A sound source producing 1.00 kHz waves moves toward a stationary listener at one-half the speed of sound.
a) What frequency will the listener hear?
(b) Suppose instead that the source is stationary and the listener moves toward the source at one half the speed of sound. What frequency does the listener hear? How does your answer compare with that in par a? Did you expect to get the same answer in both cases? Explain on physical grounds why the two answers differ

Answers

Answer 1

Answer:

2000Hz and 1500Hz

Explanation:

Using

a) f = f0((c+vr)/(c+vs))

=>>> f0((c)/(c-0.5c))

=>>>1000/0.5 = 2000Hz

b) f = f0((c+vr)/(c+vs))

=>>>f0((c+0.5c)/(c))

=>>>>1000 x 1.5 = 1500Hz

Answer 2

Here we have a problem referring to the Doppler effect, the solutions are:

a) f = 2.0 kHzb) f = 1.5 kHz

The Doppler effect:

The Doppler effect is an effect that explains how the perception of waves changes as the source moves or as the listener moves.

The formula, for sound, is:

[tex]f = \frac{v + v_0}{v - v_1}*f_0[/tex]

where:

v = velocity of the wave = 340 mf = perceived frequencyf₀ = actual frequency = 1.00kHzv₀ = velocity of the observerv₁ = velocity of the source.

a) First we have that the source moves towards a stationary listener, then we have:

[tex]f = \frac{v }{v - v/2}*1.0 kHz\\\\f = \frac{v }{v/2}*1.0 kHz = 2.0 kHz[/tex]

b) in this case, the listener moves towards the source, so we have:

[tex]f = \frac{v + v/2 }{v }*1.0 kHz\\\\f = \frac{ (3/2)*v }{v}*1.0 kHz = 1.5 kHz[/tex]

So in this case the perceived frequency is smaller than in the point a.

This is because the waves will move at a fixed rate in air, in one case, the successive waves are emitted from different points in space (each time closer to the listener) while in the other case the waves are emitted from a fixed point, and the listener moves towards them, thus feels that the waves move faster.

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Related Questions

The electric flux through a spherical surface is 1.4 ✕ 105 N · m2/C. What is the net charge (in C) enclosed by the surface?

Answers

Answer:

The  value is   [tex]Q_{net} =  1.239 *10^{-6} \  C[/tex]

Explanation:

From the question we are told that

   The electric flux is [tex]\Phi =  1.4*10^{5} \  N\cdot m^2/C[/tex]

     

Generally the net charge is mathematically represented as

    [tex]Q_{net} =  \Phi *  \epsilon_o[/tex]

Here [tex]\epsilon_o[/tex] is the permetivity of free space with value  

       [tex]\epsilon_o =  8.85*10^{-12}  \  \  m^{-3} \cdot kg^{-1}\cdot  s^4 \cdot A^2[/tex]

So

   [tex]Q_{net} =  1.4*10^5 *  8.85*10^{-12}[/tex]

=>   [tex]Q_{net} =  1.239 *10^{-6} \  C[/tex]

To conduct a study on depression, you ask people to rate their depression on
a scale of 1 to 10. Their responses are a(n) ___ in your study.
A. discrete variable
B. hidden variable
C. variable
D. observation

Answers

Answer:

The answer is C variable. Just took the quiz.

Explanation:

Answer:

C. variable

Explanation:

A kitten runs 24 x 10⁻² m away from its master in a straight line in 12.6 s, and then run halfway back in one-third the time. Calculate its average velocity. ​

Answers

Answer:

1.43 × 10^-2 m/s

Explanation:

Given the following :

Distance covered away from it's master = D1 = 24×10^-2 m

Time taken to cover the distance = t1 = 12.6s

Then runs halfway back D2 =

D1/ 2 = (24× 10^-2m) / 2 = 12 ×10^-2m

Time taken =T2 = T1/3 = 12.6/3 = 4.2s

Since the kitten ran in a straight line, the it is linear :

Average speed

Linear Average Velocity:

Change in distance / change in time

(D1 - D2) / (T2 - T1)

(24 - 12)×10^-2 / (12.6 - 4.2)

(12 × 10^-2)m / 8.4s

1.4285 × 10^-2

= 1.43 × 10^-2m/s

To whom does the vha provide care for today ?

Answers

Answer:

The Veterans Health Administration (VHA) is the largest integrated health

care system in the United States, providing care at 1,255 health care

facilities, including 170 VA Medical Centers and 1,074 outpatient sites of care

of varying complexity ( VHA outpatient clinics) to over 9 million Veterans

enrolled in the VA .

