A submarine is exploring the ocean floor and begins to ascend to the surface. The depth of the submarine in the water can be modeled by the function `d=500t-4,500` where t is the time (in minutes) since the submarine began to ascend

The table should be completed with the correct key features as follows;

Axis of symmetry (1st graph): x = 1.

Vertex (1st graph): (1, -9).

Minimum (1st graph): -9.

y-intercept (1st graph): (0, -8).

Axis of symmetry (2nd graph): x = 2.

Vertex (2nd graph): (2, 16).

Maximum (2nd graph): 16.

y-intercept (2nd graph): (0, 12).

In Mathematics and Geometry, the graph of a quadratic function would always form a parabolic curve because it is a u-shaped. Based on the first graph of a quadratic function, we can logically deduce that the graph is an upward parabola because the coefficient of x² is positive and the value of "a" is greater than zero (0).

Based on the second graph of a quadratic function, we can logically deduce that the graph is a downward parabola because the coefficient of x² is negative and the value of "a" is less than zero (0).

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Step-by-step explanation:

120 = 1000 e^(-.05t)

120/1000 = e^(-.05t)   take natural LN of both sides

-2.12 = - .05t

t = 42.4 days

The angles are 11°, 42° and 35°.

Given are circles, we need to find the missing angles,

1) ∠1 = 1/2 [119° - (360° - (119°+174°)]

= 1/2 [119° - 97°]

∠1 = 11°

2) ∠1 = 1/2[360°-138°-138°]

∠1 = 1/2 x 84

∠1 = 42°

3) ∠1 = 1/2[111°-360°-(111°+104°+104°)]

∠1 = 1/2 x 70

∠1 = 35°

Hence the angles are 11°, 42° and 35°.

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This is the equation in terms of w that models the situation:[tex]w^2 - 10w + 18.75 = 0[/tex].

Rectangle with width w and length l, enclosed by a 20-meter fence: The perimeter of the rectangle, which is equal to the length of the fence, is given by:

2w + 2l = 20

We can simplify this equation by dividing both sides by 2:

w + l = 10

We also know that the area of the rectangle is 18.75 square meters:

w * l = 18.75

We want to write an equation in terms of w, so we can solve for l in terms of w by dividing both sides by w:

l = 18.75 / w

This expression for l into the equation for the perimeter, we get:

w + (18.75 / w) = 10

Multiplying both sides by w, we get:

[tex]w^2 + 18.75 = 10w[/tex]

Rearranging this equation, we get:

[tex]w^2 - 10w + 18.75 = 0[/tex]

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The radius of convergence comes out as 1/4. To get the radius of convergence, we can use the ratio test.

Step:1. Let's call the nth term in the series a_n, where a_n = 2^(2n)/n^2.
Step:2. Using the ratio test, we take the limit as n approaches infinity of |a_(n+1)/a_n|:
|a_(n+1)/a_n| = (2^(2(n+1))/(n+1)^2) * (n^2/2^(2n))
Step:3. Simplifying this expression, we can cancel out the 2^n terms and get: |a_(n+1)/a_n| = 4((n^2)/(n+1)^2)
Step:4. Taking the limit as n approaches infinity, we get:
lim n→∞ |a_(n+1)/a_n| = 4
Since this limit is less than 1, the series converges.
Step:5. Now we just need to find the radius of convergence, which is given by:
R = 1/lim sup n→∞ |a_n|^(1/n)
Step:6. Taking the limit superior of |a_n|^(1/n), we get:
lim sup n→∞ |a_n|^(1/n) = lim sup n→∞ (2^(2n)/n^(2n/n))^(1/n)
= lim sup n→∞ 2^2 = 4
So the radius of convergence is:
R = 1/lim sup n→∞ |a_n|^(1/n) = 1/4
Therefore, the radius of convergence is 1/4.

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The  probability that the person chosen belonged to Group Y is 69/164.

As, Out of 200 persons in the sample, those having at least one dream are 200− those who had no dream are

= 200−36

=164

Now, out of 164 people belonged to group Y

= 100−21

=79

So, the probability that the person chosen belonged to Group Y become

= 69/164

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Answer:

Step-by-step explanation:

The hours and minutes elapsed from 8:00 a.m. to 2:30 p.m is 6 hours and 30 minutes.

The hours and minutes elapsed from 7:40 p.m. to 1:10 a.m. is 5 hours and 30 minutes.

The hours and minutes elapsed from 12:00 noon to 4:59 p.m is 4 hours and 59 minutes.

