a support supplies a force of 5 kn to a wall as shown below. what is the moment (in kn-m) produced by this force about an axis in the direction of i j k (from the origin)?
Answers
The moment (in KN-m) produced by the force about an axis in the direction of i+j+k (from the origin) if a force of 5 KN to a wall is 5 (cos θ + sin θ)
That is called torque when we calculate its moment of force. Torque is а meаsure of the force thаt cаn cаuse аn object to rotаte аbout аn аxis. Just аs force is whаt cаuses аn object to аccelerаte in lineаr kinemаtics, torque is whаt cаuses аn object to аcquire аngulаr аccelerаtion.
We are given:
Force = 5 KN
Horizontal Component i = [tex]F_{x}[/tex] = 5 cos θ
Vertical Component j = [tex]F_{y}[/tex] = 5 sin θ
x component of the moment (in kN-m):
M = [tex]F_{x}[/tex] × d
= 5 cos θ × d (kN - m)
d is the distance of the force form origin.
Force about an axis in the direction of i + j + k:
= [tex]F_{x}[/tex] + [tex]F_{y}[/tex] + [tex]F_{z}[/tex]
= 5 cos θ + 5 sin θ + 0
= 5 (cos θ + sin θ)
Your question is incomplete, but most probably your full question can be seen in the Attachment.
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Related Questions
A pipe discharges storm water into a creek. Water flows horizontally out of the pipe at 1.9 m/s, and the end of the pipe is 3.1 m above the creek.
How far out from the end of the pipe is the point where the stream of water meets the creek?
Answers
The distance from the end of the pipe is the point where the stream of water meets the creek is 1.52 m.
What is the time taken for the water to flow?
The time taken for the water to fall from the given height is calculated as follows;
t = √ ( 2h / g )
where;
g is acceleration due to gravityh is the height of fallt = √ ( 2 x 3.1 / 9.8 )
t = 0.8 s
The horizontal distance travelled by the stream of water is calculated as;
x = vt
x = 1.9 m/s x 0.8 s
x = 1.52 m
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while a car travels around a circular track at a constant speed, its group of answer choices velocity is zero. none of the above acceleration is zero. inertia is zero.
Answers
Answer: None of the options.
What is energy ?
-- energy, in physics, the capacity for doing work. It may exist in capacities, kinetic, thermal, electrical, chemical, nuclear, or other various forms.
-- There are, moreover, heat and work—i.e., energy in the process of transfer from one body to another
When we talk about uniform circular motion (constant speed) we yet have a changing velocity and therefore, acceleration.
How is this possible?
-- Well, velocity is a vector, and as a vector it has magnitude (the speed) and direction.
-- So, while an object performs a uniform circular motion, althought its speed is not changing, its direction does change.
-- And, since acceleration is the variation of velocity in time , certainly there is acceleration here.
On the other hand, Inertia is mathematically expressed as:
This means that for a system with a given axis of rotation and a given total mass , the greater the distance from the axis to the object that performs the circular motion, the greater the inertia.
This also means that inertia depends directly on the mass of the system and the radius of the circular motion, therefore, as long as these elements exist, in a circular motion the inertia will always be different from zero.
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a mass is attached to a vertical spring and set into vibration. the highest point of the motion is point a and the lowest point of the motion is point b. at what position or positions in its motion is the object's potential energy at a maximum? (consider the potential energy of the mass-earth-spring system.)
Answers
Peak A, which is the motion's highest point, and point B, which is its lowest point, are where the object's potential energy is greatest.
Point A, the greatest point of the motion, has the largest potential energy for the item. The mass is now at its maximal potential energy and the spring is fully expanded. The potential energy drops as the mass descends toward point B because the spring contracts and the mass loses potential energy. The potential energy is at its lowest when the mass reaches point B since the spring is entirely compressed and the mass is at its lowest point. The mass subsequently goes back up to point A, and the process is repeated, increasing the potential energy.
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Two tiny conducting spheres are identical any carry charges of `-20.0 mu C` and `+50.0 muC`. They are separated by a distance of 2.50 cm. The spheres are brought into contact and then separated to a distance of 2.50 cm. Determine the magnitude of the force that each sphere now experiences, and state whether the force is attractive or repulsive.
