Answer:
15.2 grams of calcium chloride are produced and HCl is the limiting reactant.
Explanation:
Hello there!
In this case, according to the described scenario, it is possible to realize that the reaction between hydrochloric acid and calcium hydroxide is:
[tex]2HCl+Ca(OH)_2\rightarrow CaCl_2+2H_2O[/tex]
Whereas there is a 2:1 mole ratio of the acid to the base. In such a way, with the given masses, we can compute how much calcium chloride product is produced due to the chemical reaction via stoichiometry:
[tex]m_{CaCl_2}^{by HCl}=10.0gHCl*\frac{1molHCl}{36.46gHCl}*\frac{1molCaCl_2}{2molHCl} *\frac{110.98gCaCl_2}{1molCaCl_2} =15.2gCaCl_2\\\\m_{CaCl_2}^{by Ca(OH)_2}=10.5gHCl*\frac{1molCa(OH)_2}{74.09gCa(OH)_2}*\frac{1molCaCl_2}{1molCa(OH)_2} *\frac{110.98gCaCl_2}{1molCaCl_2} =15.7gCaCl_2[/tex]
Whereas we infer that the correct amount is 15.2 g since HCl is the limiting reactant as it produces the fewest grams of the desired product. Consequently, the calcium hydroxide is the excess reactant here.
Regards!
Choose the options below that are true.
A. The rate law for a given reaction can be determined from a knowledge of the rate-determining step in that reaction's mechanism.
B. The rate laws of all chemical reactions can be determined directly from their net chemical equations.
C. The rate laws of bimolecular elementary reactions are second order overall.
D. The rate law for a given reaction can be determined from its reaction mechanism, without the accompanying rates of each elementary step in the mechanism.
Answer:
The options (A) -The rate law for a given reaction can be determined from a knowledge of the rate-determining step in that reaction's mechanism. and (C) -The rate laws of bimolecular elementary reactions are second order overall ,is true.
Explanation:
(A) -The rate law can only be calculated from the reaction's slowest or rate-determining phase, according to the first sentence.
(B) -The second statement is not entirely right, since we cannot evaluate an accurate rate law by simply looking at the net equation. It must be decided by experimentation.
(C) -Since there are two reactants, the third statement is correct: most bimolecular reactions are second order overall.
(D)-The fourth argument is incorrect. We must track the rates of and elementary phase that is following the reaction in order to determine the rate.
Therefore , the first and third statement is true.
what happens when a molecule absorbs infrared radiation
Answer:
When a molecule absorbs infrared radiation,transition s occur from the ground vibrational state to an excited vibrational state. For a molecule to be IR active there must be a change in dipole moment as a result of the vibration that occurs when IR radiation is absorbed.
If an equilibrium mixture of the three gases at 600K contains 2.92*10^-2 M COCH(g) and 1.76*10^2 M CO, what is the equilibrium
concentration of Cl2?
Answer:
C
Explanation:
does anyone know how to do this?
Answer:
nah
Explanation:
What is the source of Earth's magnetic field according to what you have read in chapter 222
Answer:
Scientists know that today the Earth's magnetic field is powered by the solidification of the planet's liquid iron core. The cooling and crystallization of the core stirs up the surrounding liquid iron, creating powerful electric currents that generate a magnetic field stretching far out into space.
1. What volume of a 2.50M Kl(aq) is needed to make 200 ml of a 1.OOM KI)aq)?
Answer:
80 ml
Explanation:
From the question,
Applying Dilution formular
MV = mv................... Equation 1
Where M = Molarity of Kl before dilution, V = Volume of Kl before dilution, m = molarity of Kl after dilution, v = volume of Kl after dilution.
make V the subject of the equation
V = mv/M............. Equation 2
Given: m = 1.00 M, v = 200 ml, M = 2.50 M
Substitute these values into equation 2
V = (1.00×200)/2.50
V = 80 ml
Help it’s due right now I will give you 15 points or more
Answer:
1. Temperature, the average kinetic energy of particles, indicates how warm something is. Thermal energy, or the overall kinetic energy of the particles, indicates how a substance or material will transmit heat or chill something else.
2. A thermal expansion is a matter to change in volume in response to a change in temperature.
3. Heat is the form of energy that is transferred between systems or objects with different temperatures.
4. Air temperature near or over bodies of water is much different from that over land due to differences in the way water and land heat and cool. Properties that affect water temperature are transparency, ability to circulate, and specific heat.
