A solution was prepared by dissolving 27.1g of sucrose (C12H22O11) in 250 g of water. Find the molality of the solution(molar mass of C12H22O11 is 342.8)
-.108 m
-108 m
-317 m
-.317 m

Answers

Answer 1

Answer:

M = 0.317 m

Explanation:

From the given information:

Using the following formula:, the molality M is:

[tex]M= \dfrac{W_A}{M_A}\times \dfrac{1000}{W_B(g)}[/tex]

where;

M = molality

[tex]W_A[/tex]= mass of the solute = 27.1 g

[tex]M_A[/tex] = molar mass of the solute = 342.8

[tex]W_B[/tex] = mass of the given solvent  = 250 g

[tex]M= \dfrac{W_A}{M_A}\times \dfrac{1000}{W_B(g)}[/tex]

[tex]M= \dfrac{27.1}{342.8}\times \dfrac{1000}{250}[/tex]

M = 0.317 m


Related Questions

A solution has a concentration of 4.55x10^-2 H+ ions what is the pH

Answers

Answer:

1.34

Explanation:

PH can be calculated by taking the negative logarithm to the base ten of the hydrogen ion concentration

Calculate how many grams of methane (CH4) are in a sealed 800. mL flask at room temperature (22 °C) and 780. mm of pressure. Show work pls.

Answers

"0.0340" mol of CH₄ are in sealed flask.

Methane (CH₄)

Methane would also be a greenhouse gas, therefore its existence tends to affect humanity's surface temp as well as weather patterns framework; it is released into the atmosphere from such a wide assortment of life forms as well as biogenic.

According to the question,

Volume, V = 800 mL or, 0.800 L

Temperature, T = 22°C or, 295

Pressure, P = [tex]\frac{780}{760}[/tex] = 1.03 atm

As we know the relation,

The gram of moles will be will be:

→ n = [tex]\frac{PV}{RT}[/tex]

By substituting the values, we get

     = [tex]\frac{1.03\times 0.800}{0.08206\times 295}[/tex]

     = [tex]\frac{0.824}{242.077}[/tex]

     = 0.0340

Thus the response above is correct.

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Diamond is the hardest mineral according to Mohs Hardness Scale having a hardness scale reading of 1. True or false ? if you get it right ill make u brainliest also ill give all points ! ​

Answers

I believe it to be true. Diamonds are the hardest minerals. Being able to cut through any gem.

Rate 2021 so far
1/5
2/5
3/5
4/5
5/5

Answers

Answer:

Is this an actual question that you had for school?

Explanation:

Answer:

3/5. Its still really stressful but at least it's better than 2020.

The equivalence point of a titration corresponds to which of the following?
O the point where equal volumes of acid and base have been used
O Equivalence point is another term for end point
All of the listed options are true
Equivalence point is defined as the point where the pH indicator changes color
O the point where the acid and base have been added in proper stoichiometric amounts

Answers

Answer:

E: the point where the acid and base have been added in proper stoichiometric amounts

Explanation:

Equivalence point in titration is simply the point where the amounts of acid and base used just sufficiently reacts chemically to cause neutralization whereas the endpoint is the point where the indicator of the titration changes colour.

The Equivalence point occurs before the endpoint.

Thus, option E is correct.

Which of the following is constant in the universe?
A. Total energy
B. Total entropy
C. Total heat
D. Total temperature

Answers

Answer:

A

Explanation:

ez l.m.a.o.

How many ions will CaBr2 dissociate to in solution?
-cannot be determined
-3
-2
-0

Answers

Answer:

3.

Explanation:

Hello there!

In this case, according to the definition of ionic bonds, whereby the cations give away their initial valence electrons to the anions, we infer that ionic species calcium bromide has three ions, one calcium ion and two bromide ions, and therefore the answer is 3.

Regards!

- Nitinol is an alloy of *
1 point
A. Nitrogen and Titanium
B. Nickel and Titanium
C. Nitrogen and Thallium
) D. Nickel and Thalium

Answers

Answer:

Nickel and Titanium

Explanation:

Nitinol is an alloy of Nickel and Titanium. It posesses two properties such that,

The shape memory effectSuper elasticity

Shape memory is the ability of nitinol to undergo deformation at one temperature, stay in its deformed shape when the external force is removed.

Superelasticity is the ability for the metal to undergo large deformations and immediately return to its undeformed shape upon removal of the external load.

Hence, the correct option is (b) "Nickel and Titanium".

What things contribute to the amount of greenhouse gasses on Earth?

Answers

Human activities are responsible for almost all of the increase in greenhouse gases in the atmosphere over the last 150 years. The largest source of greenhouse gas emissions from human activities in the United States is from burning fossil fuels for electricity, heat, and transportation.