The hours and minutes that elapsed from 1:23 a.m. to 7:35 a.m is 6 hours and 12 minutes.

The hours and minutes that belapsed from 11:28 p.m. to 5:30 a.m is 6 hours and 2 minutes.

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1.

a.

It will take 8 minutes to fill the bathtub.

b.

The relationship described is linear.

The equation is 20 = 2.5t + 0.

2.

a.

It will take approximately 4.807 hours to have at least 1,000,000 bacteria in the new colony.

b.

The relationship described is exponential,

The equation is Number of bacteria = initial number of bacteria x (reproduction factor)^(time/hour)

We have,

1.

a.

To fill the bathtub, we need 20 gallons of water.

The rate at which the water is being filled is 2.5 gallons per minute.

Using the formula:

time = amount/rate

we get:

time = 20/2.5 = 8 minutes

b.

The relationship described is linear.

The equation relating the variables can be written as:

amount of water = rate x time + initial amount

where the rate is 2.5 gallons per minute, the initial amount is 0 gallons, and the amount of water is 20 gallons.

So, the equation is:

20 = 2.5t + 0

where t is the time in minutes.

2.

a.

The relationship described is exponential.

The equation relating the variables can be written as:

number of bacteria = initial number of bacteria x (reproduction factor)^(time/hour)

where the initial number of bacteria is 1, the reproduction factor is 4, and we need to find the time it takes to reach 1,000,000 bacteria.

So, we have:

1,000,000 = 1 x 4^(time/hour)

Taking the logarithm of both sides, we get:

log(1,000,000) = log(4^(time/hour))

6 = (time/hour) x log(4)

time/hour = 6/log(4)

time = (6/log(4)) x hour

time ≈ 4.807 hours

b.

The relationship described is exponential, and the equation relating the variables is:

Number of bacteria = initial number of bacteria x (reproduction factor)^(time/hour)

where the initial number of bacteria is 1, the reproduction factor is 4, and t is the time in hours.

Thus,

1.

a.

It will take 8 minutes to fill the bathtub.

b.

The relationship described is linear.

The equation is 20 = 2.5t + 0.

2.

a.

It will take approximately 4.807 hours to have at least 1,000,000 bacteria in the new colony.

b.

The relationship described is exponential,

The equation is Number of bacteria = initial number of bacteria x (reproduction factor)^(time/hour)

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The total cost of the online purchase of $200.00 in Dallas, including the 9.75% sales tax is approximately $219.50.

To calculate the total cost, we first need to find the amount of sales tax. We do this by multiplying the cost of the item by the sales tax rate:

$200.00 x 0.0975 = $19.50

Then, we add the sales tax amount to the cost of the item to get the total cost:

$200.00 + $19.50 = $219.50

Therefore, the total cost of the online purchase of $200.00 in Dallas, including the 9.75% sales tax, is $219.50.

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Complete Question:

If the City of Dallas has a 9.75% sales tax on all online purchases, what is the total cost when you buy an item online that costs $200.00?

The equation represented on the graph obtained from equation of a sinusoidal function is the option; y = coa(x - π/4) - 2

A sinusoidal function is a periodic function that repeats at regular interval and which is based on the cosine or sine functions.

The coordinate of the points on the graph indicates that we get;

The period, T = π/4 - (-7·π/4) = 8·π/4 = 2·π

Therefore, B = 2·π/(2·π) = 1

B = 1

The amplitude, A = (-1 - (-3))/2 = 2/2 = 1

The vertical shift, D = (-1 + (-3))/2 = -4/2 = -2

The vertical shift, D = -2

The horizontal shift is the amount the midline pint is shifted relative to the y-axis

The points on the graph indicates that the peak point  close to the y-axis is shifted π/4 units to the right of y-axis, therefore, the horizontal shift, C = π/4

cos(0) = 1 which is the peak point value of the trigonometric ratio, in the function which indicates that the trigonometric function of the equation for the graph is of the form, y = A·cos(B·(x - C) + D

Plugging in the above values into the sinusoidal function equation of the form; y = A·cos(B·(x - C) + D

We get;

A = 1, B = 1, C = π/4, and D = -2

The function representing the graph is therefore;

y = cos(x - π/4) - 2

The correct option is therefore;

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To find a power series representation for f(x) = ln(2-x), we can use the formula for the power series expansion of ln(1+x):
ln(1+x) = Σ (-1)^(n+1) * (x^n / n)

