{A}[/tex]
Where
[tex]\rho[/tex] is the resistivity of wire
Also, [tex]R=\dfrac{V}{I}[/tex]
So,
[tex]\dfrac{V}{I}=\rho \dfrac{l}{A}\\\\\rho=\dfrac{V}{l\dfrac{I}{A}}[/tex]
Put all the values,
[tex]\rho=\dfrac{120}{20\times 2\times 10^8}\\\\=3\times 10^{-8}\ \Omega-m[/tex]
So, the resistivity of this wire is equal to [tex]3\times 10^{-8}\ \Omega-m[/tex].
Use the drop-down menu to answer the question.
According to "Take a Closer Look", what type of lens is used to correct nearsightedness?
Answer: A.) concave lens
Explanation: i hope this helps shawtay :)
In general, a concave lens (also known as a diverging lens) is used to correct nearsightedness, as stated in "Take a Closer Look." Option C is correct.
What is the lens?A lens is an optical component that is used to refract (bend) and focus light. It is typically made of a transparent material, such as glass or plastic, and has a specific shape that allows it to alter the path of light as it passes through.
Here,
In general, a concave lens (also known as a diverging lens) is used to correct nearsightedness, as stated in "Take a Closer Look."
A concave lens is thinnest at the center and thicker at the edges, which causes light rays passing through the lens to diverge or spread out. By placing a concave lens in front of a nearsighted eye, the lens causes incoming light rays to diverge more before they reach the eye's lens, which then focuses them properly on the retina, resulting in clearer vision.
Learn more about the lens here:
https://brainly.com/question/2919483
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POSSIBLE 1. Which of the following are examples of a physical reactions: (1) ice melting, (2) pencil breaking, (3) iron rusting, (4) wood burning? a. 1.4 b. 3,4 c. 2.3 d. 1,2
Answer:
D) 1 & 2
Explanation:
Ice melting can be refrozen and although the pencil breaks, it doesn't change the chemical formula of the pencil
how can a sound of a different note be produced in a guitar without changing the length of wire?
Answer:
how tightly strung the wire is
-- Make the string tighter or looser.
-- Keep the same length, but make the string thicker or thinner.
-- Touch the string at a point exactly 1/2, 1/3, 1/4, or 1/5 of its length from one end.
How many snowmen do you think this sled can destroy? Explain your answer.
Answer:
342,690
Explanation:
I think, given 342,690 snowmen down a giant hill, that sled could destroy every single snowman :)
9. Bryce drove his car 10 km from his house to Belle Plaine. It took him 8 minutes. He got stopped at a long
traffic light on the return home and so he took 2 minutes longer on the return trip. What was Bryce's average
speed in km per minute? (3 pt)
Answer:
2 km/minuteExplanation:
Here, we are asked to calculate the average speed in km/minute.
As we know that,
Average speed = Total distance ÷ Total time takenHere,
→ Total distance = 10 km + 10 km
Because, he first drove 10 km from his house to Belle Plaine and then he again came back to his house.→ Total distance = 20 km
→ Total time = 8 minutes + 2 minutes
→ Total time = 10 minutes
Substitute the values in the formula of average speed,
→ Average speed = Total distance ÷ Total time taken
→ Average speed = 20km ÷ 10 minutes
→ Average speed = 2 km per minuteA wire lying along a y axis form y=0 to y=0.25 m carries a current of 2.0 mA in the negative direction of the axis. the wire fully lies in a magnetic field given by (0.3y)i + (0.4y)j Tesla. what is The magnetic force on the wire
A: (0.15i+0.2j) N
B: (0.0015i+0.002j) N
C: (-6.25E-5 k) N
D:(6.25E-5 k) N
E: None of the above
Answer:
E: None of the above
Explanation:
Since the force on the wire F = ∫idL × B where i = current in wire = 2.0 mA = 2.0 × 10⁻³ A, dL = vector length of wire = dyj and we integrate from y₁ = 0 m and y₂ = 0.25 m, and B = magnetic field = (0.3y)i + (0.4y)j
So, F = ∫idL × B
and we integrate from y₁ = 0 m and y₂ = 0.25 m
F = 2.0 × 10⁻³ A∫₀⁰°²⁵[dyj m × (0.3y)i + (0.4y)j]
F = 2.0 × 10⁻³ A∫₀⁰°²⁵[dyj m × (0.3y)i + dyj m × (0.4y)j]
F = 2.0 × 10⁻³ A∫₀⁰°²⁵[(0.3y) × dy(j × i) + 0.25 × (0.4y)(j × j)]
F = 2.0 × 10⁻³ A∫₀⁰°²°⁵[(0.3ydy(-k) + 0.1y)(0)]
F = 2.0 × 10⁻³ A∫₀⁰°²⁵(-0.3ydy)k
F = 2.0 × 10⁻³ A[-0.3y²/2]₀⁰°²⁵k
F = -2.0 × 10⁻³ A[0.3(0.25)²/2 - 0.3(0)²/2]k
F = -2.0 × 10⁻³ A[0.3(0.0625)/2 - 0]k
F = -2.0 × 10⁻³ A[0.3(0.0625)/2]k
F = -1 × 10⁻³[0.01875]k N
F = -[0.01875 × 10⁻³]k N
F = -[1.875 × 10⁻⁵]k N
Since the answer is not contained in the options, the answer is E.
the spring constant for each of these springs 100 000 N m-1. Calculate the distance that each of these rear springs is compressed by this vehicle as shown in the diagram above
Answer:
sorry
Explanation:
The bumper cars crash into each other and stop. Explain why both bumper cars stop after the crash. [4marks]
Answer:
The collision is inelastic
Explanation:
There are two kinds of collision; elastic collision and inelastic collision. In an elastic collision, both momentum and kinetic energy are conserved.
However, in an inelastic collision, kinetic energy is not conserved. So, when the bumper of two cars collide, the cars come to a stop because the collision is inelastic.