PLEASE HELP! (8.01 MC)

What is capillary action? Describe how capillary action shown by water is useful for
plants and animals on Earth. (8 points)

Answers

Capillary action help the root of plant to absorb water from the soil and help animals to bring water.

What is capillary action?

Capillary action is the process by which water flow and passed through a narrow space without the help of an opposition or any form of external forces like gravity.

Therefore, Capillary action help the root of plant to absorb water from the soil and help animals to bring water.

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A buffer solution contains 0.329 M NaHCO3 and 0.246 M Na2CO3. Determine the pH change when 0.072 mol KOH is added to 1.00 L of the buffer. pH after ad

Answers

Answer:

The pH change is 0.22.

Explanation:

The pKa of the buffer NaHCO3/Na2CO3 is 10.329. To find the pH of this buffer we can use H-H equation:

pH = pKa + log [Na2CO3] / [NaHCO3]

Where pH is the pH of the buffer, pKa is 10.329 and [] could be taken as the moles of each specie.

As the initial volume of the buffer is 1.00L, the initial moles are:

[Na2CO3] = 0.246mol

[NaHCO3] = 0.329mol

Initial pH is:

pH = 10.329 + log [0.246mol] / [0.329mol]

pH = 10.20

The KOH reacts with NaHCO3 as follows:

NaHCO3 + KOH → NaKCO3 + H2O

Where NaKCO3≅ Na2CO3. That means the moles added of KOH are the increasing in moles of KOH and the moles of NaHCO3 that decreases.

Thus, moles after the addition of KOH are:

[Na2CO3] = 0.246mol + 0.072mol = 0.318mol

[NaHCO3] = 0.329mol - 0.072mol = 0.257mol

And pH is:

pH = 10.329 + log [0.318mol] / [0.257mol]

pH = 10.42

The pH change is:

10.42 - 10.20 =

0.22

List or describe 2 chemical properties of gasoline

Answers

Answer:

The typical composition of gasoline hydrocarbons (% volume) is as follows: 4-8% alkanes; 2-5% alkenes; 25-40% isoalkanes; 3-7% cycloalkanes; l-4% cycloalkenes; and 20-50% total aromatics (0.5-2.5% benzene) (IARC 1989). ... Information regarding the chemical identity of gasoline is located in Table 3-l.

Explanation:



The volume of 3.73 moles of a gas is 78.3 L at a certain temperature and pressure. At the same temperature and pressure, the moles of gas
that occupies 33.3 L is

Answers

Explanation:

) If I have 4 moles of a gas at a pressure of 5.6 atm and a volume of 12 liters, what is the temperature? P PV = nRT. 5.6 (12)=460821) T.

A student weighs 0.347 g of KHP on a laboratory balance. The KHP was titrated with NaOH and the concentration of the NaOH determined to be 0.110 M. For the second titration, the student correctly diluted 6 M HCl from the reagent shelf using a graduated cylinder to obtain approximately 0.6 M HCl. This solution was titrated with the original NaOH solution. The student calculated the concentration of NaOH from the experiment to be 0.099 M. In which experiment should the student be more confident of the concentration of the NaOH solution

Answers

Answer:

Following are the solution to the given question:

Explanation:

Each method through KHP is somewhat more precise since we have weighed that requisite quantity, we exactly know the KHP intensity appropriately. Its initial 6 M HCl concentration was never considered mandatory. They have probably prepared 6 M HCl solution although long ago and could have changed its concentration over even a period.

No bots No bots No bots No bots

Answers

Answer:

Solution given:

8.

4 hydrogen 1 oxygen

9.

4 hydrogen

2oxygen

Required reaction is:

2H2+O2➔2H2O

now

10.

oxygen have 16 amu than total mass in the left side of oxygen is:

16×2=32 amu of Oxygen

11.

total mass of Oxygen in product side is;

16×2=32 amu of Oxygen

Question If 1.2 g of a gas at 3.5 atm of pressure dissolves in
1.0 L of water at 25°C, how much pressure is needed to
dissolve 2.4 g of the gas in 1.0 L of water at the same
temperature?

Answers

Answer:

7.1 atm

Explanation:

Step 1: Calculate Henry's constant

At P = 3.5 atm, we can dissolve 1.2 g of a gas in 1.0 L of water, that is, the concentration is C = 1.2 g/1.0 L = 1.2 g/L. We can calculate Henry's constant, which relates the concentration and the pressure of a gas dissolving in a liquid, using Henry's law.

C = k × P

k = C/P = (1.2 g/L)/3.5 atm = 0.34 g/L.atm

Step 2: Calculate the pressure needed to dissolve 2.4 g of the gas in 1.0 L of water

We want to dissolve 2.4 g of the gas in 1.0 L of water, that is, C = 2.4 g/1.0 L = 2.4 g/L. We can calculate the pressure required using Henry's law.

