A superconductor performs best at ______.


Extremely high temperatures



Room temperature


Very cold temperatures


Any temperature

A Superconductor Performs Best At ______.Extremely High Temperatures Room Temperature Very Cold Temperatures

Answers

Answer 1

Answer:

c

Explanation:

Superconductors perform best at very cold temperatures because resistivity of this kind of materials decays drastically with temperature. Chromium is most likely to be the best conductor of electricity because it belongs to the Transition Metal group of the periodic table


Related Questions

A 1350 kg automobile has a kinetic energy 3.24 x 106 J. What is the velocity of the car?

Answers

Answer:

219 m/s

Explanation:

Kinetic energy is calculated using the formula:

KE = 1/2mv²

Given:

m = 1350 kg KE = 3.24 · 10⁶ J

We can solve for the unknown variable v.

Substitute these known values into the formula.

3.24 · 10⁶ = 1/2(1350)v² 3.24 · 10⁶ = 675v² (3.24 · 10⁶) / 675 = v² v² = 48,000v = 219.09 m/s

The velocity of the car is around 219 m/s.

The centripetal acceleration of an object moving in a circle of radius 20 cm is 8 m/sec ^2. The possible tangential velocity of the object will be

Answers

Answer:

v = 1.26 m/s

Explanation:

Given that,

The radius of the circle, r = 20 cm = 0.2 m

The centripetal acceleration of the object, a = 8 m/s²

We need to find the tangential velocity of the object. We know that the formula for the centripetal acceleration is given by :

[tex]a=\dfrac{v^2}{r}\\\\v=\sqrt{ar}\\\\v=\sqrt{8\times 0.2}\\\\v=1.26\ m/s[/tex]

So, the tangential velocity of the object will be 1.26 m/s.

In order to increase his gravitational potential energy by an amount equal to his kinetic energy at full speed, how high would such a sprinter need to climb

Answers

Answer:

Hola eres nuevo yo nací en el 2021 del 4 de junio

14. Name the 3 primary causes for the expected mass migration due to Climate
Change

Answers

Answer:

Climate change means a change in the state of the climate system that is sustained over a long period of time. These types of changes can occur due to natural or human causes.

Climate change and its effects on the planet can generate massive migrations, given the affectation of nature in certain parts of the planet.

Thus, an example would be the migration of populations from island countries, such as Fiji, Tonga or Samoa, to continental territories, due to the rise in sea level caused by the melting of the poles due to global warming.

Another example may be the desertification of certain regions, which would encourage migration by the inhabitants of these places to other territories.

Finally, climate change and its negative effects not only generate massive migrations caused by natural effects, but also by the economic effects of said changes, that is, by increases in poverty and inequality in the face of the scarcity of certain natural resources.

An 800-kHz radio signal is detected at a point 4.5 km distant from a transmitter tower. The electric field amplitude of the signal at that point is 0.63 V/m. Assume that the signal power is radiated uniformly in all directions and that radio waves incident upon the ground are completely absorbed. What is the magnetic field amplitude of the signal at that point

Answers

Answer:

[tex]B_2=2.1nT[/tex]

Explanation:

From the question we are told that:

Frequency [tex]F=800kHz[/tex]

Distance [tex]d=4.5km[/tex]

Electric field amplitude [tex]B_2=0.63V/m[/tex]

Generally the equation for momentum is mathematically given by

 [tex]B=\frac{E}{C}[/tex]

Therefore

 [tex]B_2=\frac{0.63}{3*10^8}[/tex]

 [tex]B_2=0.21*10^{-8}[/tex]

 [tex]B_2=2.1nT[/tex]

A 50 Ω resistor in a circuit has a current flowing through it of 2.0 A. What is the power dissipated by the resistor?
A. 50 W
B. 200 W
C. 100 W
D. 25 W

Answers

Explanation:

A nichrome (ρ = 100x10-8 Ωm) wire has a diameter of 0.40 mm. ... A power line with a resistance of 2 ohms has a current of 80 A in it

1/8 Watt 50 kΩ resistor has 70 V applied.

A 50 Ω resistor in a circuit has a current flowing through it of 2.0 A then the power dissipated by the resistor is 200 Watt. Therefore the correct option is B.

What is power?

The rate of doing work is known as power. The Si unit of power is the watt.