A car traveling at 7 m/s accelerates at a rate of -0.8 m/s for an interval of 2 seconds.
Find the final velocity.
The nosition of a ninewood derhucar a ohraniodaturi

Answers

Answer:

6.2m/s

Explanation:

v=u+at

v=7+(-0.8/2)(2)

v=7-0.8

v=6.2m/s

X-rays with wavelength of 2.0 nm scatter from a NaCL crystal with plane spacing of 0.281 nm. Find the scattering angle for the second order maxima.

Answers

Explanation:

Wavelength of x-rays = 2 nm

Plane spacing, d = 0.281 nm

It is assumed to find the scattering angle for second order maxima.

For 2nd order, Bragg's law is given by :

[tex]2dsin\theta =n\lambda[/tex]

For second order, n = 2

[tex]sin\theta =\frac{n\lambda}{2d} \\Sin\theta =\frac{2\times2}{2\times0.281} \\\theta =\arcsin (7.14)[/tex]

Here, θ is not defined. Also, the wavelength of x-rays is more than the plane spacing. It means that it cannot produce any diffraction maximum.

Find the value of x in the triangle shown below.
9
C
3

Answers

add the image so we can answer it for you, 621

a net external force of 100.0 N acts on an object of mass 20.0 kg whose initial speed is 10.0 m/s. The force acts in the opposite direction from the objects motion, and it acts for 1.00 s. what is the objects final speed in m/s

Answers

Explanation:

We know that :

[tex]F = m\frac{(v - u)}{t} [/tex]

[tex]100 = 20 \frac{(v - 10)}{1} [/tex]

[tex]v(final \: velocity) = 15 \: m \: sec^{ - 1} [/tex]

Unless indicated otherwise, assume the speed of sound in air to be v = 344 m/s. You blow across the open mouth of an empty test tube and produce the fundamental standing wave of the air column inside the test tube. The speed of sound in air is 344 m/s and the test tube acts as a stopped pipe. Required:a. If the length of the air column in the test tube is 14.0 cm, what is the frequency of this standing wave? b. What is the frequency of the fundamental standing wave in the air column if the test tube is half filled with water?

Answers

Answer:

a

 [tex]f = 614.3 \ Hz[/tex]

b

 [tex]f_h = 1229 \ Hz[/tex]

Explanation:

From the question we are told that

  The speed of sound in the air is  [tex]v_s = 344 \ m/s[/tex]

   The length of the test tube is  [tex]l = 14.0\ cm = 0.14 \ m[/tex]

Since the test tube is closed at on end  the frequency is mathematically represented as

        [tex]f = \frac{v_s}{ 4 l }[/tex]

=>     [tex]f = \frac{344}{ 4 * 0.14 }[/tex]

=>     [tex]f = 614.3 \ Hz[/tex]

From the part B the column of the test tube is half filled with water so the frequency becomes

    [tex]f_h = \frac{v_s}{ 2 l }[/tex]

     [tex]f_h = \frac{344}{ 2 * 0.14}[/tex]

    [tex]f_h = 1229 \ Hz[/tex]

A graph of x vs. t2 is linear, and intercepts the vertical axis at 12 m and the horizontal axis at 4 s2. What is the function?

Answers

Answer:

x = -3t² + 12

Explanation:

x vs t² is a line.

x = at² + b

The y intercept is 12.

x = at² + 12

At t² = 4s², x = 0.

0 = a(4) + 12

a = -3

Therefore, the function is:

x = -3t² + 12

If a baseball travels a distance of 4 meters in 5 seconds, what is its average speed

Answers

Answer:

speed=d/t.

s=4/5=0.8m/s.

A variable is defined as anything that

Answers

Answer : Quantity or quality that varies like manipulating a variable to see what will happen to another variable

A toy police car moves across the room in 10 seconds. The distance the car traveled is
450 centimeters. At what speed did the car travel?

Answers

Answer:

45cm/s

Explanation:

If the distance traveled is 450 centimeters we can assume the speed is 45cm/s by taking the distance and dividing by the time, in this case that is 450 and 10

so our answer would be 45cm/s

What is the momentum of a tiger that has a mass of 81 kg and runs with a velocity of 5.4 m/s to the east

Answers

Given :

Mass of tiger , m = 81 kg .

Velocity of tiger , v = 5.4 m/s .

To Find :

The momentum of tiger .

Solution :

We know , momentum of a body is given by the product of its mass and velocity .

[tex]P=m\times v[/tex]

Now , putting value of m and v in above equation , we get :

[tex]P=m\times v\\\\P=81\times 5.4 \ kg\ m/s\\\\P=437.4 \ kg\ m/s[/tex]

Therefore , the momentum of tiger is 437.4 kg m/s .

