A substance has a freezing point of -36 degree C and a boiling point of 356 degree C. At what temperature would this substance be in its liquid state?

Answer:

36.36 m/s

Explanation:

From the question,

Applying the law of conservation of momentum.

Total momentum before collision = Total momentum after collision .

mu+m'u' = V(m+m')................ Equation 1

Where m = mass of the rocket, m' = mass of the wood, u = initial velocity of the rock, u' = initial velocity of the wood, V = Final velocity after collision

But, the wood was initially at rest

Therefore, u' = 0 m/s

mu = V(m+m')

make V the subject of the equation

V = mu/(m+m')................. Equation 2

Given: m = 0.5 kg, u = 400 m/s, m' = 50 kg

Substitute these values into equation 2

V = (0.5×400)/(0.5+50)

V = 200/5.5

V = 36.36 m/s

Answer:

When object is placed between convex lens and focal point, image formed is virtual and magnified which is shown in the diagram. Was this answer helpful?

Answer:

The statement which explains how the total time spent in the air is affected as the projectile's angle of launch increases from 25 degrees to 50 degrees is;

C. Increasing the angle from 25° to 50° will increase the total time spent in the air

Explanation:

The equation that can be used to find the total time, T, spent in the air of a projectile is given as follows;

[tex]T = \dfrac{2 \cdot u \cdot sin(\theta) }{g}[/tex]

Where;

T = The time of flight of the projectile = The time spent in the air

u = The initial velocity of the projectile

θ = The angle of launch of the projectile

g = The acceleration due to gravity ≈ 9.81 m/s²

Given that sin(50°) > sin(25°), when the angle of launch, θ, is increased from 25 degrees to 50 degrees, we have;

Let T₁ represent the time spent in the air when the angle of launch is 25°, and let T₂ represent the time spent in the air when the angle of launch is 50°, we have;

[tex]T_1 = \dfrac{2 \cdot u \cdot sin(25^{\circ}) }{g}[/tex]

[tex]T_2 = \dfrac{2 \cdot u \cdot sin(50^{\circ}) }{g}[/tex]

sin(50°) > sin(25°), therefore, we have;

[tex]\dfrac{2 \cdot u \cdot sin(50^{\circ}) }{g} > \dfrac{2 \cdot u \cdot sin(25^{\circ}) }{g}[/tex]

Therefore;

T₂ > T₁

Therefore, increasing the angle at which the projectile is launched from 25° to 50° will increase the total time spent in the air.

Answer:

1280Nm

Explanation:

torque= I×alpha(angular acceleration)

so Angular acceleration is found by the following process.

Answer:

[tex]v = 14.78m/s[/tex]

Explanation:

Given

[tex]KE = 150J[/tex]

[tex]p = 20.3kgm/s[/tex]

Required

Determine the object's speed

Kinetic Energy is calculated as:

[tex]KE = \frac{1}{2}mv^2[/tex]

Make m the subject

[tex]m = \frac{2KE}{v^2}[/tex]

Momentum is calculated as:

[tex]p = mv[/tex]

Make m the subject

[tex]m = \frac{p}{v}[/tex]

So, we have:

[tex]m = \frac{p}{v}[/tex] and [tex]m = \frac{2KE}{v^2}[/tex]

Equate both expressions: [tex]m = m[/tex]

[tex]\frac{2KE}{v^2} = \frac{p}{v}[/tex]

Multiply both sides by v

[tex]v * \frac{2KE}{v^2} = \frac{p}{v}*v[/tex]

[tex]\frac{2KE}{v} = p[/tex]

Make v the subject

[tex]v = \frac{2KE}{p}[/tex]

Substitute [tex]KE = 150J[/tex] and [tex]p = 20.3kgm/s[/tex]

[tex]v = \frac{2 * 150}{20.3}[/tex]

[tex]v = \frac{300}{20.3}[/tex]

[tex]v = 14.78m/s[/tex]

Answer: 1.15 s

Explanation:

Given

Height of rock h=6.5 m

The horizontal speed of tiger u=3.5 m/s

In the vertical direction, there is no initial speed

Using the equation of motion

[tex]\Rightarrow h=ut+\frac{1}{2}at^2\\\\\Rightarrow 6.5=0+\frac{1}{2}\times 9.8\times t^2\\\\\Rightarrow t=\sqrt{\dfrac{13}{9.8}}=1.15\ s[/tex]

Time taken is 1.15 s

Answer:

heyy tell me ur yo u tube ch annel name I'll subscribe it and how many sub scriber u have friend

Explanation:

and are u from Ireland?

Answer:

(a) The time the ball stays in the air is approximately 4.66 seconds

(b) The distance from the cannon at which the ball will hit the ground is approximately 83.18 meters

(c) The maximum altitude of the ball is approximately 26.62 m

Explanation:

The given parameters of the question are;

The initial velocity at which a baseball cannon fires balls, u = 29 m/s

The angle at which the cannon is tilted, θ = 52°

(a) The time duration the ball stays in the air is given by the time of flight of the projected ball as follows;

[tex]2 \cdot t = \dfrac{2 \cdot u \cdot sin (\theta)}{g}[/tex]

Where;

t = The time it takes the baseball to reach maximum height

2·t = The total time of flight = The time the ball stays in the air

θ = The angle at which the ball is tilted = 52°

g = The acceleration due to gravity ≈ 9.81 m/s²

u = The initial velocity = 29 m/s

Therefore, we have;

[tex]2 \cdot t = \dfrac{2 \times 29 \ m/s\times sin (52^{\circ})}{9.81 \ m/s^2} \approx 4.66 \ s[/tex]

The time the ball stays in the air, 2·t ≈ 4.66 seconds

(b) The distance from the cannon at which the ball will hit the ground is given by the horizontal range, 'R', of the projectile as follows;

[tex]Horizontal \ range, R = \dfrac{u^2 \cdot sin(2 \cdot \theta) }{g}[/tex]

∴ The distance from the cannon at which the ball will hit the ground = R

[tex]Horizontal \ range, R = \dfrac{(29 \ (m/s))^2 \cdot sin(2 \times 52^{\circ}) }{9.81 \ m/s^2} \approx 83.18 \, m[/tex]

The distance from the cannon at which the ball will hit the ground = R ≈ 83.18 meters

(c) The maximum altitude of the ball is equal to the maximum height reached by the ball, H, which is given as follows;

[tex]H = \dfrac{u^2 \cdot sin^2 (\theta)}{2 \cdot g}[/tex]

Therefore, we have;

[tex]H = \dfrac{(29 \ m/s)^2 \times sin^2 (52^{\circ})}{2 \times 9.81 \ m/s^2} \approx 26.62 \ m[/tex]

The maximum altitude of the ball ≈ 26.62 m

Explanation:

C. neutron.

it does not contain ionizing characteristics.

hope it helps. :)

Answer:

The reason why one cannot hear in space but light can be seen is because light and sound are different kinds of wave

Light is an electromagnetic wave that propagates by a changing magnetic field hat creates a changing electric field. Light is created by a vibrating electric charge, and is transmitted through a medium by the absorption and reemission of the light by the medium particles

Sound is a longitudinal mechanical wave that is propagated by the vibration of the particles of the medium.

Sound requires a medium to propagate and it cannot be propagated or heard through space which is a vacuum.

Sound is created by a source that is vibrating and the vibration is transmitted to particles in the medium including solids, liquids, gases and plasma that the vibrating energy is in direct contact with and the transfer of the sound energy continues between layers of adjacent particles for the medium for the sound to be propagated from place to place

Explanation:

Answer:

m1 v1 + m2 v2 = m1 V1 + m2 V2       conservation of momentum

m1 = 3    m2 = 6

v2 = -4.6

V1 = -4.2

V2 = -1.5

v1 = (m1 V1 + m2 V2 - m2 v2) / m1

v1 = (3 * -4.2 + 6 * -1.5 - 6 * -4.6) / 3

v1 = (-12.6 - 9 + 27.6) / 3 = 2  initial velocity of 3 kg ball

Check:

3 * 2 + 6 * -4.6 = -21.6

3 * -4.2 + 6 -1.5 = -21.6

Answer: B  6.2 Hz

Explanation:  Equation for waves v = λf.

Frequency = speed / wavelength    f = v/λ

   f = 74 m/s / 12 m = 6.166... Hz

Answer:

Rounding is necessary: the answer is 6.2 Hz

Explanation:

Answer:

Option B

Explanation:

As we know phase difference is equal to

[tex]\psi = \frac{2\pi }{\lambda} * \Delta[/tex] ----Eq (1)

where

[tex]\Delta[/tex] is the physical difference between two points = 0.025 m

[tex]\lambda[/tex] is equal to [tex]\frac{v}{f}[/tex]

[tex]\lambda = \frac{20}{100} = 0.2[/tex]

Substituting the given values in above equation, we get -

[tex]\psi[/tex] =

[tex]\frac{2\pi }{0.2} *0.025\\\frac{\pi }{4}[/tex]

Hence, option B is correct

Answer:

a tendency to do nothing or to remain unchanged.

Explanation:

Answer:

Inertia: The resistance an object has to a change in its state of motion.

Explanation:

Hope it helps....

Have a great day!!

Answer:

A. Acidic

Explanation:

I hope this helped!

Answer:

the first statement...

Answer:

The first answer is correct.

Plz mark brainliest.

Hope I helped.

Explanation:

Hey there!

Based on the info this planet is likely to be located near the sun. If you would like to be exact it would be between Mercury and Venus. This is because it’s orbital period is half a year, Venus is about 3/4 of a year, and Mercury is about 1/3 of a year. Hopefully this helps! Good luck!

Answer:

The ampere, symbol A, is the SI unit of electric current. It is defined by taking the fixed numerical value of the elementary charge e to be 1.602 176 634 x 10-19 when expressed in the unit C, which is equal to A s, where the second is defined in terms of ΔνCs.

the device used to measure current in a circuit is ammeter

Answer:

Its indirectly Proportional

Explanation:

Answer:

r = 2.55 m

Explanation:

Given that,

First charge, q₁ = 32.2 μC

Second charge, q₂ = + 12.3 μC

The force between charges, F = 0.544 N

We need to find the distance between charges. The force between two charges is given by the formula as follows :

[tex]F=k\dfrac{q_1q_2}{r^2}\\\\r=\sqrt{\dfrac{kq_1q_2}{F}} \\\\r=\sqrt{\dfrac{9\times 10^9\times 32.2\times 10^{-6}\times 12.3\times 10^{-6}}{0.544}} \\\\r=2.55\ m[/tex]

So, the charges are 2.55 m apart.

Answer:

2.55

Explanation:

Right on Acellus

Give the other guy brainliest

You can only give brainliest if 2 people answer

Answer:

B and C is the Answer

Follow me please

Mark brainliest

Answer:

With F = MA Its should take 500 Newtons

Explanation:

F = MA

Answer:

mass= 60kg

velocity= 10m/s

momentum = mass × velocity

p=m×v

p= 60×10

p= 600kgm/s

Answer:

141m

Explanation:

Answer:

Explanation:Hertz is used to measure frequency, but decibel is used to measure intensity level.

Answer:

86.5 m

Explanation:

[tex]s = ut + \frac{1}{2} at {}^{2} \\ s = (0)(4.2) + \frac{1}{2} (9.81)(4.2) {}^{2} \\ s = 86.5m [/tex]

Answer:

86.5 m

Explanation:

Answer:

Yes, you are pulling on Earth. Reasoning. Third Newton's law of motion, action and reaction law, sates that for every action force, there is an equal (in magnitude) and opposite reaction force.

Explanation:

goo gle.