We can use this formula by setting x = -x/2 and multiplying by -1 to get:
ln(2-x) = ln(1 + (-x/2 - 1)) = Σ (-1)^(n+1) * ((-1)^n * (x^n+1 / (n+1) * 2^(n+1)))
Therefore, the power series representation for f(x) is:
f(x) = Σ (-1)^(n+1) * ((-1)^n * (x^n+1 / (n+1) * 2^(n+1)))

The radius of convergence of this series can be found using the ratio test:
lim |a_n+1 / a_n| = lim |(-1)^(n+2) * (x^(n+2) / (n+2) * 2^(n+3)) * (n+1) / (-1)^(n+1) * (x^(n+1) / (n+1) * 2^(n+2))|
= lim |x / 2 * (n+1) / (n+2)| = |x/2|

Therefore, the radius of convergence is R = 2. The power series representation centered at x = 0 is:
f(x) = Σ (-1)^(n+1) * ((-1)^n * (x^n+1 / (n+1) * 2^(n+1)))
To find a power series representation for the function f(x) = ln(2 - x), we can first rewrite the function as f(x) = ln(1 + (1 - x)). Now, we'll use the Taylor series formula for ln(1 + u) centered at x = 0:

ln(1 + u) = u - (1/2)u^2 + (1/3)u^3 - (1/4)u^4 + ... + (-1)^n(1/n)u^n + ...
In our case, u = (1 - x), so we can substitute it into the formula:
f(x) = (1 - x) - (1/2)(1 - x)^2 + (1/3)(1 - x)^3 - (1/4)(1 - x)^4 + ... + (-1)^n(1/n)(1 - x)^n + ...

This is the power series representation of the function f(x) = ln(2 - x) centered at x = 0.
Now, let's find the radius of convergence (R) using the ratio test:
lim (n -> ∞) |(-1)^{n+1}(1/n+1)(1 - x)^{n+1}| / |(-1)^n(1/n)(1 - x)^n|
Simplify the expression:
lim (n -> ∞) |(n/n+1)(1 - x)|
The limit depends on the value of (1 - x). To ensure convergence, the limit should be less than 1:
|(1 - x)| < 1

This inequality holds for -1 < (1 - x) < 1, which implies that the interval of convergence is 0 < x < 2. Therefore, the radius of convergence, R, is 1.

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For problem 1, the solution is an = n.

For problem 2, the solution is an = 3n - 1.

For problem 3 (the hard problem), we can solve for the values of a, b, and c in the quadratic equation: [tex]an^2 + bn + c = 0[/tex], where a = 5, b = 6n - 1, and c = -2.

Using the quadratic formula, we get:

[tex]n= \frac{-b±\sqrt{b^{2}-4ac }  }{2a}[/tex]

Substituting the values of a, b, and c, we get:

[tex]n= \frac{-(6n-1)±\sqrt{(6n-1)^{2}-4(5)(-2) }  }{2(5)}[/tex]

Simplifying, we get:

[tex]n = \frac{(-6n+1 ± \sqrt{36n^{2}-48n+49 } ) }{10}[/tex]

Therefore, the solution for problem 3 is:

[tex]an= 5n^{2} + \frac{-6n+1 + \sqrt{36n^{2}-48n+49 } }{10}[/tex]

or

[tex]an= 5n^{2} + \frac{-6n+1 - \sqrt{36n^{2}-48n+49 } }{10}[/tex]

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The correct formula to calculate the variance of a probability distribution is σ2 = Σ[(x - μ)2 P(X)].

The formula is σ2 = Σ[(x - μ)2 P(X)],

where σ2 represents the variance, Σ represents the sum of, x represents the possible outcomes, μ represents the mean or expected value of the distribution, and P(X) represents the probability of each outcome.

The number of trials and the probability of success are not directly involved in this formula, but they may be used to calculate the probabilities of each outcome.

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Step-by-step explanation:

Area of base ( 1/2 *  L1  *  L2 )     *  height = volume

            1/2 ( 7)(8)     *   5 =  140 in^3

Answer:

1. a

2. a

3. b

Step-by-step explanation:

Q1. The equation is 3x+6=30. b c d are all good answers so it has to be a. If you want more details on why a is wrong, if you expand it becomes 3x+18=30 which is wrong

Q2. This one is 4(x+6) = 40 because you have x+6 4 times and it tells you the total is 40. So the one that matches is a.

Q3.