A. 1.30 x 10^(2) N, attractive
B. 3.24 x 10^(3) N, attractive
C. 3.24 x 10^(3) N, repulsive
D. 1.44 x 10^(4) N, repulsive
Answers
The magnitude of the force that each sphere before contact and after contact are 1.438 × 10¹⁶ N and 3.5 × 10¹⁴ N respectively.
"Coulomb's law states that the force of attraction or repulsion between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between them." It runs on the same track as the two charges, which are thought of as point charges.
Q₁ = -20 C
Q₂ = +50 C
Distance d = 2.5 cm equals 0.025 metres
F = (k Q₁ Q₂)/d² = (8.99 × 10⁹ × 20×50) /(0.025)² = 1.438×10¹⁶ N
Given that, the charges have opposing signs, the force is alluring.
The charge on each sphere after contact,
Q = Q₁ + Q₂/2 = -20+ 50/2 = -20 + 25 = 5 C
Magnitude of force = k Q²/d² = (8.99× 10⁹ × 5²)/(0.025)² = 224.75× 10⁹/(0.000625) = 359600× 10⁹ = 3.5 × 10¹⁴ N
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20N , 5m
2. If the crate does not move, does Ignacio perform any work? Does he use any
power? Explain.
th
probl
Study the illustration above, and then answer the following questions on a separate
sheet of paper.
1. Ignacio is trying to move this crate. What are the two equations you can use to
calculate the power Ignacio must use to move the crate?
3. What else do you need to know to find the power Ignacio uses when he moves
the crate?
4. Ignacio moves the crate in 10 s. How much power, in watts, does he use?
5. Carolina moves the crate in 5 s. How much power, in joules per second, does
she use?
6. Felix moves the crate twice as far as Ignacio and Carolina in 5 s. How much
power, in watts, does he use?
Answers
The quantity of internal and mechanical energy that things contain fluctuates as a result of work.
How can you tell if someone is working on something or not?Example of a Work, An item must be subjected to a force and move in the direction of the force in order for work to be done on it.The quantity of internal and mechanical energy that things contain fluctuates as a result of work. Energy is contributed to a system or an item when work is done on it. A system or item transfers part of its energy to something else when it does work. When a ball is thrown, a hand exerts force while an arm swings forward.To learn more about mechanical energy refer to:
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a certain voltage source provides a constant 6v. the circuit connected to the source draws an exponentially decaying current from the source given by ma, for , where 749ma and 67ms. assuming that for , at what point in time has the source provided 46mj of energy? express your answer in units of ms (milli-seconds).
Answers
At a certain time, by performing the given steps of calculation with appropriate values one can find the point of time at 46mj energy.
To find the point in time at which the source has provided 46mJ of energy, we need to integrate the current over time and set it equal to 46mJ.
The current as a function of time is given by:
i(t) = 749mA * e^(-t/67ms)
The energy provided by the source is given by the integral of the current with respect to time.
E = ∫i(t) dt
To solve the integral, we can use the power rule of integration:
∫e^(ax) dx = e^(ax) / a + C
By substituting the values in the above equation we can get the time at which the source provided 46mJ of energy.
E = ∫(749mA * e^(-t/67ms)) dt
E = 749mA * (e^(-t/67ms) / (-1/67ms)) + C
E = 749mA * (-67ms * e^(-t/67ms)) + C
Solving for t we get t = 67ms * ln(46mJ/(749mA * 67ms))
Therefore, at t = 67ms * ln(46mJ/(749mA * 67ms)) the source has provided 46mJ of energy.
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A fox fleeing from a hunter encounters a 0.745 m tall fence and attempts to jump it. The fox jumps with an initial velocity of 7.50 m/s at an angle of 45.0°, beginning the jump 1.99 m from the fence. By how much does the fox clear the fence? Treat the fox as a particle.
Answers
The fox which is fleeing from a hunter encounters a 0.745 m tall fence and this fox can clear the fence with a height of up to 0.895 meters.
What is Velocity?Velocity can be defined as the rate of change in the displacement of an object. It is a vector quantity as it has both the magnitude and direction. The change in velocity of an object is known as acceleration.
Given,
Initial velocity (u) = 7.50 m/s
Launch angle, θ = 45°
Height of fence = 0.745 m
Trajectory of Projectile is given by:
y = x tanθ - gx²/ 2u²cos²θ
For x = 1.99 m
y = 1.99 × tan 45° - 9.8 × (1.99)²/ 2 × (7.5)² × (cos45°)²
y = 1.99 × 1 - 9.8 × 3.96/ 2 × 56.25 × (1)²
y = 1.99 - 38.80/112.5
y = 1.99 - 0.345
y = 1.64m
At x = 1.99 m, the value of y = 1.64 m
Therefore, fox clear fence by a margin = 1.64 - 0.745 = 0.895 meters.