Hence , this is the required solution .

Answer:

437.4

Explanation: did the math

If a proton and an electron are released when they are 7.00×10−10 m apart (typical atomic distances), find the initial acceleration of each of them. aelectron = nothing m/s2

Answers

Answer:

The acceleration of the proton is 2.823 x 10¹⁷ m/s²

The acceleration of the electron is 5.175 x 10²⁰ m/s²

Explanation:

Given;

distance between the electron and proton, r = 7 x 10⁻¹⁰ m

mass of proton, [tex]m_p[/tex] = 1.67 x 10⁻²⁷ kg

mass of electron, [tex]m_e[/tex] = 9.11 x 10⁻³¹ kg

The attractive force between the two charges is given by Coulomb's law;

[tex]F = \frac{k(q_p)(q_e)}{r^2}[/tex]

where;

k is Coulomb's constant = 9 x 10⁹ Nm²/c²

[tex]F = \frac{k(q_p)(q_e)}{r^2} \\\\F = \frac{(9*10^9)(1.602*10^{-19})(1.602*10^{-19})}{(7*10^{-10})^2} \\\\F = 4.714 *10^{-10} \ N[/tex]

Acceleration of proton is given by;

F = ma

[tex]F = m_pa_p\\\\a_p = \frac{F}{m_p}\\\\a_p = \frac{4.714*10^{-10}}{1.67*10^{-27}}\\\\a_p = 2.823 *10^{17} \ m/s^2[/tex]

Acceleration of the electron is given by;

[tex]F = m_ea_e\\\\a_e = \frac{F}{m_e}\\\\a_e = \frac{4.714*10^{-10}}{9.11*10^{-31}}\\\\a_e = 5.175 *10^{20} \ m/s^2[/tex]

The acceleration of proton and electron will be "[tex]2.823\times 10^{17} \ m/s^2[/tex]" and "[tex]5.175\times 10^{20} \ m/s^2[/tex]".

Given:

Mass of proton, [tex]m_p = 1.67\times 10^{-27} \ kg[/tex]Mass of electron, [tex]m_e = 9.11\times 10^{-31 } \ kg[/tex]Distance between electron & proton, [tex]r = 7\times 10^{-10} \ m[/tex]

By using Coulomb's law, the attractive force will be:

→ [tex]F = \frac{k(q_p) (q_e)}{r^2}[/tex]

By substituting the values, we get

        [tex]= \frac{(9\times 10^9)(1.602\times 10^{-19}) (1.602\times 10^{-19})}{(7\times 10^{-10})^2}[/tex]

        [tex]= 4.714\times 10^{-10} \ N[/tex]

Now,

The acceleration of proton will be:

→ [tex]F = ma[/tex]

       [tex]= m_p a_p[/tex]

or,

→ [tex]a_p = \frac{F}{m_p}[/tex]

        [tex]= \frac{4.714\times 10^{-10}}{1.67\times 10^{-27}}[/tex]

        [tex]= 2.823\times 10^{17} \ m/s^2[/tex]  

and,

The acceleration of electron will be:

→ [tex]F = m_c a_c[/tex]

or,

→ [tex]a_e = \frac{F}{m_e}[/tex]

        [tex]= \frac{4.714\times 10^{-10}}{9.11\times 10^{-31}}[/tex]

        [tex]= 5.175\times 10^{20} \ m/s^2[/tex]

Thus the above answer is correct.

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You want to create an electric field vector E = < 0, 5 104, 0> N/C at location < 0, 0, 0>. Where would you place a proton to produce this field at the origin?

Answers

Answer:

1.696 × 10^(-7) m on the y axis.

Explanation:

We are given the electric field as;

E = < 0, 5 × 10⁴, 0> N/C

This is written in (x, y, z) co-ordinates. So it means that it lies on the y-axis.

So,

E = 5 × 10⁴ N/C in the y direction.

Formula for Electric field is;

E = kq/r²

where;

k is a constant with a value of 8.99 x 10^(9) N.m²/C²

q is charge on the proton = 1.6 × 10^(-19) C

r is the distance

Thus, making r the subject gives;

r = √(kq/E)

Plugging in the relevant values gives;

r = √(8.99 × 10^(9) × 1.6 × 10^(-19)/(5 × 10⁴))

r = 1.696 × 10^(-7) m on the y axis.

The proton to produce this field at the origin should be put on [tex]1.696 \times 10^{(-7)} [/tex]m on the y axis.