5. Radiation is the transfer of heat energy through space by electromagnetic radiation.
6. Radiation is natural and found everywhere, it comes from outer space, the air we breathe, and the earth we tread.
7. When a fluid, such as air or a liquid, is heated and then travels away from the source, it carries the thermal energy along. The fluid above a hot surface expands, becomes less dense, and rises.
8. Convection currents in the Earth occur in the mantle
9. The fire's heat causes molecules in the pan to vibrate faster, making it hotter. These vibrating molecules collide with their neighboring molecules, making them also vibrate faster.
10. Since air is a poor conductor, most energy transfer by conduction occurs right near Earth's surface. Conduction directly affects air temperature only a few centimeters into the atmosphere.
- Hope this helps!
Gallium (, ) is a metalloid obtained from its salts during the smelting of ores of other elements, like Zinc. has broad applicability in the electronics industry. It is also used as a safe replacement for mercury in thermometers as it melts at and has a heat of fusion of . What is the entropy change of of gallium in as it melts when placed on a surface at
The given question is incomplete. The complete question is:
Gallium (Ga, 69.723 g/mol) is a metalloid obtained from its salts during the smelting of ores of other elements, like Zinc. has broad applicability in the electronics industry. It is also used as a safe replacement for mercury in thermometers as it melts at 29.8 °C and has a heat of fusion of 5.59 kJ/mol. What is the entropy change of 22 g of gallium in J/K as it melts when placed on a surface at 29.8°C?
Answer: The entropy change of of gallium in as it melts when placed on a surface at is 5.81 J/K
Explanation:
Latent heat of fusion is the amount of heat required to convert 1 mole of solid to liquid at atmospheric pressure.
Amount of heat required to melt 1 mole of Ga = 5.59 kJ
Mass of Ga given = 22 gram
Heat required to melt 69.723 g of Ga = 5.59 kJ
Thus Heat required to melt 22 g of Ga = [tex]\frac{5.59kJ}{69.723}\times 22=1.76kJ[/tex]
Temperature = [tex]29.8^0C=(273+29.8)kJ=302.8kJ[/tex]
Now entropy change = [tex]\frac{\text {heat of fusion}}{\text {temperature in K}}=\frac{1.76kJ}{302.8K}=0.00581kJ/mol=5.81J/K[/tex]
Thus the entropy change of of gallium in as it melts when placed on a surface at [tex]29.8^0C[/tex] is 5.81 J/K
What do the symbols in the parentheses indicate
Answer:
(C) the physical state of each reactant and product
Explanation:
Hope this helps
The speed of an electron is 1.68*10^8m/s what is the wavelength
Answer:
[tex]\lambda =4.33x10^{-12}m=4.33pm[/tex]
Explanation:
Hello there!
In this case, since the speed, wavelength and mass of an electron are related via the the Broglie wavelength:
[tex]\lambda =\frac{h}{m*v}[/tex]
Thus, by plugging in the mass of the electron and the Planck's constant, we obtain the following wavelength:
[tex]\lambda =\frac{6.626x10^{-34}J*s}{9.11x10^{-31}kg*1.68x10^{8}m/s}\\\\\lambda =4.33x10^{-12}m=4.33pm[/tex]
Best regards!
Why aren't gas molecules attracted to each other? Explain.
Answer:
As gas is compressed, the individual molecules begin to move in each others way creating a very repulsive force. It acts to oppose any further volume decrease. At very close distances, all molecules repel each other as their electron clouds emerge.
Explanation:
Which metals will switch in this single replacement reaction Zn + MgO -->
a. Mg and Zn
b. Zn and O
c. Mg and O
d. This is not a single replacement reaction
Answer:
D
Explanation:
Magnesium is more reactive than zinc so no reaction will take place
What is the chemical formula for an acid?
ANSWER THIS GET 25 POINTS!!!!
Sam is walking in a garden on a day represented by the figure above. Which plants in the garden could be blooming on this day?
A:long-day and day-neutral plants
B: day-neutral plants only
C: short-day and day-neutral plants
D: short-day, long-day, and day-neutral plants
Answer:
C: short-day and day-neutral plants
Explanation:
There is no figure above.
What material would make the most efficient hot pack?
●Lithium Chloride
●Sodium Chloride
●Sodium Hydroxide
●Potassium Chloride
Answer:
Lithium Chloride would be the best one
Sodium Hydroxide would be the second best
Explanation:
Write a net ionic equation for the reaction that occurs when aqueous solutions of hydrofluoric acid and barium hydroxide are combined. Include solubility states
Answer: The net ionic equation is [tex]2H^+(aq)+2F^-(aq)+Ba^{2+}(aq)+2OH^-(aq)\rightarrow BaF_2(s)+2H_2O(l)[/tex]
Explanation:
The net ionic equation of any reaction does not include any spectator ions.
Spectator ions are defined as ions that do not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.
The chemical equation for the reaction of hydrofluoric acid and barium hydroxide follows:
[tex]2HF(aq)+Ba(OH)_2(aq)\rightarrow BaF_2(s)+2H_2O(l)[/tex]
The ionic form of the above equation follows:
[tex]2H^+(aq)+2F^-(aq)+Ba^{2+}(aq)+2OH^-(aq)\rightarrow BaF_2(s)+2H_2O(l)[/tex]
There are no spectator ions in the ionic form.
The net ionic equation for the above reaction follows:
[tex]2H^+(aq)+2F^-(aq)+Ba^{2+}(aq)+2OH^-(aq)\rightarrow BaF_2(s)+2H_2O(l)[/tex]
if a gas sample has a pressure of 30.7 kPa at 273 K, what does the temperature have to decrease to lower the pressure to 28.4 kPa?
253K
268K
262K
What is the entropy of this collection of training examples with respect to the positive class B. What are the information gains of A1 and A2 relative to the training dataset For A3, which is a continuous attribute, compute the information gain for every possible split. C. What is the best split (among A1,A2, and A3) according to the information gain
The data set is missing in the question. The data set is given in the attachment.
Solution :
a). In the table, there are four positive examples and give number of negative examples.
Therefore,
[tex]$P(+) = \frac{4}{9}$[/tex] and
[tex]$P(-) = \frac{5}{9}$[/tex]
The entropy of the training examples is given by :
[tex]$ -\frac{4}{9}\log_2\left(\frac{4}{9}\right)-\frac{5}{9}\log_2\left(\frac{5}{9}\right)$[/tex]
= 0.9911
b). For the attribute all the associating increments and the probability are :
[tex]$a_1$[/tex] + -
T 3 1
F 1 4
Th entropy for [tex]$a_1$[/tex] is given by :
[tex]$\frac{4}{9}[ -\frac{3}{4}\log\left(\frac{3}{4}\right)-\frac{1}{4}\log\left(\frac{1}{4}\right)]+\frac{5}{9}[ -\frac{1}{5}\log\left(\frac{1}{5}\right)-\frac{4}{5}\log\left(\frac{4}{5}\right)]$[/tex]
= 0.7616
Therefore, the information gain for [tex]$a_1$[/tex] is
0.9911 - 0.7616 = 0.2294
Similarly for the attribute [tex]$a_2$[/tex] the associating counts and the probabilities are :
[tex]$a_2$[/tex] + -
T 2 3
F 2 2
Th entropy for [tex]$a_2$[/tex] is given by :
[tex]$\frac{5}{9}[ -\frac{2}{5}\log\left(\frac{2}{5}\right)-\frac{3}{5}\log\left(\frac{3}{5}\right)]+\frac{4}{9}[ -\frac{2}{4}\log\left(\frac{2}{4}\right)-\frac{2}{4}\log\left(\frac{2}{4}\right)]$[/tex]
= 0.9839
Therefore, the information gain for [tex]$a_2$[/tex] is
0.9911 - 0.9839 = 0.0072
[tex]$a_3$[/tex] Class label split point entropy Info gain
1.0 + 2.0 0.8484 0.1427
3.0 - 3.5 0.9885 0.0026
4.0 + 4.5 0.9183 0.0728
5.0 -
5.0 - 5.5 0.9839 0.0072
6.0 + 6.5 0.9728 0.0183
7.0 +
7.0 - 7.5 0.8889 0.1022
The best split for [tex]$a_3$[/tex] observed at split point which is equal to 2.
c). From the table mention in part (b) of the information gain, we can say that [tex]$a_1$[/tex] produces the best split.