C = k × P

P = C/k = (2.4 g/L)/(0.34 g/L.atm) = 7.1 atm

Why does 50 g of copper require less heat (q) than 50 g of water, in order to raise the temperature by 15 oC? (Hint - the heat capacity may play a role, but how?)

Answers

Answer:

See Explanation

Explanation:

Specific heat capacity is an intensive physical property of matter. It is a measure of the quantity of heat that must be supplied in order to change the temperature of a unit mass of a substance by 1°C.

The specific heat capacity of a substance determines the quantity of heat that must be supplied in order to effect a temperature change of a unit mass of a substance. The higher the specific heat capacity of a substance, the greater the quantity of heat required to effect a temperature change in a given mass of the substance.

The specific heat capacity of water is 4,200 Joules per kilogram while the specific heat capacity of copper is 385 Joules per kilogram. Hence, the heat capacity of water is far greater than that of copper and consequently, 50 g of copper require less heat (q) than 50 g of water, in order to raise the temperature by 15 oC.

Cu+k.HNO3 --> Cu(No3)2+..........+...........

Answers

Answer:

Cu + HNO3 → Cu(NO3)2 + H2O + NO2

Cu + 4HNO3 → Cu(NO3)2 + 2H2O + 2NO2 (balanced equation)

1. A volume of 120.0 liters of a gas is prepared at a pressure of 400.0 mm Hg and a temperature
100.0 °C. The gas is placed into a tank under high pressure. When the tank cools to 10.0°C,
the pressure of the gas is 20.0 mm Hg. What is the volume of the gas?

Answers

Answer:

[tex]V_2=2487.9L[/tex]

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to calculate the final volume by using the combined ideal gas:

[tex]\frac{P_2V_2}{T_2}=\frac{P_1V_1}{T_1}[/tex]

In such a way, by solving for the final volume, V2, we obtain:

[tex]V_2=\frac{P_1V_1T_2}{P_2T_1} \\\\[/tex]

Now, by plugging in the pressures, temperatures in Kelvins and initial volume, we will obtain:

[tex]V_2=\frac{(400.0mmHg)(120.0L)(283.15K)}{(20.0mmHg)(273.15K)}\\\\V_2=2487.9L[/tex]

Regards!

What is the relative humidity of the air when the dry-bulb temperature is 4°C and the dewpoint is -4°C?
1.
42%
2.
46%
3
51%
4
56%

Answers

Answer:56%

Explanation:

In the dewpoint chart when you line it up it ends up at 56%

The relative humidity of the air when the dry temperature is about 4 degrees and the dew point is about -4 degrees C is 56%. Hence option  4 is correct.

What is dewpoint?

The dew point is the temperature at which the air needs to be colled at a ta constant pressure in order to have an RH of 100%. The dew point is minus four degrees and the RH of the air is 4 degrees.

For the forces to initiate the air must get cooler and a constant addition of water pressure should be there. Thus substrating the temperature of the wet bulb, putting the thermometer on the dry bulb, and making use of the RH chart tells us that RH is 56%

Find out more information about the relative humidity.

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Robert Hooke observed a slice of cork under a microscope. He saw what looked like “pores” or “cells” in it. Hooke can assume that the cork is most likely - Answer F A man made material G A type of living organism H A type of mineral J A petroleum based product

Answers

The cork oak tree from which cork is extracted is native to southwest europe and northwest africa. Cork is extracted from cork oak trees without harming the tree. So cork is a type of mineral. The correct option is C.

What is a cork cell?

The dead cells without having intercellular spaces are defined as the cork cells. They appear at the periphery of roots and stems when they grow older and increase in girth. They also have a chemical called suberin in their walls.

It is the suberin which makes them impervious to gases and water. The outer protective coat of a tree is called the cork. It is one of the components of bark of the tree. The tissues of bark become old and the secondary mersitem replaces them.

Cork is made up of multiple thick layers and it protects the tree from bacterial or fungal infection.

Thus the correct option is C.

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I have 0.76 moles of gas held at a pressure of 1.2 atm and in a container with a volume of 6.7 liters, what is the temperature of the gas

Answers

Answer:

do ñao esceuji  iof

Explanation:

How many moles of KI are present in 0.85L of a 0.55 M KI solution?

Answers

Answer: Amount of moles is 0.47 mol

Explanation: Amount of moles n = cV = 0.55 M · 0.85 l = 0.4675 mol

There are 0.4675 moles of KI in 0.85L of a 0.55 M KI solution

WHAT IS MOLARITY?