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a gardener mows a lawn with a push mower. the handle of the mower makes an angle of 32 degrees. if a 209 n force is applied along the handle of the 18 kg mower, what is the normal force exerted on the mower?
Answers
The normal force exerted on the mower is 290.8 N. The result is obtained by using the concept of Newton's first law.
What is Newton's first law?Newton's first law states that every object will remain at rest or keep constantly moving in a straight line unless an external force acts upon it.
The equation of Newton's first law can be expressed as
∑F = 0
A gardener mows a lawn with a push mower with
Angle, θ = 32 degreesForce, F = 209 NMass = 18 kgFind the normal force exerted on the mower?
We use g = 9.8 m/s².
See the illustration picture of forces directions in the attachment!
The direction of normal force is up. Using the Newton's first law, we will add parallel forces.
∑F = 0
Fn - F sin θ - W = 0
Fn = F sin θ + W
Fn = 209 sin 32° + 18 × 10
Fn = 209 (0.53) + 180
Fn ≈ 290.8 N
Hence, the mower will exert the normal force of 290.8 N.
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which diagram best represents the position of a ball , at equal time intervals as it falls freely
Answers
The diagram that represents the position of a ball, at equal time intervals, as it falls freely is diagram B.
What is free fall kinematics?The acceleration of an item in free fall is -9.8 m/s/s. (The minus symbol represents a downward acceleration.) For any freely falling item, the acceleration in the kinematic equations is -9.8 m/s/s, whether or not this is explicitly stated.
vf = g x t where g is the acceleration of gravity. The value for g on Earth is 9.8 m/s/s. This formula is used to determine the object's speed after being dropped from rest for any period of time.
Therefore, the correct option is B. diagram B.
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The question is incomplete. Your most probably complete question is given below: the options are attached below.
In the Soapbox Derby in, young participants build non-motorized cars with very low-friction wheels. Cars race by rolling down a hill. Assume that the track begins with a 51-ft-long (1 m= 3.28 ft) section tilted 14 ∘ below horizontal.
What is the maximum possible acceleration of a car moving down this stretch of track?
If a car starts from rest and undergoes this acceleration for the full l, what is its final speed in m/s ?
Answers
(a) The maximum possible acceleration of a car moving down this stretch of track is 2.38 m/s².
(b) The final speed of the car is 8.6 m/s.
What is the coefficient of friction on the incline?The coefficient of friction acting on the inclined surface is calculated by applying the following formula.
μ = tanθ
where;
θ is the angle of inclination of the inclineμ = tanθ
μ = tan (14)
μ = 0.25
The maximum possible acceleration of a car moving down this stretch of track is calculated as follows;
ma = μmg cosθ
a = μg cosθ
a = ( 0.25 x 9.8 m/s² ) x cos (14)
a = 2.38 m/s²
The final speed of the car when accelerating at maximum acceleration is calculated as follows;
s = distance travelled by the car = length of the incline
s = ( 1 m / 3.28 ft ) x ( 51 ft ) = 15.55 m
v² = u² + 2as
where;
u is the initial speed of the car = 0v is the final speedv² = 0 + 2as
v² = 2as
v = √ ( 2as )
v = √ ( 2 x 2.38 x 15.55 )
v = 8.6 m/s
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A substance has a triple point at a temperature of 17 ∘C and a pressure of 3. 2 atmospheres. In what states can the substance exist on the surface of Earth at sea level (open to the atmosphere)?
Answers
Due to changes in temperature and pressure, the substance can exist either as a solid or a gas.
Given The triple point temperature is, (T) = 17 ∘C
The pressure of substance at triple point (P) = 3.2atm
The triple point is the temperature at which a certain substance can exist in all three of its major forms (solid, liquid and gas). Generally speaking, there are three stages of states that can be used to classify the states of matter. At sea level, we will experience conditions with a pressure of 1 atm and a temperature of 25∘C. At the sea level surface of the Earth, the triple point temperature is exceeded and the pressure decreases. The material can therefore exist in both the solid and gas phases. As a result, we can draw the conclusion that the substance can exist in both a solid and a gaseous state due to temperature and pressure variations.
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Two Small Spheres Spaced 20.0 Cm Apart Have Equal Charge. &Nbsp; How Many Excess Electrons Must Be Present On Each Sphere If The Magnitude Of The Force Of Repulsion Between Them Is 4.57 X 10-21 N? &Nbsp; Number Of Electrons = ?This problem has been solved!You'll get a detailed solution from a subject matter expert that helps you learn core concepts.See AnswerTwo small spheres spaced 20.0 cm apart have equal charge.How many excess electrons must be present on each sphere if the magnitude of the force of repulsion between them is 4.57 x 10-21 N?Number of Electrons = ?
Answers
The number of excess electrons in each sphere is equal to 1.24 x 10^-19 C / 1.6 x 10^-19 C/electron = 0.78 x 10^19 electrons.
How to calculate the number of excess electrons?The number of extra electrons in each sphere can be calculated using Coulomb's law. Coulomb's law states that the repulsive force between two charges is proportional to the product of the charges and inversely proportional to the square of the distance between them.
F = k * (q1 * q2) / d^2
where F is the repulsive force, q1 and q2 are the charges on the two spheres, d is the distance between the spheres, and k is the Coulomb constant (8.99 x 10^9 Nm^2/C^2).
Since the repulsive force is 4.57 x 10-21 N and the distance between the spheres is 20 cm = 0.2 m, we can rearrange the equations to find the charge on each sphere.
q1 = sqrt(F * d^2 / k)
q1 = square root (4.57 x 10-21 N * (0.2 m)^2 / (8.99 x 10^9 Nm^2/C^2)) = 1.24 x 10^-19 C
So the number of extra electrons in each sphere is equal to 1.24 x 10^-19 C / 1.6 x 10^-19 C/electron = 0.78 x 10^19 electrons.
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A 7. 00-kg box is attached to a 3. 00-kg box by rope 1. The 7. 00-kg box is pulled by rope 2 with a force of 25. 0 N. Determine the acceleration of the boxes and the tension in rope 1. The coefficient of friction between the ground and the boxes is 0. 120
Answers
Answer:
net force=applied force
Explanation:
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how many decibels are emitted from a jet plane with a sounf intensity of 8.5*10^2 watts per square meter
Answers
The jet plane emits 149 914 decibels at 8.2 .
What is the jet plane?
The Principal Differences. The key difference between a jet and an airplane is that to be a jet, a plane has to have a jet engine. Essentially, every jet is an airplane but not every airplane is a jet. A jet engine could either be a turbojet or turbofan, while a non-jet engine is usually a turboprop.A jet aircraft (or simply jet) is an aircraft (nearly always a fixed-wing aircraft) propelled by jet engines.While the typical VLJ and light jet carry a maximum of six passengers, a mid-size business jet offers comfortable seating for up to 10 passengers.A Jet aircraft flies much faster at higher altitudes, as high as 33,000–49,000 ft, than a propeller-powered aircraft. The Jet engine consists of an engine with a rotary air compressor powered by a turbine, with the leftover power providing thrust via a propelling nozzle.To learn more about jet refers to:
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while playing ulimate frisbee you run north for 10 m, then eas for 30 m, adn finally 34 m in a direction 37 degrees south of east. what is your total displacememnt (magnitude and direction) during this run?
Answers
The total displacement is 48m in a direction 30° south of east.
What is total displacement?Total displacement is the vector sum of all individual displacements that an object has undergone during a certain period of time.
To calculate this, we first need to calculate the displacement when running north for 10m. That would be 10m in a direction of 0° (due north).
Next, when running east for 30m, the displacement would be 30m in a direction of 90° (due east).
Finally, when running in a direction 37° south of east for 34m, the displacement would be 34m in a direction of 37° south of east.
Now to calculate the total displacement, we need to add the vector components of each of these three displacement vectors together.
The x component of the total displacement is 10m + 30m + (34m * cos(37°)) = 48m.
The y component of the total displacement is 0m + 0m + (34m * sin(37°)) = 31m.
Using the Pythagorean theorem, we can calculate the magnitude of the displacement vector to be sqrt(48^2 + 31^2) = 59.48m.
To calculate the direction of the displacement vector, we can use the inverse tangent function, arctan(31/48) = 30.14°.
Therefore, the total displacement is 48m in a direction 30° south of east.
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A 0. 6 kg basketball is thrown straight up at a velocity of 4 m/s. What is the initial kinetic energy of the basketball?
Answers
The initial kinetic energy of the basketball is 8 J.
What do you mean by Kinetic Energy?Kinetic energy is the energy an object possesses due to its motion. Kinetic energy is proportional to the square of an object's velocity and is expressed as KE = 0.5 * m * v^2, where m is the mass of the object and v is its velocity. Kinetic energy is a scalar quantity, meaning it only has magnitude and not direction. When an object slows down or comes to rest, its kinetic energy is converted into other forms of energy, such as heat or potential energy. Kinetic energy is a crucial concept in the fields of mechanics, thermodynamics, and other branches of physics.
The initial kinetic energy of the basketball can be found using the formula:
KE = 1/2 * m * v^2, where m is the mass of the object and v is its velocity.
For the 0.6 kg basketball with a velocity of 4 m/s, the initial kinetic energy is:
KE = 1/2 * 0.6 kg * (4 m/s)^2
KE = 8 J
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A source produced 15 waves in 3 seconds , The distance between a crust is 15cm . Find frequency and wavelength
Answers
Frequency and wavelength is 100m/s.
Exactly how is frequency calculated?Pictures for Calculate the frequency and wavelength. The formula for frequency expressed in terms of time is given as follows: f = 1/T, where T is the duration of a cycle expressed in seconds and f is the frequency expressed in hertz. The frequency formula is stated as f = / where denotes the wave speed and the wavelength of the wave.
Explanation:
In 3 seconds, the source is generating 15 waves.
In a second, there are 15/3 waves, or 5 waves, produced.
Thus, the frequency is 5 Hz.
assuming that the wave length /2 = 10 cm
so that =20 cm
speed = frequency *wavelength v=5*20
v=100m/s.
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How do microorganisms work as decomposers in an ecosystem
Answers
Answer:
they eat what is decomposing speeding up the decomposition
You are riding a bike with a bag in the front basket. A friend
on the sidewalk watches you ride by, heading south.
Which statement best describes how the bag's motion is
relative to the frame of reference - you and your friend?
Answers
Bag's motion is ,a straight line with a constant slope (positive slope) and positive value represents a positive, steady velocity (upwards sloping).
Describe a speed example?In a specific direction, accelerate. A 50 mph Eastbound automobile is an illustration. the relationship between an object's motion's distance and time is demonstrated. An object's speed is depicted by the line.An object's velocity is altered by a net force; the acceleration increases with the magnitude of the net force. For an item to accelerate by the same amount as an object that is less massive, more net forces are needed.A straight line with a constant slope (positive slope) and positive value represents a positive, steady velocity (upwards sloping).To learn more about motion refer to:
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what is the minimum hose diameter of an ideal vacuum cleaner that could lift a 11 kg dog off the floor?
Answers
4 cm hose diameter required of an ideal vacuum cleaner that could lift a 11 kg dog off the floor.
How to measuring a Hoses Diameter?The internal diameter of your hose is the measurement across its width. There are two simple methods for measuring this.
Take a ruler to your hose and measure across the interior if you want it to be the same size as what you now have. Alternately, place a paper tube inside the aperture and measure across it.
You might try see if the spray attachment's existing type of fitting would accept that size. It never hurts to double-check, but most fitting like a 1 quick-connect coupler are universal.
What are Different Diameter Sizes Of Garden Hoses?The 5/8 diameter is the most prevalent size. It is a generally suitable size for your yard. The flow is also stronger. Using attachments like a hose nozzle, you want to manage that flow. In particular, if you have to lay it down while watering, you don't want to flood your yard. Additionally, it's perfect for filling up the kiddie pool or keeping an eye on your car. It is an excellent all-purpose hose.
Additionally, you'll discover that many hoses with diameters of 3/4 and 1/2 inches, which are slightly smaller than the 5/8 size, will also function well and are great for baskets and container plants. It enables a lovely trickle of water without endangering your sensitive plants.
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a stream 1 km wide has a constant current of 4 km/h. at what angle to the shore should a person navigate a boat, which is maintaining a constant speed of 16 km/h, in order to reach a point directly opposite? (give your answer for acute angle in decimal degrees, rounded to one decimal place.)
Answers
angle to the shore should a person navigate a boat, which is maintaining a constant speed of 16 km/h, in order to reach a point directly opposite is 75.5 degrees.
Since the stream is flowing parallel alongside the shore, it takes the vector form of v {stream} = [0,4]
the boat velocity is perpendicular to the stream, it's takes the vector form of v{boat} = [-16,0]
The resultant velocity of the boat is the sum of the velocity of the boat and stream, thus it takes the form
v{total} = [-16,0] + [0,4]
= [ -16,4]
the cosine of angle to the shore,
cos {theta} = v{total} . v {stream} / ||v{total} || x ||v {stream}||
= [ -16,4] . [0,4] / (16x4)
= 16/64
= 0.25
angle = 75.7 degrees.
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What simple machine did you find the most useful in everyday life? Explain why.
Answers
Simple machines are advantageous because they lessen labor requirements or enable people to undertake things that would otherwise be beyond their capacity.
What six simple machines can you recall?The airplane, wedge, screw, lever, pulley, and wheel-and-axle are the six most typical simple machines. They are made to change the direction or strength of the force (remember that work is equal to force times distance), which makes the task easier to complete.
Which basic machines are the most popular ones?Simple machines including the axle, wheel and axle, pulleys, inclined plane, screw, wedge, and lever are frequently utilized. Although simple machines may increase or decrease the forces which can be applied on them, they have no effect on the overall amount of work required to complete the activity.
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if half of the weight of a flatbed truck is supported by its two drive wheels, what is the maximum acceleration (in m/s2) it can achieve on wet concrete where the coefficient of kinetic friction is 0.5 and the coefficient of static friction is 0.7.
Answers
The maximum acceleration that the flatbed truck can achive on wet concrete is 5[tex]m/s^{2}[/tex]
The maximum acceleration a truck can achieve on wet concrete is determined by the coefficient of friction between the two drive wheels and the surface.
Taking into account the coefficients of static and kinetic friction between the drive wheels and a wet concrete surface—0.7 and 0.5, respectively—the maximum acceleration of a truck with half its weight supported by its two drive wheels can be calculated using Newton's Second Law of Motion.
According to Newton's Second Law, F = ma, where F is force, m is mass and a is acceleration.
Since the truck has half its weight supported by its two drive wheels, we know that F = 0.5 mg (where m is mass and g is gravitational acceleration). Thus, when solving for a (acceleration), we have:
a = F/m
= 0.5mg/m
= 0.5g
= 4.9 [tex]m/s^{2}[/tex] ≈ 5 [tex]m/s^{2}[/tex]
This means that on wet concrete with coefficients of static friction and kinetic friction at 0.7 and 0.5 respectively, the maximum acceleration a truck with half its weight supported by its two driving wheels can achieve is 5 [tex]m/s^{2}[/tex].
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will wants to allow sunlight into his living room, but he needs to angle the light to avoid glare on his tv. which window treatments will achieve this result?
Answers
Blinds window treatments will allow sunlight into his living room, but he needs to angle the light to avoid glare on his tv.
Even additional light will enter through the open window, further illuminating the space. You should think about some strategic lighting solutions for dark spaces in addition to trying to increase any available natural light.
East and west-facing windows frequently receive excessive sunlight, exposing these rooms to the sun at its hottest part of the day. The warmth in the room rises due to the sun's glare through these windows, which might make it difficult to read or watch television.
According to Lowe's, temporary heat-control window film should be used to cover windows that face south and west in order to reduce glare from the sun. This film is specifically created to prevent UV sun rays while yet allowing allowing some daylight to enter.
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if a vehicle is of length 4.7 m on the average, what is the average spacing between vehicles at the above traffic density?
Answers
Average vehicle spacing at higher traffic density is 35.4 m for a vehicle with a length of 4.7 m.
Let's assume that Traffic flows at 96 km/h as per international data.
We need to find average vehicle spacing.
It indicates that a 96 km stretch of traffic gets cleared in one hour. In addition, 2400 cars may be supported in one lane for an hour. It implies that at least 96km must be taken up by 2400 automobiles. Congestion results from more vehicles moving at the same speed but occupying a smaller space as the number of automobiles increases.
Here, the key to the issue is that you must just consider length. 96 kilometres equal 96,000 metres at this time. If 2400 automobiles take up this much space [just lengthwise], 1 car will take up 96000/2400 m. it is 40 metres. Therefore, each automobile may use up 40m. But the automobile is 4.2 metres long.
It can thus also have a free space of 40 - 4.6 = 35.4 m.
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a meter stick is supported at each end by a spring scale. a heavy mass is then hung on the meter stick so that the spring scale on the left hand side reads four times the value of the spring scale on the right hand side. if the mass of the meter stick is negligible compared to the hanging mass, how far from the right hand side is the large mass hanging?
Answers
The mass is dangling 4/5 of the length of the metre stick away from the right side if the mass of the metre stick is insignificant in comparison to the hanging mass.
The turning force on an item is measured by torque, which is computed by dividing the force by the separation from the pivot point.
Let's designate the forces on the left and right spring scales as F1 and F2, respectively.
F1 = 4F2, as we are aware.
The left side's torque is F1 * L, while the right side's torque is F2 * L (L is the distance from the right side).
Accordingly, F1 * L = F2 * L 4 F2 * L = F2 * L, the total torque on the left side must match the total torque on the right side.
It is evident that L = 4L/5.
In other words, the mass is dangling 4/5 of the way down the metre stick from the right side.
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a cubical gaussian surface surrounds two charges q1 6.8 10 12 c and q2 2.0 10 12 c as the drawing shows what is the electric flux passing through the surface how do i get the answer as 0.54 n m 2 c a see answer
Answers
For the given statement the Electric flux through the surface is 0.54 N m 2 /C.
Note: we are considering the distance between two charges to be 0.1 m
Electric flux in electromagnetism is a measurement of the electric field passing through a certain surface. The SI unit for the scalar quantity known as electric flux is newton-meters squared per coulomb (N m 2 /C). N · m 2 /C )
The electric flux passing through a surface can be calculated using the equation:
Φ = E * A = (k * q1 + k * q2) / r^2 * A
k = Coulomb's constant = 8.99 x 10^9 N * m^2 / C^2
r = distance between the charges = 0.1 m
A = surface area = 0.1 m * 0.1 m = 0.01 m^2
Now if we calculate:
Φ = (k * q1 + k * q2) / r^2 * A = [(0.01 m^2)]* [(8.99 x 10^9 N * m^2 / C^2) *( 6.8 x 10^-12 C)] + [(8.99 x 10^9 N * m^2 / C^2) * (2 x 10^-12 C)] / (0.1 m)^2 = 0.54 N * m^2 / C.
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can you receive a shock severe enough to prevent you from releasing the wire from an ordinary outlet with dry hands?
Answers
It is possible to receive a severe electrical shock from an ordinary outlet that would prevent a person from releasing the wire with dry hands, but it is not likely.
What are the factors to judge the severity of an electrical shock?The severity of an electrical shock depends on several factors, including the amount of current flowing through the body, the duration of the shock, and the path the current takes through the body. In most cases, a person would be able to release the wire from an outlet even if they received a shock. However, it is important to note that any electrical shock can be dangerous and should be avoided.
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oak is 0.8 as dense are water and therefore floats in water. what weight of water will be displaced by a 50 kg floating oak beam?
Answers
613.25 N is the weight of water will be displaced by a 50 kg floating oak beam, if oak is 0.8 times dense of water.
Density of water, = 1000 kg/m³
Density of oak, = 0.8 × 1000 = 800 kg/m³
Floating of an object is possible if the upward force exerted by the water is equal to the weight of the object. And this upward force is equal to the weight of water displaced by the floating object.
Volume of the water displaced by the 50 kg oak, V = 50/800 = 0.0625 m³
Mass of the displaced water = 0.0625 × 1000 = 62.5 kg
Weight of the displaced water = 62.5 × 9.81 = 613.13 N.
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To determine the density of a piece of glass, a forensic technician places the glass in a liquid with a density of 2. 1 g/mL. The glass sinks. What should the technician do now?
a. Record that the density is greater than 2. 1 g/mL and stop the analysis.
b. Add a liquid with a density less than 2. 1 g/mL until the glass begins to float.
c. Add a liquid with a density greater than 2. 1 g/mL until the glass begins to float.
d. Record that the density is less than 2. 1 g/mL and stop the analysis
Answers
The technician can either note that the density is more than 2.1 g/mL and halt the analysis, or he can add more liquid until the glass starts to float.
The density of a material is an indicator of how heavy it is in relation to its size. An object will float when submerged in water if its density is lower than that of the water, while sinking if its density is higher. A differentiating characteristic that is unrelated to a substance's volume is its density. By suspending a glass sample in a liquid solution, one can calculate the density of an unknown glass sample. The density of the liquid is then determined, either directly or by comparison with a glass sample.
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