Estimate your de Broglie wavelength when you are running. (For this problem use h = 10^−34 in SI units and 1 lb is equivalent to 0.45 kg.) For the computation, estimate how fast you can run in meters per second.
A. your running speed ______ m/s
B. your mass ______kg
C. your de Broglie wavelength ______ m
Answer:
A. your running speed 1.5 m/s
B. your mass 70 kg
C. your de Broglie wavelength [tex]6.32x10^{-36}[/tex]m
Explanation:
Hello there!
In this case, since the equation for the calculation of the Broglie wavelength is:
[tex]\lambda =\frac{h}{m*v}[/tex]
We can assume a running speed of about 1.5 m/s and a mass of 70 kg, so the resulting Broglie wavelength is:
[tex]\lambda =\frac{6.626x10^{-34}kg\frac{m}{s} }{70kg*1.5\frac{m}{s} }\\\\\lambda =6.32x10^-36m[/tex]
Best regards!
From these four cycles which are water cycle, carbon cycle, nitrogen cycle, and phosphorus cycle which cycle has more nutrients
Answer:
Nitrogen cycle
Explanation:
How many moles of Cs are contained in 3 moles of Cs3PO4?
Answer:
[tex]\boxed {\boxed {\sf 9 \ moles \ Cs}}[/tex]
Explanation:
We are given the compound: Cs₃PO₄
According to the formula, 1 mole of cesium phosphate contains 3 moles of cesium, 1 mole of phosphate, and 4 moles of oxygen.
Therefore, there are 3 moles of cesium for 1 mole of cesium phosphate.
[tex]\frac {3 \ mol \ Cs}{1 \ mol \ Cs_3PO_4}[/tex]
We want to calculate the moles of cesium in 3 moles of cesium phosphate, so we multiply the ratio by 3.
[tex]3 \ mol \ Cs_3PO_4 *\frac {3 \ mol \ Cs}{1 \ mol \ Cs_3PO_4}[/tex]
[tex]3 *\frac {3 \ mol \ Cs}{1 }= 9 \ mol \ Cs[/tex]
3 moles of cesium phosphate contains 9 moles of cesium.
Do nitrates always form precipitates?
Answer:
Nitrates compared to sulphates are much more soluble therefore won't form precipitates easily.
Can tell the answer pls
Explanation: where the article????
Which sublevels hold valence electrons?
Answer:
The Periodic Table can be divided into s, d, p, and f sublevel blocks. For elements in the s sublevel block, all valence electrons are found in s orbitals. For elements in the p sublevel block, the highest energy valence electrons are found in p orbitals.
Explanation:
Use this picture to explain that an electrically charged object can attract an uncharged object without any contact. Your answer should be at least three sentences long. (2 points) a balloon hanging from a string with small pieces of paper stuck to the bottom of it, with a few pieces on the ground
Answer: Insufficient amount of work provided.
Explanation:
Please help ASAP
Identify the atom with the ground-state electron configuration shown for its valence shell.
3s^2 3p^1
8. How much heat will be released when
18.6 g of hydrogen reacts with excess O2
according to the following equation?
Answer:
15 is it
Explanation:
The addition, removal, or substitution of nitrogenous bases in a DNA molecule may be caused by . Synapsis C. Disjunction B. Hybridization D. Mutation
Answer:
D. Mutation
Explanation:
Mutation is any change or alteration that occurs to the nucleotide sequence of a gene induced during DNA replication or by mutation-causing substances called MUTAGENS.
Mutation can be in the form of addition, removal, or substitution of nitrogenous bases in a DNA molecule. For example, in an original DNA sequence as follows: GAT ATC TGA, the following mutation can occur:
Addition: GAT ATC CTG A
Removal: GAT ATT GA
Substitution: GAT CTC TGA
What type of Weathering is important to sand storms on Mars? Physical or
Chemical?
Why would 3D printing be important on Mars and why would you use material from the surface of Mars.
We could "print" things that we need on Mars.
We could print things that we need on Mars and use material that is already on the planet
It would be so cool
The cost would be less expensive.
Answer:
1. Physical Weathering
2. Option B
Explanation:
1. Physical weathering
On Mars, there are two types of weathering agents a) wind and b) acid fog. Thus, they will carry out only physical weathering
2. Option B
3D can be used to produce things that are required on the Mars and also the locally available raw material can be used for printing thereby saving the cost.
a Technical
How to write
report