Power =work/time

The mathematical expression for the power is as follows

P = VI

where P is the power

V is the voltage

I is  current passing through the circuit

The expression of power can be represented in many different forms by using the ohms law

As we know from Ohm's law that V= IR

Power = VI

by substituting V=IR in place of the voltage in power formula

P = I²R

As given in the problem a 50 Ω resistor in a circuit has a current flowing through it of 2.0 A so by substituting the values of the current and the resistance in the formula of power

P = 2²×50

  = 200 Watt

Therefore the correct answer is B.

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A car pulled by a tow truck has an acceleration of 2.0 m/s^2. What is the mass of the car if the net force on the car is 3,500 N?​

Answers

Answer:

ans: 1750 kg

Explanation:

F = ma

so ,

m = F/a

= 3500 / 2

= 1750 kg

PLEASE HELP ME WITH THIS ONE QUESTION
Given the atomic mass of Boron-9 is 9.0133288 u, what is the nuclear binding energy of Boron-9? (Mproton = 1.0078251, Mneutron = 1.0086649, c^2 = 931.5 eV/u)

Answers

Answer:

The binding energy is -882.5 MeV.

Explanation:

The nuclear binding energy of Boron-9 can be found as follows:

[tex] B = [Zm_{p} + Nm_{n} - M]c^{2} [/tex]      

Where:

Z: is the number of protons = atomic number = 5                                          

N: is the number of neutrons = A - Z = 9 - 5 = 4  

[tex]m_{p}[/tex]: is the mass of the proton = 1.0078251 u

[tex]m_{n}[/tex]: is the mass of the neutron = 1.0086649 u

M: is the atomic mass of B-9 = 9.0133288 u

c² = 931.5 MeV/u                                                                                                                                                                                                  

Hence, the nuclear binding energy is:                                                      

[tex] B = [Zm_{p} + Nm_{n} - M]c^{2} = [4*1.0078251 u + 4*1.0086649 u - 9.0133288 u]*931.5 MeV/u = -882.5 MeV [/tex]  

Therefore, the binding energy is -882.5 MeV.

I hope it helps you!


46) The rapid change of an electric field induces

A) a stronger electric field.
B) a magnetic field.
C) both of these
D) none of the above

Answers

Answer:

The answer is Option no. C because rapid changes can cause both magnetic field and stronger electric field

21. The value of 'g on the surface of earth is 9.8 m/s. If mass of Jupiter is 319 times the mass of the
arth and its radius is 11 times the radius of the earth, find the value of 'g' on the surface of Jupiter.
What will be the weight of a man having mass 50 kg on the surface of Jupiter?
Vhy? Also write solve step by step​

Answers

.

The answer is in the photo. Hope you are satisfied.Have a nice day ☺️

To solve this we must be knowing each and every concept related to  acceleration due to gravity and its calculation. Therefore, the value of 'g' on the surface of Jupiter is 25.8m/s².

What is acceleration due to gravity?

Gravitational acceleration is indeed a vector, which implies it has a direction and a magnitude. The acceleration caused by gravity at the Earth's surface is denoted by the symbol g. It possesses a standard value of 9.80665 m/s².

Mathematically, the formula for acceleration due to gravity can be given as

g = G M /R²

G=6.674 x 10⁻¹¹ m³ kg⁻¹s⁻²

Mass of Jupiter=319×mass of earth

Radius of Jupiter=11×radius of earth

substituting all the given values in the above equation, we get

g = 6.674 x 10⁻¹¹× 319×6×10²⁴ /(11×6378 10³)²

On calculations, we get

g=25.8m/s²

Therefore, the value of 'g' on the surface of Jupiter is 25.8m/s².

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What is the current running through a parallel circuit containing a 10 V battery and three resistors, each 3 ohms

Answers

Answer:

the current through the circuit is 10 A.

Explanation:

Given;

voltage of the battery, V = 10 V

number of the parallel resistors, = 3

resistance of each resistor, r = 3 ohms

The equivalent resistance is calculated as;

[tex]\frac{1}{R_t} = \frac{1}{r_1}+ \frac{1}{r_2} + \frac{1}{r_3} \\\\\frac{1}{R_t} = \frac{1}{3}+ \frac{1}{3} + \frac{1}{3}\\\\\frac{1}{R_t} =\frac{3}{3} \\\\\frac{1}{R_t} = 1\\\\R_t = 1 \ ohms[/tex]

The current through the circuit is calculated as;

V = IRt

I = V/Rt

I = 10/1

I = 10 A

Therefore, the current through the circuit is 10 A.