Molarity is a measure of the concentration of a solution. It is calculated by dividing the number of moles (n) of a solute by the volume of a solution (V)

Molarity = number of moles (n) ÷ volume (V)

According to this question, the molarity of a KI solution with a volume of 0.85L is 0.55 M. Hence, the number of moles of KI in the solution can be calculated as follows:

Molarity = n/V

0.55 = n/0.85

n = 0.55 × 0.85

n = 0.4675 moles

Therefore, there are 0.4675 moles of KI in 0.85L of a 0.55 M KI solution.

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What is the volume of a balloon if it contains 3.2 moles of helium at a temperature of 20. °C and standard pressure?

Answers

Answer:

1.14 mol

Explanation:

The concept ideal gas law can be used here to determine the volume of the balloon. The volume of the balloon is 76.97 L.

What is ideal gas law?

The combination of Boyle's law, Charles's law and Avogadro's law leads to an equation which gives the combined effect of change of temperature and pressure on the volume of a gas.

According to Boyle's law, V ∝ 1/P

According to Charles's law, V ∝ T

According to Avogadro's law, V ∝ n

On combining all these equations, the ideal gas equation is given as:

PV = nRT

P - Pressure

V - Volume

n - Number of moles

R - Universal Gas constant

T - Temperature

Here the standard pressure is 1 atm

20°C = 20 + 273 = 293 K

V = nRT / P

3.2 × 0.0821 × 293 / 1

= 76.97 L

Thus the volume of balloon is 76.97 L.

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which ecosystem is the least stable

Answers

Answer:

cornfield

Explanation:

I really need helpp

Answers

Answer:

option b

Explanation:

What is the mass number of sodium?

Answers

Answer: Since all sodium atoms have 11 protons, this one has 11 protons. This tells us that it also has 11 electrons. Since the mass number is 23, we know that the sum of protons and neutrons in the nucleus must equal 23.

So the answer is : Mass number = 23

Explanation:

23 sowwy if im wrong 0_0

What is the final volume of a gas (in liters) when the initial volume is 14.00 L at
0.9600 atm, and the pressure changes to 0.01000 atm?

Answers

Answer:

[tex]V_2=1344L[/tex]

Explanation:

Hello there!

In this case, since we have a problem about volume-pressure relationship, the idea here is to use the Boyle's law to calculate the final volume as shown below:

[tex]P_2V_2=P_1V_1\\\\V_2=\frac{P_2V_2}{P_1}\\[/tex]

Then, we plug in the initial and final pressures and the initial volume to obtain:

[tex]V_2=\frac{14.00L*0.9600atm}{0.01000atm}\\\\V_2=1344L[/tex]

Regards!

The equilibrium constant, Kp, for the following reaction is 10.5 at 350 K: 2CH2Cl2(g) CH4(g) CCl4(g) Calculate the equilibrium partial pressures of

Answers

The complete question is as follows: The equilibrium constant, Kp, for the following reaction is 10.5 at 350 K: 2CH2Cl2(g) CH4(g) + CCl4(g) Calculate the equilibrium partial pressures of all species when CH2Cl2(g) is introduced into an evacuated flask at a pressure of 0.968 atm at 350 K. PCH2Cl2 = atm PCH4 = atm PCCl4 = atm

Answer: The equilibrium partial pressures of all species, that is, [tex]CH_{4}[/tex], [tex]CCl_{4}[/tex] and [tex]CH_{2}Cl_{2}[/tex] is 0.420 atm, 0.420 atm and 0.128 atm.

Explanation:

For the given reaction equation, the initial and equilibrium concentration of involved species is as follows.

                       [tex]2CH_{2}Cl_{2}(g) \rightarrow CH_{4}(g) + CCl_{4}(g)\\[/tex]

Initial:                0.968 atm         0               0

Equilibrium:  (0.968 - 2x)           x                x

Now, [tex]K_{p}[/tex] for this reaction is as follows.

[tex]K_{p} = \frac{P_{CH_{4}}P_{CCl_{4}}}{P^{2}_{CH_{2}Cl_{2}}}\\10.5 = \frac{x \times x}{(0.968 - 2x)^{2}}\\x = 0.420[/tex]

[tex]P_{CH_{4}} = x = 0.420 atm\\P_{CCl_{4}} = x = 0.420 atm\\P_{CH_{2}Cl_{2}} = (0.968 atm - 2x) = (0.968 atm - 2(0.420)) = 0.128 atm[/tex]

Thus, we can conclude that the equilibrium partial pressures of all species, that is, [tex]CH_{4}[/tex], [tex]CCl_{4}[/tex] and [tex]CH_{2}Cl_{2}[/tex] is 0.420 atm, 0.420 atm and 0.128 atm.

True or False. And please show your work!

Answers

false I think? I could be wrong

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