You have 6 plus 4 x which makes a total of 40.

So 6 + 4x = 40. The equation that matches is b.

Hmu if you need more explanation

Answer:

0.2

Step-by-step explanation:

1.26 more than the scarf originally so 8.26 for each scarf and 430 total made from the markup and the total profit is 63 dollars.

P(x > 76 and -2.86 < z < 0) = 0.5000 - 0.3665 = 0.1335.

(a) P(x < 21 and z < 3)

Using standardization, we get:

z = (21 - 25)/3 = -4/3

Using the standard normal table, the corresponding probability for z = -4/3 is 0.0912.

Therefore, P(x < 21 and z < 3) = 0.0912.

(b) P(24 < x < 30 and a < z < 8)

Using standardization, we get:

z1 = (24 - 26)/3 = -2/3

z2 = (30 - 26)/3 = 4/3

Using the standard normal table, the corresponding probability for z = -2/3 is 0.2514 and for z = 4/3 is 0.4082.

Therefore, P(24 < x < 30 and a < z < 8) = 0.4082 - 0.2514 = 0.1568.

(c) P(x > 25 and z < 5)

Using standardization, we get:

z = (25 - 30)/5 = -1

Using the standard normal table, the corresponding probability for z = -1 is 0.1587.

Therefore, P(x > 25 and z < 5) = 0.1587.

(d) P(17 < x < 21)

Using standardization, we get:

z1 = (17 - 20)/3 = -1

z2 = (21 - 20)/3 = 1/3

Using the standard normal table, the corresponding probability for z = -1 is 0.1587 and for z = 1/3 is 0.3707.

Therefore, P(17 < x < 21) = 0.3707 - 0.1587 = 0.2120.

(e) P(x > 76 and -2.86 < z < 0)

Using standardization, we get:

z1 = (76 - 80)/12 = -1/3

z2 = 0

Using the standard normal table, the corresponding probability for z = -1/3 is 0.3665 and for z = 0 is 0.5000.

Therefore, P(x > 76 and -2.86 < z < 0) = 0.5000 - 0.3665 = 0.1335.

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The calculated value of the probability P(head) is 0.5 i.e. one half

From the question, we have the following parameters that can be used in our computation:

Sections = 2

Sections = head and tail

Using the above as a guide, we have the following:

Head = 1

When the head section is flipped, we have

P(head) = head/section

The required probability is

P(head) = 1/2

Evaluate

P(head) = 0.5

Hence, the value is 0.5

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To find the volume of the right prism, we used the Pythagorean theorem to determine the height of the triangular base is 1.197 inches. We then used the formula V = Bh to calculate the volume, which was approximately 2.70 cubic inches.

To find the height of the prism, we need to use the information provided about the triangular base. Since the triangular base is equilateral with a dimension of 1.74 inches, the height of the triangle (and therefore, the height of the prism) can be found by using the Pythagorean theorem.

If we draw a line from the center of the base to the midpoint of one of the sides, we create a right triangle with hypotenuse 1.74 in (which is also the height of the triangle) and one leg equal to half the length of one of the sides of the triangle (since the base of the prism is a square with dimension 1.5 in).

Using the Pythagorean theorem, we can solve for the height of the triangle (and prism)

(1.74/2)² + (1.5/2)² = h²

0.8725 + 0.5625 = h²

h² = 1.435

h ≈ 1.197 inches

Now, we can use the formula V = Bh to find the volume of the prism

V = (1.5 x 1.5) x 1.197 ≈ 2.70 cubic inches

Therefore, the volume of the right prism is approximately 2.70 cubic inches.

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Answer:

First, we need to convert the mixed number −3 1/3 to a fraction. −3 1/3 = −(3 + 1/3) = −(10/3).

Now, we can divide the fraction by the decimal. −(10/3) ÷ (-2.4) = −(10/3) ÷ (-24/10) = −(10/3) x (10/-24) = 10/-7.2 = -1.388888889.

Therefore, the value of the expression is −1.388888889.

Step-by-step explanation:

1. Convert the mixed number to a fraction.

```

-3 1/3 = -(3 + 1/3) = -(10/3)

```

2. Multiply the numerator and denominator of the fraction by -1.

```

-(10/3) = (-1)(10/3) = -10/3

```

3. Divide the numerator and denominator of the fraction by -24.

```

-10/3 = (-10/3) ÷ (-24/10) = 10/-7.2 = -1.388888889

```

Therefore, the value of the expression is −1.388888889.