A particle with charge q1 = +4.0 µC is located at x = 0, and a second particle with charge q2 = −2.1 µC is located at x = 15 cm. Determine the location of a third particle with charge q3 = +4.6 µC such that the net electric field at x = 25 cm is zero.

Answers

Answer:

 x₃ = 0.0725 m

Explanation:

The force between the particles is electrical

          F = [tex]k \frac{q_1q_2}{r_{12}^2}[/tex]

          F = q₀ E_total

don q₀ is a positive test charge at the point of interest, therefore we can calculate the electric field at the point of interest x₀ = 0.25 cm

          F = 0   → E_total = 0

          E_total = E₁ + E₂ + E₃

           E_total = [tex]k \frac{q_1}{r_{1o}^2} + k \frac{q_2}{r_{2o}^2} + k \frac{q_3}{r_{3o}^2}[/tex]

          E_total = k ( [tex]\frac{q_1}{r_{1o}^2} + \frac{q_2}{r_{2o}^2} + \frac{q_3}{r_{3o}^2}[/tex] )

let's look for the distances

           

          r₁₀ = (x₀ - 0)

          r₁₀ = 0.25 m

          r₂₀ = √(x₀ - x₂) ²

          r₂₀ = √ (0.25 - 0.15) ²

          r₂₀ = 0.10 m

          r₃₀ = √ (0.25 - x₃) ²

we substitute

           0 = 9 10⁹ (4 / 0.25² - 2.1 / 0.1² + 4.6 / (0.25-x₃)² )

            4.6 / (0.25-x3)² = -4 / 0.25² + 2.1 / 0.1²

             4.6 / (0.25-x3) ² = -146

             (0.25 - x3) ² = - 4.6 / 146 = - 0.0315068

              0.25 - x3 = 0.1775

              x₃ = 0.25 - 0.1775

              x₃ = 0.0725 m

You lift a 10-N physics book up in the air a distance of 1.0 m, at a constant velocity
of 0.50 m/s. What is the work done by gravity on the book?
1) +10 J
2) -10
3) +5.0
4) -5.0

Answers

The book is lifted upward, but gravity points down, so the work done by gravity must be negative (so you can eliminate options 1 and 3).

The force exerted on the book by gravity has magnitude

F = mg = (10 N) (9.80 m/s^2) = 9.8 N ≈ 10 N

You raise the book 1.0 m in the opposite direction, so the work done is

W = (10 N) (-1.0 m) = -10 J

The work done by gravity on the book is -10 Joules. The correct option is 2.

What is gravity?

The force of attraction felt by a person at the center of a planet or Earth is called as the gravity.

Given are the three positions. The Earth has the acceleration due to gravity, g =  9.81 m/s²,

The book is lifted upward, but gravity points down, so the work done by gravity must be negative (so you can eliminate options 1 and 3).

The force exerted on the book by gravity has magnitude

F = mg = 10 N x( -9.80 m/s² )= -9.8 N

F ≈ -10 N

The book is raised by  1.0 m in the opposite direction, so the work done is

W =- 10 N x 1.0 m = -10 J

Thus, the correct option is 2.

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In an experiment, students measure the position x of a cart as a function of time t for a cart that starts at rest and moves with a constant acceleration. The following data are collected for the cart.

t(s) x(m)
0 0
1 4
2 16
3 36
4 64

The acceleration of the cart is most nearly:_____

Answers

Given :

Initial velocity , u = 0 m/s² .

To Find :

The acceleration of the cart.

Solution :

Since, acceleration is constant.

Using equation of motion :

[tex]x = ut + \dfrac{at^2}{2}\\\\x = \dfrac{at^2}{2}[/tex]

Putting, t = 1 s  and x = 4 m in above equation, we get :

[tex]4 = \dfrac{a(1)^2}{2}\\\\a = 8 \ m/s^2[/tex]

Therefore, the acceleration of the cart is 8 m/s².

Is an object on the surface of Earth sitting still relative to outer space?

Answers

Answer:

The object is not still as it observe from the outer space.

Explanation:

Our earth is not stationary.

It rotates about its own axis with the period of 24 hours and it revolves around the sun with the period of 1 year.

An object is said to be at rest if the position of the object with respect to time changes.

An object is said to be in motion when the position of the object changes with respect to time.

Both the terms rest and motion are relative to each other.  

If an observer observe an object on the earth from the outer space, he observe that the object s not still it is also moving as the earth is moving.

So, the object is not still as it observe from the outer space.

a stone is thrown vertically upward with an initial velocity of 14m/sc negleting in air resistance find (a)Maximum height reached and (b)Time taken before it reached the ground ​

Answers

Answer:

1/2 m v^2 = m g H      conservation of energy

H = (v^2 / (2 * g))^1/2 = (14^2 / 19.6)^1/2 = 10 m

H = 1/2 g t^2       time to fall 10 m

t = (2 * H / g)^1/2 = (20 / 9.8)^1/2 = 1.43 sec

Total time in air = 2 * 1.43 = 2.86

You can also use 2 a S = V0^2 since final velocity = 1.43 * 9.8 m/s = 14 m / s

and 2 a S = 2 * 9.8 * 10 = 196 m^2 / s^2   which is V0 squared

which equation describes the sum of the vectors plotted below

Answers

Answer:

i think it could be d

Explanation:

I'm not sure

The sum of the vectors plotted below describes by 2x i + 4y j. Hence, option (B) is correct.

What is vector?

Physical quantities that exhibit both magnitude and direction are referred to as vector quantities. As an illustration, consider displacement, force, torque, momentum, acceleration, and velocity.

It is more complicated to add vectors than it is to add scalars. It is impossible to simply add two vectors together to get their sum since vectors include both magnitude and direction. The Triangle law is used to calculate the vector addition.

According to the figure:

the sum of the vectors is position vector of second vector, that is,  r = 2x i + 4y j.

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A harmonic force of maximum value 25 N and frequency of 180 cycles>min acts on a machine of 25 kg mass. Design a support system for the machine (i.e., choose c, k) so that only 10% of the force applied to the machine is transmitted to the base supporting the machine.

Answers

Answer:

registrar y de h2rhrjlekeek tert2h2jwkwlwlwlwlwlwñlwk

What do different forms of energy have in common?
A. They can push or pull on objects.
B. They give objects mass.
C. They can cause changes in matter.
d
D. They can cause objects to move.

Helllp meeee

Answers

C.ccccccccccccccccccccccccccccccccccccc

d. What is one watt power? Calculate the power of
a man if he can lift a load of 175 N to a height of
25 m in 10 second (1+2)​

Answers

Answer:

437.5 watts.

Explanation:

One watt power (1-watt) is used to describe the situation of an electrical appliance where 1 joule of energy per seconds of time (1 J/s) is consumed or used.

According to the information in the question, a man can lift a load of 175N (Force) to a height of 25 m (distance) in 10 seconds (time).

Power = Workdone (J) ÷ time (s)

Workdone = Force (N) × distance (m)

Workdone = 175 × 25

Workdone (W) = 4375J

Power = W/t

P = 4375/10

P = 437.5 watts.

prove first equation of motion​

Answers

Answer:

Let us assume a body has initial velocity ' u ' and it is subjected to a uniform acceleration ' a ' so that the final velocity be ' v ' after a time interval ' t '. Acceleration is the rate of change of Velocity.Now , by the definition of acceleration , we have :

[tex] \large{ \tt{❃ \: a = \frac{v - u}{t}}} [/tex]

[tex] \large{ \tt{ \dashrightarrow \: at = v - u}}[/tex]

[tex] \large{ \tt{∴ \: v = u + at - - - \tt{ {1}^{st} EQUATION \: OF \: MOTION}}}[/tex]

And we're done! ☂

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

The work function of titanium metal is 6.93 x 10-19 J. Calculate the kinetic energy of the ejected electrons if light of frequency 2.50 X 1015 s-1 is used to irradiate the metal.

Answers

Answer:

g m t o k liye cbbhhhf to be be free and ear is not a short time to be a short of a week and I am a short kat key and ear to be free and ear is not a short time and ear buds and duster for a short of a week of the action is not by the action is not a short time to make sure to be free and duster and not by the way to

Explanation:

ahhhhhhh to be be free and ear is nothing to be be free and ear is not a short time to be be free and ear is not by the class is not a a short time to be be free and

A banked curve is designed for a roadway. The curve is designed so that a car traveling at 19.2 m/s can negotiate it without relying on the force of static friction. The radius of the curve is 51.2 in and the car has a mass of 2300 kg. a. What angle is the curve banked at (degrees)? b. What is the magnitude of the Normal force (N) between the road and the car when it is traveling at the designed speed? c. If a careless driver tries to negotiate the curve at a speed of 25 m/s ,will the direction of the frictional force be inward or outward?