The calculation is as follows:

We are given the electric field as;

[tex]E = < 0, 5 \times 10^{4}, 0> N/C[/tex]

This is written in (x, y, z) co-ordinates. So it means that it lies on the y-axis.

So,

[tex]E = 5 \times 10^{4} N/C[/tex] in the y direction.

The Formula for Electric field is;

E = kq/r²

where;

k is a constant with a value of 8.99 x 10^(9) N.m²/C²

q is charge on the proton = 1.6 × 10^(-19) C

r is the distance

Thus, making r the subject gives;

r = √(kq/E)

Now Plugging in the relevant values gives;

r = √(8.99 × 10^(9) × 1.6 × 10^(-19)/(5 × 10⁴))

r = 1.696 × 10^(-7) m on the y axis.

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Tim can type 2,000 words at a speed of 50 words per min.
Bob's typing speed is 80 words per min. How much less time
did Bob take than Tim to type 2000 words?
min
h

Answers

Answer: the awnser to this question is 15

Explanation:

First you will divide the typing speed and the total number of words by the speed 2000 ÷ 50

Then divide bobs typing speed by 2000 equation 2000÷80 once you get the total both you will subtract the 2 totals together and get 15 as your awnser.

Hoped this helped!

When a circuit is arranged in parallel
A. There are multiple paths that electrons can take through the circuit, and it is possible for the electron to pass through one circuit component but not another.
B. There is only one path the electrons can take through the circuit, and they must pass through all circuit components

Answers

Answer:

A. There are multiple paths that electrons can take through the circuit, and it is possible for the electron to pass through one circuit component but not another.

Explanation:

Parallel arrangement of components in an electric circuit puts different parts of the circuit on different branches. In a parallel connection, there are multiple paths for the electrons to take, and it is possible for electrons to pass through on circuit component without going through another. This is the reason why If there is a break in one branch of the circuit, electrons can still flow in other branches, and the same reason why one bulb going off in your home does prevent the other components in your home from coming on (your home is wired in a parallel electric circuit).

when would a swimmer have the most potential energy due to her position

Answers

Answer: A

Explanation:

A swimmer have the most potential energy due to her position.When he is sitting on the highest diving board at the pool.

What is potential energy?

The potential energy is the due to the virtue of the position and the height. The unit for the potential energy is joule.

The potential energy is found as;

[tex]\rm PE = mgh[/tex]

The potential energy is mainly depending upon the height of the object.

When the swimmer is at the highest position, the height is maximum. Therefore, the potential energy is also maximum.

Hence, a swimmer have the most potential energy due to her position.When he is sitting on the highest diving board at the pool.

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In the absence of government, what would determine the way people act towards each other?

Answers

Answer:

In the absence of government, what would determine the way people act towards each other is the need to acquire means of survival such as food or shelter.

Thus, since the government regulates the rights and obligations of citizens to guarantee equal access to essential services and goods for life, in the event of the disappearance of the state as a form of social organization, people would tend to act selfishly. to provide itself with those goods and services.

Society would then return to a state of nature, where man competes with his peers for access to resources. So the need for those resources would ultimately determine the way humans relate to each other.

Throughout the absence of regulation, the necessity to gain means of subsistence, which includes extra help, would decide how individuals interact with one another.

Absence of Government:

As a consequence, while the organization governs individuals' rights and duties purpose of providing equitable access to vital services and products for life, if the community as more than just a form of social organization disappears, individuals might likely behave selfishly to offer such commodities.

The community would therefore revert to its natural condition, with man competing with equal fellows for distribution of wealth. As a result, the necessity for such resources would eventually decide how humans interact with one another.

Thus the response above is right.

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which component of health related fitness is developed by performing a wall sit

Answers

Answer:

it develop isometric strength and endurance in glutes calves quadriceps,hamstring and adductor muscle

If you were to drop a rock from a tall building, assuming that it had not yet hit the ground, and neglecting air resistance, after 10 s: How fast (speed) would it be traveling (in m/s)

Answers

Answer:

Explanation:

Using the equation of motion v = u + at to get the speed at which the object would be travelling.

v is the final speed (in m/s)

u is the initial velocity (in m/s)

a is the acceleration (in m/s²)

t is the time taken (in  secs)

Given parameters

u = 0m/s

t = 10s

a = g = 9.8m/s²

Substituting this values into the formula;

v = 0+9.8(10)

v = 0+ 98

v  = 98m/s

Hence the rock will be travelling at a speed of 98m/s.

Robert pushes the box to the left at constant speed. In doing so, Robert does ______ work on the box. A. positive B. negative C. zero

Answers

Answer:

He does postive work

Explanation:

Because W= F xS sinစ

So since work is done such that Force and distance have the Sam direction

Thus စ=0

Then work is positive in value

A 7600 kg satellite is in a circular orbit around Earth at a height of 2300 km above Earth's surface. What is this satellite's speed

Answers

Answer:

6779.7m/s

Explanation:

Using

GMm/(Re +h)² = mv²/ (Re+h)

So making v subject we have

V= √GM/Re+h

So

V = √ 6.67*10^-11 x 5.97*10^24/(6371+2300)*10^3

V= 6779.7m/s

Note h = height of satellite

Re= radius of the earth

M = mass of the earth


State two precautions each that you will take while performing refractive index of a glass box experiment​

Answers

Answer:

light should be direct

glass should not be cracked

pins should be pointed carefully

Explanation:

The harder a gas pedal in a car is pressed the faster the car's velocity increases. Which phrase best describes the relationship between how hard the gas pedal is pressed and the acceleration of the car?

A. There is both a negative correlation and causation

B. There is a positive correlation but no causation.

C. There is a negative correlation but no causation.

D. There is both a positive correlation and causation.​

Answers

Answer:

D

There is both a positive correlation and causation

The relationship between how hard the gas pedal is pressed and the acceleration of the car is positive correlation and causation.

From the given statement the relationship between the cause (pedal) and the effect (velocity) can be described as direct relationship.

In direct proportionality, the outcome of one variable produces similar effect to the other variable.

The harder the gas pedal in a car is pressed, the velocity increases. This shows that as the force applied to the gas pedal increases (the cause of the action), the greater the velocity of the car (the effect of the cause).

Thus, we can conclude that the relationship between how hard the gas pedal is pressed and the acceleration of the car is positive correlation and causation.

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Why are experimental investigations the best type of scientific investigation o demonstrat cause-and-effect relationships?

Answers

Answer:

Isolation of Variables.

Explanation:

I am just taking a guess but Experimental investigations allow you to isolate variables (making most variables constant, allowing only the independent variable to have an impact on the dependent variable). With other scientific investigations, if they don't isolate the variables it is very possible that an unknown third variable could be skewing the results (which will result in correlation but not causation).

Answer:

Experimental investigations are the best type of scientific investigation to demonstrate cause-and-effect relationships because they allow the investigator to actively manipulate variables and control conditions. The independent variable can be isolated and manipulated, producing a change (or no change) in the dependent variable. This change can be measured to gather evidence to support or refute the cause-and-effect relationship. Experimental investigations also use a control group (a group that does not receive the factor being tested) for comparison.

Explanation:

Automated-response....it's right

As the frequency of the ac voltage across an inductor approaches zero, the inductive reactance of that coil Group of answer choices

Answers

Answer:

The inductive reactance also approaches zero

Explanation:

This is because from the relation

XL = 2πfL

Meaning frequency f and inductive reactance XL are directly proportional so as one approaches zero so does the other

Identify two types of motion where an object's speed remains the same while it continues to change direction.

Answers

Answer:

circular motionmotion of light (photons) on a non-linear path

Explanation:

Velocity is a vector with speed and direction components. If the speed does not change, then the direction must. In order to change the direction of a velocity vector, there must be some acceleration, and it must be orthogonal to the direction of motion.

Circular motion is motion that has a constant acceleration perpendicular to the direction of travel.

__

Another kind of motion that meets the requirement is the motion of light. Light travels at a constant speed, regardless. If light changes direction (as in a gravitational field or when reflected), its direction will change, but its speed will not.

Which of these equations is dimensionally correct?
I. mv/ t= F
II. xv^2= Fx^3/ x^2
III. xt= vt^2+at^3

Answers

Answer: first and third.

Explanation:

An equation is dimensionally correct if the units are the same in both sides of the equation.

first, let's define the units used:

{m} = kg

{v} = m/s

{F} = kg*m/s^2

{x} = m

{t} = s

{a} = m/s^2

Now, let's analyze each option:

1) m*v/t = F

in the left side the units are:

{m}*{v}/{t} =  kg*(m/s)*(1/s) = kg*m/s^2

And as is written above, these are the units of F, so this is correct.

2) x*v^2 = F*(x^3/x^2)

This is more trivial, in the right side we can see an F, that has mass units (kg)  and in the left side we have x and v, and we know that none of these have mass units, so this expression is not correct.

3) xt= vt^2+at^3

the units in the right side are:

{x}*{t] = m*s

in the right side are:

{v}*{t}^2 + {a}*{t}^2 = (m/s)*s^2 + (m/s^2)*s^3 = m*s + m*s

So in both sides of the equation we have the same units, then this equation is dimensionally correct.

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