Here is a visual representation of the steps:

```

-3 1/3 ÷ (-2.4)

= -(10/3) ÷ (-24/10)

= -(10/3) x (10/-24)

= 10/-7.2

= -1.388888889

```

Answer:no it doesn’t it makes a trapezoid which doesn’t have 90 degree angles or right angles

Step-by-step explanation:

Answer:

246 boys like to play outdoors

Step-by-step explanation:

82% = 0.82

0.82 x 300 = 246

Answer:

246 boys like to play outdoors

Step-by-step explanation:

82% = 0.82

0.82 x 300 = 246

We have shown that the given set of functions {-3x + 4, 1 - 8x^2 + 8x} is orthogonal with respect to the weight function w(x) = 1 on the interval [-1, 1].

To show that the given set of functions is orthogonal with respect to the given weight on the prescribed interval, we need to show that the integral of the product of any two functions in the set, multiplied by the weight function, over the interval is equal to zero, except when the two functions are the same.

Let's consider two functions from the set: sin(mx) and cos(nx), where m and n are integers.

∫₀²π sin(mx) cos(nx) dx = 0

We can use the trigonometric identity sin(a + b) = sin(a)cos(b) + cos(a)sin(b) to rewrite the integral as:

∫₀²π (1/2)[sin((m+n)x) + sin((m-n)x)] dx

Since m and n are integers, the two sine terms inside the integral have different frequencies and are orthogonal on the interval [0, 2π]. Therefore, their integral over this interval is zero. Thus, we have:

∫₀²π sin(mx) cos(nx) dx = 0, for any integers m and n

Similarly, we can show that the integral of the product of any two other functions in the set, multiplied by the weight function, over the interval is also equal to zero, except when the two functions are the same. Therefore, we have shown that the given set of functions {1, sin(x), cos(x), sin(2x), cos(2x), sin(3x), cos(3x), ...} is orthogonal with respect to the weight function w(x) = 1 on the interval [0, 2π].

To show that the given set of functions is orthogonal with respect to the given weight on the prescribed interval, we need to show that the integral of the product of any two functions in the set, multiplied by the weight function, over the interval is equal to zero, except when the two functions are the same.

Let's consider two functions from the set: -3x + 4 and 1 - 8x^2 + 8x.

∫₋₁¹ (-3x + 4)(1 - 8x^2 + 8x) dx = 0

Expanding the product and integrating, we get:

∫₋₁¹ (-3x + 4)(1 - 8x^2 + 8x) dx = ∫₋₁¹ (-3x + 4) dx - 8∫₋₁¹ x^3 dx + 8∫₋₁¹ x^2 dx

Evaluating the integrals, we get:

∫₋₁¹ (-3x + 4)(1 - 8x^2 + 8x) dx = 0

Therefore, we have shown that the given set of functions {-3x + 4, 1 - 8x^2 + 8x} is orthogonal with respect to the weight function w(x) = 1 on the interval [-1, 1].

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The circumference of 1/8th of a circle with a radius of 30 centimeters is 11.78 centimeters.

The formula for the circumference of a circle is C = 2πr, where C is the circumference, π is a mathematical constant approximately equal to 3.14, and r is the radius of the circle.

To find the circumference of 1/8th of a circle, we need to divide the circumference of the full circle by 8. So, the formula becomes:

C = (1/8) * 2πr

Substituting the given value of the radius, we get:

C = (1/8) * 2π(30)

Simplifying, we get:

C = (1/4) * π(30)

C = (1/4) * 30π

C = 7.5π

Approximating π as 3.14, we get:

C = 7.5 * 3.14

C = 23.55/2

C = 11.78

Therefore, the circumference of 1/8th of a circle with a radius of 30 centimeters is 11.78 centimeters.

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Complete Question:

Circumference of 1/8th of a circle. There is 1/8 of a circle. The radius of the circle is 30 centimeters. The radius of the circle is 30 centimeters. Find the distance of the figure. Give steps.

(a) The given statement, "If A is linearly dependent, then Sp{u, v} = Sp{u, w}" is false because there exist scalars α, β, and γ, not all zero, such that αu + βv + γw = 0.

(b) The given statement, "The set A is linearly independent if and only if {u+v,v-w, w+ 2u} is linearly independent" is true because A is linearly independent if and only if the determinant of the matrix formed by u, v, and w is nonzero. The determinant of the matrix formed by {u+v, v-w, w+2u} can be obtained by performing column operations on the original matrix. Since these operations do not change the determinant, the set {u+v, v-w, w+2u} is linearly independent if and only if A is linearly independent.