Answers

I don’t know wait for someone else

37 microgram to Gigagram​

Answers

3.7e-1437 Gigagram

BRAINILIEST PLEASE


John and Caroline go out for a walk one day. This graph represents the distance they traveled over time.
During what part of thelr walk are they not moving?
A) From 0 to 0.75 hours
B)From 1.25 to 2.0 hours
From 0.75 to 1.25 hours
C) from 1.25 to 2.0 hours
D) they are moving the entire time

Answers

Answer:

From 0.75 to 1.25 hours

Explanation:

Given

See attachment for graph

Required

Point where they didn't move

This means that we identify the point where the distance didn't change.

Given that the distance is plotted on the y-axis, we simply check for the end points of any horizontal line on the graph

The horizontal line on the graph represents 30km and the time interval is: 0.75 to 1.25 hours.

Hence, (c)  is correct

motto that will help in reaching a goal in life that related the projectile motion ​

Answers

Explanation:

hmm! very good questions I hope u understand

A family uses an electric frying pan with a power rating of 1.2 X 10^3 W. Although the pan is thermostatically controlled, its element was drawing power for 6.3 X 10^2 min in a period of one month. Calculate the electrical energy in kWh used by the pan during the month

Answers

Answer:

378 KWh

Explanation:

We'll begin by converting 1.2×10³ W to KW. This can be obtained as follow:

10³ W = 1 KW

Therefore,

1.2×10³ W = 1.2×10³ W × 1 KW / 10³ W

1.2×10³ W = 1.2 KW

Next, we shall convert 6.3×10² mins to hours (h). This can be obtained as follow:

60 mins = 1 h

Therefore,

6.3×10² mins = 6.3×10² mins × 1 h / 60 mins

6.3×10² mins = 10.5 h

Finally, we shall determine the electrical energy in KWh used for 1 month (i.e 30 days). This can be obtained as follow:

Power (P) = 1.2 KW

Time (t) for 1 month (30 days) = 10.5 h × 30

= 315 h

Energy (E) =?

E = Pt

E = 1.2 × 315

E = 378 KWh

Thus, the electrical energy used for 1 month (i.e 30 days) is 378 KWh.

Two blocks A and B with mA = 2.9 kg and mB = 0.87 kg are connected by a string of negligible mass. They rest on a frictionless horizontal surface. You pull on block A with a horizontal force of 6 N. Determine the tension in the string connecting the two blocks.

Answers

Answer:

Tension = 1.38 N

Explanation:

Given that:

Mass of block A [tex]m_A[/tex] = 2.9 kg

mass of block B [tex]m_B[/tex] = 0.87 kg

Force F = 6 N

Assume a = acceleration of the blocks.

Then:

[tex]m_A[/tex] (a) + [tex]m_B[/tex] (a) = 6

2.9a + 0.87a = 6

3.77a = 6

a = 6/3.77

a = 1.59 m/s²

Suppose T to be the tension in the string.

If we take a look at the forces acting on the first block, then:

F - T = [tex]m_A[/tex] (a)

T = F - [tex]m_A[/tex] (a)

T = 6 - 2.9(1.59)

T = 6 - 4.62

T = 1.38 N

Ples helppp meeeeee this is timedd

Answers

Answer:

50 km/h

Explanation:

From the graph, we can deduce the following parameters;

Distance = 20, 40, 60, 80, 100 km

Time = 0.5, 1.0, 1.5, 2.0 hours

To find the average velocity of the car over the first 2.00 hours.

First of all, we would determine the total distance and time.

Total distance = 20 + 40 + 60 + 80 + 100 = 300 km

Total time = 0.5 + 1.0 + 1.5 + 2.0 = 5

Average velocity = distance/time

Average velocity = 100/2

Average velocity = 50 km/h

State the relation between acceleration and momentum​

Answers

Answer:

Acceleration is the rate of change in velocity. Momentum is the mass times the velocity. So if you multiply the mass times the acceleration, you get the of change of momentum.

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