A student mixes 250 millimeters of a strong base with 100 millimeters of a strong acid. What will the result be?
- a weak base
— weak acid
- a stronger base
- a stronger acid

Explanation:

The halogen family and noble gases are similar in just one particular way, they are groups of non-metals. All members of these two groups are categorized as non-metals.

Here are some of the differences between them;

Answer:C - 3.115 g

Explanation:Correct

Answer: Inertia

Explanation:

Answer:

67.6 years is the time the isotope take to decay from 0.900g to 0.170g

Explanation:

The radioactive decay follows first order law:

Ln [A] = -kt + ln[A]₀

Where [A] is concentration after time t,

k is decay constant:

k = ln 2 / t(1/2)

k = ln2 / 28.1 years

k = 0.02467 years⁻¹

[A]₀ = Initial concentration.

We can replace concentration and use the mass of the isotope:

Ln [A] = -kt + ln[A]₀

Ln [0.170g] = -0.02467 years⁻¹t + ln[0.900g]

-1.667 = -0.02467 years⁻¹t

t =

The time required for the sample to reduce to 0.170 grams has been 67.75 years.

Half-life can be defined as the times required by the substance to reduce to half of its initial concentration.

The half-life can be expressed as:

Amount left = Initial amount [tex]\times[/tex] [tex]\rm \dfrac{1}{2}^\dfrac{time}{Half-life}[/tex]

From the given:

0.17 g = 0.9 [tex]\rm \times\;\dfrac{1}{2}^\dfrac{t}{28.1}[/tex]

[tex]\rm \dfrac{0.17}{0.9}[/tex] = [tex]\rm \dfrac{1}{2}^\dfrac{t}{28.1}[/tex]

0.188 = [tex]\rm (0.5)^\dfrac{t}{28.1}[/tex]

Taking log on both the sides,

log 0.188 = [tex]\rm \dfrac{t}{28.1}\;\times[/tex] log 0.5

2.411 = [tex]\rm\dfrac{t}{28.1}[/tex]

t = 2.411 [tex]\times[/tex] 28.1 years

Time = 67.75 years.

The time required for the sample to reduce to 0.170 grams has been 67.75 years.

For more information about half-life, refer to the link:

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Answer:

A . The work done stretching a spring is transformed into stored energy in the spring

Explanation:

The work done stretching a spring is transformed into stored energy in the spring is clear indication of the law of conservation of energy.

The law of conservation of energy states that "energy is neither created nor destroyed but transformed from one form to another".

This is an energy transformation process.

Answer:

The answer is that light is faster than sound.

Explanation:

A good example is of lightning and thunder during a thunderstorm.

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Answer:

beryllium has a higher ionization energy because its radius is smaller. boron has a higher ionization energy because its radius is smaller.

Answer:

you can burn it.

Explanation:

that is the way to change paper

Answer:

2.1 moles of water formed.

Explanation:

Given data:

Moles of water formed = ?

Moles of Ni(OH) = 4.20 mol

Solution:

Chemical equation:

2Ni(OH)    →  Ni₂O + H₂O

Now we will compare the moles of Ni(OH)  with water.

             Ni(OH)           :            H₂O

                2                 :              1

              4.20             :            1/2×4.20 = 2.1 mol

2.1 moles of water formed.

Answer:

True

Explanation:

All irreversible reactions go to completion because the process cannot proceed in the backward direction.

A reversible reaction is one that does not go into completion in one direction.

An irreversible direction completely uses up the reactants to form the products and goes into completion.

These reactions can only proceed in one direction and not both.

Answer:

159g

Explanation:

Copper (I) sulfide is formed by the chemical reaction between copper and sulfur. Copper is a limiting reagent that results in the formation of 190.26 grams of copper(I) sulfide.

A limiting reagent is defined as the reactant that gets completely utilized in the reaction and affects the amount of the product formation. On the contrary, the excess reagent is present in more amounts.

Given,

Mass of copper = 127 gm

Mass of sulfur = 41 gm

Moles of copper:

n = mass ÷ molar mass

n = 127 ÷ 63.546

n = 1.99

Moles of sulfur:

n = 41 ÷ 32.065

n = 1.27

The reaction is shown as:

Cu + S → CuS

Here, 9 g of sulfur remains unreacted and hence is an excess reagent, and copper being consumed is a limiting reagent.

Here, 1 mole of copper reacts to form 1 mole of copper sulfide hence, 1.99 moles of Cu produces, 1.99 moles of copper sulfide.

Mass of CuS is calculated as:

Mass = moles × molar mass

Mass = 1.99 mol × 95.611 g/mol

= 190.26 grams

Therefore, 127 gm of copper and 41 gm of sulfur produces 190.26 grams of copper sulfide.

Learn more about limiting reagents, here:

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Answer:

3.1 moles of ammonia

18.67× 10²³ molecules

Mass = 52.7 g

Explanation:

Given data:

Number of atoms of hydrogen = 5.68×10²⁴ atoms

A) Number of molecules of ammonia = ?

Solution:

First of all we will calculate the number of moles of hydrogen.

1 mole = 6.022× 10²³ atoms

5.68×10²⁴ atoms × 1 mol / 6.022× 10²³ atoms

0.94×10¹ mol

9.4 moles of hydrogen

Moles of ammonia:

3 moles of hydrogen are present in one mole of ammonia.

9.4 moles of hydrogen = 1/3×9.4 =

3.1 moles of ammonia

Number of molecules of ammonia:

1 mole contain 6.022× 10²³ molecules.

3.1 mol × 6.022× 10²³ molecules / 1 mol

18.67× 10²³ molecules

c) Mass of sample = ?

Mass = number of moles × molar mass

Mass = 3.1 moles × 17 g/mol

Mass = 52.7 g

Answer:

If the pH of a solution is less than 7, the solution is called acidic; if the pH is about 7, the solution is neutral; if the pH is greater than 7, the solution is is called basic. In an acidic solution, then, the concentration of hydrogen ions is greater than the concentration of hydroxide ions.

Explanation:

Not sure about the context of the question, but you can check with a ph scale tester.