(c)The given statement, "Assume that A is linearly dependent. We define u₁ = 2u, v₁ = -3u + 4v, and W₁ = u + 2v - tw for some t E R. Then, there exists t E R such that {u₁, v₁, w₁} is linearly independent" is true because  A is linearly dependent, there exist scalars α, β, and γ, not all zero, such that αu + βv + γw = 0.

Let us discuss this in detail.

(a) False. If A is linearly dependent, then there exist scalars α, β, and γ, not all zero, such that αu + βv + γw = 0. Without loss of generality, assume α ≠ 0. Then we can solve for u: u = (-β/α)v + (-γ/α)w. Therefore, u is a linear combination of v and w, which means Sp{u, v} = Sp{u, w}.

(b) True. We can write each vector in {u+v,v-w, w+2u} as a linear combination of u, v, and w:
u + v = 1u + 1v + 0w
v - w = 0u + 1v - 1w
w + 2u = 2u + 0v + 1w
We can set up the equation α(u+v) + β(v-w) + γ(w+2u) = 0 and solve for α, β, and γ:
α + β + 2γ = 0 (from the coefficient of u)
α + β = 0 (from the coefficient of v)
-β + γ = 0 (from the coefficient of w)
Solving this system of equations, we get α = β = γ = 0, which means {u+v,v-w, w+2u} is linearly independent.

(c) True. Since A is linearly dependent, there exist scalars α, β, and γ, not all zero, such that αu + βv + γw = 0. Without loss of generality, assume α ≠ 0. Then we can solve for u: u = (-β/α)v + (-γ/α)w. Therefore, u is a linear combination of v and w, which means we can write u as a linear combination of u₁, v₁, and w₁:
u = (2/5)u₁ + (-3/5)v₁ + (1/5)w₁
Similarly, we can write v and w as linear combinations of u₁, v₁, and w₁:
v = (-2/5)u₁ + (4/5)v₁ + (1/5)w₁
w = u₁ + 2v₁ - t₁w₁
where t₁ = (α + 2β - γ)/(-t). We can set up the equation αu₁ + βv₁ + γw₁ = 0 and solve for α, β, and γ:
2α - 3β + γ = 0 (from the coefficient of u₁)
-3β + 4γ = 0 (from the coefficient of v₁)
-α + 2β - tγ = 0 (from the coefficient of w₁)
Solving this system of equations, we get α = β = γ = 0 if and only if t = -8/5. Therefore, if we choose any t ≠ -8/5, then {u₁, v₁, w₁} is linearly independent.

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The differential   [tex]dy=2[/tex] when [tex]x = 4[/tex]  and [tex]dx = 0. 2.[/tex]

To find the change in [tex]y,Δy[/tex] , when x changes from, we can use the [tex]4 to 4 +Δx = 4 + 0.2 = 4.2[/tex] formula:

[tex]Δy = y(x + Δx) - y(x)[/tex]

where[tex]y(x) = 5x^2.[/tex]

So, plugging in[tex]x = 4[/tex] and[tex]x + Δx = 4.2[/tex] , we get:

[tex]Δy = y(4.2) - y(4)[/tex]

[tex]= 5(4.2)^2 - 5(4)^2[/tex]

[tex]= 44.2[/tex]

Therefore, the change in y is [tex]44.2[/tex] when x changes from [tex]4 to 4.2.[/tex]

To find the differential dy when [tex]x = 4[/tex] and [tex]dx = 0.2,[/tex]  we can use the formula:

[tex]dy = f'(x) × dx[/tex]

where the derivative of y with respect to x, which is:

[tex]f'(x) = 10x[/tex]

Plugging in [tex]x = 4[/tex]   we get:

[tex]= 2[/tex]

Therefore, the differential [tex]dy = 2[/tex] when [tex]x = 4[/tex] and [tex]dx = 0.2.[/tex]

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Answer:

The range of a set of data is the difference between the highest and lowest values. In this case, the highest value is 98 and the lowest value is 65, so the range is 98-65 = 33. This means that the scores on the test ranged from 65 to 98, a difference of 33 points.

The range is a measure of the spread of the data. In this case, the range is relatively large, which means that the scores were spread out over a wide range of values. This suggests that the test was challenging and that there was a wide range of student abilities.

Answer:

-13.57142857142857

Step-by-step explanation: